F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N

Size: px
Start display at page:

Download "F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N"

Transcription

1 Chapte answes Heinemann Physics 4e Section. Woked example: Ty youself.. GRAVITATIONAL ATTRACTION BETWEEN SMALL OBJECTS Two bowling balls ae sitting next to each othe on a shelf so that the centes of the balls ae 60 cm apat. Ball has a mass of 7.0 kg and ball has a mass of 5.5 kg. Calculate the foce of gavitational attaction between them. Recall the fomula fo Newton s law of univesal gavitation. Identify the infomation equied, and convet values into appopiate units when necessay. G mm m 7.0 kg m 5.5 kg 0.60 m G N m kg Substitute the values into the equation. Solve the equation N Woked example: Ty youself.. GRAVITATIONAL ATTRACTION BETWEEN LARGE OBJECTS Calculate the foce of gavitational attaction between the Eath and the Moon, given the following data: m Eath kg m Moon kg Moon Eath m Recall the fomula fo Newton s law of univesal gavitation. Identify the infomation equied. G mm m kg m kg m G N m kg Substitute the values into the equation. Solve the equation N ( ) 4 Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

2 Heinemann Physics 4e Woked example: Ty youself..3 ACCELERATION CAUSED BY A GRAVITATIONAL FORCE The foce of gavitational attaction between the Sun and the Eath is appoximately N. Calculate the acceleation of the Eath and the Sun caused by this foce. Compae these acceleations by calculating the atio a a Use the following data: m Eath kg m Sun kg Eath Sun. Recall the fomula fo Newton s second law of motion. F ma Tanspose the equation to make a the subject. a F m Substitute values into this equation to find the acceleations of the Eath and the Sun. a Eath a Sun m s m s Compae the two acceleations. 3 aeath asun.8 0 The acceleation of the Eath is times geate than the acceleation of the Sun. Woked example: Ty youself..4 GRAVITATIONAL FORCE AND WEIGHT Compae the weight of a.0 kg mass on the Eath s suface calculated using the fomulas mg and G mm Use the following dimensions of the Eath whee necessay: g 9.8 m s m Eath kg Eath m. Apply the weight equation. Apply Newton s law of univesal gavitation. mg N G mm N 9.8 N ( ) Compae the two values. Both equations give the same esult to two significant figues. Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

3 Heinemann Physics 4e Woked example: Ty youself..5 APPARENT WEIGHT Calculate the appaent weight of a 90 kg peson in an elevato which is acceleating downwads at 0.8 m s. Use g 9.8 m s. Calculate the weight of the peson using mg. Calculate the foce equied to acceleate the peson at 0.8 m s. The net foce that causes the acceleation consists of the nomal eaction foce (upwads) and the weight foce (downwads). Since the elevato is acceleating downwads, > F N. Notice that, as the peson is patially falling in the diection of gavitational acceleation, thee is less contact foce and the peson feels lighte than if standing still. mg N F net ma N F net 7 F N 7 88 F N 7 F N 88 7 Appaent weight 80 N. eview The foce of attaction between any two bodies in the univese is diectly popotional to the poduct of thei masses and invesely popotional to the squae of the distance between them. is the distance between the centes of the two objects. 3 G mm (. 0 ) N 4 m Mas a Mas a Mas.8 0 a Mas m s 5 a Note: million km 0 6 km 0 9 m G mm ( ) N b G mm ( ) N c % compaison ( ) (3.4 0 ) %. The Mas Eath foce was % of the Sun Eath foce. 6 The Moon has a smalle mass than the Eath and theefoe expeiences a lage acceleation fom the same gavitational foce. 7 a g G M g m s 8 G mm N ( ) ( ) Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

4 Heinemann Physics 4e 9 On Eath, weight is the gavitational foce acting on an object nea the Eath s suface wheeas appaent weight is the contact foce between the object and the Eath s suface. In many situations, these two foces ae equal in magnitude but ae in opposite diections. This is because appaent weight is a eaction foce to the weight of an object esting on the gound. Howeve, in an elevato acceleating upwads, the appaent weight of an object would be geate than its weight since an additional foce would be equied to cause the object to acceleate upwads. 0 a mg N When acceleating upwads at. m s, the net foce is F net ma N, and F N >. F net F N 60 N F N N. The peson s appaent weight is 550 N. b When the peson is moving at a constant speed, thei appaent weight is equal to thei weight. F N mg N Section. Woked example: Ty youself.. INTERPRETING GRAVITATIONAL FIELD DIAGRAMS The diagam below shows the gavitational field of a planet. A B C (a) Use aows to indicate the diection of the gavitational foce acting at points A, B and C. The diection of the field aows indicates the diection of the gavitational foce, which is inwads towads the cente of the planet. A B C Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

5 Heinemann Physics 4e (b) Indicate the elative stength of the gavitational field at each point. The close the field lines, the stonge the foce. A weakest field B stongest field mediumstength field C Woked example: Ty youself.. CALCULATING GRAVITATIONAL FIELD STRENGTH A student uses a sping balance to measue the weight of a piece of wood as.5 N. If the piece of wood is thought to have a mass of 60 g, calculate the gavitational field stength indicated by this expeiment. Recall the equation fo gavitational field stength. Substitute in the appopiate values. g m g Solve the equation. g 9.6 N kg Woked example: Ty youself..3 CALCULATING GRAVITATIONAL FIELD STRENGTH AT DIFFERENT ALTITUDES Commecial ailines typically fly at an altitude of 000 m. Calculate the gavitational field stength of the Eath at this height using the following data: Eath m m Eath kg Recall the fomula fo gavitational field stength. g G M Add the altitude of the plane to the adius of the Eath m m Substitute the values into the fomula. g G M N kg ( ) 6 Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

6 Heinemann Physics 4e Woked example: Ty youself..4 GRAVITATIONAL FIELD STRENGTH ON ANOTHER PLANET OR MOON Calculate the stength of the gavitational field on the suface of Mas. m Mas kg Mas 3390 km Give you answe coect to two significant figues. Recall the fomula fo gavitational field stength. g G M Convet Mas adius to m km m Substitute values into the fomula. g G M N kg ( ) 6. eview N kg g m N kg The distance has been inceased thee times fom 400 km to 00 km so, in tems of the invese squae law, and the oiginal distance, : F ( 3 ) ( 9 ) of the oiginal 9 4 a g G M N kg ( ) 4 ( ) 3 b g G M N kg ( ) ( ) 3 c g G M N kg ( ) ( ) 3 d g G M N kg ( ) ( ) 3 Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

7 Heinemann Physics 4e 5 g G M N kg o N kg 3 6 g G M Mecuy: g (.44 0) Satun: g (6.03 0) Jupite: g (7.5 0) 7 g G M (0 0) N kg 0.4 N kg 4.8 N kg 0 N kg 8 g poles G M M kg M g equato G M N kg The gavitational field stength at the poles is.4 times that at the equato. (Altenatively, the invese squae law could also be used to find this elationship.) 9 Let x be the distance fom the cente of the Eath whee the Eath s gavity equals the Moon s gavity. Then: g Eath x g Moon 8 ( x) Equating these two expessions gives: x 8 ( x) 8. x x ( ) Taking squae oots of both sides gives: 9.07 x x ( ) Inveting both sides gives: x x x x 0.07x x m 0 g is popotional to, so if g becomes 0 times means a distance of 0 Eath adii. 00 th of its value, must become 0 times its value so that becomes 00. Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

8 Heinemann Physics 4e Section.3 Woked example: Ty youself.3. WORK DONE FOR A CHANGE IN GRAVITATIONAL POTENTIAL ENERGY Calculate the wok done (in MJ) to lift a weathe satellite of 3. tonnes fom the Eath s suface to the limit of the atmosphee, which ends at the Kaman line (exactly 00 km up fom the suface of the Eath). Assume g 9.8 N kg. Convet the values into the appopiate units. m 3. tonnes 300 kg h 00 km m Substitute the values into E g mgδh. Remembe to give you answe in MJ to two significant figues. The wok done is equal to the change in gavitational potential enegy. E g mgδh J MJ W E MJ Woked example: Ty youself.3. SPEED OF A FALLING OBJECT Calculate how fast a 450 g hamme would be going as it hit the gound if it was dopped fom a height of.4 m on Eath, whee g 9.8 N kg. Calculate the gavitational potential enegy of the hamme on Eath. Assume that when the hamme hits the suface of the Eath, all of its gavitational potential enegy has been conveted into kinetic enegy. Use the definition of kinetic enegy to calculate the speed of the hamme as it hits the gound. E g mgδh J E k E g 6. J E k mv v v v 5. m s Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

9 Heinemann Physics 4e Woked example: Ty youself.3.3 CHANGE IN GRAVITATIONAL POTENTIAL ENERGY USING A FORCE DISTANCE GRAPH A 500 kg lump of space junk is plummeting towads the Moon. The Moon has a adius of m. Using the foce distance gaph, detemine the decease in gavitational potential enegy of the junk as it falls to the Moon s suface. m 500 kg v 50 m s m m Gavitational foce on space junk (N) Distance fom cente of Moon ( 0 6 m) Count the numbe of shaded squaes. (Only count squaes that ae at least 50% shaded.) Numbe of shaded squaes 5 Calculate the aea (enegy value) of each squae. E squae J To calculate the enegy change, multiply the numbe of shaded squaes by the enegy value of each squae. ΔE g 5 ( 0 7 ) J Woked example: Ty youself.3.4 CHANGE IN GRAVITATIONAL POTENTIAL ENERGY USING A GRAVITATIONAL FIELD STRENGTH DISTANCE GRAPH A 3000 kg Soyuz ocket moves fom an obital height of 300 km above the Eath s suface to dock with the Intenational Space Station at a height of 500 km. Use the gaph of the gavitational field stength of the Eath below to detemine the appoximate change in gavitational potential enegy of the ocket. Gavitational field stength (N kg ) Altitude (km) Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

10 Heinemann Physics 4e Count the numbe of shaded squaes. Only count squaes that ae at least 50% shaded. Numbe of shaded squaes 36 Calculate the enegy value of each squae. E squae m N kg J kg To calculate the enegy change, multiply the numbe of shaded squaes by the enegy value of each squae and the mass of the ocket. E g J.3 eview C. A stable obit suggests that the object is in a unifom gavitational field, hence its gavitational potential enegy does not change. Its speed will also emain the same in a stable obit. g inceases fom point A to point D. 3 The meteo is unde the influence of the Eath s gavitational field which will cause it to acceleate at an inceasing ate as it appoaches the Eath. 4 A, B and C ae all coect. The total enegy of the system does not change. 5 W E g J 6 E g mg h J E k mv v v m s 7 a 00 km above the Eath s suface is a distance of m m m. Accoding to the gaph, F is between 9 N and 9. N at this height. b Accoding to the gaph, 5 N occus at appoximately m fom the cente of the Eath. So, the height above the Eath s suface m o 600 km. 8 a Convet km s to m s then apply the ule: E k mv J b E k E g E g aea unde the gaph aea 9 squaes J c new E k stating E k + E k J d new speed m s o 7.3 km s km above the Eath s suface m o 7000 km Aea unde the gaph between 7000 km and 8000 km is appoximately 7 squaes. As the satellite comes to a stop, the change in kinetic enegy ove the distance is the same as the E k at its launch. E k aea unde the gaph mass of the satellite 7 squaes J Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

11 Heinemann Physics 4e km above the Eath s suface m o 7000 km 600 km above the Eath s suface m o 9000 km. The aea unde the gaph between 7000 km and 9000 km is appoximately 6 squaes. E g aea unde the gaph mass of the satellite 6 squaes J CHAPTER REVIEW G mm ( ) 730 N G mm F ma Sun m m a Sun F m m s 4 a The foce exeted on Jupite by the Sun is equal to the foce exeted on the Sun by Jupite. b The acceleation of Jupite caused by the Sun is geate than the acceleation of the Sun caused by Jupite. 5 g G M m s ( ) 6 a mg N When acceleating downwads at 0.6 m s, the net foce is F net ma N and > F N. F N F N 30 F N N b When the peson is moving at a constant speed, thei appaent weight is equal to thei weight: F N 490 N 7 a F G mm 7 ( ) 7 (7.5 0) N b The magnitude of the gavitational foce that the comet exets on Jupite is equal to the magnitude of the gavitational foce that Jupite exets on the comet N. net c a F m m s net d a F m m s Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

12 Heinemann Physics 4e 8 D. At a height of two Eath adii above the Eath s suface, a peson is a distance of thee Eath adii fom the cente of the Eath Then F 00 N a D. F net F N ma F N N o 300 N b B. Fom pat (a), the appaent weight is geate than the weight of the astonaut. c C. Tue weight is unchanged duing lift-off as g is constant. d A. Duing obit, the astonaut is in fee fall. e D. ma N o 660 N 0 When epesenting a gavitational field with a field diagam, the diection of the aowhead indicates the diection of the gavitational foce and the space between the aows indicates the magnitude of the field. In gavitational fields, the field lines always point towads the souces of the field. 600 g 9.76 N kg m 6.5 a g G M ( ) 9.79 N kg b g G M ( ) 9.85 N kg % % a g G M (.48 0). N kg b C. It will acceleate at a ate given by the gavitational field stength, g. 4 G M ( 0.8R) M m M m G m ( 0.R) a Incease in E k aea unde the gaph between m and m 6 squaes J b E k(initial) mv J E k(new) J 7 Ek 4 0 c v 000 m s o km s m 0 d Fom the gaph, F 70 N mg g N kg km m o m Fom the gaph, g 9 N kg at this altitude. 7 D. The units on the gaph ae N m kg, which ae the same as J kg 8 C. As the satellite falls, its gavitational potential enegy deceases. The units on the gaph ae J kg, so theefoe C is coect. 9 Incease in E k aea unde the gaph mass of the satellite 35 squaes J 0 No. Ai esistance will play a majo pat as the satellite e-entes the Eath s atmosphee. Copyight Peason Austalia 06 (a division of Peason Austalia Goup Pty Ltd) ISBN

Between any two masses, there exists a mutual attractive force.

Between any two masses, there exists a mutual attractive force. YEAR 12 PHYSICS: GRAVITATION PAST EXAM QUESTIONS Name: QUESTION 1 (1995 EXAM) (a) State Newton s Univesal Law of Gavitation in wods Between any two masses, thee exists a mutual attactive foce. This foce

More information

Circular Orbits. and g =

Circular Orbits. and g = using analyse planetay and satellite motion modelled as unifom cicula motion in a univesal gavitation field, a = v = 4π and g = T GM1 GM and F = 1M SATELLITES IN OBIT A satellite is any object that is

More information

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature)

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature) a = c v 2 Recap Centipetal acceleation: m/s 2 (towads cente of cuvatue) A centipetal foce F c is equied to keep a body in cicula motion: This foce poduces centipetal acceleation that continuously changes

More information

kg 2 ) 1.9!10 27 kg = Gm 1

kg 2 ) 1.9!10 27 kg = Gm 1 Section 6.1: Newtonian Gavitation Tutoial 1 Pactice, page 93 1. Given: 1.0 10 0 kg; m 3.0 10 0 kg;. 10 9 N; G 6.67 10 11 N m /kg Requied: Analysis: G m ; G m G m Solution: G m N m 6.67!10 11 kg ) 1.0!100

More information

Universal Gravitation

Universal Gravitation Chapte 1 Univesal Gavitation Pactice Poblem Solutions Student Textbook page 580 1. Conceptualize the Poblem - The law of univesal gavitation applies to this poblem. The gavitational foce, F g, between

More information

Ch 13 Universal Gravitation

Ch 13 Universal Gravitation Ch 13 Univesal Gavitation Ch 13 Univesal Gavitation Why do celestial objects move the way they do? Keple (1561-1630) Tycho Bahe s assistant, analyzed celestial motion mathematically Galileo (1564-1642)

More information

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and Exta notes fo cicula motion: Cicula motion : v keeps changing, maybe both speed and diection ae changing. At least v diection is changing. Hence a 0. Acceleation NEEDED to stay on cicula obit: a cp v /,

More information

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11.

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11. NSWRS - P Physics Multiple hoice Pactice Gavitation Solution nswe 1. m mv Obital speed is found fom setting which gives v whee M is the object being obited. Notice that satellite mass does not affect obital

More information

OSCILLATIONS AND GRAVITATION

OSCILLATIONS AND GRAVITATION 1. SIMPLE HARMONIC MOTION Simple hamonic motion is any motion that is equivalent to a single component of unifom cicula motion. In this situation the velocity is always geatest in the middle of the motion,

More information

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9 SPH4 nit 6.3 Gavitational Potential negy Page of Notes Physics ool box he gavitational potential enegy of a syste of two (spheical) asses is diectly popotional to the poduct of thei asses, and invesely

More information

Chapter 13 Gravitation

Chapter 13 Gravitation Chapte 13 Gavitation In this chapte we will exploe the following topics: -Newton s law of gavitation, which descibes the attactive foce between two point masses and its application to extended objects

More information

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE VISUAL PHYSICS ONLINE MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES SATELLITES: Obital motion of object of mass m about a massive object of mass M (m

More information

m1 m2 M 2 = M -1 L 3 T -2

m1 m2 M 2 = M -1 L 3 T -2 GAVITATION Newton s Univesal law of gavitation. Evey paticle of matte in this univese attacts evey othe paticle with a foce which vaies diectly as the poduct of thei masses and invesely as the squae of

More information

Practice. Understanding Concepts. Answers J 2. (a) J (b) 2% m/s. Gravitation and Celestial Mechanics 287

Practice. Understanding Concepts. Answers J 2. (a) J (b) 2% m/s. Gravitation and Celestial Mechanics 287 Pactice Undestanding Concepts 1. Detemine the gavitational potential enegy of the Eath Moon system, given that the aveage distance between thei centes is 3.84 10 5 km, and the mass of the Moon is 0.0123

More information

(a) Calculate the apparent weight of the student in the first part of the journey while accelerating downwards at 2.35 m s 2.

(a) Calculate the apparent weight of the student in the first part of the journey while accelerating downwards at 2.35 m s 2. Chapte answes Heineann Physics 1 4e Section.1 Woked exaple: Ty youself.1.1 CALCULATING APPARENT WEIGHT A 79.0 kg student ides a lift down fo the top floo of an office block to the gound. Duing the jouney

More information

Unit 6 Test Review Gravitation & Oscillation Chapters 13 & 15

Unit 6 Test Review Gravitation & Oscillation Chapters 13 & 15 A.P. Physics C Unit 6 Test Review Gavitation & Oscillation Chaptes 13 & 15 * In studying fo you test, make sue to study this eview sheet along with you quizzes and homewok assignments. Multiple Choice

More information

Chapter 4. Newton s Laws of Motion

Chapter 4. Newton s Laws of Motion Chapte 4 Newton s Laws of Motion 4.1 Foces and Inteactions A foce is a push o a pull. It is that which causes an object to acceleate. The unit of foce in the metic system is the Newton. Foce is a vecto

More information

PHYSICS NOTES GRAVITATION

PHYSICS NOTES GRAVITATION GRAVITATION Newton s law of gavitation The law states that evey paticle of matte in the univese attacts evey othe paticle with a foce which is diectly popotional to the poduct of thei masses and invesely

More information

Chap13. Universal Gravitation

Chap13. Universal Gravitation Chap13. Uniesal Gaitation Leel : AP Physics Instucto : Kim 13.1 Newton s Law of Uniesal Gaitation - Fomula fo Newton s Law of Gaitation F g = G m 1m 2 2 F21 m1 F12 12 m2 - m 1, m 2 is the mass of the object,

More information

Physics 111. Ch 12: Gravity. Newton s Universal Gravity. R - hat. the equation. = Gm 1 m 2. F g 2 1. ˆr 2 1. Gravity G =

Physics 111. Ch 12: Gravity. Newton s Universal Gravity. R - hat. the equation. = Gm 1 m 2. F g 2 1. ˆr 2 1. Gravity G = ics Announcements day, embe 9, 004 Ch 1: Gavity Univesal Law Potential Enegy Keple s Laws Ch 15: Fluids density hydostatic equilibium Pascal s Pinciple This week s lab will be anothe physics wokshop -

More information

= 4 3 π( m) 3 (5480 kg m 3 ) = kg.

= 4 3 π( m) 3 (5480 kg m 3 ) = kg. CHAPTER 11 THE GRAVITATIONAL FIELD Newton s Law of Gavitation m 1 m A foce of attaction occus between two masses given by Newton s Law of Gavitation Inetial mass and gavitational mass Gavitational potential

More information

Physics 107 TUTORIAL ASSIGNMENT #8

Physics 107 TUTORIAL ASSIGNMENT #8 Physics 07 TUTORIAL ASSIGNMENT #8 Cutnell & Johnson, 7 th edition Chapte 8: Poblems 5,, 3, 39, 76 Chapte 9: Poblems 9, 0, 4, 5, 6 Chapte 8 5 Inteactive Solution 8.5 povides a model fo solving this type

More information

DYNAMICS OF UNIFORM CIRCULAR MOTION

DYNAMICS OF UNIFORM CIRCULAR MOTION Chapte 5 Dynamics of Unifom Cicula Motion Chapte 5 DYNAMICS OF UNIFOM CICULA MOTION PEVIEW An object which is moing in a cicula path with a constant speed is said to be in unifom cicula motion. Fo an object

More information

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed?

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 10, 2012 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

2013 Checkpoints Chapter 7 GRAVITY

2013 Checkpoints Chapter 7 GRAVITY 0 Checkpoints Chapte 7 GAVIY Question 64 o do this question you must et an equation that has both and, whee is the obital adius and is the peiod. You can use Keple s Law, which is; constant. his is a vey

More information

PS113 Chapter 5 Dynamics of Uniform Circular Motion

PS113 Chapter 5 Dynamics of Uniform Circular Motion PS113 Chapte 5 Dynamics of Unifom Cicula Motion 1 Unifom cicula motion Unifom cicula motion is the motion of an object taveling at a constant (unifom) speed on a cicula path. The peiod T is the time equied

More information

Chapter 13: Gravitation

Chapter 13: Gravitation v m m F G Chapte 13: Gavitation The foce that makes an apple fall is the same foce that holds moon in obit. Newton s law of gavitation: Evey paticle attacts any othe paticle with a gavitation foce given

More information

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS LSN 10-: MOTION IN A GRAVITATIONAL FIELD Questions Fom Reading Activity? Gavity Waves? Essential Idea: Simila appoaches can be taken in analyzing electical

More information

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE.

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE. Unit 6 actice Test 1. Which one of the following gaphs best epesents the aiation of the kinetic enegy, KE, and of the gaitational potential enegy, GE, of an obiting satellite with its distance fom the

More information

Physics: Work & Energy Beyond Earth Guided Inquiry

Physics: Work & Energy Beyond Earth Guided Inquiry Physics: Wok & Enegy Beyond Eath Guided Inquiy Elliptical Obits Keple s Fist Law states that all planets move in an elliptical path aound the Sun. This concept can be extended to celestial bodies beyond

More information

Chapter 8. Accelerated Circular Motion

Chapter 8. Accelerated Circular Motion Chapte 8 Acceleated Cicula Motion 8.1 Rotational Motion and Angula Displacement A new unit, adians, is eally useful fo angles. Radian measue θ(adians) = s = θ s (ac length) (adius) (s in same units as

More information

Potential Energy and Conservation of Energy

Potential Energy and Conservation of Energy Potential Enegy and Consevation of Enegy Consevative Foces Definition: Consevative Foce If the wok done by a foce in moving an object fom an initial point to a final point is independent of the path (A

More information

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE VISUAL PHYSICS ONLIN MODUL 5 ADVANCD MCHANICS GRAVITATIONAL FILD: MOTION OF PLANTS AND SATLLITS SATLLITS: Obital motion of object of mass m about a massive object of mass M (m

More information

Chapter 5: Uniform Circular Motion

Chapter 5: Uniform Circular Motion Chapte 5: Unifom Cicula Motion Motion at constant speed in a cicle Centipetal acceleation Banked cuves Obital motion Weightlessness, atificial gavity Vetical cicula motion Centipetal Foce Acceleation towad

More information

AP Physics 1 - Circular Motion and Gravitation Practice Test (Multiple Choice Section) Answer Section

AP Physics 1 - Circular Motion and Gravitation Practice Test (Multiple Choice Section) Answer Section AP Physics 1 - Cicula Motion and Gaitation Pactice est (Multiple Choice Section) Answe Section MULIPLE CHOICE 1. B he centipetal foce must be fiction since, lacking any fiction, the coin would slip off.

More information

PHYS Summer Professor Caillault Homework Solutions. Chapter 5

PHYS Summer Professor Caillault Homework Solutions. Chapter 5 PHYS 1111 - Summe 2007 - Pofesso Caillault Homewok Solutions Chapte 5 7. Pictue the Poblem: The ball is acceleated hoizontally fom est to 98 mi/h ove a distance of 1.7 m. Stategy: Use equation 2-12 to

More information

PHYSICS 1210 Exam 2 University of Wyoming 14 March ( Day!) points

PHYSICS 1210 Exam 2 University of Wyoming 14 March ( Day!) points PHYSICS 1210 Exam 2 Univesity of Wyoming 14 Mach ( Day!) 2013 150 points This test is open-note and closed-book. Calculatos ae pemitted but computes ae not. No collaboation, consultation, o communication

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion Intoduction Ealie we defined acceleation as being the change in velocity with time: a = v t Until now we have only talked about changes in the magnitude of the acceleation: the speeding

More information

Gaia s Place in Space

Gaia s Place in Space Gaia s Place in Space The impotance of obital positions fo satellites Obits and Lagange Points Satellites can be launched into a numbe of diffeent obits depending on thei objectives and what they ae obseving.

More information

HW Solutions # MIT - Prof. Please study example 12.5 "from the earth to the moon". 2GmA v esc

HW Solutions # MIT - Prof. Please study example 12.5 from the earth to the moon. 2GmA v esc HW Solutions # 11-8.01 MIT - Pof. Kowalski Univesal Gavity. 1) 12.23 Escaping Fom Asteoid Please study example 12.5 "fom the eath to the moon". a) The escape velocity deived in the example (fom enegy consevation)

More information

21 MAGNETIC FORCES AND MAGNETIC FIELDS

21 MAGNETIC FORCES AND MAGNETIC FIELDS CHAPTER 1 MAGNETIC ORCES AND MAGNETIC IELDS ANSWERS TO OCUS ON CONCEPTS QUESTIONS 1. (d) Right-Hand Rule No. 1 gives the diection of the magnetic foce as x fo both dawings A and. In dawing C, the velocity

More information

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once.

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once. Honos Physics Fall, 2016 Cicula Motion & Toque Test Review Name: M. Leonad Instuctions: Complete the following woksheet. SHOW ALL OF YOUR WORK ON A SEPARATE SHEET OF PAPER. 1. Detemine whethe each statement

More information

Chapter 4: The laws of motion. Newton s first law

Chapter 4: The laws of motion. Newton s first law Chapte 4: The laws of motion gavitational Electic magnetic Newton s fist law If the net foce exeted on an object is zeo, the object continues in its oiginal state of motion: - an object at est, emains

More information

Electrostatics. 3) positive object: lack of electrons negative object: excess of electrons

Electrostatics. 3) positive object: lack of electrons negative object: excess of electrons Electostatics IB 12 1) electic chage: 2 types of electic chage: positive and negative 2) chaging by fiction: tansfe of electons fom one object to anothe 3) positive object: lack of electons negative object:

More information

Chap 5. Circular Motion: Gravitation

Chap 5. Circular Motion: Gravitation Chap 5. Cicula Motion: Gavitation Sec. 5.1 - Unifom Cicula Motion A body moves in unifom cicula motion, if the magnitude of the velocity vecto is constant and the diection changes at evey point and is

More information

TAMPINES JUNIOR COLLEGE 2009 JC1 H2 PHYSICS GRAVITATIONAL FIELD

TAMPINES JUNIOR COLLEGE 2009 JC1 H2 PHYSICS GRAVITATIONAL FIELD TAMPINES JUNIOR COLLEGE 009 JC1 H PHYSICS GRAVITATIONAL FIELD OBJECTIVES Candidates should be able to: (a) show an undestanding of the concept of a gavitational field as an example of field of foce and

More information

10. Universal Gravitation

10. Universal Gravitation 10. Univesal Gavitation Hee it is folks, the end of the echanics section of the couse! This is an appopiate place to complete the study of mechanics, because with his Law of Univesal Gavitation, Newton

More information

Midterm Exam #2, Part A

Midterm Exam #2, Part A Physics 151 Mach 17, 2006 Midtem Exam #2, Pat A Roste No.: Scoe: Exam time limit: 50 minutes. You may use calculatos and both sides of ONE sheet of notes, handwitten only. Closed book; no collaboation.

More information

Gravitational Potential Energy in General

Gravitational Potential Energy in General Gavitational Potential Enegy in Geneal 6.3 To exploe such concepts as how much enegy a space pobe needs to escape fom Eath s gavity, we must expand on the topic of gavitational potential enegy, which we

More information

Objective Notes Summary

Objective Notes Summary Objective Notes Summay An object moving in unifom cicula motion has constant speed but not constant velocity because the diection is changing. The velocity vecto in tangent to the cicle, the acceleation

More information

1) Consider a particle moving with constant speed that experiences no net force. What path must this particle be taking?

1) Consider a particle moving with constant speed that experiences no net force. What path must this particle be taking? Chapte 5 Test Cicula Motion and Gavitation 1) Conside a paticle moving with constant speed that expeiences no net foce. What path must this paticle be taking? A) It is moving in a paabola. B) It is moving

More information

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer.

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer. Kiangsu-Chekiang College (Shatin) F:EasteHolidaysAssignmentAns.doc Easte Holidays Assignment Answe Fom 6B Subject: Physics. (a) State the conditions fo a body to undego simple hamonic motion. ( mak) (a)

More information

Physics Electrostatics: Coulomb s Law

Physics Electrostatics: Coulomb s Law A C U L T Y O E D U C A T I O N Depatment of Cuiculum and Pedagogy Physics Electostatics: Coulomb s Law Science and Mathematics Education Reseach Goup Suppoted by UBC Teaching and Leaning Enhancement und

More information

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS TSOKOS LESSON 6- THE LAW OF GRAVITATION Essential Idea: The Newtonian idea of gavitational foce acting between two spheical bodies and the laws of mechanics

More information

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS TSOKOS LESSON 10-1 DESCRIBING FIELDS Essential Idea: Electic chages and masses each influence the space aound them and that influence can be epesented

More information

Spring 2001 Physics 2048 Test 3 solutions

Spring 2001 Physics 2048 Test 3 solutions Sping 001 Physics 048 Test 3 solutions Poblem 1. (Shot Answe: 15 points) a. 1 b. 3 c. 4* d. 9 e. 8 f. 9 *emembe that since KE = ½ mv, KE must be positive Poblem (Estimation Poblem: 15 points) Use momentum-impulse

More information

20-9 ELECTRIC FIELD LINES 20-9 ELECTRIC POTENTIAL. Answers to the Conceptual Questions. Chapter 20 Electricity 241

20-9 ELECTRIC FIELD LINES 20-9 ELECTRIC POTENTIAL. Answers to the Conceptual Questions. Chapter 20 Electricity 241 Chapte 0 Electicity 41 0-9 ELECTRIC IELD LINES Goals Illustate the concept of electic field lines. Content The electic field can be symbolized by lines of foce thoughout space. The electic field is stonge

More information

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun Chapte 12 Gavitation PowePoint Lectues fo Univesity Physics, Twelfth Edition Hugh D. Young and Roge A. Feedman Lectues by James Pazun Modified by P. Lam 5_31_2012 Goals fo Chapte 12 To study Newton s Law

More information

Gravitation. AP/Honors Physics 1 Mr. Velazquez

Gravitation. AP/Honors Physics 1 Mr. Velazquez Gavitation AP/Honos Physics 1 M. Velazquez Newton s Law of Gavitation Newton was the fist to make the connection between objects falling on Eath and the motion of the planets To illustate this connection

More information

Chapter 5 Force and Motion

Chapter 5 Force and Motion Chapte 5 Foce and Motion In Chaptes 2 and 4 we have studied kinematics, i.e., we descibed the motion of objects using paametes such as the position vecto, velocity, and acceleation without any insights

More information

Chapter 5 Force and Motion

Chapter 5 Force and Motion Chapte 5 Foce and Motion In chaptes 2 and 4 we have studied kinematics i.e. descibed the motion of objects using paametes such as the position vecto, velocity and acceleation without any insights as to

More information

7.2. Coulomb s Law. The Electric Force

7.2. Coulomb s Law. The Electric Force Coulomb s aw Recall that chaged objects attact some objects and epel othes at a distance, without making any contact with those objects Electic foce,, o the foce acting between two chaged objects, is somewhat

More information

Determining solar characteristics using planetary data

Determining solar characteristics using planetary data Detemining sola chaacteistics using planetay data Intoduction The Sun is a G-type main sequence sta at the cente of the Sola System aound which the planets, including ou Eath, obit. In this investigation

More information

Objects usually are charged up through the transfer of electrons from one object to the other.

Objects usually are charged up through the transfer of electrons from one object to the other. 1 Pat 1: Electic Foce 1.1: Review of Vectos Review you vectos! You should know how to convet fom pola fom to component fom and vice vesa add and subtact vectos multiply vectos by scalas Find the esultant

More information

AP * PHYSICS B. Circular Motion, Gravity, & Orbits. Teacher Packet

AP * PHYSICS B. Circular Motion, Gravity, & Orbits. Teacher Packet AP * PHYSICS B Cicula Motion, Gavity, & Obits Teache Packet AP* is a tademak of the College Entance Examination Boad. The College Entance Examination Boad was not involved in the poduction of this mateial.

More information

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block?

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 13, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

Electric Forces: Coulomb s Law

Electric Forces: Coulomb s Law Electic Foces: Coulomb s Law All the matte aound you contains chaged paticles, and it is the electic foces between these chaged paticles that detemine the stength of the mateials and the popeties of the

More information

Physics 11 Chapter 4: Forces and Newton s Laws of Motion. Problem Solving

Physics 11 Chapter 4: Forces and Newton s Laws of Motion. Problem Solving Physics 11 Chapte 4: Foces and Newton s Laws of Motion Thee is nothing eithe good o bad, but thinking makes it so. William Shakespeae It s not what happens to you that detemines how fa you will go in life;

More information

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE.

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE. Unit 6 actice Test 1. Which one of the following gaphs best epesents the aiation of the kinetic enegy, KE, and of the gaitational potential enegy, GE, of an obiting satellite with its distance fom the

More information

Lecture 22. PE = GMm r TE = GMm 2a. T 2 = 4π 2 GM. Main points of today s lecture: Gravitational potential energy: Total energy of orbit:

Lecture 22. PE = GMm r TE = GMm 2a. T 2 = 4π 2 GM. Main points of today s lecture: Gravitational potential energy: Total energy of orbit: Lectue Main points of today s lectue: Gavitational potential enegy: Total enegy of obit: PE = GMm TE = GMm a Keple s laws and the elation between the obital peiod and obital adius. T = 4π GM a3 Midtem

More information

GRAVITATION. Thus the magnitude of the gravitational force F that two particles of masses m1

GRAVITATION. Thus the magnitude of the gravitational force F that two particles of masses m1 GAVITATION 6.1 Newton s law of Gavitation Newton s law of gavitation states that evey body in this univese attacts evey othe body with a foce, which is diectly popotional to the poduct of thei masses and

More information

University Physics Volume I Unit 1: Mechanics Chapter 13: Gravitation Conceptual Questions

University Physics Volume I Unit 1: Mechanics Chapter 13: Gravitation Conceptual Questions OpenStax Univesity Physics Volume I Univesity Physics Volume I Conceptual Questions 1. Action at a distance, such as is the case fo gavity, was once thought to be illogical and theefoe untue. What is the

More information

Physics 181. Assignment 4

Physics 181. Assignment 4 Physics 181 Assignment 4 Solutions 1. A sphee has within it a gavitational field given by g = g, whee g is constant and is the position vecto of the field point elative to the cente of the sphee. This

More information

History of Astronomy - Part II. Tycho Brahe - An Observer. Johannes Kepler - A Theorist

History of Astronomy - Part II. Tycho Brahe - An Observer. Johannes Kepler - A Theorist Histoy of Astonomy - Pat II Afte the Copenican Revolution, astonomes stived fo moe obsevations to help bette explain the univese aound them Duing this time (600-750) many majo advances in science and astonomy

More information

Physics 211: Newton s Second Law

Physics 211: Newton s Second Law Physics 211: Newton s Second Law Reading Assignment: Chapte 5, Sections 5-9 Chapte 6, Section 2-3 Si Isaac Newton Bon: Januay 4, 1643 Died: Mach 31, 1727 Intoduction: Kinematics is the study of how objects

More information

Lab #4: Newton s Second Law

Lab #4: Newton s Second Law Lab #4: Newton s Second Law Si Isaac Newton Reading Assignment: bon: Januay 4, 1643 Chapte 5 died: Mach 31, 1727 Chapte 9, Section 9-7 Intoduction: Potait of Isaac Newton by Si Godfey Knelle http://www.newton.cam.ac.uk/at/potait.html

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion constant speed Pick a point in the objects motion... What diection is the velocity? HINT Think about what diection the object would tavel if the sting wee cut Unifom Cicula Motion

More information

Our Universe: GRAVITATION

Our Universe: GRAVITATION Ou Univese: GRAVITATION Fom Ancient times many scientists had shown geat inteest towads the sky. Most of the scientist studied the motion of celestial bodies. One of the most influential geek astonomes

More information

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s 1. A stone falls fom a platfom 18 m high. When will it hit the gound? (a) 1.74 s (b) 1.83 s (c) 1.9 s (d).01 s Constant acceleation D = v 0 t + ½ a t. Which, if any, of these foces causes the otation of

More information

Section 26 The Laws of Rotational Motion

Section 26 The Laws of Rotational Motion Physics 24A Class Notes Section 26 The Laws of otational Motion What do objects do and why do they do it? They otate and we have established the quantities needed to descibe this motion. We now need to

More information

Quiz 6--Work, Gravitation, Circular Motion, Torque. (60 pts available, 50 points possible)

Quiz 6--Work, Gravitation, Circular Motion, Torque. (60 pts available, 50 points possible) Name: Class: Date: ID: A Quiz 6--Wok, Gavitation, Cicula Motion, Toque. (60 pts available, 50 points possible) Multiple Choice, 2 point each Identify the choice that best completes the statement o answes

More information

to point uphill and to be equal to its maximum value, in which case f s, max = μsfn

to point uphill and to be equal to its maximum value, in which case f s, max = μsfn Chapte 6 16. (a) In this situation, we take f s to point uphill and to be equal to its maximum value, in which case f s, max = μsf applies, whee μ s = 0.5. pplying ewton s second law to the block of mass

More information

Physics 4A Chapter 8: Dynamics II Motion in a Plane

Physics 4A Chapter 8: Dynamics II Motion in a Plane Physics 4A Chapte 8: Dynamics II Motion in a Plane Conceptual Questions and Example Poblems fom Chapte 8 Conceptual Question 8.5 The figue below shows two balls of equal mass moving in vetical cicles.

More information

Electricity Revision ELECTRICITY REVISION KEY CONCEPTS TERMINOLOGY & DEFINITION. Physical Sciences X-Sheets

Electricity Revision ELECTRICITY REVISION KEY CONCEPTS TERMINOLOGY & DEFINITION. Physical Sciences X-Sheets Electicity Revision KEY CONCEPTS In this session we will focus on the following: Stating and apply Coulomb s Law. Defining electical field stength and applying the deived equations. Dawing electical field

More information

Physics 235 Chapter 5. Chapter 5 Gravitation

Physics 235 Chapter 5. Chapter 5 Gravitation Chapte 5 Gavitation In this Chapte we will eview the popeties of the gavitational foce. The gavitational foce has been discussed in geat detail in you intoductoy physics couses, and we will pimaily focus

More information

Physics 201 Homework 4

Physics 201 Homework 4 Physics 201 Homewok 4 Jan 30, 2013 1. Thee is a cleve kitchen gadget fo dying lettuce leaves afte you wash them. 19 m/s 2 It consists of a cylindical containe mounted so that it can be otated about its

More information

Escape Velocity. GMm ] B

Escape Velocity. GMm ] B 1 PHY2048 Mach 31, 2006 Escape Velocity Newton s law of gavity: F G = Gm 1m 2 2, whee G = 667 10 11 N m 2 /kg 2 2 3 10 10 N m 2 /kg 2 is Newton s Gavitational Constant Useful facts: R E = 6 10 6 m M E

More information

Section 6.2: Orbits. Gm r. v = v 2 = Gm r. m = rv2 G. Solution: m = rv2 G ( )( 7.5!10 5 m/s ) 2. = 5.34!1017 m m kg # # m2. kg 2

Section 6.2: Orbits. Gm r. v = v 2 = Gm r. m = rv2 G. Solution: m = rv2 G ( )( 7.5!10 5 m/s ) 2. = 5.34!1017 m m kg # # m2. kg 2 Section 6.2: Obits Mini Inestigation: Exploing Gaity and Obits, page 298 A. When I incease the size of the Sun, Eath s obit changes: the obit is close to the Sun. B. he Moon is pulled out of Eath s obit

More information

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions )

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions ) 06 - ROTATIONAL MOTION Page ) A body A of mass M while falling vetically downwads unde gavity beaks into two pats, a body B of mass ( / ) M and a body C of mass ( / ) M. The cente of mass of bodies B and

More information

ω = θ θ o = θ θ = s r v = rω

ω = θ θ o = θ θ = s r v = rω Unifom Cicula Motion Unifom cicula motion is the motion of an object taveling at a constant(unifom) speed in a cicula path. Fist we must define the angula displacement and angula velocity The angula displacement

More information

Experiment 09: Angular momentum

Experiment 09: Angular momentum Expeiment 09: Angula momentum Goals Investigate consevation of angula momentum and kinetic enegy in otational collisions. Measue and calculate moments of inetia. Measue and calculate non-consevative wok

More information

Central Force Motion

Central Force Motion Cental Foce Motion Cental Foce Poblem Find the motion of two bodies inteacting via a cental foce. Examples: Gavitational foce (Keple poblem): m1m F 1, ( ) =! G ˆ Linea estoing foce: F 1, ( ) =! k ˆ Two

More information

PHYSICS 1050 Mid-term Test 1 University of Wyoming 8 February 2007

PHYSICS 1050 Mid-term Test 1 University of Wyoming 8 February 2007 Name: PHYSICS 1050 Mid-tem Test 1 Univesity of Wyoming 8 Febuay 2007 This test is open-note and open-book. This means that any efeence mateial is pemitted duing the test. Calculatos also ae pemitted. Howeve,

More information

Force of gravity and its potential function

Force of gravity and its potential function F. W. Phs0 E:\Ecel files\ch gavitational foce and potential.doc page of 6 0/0/005 8:9 PM Last pinted 0/0/005 8:9:00 PM Foce of gavit and its potential function (.) Let us calculate the potential function

More information

Physics 1114: Unit 5 Hand-out Homework (Answers)

Physics 1114: Unit 5 Hand-out Homework (Answers) Physics 1114: Unit 5 Hand-out Homewok (Answes) Poblem set 1 1. The flywheel on an expeimental bus is otating at 420 RPM (evolutions pe minute). To find (a) the angula velocity in ad/s (adians/second),

More information

Objectives: After finishing this unit you should be able to:

Objectives: After finishing this unit you should be able to: lectic Field 7 Objectives: Afte finishing this unit you should be able to: Define the electic field and explain what detemines its magnitude and diection. Wite and apply fomulas fo the electic field intensity

More information

Chapter. s r. check whether your calculator is in all other parts of the body. When a rigid body rotates through a given angle, all

Chapter. s r. check whether your calculator is in all other parts of the body. When a rigid body rotates through a given angle, all conveted to adians. Also, be sue to vanced to a new position (Fig. 7.2b). In this inteval, the line OP has moved check whethe you calculato is in all othe pats of the body. When a igid body otates though

More information

AST 121S: The origin and evolution of the Universe. Introduction to Mathematical Handout 1

AST 121S: The origin and evolution of the Universe. Introduction to Mathematical Handout 1 Please ead this fist... AST S: The oigin and evolution of the Univese Intoduction to Mathematical Handout This is an unusually long hand-out and one which uses in places mathematics that you may not be

More information

PHYSICS 220. Lecture 08. Textbook Sections Lecture 8 Purdue University, Physics 220 1

PHYSICS 220. Lecture 08. Textbook Sections Lecture 8 Purdue University, Physics 220 1 PHYSICS 0 Lectue 08 Cicula Motion Textbook Sections 5.3 5.5 Lectue 8 Pudue Univesity, Physics 0 1 Oveview Last Lectue Cicula Motion θ angula position adians ω angula velocity adians/second α angula acceleation

More information

Basic oces an Keple s Laws 1. Two ientical sphees of gol ae in contact with each othe. The gavitational foce of attaction between them is Diectly popotional to the squae of thei aius ) Diectly popotional

More information