Gravity and isostasy

Size: px
Start display at page:

Download "Gravity and isostasy"

Transcription

1 Gavity and isostasy Reading: owle p60 74 Theoy of gavity Use two of Newton s laws: ) Univesal law of gavitation: Gmm = m m Univesal gavitational constant G=6.67 x 0 - Nm /kg ) Second law of motion: = ma We can combine them to obtain the gavitational acceleation of m towad m : Gm a = The gavitational attaction de to sphee mass M is the same as placing all the mass at the cente of the sphee as long as the mass being attacted is otside the sphee.

2 Theoy of gavity Gavitational acceleation: Gm a = m m Gavitational potential: Relationship: Gm = V V a = Definition: The gavitational potential, V, de to a point mass m, at a distance fom m, is the wok done by the gavitational foce in moving a nit mass fom infinity to to a position fom m. The gavitational acceleation is eqal to the ate of change in the potential field Gavitational acceleation on ath If the ath was a sphee the gavitational acceleation at the sface of the ath wold be: g = GM R Typical vale: 9.8 m/s Note that g is not dependent of the mass of the object being acceleated towad the cente of the ath Gavity nit: gal gal = 0.0 m/s Typical vale: g = 98 gal Named afte Galileo who did mch of the pioneeing stdies into gavity Is the ath s gavitational acceleation a constant?

3 Gavitational acceleation on ath ath is not a stationay sphee! The ath is an oblate spheoid atte at the eqato and thinne at the poles The ath is otating Centifgal acceleation edces gavitational attaction. The fthe yo ae fom the otation axis the geate the centifgal acceleation Refeence gavity fomla The mathematically detemined gavitational acceleation on a 4 g( λ ) = g ( + α sin λ + β sin otating oblate spheoid e Whee λ is the latitde, g e the gavitational acceleation at the eqato g e = m/s, and constants α = β = Obits of satellites When a mass gets caght in the gavitational field of a planet it stats to obit the planet. The gavitational attaction of the planet balances the otwad centifgal foce: GM m = mω The distance of the satellite fom the ath is dependent on the gavitational attaction By monitoing the obits of man made satellites we can detemine vaiations in g aond the globe Also, sing satellite altimety we can mease the distance of the ath sface below the satellite and detemine the ath s shape

4 The geoid Mean sea level is an eqipotential sface it is the geoid These figes show the diffeences between the geoid and the efeence ellipsoid/spheoid Geoid anomalies Diffeences between the geoid and efeence ellipsoid ae de to lateal density anomalies De to topogaphy De to highe and lowe density mateial in the cst o mantle Meased gavity anomalies ae small compaed to mean gavity mean g = 9.8 m/s mease gavity anomalies of 0-8 of the mean sface vale Instment sensitivity: John Milne (906): When a sqad of 76 men mached to within 6 o 0 feet of the Oxfod Univesity Obsevatoy it was fond that a hoizontal pendlm inside the bilding meased a deflection in the diection of the advancing load

5 Isostasy 8 th and 9 th centy sveys set ot to mease the shape of the ath. They sed plmb bobs and expected them to be attacted towad adjacent montain chains eg the Andes and Himalayas Bt the plmb bob was not attacted as mch as expected They calclated that the obseved deflection cold be explained if the excess montain mass was matched by an eqal mass deficiency beneath The montains wee in isostatic eqilibim The ath s lithosphee is floating on the dense asthenosphee Aiy s hypothesis 3 to accont fo the mass deficiency beneath montains Two densities, that of the igid ppe laye, ρ, and that of the sbstatm, ρ s Montains theefoe have deep oots The compensation depth is the depth below which all pesses ae hydostatic qating the masses in vetical colmns above the compensation depth: 3 tρ ρ = h + t ) ρ tρ + ρ = dρ + t d ) ρ + ( ) ρ + s ( + s w ( s A montain height h is ndelain by a oot of thickness: h ρ ρ ρ = s Ocean basin depth, d, is ndelain by a anti-oot of thickness: d( ρ ρw) 3 = ρ ρ s

6 Patt s hypothesis 3 to accont fo the mass deficiency beneath montains The depth of the base of the ppe laye is constant Montains theefoe have low density oots The compensation depth is the depth below which all pesses ae hydostatic qating the masses in vetical colmns above the compensation depth: 3 Dρ = ( h + D ρ Dρ = dρ + ρ ( D d) ) w d A montain height h is ndelain by low density mateial, density ρ : D ρ = ρ h + D Ocean basin depth, d, is ndelain by a high density mateial, density ρ d : ρ D ρ d w ρd = D d Which hypothesis? is opeating on the ath? o a given location we mst ask oselves Is thee isostatic eqilibim? Which pocess is opeating? We can stat to addess Is it a combination of the two? some of these qestions Patt and Aiy ae end membes with gavity measements Bt fist, we mst coect o measements

7 Gavity coections Obsevations still sbject to extaneos effects nelated to sbsface geology Mst make coections. Latitde coection. ee-ai coection 3. Boge coection 4. Teain coection Latitde coection coect fo the spheoid Refeence fomla: = e 4 g( λ ) g ( + α sin λ + β sin m/s Whee λ is the latitde, g e the gavitational acceleation at the eqato g e = m/s, and constants α = β = This fomla povides the vaiation in g de to the spheoid It is a fnction of latitde λ only Calclate the coection fo latitde of obsevation point

8 ee-ai coection Acconts fo the / decease in gavity with distance fom the cente of the ath. A given gavity measement was made at an elevation h, not at sea level, ecall: The gavity at elevation h above sea level is appoximated by: The fee-ai coection is theefoe: g δg h R ( h) = g0 h ( g R = g0 g h) = GM g = R 0 g 0 is the gavity at sea level, ie g 0 = g( Gavity deceases with distance fom the cente of the ath The fee-ai coection is theefoe added ee-ai anomaly A gavity anomaly sggests the diffeence between a theoetical and obseved vale The fee-ai anomaly is calclated by coecting an obsevation fo expected vaiations de to () the spheoid and () elevation above the spheoid (ie the geoid ie sea level) Then the fee-ai anomaly is: g = g = g = g obs obs obs g( + δg h g( + g( R h g( R

9 Boge coection Acconts fo ock thickness between obsevation and sea level h Sea level Teat the ock as an infinite hoizontal slab, the Boge coection is: g B δ = πgρh This additional slab of ock between the obsevation point and sea level cases an additional attaction The Boge coection is sbtacted fom the obsevation Teain coection When Boge coection is inadeqate, also se teain coection hill valley Appoaches to coection Rectangla gid Hamme segments both se elevation diffeences between station and sond o cstal scale stdies the teain coections ae sally insignificant so ignoe

10 Teain coection Hamme coection Boge anomaly Apply all the coections: g B = g = g obs δg B + δg T g( + δg With the Boge anomaly We have sbtacted theoetical vales fo the latitde and elevation We have emoved the ock above sea level so the anomaly epesents the density stcte of mateial below sea level This is compaable to the fee-ai anomaly ove the oceans and both have been coected to sea level δg B + δg T watch the signs! Boge anomaly fo offshoe gavity: Replace the wate with ock Apply teain coection fo seabed topogaphy

Gravity. Gravitational Acceleration.

Gravity. Gravitational Acceleration. Gavity Using the Eath s gavitational field to study its intenal stuctue has poven to be an extemely effective means of pobing stuctual vaiations at all levels depths and length scales within the Eath.

More information

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and Exta notes fo cicula motion: Cicula motion : v keeps changing, maybe both speed and diection ae changing. At least v diection is changing. Hence a 0. Acceleation NEEDED to stay on cicula obit: a cp v /,

More information

OSCILLATIONS AND GRAVITATION

OSCILLATIONS AND GRAVITATION 1. SIMPLE HARMONIC MOTION Simple hamonic motion is any motion that is equivalent to a single component of unifom cicula motion. In this situation the velocity is always geatest in the middle of the motion,

More information

Escape Velocity. GMm ] B

Escape Velocity. GMm ] B 1 PHY2048 Mach 31, 2006 Escape Velocity Newton s law of gavity: F G = Gm 1m 2 2, whee G = 667 10 11 N m 2 /kg 2 2 3 10 10 N m 2 /kg 2 is Newton s Gavitational Constant Useful facts: R E = 6 10 6 m M E

More information

= 4 3 π( m) 3 (5480 kg m 3 ) = kg.

= 4 3 π( m) 3 (5480 kg m 3 ) = kg. CHAPTER 11 THE GRAVITATIONAL FIELD Newton s Law of Gavitation m 1 m A foce of attaction occus between two masses given by Newton s Law of Gavitation Inetial mass and gavitational mass Gavitational potential

More information

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS TSOKOS LESSON 10-1 DESCRIBING FIELDS Essential Idea: Electic chages and masses each influence the space aound them and that influence can be epesented

More information

m1 m2 M 2 = M -1 L 3 T -2

m1 m2 M 2 = M -1 L 3 T -2 GAVITATION Newton s Univesal law of gavitation. Evey paticle of matte in this univese attacts evey othe paticle with a foce which vaies diectly as the poduct of thei masses and invesely as the squae of

More information

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE VISUAL PHYSICS ONLIN MODUL 5 ADVANCD MCHANICS GRAVITATIONAL FILD: MOTION OF PLANTS AND SATLLITS SATLLITS: Obital motion of object of mass m about a massive object of mass M (m

More information

Physics 181. Assignment 4

Physics 181. Assignment 4 Physics 181 Assignment 4 Solutions 1. A sphee has within it a gavitational field given by g = g, whee g is constant and is the position vecto of the field point elative to the cente of the sphee. This

More information

PHYSICS NOTES GRAVITATION

PHYSICS NOTES GRAVITATION GRAVITATION Newton s law of gavitation The law states that evey paticle of matte in the univese attacts evey othe paticle with a foce which is diectly popotional to the poduct of thei masses and invesely

More information

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N Chapte answes Heinemann Physics 4e Section. Woked example: Ty youself.. GRAVITATIONAL ATTRACTION BETWEEN SMALL OBJECTS Two bowling balls ae sitting next to each othe on a shelf so that the centes of the

More information

Gravitation. AP/Honors Physics 1 Mr. Velazquez

Gravitation. AP/Honors Physics 1 Mr. Velazquez Gavitation AP/Honos Physics 1 M. Velazquez Newton s Law of Gavitation Newton was the fist to make the connection between objects falling on Eath and the motion of the planets To illustate this connection

More information

Gaia s Place in Space

Gaia s Place in Space Gaia s Place in Space The impotance of obital positions fo satellites Obits and Lagange Points Satellites can be launched into a numbe of diffeent obits depending on thei objectives and what they ae obseving.

More information

Circular Orbits. and g =

Circular Orbits. and g = using analyse planetay and satellite motion modelled as unifom cicula motion in a univesal gavitation field, a = v = 4π and g = T GM1 GM and F = 1M SATELLITES IN OBIT A satellite is any object that is

More information

Between any two masses, there exists a mutual attractive force.

Between any two masses, there exists a mutual attractive force. YEAR 12 PHYSICS: GRAVITATION PAST EXAM QUESTIONS Name: QUESTION 1 (1995 EXAM) (a) State Newton s Univesal Law of Gavitation in wods Between any two masses, thee exists a mutual attactive foce. This foce

More information

kg 2 ) 1.9!10 27 kg = Gm 1

kg 2 ) 1.9!10 27 kg = Gm 1 Section 6.1: Newtonian Gavitation Tutoial 1 Pactice, page 93 1. Given: 1.0 10 0 kg; m 3.0 10 0 kg;. 10 9 N; G 6.67 10 11 N m /kg Requied: Analysis: G m ; G m G m Solution: G m N m 6.67!10 11 kg ) 1.0!100

More information

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11.

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11. NSWRS - P Physics Multiple hoice Pactice Gavitation Solution nswe 1. m mv Obital speed is found fom setting which gives v whee M is the object being obited. Notice that satellite mass does not affect obital

More information

Objective Notes Summary

Objective Notes Summary Objective Notes Summay An object moving in unifom cicula motion has constant speed but not constant velocity because the diection is changing. The velocity vecto in tangent to the cicle, the acceleation

More information

Chapter 13 Gravitation

Chapter 13 Gravitation Chapte 13 Gavitation In this chapte we will exploe the following topics: -Newton s law of gavitation, which descibes the attactive foce between two point masses and its application to extended objects

More information

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9 SPH4 nit 6.3 Gavitational Potential negy Page of Notes Physics ool box he gavitational potential enegy of a syste of two (spheical) asses is diectly popotional to the poduct of thei asses, and invesely

More information

Chapter 5: Uniform Circular Motion

Chapter 5: Uniform Circular Motion Chapte 5: Unifom Cicula Motion Motion at constant speed in a cicle Centipetal acceleation Banked cuves Obital motion Weightlessness, atificial gavity Vetical cicula motion Centipetal Foce Acceleation towad

More information

1 Dark Cloud Hanging over Twentieth Century Physics

1 Dark Cloud Hanging over Twentieth Century Physics We ae Looking fo Moden Newton by Caol He, Bo He, and Jin He http://www.galaxyanatomy.com/ Wuhan FutueSpace Scientific Copoation Limited, Wuhan, Hubei 430074, China E-mail: mathnob@yahoo.com Abstact Newton

More information

Our Universe: GRAVITATION

Our Universe: GRAVITATION Ou Univese: GRAVITATION Fom Ancient times many scientists had shown geat inteest towads the sky. Most of the scientist studied the motion of celestial bodies. One of the most influential geek astonomes

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion constant speed Pick a point in the objects motion... What diection is the velocity? HINT Think about what diection the object would tavel if the sting wee cut Unifom Cicula Motion

More information

Physics 235 Chapter 5. Chapter 5 Gravitation

Physics 235 Chapter 5. Chapter 5 Gravitation Chapte 5 Gavitation In this Chapte we will eview the popeties of the gavitational foce. The gavitational foce has been discussed in geat detail in you intoductoy physics couses, and we will pimaily focus

More information

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS TSOKOS LESSON 6- THE LAW OF GRAVITATION Essential Idea: The Newtonian idea of gavitational foce acting between two spheical bodies and the laws of mechanics

More information

Chapter 8. Accelerated Circular Motion

Chapter 8. Accelerated Circular Motion Chapte 8 Acceleated Cicula Motion 8.1 Rotational Motion and Angula Displacement A new unit, adians, is eally useful fo angles. Radian measue θ(adians) = s = θ s (ac length) (adius) (s in same units as

More information

ww.trbtnpsc.com/2017/09/11th-quarterly-exam-question-paper-and-answer-keys-download-20

ww.trbtnpsc.com/2017/09/11th-quarterly-exam-question-paper-and-answer-keys-download-20 ww.tbtnpsc.com/07/09/th-qately-eam-qestion-pape-and-answe-keys-download-0 336 Sa s + Std - Physics Qately - 07 Qestion Pape th STD. Qately - 07 Qestion Pape with Answes Time : ½ Hos Physics Ma. Maks :

More information

Chapter 12: Kinematics of a Particle 12.8 CURVILINEAR MOTION: CYLINDRICAL COMPONENTS. u of the polar coordinate system are also shown in

Chapter 12: Kinematics of a Particle 12.8 CURVILINEAR MOTION: CYLINDRICAL COMPONENTS. u of the polar coordinate system are also shown in ME 01 DYNAMICS Chapte 1: Kinematics of a Paticle Chapte 1 Kinematics of a Paticle A. Bazone 1.8 CURVILINEAR MOTION: CYLINDRICAL COMPONENTS Pola Coodinates Pola coodinates ae paticlaly sitable fo solving

More information

Chapter 5 Force and Motion

Chapter 5 Force and Motion Chapte 5 Foce and Motion In Chaptes 2 and 4 we have studied kinematics, i.e., we descibed the motion of objects using paametes such as the position vecto, velocity, and acceleation without any insights

More information

Chapter 5 Force and Motion

Chapter 5 Force and Motion Chapte 5 Foce and Motion In chaptes 2 and 4 we have studied kinematics i.e. descibed the motion of objects using paametes such as the position vecto, velocity and acceleation without any insights as to

More information

Universal Gravitation

Universal Gravitation Chapte 1 Univesal Gavitation Pactice Poblem Solutions Student Textbook page 580 1. Conceptualize the Poblem - The law of univesal gavitation applies to this poblem. The gavitational foce, F g, between

More information

TAMPINES JUNIOR COLLEGE 2009 JC1 H2 PHYSICS GRAVITATIONAL FIELD

TAMPINES JUNIOR COLLEGE 2009 JC1 H2 PHYSICS GRAVITATIONAL FIELD TAMPINES JUNIOR COLLEGE 009 JC1 H PHYSICS GRAVITATIONAL FIELD OBJECTIVES Candidates should be able to: (a) show an undestanding of the concept of a gavitational field as an example of field of foce and

More information

Angular Momentum About Spin Axis

Angular Momentum About Spin Axis Angla Momentm Angla Momentm Abot Spin Axis Ω AM (pe nit mass) = velocity moment am M =( + ) = a cos φ Thin-shell appoximation: take distance fom any point in atmosphee to planet s baycente eqal to constant

More information

Chapter 5. Uniform Circular Motion. a c =v 2 /r

Chapter 5. Uniform Circular Motion. a c =v 2 /r Chapte 5 Unifom Cicula Motion a c =v 2 / Unifom cicula motion: Motion in a cicula path with constant speed s v 1) Speed and peiod Peiod, T: time fo one evolution Speed is elated to peiod: Path fo one evolution:

More information

Ch 13 Universal Gravitation

Ch 13 Universal Gravitation Ch 13 Univesal Gavitation Ch 13 Univesal Gavitation Why do celestial objects move the way they do? Keple (1561-1630) Tycho Bahe s assistant, analyzed celestial motion mathematically Galileo (1564-1642)

More information

Unit 6 Test Review Gravitation & Oscillation Chapters 13 & 15

Unit 6 Test Review Gravitation & Oscillation Chapters 13 & 15 A.P. Physics C Unit 6 Test Review Gavitation & Oscillation Chaptes 13 & 15 * In studying fo you test, make sue to study this eview sheet along with you quizzes and homewok assignments. Multiple Choice

More information

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block?

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 13, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

Physics: Work & Energy Beyond Earth Guided Inquiry

Physics: Work & Energy Beyond Earth Guided Inquiry Physics: Wok & Enegy Beyond Eath Guided Inquiy Elliptical Obits Keple s Fist Law states that all planets move in an elliptical path aound the Sun. This concept can be extended to celestial bodies beyond

More information

7.2. Coulomb s Law. The Electric Force

7.2. Coulomb s Law. The Electric Force Coulomb s aw Recall that chaged objects attact some objects and epel othes at a distance, without making any contact with those objects Electic foce,, o the foce acting between two chaged objects, is somewhat

More information

AP * PHYSICS B. Circular Motion, Gravity, & Orbits. Teacher Packet

AP * PHYSICS B. Circular Motion, Gravity, & Orbits. Teacher Packet AP * PHYSICS B Cicula Motion, Gavity, & Obits Teache Packet AP* is a tademak of the College Entance Examination Boad. The College Entance Examination Boad was not involved in the poduction of this mateial.

More information

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once.

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once. Honos Physics Fall, 2016 Cicula Motion & Toque Test Review Name: M. Leonad Instuctions: Complete the following woksheet. SHOW ALL OF YOUR WORK ON A SEPARATE SHEET OF PAPER. 1. Detemine whethe each statement

More information

PS113 Chapter 5 Dynamics of Uniform Circular Motion

PS113 Chapter 5 Dynamics of Uniform Circular Motion PS113 Chapte 5 Dynamics of Unifom Cicula Motion 1 Unifom cicula motion Unifom cicula motion is the motion of an object taveling at a constant (unifom) speed on a cicula path. The peiod T is the time equied

More information

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j.

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j. 7. We denote the two foces F A + F B = ma,sof B = ma F A. (a) In unit vecto notation F A = ( 20.0 N)ˆ i and Theefoe, Phys 201A Homewok 6 Solutions F A and F B. Accoding to Newton s second law, a = [ (

More information

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s 1. A stone falls fom a platfom 18 m high. When will it hit the gound? (a) 1.74 s (b) 1.83 s (c) 1.9 s (d).01 s Constant acceleation D = v 0 t + ½ a t. Which, if any, of these foces causes the otation of

More information

Dynamic Meteorology 1

Dynamic Meteorology 1 Dynamic Meteooloy 1 Lecte 3 Sahaei Physics Depatment, Rai Univesity http://www.ai.ac.i/sahaei Physical meanin of The Laplacian ives the smoothness of a fnction.it meases the diffeence between the vale

More information

Physics 312 Introduction to Astrophysics Lecture 7

Physics 312 Introduction to Astrophysics Lecture 7 Physics 312 Intoduction to Astophysics Lectue 7 James Buckley buckley@wuphys.wustl.edu Lectue 7 Eath/Moon System Tidal Foces Tides M= mass of moon o sun F 1 = GMm 2 F 2 = GMm ( + ) 2 Diffeence in gavitational

More information

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK.

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK. AP Physics C Sping, 2017 Cicula-Rotational Motion Mock Exam Name: Answe Key M. Leonad Instuctions: (92 points) Answe the following questions. SHOW ALL OF YOUR WORK. ( ) 1. A stuntman dives a motocycle

More information

Physics 111. Ch 12: Gravity. Newton s Universal Gravity. R - hat. the equation. = Gm 1 m 2. F g 2 1. ˆr 2 1. Gravity G =

Physics 111. Ch 12: Gravity. Newton s Universal Gravity. R - hat. the equation. = Gm 1 m 2. F g 2 1. ˆr 2 1. Gravity G = ics Announcements day, embe 9, 004 Ch 1: Gavity Univesal Law Potential Enegy Keple s Laws Ch 15: Fluids density hydostatic equilibium Pascal s Pinciple This week s lab will be anothe physics wokshop -

More information

A thermodynamic degree of freedom solution to the galaxy cluster problem of MOND. Abstract

A thermodynamic degree of freedom solution to the galaxy cluster problem of MOND. Abstract A themodynamic degee of feedom solution to the galaxy cluste poblem of MOND E.P.J. de Haas (Paul) Nijmegen, The Nethelands (Dated: Octobe 23, 2015) Abstact In this pape I discus the degee of feedom paamete

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion Intoduction Ealie we defined acceleation as being the change in velocity with time: a = v t Until now we have only talked about changes in the magnitude of the acceleation: the speeding

More information

The Millikan Experiment: Determining the Elementary Charge

The Millikan Experiment: Determining the Elementary Charge LAB EXERCISE 7.5.1 7.5 The Elementay Chage (p. 374) Can you think of a method that could be used to suggest that an elementay chage exists? Figue 1 Robet Millikan (1868 1953) m + q V b The Millikan Expeiment:

More information

Paths of planet Mars in sky

Paths of planet Mars in sky Section 4 Gavity and the Sola System The oldest common-sense view is that the eath is stationay (and flat?) and the stas, sun and planets evolve aound it. This GEOCENTRIC MODEL was poposed explicitly by

More information

Basic oces an Keple s Laws 1. Two ientical sphees of gol ae in contact with each othe. The gavitational foce of attaction between them is Diectly popotional to the squae of thei aius ) Diectly popotional

More information

Chapter 13: Gravitation

Chapter 13: Gravitation v m m F G Chapte 13: Gavitation The foce that makes an apple fall is the same foce that holds moon in obit. Newton s law of gavitation: Evey paticle attacts any othe paticle with a gavitation foce given

More information

CHAPTER 5: Circular Motion; Gravitation

CHAPTER 5: Circular Motion; Gravitation CHAPER 5: Cicula Motion; Gavitation Solution Guide to WebAssign Pobles 5.1 [1] (a) Find the centipetal acceleation fo Eq. 5-1.. a R v ( 1.5 s) 1.10 1.4 s (b) he net hoizontal foce is causing the centipetal

More information

PHYSICS 1210 Exam 2 University of Wyoming 14 March ( Day!) points

PHYSICS 1210 Exam 2 University of Wyoming 14 March ( Day!) points PHYSICS 1210 Exam 2 Univesity of Wyoming 14 Mach ( Day!) 2013 150 points This test is open-note and closed-book. Calculatos ae pemitted but computes ae not. No collaboation, consultation, o communication

More information

Physics 4A Chapter 8: Dynamics II Motion in a Plane

Physics 4A Chapter 8: Dynamics II Motion in a Plane Physics 4A Chapte 8: Dynamics II Motion in a Plane Conceptual Questions and Example Poblems fom Chapte 8 Conceptual Question 8.5 The figue below shows two balls of equal mass moving in vetical cicles.

More information

Lecture 22. PE = GMm r TE = GMm 2a. T 2 = 4π 2 GM. Main points of today s lecture: Gravitational potential energy: Total energy of orbit:

Lecture 22. PE = GMm r TE = GMm 2a. T 2 = 4π 2 GM. Main points of today s lecture: Gravitational potential energy: Total energy of orbit: Lectue Main points of today s lectue: Gavitational potential enegy: Total enegy of obit: PE = GMm TE = GMm a Keple s laws and the elation between the obital peiod and obital adius. T = 4π GM a3 Midtem

More information

ω = θ θ o = θ θ = s r v = rω

ω = θ θ o = θ θ = s r v = rω Unifom Cicula Motion Unifom cicula motion is the motion of an object taveling at a constant(unifom) speed in a cicula path. Fist we must define the angula displacement and angula velocity The angula displacement

More information

Physics 107 TUTORIAL ASSIGNMENT #8

Physics 107 TUTORIAL ASSIGNMENT #8 Physics 07 TUTORIAL ASSIGNMENT #8 Cutnell & Johnson, 7 th edition Chapte 8: Poblems 5,, 3, 39, 76 Chapte 9: Poblems 9, 0, 4, 5, 6 Chapte 8 5 Inteactive Solution 8.5 povides a model fo solving this type

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion Have you eve idden on the amusement pak ide shown below? As it spins you feel as though you ae being pessed tightly against the wall. The ide then begins to tilt but you emain glued

More information

PHYSICS 220. Lecture 08. Textbook Sections Lecture 8 Purdue University, Physics 220 1

PHYSICS 220. Lecture 08. Textbook Sections Lecture 8 Purdue University, Physics 220 1 PHYSICS 0 Lectue 08 Cicula Motion Textbook Sections 5.3 5.5 Lectue 8 Pudue Univesity, Physics 0 1 Oveview Last Lectue Cicula Motion θ angula position adians ω angula velocity adians/second α angula acceleation

More information

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun Chapte 12 Gavitation PowePoint Lectues fo Univesity Physics, Twelfth Edition Hugh D. Young and Roge A. Feedman Lectues by James Pazun Modified by P. Lam 5_31_2012 Goals fo Chapte 12 To study Newton s Law

More information

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature)

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature) a = c v 2 Recap Centipetal acceleation: m/s 2 (towads cente of cuvatue) A centipetal foce F c is equied to keep a body in cicula motion: This foce poduces centipetal acceleation that continuously changes

More information

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE VISUAL PHYSICS ONLINE MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES SATELLITES: Obital motion of object of mass m about a massive object of mass M (m

More information

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions )

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions ) 06 - ROTATIONAL MOTION Page ) A body A of mass M while falling vetically downwads unde gavity beaks into two pats, a body B of mass ( / ) M and a body C of mass ( / ) M. The cente of mass of bodies B and

More information

Chapter 12. Kinetics of Particles: Newton s Second Law

Chapter 12. Kinetics of Particles: Newton s Second Law Chapte 1. Kinetics of Paticles: Newton s Second Law Intoduction Newton s Second Law of Motion Linea Momentum of a Paticle Systems of Units Equations of Motion Dynamic Equilibium Angula Momentum of a Paticle

More information

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b,

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b, SAMPLE QUIZ 3 - PHYSICS 1301.1 his is a closed book, closed notes quiz. Calculatos ae pemitted. he ONLY fomulas that may be used ae those given below. Define all symbols and justify all mathematical expessions

More information

EN40: Dynamics and Vibrations. Midterm Examination Thursday March

EN40: Dynamics and Vibrations. Midterm Examination Thursday March EN40: Dynamics and Vibations Midtem Examination Thusday Mach 9 2017 School of Engineeing Bown Univesity NAME: Geneal Instuctions No collaboation of any kind is pemitted on this examination. You may bing

More information

SIO 229 Gravity and Geomagnetism. Lecture 6. J 2 for Earth. J 2 in the solar system. A first look at the geoid.

SIO 229 Gravity and Geomagnetism. Lecture 6. J 2 for Earth. J 2 in the solar system. A first look at the geoid. SIO 229 Gavity and Geomagnetism Lectue 6. J 2 fo Eath. J 2 in the sola system. A fist look at the geoid. The Thee Big Themes of the Gavity Lectues 1.) An ellipsoidal otating Eath Refeence body (mass +

More information

HW Solutions # MIT - Prof. Please study example 12.5 "from the earth to the moon". 2GmA v esc

HW Solutions # MIT - Prof. Please study example 12.5 from the earth to the moon. 2GmA v esc HW Solutions # 11-8.01 MIT - Pof. Kowalski Univesal Gavity. 1) 12.23 Escaping Fom Asteoid Please study example 12.5 "fom the eath to the moon". a) The escape velocity deived in the example (fom enegy consevation)

More information

Physics 1114: Unit 5 Hand-out Homework (Answers)

Physics 1114: Unit 5 Hand-out Homework (Answers) Physics 1114: Unit 5 Hand-out Homewok (Answes) Poblem set 1 1. The flywheel on an expeimental bus is otating at 420 RPM (evolutions pe minute). To find (a) the angula velocity in ad/s (adians/second),

More information

Solving Problems of Advance of Mercury s Perihelion and Deflection of. Photon Around the Sun with New Newton s Formula of Gravity

Solving Problems of Advance of Mercury s Perihelion and Deflection of. Photon Around the Sun with New Newton s Formula of Gravity Solving Poblems of Advance of Mecuy s Peihelion and Deflection of Photon Aound the Sun with New Newton s Fomula of Gavity Fu Yuhua (CNOOC Reseach Institute, E-mail:fuyh945@sina.com) Abstact: Accoding to

More information

Midterm Exam #2, Part A

Midterm Exam #2, Part A Physics 151 Mach 17, 2006 Midtem Exam #2, Pat A Roste No.: Scoe: Exam time limit: 50 minutes. You may use calculatos and both sides of ONE sheet of notes, handwitten only. Closed book; no collaboation.

More information

20-9 ELECTRIC FIELD LINES 20-9 ELECTRIC POTENTIAL. Answers to the Conceptual Questions. Chapter 20 Electricity 241

20-9 ELECTRIC FIELD LINES 20-9 ELECTRIC POTENTIAL. Answers to the Conceptual Questions. Chapter 20 Electricity 241 Chapte 0 Electicity 41 0-9 ELECTRIC IELD LINES Goals Illustate the concept of electic field lines. Content The electic field can be symbolized by lines of foce thoughout space. The electic field is stonge

More information

Phys102 Second Major-182 Zero Version Monday, March 25, 2019 Page: 1

Phys102 Second Major-182 Zero Version Monday, March 25, 2019 Page: 1 Monday, Mach 5, 019 Page: 1 Q1. Figue 1 shows thee pais of identical conducting sphees that ae to be touched togethe and then sepaated. The initial chages on them befoe the touch ae indicated. Rank the

More information

Revision Guide for Chapter 11

Revision Guide for Chapter 11 Revision Guide fo Chapte 11 Contents Revision Checklist Revision Notes Momentum... 4 Newton's laws of motion... 4 Wok... 5 Gavitational field... 5 Potential enegy... 7 Kinetic enegy... 8 Pojectile... 9

More information

Quiz 6--Work, Gravitation, Circular Motion, Torque. (60 pts available, 50 points possible)

Quiz 6--Work, Gravitation, Circular Motion, Torque. (60 pts available, 50 points possible) Name: Class: Date: ID: A Quiz 6--Wok, Gavitation, Cicula Motion, Toque. (60 pts available, 50 points possible) Multiple Choice, 2 point each Identify the choice that best completes the statement o answes

More information

b) (5) What average force magnitude was applied by the students working together?

b) (5) What average force magnitude was applied by the students working together? Geneal Physics I Exam 3 - Chs. 7,8,9 - Momentum, Rotation, Equilibium Nov. 3, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults

More information

Gravity Notes for PHYS Joe Wolfe, UNSW

Gravity Notes for PHYS Joe Wolfe, UNSW Gavity Notes fo PHYS 111-1131. Joe Wolfe, UNSW 1 Gavity: whee does it fit in? Gavity [geneal elativity] Electic foce* gavitons photons Weak nuclea foce intemediate vecto bosons Stong nuclea foce Colou

More information

The Laws of Motion ( ) N SOLUTIONS TO PROBLEMS ! F = ( 6.00) 2 + ( 15.0) 2 N = 16.2 N. Section 4.4. Newton s Second Law The Particle Under a Net Force

The Laws of Motion ( ) N SOLUTIONS TO PROBLEMS ! F = ( 6.00) 2 + ( 15.0) 2 N = 16.2 N. Section 4.4. Newton s Second Law The Particle Under a Net Force SOLUTIONS TO PROBLEMS The Laws of Motion Section 4.3 Mass P4. Since the ca is moving with constant speed and in a staight line, the esultant foce on it must be zeo egadless of whethe it is moving (a) towad

More information

Chapter. s r. check whether your calculator is in all other parts of the body. When a rigid body rotates through a given angle, all

Chapter. s r. check whether your calculator is in all other parts of the body. When a rigid body rotates through a given angle, all conveted to adians. Also, be sue to vanced to a new position (Fig. 7.2b). In this inteval, the line OP has moved check whethe you calculato is in all othe pats of the body. When a igid body otates though

More information

DYNAMICS OF UNIFORM CIRCULAR MOTION

DYNAMICS OF UNIFORM CIRCULAR MOTION Chapte 5 Dynamics of Unifom Cicula Motion Chapte 5 DYNAMICS OF UNIFOM CICULA MOTION PEVIEW An object which is moing in a cicula path with a constant speed is said to be in unifom cicula motion. Fo an object

More information

10. Universal Gravitation

10. Universal Gravitation 10. Univesal Gavitation Hee it is folks, the end of the echanics section of the couse! This is an appopiate place to complete the study of mechanics, because with his Law of Univesal Gavitation, Newton

More information

Chap 5. Circular Motion: Gravitation

Chap 5. Circular Motion: Gravitation Chap 5. Cicula Motion: Gavitation Sec. 5.1 - Unifom Cicula Motion A body moves in unifom cicula motion, if the magnitude of the velocity vecto is constant and the diection changes at evey point and is

More information

Objects usually are charged up through the transfer of electrons from one object to the other.

Objects usually are charged up through the transfer of electrons from one object to the other. 1 Pat 1: Electic Foce 1.1: Review of Vectos Review you vectos! You should know how to convet fom pola fom to component fom and vice vesa add and subtact vectos multiply vectos by scalas Find the esultant

More information

Hoizontal Cicula Motion 1. A paticle of mass m is tied to a light sting and otated with a speed v along a cicula path of adius. If T is tension in the sting and mg is gavitational foce on the paticle then,

More information

Chapter 7. Rotational Motion Angles, Angular Velocity and Angular Acceleration Universal Law of Gravitation Kepler s Laws

Chapter 7. Rotational Motion Angles, Angular Velocity and Angular Acceleration Universal Law of Gravitation Kepler s Laws Chapte 7 Rotational Motion Angles, Angula Velocity and Angula Acceleation Univesal Law of Gavitation Keple s Laws Angula Displacement Cicula motion about AXIS Thee diffeent measues of angles: 1. Degees.

More information

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS LSN 10-: MOTION IN A GRAVITATIONAL FIELD Questions Fom Reading Activity? Gavity Waves? Essential Idea: Simila appoaches can be taken in analyzing electical

More information

Centripetal Force. Lecture 11. Chapter 8. Course website:

Centripetal Force. Lecture 11. Chapter 8. Course website: Lectue 11 Chapte 8 Centipetal Foce Couse website: http://faculty.uml.edu/andiy_danylov/teaching/physicsi PHYS.1410 Lectue 11 Danylov Depatment of Physics and Applied Physics Today we ae going to discuss:

More information

GRAVITATION. Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., New Delhi -18 PG 1

GRAVITATION. Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., New Delhi -18 PG 1 Einstein Classes, Unit No. 0, 0, Vahman Ring Roa Plaza, Vikas Pui Extn., New Delhi -8 Ph. : 96905, 857, E-mail einsteinclasses00@gmail.com, PG GRAVITATION Einstein Classes, Unit No. 0, 0, Vahman Ring Roa

More information

Tidal forces. m r. m 1 m 2. x r 2. r 1

Tidal forces. m r. m 1 m 2. x r 2. r 1 Tidal foces Befoe we look at fee waves on the eath, let s fist exaine one class of otion that is diectly foced: astonoic tides. Hee we will biefly conside soe of the tidal geneating foces fo -body systes.

More information

constant t [rad.s -1 ] v / r r [m.s -2 ] (direction: towards centre of circle / perpendicular to circle)

constant t [rad.s -1 ] v / r r [m.s -2 ] (direction: towards centre of circle / perpendicular to circle) VISUAL PHYSICS ONLINE MODULE 5 ADVANCED MECHANICS NON-UNIFORM CIRCULAR MOTION Equation of a cicle x y Angula displacement [ad] Angula speed d constant t [ad.s -1 ] dt Tangential velocity v v [m.s -1 ]

More information

Spring 2001 Physics 2048 Test 3 solutions

Spring 2001 Physics 2048 Test 3 solutions Sping 001 Physics 048 Test 3 solutions Poblem 1. (Shot Answe: 15 points) a. 1 b. 3 c. 4* d. 9 e. 8 f. 9 *emembe that since KE = ½ mv, KE must be positive Poblem (Estimation Poblem: 15 points) Use momentum-impulse

More information

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer.

15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer. Kiangsu-Chekiang College (Shatin) F:EasteHolidaysAssignmentAns.doc Easte Holidays Assignment Answe Fom 6B Subject: Physics. (a) State the conditions fo a body to undego simple hamonic motion. ( mak) (a)

More information

Physics 201 Homework 4

Physics 201 Homework 4 Physics 201 Homewok 4 Jan 30, 2013 1. Thee is a cleve kitchen gadget fo dying lettuce leaves afte you wash them. 19 m/s 2 It consists of a cylindical containe mounted so that it can be otated about its

More information

Orbits. Newton suggested that an object could be put into orbit if it were launched from a high hill at a high speed

Orbits. Newton suggested that an object could be put into orbit if it were launched from a high hill at a high speed Satellites & Obits Obits Newton suggested that an object could be put into obit if it wee launched fom a high hill at a high speed If the launch speed was high enough, the object would fall aound Eath

More information

AY 7A - Fall 2010 Section Worksheet 2 - Solutions Energy and Kepler s Law

AY 7A - Fall 2010 Section Worksheet 2 - Solutions Energy and Kepler s Law AY 7A - Fall 00 Section Woksheet - Solutions Enegy and Keple s Law. Escape Velocity (a) A planet is obiting aound a sta. What is the total obital enegy of the planet? (i.e. Total Enegy = Potential Enegy

More information

AP Physics - Coulomb's Law

AP Physics - Coulomb's Law AP Physics - oulomb's Law We ve leaned that electons have a minus one chage and potons have a positive one chage. This plus and minus one business doesn t wok vey well when we go in and ty to do the old

More information