# Abstract Algebra, Second Edition, by John A. Beachy and William D. Blair. Corrections and clarifications

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9 read page 373, line 3 For x read x 3 1 page 373, line 4 For x 3 1 read x To show uniqueness, let (a/b)f (x) = (c/d)g (x), where g (x) is primitive and c and d have no irreducible factors in common. Then adf (x) = bcg (x), so the irreducible factors of ad and bc must be the same. Since a and b have no irreducible factors in common and D is a unique factorization domain, we see that a and c are associates, and that b and d are associates. Thus f (x) and g (x) are associates. page 373, line 12 For the defining identity read the defining equation page 393, line -14 For (z + w) = z + w and (zw) = zw. read z + w = z + w and zw = z w. page 413, line -3 For [x + 1] [0] [x + 1] [x + 1] [x + 1] read [x + 1] [0] [x + 1] [x + 1] [0] 9 Last revision: 2/22/2005

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