b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block?

Size: px
Start display at page:

Download "b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block?"

Transcription

1 Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 13, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with coect units and significant figues. Patial cedit is available if you wok is clea. Points shown in paenthesis. Fo TF and MC, choose the best answe. 1. (6) The diagam shows the foces acting on a ca acceleating to the ight. The pavement is level. F oad is the fiction foce of the oad on the ties, and F ai is the ai esistance. Select the coect elationship between the foce magnitudes. a) a. F oad > F ai b. F oad = F ai c. F oad < F ai b) a. F N > mg b. F N = mg c. F N < mg 2. (6) A ca is moving at constant speed up a θ = 30 incline; the foces ae shown on the diagam. Choose the coect elationships between the foce magnitudes. a) a. F oad = F ai b. F oad = F ai mg sin θ c. F oad = F ai + mg sin θ b) a. F N = mg b. F N = mg cos θ c. F N = mg sin θ 3. (16) A constant foce F 1 = 72.0 N is applied to a 6.00-kg block, which contacts a 12.0-kg block. They acceleate togethe on a hoizontal fictionless suface. a) (6) How lage is thei common acceleation? b) (5) What is the magnitude of the foce on the 6.0-kg block due to the contact with the 12.0-kg block? c) (5) What is the magnitude of the net foce on the 6.0-kg block? 4. (2) T F If the acceleation of a mass is zeo, then thee ae no foces acting on it. 5. (2) T F The foce fom the dive tain tuning the wheels is what acceleates a ca. 6. (2) T F A static fiction foce on a mass always pevents the mass fom moving. 7. (2) T F Eath s gavitational foce on you is geate than you gavitational foce on the Eath. 8. (2) T F Sliding on a fictionless incline, a box acceleates moe going downhill athe than uphill. 9. (2) T F On an incline with fiction, a sliding box acceleates moe going downhill athe than uphill. 10. (2) T F Fo contact between two given mateials, static fiction is stonge than kinetic fiction. 1

2 11. (10) A 2.2-kg fish is being pulled out of the wate, in such a way that the tension in the fishing line is 3.0 times its weight. Daw the foces acting on the fish (fee body diagam) and find the acceleation of the fish (magnitude and diection). 12. (14) A space station is a hollow cylinde of adius 440 m, that otates to simulate gavity by its centipetal acceleation. The astonauts live at the adius 440 m fom the cente, with thei heads pointing inwad and thei feet outwad! a) (6) What speed v should the otation give the astonauts so they feel like they ae in atificial gavity of stength 2.50 g (2.5 gavity on Eath)? b) (4) Find the peiod of the otation in seconds. c) (4) Find the otation speed in evolutions pe minute. 13. (2) The flying pig, suspended fom a cable (demo in lectue), moves at constant speed in a hoizontal cicle. The net foce on him must point a) along the cable. b) hoizontally, towads the cente of the cicle. c) vetically, due to his weight. d) none of these, because the net foce is zeo. 2

3 Name Rec. Inst. Rec. Time 14. (10) A physics student takes a 5.0-kg pail of wate connected on a ope, and swings it in a vetical cicle of adius 90.0 cm at a constant speed of 7.0 m/s. a) (5) When the pail passes its highest point, what ae the magnitude and diection of its acceleation? b) (5) When the pail passes its highest point, what is the tension in the ope? 15. (10) The acceleation due to gavity at the suface of a planet of mass M, adius R, is given by the expession, g = GM/R 2. On Eath, this value is g = 9.80 m/s 2. a) (4) If Eath s diamete wee half what it is, while keeping the same mass, what would g be in m/s 2? b) (6) Suppose a planet is discoveed that has a mass 12 times that of Eath, and a adius 2.0 times that of Eath. What is the value of g in m/s 2 on this planet? 16. (6) A 145-kg football playe applies a foce of 520 N hoizontally on the opposing 125-kg quateback, while pushing him backwads 3.3 m at constant speed befoe being tackled. How much wok did the tackle do while pushing? 3

4 17. (2) T F Fiction foces always do negative wok. 18. (2) T F A ca can acceleate faste if the fiction between the oad and its ties is smalle. 19. (2) T F The gavitational foce does positive wok on a ising object. 20. (2) T F Potential enegy stoed in spings is always negative. 21. (2) T F When ascending a flight of stais, you gavitational potential enegy deceases. 22. (2) A foce F acting though a displacement d does negative wok when a. F is paallel to d. b. F is pependicula to d. c. F is anti-paallel to d. 23. (18) A 2200-kg ca is initially coasting at a speed of 24 m/s when it comes to a θ = 12.0 incline. It coasts without fiction o ai esistance, up the incline. a) (6) How lage is the initial kinetic enegy of the ca, in kj? b) (6) Afte it tavels 75.0 m along the incline, how lage is the gavitational potential enegy of the ca, in kj? Take the zeo of PE to be at the bottom of the incline. c) (6) How fast is the ca coasting now afte it went 75.0 m along the incline? 24. (8) A 62-kg athlete uns up a flight of stais at constant speed, gaining an elevation of 50.0 m in 40.0 s. What was the aveage mechanical powe output of he body, in watts? Scoe = /132. 4

5 Pefixes a=10 18, f=10 15, p=10 12, n=10 9, µ = 10 6, m=10 3, c=10 2, k=10 3, M=10 6, G=10 9, T=10 12, P=10 15 Physical Constants g = 9.80 m/s 2 (gavitational acceleation) M E = kg (mass of Eath) m e = kg (electon mass) c = m/s (speed of light) G = N m 2 /kg 2 (Gavitational constant) R E = 6380 km (mean adius of Eath) m p = kg (poton mass) Units and Convesions 1 inch = 1 in = 2.54 cm (exactly) 1 foot = 1 ft = 12 in = cm (exactly) 1 mile = 5280 ft 1 mile = m = km 1 m/s = 3.6 km/hou 1 ft/s = mile/hou 1 ace = ft 2 = (1 mile) 2 /640 1 hectae = 10 4 m 2 Tig summay sin θ = (opp) (hyp), (adj) cos θ = (hyp), (opp) tan θ = (adj), (opp)2 + (adj) 2 = (hyp) 2. sin θ = sin(180 θ), cos θ = cos( θ), tan θ = tan(180 + θ), sin 2 θ + cos 2 θ = 1. Chapte 1 Equations Pecent eo: If a measuement = value ± eo, the pecent eo = eo value 100 %. Chapte 2 Equations Motion: v = x t, x = x x 0, slope of x(t) cuve = v(t). ā = v t, v = v v 0, slope of v(t) cuve = a(t). Fo constant acceleation in one-dimension: v = 1 2 (v 0 + v), v = v 0 + at, x = x 0 + v 0 t at2, v 2 = v a(x x 0 ). Fo fee fall on Eath, using an upwad y-axis, with g = 9.80 m/s 2 downwad: v y = 1 2 (v y0 + v y ), v y = v y0 gt, y = y 0 + v y0 t 1 2 gt2, v 2 y = v 2 y0 2g y. Chapte 3 Equations Vectos Witten V o V, descibed by magnitude=v, diection=θ o by components (V x, V y ). V x = V cos θ, V y = V sin θ, V = Vx 2 + V 2 tan θ = Vy θ is the angle fom V to x-axis. y, V x. Addition: A + B, head to tail. Subtaction: A B is A + ( B), B is B evesed. Pojectiles a x = 0, v x = v x0, x = x 0 + v x0 t. Fo a hoizontal x-axis. a y = g, v y = v y0 gt, y = y 0 + v y0 t 1 2 gt2. Fo an upwad y-axis. R = v2 0 g sin 2θ 0, Relative Motion V BS = V BW + V WS, (Fo level gound only.) B=Boat, S=Shoe, W=Wate. BS means boat elative to shoe, etc. Must be applied as a vecto equation! 5

6 Chapte 4 Equations Newton s Second Law: F net = m a, means ΣF x = ma x and ΣF y = ma y. Fnet = Fi, sum ove all foces on a mass. Fiction (magnitude): f s µ s N o F f µ s F N (static fiction). f k = µ k N o F f = µ k F N. (kinetic o sliding fiction) Gavitational foce nea Eath: F G = mg, downwad. Chapte 5 Equations Centipetal Acceleation: a R = v2, towads the cente of the cicle. Cicula motion: speed v = 2π T = 2πf, fequency f = 1 T, whee T is the peiod of one evolution. Gavitation: F = G m1m2 ; 2 g = GM, 2 whee G = Nm 2 /kg 2 ; Obits: v 2 = g = GM 2 ; v = Chapte 6 Equations GM. centipetal acceleation = fee fall acceleation. Wok & Kinetic & Potential Enegies: W = F d cos θ, KE = 1 2 mv2, PE gavity = mgy, PE sping = 1 2 kx2. θ = angle btwn F and d. Consevation o Tansfomation of Enegy: Wok-KE theoem: KE = W net = wok of all foces. Powe: P ave = W t, o use P ave = enegy time. Geneal enegy-consevation law: KE + PE = W NC = wok of non-consevative foces. 6

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed?

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 10, 2012 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

b) (5) What average force magnitude was applied by the students working together?

b) (5) What average force magnitude was applied by the students working together? Geneal Physics I Exam 3 - Chs. 7,8,9 - Momentum, Rotation, Equilibium Nov. 3, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults

More information

PHYS 1114, Lecture 21, March 6 Contents:

PHYS 1114, Lecture 21, March 6 Contents: PHYS 1114, Lectue 21, Mach 6 Contents: 1 This class is o cially cancelled, being eplaced by the common exam Tuesday, Mach 7, 5:30 PM. A eview and Q&A session is scheduled instead duing class time. 2 Exam

More information

Chapter 5: Uniform Circular Motion

Chapter 5: Uniform Circular Motion Chapte 5: Unifom Cicula Motion Motion at constant speed in a cicle Centipetal acceleation Banked cuves Obital motion Weightlessness, atificial gavity Vetical cicula motion Centipetal Foce Acceleation towad

More information

PS113 Chapter 5 Dynamics of Uniform Circular Motion

PS113 Chapter 5 Dynamics of Uniform Circular Motion PS113 Chapte 5 Dynamics of Unifom Cicula Motion 1 Unifom cicula motion Unifom cicula motion is the motion of an object taveling at a constant (unifom) speed on a cicula path. The peiod T is the time equied

More information

Physics 111 Lecture 5 Circular Motion

Physics 111 Lecture 5 Circular Motion Physics 111 Lectue 5 Cicula Motion D. Ali ÖVGÜN EMU Physics Depatment www.aovgun.com Multiple Objects q A block of mass m1 on a ough, hoizontal suface is connected to a ball of mass m by a lightweight

More information

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet Linea and angula analogs Linea Rotation x position x displacement v velocity a T tangential acceleation Vectos in otational motion Use the ight hand ule to detemine diection of the vecto! Don t foget centipetal

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion Intoduction Ealie we defined acceleation as being the change in velocity with time: a = v t Until now we have only talked about changes in the magnitude of the acceleation: the speeding

More information

Physics 4A Chapter 8: Dynamics II Motion in a Plane

Physics 4A Chapter 8: Dynamics II Motion in a Plane Physics 4A Chapte 8: Dynamics II Motion in a Plane Conceptual Questions and Example Poblems fom Chapte 8 Conceptual Question 8.5 The figue below shows two balls of equal mass moving in vetical cicles.

More information

DYNAMICS OF UNIFORM CIRCULAR MOTION

DYNAMICS OF UNIFORM CIRCULAR MOTION Chapte 5 Dynamics of Unifom Cicula Motion Chapte 5 DYNAMICS OF UNIFOM CICULA MOTION PEVIEW An object which is moing in a cicula path with a constant speed is said to be in unifom cicula motion. Fo an object

More information

Chapter 5. Uniform Circular Motion. a c =v 2 /r

Chapter 5. Uniform Circular Motion. a c =v 2 /r Chapte 5 Unifom Cicula Motion a c =v 2 / Unifom cicula motion: Motion in a cicula path with constant speed s v 1) Speed and peiod Peiod, T: time fo one evolution Speed is elated to peiod: Path fo one evolution:

More information

Quiz 6--Work, Gravitation, Circular Motion, Torque. (60 pts available, 50 points possible)

Quiz 6--Work, Gravitation, Circular Motion, Torque. (60 pts available, 50 points possible) Name: Class: Date: ID: A Quiz 6--Wok, Gavitation, Cicula Motion, Toque. (60 pts available, 50 points possible) Multiple Choice, 2 point each Identify the choice that best completes the statement o answes

More information

Chapter 8. Accelerated Circular Motion

Chapter 8. Accelerated Circular Motion Chapte 8 Acceleated Cicula Motion 8.1 Rotational Motion and Angula Displacement A new unit, adians, is eally useful fo angles. Radian measue θ(adians) = s = θ s (ac length) (adius) (s in same units as

More information

Describing Circular motion

Describing Circular motion Unifom Cicula Motion Descibing Cicula motion In ode to undestand cicula motion, we fist need to discuss how to subtact vectos. The easiest way to explain subtacting vectos is to descibe it as adding a

More information

Midterm Exam #2, Part A

Midterm Exam #2, Part A Physics 151 Mach 17, 2006 Midtem Exam #2, Pat A Roste No.: Scoe: Exam time limit: 50 minutes. You may use calculatos and both sides of ONE sheet of notes, handwitten only. Closed book; no collaboation.

More information

Physics 101 Lecture 6 Circular Motion

Physics 101 Lecture 6 Circular Motion Physics 101 Lectue 6 Cicula Motion Assist. Pof. D. Ali ÖVGÜN EMU Physics Depatment www.aovgun.com Equilibium, Example 1 q What is the smallest value of the foce F such that the.0-kg block will not slide

More information

to point uphill and to be equal to its maximum value, in which case f s, max = μsfn

to point uphill and to be equal to its maximum value, in which case f s, max = μsfn Chapte 6 16. (a) In this situation, we take f s to point uphill and to be equal to its maximum value, in which case f s, max = μsf applies, whee μ s = 0.5. pplying ewton s second law to the block of mass

More information

Hoizontal Cicula Motion 1. A paticle of mass m is tied to a light sting and otated with a speed v along a cicula path of adius. If T is tension in the sting and mg is gavitational foce on the paticle then,

More information

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer.

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer. Kiangsu-Chekiang College (Shatin) F:EasteHolidaysAssignmentAns.doc Easte Holidays Assignment Answe Fom 6B Subject: Physics. (a) State the conditions fo a body to undego simple hamonic motion. ( mak) (a)

More information

PHYSICS 220. Lecture 08. Textbook Sections Lecture 8 Purdue University, Physics 220 1

PHYSICS 220. Lecture 08. Textbook Sections Lecture 8 Purdue University, Physics 220 1 PHYSICS 0 Lectue 08 Cicula Motion Textbook Sections 5.3 5.5 Lectue 8 Pudue Univesity, Physics 0 1 Oveview Last Lectue Cicula Motion θ angula position adians ω angula velocity adians/second α angula acceleation

More information

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session.

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session. - 5 - TEST 1R This is the epeat vesion of TEST 1, which was held duing Session. This epeat test should be attempted by those students who missed Test 1, o who wish to impove thei mak in Test 1. IF YOU

More information

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature)

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature) a = c v 2 Recap Centipetal acceleation: m/s 2 (towads cente of cuvatue) A centipetal foce F c is equied to keep a body in cicula motion: This foce poduces centipetal acceleation that continuously changes

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion constant speed Pick a point in the objects motion... What diection is the velocity? HINT Think about what diection the object would tavel if the sting wee cut Unifom Cicula Motion

More information

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK.

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK. AP Physics C Sping, 2017 Cicula-Rotational Motion Mock Exam Name: Answe Key M. Leonad Instuctions: (92 points) Answe the following questions. SHOW ALL OF YOUR WORK. ( ) 1. A stuntman dives a motocycle

More information

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s 1. A stone falls fom a platfom 18 m high. When will it hit the gound? (a) 1.74 s (b) 1.83 s (c) 1.9 s (d).01 s Constant acceleation D = v 0 t + ½ a t. Which, if any, of these foces causes the otation of

More information

Motion in Two Dimensions

Motion in Two Dimensions SOLUTIONS TO PROBLEMS Motion in Two Dimensions Section 3.1 The Position, Velocity, and Acceleation Vectos P3.1 x( m) 0!3 000!1 70!4 70 m y( m)!3 600 0 1 70! 330 m (a) Net displacement x + y 4.87 km at

More information

Potential Energy and Conservation of Energy

Potential Energy and Conservation of Energy Potential Enegy and Consevation of Enegy Consevative Foces Definition: Consevative Foce If the wok done by a foce in moving an object fom an initial point to a final point is independent of the path (A

More information

AP Physics 1 - Circular Motion and Gravitation Practice Test (Multiple Choice Section) Answer Section

AP Physics 1 - Circular Motion and Gravitation Practice Test (Multiple Choice Section) Answer Section AP Physics 1 - Cicula Motion and Gaitation Pactice est (Multiple Choice Section) Answe Section MULIPLE CHOICE 1. B he centipetal foce must be fiction since, lacking any fiction, the coin would slip off.

More information

Physics 1114: Unit 5 Hand-out Homework (Answers)

Physics 1114: Unit 5 Hand-out Homework (Answers) Physics 1114: Unit 5 Hand-out Homewok (Answes) Poblem set 1 1. The flywheel on an expeimental bus is otating at 420 RPM (evolutions pe minute). To find (a) the angula velocity in ad/s (adians/second),

More information

Conflict Exam Issue. Sorry, Can t do it. Please see Kevin Pitts if you have any additional questions or concerns about this. Office is 231 Loomis

Conflict Exam Issue. Sorry, Can t do it. Please see Kevin Pitts if you have any additional questions or concerns about this. Office is 231 Loomis Conflict Exam Issue. Soy, Can t do it I was told that: Students can only be excused fom the scheduled final fo illness, death in the family o eligious holiday. No exceptions. Please see Kevin Pitts if

More information

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and Exta notes fo cicula motion: Cicula motion : v keeps changing, maybe both speed and diection ae changing. At least v diection is changing. Hence a 0. Acceleation NEEDED to stay on cicula obit: a cp v /,

More information

Chapter 1: Mathematical Concepts and Vectors

Chapter 1: Mathematical Concepts and Vectors Chapte : Mathematical Concepts and Vectos giga G 9 mega M 6 kilo k 3 centi c - milli m -3 mico μ -6 nano n -9 in =.54 cm m = cm = 3.8 t mi = 58 t = 69 m h = 36 s da = 86,4 s ea = 365.5 das You must know

More information

PHYS Summer Professor Caillault Homework Solutions. Chapter 5

PHYS Summer Professor Caillault Homework Solutions. Chapter 5 PHYS 1111 - Summe 2007 - Pofesso Caillault Homewok Solutions Chapte 5 7. Pictue the Poblem: The ball is acceleated hoizontally fom est to 98 mi/h ove a distance of 1.7 m. Stategy: Use equation 2-12 to

More information

Objective Notes Summary

Objective Notes Summary Objective Notes Summay An object moving in unifom cicula motion has constant speed but not constant velocity because the diection is changing. The velocity vecto in tangent to the cicle, the acceleation

More information

CHAPTER 5: Circular Motion; Gravitation

CHAPTER 5: Circular Motion; Gravitation CHAPER 5: Cicula Motion; Gavitation Solution Guide to WebAssign Pobles 5.1 [1] (a) Find the centipetal acceleation fo Eq. 5-1.. a R v ( 1.5 s) 1.10 1.4 s (b) he net hoizontal foce is causing the centipetal

More information

Physics 107 TUTORIAL ASSIGNMENT #8

Physics 107 TUTORIAL ASSIGNMENT #8 Physics 07 TUTORIAL ASSIGNMENT #8 Cutnell & Johnson, 7 th edition Chapte 8: Poblems 5,, 3, 39, 76 Chapte 9: Poblems 9, 0, 4, 5, 6 Chapte 8 5 Inteactive Solution 8.5 povides a model fo solving this type

More information

Centripetal Force. Lecture 11. Chapter 8. Course website:

Centripetal Force. Lecture 11. Chapter 8. Course website: Lectue 11 Chapte 8 Centipetal Foce Couse website: http://faculty.uml.edu/andiy_danylov/teaching/physicsi PHYS.1410 Lectue 11 Danylov Depatment of Physics and Applied Physics Today we ae going to discuss:

More information

Spring 2001 Physics 2048 Test 3 solutions

Spring 2001 Physics 2048 Test 3 solutions Sping 001 Physics 048 Test 3 solutions Poblem 1. (Shot Answe: 15 points) a. 1 b. 3 c. 4* d. 9 e. 8 f. 9 *emembe that since KE = ½ mv, KE must be positive Poblem (Estimation Poblem: 15 points) Use momentum-impulse

More information

Momentum is conserved if no external force

Momentum is conserved if no external force Goals: Lectue 13 Chapte 9 v Employ consevation of momentum in 1 D & 2D v Examine foces ove time (aka Impulse) Chapte 10 v Undestand the elationship between motion and enegy Assignments: l HW5, due tomoow

More information

PHYSICS 1210 Exam 2 University of Wyoming 14 March ( Day!) points

PHYSICS 1210 Exam 2 University of Wyoming 14 March ( Day!) points PHYSICS 1210 Exam 2 Univesity of Wyoming 14 Mach ( Day!) 2013 150 points This test is open-note and closed-book. Calculatos ae pemitted but computes ae not. No collaboation, consultation, o communication

More information

Physics Fall Mechanics, Thermodynamics, Waves, Fluids. Lecture 6: motion in two and three dimensions III. Slide 6-1

Physics Fall Mechanics, Thermodynamics, Waves, Fluids. Lecture 6: motion in two and three dimensions III. Slide 6-1 Physics 1501 Fall 2008 Mechanics, Themodynamics, Waves, Fluids Lectue 6: motion in two and thee dimensions III Slide 6-1 Recap: elative motion An object moves with velocity v elative to one fame of efeence.

More information

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once.

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once. Honos Physics Fall, 2016 Cicula Motion & Toque Test Review Name: M. Leonad Instuctions: Complete the following woksheet. SHOW ALL OF YOUR WORK ON A SEPARATE SHEET OF PAPER. 1. Detemine whethe each statement

More information

Physics 201 Homework 4

Physics 201 Homework 4 Physics 201 Homewok 4 Jan 30, 2013 1. Thee is a cleve kitchen gadget fo dying lettuce leaves afte you wash them. 19 m/s 2 It consists of a cylindical containe mounted so that it can be otated about its

More information

OSCILLATIONS AND GRAVITATION

OSCILLATIONS AND GRAVITATION 1. SIMPLE HARMONIC MOTION Simple hamonic motion is any motion that is equivalent to a single component of unifom cicula motion. In this situation the velocity is always geatest in the middle of the motion,

More information

Sections and Chapter 10

Sections and Chapter 10 Cicula and Rotational Motion Sections 5.-5.5 and Chapte 10 Basic Definitions Unifom Cicula Motion Unifom cicula motion efes to the motion of a paticle in a cicula path at constant speed. The instantaneous

More information

Chapter 5. really hard to start the object moving and then, once it starts moving, you don t have to push as hard to keep it moving.

Chapter 5. really hard to start the object moving and then, once it starts moving, you don t have to push as hard to keep it moving. Chapte 5 Fiction When an object is in motion it is usually in contact with a viscous mateial (wate o ai) o some othe suface. So fa, we have assumed that moving objects don t inteact with thei suoundings

More information

Physics 2001 Problem Set 5 Solutions

Physics 2001 Problem Set 5 Solutions Physics 2001 Poblem Set 5 Solutions Jeff Kissel Octobe 16, 2006 1. A puck attached to a sting undegoes cicula motion on an ai table. If the sting beaks at the point indicated in the figue, which path (A,

More information

Physics 11 Chapter 3: Vectors and Motion in Two Dimensions. Problem Solving

Physics 11 Chapter 3: Vectors and Motion in Two Dimensions. Problem Solving Physics 11 Chapte 3: Vectos and Motion in Two Dimensions The only thing in life that is achieved without effot is failue. Souce unknown "We ae what we epeatedly do. Excellence, theefoe, is not an act,

More information

ω = θ θ o = θ θ = s r v = rω

ω = θ θ o = θ θ = s r v = rω Unifom Cicula Motion Unifom cicula motion is the motion of an object taveling at a constant(unifom) speed in a cicula path. Fist we must define the angula displacement and angula velocity The angula displacement

More information

Exam 3: Equation Summary

Exam 3: Equation Summary MAACHUETT INTITUTE OF TECHNOLOGY Depatment of Physics Physics 8. TEAL Fall Tem 4 Momentum: p = mv, F t = p, Fext ave t= t f t = Exam 3: Equation ummay = Impulse: I F( t ) = p Toque: τ =,P dp F P τ =,P

More information

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j.

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j. 7. We denote the two foces F A + F B = ma,sof B = ma F A. (a) In unit vecto notation F A = ( 20.0 N)ˆ i and Theefoe, Phys 201A Homewok 6 Solutions F A and F B. Accoding to Newton s second law, a = [ (

More information

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N Chapte answes Heinemann Physics 4e Section. Woked example: Ty youself.. GRAVITATIONAL ATTRACTION BETWEEN SMALL OBJECTS Two bowling balls ae sitting next to each othe on a shelf so that the centes of the

More information

= 4 3 π( m) 3 (5480 kg m 3 ) = kg.

= 4 3 π( m) 3 (5480 kg m 3 ) = kg. CHAPTER 11 THE GRAVITATIONAL FIELD Newton s Law of Gavitation m 1 m A foce of attaction occus between two masses given by Newton s Law of Gavitation Inetial mass and gavitational mass Gavitational potential

More information

Chap 5. Circular Motion: Gravitation

Chap 5. Circular Motion: Gravitation Chap 5. Cicula Motion: Gavitation Sec. 5.1 - Unifom Cicula Motion A body moves in unifom cicula motion, if the magnitude of the velocity vecto is constant and the diection changes at evey point and is

More information

A car of mass m, traveling at constant speed, rides over the top of a circularly shaped hill as shown.

A car of mass m, traveling at constant speed, rides over the top of a circularly shaped hill as shown. A ca of mass m, taveling at constant speed, ides ove the top of a ciculaly shaped hill as shown. The magnitude of the nomal foce N of the oad on the ca is. A) Geate than the weight of the ca, N > mg. B)

More information

Physics 181. Assignment 4

Physics 181. Assignment 4 Physics 181 Assignment 4 Solutions 1. A sphee has within it a gavitational field given by g = g, whee g is constant and is the position vecto of the field point elative to the cente of the sphee. This

More information

Kinematics in 2-D (II)

Kinematics in 2-D (II) Kinematics in 2-D (II) Unifom cicula motion Tangential and adial components of Relative velocity and acceleation a Seway and Jewett 4.4 to 4.6 Pactice Poblems: Chapte 4, Objective Questions 5, 11 Chapte

More information

Chapter 5 Force and Motion

Chapter 5 Force and Motion Chapte 5 Foce and Motion In Chaptes 2 and 4 we have studied kinematics, i.e., we descibed the motion of objects using paametes such as the position vecto, velocity, and acceleation without any insights

More information

Chapter 5 Force and Motion

Chapter 5 Force and Motion Chapte 5 Foce and Motion In chaptes 2 and 4 we have studied kinematics i.e. descibed the motion of objects using paametes such as the position vecto, velocity and acceleation without any insights as to

More information

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE.

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE. Unit 6 actice Test 1. Which one of the following gaphs best epesents the aiation of the kinetic enegy, KE, and of the gaitational potential enegy, GE, of an obiting satellite with its distance fom the

More information

21 MAGNETIC FORCES AND MAGNETIC FIELDS

21 MAGNETIC FORCES AND MAGNETIC FIELDS CHAPTER 1 MAGNETIC ORCES AND MAGNETIC IELDS ANSWERS TO OCUS ON CONCEPTS QUESTIONS 1. (d) Right-Hand Rule No. 1 gives the diection of the magnetic foce as x fo both dawings A and. In dawing C, the velocity

More information

Exam 3: Equation Summary

Exam 3: Equation Summary MAACHUETT INTITUTE OF TECHNOLOGY Depatment of Physics Physics 8. TEAL Fall Tem 4 Momentum: p = mv, F t = p, Fext ave t= t f t = Exam 3: Equation ummay = Impulse: I F( t ) = p Toque: τ =,P dp F P τ =,P

More information

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11.

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11. NSWRS - P Physics Multiple hoice Pactice Gavitation Solution nswe 1. m mv Obital speed is found fom setting which gives v whee M is the object being obited. Notice that satellite mass does not affect obital

More information

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b,

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b, SAMPLE QUIZ 3 - PHYSICS 1301.1 his is a closed book, closed notes quiz. Calculatos ae pemitted. he ONLY fomulas that may be used ae those given below. Define all symbols and justify all mathematical expessions

More information

PHYSICS 1050 Mid-term Test 1 University of Wyoming 8 February 2007

PHYSICS 1050 Mid-term Test 1 University of Wyoming 8 February 2007 Name: PHYSICS 1050 Mid-tem Test 1 Univesity of Wyoming 8 Febuay 2007 This test is open-note and open-book. This means that any efeence mateial is pemitted duing the test. Calculatos also ae pemitted. Howeve,

More information

Between any two masses, there exists a mutual attractive force.

Between any two masses, there exists a mutual attractive force. YEAR 12 PHYSICS: GRAVITATION PAST EXAM QUESTIONS Name: QUESTION 1 (1995 EXAM) (a) State Newton s Univesal Law of Gavitation in wods Between any two masses, thee exists a mutual attactive foce. This foce

More information

Chapter 4: The laws of motion. Newton s first law

Chapter 4: The laws of motion. Newton s first law Chapte 4: The laws of motion gavitational Electic magnetic Newton s fist law If the net foce exeted on an object is zeo, the object continues in its oiginal state of motion: - an object at est, emains

More information

Chapter 13 Gravitation

Chapter 13 Gravitation Chapte 13 Gavitation In this chapte we will exploe the following topics: -Newton s law of gavitation, which descibes the attactive foce between two point masses and its application to extended objects

More information

Circular Motion. Mr. Velazquez AP/Honors Physics

Circular Motion. Mr. Velazquez AP/Honors Physics Cicula Motion M. Velazquez AP/Honos Physics Objects in Cicula Motion Accoding to Newton s Laws, if no foce acts on an object, it will move with constant speed in a constant diection. Theefoe, if an object

More information

Rotational Motion: Statics and Dynamics

Rotational Motion: Statics and Dynamics Physics 07 Lectue 17 Goals: Lectue 17 Chapte 1 Define cente of mass Analyze olling motion Intoduce and analyze toque Undestand the equilibium dynamics of an extended object in esponse to foces Employ consevation

More information

2013 Checkpoints Chapter 6 CIRCULAR MOTION

2013 Checkpoints Chapter 6 CIRCULAR MOTION 013 Checkpoints Chapte 6 CIRCULAR MOTIO Question 09 In unifom cicula motion, thee is a net foce acting adially inwads. This net foce causes the elocity to change (in diection). Since the speed is constant,

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion Have you eve idden on the amusement pak ide shown below? As it spins you feel as though you ae being pessed tightly against the wall. The ide then begins to tilt but you emain glued

More information

Objectives: After finishing this unit you should be able to:

Objectives: After finishing this unit you should be able to: lectic Field 7 Objectives: Afte finishing this unit you should be able to: Define the electic field and explain what detemines its magnitude and diection. Wite and apply fomulas fo the electic field intensity

More information

kg 2 ) 1.9!10 27 kg = Gm 1

kg 2 ) 1.9!10 27 kg = Gm 1 Section 6.1: Newtonian Gavitation Tutoial 1 Pactice, page 93 1. Given: 1.0 10 0 kg; m 3.0 10 0 kg;. 10 9 N; G 6.67 10 11 N m /kg Requied: Analysis: G m ; G m G m Solution: G m N m 6.67!10 11 kg ) 1.0!100

More information

AP * PHYSICS B. Circular Motion, Gravity, & Orbits. Teacher Packet

AP * PHYSICS B. Circular Motion, Gravity, & Orbits. Teacher Packet AP * PHYSICS B Cicula Motion, Gavity, & Obits Teache Packet AP* is a tademak of the College Entance Examination Boad. The College Entance Examination Boad was not involved in the poduction of this mateial.

More information

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions )

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions ) 06 - ROTATIONAL MOTION Page ) A body A of mass M while falling vetically downwads unde gavity beaks into two pats, a body B of mass ( / ) M and a body C of mass ( / ) M. The cente of mass of bodies B and

More information

Chapter 5. Applying Newton s Laws. Newton s Laws. r r. 1 st Law: An object at rest or traveling in uniform. 2 nd Law:

Chapter 5. Applying Newton s Laws. Newton s Laws. r r. 1 st Law: An object at rest or traveling in uniform. 2 nd Law: Chapte 5 Applying Newton s Laws Newton s Laws st Law: An object at est o taveling in unifom motion will emain at est o taveling in unifom motion unless and until an extenal foce is applied net ma nd Law:

More information

CIRCULAR MOTION. Particle moving in an arbitrary path. Particle moving in straight line

CIRCULAR MOTION. Particle moving in an arbitrary path. Particle moving in straight line 1 CIRCULAR MOTION 1. ANGULAR DISPLACEMENT Intoduction: Angle subtended by position vecto of a paticle moving along any abitay path w..t. some fixed point is called angula displacement. (a) Paticle moving

More information

( ) ( ) Review of Force. Review of Force. r = =... Example 1. What is the dot product for F r. Solution: Example 2 ( )

( ) ( ) Review of Force. Review of Force. r = =... Example 1. What is the dot product for F r. Solution: Example 2 ( ) : PHYS 55 (Pat, Topic ) Eample Solutions p. Review of Foce Eample ( ) ( ) What is the dot poduct fo F =,,3 and G = 4,5,6? F G = F G + F G + F G = 4 +... = 3 z z Phs55 -: Foce Fields Review of Foce Eample

More information

m1 m2 M 2 = M -1 L 3 T -2

m1 m2 M 2 = M -1 L 3 T -2 GAVITATION Newton s Univesal law of gavitation. Evey paticle of matte in this univese attacts evey othe paticle with a foce which vaies diectly as the poduct of thei masses and invesely as the squae of

More information

Circular Orbits. and g =

Circular Orbits. and g = using analyse planetay and satellite motion modelled as unifom cicula motion in a univesal gavitation field, a = v = 4π and g = T GM1 GM and F = 1M SATELLITES IN OBIT A satellite is any object that is

More information

Gravitation. AP/Honors Physics 1 Mr. Velazquez

Gravitation. AP/Honors Physics 1 Mr. Velazquez Gavitation AP/Honos Physics 1 M. Velazquez Newton s Law of Gavitation Newton was the fist to make the connection between objects falling on Eath and the motion of the planets To illustate this connection

More information

Lecture 22. PE = GMm r TE = GMm 2a. T 2 = 4π 2 GM. Main points of today s lecture: Gravitational potential energy: Total energy of orbit:

Lecture 22. PE = GMm r TE = GMm 2a. T 2 = 4π 2 GM. Main points of today s lecture: Gravitational potential energy: Total energy of orbit: Lectue Main points of today s lectue: Gavitational potential enegy: Total enegy of obit: PE = GMm TE = GMm a Keple s laws and the elation between the obital peiod and obital adius. T = 4π GM a3 Midtem

More information

ΣF = r r v. Question 213. Checkpoints Chapter 6 CIRCULAR MOTION

ΣF = r r v. Question 213. Checkpoints Chapter 6 CIRCULAR MOTION Unit 3 Physics 16 6. Cicula Motion Page 1 of 9 Checkpoints Chapte 6 CIRCULAR MOTION Question 13 Question 8 In unifom cicula motion, thee is a net foce acting adially inwads. This net foce causes the elocity

More information

Principles of Physics I

Principles of Physics I Pinciples of Physics I J. M. Veal, Ph. D. vesion 8.05.24 Contents Linea Motion 3. Two scala equations........................ 3.2 Anothe scala equation...................... 3.3 Constant acceleation.......................

More information

Chapter 7-8 Rotational Motion

Chapter 7-8 Rotational Motion Chapte 7-8 Rotational Motion What is a Rigid Body? Rotational Kinematics Angula Velocity ω and Acceleation α Unifom Rotational Motion: Kinematics Unifom Cicula Motion: Kinematics and Dynamics The Toque,

More information

AH Mechanics Checklist (Unit 2) AH Mechanics Checklist (Unit 2) Circular Motion

AH Mechanics Checklist (Unit 2) AH Mechanics Checklist (Unit 2) Circular Motion AH Mechanics Checklist (Unit ) AH Mechanics Checklist (Unit ) Cicula Motion No. kill Done 1 Know that cicula motion efes to motion in a cicle of constant adius Know that cicula motion is conveniently descibed

More information

Multiple choice questions [100 points] As shown in the figure, a mass M is hanging by three massless strings from the ceiling of a room.

Multiple choice questions [100 points] As shown in the figure, a mass M is hanging by three massless strings from the ceiling of a room. Multiple choice questions [00 points] Answe all of the following questions. Read each question caefully. Fill the coect ule on you scanton sheet. Each coect answe is woth 4 points. Each question has exactly

More information

1121 T Question 1

1121 T Question 1 1121 T1 2008 Question 1 ( aks) You ae cycling, on a long staight path, at a constant speed of 6.0.s 1. Anothe cyclist passes you, tavelling on the sae path in the sae diection as you, at a constant speed

More information

Rotational Motion. Every quantity that we have studied with translational motion has a rotational counterpart

Rotational Motion. Every quantity that we have studied with translational motion has a rotational counterpart Rotational Motion & Angula Momentum Rotational Motion Evey quantity that we have studied with tanslational motion has a otational countepat TRANSLATIONAL ROTATIONAL Displacement x Angula Position Velocity

More information

Objects usually are charged up through the transfer of electrons from one object to the other.

Objects usually are charged up through the transfer of electrons from one object to the other. 1 Pat 1: Electic Foce 1.1: Review of Vectos Review you vectos! You should know how to convet fom pola fom to component fom and vice vesa add and subtact vectos multiply vectos by scalas Find the esultant

More information

ROTATORY MOTION HORIZONTAL AND VERTICAL CIRCULAR MOTION

ROTATORY MOTION HORIZONTAL AND VERTICAL CIRCULAR MOTION ROTATORY MOTION HORIZONTAL AND VERTICAL CIRCULAR MOTION POINTS TO REMEMBER 1. Tanslatoy motion: Evey point in the body follows the path of its peceding one with same velocity including the cente of mass..

More information

PROBLEM (page 126, 12 th edition)

PROBLEM (page 126, 12 th edition) PROBLEM 13-27 (page 126, 12 th edition) The mass of block A is 100 kg. The mass of block B is 60 kg. The coefficient of kinetic fiction between block B and the inclined plane is 0.4. A and B ae eleased

More information

PHYS Summer Professor Caillault Homework Solutions. Chapter 9

PHYS Summer Professor Caillault Homework Solutions. Chapter 9 PHYS - Summe 007 - Pofesso Caillault Homewok Solutions Chapte 9 3. Pictue the Poblem The owne walks slowly towad the notheast while the cat uns eastwad and the dog uns nothwad. Stategy Sum the momenta

More information

Name. Date. Period. Engage Examine the pictures on the left. 1. What is going on in these pictures?

Name. Date. Period. Engage Examine the pictures on the left. 1. What is going on in these pictures? AP Physics 1 Lesson 9.a Unifom Cicula Motion Outcomes 1. Define unifom cicula motion. 2. Detemine the tangential velocity of an object moving with unifom cicula motion. 3. Detemine the centipetal acceleation

More information

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun Chapte 12 Gavitation PowePoint Lectues fo Univesity Physics, Twelfth Edition Hugh D. Young and Roge A. Feedman Lectues by James Pazun Modified by P. Lam 5_31_2012 Goals fo Chapte 12 To study Newton s Law

More information

Ch 13 Universal Gravitation

Ch 13 Universal Gravitation Ch 13 Univesal Gavitation Ch 13 Univesal Gavitation Why do celestial objects move the way they do? Keple (1561-1630) Tycho Bahe s assistant, analyzed celestial motion mathematically Galileo (1564-1642)

More information

Easy. P4.2 Since the car is moving with constant speed and in a straight line, the. resultant force on it must be regardless of whether it is moving

Easy. P4.2 Since the car is moving with constant speed and in a straight line, the. resultant force on it must be regardless of whether it is moving Chapte 4 Homewok Solutions Easy P4. Since the ca is moving with constant speed and in a staight line, the zeo esultant foce on it must be egadless of whethe it is moving (a) towad the ight o the left.

More information

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9 SPH4 nit 6.3 Gavitational Potential negy Page of Notes Physics ool box he gavitational potential enegy of a syste of two (spheical) asses is diectly popotional to the poduct of thei asses, and invesely

More information

Phys 201A. Homework 5 Solutions

Phys 201A. Homework 5 Solutions Phys 201A Homewok 5 Solutions 3. In each of the thee cases, you can find the changes in the velocity vectos by adding the second vecto to the additive invese of the fist and dawing the esultant, and by

More information