Reinforced Concrete Structures/Design Aids
|
|
- Amanda Nelson
- 5 years ago
- Views:
Transcription
1 AREA OF BARS (mm 2 ) Reinforced Concrete Structures/Design Aids Size of s (mm) Number of s * Available troug special request. MINIMUM BEAM WIDTH (mm) ACCORDING TO THE ACI CODE Size of Bars (mm) Number of s Add for eac added Table sows minimum beam widts wen φ10 stirrups are used. For additional s, add dimension in last column for eac added. For s of different sizes, determine from te table te beam widt for smaller size s and ten add last column figure for eac larger used. Assume maximum aggregate size does not exceed tree-fort of te clear space between s (ACI-3-3.3). Table computation procedure is in agreement wit te ACI code interpretation of te ACI Committee 340. A B C D A = 40 mm clear cover to stirrups B = 10 mm stirrup diameter C = use twice te diameter of φ10 stirrups. D = clear distance between s = d b or 25.4 mm, wicever is greater (were d b is te diameter of te larger adjacent longitudinal ) Dr. Hazim Dwairi/Hasemite University Page 1
2 Development Lengt of Straigt Bars and Standard Hooks For deformed s, ACI Section defines te development lengt ld given in te table below. Note tat ld sall not be less tan 300 mm. Case f20 > f20 Case 1: Clear spacing of s being developed not less tan db, clear cover not less tan db, and stirrups trougout ld not less tan code minimum or Case 2: Clear spacing of s being developed not less tan 2db and clear cover not less tan db l 12 f ψ ψ λ 12 f ψ ψ λ y t e y t e d = db ld = d b ' ' 25 fc 20 f c Oter cases l d 18 f ψ ψ λ 18 f ψ ψ λ y t e y t e = d b ld = d b ' ' 25 f c 20 f c Te terms in te foregoing equations are as follows: ψ t = reinforcement location factor Horizontal reinforcement so placed tat more tan 300 mm of fres concrete is cast in te member below te development lengt Oter reinforcement ψ e = coating factor Epoxy-coated s wit cover less tan 3db, or clear spacing less tan 6db All oter epoxy-coated s Uncoated reinforcement λ = ligtweigt aggregate concrete factor Wen all-ligtweigt aggregate concrete is used Wen sand-ligtweigt aggregate concrete is used Normal weigt concrete is used Dr. Hazim Dwairi/Hasemite University Page 2
3 Table 1: Basic tension development-lengt ratio, l d /d b (mm/mm) ldb ld = ψ eλ d b, but not less tan 300 mm d Bar size (mm) b f c = 21 MPa f c = 25 MPa f c = 28 MPa f c = 30 MPa f c = 35 MPa Bottom Top Bottom Top Bottom Top Bottom Top Bottom Top Case 1: Clear spacing of s being developed not less tan db, clear cover not less tan db, and stirrups trougout ld not less tan code minimum, or Case 2: Clear spacing of s being developed not less tan 2db and clear cover not less tan db f y = 420 MPa, uncoated s, normal weigt concrete f > f f y = 300 MPa, uncoated s, normal weigt concrete f Oter Cases: f > f f y = 300 MPa, uncoated s, normal weigt concrete f For top s, more tan 300 mm of fres concrete is cast in te member (i.e. α = 1.3) β is te coating factor, and λ is te ligtweigt concrete factor Wen tere is insufficient lengt available to develop a straigt, standard ooks are used. Te standard 90 degree ook is sown below: φ10 to φ25: R = 3d b φ28 to φ32: R = 4d b φ28 to φ50: R = 5d b Dr. Hazim Dwairi/Hasemite University Page 3
4 Te development lengt of a ook, l d, is given by te following equation. Note tat te development lengt sall not be less tan 8db nor less tan 150mm: l d 0.24 f yψ = ' f c e λ d b 8db larger of 150mm were ψ e = te coating factor = 1.2 for epoxy coated s and 1.0 for uncoated reinforcement, and λ is te ligtweigt aggregate factor = 1.3 for ligtweigt aggregate concrete. For oter cases ψ e and λ, sall be taken as 1.0 Standard Hooks ACI sections 7.1 and Ld db Ld db R R 2R 12db o 90 Hook 4db or 65 mm o 180 Hook φ10 to φ25: R = 3d b φ28 and φ32: R = 4d b φ50: R = 5d b Stirrups and tie ooks ACI section φ16 and smaller: 6db φ18 to φ25: 12db φ25 and smaller: 6db R R R R Beam C L Beam C L R R o 90 Stirrup Hooks o 135 Stirrup Hooks φ16 & smaller: R = 2d b φ18 to φ25: R = 4d b Dr. Hazim Dwairi/Hasemite University Page 4
5 Requirements for structural integrity in spandrel beams Requirements for structural integrity in interior beams Dr. Hazim Dwairi/Hasemite University Page 5
6 ACI Moment and Sear Coefficients M u = C m (w u l n 2 ) ; C m : moment envelope coefficient V u = C v (w u l n /2) ; C v : sear envelope coefficient Were w u is total factored load and l n is clear span Discontinuous End End Span Interior Spans Interior face of exterior support (a) Terminology Exterior face of first interior support C m = -1/9 if only two spans Oter faces of interior supports C m = C v = 0.0 1/11-1/10-1/11-1/16-1/11-1/ Eq Eq (b) Discontinuous end unrestrained C m = -1/9 if only two spans C m = C v = -1/24 1/14-1/10-1/11 1/16-1/11-1/ Eq Eq (c) Discontinuous end integral wit support were support is spandrel beam C m = -1/9 if only two spans C m = C v = -1/16 1/14-1/10-1/11 1/16-1/11-1/ Eq Eq (d) Discontinuous end integral wit support were support is a column 0.25wLu Eq. 1: C = v l arger of (0.15) or, were w Lu is factored live wu Dr. Hazim Dwairi/Hasemite University Page 6
7 Dr. Hazim Dwairi/Hasemite University Page 7
8 Instantaneous Deflection Calculations: Δ = 5 48 M a is te support moment for cantilevers and te midspan moment (wen K is so defined) for simple and continuous beams. Long-term Deflection: Δ = (Δ ) = 1+50 ξ = t = 3 monts ξ = t = 6 monts ξ = t = one year ξ = t > 5 years Dr. Hazim Dwairi/Hasemite University Page 8
9 Direct Design Metod (DDM) Two-way Slabs Total Static Moment = M = o w u l 8 l 2 2 n Dr. Hazim Dwairi/Hasemite University Page 9
10 Total static moment distribution Dr. Hazim Dwairi/Hasemite University Page 10
11 Dr. Hazim Dwairi/Hasemite University Page 11
12 Rectangular Column Interaction Diagrams Dr. Hazim Dwairi/Hasemite University Page 12
13 Dr. Hazim Dwairi/Hasemite University Page 13
14 Dr. Hazim Dwairi/Hasemite University Page 14
15 Circular Column Interaction Diagrams Dr. Hazim Dwairi/Hasemite University Page 15
16 Dr. Hazim Dwairi/Hasemite University Page 16
6. Non-uniform bending
. Non-uniform bending Introduction Definition A non-uniform bending is te case were te cross-section is not only bent but also seared. It is known from te statics tat in suc a case, te bending moment in
More informationLecture 7 Two-Way Slabs
Lecture 7 Two-Way Slabs Two-way slabs have tension reinforcing spanning in BOTH directions, and may take the general form of one of the following: Types of Two-Way Slab Systems Lecture 7 Page 1 of 13 The
More information232 Calculus and Structures
3 Calculus and Structures CHAPTER 17 JUSTIFICATION OF THE AREA AND SLOPE METHODS FOR EVALUATING BEAMS Calculus and Structures 33 Copyrigt Capter 17 JUSTIFICATION OF THE AREA AND SLOPE METHODS 17.1 THE
More informationNCCI: Simple methods for second order effects in portal frames
NCC: Simple metods for second order effects in portal frames NCC: Simple metods for second order effects in portal frames NCC: Simple metods for second order effects in portal frames Tis NCC presents information
More informationCE5510 Advanced Structural Concrete Design - Design & Detailing of Openings in RC Flexural Members-
CE5510 Advanced Structural Concrete Design - Design & Detailing Openings in RC Flexural Members- Assoc Pr Tan Kiang Hwee Department Civil Engineering National In this lecture DEPARTMENT OF CIVIL ENGINEERING
More informationLecture-05 Serviceability Requirements & Development of Reinforcement
Lecture-05 Serviceability Requirements & Development of Reinforcement By: Prof Dr. Qaisar Ali Civil Engineering Department UET Peshawar drqaisarali@uetpeshawar.edu.pk www.drqaisarali.com 1 Section 1: Deflections
More informationFigure 1: Representative strip. = = 3.70 m. min. per unit length of the selected strip: Own weight of slab = = 0.
Example (8.1): Using the ACI Code approximate structural analysis, design for a warehouse, a continuous one-way solid slab supported on beams 4.0 m apart as shown in Figure 1. Assume that the beam webs
More information3.5 Reinforced Concrete Section Properties
CHAPER 3: Reinforced Concrete Slabs and Beams 3.5 Reinforced Concrete Section Properties Description his application calculates gross section moment of inertia neglecting reinforcement, moment of inertia
More informationε t increases from the compressioncontrolled Figure 9.15: Adjusted interaction diagram
CHAPTER NINE COLUMNS 4 b. The modified axial strength in compression is reduced to account for accidental eccentricity. The magnitude of axial force evaluated in step (a) is multiplied by 0.80 in case
More information3. Using your answers to the two previous questions, evaluate the Mratio
MASSACHUSETTS INSTITUTE OF TECHNOLOGY DEPARTMENT OF MECHANICAL ENGINEERING CAMBRIDGE, MASSACHUSETTS 0219 2.002 MECHANICS AND MATERIALS II HOMEWORK NO. 4 Distributed: Friday, April 2, 2004 Due: Friday,
More informationAppendix K Design Examples
Appendix K Design Examples Example 1 * Two-Span I-Girder Bridge Continuous for Live Loads AASHTO Type IV I girder Zero Skew (a) Bridge Deck The bridge deck reinforcement using A615 rebars is shown below.
More informationThe Derivative as a Function
Section 2.2 Te Derivative as a Function 200 Kiryl Tsiscanka Te Derivative as a Function DEFINITION: Te derivative of a function f at a number a, denoted by f (a), is if tis limit exists. f (a) f(a + )
More informationDesign 1 Calculations
Design 1 Calculations The following calculations are based on the method employed by Java Module A and are consistent with ACI318-99. The values in Fig. 1 below were taken from the Design 1 Example found
More informationChapter 9. τ all = min(0.30s ut,0.40s y ) = min[0.30(58), 0.40(32)] = min(17.4, 12.8) = 12.8 kpsi 2(32) (5/16)(4)(2) 2F hl. = 18.1 kpsi Ans. 1.
budynas_sm_c09.qxd 01/9/007 18:5 Page 39 Capter 9 9-1 Eq. (9-3: F 0.707lτ 0.707(5/1(4(0 17.7 kip 9- Table 9-: τ all 1.0 kpsi f 14.85 kip/in 14.85(5/1 4.4 kip/in F fl 4.4(4 18.5 kip 9-3 Table A-0: 1018
More information158 Calculus and Structures
58 Calculus and Structures CHAPTER PROPERTIES OF DERIVATIVES AND DIFFERENTIATION BY THE EASY WAY. Calculus and Structures 59 Copyrigt Capter PROPERTIES OF DERIVATIVES. INTRODUCTION In te last capter you
More informationA = h w (1) Error Analysis Physics 141
Introduction In all brances of pysical science and engineering one deals constantly wit numbers wic results more or less directly from experimental observations. Experimental observations always ave inaccuracies.
More informationChapter. Materials. 1.1 Notations Used in This Chapter
Chapter 1 Materials 1.1 Notations Used in This Chapter A Area of concrete cross-section C s Constant depending on the type of curing C t Creep coefficient (C t = ε sp /ε i ) C u Ultimate creep coefficient
More informationMoment Redistribution
TIME SAVING DESIGN AID Page 1 of 23 A 3-span continuous beam has center-to-center span lengths of 30 ft-0 in. The beam is 20 in. by 28 in. and all columns are 20 in. by 20 in. In this example, the beam
More information3.4 Reinforced Concrete Beams - Size Selection
CHAPER 3: Reinforced Concrete Slabs and Beams 3.4 Reinforced Concrete Beams - Size Selection Description his application calculates the spacing for shear reinforcement of a concrete beam supporting a uniformly
More informationAN ANALYSIS OF AMPLITUDE AND PERIOD OF ALTERNATING ICE LOADS ON CONICAL STRUCTURES
Ice in te Environment: Proceedings of te 1t IAHR International Symposium on Ice Dunedin, New Zealand, nd t December International Association of Hydraulic Engineering and Researc AN ANALYSIS OF AMPLITUDE
More informationDesign of Reinforced Concrete Structures (II)
Design of Reinforced Concrete Structures (II) Discussion Eng. Mohammed R. Kuheil Review The thickness of one-way ribbed slabs After finding the value of total load (Dead and live loads), the elements are
More informationChapter 2. Design for Shear. 2.1 Introduction. Neutral axis. Neutral axis. Fig. 4.1 Reinforced concrete beam in bending. By Richard W.
Chapter 2 Design for Shear By Richard W. Furlong 2.1 Introduction Shear is the term assigned to forces that act perpendicular to the longitudinal axis of structural elements. Shear forces on beams are
More information1. Which one of the following expressions is not equal to all the others? 1 C. 1 D. 25x. 2. Simplify this expression as much as possible.
004 Algebra Pretest answers and scoring Part A. Multiple coice questions. Directions: Circle te letter ( A, B, C, D, or E ) net to te correct answer. points eac, no partial credit. Wic one of te following
More informationspslab v3.11. Licensed to: STRUCTUREPOINT, LLC. License ID: D2DE-2175C File: C:\Data\CSA A Kt Revised.slb
X Z Y spslab v3.11. Licensed to: STRUCTUREPOINT, LLC. License ID: 00000-0000000-4-2D2DE-2175C File: C:\Data\CSA A23.3 - Kt Revised.slb Project: CSA A23.3 - Kt Torsional Stiffness Illustration Frame: Engineer:
More informationDr. Hazim Dwairi 10/16/2008
10/16/2008 Department o Civil Engineering Flexural Design o R.C. Beams Tpes (Modes) o Failure Tension Failure (Dutile Failure): Reinorement ields eore onrete ruses. Su a eam is alled under- reinored eam.
More informationMTH-112 Quiz 1 Name: # :
MTH- Quiz Name: # : Please write our name in te provided space. Simplif our answers. Sow our work.. Determine weter te given relation is a function. Give te domain and range of te relation.. Does te equation
More informationServiceability Deflection calculation
Chp-6:Lecture Goals Serviceability Deflection calculation Deflection example Structural Design Profession is concerned with: Limit States Philosophy: Strength Limit State (safety-fracture, fatigue, overturning
More informationUC Berkeley CE 123 Fall 2017 Instructor: Alan Kren
CE 123 - Reinforced Concrete Midterm Examination No. 2 Instructions: Read these instructions. Do not turn the exam over until instructed to do so. Work all problems. Pace yourself so that you have time
More informationOrder of Accuracy. ũ h u Ch p, (1)
Order of Accuracy 1 Terminology We consider a numerical approximation of an exact value u. Te approximation depends on a small parameter, wic can be for instance te grid size or time step in a numerical
More informationContinuity. Example 1
Continuity MATH 1003 Calculus and Linear Algebra (Lecture 13.5) Maoseng Xiong Department of Matematics, HKUST A function f : (a, b) R is continuous at a point c (a, b) if 1. x c f (x) exists, 2. f (c)
More informationChapter 8. Shear and Diagonal Tension
Chapter 8. and Diagonal Tension 8.1. READING ASSIGNMENT Text Chapter 4; Sections 4.1-4.5 Code Chapter 11; Sections 11.1.1, 11.3, 11.5.1, 11.5.3, 11.5.4, 11.5.5.1, and 11.5.6 8.2. INTRODUCTION OF SHEAR
More informationCCSD Practice Proficiency Exam Spring 2011
Spring 011 1. Use te grap below. Weigt (lb) 00 190 180 170 160 150 140 10 10 110 100 90 58 59 60 61 6 6 64 65 66 67 68 69 70 71 Heigt (in.) Wic table represents te information sown in te grap? Heigt (in.)
More informationWeek #15 - Word Problems & Differential Equations Section 8.2
Week #1 - Word Problems & Differential Equations Section 8. From Calculus, Single Variable by Huges-Hallett, Gleason, McCallum et. al. Copyrigt 00 by Jon Wiley & Sons, Inc. Tis material is used by permission
More informationNumerical Differentiation
Numerical Differentiation Finite Difference Formulas for te first derivative (Using Taylor Expansion tecnique) (section 8.3.) Suppose tat f() = g() is a function of te variable, and tat as 0 te function
More informationMATH CALCULUS I 2.1: Derivatives and Rates of Change
MATH 12002 - CALCULUS I 2.1: Derivatives and Rates of Cange Professor Donald L. Wite Department of Matematical Sciences Kent State University D.L. Wite (Kent State University) 1 / 1 Introduction Our main
More informationJune : 2016 (CBCS) Body. Load
Engineering Mecanics st Semester : Common to all rances Note : Max. marks : 6 (i) ttempt an five questions (ii) ll questions carr equal marks. (iii) nswer sould be precise and to te point onl (iv) ssume
More informationMAT 145. Type of Calculator Used TI-89 Titanium 100 points Score 100 possible points
MAT 15 Test #2 Name Solution Guide Type of Calculator Used TI-89 Titanium 100 points Score 100 possible points Use te grap of a function sown ere as you respond to questions 1 to 8. 1. lim f (x) 0 2. lim
More informationClick here to see an animation of the derivative
Differentiation Massoud Malek Derivative Te concept of derivative is at te core of Calculus; It is a very powerful tool for understanding te beavior of matematical functions. It allows us to optimize functions,
More informationNonlinear correction to the bending stiffness of a damaged composite beam
Van Paepegem, W., Decaene, R. and Degrieck, J. (5). Nonlinear correction to te bending stiffness of a damaged composite beam. Nonlinear correction to te bending stiffness of a damaged composite beam W.
More informationSection 15.6 Directional Derivatives and the Gradient Vector
Section 15.6 Directional Derivatives and te Gradient Vector Finding rates of cange in different directions Recall tat wen we first started considering derivatives of functions of more tan one variable,
More informationExample 1. Examples for walls are available on our Web page: Columns
Portlan Cement Association Page 1 o 9 Te ollowing examples illustrate te esign metos presente in te article Timesaving Design Ais or Reinorce Concrete, Part 3: an Walls, by Davi A. Fanella, wic appeare
More informationExam 1 Review Solutions
Exam Review Solutions Please also review te old quizzes, and be sure tat you understand te omework problems. General notes: () Always give an algebraic reason for your answer (graps are not sufficient),
More informationCase Study in Reinforced Concrete adapted from Simplified Design of Concrete Structures, James Ambrose, 7 th ed.
ARCH 631 Note Set 11 S017abn Case Study in Reinforced Concrete adapted from Simplified Design of Concrete Structures, James Ambrose, 7 th ed. Building description The building is a three-story office building
More informationIntroduction to Derivatives
Introduction to Derivatives 5-Minute Review: Instantaneous Rates and Tangent Slope Recall te analogy tat we developed earlier First we saw tat te secant slope of te line troug te two points (a, f (a))
More informationLines, Conics, Tangents, Limits and the Derivative
Lines, Conics, Tangents, Limits and te Derivative Te Straigt Line An two points on te (,) plane wen joined form a line segment. If te line segment is etended beond te two points ten it is called a straigt
More informationtwenty one concrete construction: shear & deflection ARCHITECTURAL STRUCTURES: FORM, BEHAVIOR, AND DESIGN DR. ANNE NICHOLS SUMMER 2014 lecture
ARCHITECTURAL STRUCTURES: FORM, BEHAVIOR, AND DESIGN DR. ANNE NICHOLS SUMMER 2014 lecture twenty one concrete construction: Copyright Kirk Martini shear & deflection Concrete Shear 1 Shear in Concrete
More informationStatic Response Analysis of a FGM Timoshenko s Beam Subjected to Uniformly Distributed Loading Condition
Static Response Analysis of a FGM Timoseno s Beam Subjected to Uniformly Distributed Loading Condition 8 Aas Roy Department of Mecanical Engineering National Institute of Tecnology Durgapur Durgapur, Maatma
More informationINTRODUCTION AND MATHEMATICAL CONCEPTS
Capter 1 INTRODUCTION ND MTHEMTICL CONCEPTS PREVIEW Tis capter introduces you to te basic matematical tools for doing pysics. You will study units and converting between units, te trigonometric relationsips
More informationHomework Assignment on Fluid Statics
AMEE 0 Introduction to Fluid Mecanics Instructor: Marios M. Fyrillas Email: m.fyrillas@fit.ac.cy Homework Assignment on Fluid Statics --------------------------------------------------------------------------------------------------------------
More informationlim 1 lim 4 Precalculus Notes: Unit 10 Concepts of Calculus
Syllabus Objectives: 1.1 Te student will understand and apply te concept of te limit of a function at given values of te domain. 1. Te student will find te limit of a function at given values of te domain.
More information(a) At what number x = a does f have a removable discontinuity? What value f(a) should be assigned to f at x = a in order to make f continuous at a?
Solutions to Test 1 Fall 016 1pt 1. Te grap of a function f(x) is sown at rigt below. Part I. State te value of eac limit. If a limit is infinite, state weter it is or. If a limit does not exist (but is
More informationChapter 9. Figure for Probs. 9-1 to Given, b = 50 mm, d = 50 mm, h = 5 mm, allow = 140 MPa.
Capter 9 Figure for Probs. 9-1 to 9-4 9-1 Given, b = 50 mm, d = 50 mm, = 5 mm, allow = 140 MPa. F = 0.707 l allow = 0.707(5)[(50)](140)(10 ) = 49.5 kn Ans. 9- Given, b = in, d = in, = 5/16 in, allow =
More informationWYSE Academic Challenge 2004 Sectional Mathematics Solution Set
WYSE Academic Callenge 00 Sectional Matematics Solution Set. Answer: B. Since te equation can be written in te form x + y, we ave a major 5 semi-axis of lengt 5 and minor semi-axis of lengt. Tis means
More informationContinuity and Differentiability Worksheet
Continuity and Differentiability Workseet (Be sure tat you can also do te grapical eercises from te tet- Tese were not included below! Typical problems are like problems -3, p. 6; -3, p. 7; 33-34, p. 7;
More informationLIMITS AND DERIVATIVES CONDITIONS FOR THE EXISTENCE OF A LIMIT
LIMITS AND DERIVATIVES Te limit of a function is defined as te value of y tat te curve approaces, as x approaces a particular value. Te limit of f (x) as x approaces a is written as f (x) approaces, as
More informationThe total error in numerical differentiation
AMS 147 Computational Metods and Applications Lecture 08 Copyrigt by Hongyun Wang, UCSC Recap: Loss of accuracy due to numerical cancellation A B 3, 3 ~10 16 In calculating te difference between A and
More informationPath to static failure of machine components
Pat to static failure of macine components Load Stress Discussed last week (w) Ductile material Yield Strain Brittle material Fracture Fracture Dr. P. Buyung Kosasi,Spring 008 Name some of ductile and
More informationPlastic design of continuous beams
Budapest University of Technology and Economics Department of Mechanics, Materials and Structures English courses Reinforced Concrete Structures Code: BMEEPSTK601 Lecture no. 4: Plastic design of continuous
More information5.1. Cross-Section and the Strength of a Bar
TRENGTH OF MTERL Meanosüsteemide komponentide õppetool 5. Properties of ections 5. ross-ection and te trengt of a Bar 5. rea Properties of Plane apes 5. entroid of a ection 5.4 rea Moments of nertia 5.5
More informationMATH Fall 08. y f(x) Review Problems for the Midterm Examination Covers [1.1, 4.3] in Stewart
MATH 121 - Fall 08 Review Problems for te Midterm Eamination Covers [1.1, 4.3] in Stewart 1. (a) Use te definition of te derivative to find f (3) wen f() = π 1 2. (b) Find an equation of te tangent line
More informationChapter 1 Functions and Graphs. Section 1.5 = = = 4. Check Point Exercises The slope of the line y = 3x+ 1 is 3.
Capter Functions and Graps Section. Ceck Point Exercises. Te slope of te line y x+ is. y y m( x x y ( x ( y ( x+ point-slope y x+ 6 y x+ slope-intercept. a. Write te equation in slope-intercept form: x+
More informationTherefore, for all members designed according to ACI 318 Code, f s =f y at failure, and the nominal strength is given by:
5.11. Under-reinforced Beams (Read Sect. 3.4b oour text) We want the reinforced concrete beams to fail in tension because is not a sudden failure. Therefore, following Figure 5.3, you have to make sure
More informationSection 2.7 Derivatives and Rates of Change Part II Section 2.8 The Derivative as a Function. at the point a, to be. = at time t = a is
Mat 180 www.timetodare.com Section.7 Derivatives and Rates of Cange Part II Section.8 Te Derivative as a Function Derivatives ( ) In te previous section we defined te slope of te tangent to a curve wit
More informationConsider a function f we ll specify which assumptions we need to make about it in a minute. Let us reformulate the integral. 1 f(x) dx.
Capter 2 Integrals as sums and derivatives as differences We now switc to te simplest metods for integrating or differentiating a function from its function samples. A careful study of Taylor expansions
More informationDESIGN AND DETAILING OF COUNTERFORT RETAINING WALL
DESIGN AND DETAILING OF COUNTERFORT RETAINING WALL When the height of the retaining wall exceeds about 6 m, the thickness of the stem and heel slab works out to be sufficiently large and the design becomes
More informationChapter 2 GEOMETRIC ASPECT OF THE STATE OF SOLICITATION
Capter GEOMETRC SPECT OF THE STTE OF SOLCTTON. THE DEFORMTON ROUND PONT.. Te relative displacement Due to te influence of external forces, temperature variation, magnetic and electric fields, te construction
More informationy = x 5 ( ) + 22 at the rate of 3 units per second.
C 4-6,8 Review Pre-Calculus Name Period THEME 1 Parametric Equations Refreser notes: 1) Maggie moves at constant speed of 6 m/s. Se starts at te point (12,3) and eads towards te y-axis along te line y
More informationFlexure: Behavior and Nominal Strength of Beam Sections
4 5000 4000 (increased d ) (increased f (increased A s or f y ) c or b) Flexure: Behavior and Nominal Strength of Beam Sections Moment (kip-in.) 3000 2000 1000 0 0 (basic) (A s 0.5A s ) 0.0005 0.001 0.0015
More information1. State whether the function is an exponential growth or exponential decay, and describe its end behaviour using limits.
Questions 1. State weter te function is an exponential growt or exponential decay, and describe its end beaviour using its. (a) f(x) = 3 2x (b) f(x) = 0.5 x (c) f(x) = e (d) f(x) = ( ) x 1 4 2. Matc te
More informationUNIT #6 EXPONENTS, EXPONENTS, AND MORE EXPONENTS REVIEW QUESTIONS
Answer Key Name: Date: UNIT # EXPONENTS, EXPONENTS, AND MORE EXPONENTS REVIEW QUESTIONS Part I Questions. Te epression 0 can be simpliied to () () 0 0. Wic o te ollowing is equivalent to () () 8 8? 8.
More informationUNIVERSITY OF SASKATCHEWAN Department of Physics and Engineering Physics
UNIVERSITY O SASKATCHEWAN Department of Pysics and Engineering Pysics Pysics 117.3 MIDTERM EXAM Regular Sitting NAME: (Last) Please Print (Given) Time: 90 minutes STUDENT NO.: LECTURE SECTION (please ceck):
More informationAnnex - R C Design Formulae and Data
The design formulae and data provided in this Annex are for education, training and assessment purposes only. They are based on the Hong Kong Code of Practice for Structural Use of Concrete 2013 (HKCP-2013).
More informationTaylor Series and the Mean Value Theorem of Derivatives
1 - Taylor Series and te Mean Value Teorem o Derivatives Te numerical solution o engineering and scientiic problems described by matematical models oten requires solving dierential equations. Dierential
More information1 Power is transferred through a machine as shown. power input P I machine. power output P O. power loss P L. What is the efficiency of the machine?
1 1 Power is transferred troug a macine as sown. power input P I macine power output P O power loss P L Wat is te efficiency of te macine? P I P L P P P O + P L I O P L P O P I 2 ir in a bicycle pump is
More informationLecture-08 Gravity Load Analysis of RC Structures
Lecture-08 Gravity Load Analysis of RC Structures By: Prof Dr. Qaisar Ali Civil Engineering Department UET Peshawar www.drqaisarali.com 1 Contents Analysis Approaches Point of Inflection Method Equivalent
More informationM12/4/PHYSI/HPM/ENG/TZ1/XX. Physics Higher level Paper 1. Thursday 10 May 2012 (afternoon) 1 hour INSTRUCTIONS TO CANDIDATES
M12/4/PHYSI/HPM/ENG/TZ1/XX 22126507 Pysics Higer level Paper 1 Tursday 10 May 2012 (afternoon) 1 our INSTRUCTIONS TO CANDIDATES Do not open tis examination paper until instructed to do so. Answer all te
More informationAppendix J. Example of Proposed Changes
Appendix J Example of Proposed Changes J.1 Introduction The proposed changes are illustrated with reference to a 200-ft, single span, Washington DOT WF bridge girder with debonded strands and no skew.
More informationDEFLECTION CALCULATIONS (from Nilson and Nawy)
DEFLECTION CALCULATIONS (from Nilson and Nawy) The deflection of a uniformly loaded flat plate, flat slab, or two-way slab supported by beams on column lines can be calculated by an equivalent method that
More informationCHAPTER (A) When x = 2, y = 6, so f( 2) = 6. (B) When y = 4, x can equal 6, 2, or 4.
SECTION 3-1 101 CHAPTER 3 Section 3-1 1. No. A correspondence between two sets is a function only if eactly one element of te second set corresponds to eac element of te first set. 3. Te domain of a function
More informationMATH 111 CHAPTER 2 (sec )
MATH CHAPTER (sec -0) Terms to know: function, te domain and range of te function, vertical line test, even and odd functions, rational power function, vertical and orizontal sifts of a function, reflection
More informationMODELING THE EFFECTIVE ELASTIC MODULUS OF RC BEAMS EXPOSED TO FIRE
Journal of Marine Science and Technology, Vol., No., pp. -8 () MODELING THE EFFECTIVE ELASTIC MODULUS OF RC BEAMS EXPOSED TO FIRE Jui-Hsiang Hsu*, ***, Cherng-Shing Lin**, and Chang-Bin Huang*** Key words:
More informationSFU UBC UNBC Uvic Calculus Challenge Examination June 5, 2008, 12:00 15:00
SFU UBC UNBC Uvic Calculus Callenge Eamination June 5, 008, :00 5:00 Host: SIMON FRASER UNIVERSITY First Name: Last Name: Scool: Student signature INSTRUCTIONS Sow all your work Full marks are given only
More informationMath 102 TEST CHAPTERS 3 & 4 Solutions & Comments Fall 2006
Mat 102 TEST CHAPTERS 3 & 4 Solutions & Comments Fall 2006 f(x+) f(x) 10 1. For f(x) = x 2 + 2x 5, find ))))))))) and simplify completely. NOTE: **f(x+) is NOT f(x)+! f(x+) f(x) (x+) 2 + 2(x+) 5 ( x 2
More informationColumn Analogy in Multi-Cell Structures with Fixed Columns
Electronic Journal of Structural Engineering 12(1) 2012 Column Analogy in Multi-Cell Structures with Fixed Columns A. Badir Department of Environmental & Civil Engineering, U.A. Whitaker College of Engineering,
More information1. Questions (a) through (e) refer to the graph of the function f given below. (A) 0 (B) 1 (C) 2 (D) 4 (E) does not exist
Mat 1120 Calculus Test 2. October 18, 2001 Your name Te multiple coice problems count 4 points eac. In te multiple coice section, circle te correct coice (or coices). You must sow your work on te oter
More informationSERVICEABILITY LIMIT STATE DESIGN
CHAPTER 11 SERVICEABILITY LIMIT STATE DESIGN Article 49. Cracking Limit State 49.1 General considerations In the case of verifications relating to Cracking Limit State, the effects of actions comprise
More informationLIMITATIONS OF EULER S METHOD FOR NUMERICAL INTEGRATION
LIMITATIONS OF EULER S METHOD FOR NUMERICAL INTEGRATION LAURA EVANS.. Introduction Not all differential equations can be explicitly solved for y. Tis can be problematic if we need to know te value of y
More informationAnalysis of Stress and Deflection about Steel-Concrete Composite Girders Considering Slippage and Shrink & Creep Under Bending
Send Orders for Reprints to reprints@bentamscience.ae Te Open Civil Engineering Journal 9 7-7 7 Open Access Analysis of Stress and Deflection about Steel-Concrete Composite Girders Considering Slippage
More informationMVT and Rolle s Theorem
AP Calculus CHAPTER 4 WORKSHEET APPLICATIONS OF DIFFERENTIATION MVT and Rolle s Teorem Name Seat # Date UNLESS INDICATED, DO NOT USE YOUR CALCULATOR FOR ANY OF THESE QUESTIONS In problems 1 and, state
More informationThe Verlet Algorithm for Molecular Dynamics Simulations
Cemistry 380.37 Fall 2015 Dr. Jean M. Standard November 9, 2015 Te Verlet Algoritm for Molecular Dynamics Simulations Equations of motion For a many-body system consisting of N particles, Newton's classical
More informationUSER BULLETIN 3: DETERMINATION OF UNSUPPORTED LENGTH RATIO L/Db
USER BULLETIN 3: DETERMINATION OF UNSUPPORTED LENGTH RATIO L/Db The unsupported length ratio (L/Db) is calculated by the automatic Sectional modeler spreadsheet using Dhakal and Maekawa [1]. This method
More informationDesign of a Multi-Storied RC Building
Design of a Multi-Storied RC Building 16 14 14 3 C 1 B 1 C 2 B 2 C 3 B 3 C 4 13 B 15 (S 1 ) B 16 (S 2 ) B 17 (S 3 ) B 18 7 B 4 B 5 B 6 B 7 C 5 C 6 C 7 C 8 C 9 7 B 20 B 22 14 B 19 (S 4 ) C 10 C 11 B 23
More informationPolynomial Interpolation
Capter 4 Polynomial Interpolation In tis capter, we consider te important problem of approximatinga function fx, wose values at a set of distinct points x, x, x,, x n are known, by a polynomial P x suc
More informationSome Review Problems for First Midterm Mathematics 1300, Calculus 1
Some Review Problems for First Midterm Matematics 00, Calculus. Consider te trigonometric function f(t) wose grap is sown below. Write down a possible formula for f(t). Tis function appears to be an odd,
More information1. (a) 3. (a) 4 3 (b) (a) t = 5: 9. (a) = 11. (a) The equation of the line through P = (2, 3) and Q = (8, 11) is y 3 = 8 6
A Answers Important Note about Precision of Answers: In many of te problems in tis book you are required to read information from a grap and to calculate wit tat information. You sould take reasonable
More informationNumerical Analysis MTH603. dy dt = = (0) , y n+1. We obtain yn. Therefore. and. Copyright Virtual University of Pakistan 1
Numerical Analysis MTH60 PREDICTOR CORRECTOR METHOD Te metods presented so far are called single-step metods, were we ave seen tat te computation of y at t n+ tat is y n+ requires te knowledge of y n only.
More information(4.2) -Richardson Extrapolation
(.) -Ricardson Extrapolation. Small-O Notation: Recall tat te big-o notation used to define te rate of convergence in Section.: Suppose tat lim G 0 and lim F L. Te function F is said to converge to L as
More informationSimulation and verification of a plate heat exchanger with a built-in tap water accumulator
Simulation and verification of a plate eat excanger wit a built-in tap water accumulator Anders Eriksson Abstract In order to test and verify a compact brazed eat excanger (CBE wit a built-in accumulation
More information2.8 The Derivative as a Function
.8 Te Derivative as a Function Typically, we can find te derivative of a function f at many points of its domain: Definition. Suppose tat f is a function wic is differentiable at every point of an open
More informationA general articulation angle stability model for non-slewing articulated mobile cranes on slopes *
tecnical note 3 general articulation angle stability model for non-slewing articulated mobile cranes on slopes * J Wu, L uzzomi and M Hodkiewicz Scool of Mecanical and Cemical Engineering, University of
More information