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1 Serial : SK1_U+I_CE_Surveying Engineering_ Delhi oida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubaneswar Kolkata Patna Web: info@madeeasy.in Ph: CLASS TEST CIVIL EGIEERIG Subject : Surveying Engineering Date of test : 01/09/018 Answer Key 1. (a) 7. (c) 13. (b) 19. (d) 5. (d). (c) 8. (a) 14. (c) 0. (d) 6. (a) 3. (c) 9. (c) 15. (b) 1. (c) 7. (c) 4. (c) 10. (b) 16. (a). (d) 8. (d) 5. (d) 11. (c) 17. (b) 3. (a) 9. (b) 6. (d) 1. (c) 18. (c) 4. (a) 30. (c)

2 6 Civil Engineering Detailed Explanations 1. (a) Correction per chain (l l ) l l + 0.1m ( ) Correction per metre l l' l Total correction, C a m Correct distance, L m. (c) Original distance between two points as per to old plan Scale Distance on plan m ew scale, 1 cm 80 m Distance between two points on new plan Original distance between two points ew Scale Alternate method cm 80 (R.F.) initially 1 Map distance Original distance Original distance m 100 (R.F.) initially 1 Map distance Original distance Map distance cm (c) The refraction error can not be fully eliminated as there is always a possibility that the air may get changed during shifting from one location to another. 5. (d) (i) Radiation: In this method a ray is drawn from the instrument station towards the point, the distance is measured between the instrument station and that point, and the point is located by plotting to some scale the distance so measured. (ii) Lehmann s method : It is a trial and error method of establishing location of station on plan. (iii) Intersection : It is the method of plotting the location of an object on plan by sighting at the object from two plane table stations which are already plotted. (iv) Resection : The method consist in drawing two rays to the two points of known location on the plan after the table has been oriented. The rays drawn from the unplotted location of the station to the points of known location are called resectors, the intersection of which gives the required location of the instrument stations.

3 CT-018 CE Surveying Engineering 7 6. (d) Horizontal distance l cosθ 48 cos m 11. (c) As the Fore Bearing and Back Bearing of line EA differ exactly by 180, stations E and A are free from local attraction. Therefore, the Fore Bearing of AB and Back Bearing of DE are also free from local attraction. First Method E D A B C Correct FB of DE Error at D Correction at D + 30 Correct BB of CD Correct FB of CD Error at C Correction at C Correct BB of BC Correct FB of BC Error at B Correction at B +15 Correct BB of AB Correct FB of AB Error at A Second Method Also A B (exterior) (interior) C (exterior) (interior) D E Sum of included angles ( 4) 90 ( 5 4) There is no error in the sum of the included angles. As there is no local attraction at A, the F.B. of AB is correct. Correct B.B. of AB Correct F.B. of BC B Correct B.B. of BC Correct F.B. of CD Correct B.B. of CD Correct F.B. of DE Correct B.B. of DE As there is no local attraction at E, the computed B.B. of DE is equal to the observed bearing.

4 8 Civil Engineering 13. (b) C River True orth B 150m P m A tan PAB PAB APC ACP 180 PAB APC BCP BC PB tan BCP 11.5 m 14. (c) Since the distance of P from instrument is small, the correction for curvature etc. is negligible but this is not negligible for station Q. Combined correction for Q (1.80) m (subtractive) Correct staff reading at Q Difference in elevation between P and Q m (Q being lower) 15. (b) Staff intercept m Position of centre of bubble in first deviated condition divisions towards eye-piece. Position of centre of bubble in second deviated position division towards object glass. Total movement of the bubble division nd l R 5.64 m S (b) Shrinkage factor Reduced plan area (Shrinkage factor) Actual plan area 34 (0.9) Actual plan area Actual plan area 400 cm Actual area of survey in m 400 (0)

5 CT-018 CE Surveying Engineering (c) Distance of the observer from the point 0 where line of sight laches the surface of sea d km. Distance of light house d km. Total distance from observer to light house d 1 + d km d D 4 m A d 1 C 64 O 19. (d) For a closed transverse ΣL 0 00 cos cos cos10 + L cosθ 0 L cosθ (i) ΣD 0 00 sin sin sin10 + L sinθ L sinθ 0 L sinθ (ii) From equation (i) and (ii), tanθ 3.50 θ 7.91 ~ 73 θ 5.91 ~ 53 L ~ 1555 m sin53 0. (d) Let the vertical angle is θ True horizontal distance D ks cos θ Sloping distance L ks Permissible error is in 500 Sloping distance Horizontal distance ks sec θ ks cos θ So L D sec θ θ 3.6

6 10 Civil Engineering 1. (c) Rod Reading (m) v (m) v Mean :.31 Σ v From equation, E s ± ± metre 8 1 E and E m s ± ± metre. n 8. (d) Starting from the point 7, the R.L. of point 6 is obtained. H.I. at point R.I. of point H.I. of point 3 B.M B.S.(m) I.S.(m) F.S.(m) H.I.(m) R.L.(m) Remarks Point Point Point B.M Point Point 5 Staff Inverted Point Point Arithmetic Check R.L. of point R.L. of point I.S. at point F.S. at point H.I. at point I.S. at point B.S. F.S. Last R.L. First R.L (O.K)

7 CT-018 CE Surveying Engineering (a) (i) (ii) (iii) (iv) Correction for pull: Correction for temperature: Correction for slope: Correction for mean sea level: ( P ) 0 C p P L AE ( ) m( + ) ve C t α (T m T o ) L (35 15) m (+ve) h L C d 10 m( ve) C R h L m ( ve) R Total correction m Corrected length of the base line m 4. (a) Height of transit station H d sinα H d H α sinα sin , e α 30, e d 0.08 m d cosα 00 cos m e H H H e L e + α d α 5. (d) d r ( ) + ( ) ± 0.95 m h H d hr H where, d relief displacement H flying height d will decrease with increase in flying height (H) and d will decrease with decrease in r and h.

8 1 Civil Engineering 6. (a) 7. (c) Lh C h 0.01 m R Equivalent length, L e m Ground speed m/s km/h 5 8. (d) Difference in longitude 90 E 8 30 E 7 30 E 30 min Hence the place is east of meridian Standard Time LMT Difference in longitudes LMT 8 hour 30 min + 30 min 9 hour 00 min

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