AIPMT 2014 TEST PAPER WITH SOLUTIONS (HELD ON SUNDAY 04 th MAY, 2014)

Size: px
Start display at page:

Download "AIPMT 2014 TEST PAPER WITH SOLUTIONS (HELD ON SUNDAY 04 th MAY, 2014)"

Transcription

1 6. What is the maximum umber of orbitals that ca be idetified ith the folloig quatum umbers? =, =, m = 0 () () () () =, =, m = 0 rbital is p z. 7. Calculate the eergy i joule correspodig to light of avelegth 5 m : (lack's costat h = Js; speed of light c = 0 8 ms ) () () (). 0 5 (). 0 8 E = hc = E =. 0 8 J 8. Equal masses of, ad methae have bee take i a cotaier of volume V at temeprature 7 C i idetical coditios. The ratio of the volumes of gases : : methae ould be : () 8 : 6 : () 6 : 8 : () 6 : : () 8 : : Accordig to Avogadro's hypothesis volume moles C So, ratio is 6 : : 6 = 6 : : 9. If a is the legth of the side of a cube, the distace betee the body cetered atom ad oe corer atom i the cube ill be : () () a a AIMT 0 TEST AER WIT SLUTINS (ELD N SUNDAY 0 th MAY, 0) () () a a CDE- The distace betee the body cetred atom ad oe corer atom is a 50. Which property of colloids is ot depedet o the charge o colloidal particles? () Coagulatio () Electrophoresis () Electro - osmosis () Tyadall effect Tydall effect is optical property. 5. Which of the folloig salts ill give highest p i ater? () KCl () NaCl () Na C () CuS Na C ill give highest p i ater because it is salt of strog base ad eak acid 5. f the folloig 0.0m aqueous solutios, hich oe ill exhibit the largest freezig poit depressio? () KCl () C 6 6 () Al (S ) () K S Depressio i freezig poit vat off's factor (i) for Al (S ) i = 5 5. Whe. litres of (g) is mixed ith. litres of Cl (g), each at S.T.., the moles of Cl (g) formed is equal to :- () mol of Cl (g) () mol of Cl (g) () 0.5 mol of Cl (g) ().5 mol of Cl (g) V(L). =.L. =. Cl = 0.5 mole. (g) Cl (g) Cl (g) iitially - mole 0.5 mole 0 after reactio (-0.5) 0.5 =0.5 mole 0 = mole

2 AIMT-0 5. Whe 0. mol M is oxidised the quatity of electricity required to completely oxidise to M is :- () C () C () 9650 C () C 6 M 7 M e M 0. mole 0. mole charge required = 0. F = = 9650 C 55. Usig the Gibbs eergy chage, G = 6.kJ, for the folloig ractio, Ag C Ag (aq) C (aq) the K sp of Ag C (s) i ater at 5 C is :- (R = 8. J K mol ) (). 0 6 () ().9 0 () As. () G =.0 RT log K sp = log Ksp log Ksp =.09 Ksp = 0.09 = The eight of silver (at t. = 08) displaced by a quatity of electricity hich displaces 5600 ml of at ST ill be :- () 5. g () 0.8 g () 5.9 g () 08.0 g Accordig to faraday's d la E Ag Ag E 600 Ag Ag = 08g 57. Which of the folloig statemets is correct for the spotaeous adsorptio of a gas? () S is egative ad, therefore, should be highly positive () S is egative ad therefore, should be highly egative () S is positive ad, therefore, should be egative () S is positive ad, therefore, should also be highly positive As. () Durig adsorptio etropy decreases, so S < 0. G = TS For spotaeous adsorptio G < 0 so should be highly egative. 58. For the reactio : X () X (g) U =. k cal, S = 0 cal K at 00 K ece G is :- ().7 k cal ().7 k cal () 9. k cal () 9. k cal Accordig to Le-Chatelier's riciple I exothermic reactios lo temperature favours the forard reactio icreasig pressure equilibrium shifts toards less umber of moles. 59. For a give exothermic reactio, K p ad K are the equilibrium costats at temperatures T ad T, respectively. Assumig that heat of reactio is costat i temperature rage betee T ad T, it is readily observed that :- () K p > K () K p < K () K p = K () K p = K As. () X () X (g); g = 0 = = U g RT =. =. kcal G = T.S = ; G =.7 Kcal 60. Which of the folloig orders of ioic radii is correctly represeted? () > > () Na > F > () F > > Na () Al > Mg > N I exothermic reactios o icreasig temperature value of K p decreases. So, K p > K p '

3 CDE g of magesium is burt ith 0.56 g i a closed vessel. Which reactat is left i excess ad ho much? (At. t. Mg = ; = 6) () Mg, 0.6 g (), 0.6 g () Mg, 0. g (), 0.8 g As. (B) 6. The pair of compouds that ca exist together is:- () Mg, 0.6 g (), 0.6 g () Mg, 0. g (), 0.8 g Mg = Iitially mole, = 0.56 moles Mg(s) (g) mole 0.56 mole Mg(s) 0.06 mole mole 0 after ( ) mole reactio mole mass of Mg = g = 0.6 g 6. The pair of compouds that ca exist together is:- () FeCl, SCl () gcl, SCl () FeCl, SCl () FeCl, Kl Both are reducig aget 6. Be is isoelectroic ith hich of the folloig ios? () () Li () Na () Mg As. () Li, Be & Li both have electro. 65. Which of the folloig molecules has the maximum dipolemet? () C () C () N () NF N > F N F µ =. D 0. D F 66. Which oe of the folloig species has plae triagular shape? As. () () N () N () N () C N has sp hybridisatio i.e. hy has plaar shape. 67. Acidity of diprotic acids i aqueous solutios icreases i the order :- () S < Se < Te () Se < S < Te () Te < S < Se () Se < Te < S movig do the group bod legth icreases so liberatio tedecy of ill be more. 68. (a) (b) Ag Ag Role of hydroge peroxide i the above reactios is respectively - () xidizig i (a) ad reducig i (b) () Reducig i (a) ad oxidizig i (b) () Reducig i (a) ad (b) () xidizig i (a) ad (b) 69. Artificial seeter hich is stable uder cold coditios oly is :- () Saccharie () Sucralose () Aspartame () Alitame 70. I acidic medium, chages Cr to Cr 7 5 hich has to ( ) bods. xidatio state of Cr i Cr 5 is :- () 5 () () 6 () 0 Cr Cr 5 has peroxy likage.

4 AIMT-0 7. The reactio of aqueous KM ith i acidic coditios gives :- () M ad () M ad () M ad () M ad M As. () KM is a strog oxidisig aget & ll oxidise to. 7. Amog the folloig complexes the oe hich shos Zero crystal field stabilizatio eergy (CFSE):- () [M( ) 6 ] () [Fe( ) 6 ] () [Co( ) 6 ] () [Co( ) 6 ] As. () Due to d 5 cofiguratio ad is a eak ligad. 7. Magetic momet.8 BM is give by hich of the folloig ios? (At. os. Ti =, Cr =, M = 5, Ni = 8):- () Ti () Ni () Cr () M As. () Ni has to upaired electro. 7. Which of the folloig complexes is :- () mer-[co(n ) Cl ] () cis-[tcl (N ) ] () cis-k [tcl ] () Na CoCl As. () Cis-plati is used as a aticacer uit. 75. Reaso of lathaoid cotractio is :- () Negligible screeig effect of 'f' orbitals () Icreasig uclear charge () Decreasig uclear charge () Decreasig screeig effect Due to poor shieldig of f-orbitals ucleus ill exert a strog attractio. Cauces lathaoid cotractio. 76. I the folloig reactio, the product (A) NNCl N () N=N N N () N=N () N=N N () N=N N (A) is :- Yello dye This is a example of electrophilic substritituio reactio [couplig reactio] N N.Cl N = N N p-aioazobezee (yello dye) Cl N 77. Which of the folloig ill be most stable diazoium salt RN X? () N X () C 6 5 N X () C N X () C 6 5 C N X As. () rimary aliphatic amies form highly ustable alkyldiazoium salts. rimary aromatic amies form aree diazoium salts hich are stable for a short time i solutio at lo temperature (7 78 K). The stability of areediazoium ca be explaied o the basis of resoace. Salt N N N = N: N = N: N = N: 78. D () glucose reacts ith hydroxylamie ad yields a oxime. The structure of the oxime ould be : () () C = N C C C C C C C = N C C C C () () C = N C C C C C C = N C C C C C

5 CDE- Glucose reacts ith hydroxyl amie to form a oxime. C C D()glucose N- C=N C 79. Which of the folloig hormoes is produced uder the coditio of stress hich stimulates glycogeolysis i the liver of huma beigs? () Thyroxi () Isuli () Adrealie () Estradiol Adrealie commoly ko as fight or flight hormoe, it is produced by the adreal glads after recevig a message from the brai that a stressful situatio has preseted itself. 80. Which oe of the folloig is a example of a thermosettig polymer? () () () () ( C C = C C ) Cl ( C C ) Cl ( N (C ) 6 N C (C ) C ) C C Thermosettig polymers are cross liked or heavily brached molecules, hich o heatig udergo extesive cross likig i moulds ad agai become i fusible. Most commo examples are bakelite. 8. Which of the folloig orgaic compouds polymerizes to form the polyester Dacro? () ropylee ad para (C 6 ) () Bezoic acid a ethaol () Terephthalic acid ad ethylee glycol () Bezoic acid ad para (C 6 ) Dacro or terylee is the best ko example of polyesters. It is maufactured by heatig a mixture of ethylee glycol ad terephthalic acid at 0 to 60 K i the presece of zic acetate-atimaoy trioxide catalyst. C C Ethylee glycol [Ethae-,-diol] C Terephthalic acid [Bezee-,-di carboxylic acid] C C C C Terylee or Dacro C 8. Which of the folloig is ot a commo compoet of hotochemical Smog? () zoe () Acrolei () eroxyacetyl itrate () Chlorofluorocarbos The commo compoets of photochemical smog are ozoe, itric oxide, ocrolei, for malde yde ad peroxyacehyl itrate (AN). ece (FC is ot commo compoet of photochemical smog. 8. I the Kjeldahl's method for estimatio of itroge preset i a soil sample, ammoia evolved from 0.75 g of sample eutralized 0 ml of M S. The percetage of itroge i the soil is : () 7. () 5. () 5. (). M V (ml) = m mol 0 m mol S = 0 m mol of N [ S N (N ) S ] mol N cotais g itroge 0 0 mol N cotais 0 0 itroge 0.75 g of sample cotais % Nitroge = = 7.% 5

6 AIMT-0 8. What products are formed he the folloig compouds is treated ith i the presece of Fe? I the above compoud,-dimethylbezee, sites for the attackig electrophile are c a b () () () () ad ad ad ad attack of electrophile o sites b & c results i same compoud as product. Although tedecy of electrophile to attack o site a is very less due to high steric hiderace so respective product is favoured ith very very less amout. 85. Which of the folloig compouds ill udergo racemisatio he solutio of K hydrolyses? (i) C Cl (ii) C C Cl (iii) (iv) C C CCl C C 5 Cl () (i) ad (ii) () (ii) ad (iv) () (iii) ad (iv) As. (,) () (i) ad (iv) As. (B) Fe (major) (mior) ly compoud (iv) C Cl results i C 5 formatio of racemic product due to chirality. 6

7 CDE- 86. Amog the folloig sets of reactats hich oe produces aisole? () C ; RMgX () C 6 5 ; Na ; I () C 6 5 ; eutral FeCl Reactivity of carboyl compouds toards NAR depeds o steric ad electroic effects. NAR reactivity : C C C C As. () () C 6 5 ; CCl; AlCl > > > N Na Na CI (SN ) 87. Which of the folloig ill ot be soluble i sodium hydroge carboate? (),, 6-triitropheol () Bezoic acid () o-nitropheol () Bezeesulphoic acid N Na Co carboic acid hile..6-triitro pheot, bezoic acid ad bezee sulphoic acid are sobuble i Na. R Acid NaC salt Co Reactio is possible i forard directio if acid is more acidic the Co. -itropheol is less acidic tha Co, hece does ot soluble i sodium hydroge carboate. 88. Which oe is most reactive toards Nucleophilic additio reactio? () C () C M of N icrease ()ve charge o sp c of 89. Idetify Z i the sequece of reactios: / C C = C () (C ) C () ( ) )C C () (C ) C C5Na Y () C C( ) C / C C=C (eroxide effect) C C C (y) Z C (C ) C C (z) 90. Which of the folloig orgaic compouds has same hybridizatio as its combustio product (C )? () Ethae () Ethye () Ethee () Ethaol As. () C C 5 C C () () N Both CC & C has same hybridisatio of carbo atom. (sp). 7

Practice Questions for Exam 3 CH 1020 Spring 2017

Practice Questions for Exam 3 CH 1020 Spring 2017 Practice Questios for Exam 3 C 1020 Sprig 2017 1. Which of the followig ca be cosidered a Brøsted-Lowry base? 5. What is the p of a solutio for which [Ba(O) 2 ] = 0.015 M? 6. The figure below shows three

More information

CHAPTER 11. Practice Questions (a) OH (b) I. (h) NH 3 CH 3 CO 2 (j) C 6 H 5 O - (k) (CH 3 ) 3 N conjugate pair

CHAPTER 11. Practice Questions (a) OH (b) I. (h) NH 3 CH 3 CO 2 (j) C 6 H 5 O - (k) (CH 3 ) 3 N conjugate pair CAPTER 11 Practice Questios 11.1 (a) O (b) I (c) NO 2 (d) 2 PO 4 (e) 2 PO 4 (f) 3 PO 4 (g) SO 4 (h) N 3 (i) C 3 CO 2 (j) C 6 5 O - (k) (C 3 ) 3 N 11.3 cojugate pair PO 3 4 (aq) C 3 COO(aq) PO 2 4 (aq)

More information

Section 7.4: Calculations Involving Limiting Reagents

Section 7.4: Calculations Involving Limiting Reagents Sectio 7.4: Calculatios Ivolvig Limitig Reagets Tutorial 1 Practice, page 33 1. Give:.3 mol ;.0 mol HNO = 3 Required: amout of water, NaCO = 3 O H Solutio: Step 1. List the give values ad the required

More information

Chemistry 104 Chapter 17 Summary and Review Answers

Chemistry 104 Chapter 17 Summary and Review Answers Chemistry 104 Chapter 17 Summary ad Review Aswers 1. You eed to make a buffer with a ph of 4.80. You have 0.150 M sodium hydroxide, 0.150 M acetic acid ad 0.150 M sodium bicarboate. What do you do? (Make

More information

Name ID# Section # CH 1020 EXAM 3 Spring Form A

Name ID# Section # CH 1020 EXAM 3 Spring Form A Name ID# Sectio # CH 1020 EXAM 3 Sprig 2016 - Form A Fill i your ame, ID#, ad sectio o this test booklet. Fill i ad bubble i your ame, ID# (bubble 0 for C ), ad sectio o the scatro form. For questio #60

More information

Q. No. PHYSICS CHEMISTRY MATHEMATICS

Q. No. PHYSICS CHEMISTRY MATHEMATICS AITS-CRT-I (Paper-)-PCM(Sol)-JEE(Advaced)/5 FIITJEE Studets From All Programs have bagged 4 i Top 00, 66 i Top 00 ad 74 i Top 500 All Idia Raks. FIITJEE Performace i JEE (Advaced), 04: 5 FIITJEE Studets

More information

ALDEHYDES AND KETONES

ALDEHYDES AND KETONES ALDEHYDES AND KETONES Itroductio The group C=O is kow as carboyl group. This group is foud i aldehydes, ketoes, carboxylic acids, esters ad acid derivatives. I this group carbo atom makes sp hybridizatio.

More information

Material Balances on Reactive Processes F&R

Material Balances on Reactive Processes F&R Material Balaces o Reactive Processes F&R 4.6-4.8 What does a reactio do to the geeral balace equatio? Accumulatio = I Out + Geeratio Cosumptio For a reactive process at steady-state, the geeral balace

More information

Polymerization Lab p. 1 Polymerization Lab

Polymerization Lab p. 1 Polymerization Lab Polymerizatio Lab p. 1 Polymerizatio Lab Itroductio: Polymers (Greek-PLY...may ad MES...parts) have existed sice the begiig of life. Both "atural" ad "sythetic" polymers are a itegral part of our life.

More information

Chapter 14: Chemical Equilibrium

Chapter 14: Chemical Equilibrium hapter 14: hemical Equilibrium 46 hapter 14: hemical Equilibrium Sectio 14.1: Itroductio to hemical Equilibrium hemical equilibrium is the state where the cocetratios of all reactats ad products remai

More information

ChemGGuru. Questions & Answer CHEMISTRY

ChemGGuru. Questions & Answer CHEMISTRY CAREER PIT JEE Mai lie Paper JEE Mai lie Exam 09 [Memory Based Paper] Q. Which of the followig is amphoteric i ature As. [] ` Questios & Aswer th Jauary 09 Shift - I CHEMISTRY Mg(H ( Be(H Ca(H Sr(H Q.

More information

CHEE 221: Chemical Processes and Systems

CHEE 221: Chemical Processes and Systems CHEE 221: Chemical Processes ad Systems Module 3. Material Balaces with Reactio Part a: Stoichiometry ad Methodologies (Felder & Rousseau Ch 4.6 4.8 ot 4.6c ) Material Balaces o Reactive Processes What

More information

All Excuses must be taken to 233 Loomis before 4:15, Monday, April 30.

All Excuses must be taken to 233 Loomis before 4:15, Monday, April 30. Miscellaeous Notes The ed is ear do t get behid. All Excuses must be take to 233 Loomis before 4:15, Moday, April 30. The PYS 213 fial exam times are * 8-10 AM, Moday, May 7 * 8-10 AM, Tuesday, May 8 ad

More information

POLYMERS

POLYMERS POLYMERS Short Aswer Questios: **1.What is PHBV? How is it useful to ma? As. PHBV is Poly β-hydroxy butyrate-co- β-hydroxy valerate.it is a biodegradable polymer. It is used i speciality packig, orthopaedic

More information

SOLUTIONS Homogeeous mixture: Substaces which dissolve with each other thoroughly to form a uiform mixture is called homogeeous mixture. Eg: Water + Salt. Solutios: homogeeous mixture formed with two or

More information

IIT-JEE 2006 Solutions by MOMENTUM (questions based on memory of students) CHEMISTRY

IIT-JEE 2006 Solutions by MOMENTUM (questions based on memory of students) CHEMISTRY IIT JEE 006 IIT-JEE 006 Solutios by MMENTUM (questios based o memory of studets) CHEMISTRY INSTRUCTINS: (i) Questio o. 1 to 1 has oly oe correct optio. You will be awarded marks for right aswer ad 1 mark

More information

What Is Given? You know the solubility of magnesium fluoride is mol/l. [Mg 2+ ] = [MgF 2 ] = mol/l

What Is Given? You know the solubility of magnesium fluoride is mol/l. [Mg 2+ ] = [MgF 2 ] = mol/l 122. Magesium fluoride, MgF 2 (aq) has a molar solubility of 2.7 10 3 mol/l. Use this iformatio to determie the K sp value for the solid. You eed to calculate the K sp for magesium fluoride, MgF 2. You

More information

1. Collision Theory 2. Activation Energy 3. Potential Energy Diagrams

1. Collision Theory 2. Activation Energy 3. Potential Energy Diagrams Chemistry 12 Reactio Kietics II Name: Date: Block: 1. Collisio Theory 2. Activatio Eergy 3. Potetial Eergy Diagrams Collisio Theory (Kietic Molecular Theory) I order for two molecules to react, they must

More information

Nernst Equation. Nernst Equation. Electric Work and Gibb's Free Energy. Skills to develop. Electric Work. Gibb's Free Energy

Nernst Equation. Nernst Equation. Electric Work and Gibb's Free Energy. Skills to develop. Electric Work. Gibb's Free Energy Nerst Equatio Skills to develop Eplai ad distiguish the cell potetial ad stadard cell potetial. Calculate cell potetials from kow coditios (Nerst Equatio). Calculate the equilibrium costat from cell potetials.

More information

Chapter 5 Gases A Summary

Chapter 5 Gases A Summary Chapter 5 Gases A Summary 5. ressure A. roperties of gases. Gases uiformly fill ay cotaier. Gases are easily compressed 3. Gases mix completely with ay other gas 4. Gases exert pressure o their surroudigs

More information

MOLE CONCEPT. 6. (C) Equal volumes of gases have equal number of molecules (not atoms) at same temperature and pressure condition

MOLE CONCEPT. 6. (C) Equal volumes of gases have equal number of molecules (not atoms) at same temperature and pressure condition FOUNDTION BUILDER (OBJECTIVE). (D). (D). (B) MOLE CONCEPT 4. () Most stable isotope of carbo 5. (D) 6. (C) Equal volumes of gases have equal umber of molecules (ot atoms) at same temperature ad pressure

More information

Solutions to Equilibrium Practice Problems

Solutions to Equilibrium Practice Problems Solutios to Equilibrium Practice Problems Chem09 Fial Booklet Problem 1. Solutio: PO 4 10 eq The expressio for K 3 5 P O 4 eq eq PO 4 10 iit 1 M I (a) Q 1 3, the reactio proceeds to the right. 5 5 P O

More information

What Is Required? You need to find the molar concentration, c, of the ions in a solution of ammonium phosphate.

What Is Required? You need to find the molar concentration, c, of the ions in a solution of ammonium phosphate. Chemistry 11 Solutios Sectio 9.2 Solutio Stoichiometry Solutios for Practice Problems Studet Editio page 417 11. Practice Problem (page 417) If 8.5 g of pure ammoium phosphate, (NH 4 ) 3 PO 4 (s), is dissolved

More information

P 1 V V V T V V. AP Chemistry A. Allan Chapter 5 - Gases

P 1 V V V T V V. AP Chemistry A. Allan Chapter 5 - Gases A Chemistry A. Alla Chapter 5 - Gases 5. ressure A. roperties of gases. Gases uiformly fill ay cotaier. Gases are easily compressed 3. Gases mix completely with ay other gas 4. Gases exert pressure o their

More information

( ) 2n. 2 n( ) ( iii) P n n T T. E mv ev. 1 2 m v p

( ) 2n. 2 n( ) ( iii) P n n T T. E mv ev. 1 2 m v p PART B CHEMISTRY. At 300 K ad atm, 5 ml of a gaseous hydrocarbo requires 375 ml air cotaiig 0% O by volume for complete combustio. After combustio the gases occupy 330 ml. Assumig that the water formed

More information

4. Amines, Amides and Amino Acids

4. Amines, Amides and Amino Acids 4. Amies, Amides ad Amio Acids amig Amies These ed i amie. There is, however, rather cofusigly two ways of usig this suffix. The exam board ted to use the propylamie commo versio where the ame r propa-1-amie

More information

Zumdahl (pp [atomic properties] ), [ionic radii] )

Zumdahl (pp [atomic properties] ), [ionic radii] ) Chemistry 1B-AL Fall 2016 advetures lectures 7-8 Zumdahl (pp. 571-582 [atomic properties] ), 606-609 [ioic radii] ) 1 Chemistry 1B AL Electroic Structure ad Periodic Properties of Atoms 2 Zumdahl (pp.

More information

Check Your Solution The units for amount and concentration are correct. The answer has two significant digits and seems reasonable.

Check Your Solution The units for amount and concentration are correct. The answer has two significant digits and seems reasonable. Act o Your Strategy Amout i moles,, of Ca(CH 3 COO) 2 (aq): CaCH3COO 2 c V 0.40 mol/ L 0.250 L 0.10 mol Molar mass, M, of Ca(CH 3 COO) 2 (s): M 1 M 4 M 6 M 4M Ca CH COO 3 2 Ca C H O 1 40.08 g/mol 4 12.01

More information

A. Much too slow. C. Basically about right. E. Much too fast

A. Much too slow. C. Basically about right. E. Much too fast Geeral Questio 1 t this poit, we have bee i this class for about a moth. It seems like this is a good time to take stock of how the class is goig. g I promise ot to look at idividual resposes, so be cadid!

More information

Review Sheet for Final Exam

Review Sheet for Final Exam Sheet for ial To study for the exam, we suggest you look through the past review sheets, exams ad homework assigmets, ad idetify the topics that you most eed to work o. To help with this, the table give

More information

Chemical Kinetics CHAPTER 14. Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop. CHAPTER 14 Chemical Kinetics

Chemical Kinetics CHAPTER 14. Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop. CHAPTER 14 Chemical Kinetics Chemical Kietics CHAPTER 14 Chemistry: The Molecular Nature of Matter, 6 th editio By Jesperso, Brady, & Hyslop CHAPTER 14 Chemical Kietics Learig Objectives: Factors Affectig Reactio Rate: o Cocetratio

More information

9.4.3 Fundamental Parameters. Concentration Factor. Not recommended. See Extraction factor. Decontamination Factor

9.4.3 Fundamental Parameters. Concentration Factor. Not recommended. See Extraction factor. Decontamination Factor 9.4.3 Fudametal Parameters Cocetratio Factor Not recommeded. See Extractio factor. Decotamiatio Factor The ratio of the proportio of cotamiat to product before treatmet to the proportio after treatmet.

More information

Miscellaneous Notes. Lecture 19, p 1

Miscellaneous Notes. Lecture 19, p 1 Miscellaeous Notes The ed is ear do t get behid. All Excuses must be take to 233 Loomis before oo, Thur, Apr. 25. The PHYS 213 fial exam times are * 8-10 AM, Moday, May 6 * 1:30-3:30 PM, Wed, May 8 The

More information

Narayana IIT Academy

Narayana IIT Academy -0-8_Sr. IIT_IZ_Ph-I_JEE-ADV_New Model-_P_GTA-9_Key&Sol s Narayaa IIT Academy INDIA Sec: Sr.IIT_IZ GTA-9 Date: -0-8 Time: 0:00 PM to 05:00 PM NEW Model-(P) Ma Marks: 64 KEY & SLUTINS MATHS AB ABC 3 AB

More information

--Lord Kelvin, May 3rd, 1883

--Lord Kelvin, May 3rd, 1883 Whe you ca measure what you are speakig about ad express it i umbers, you kow somethig about it; but whe you caot measure it, whe you caot express it i umbers, you kowledge is of a meager ad usatisfactory

More information

What is the oxidation number of N in KNO3? Today. Review for our Quiz! K is +1, O is -2 molecule is no charge 1(+1) + 3(-2) = -5 N must be +5

What is the oxidation number of N in KNO3? Today. Review for our Quiz! K is +1, O is -2 molecule is no charge 1(+1) + 3(-2) = -5 N must be +5 Today What is the oxidatio umber of N i KNO3? Review for our Quiz! Thermo ad Electrochemistry What happes whe the coditios are ot stadard Nerst Equatio! A.!! 0! B.!! +1! C.!! -1! D.!! +3! E.!! +5 K is

More information

MOLE CONCEPT (MAIN) FOUNDATION BUILDER (OBJECTIVE) 1. (D) 2. (D) 3. (B) 4. (A) (Most stable isotope of carbon) 5. (D) 6.

MOLE CONCEPT (MAIN) FOUNDATION BUILDER (OBJECTIVE) 1. (D) 2. (D) 3. (B) 4. (A) (Most stable isotope of carbon) 5. (D) 6. FOUNDTION BUILDER (OBJECTIVE). (D). (D). (B) 4. () (Most stable isotope of carbo) 5. (D) 6. (C) 7. () Moles of gas = 5.6 0.5.4 Molecular weight of gas = 7.5 0 0.5 Hece NO. MOLE CONCEPT (MIN) 8. () Molecular

More information

N Goalby chemrevise.org

N Goalby chemrevise.org 21. olymers There are two types of polymerisatio additio ad codesatio Additio olymerisatio A additio polymer forms whe usaturated moomers react to form a polymer Moomers cotai = bods oly(alkees) are chemically

More information

The Advanced Placement Examination in Chemistry. Part II - Free Response Questions & Answers 1970 to Electrochemistry

The Advanced Placement Examination in Chemistry. Part II - Free Response Questions & Answers 1970 to Electrochemistry The Advaced Placemet Examiatio i Chemistry Part II - Free Respose Questios & Aswers 970 to 005 Electrochemistry Teachers may reproduce this publicatio, i whole or i part, i limited prit quatities for o-commercial,

More information

Free Radical Polymerization

Free Radical Polymerization Free Radical Polymerizatio Referece: Aspe Polymers: Uit Operatios ad Reactio Models, Aspe Techology, Ic., 2013. 1. Itroductio The free-radical bulk/solutio polymerizatio model is applicable to bulk ad

More information

NARAYANA. XI-REG (Date: ) Physics Chemistry Mathematics

NARAYANA. XI-REG (Date: ) Physics Chemistry Mathematics CPT-5 / XI-REG / 0..07 / Hits & Solutio CODE NARAYANA I I T / N E E T A C A D E M Y XI-REG XI-REG (Date: 0..07) Physics Chemistry Mathematics. 3. 6.. 3 3. 6. 3. 33. 63.. 3. 6. 5. 35. 65. 6. 3 36. 66. 7.

More information

Standard Potentials. Redox Reaction - the basics. Ch. 14 & 16 An Introduction to Electrochemistry & Redox Titrations. Standard Electrode Potentials

Standard Potentials. Redox Reaction - the basics. Ch. 14 & 16 An Introduction to Electrochemistry & Redox Titrations. Standard Electrode Potentials Red Reactio - the basics Ch. 4 & 6 Itroductio to lectrochemistry & Red Titratios Reduced Oxidizig get Reducig get Oxidized Red reactios: ivolve trasfer of electros from oe species to aother. Oxidizig

More information

CAREER POINT. CENTRAL BOARD OF SENIOR SECONDARY EXAMINATION CHEMISTRY (Theory) SOLUTIONS

CAREER POINT. CENTRAL BOARD OF SENIOR SECONDARY EXAMINATION CHEMISTRY (Theory) SOLUTIONS CAREER PINT MCK TEST PAPER CENTRAL BARD SENI SECNDARY EXAMINATIN CHEMISTRY (Theory) SLUTINS Sol. 1 Negative deviatio Sol. 9 (a) p-type, because I has 3 valece electros. Holes are produced which ca Sol.

More information

Announcements, Nov. 19 th

Announcements, Nov. 19 th Aoucemets, Nov. 9 th Lecture PRS Quiz topic: results Chemical through Kietics July 9 are posted o the course website. Chec agaist Kietics LabChec agaist Kietics Lab O Fial Exam, NOT 3 Review Exam 3 ad

More information

Advanced Chemistry Practice Problems

Advanced Chemistry Practice Problems Advaced hemistry Practice Problems Aqueous Equilibria: Buffer Actio 1. Questio: A small amout of HBr is added to a buffer which is 0.10 M HHO ad 0.15 M NaHO. What species i the buffer will eutralize the

More information

Chemistry for Students of Mechanical Engineering

Chemistry for Students of Mechanical Engineering Grudlage der hemie für Studierede des Maschiebaus, Prof. Dr. Meier hemistry for Studets of Mechaical Egieerig Friday, 4th October 2013, 15:00-18:00 No uauthorised resources (e.g. lecture otes, textbooks

More information

5.1 Energy Changes in Chemical and Nuclear Reactions

5.1 Energy Changes in Chemical and Nuclear Reactions Figure 1 Our use of fossil fuels is usustaiable. New sources of gree, sustaiable eergy are eeded to meet the world s growig demad. 5.1 Eergy Chages i Chemical ad Nuclear Reactios Our ability to haress

More information

Principle Of Superposition

Principle Of Superposition ecture 5: PREIMINRY CONCEP O RUCUR NYI Priciple Of uperpositio Mathematically, the priciple of superpositio is stated as ( a ) G( a ) G( ) G a a or for a liear structural system, the respose at a give

More information

Unit 5. Gases (Answers)

Unit 5. Gases (Answers) Uit 5. Gases (Aswers) Upo successful completio of this uit, the studets should be able to: 5. Describe what is meat by gas pressure.. The ca had a small amout of water o the bottom to begi with. Upo heatig

More information

17 Phonons and conduction electrons in solids (Hiroshi Matsuoka)

17 Phonons and conduction electrons in solids (Hiroshi Matsuoka) 7 Phoos ad coductio electros i solids Hiroshi Matsuoa I this chapter we will discuss a miimal microscopic model for phoos i a solid ad a miimal microscopic model for coductio electros i a simple metal.

More information

Complexation Reactions and Titrations

Complexation Reactions and Titrations Chapter 17 Complexatio Reactios ad Titratios Lewis acid-base cocept Lewis acid electro pair acceptor [metal catios, M + ] Lewis base electro pair door [ligad, molecules or ios] Coordiate covalet bod a

More information

Homework 7 Due 5 December 2017 The numbers following each question give the approximate percentage of marks allocated to that question.

Homework 7 Due 5 December 2017 The numbers following each question give the approximate percentage of marks allocated to that question. Name: Homework 7 Due 5 December 2017 The umbers followig each questio give the approximate percetage of marks allocated to that questio. 1. Use the reciprocal metric tesor agai to calculate the agle betwee

More information

Exercises and Problems

Exercises and Problems HW Chapter 4: Oe-Dimesioal Quatum Mechaics Coceptual Questios 4.. Five. 4.4.. is idepedet of. a b c mu ( E). a b m( ev 5 ev) c m(6 ev ev) Exercises ad Problems 4.. Model: Model the electro as a particle

More information

True Nature of Potential Energy of a Hydrogen Atom

True Nature of Potential Energy of a Hydrogen Atom True Nature of Potetial Eergy of a Hydroge Atom Koshu Suto Key words: Bohr Radius, Potetial Eergy, Rest Mass Eergy, Classical Electro Radius PACS codes: 365Sq, 365-w, 33+p Abstract I cosiderig the potetial

More information

Mathematics of the Variation and Mole Ratio Methods of Complex Determination

Mathematics of the Variation and Mole Ratio Methods of Complex Determination Joural of the Arkasas Academy of Sciece Volume 22 Article 18 1968 Mathematics of the Variatio ad Mole Ratio Methods of omplex Determiatio James O. Wear Souther Research Support eter Follow this ad additioal

More information

Narayana IIT Academy

Narayana IIT Academy Narayaa IIT Academy INDIA XII_IC_SPARK JEE-MAIN Date: 3-7-7 Time : 3 Hours CPT -5 Ma Marks : 36 KEY SHEET PHYSICS ) B ) C 3) A 4) C 5) B 6) A 7) A 8) C 9) D ) A ) B ) C 3) D 4) B 5) A 6) A 7) C 8) C 9)

More information

4.7 Organic Chemistry

4.7 Organic Chemistry 4.7 rgaic hemistry rude oil rude oil is a fiite resource foud i rocks. rude oil is the remais of a aciet biomass cosistig maily of plakto that was buried i mud. Alkaes Most of the hydrocarbos i crude oil

More information

Chem Discussion #13 Chapter 10. Correlation diagrams for diatomic molecules. Key

Chem Discussion #13 Chapter 10. Correlation diagrams for diatomic molecules. Key Chem 101 017 Discussio #13 Chapter 10. Correlatio diagrams for diatomic molecules. Key 1. Below is a plot of the first 10 ioizatio eergies for a sigle atom i 3 rd row of the periodic table. The x- axis

More information

A Brief Introduction to the Physical Basis for Electron Spin Resonance

A Brief Introduction to the Physical Basis for Electron Spin Resonance A Brief Itroductio to the Physical Basis for Electro Spi Resoace I ESR measuremets, the sample uder study is exposed to a large slowly varyig magetic field ad a microwave frequecy magetic field orieted

More information

Chapter 2. Aromatic Polyketones from α-aminonitriles

Chapter 2. Aromatic Polyketones from α-aminonitriles hapter 2 Aromatic Polyketoes from α-amioitriles 2.1 ythesis of α-amioitriles α-amioitriles 1 are a class of compouds which cotai the amie ad itrile fuctioal groups o the same carbo. The geeral structure

More information

Narayana IIT Academy

Narayana IIT Academy INDIA XI STD IIT_LJ Jee-Advaced Date: 08-0-08 Time: HS 0_P MODEL Max.Marks:80 KEY SHEET PHYSICS b a b 4 d 5 b 6 c 7 c 8 c 9 d 0 b a,b,c a,c b,c 4 a,c 5 b,c,d 6 5 7 8 4 9 0 6 CHEMISTY c c b 4 a 5 c 6 b

More information

AME 513. " Lecture 3 Chemical thermodynamics I 2 nd Law

AME 513.  Lecture 3 Chemical thermodynamics I 2 nd Law AME 513 Priciples of Combustio " Lecture 3 Chemical thermodyamics I 2 d Law Outlie" Why do we eed to ivoke chemical equilibrium? Degrees Of Reactio Freedom (DORFs) Coservatio of atoms Secod Law of Thermodyamics

More information

Determination of Amount of Acid by Back Titration. Experiment 4. Experiment 4

Determination of Amount of Acid by Back Titration. Experiment 4. Experiment 4 Determiatio of Amout of Acid by Back Titratio Experimet 4 Goal: Experimet 4 Determie amout of acid that ca be eutralized by a commercial atacid Method: React atacid tablet with excess stomach acid (HCl)

More information

Section 5.2: Calorimetry and Enthalpy Tutorial 1 Practice, page 297

Section 5.2: Calorimetry and Enthalpy Tutorial 1 Practice, page 297 Sectio 52: Calorietry ad Ethalpy Tutorial 1 Practice, page 297 1 Give: V 60 L ; T iitial 25 C ; T fial 75 C; d H2O(l) H2O(l) 100 g/l Required: theral eergy required, q Aalysis: q cδt Solutio: Step 1: Deterie

More information

Physics Supplement to my class. Kinetic Theory

Physics Supplement to my class. Kinetic Theory Physics Supplemet to my class Leaers should ote that I have used symbols for geometrical figures ad abbreviatios through out the documet. Kietic Theory 1 Most Probable, Mea ad RMS Speed of Gas Molecules

More information

UNIFIED COUNCIL. An ISO 9001: 2015 Certified Organisation NATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION (UPDATED)

UNIFIED COUNCIL. An ISO 9001: 2015 Certified Organisation NATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION (UPDATED) UNIFIED COUNCIL A ISO 900: 05 Certified Orgaisatio NATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION (UPDATED) CLASS - (PCM) Questio Paper Code : UN6 KEY A C A B 5 B 6 D 7 C 8 A 9 B 0 D A C B B 5 C 6 D

More information

Department of Chemistry University of Texas at Austin

Department of Chemistry University of Texas at Austin Electrochemical Cells II Supplemetal Worksheet All the electrochemical cells o this worksheet are the same oes o the first Electrochemical Cells worksheet. To make the work o this worksheet easier, refer

More information

SOLUTIONS 499 G. 7. (2) Li +1 H 2 He +2 He + Q Q = BE4 + 2BEHe = = Q = = 17.

SOLUTIONS 499 G. 7. (2) Li +1 H 2 He +2 He + Q Q = BE4 + 2BEHe = = Q = = 17. AIMT SOLUTIONS. () [Fact]. () î ĵ ˆ i ˆj r r r r iˆ ˆj t. () [Fact] î ĵ. () Original energy o photon be K = - φ. e = -...(i) K =. φ.8 e =. - (ii) From equation (i) and (ii). = (.8..8) e = e. () Let the

More information

. Mass of Pb(NO) 3 (g) Mass of PbI 2 (g) , (1.000 g KI) (2.000 g KI) 2,778

. Mass of Pb(NO) 3 (g) Mass of PbI 2 (g) , (1.000 g KI) (2.000 g KI) 2,778 Problem : Lead iodide. The graph obtaied i oe of two traight lie, meetig at a pea of about.50 g Pb(O ). Data accordig to the reactio KI(aq) + Pb(O ) (aq) KO (aq) + PbI () Ma of PbI () i g 5.00.00.00. Ma

More information

Lecture 6. Semiconductor physics IV. The Semiconductor in Equilibrium

Lecture 6. Semiconductor physics IV. The Semiconductor in Equilibrium Lecture 6 Semicoductor physics IV The Semicoductor i Equilibrium Equilibrium, or thermal equilibrium No exteral forces such as voltages, electric fields. Magetic fields, or temperature gradiets are actig

More information

TRU Chemistry Contest Chemistry 12 May 21, 2003 Time: 90 minutes

TRU Chemistry Contest Chemistry 12 May 21, 2003 Time: 90 minutes TRU Chemistry Contest Chemistry 12 May 21, 2003 Time: 90 minutes Last Name First name School Teacher Please follow the instructions below. We will send your teacher a report on your performance. Top performers

More information

AME 513. " Lecture 2 Chemical thermodynamics I 1 st Law

AME 513.  Lecture 2 Chemical thermodynamics I 1 st Law AME 513 Priciples of ombustio " Lecture 2 hemical thermodyamics I 1 st Law Outlie" Fuels - hydrocarbos, alteratives Balacig chemical reactios Stoichiometry Lea & rich mixtures Mass ad mole fractios hemical

More information

What Is Required? You need to find the ph at a certain point in the titration using hypobromous acid and potassium hydroxide solutions.

What Is Required? You need to find the ph at a certain point in the titration using hypobromous acid and potassium hydroxide solutions. 104. A chemist titrated 35.00 ml of a 0.150 mol/l solutio of hypobromous acid, HBrO(aq), K a = 2.8 10 9. Calculate the resultig ph after the additio of 15.00 ml of 0.1000 mol/l sodium hydroxide solutio,

More information

Math 116 Final Exam December 19, 2016

Math 116 Final Exam December 19, 2016 Math 6 Fial Exam December 9, 06 UMID: EXAM SOLUTIONS Iitials: Istructor: Sectio:. Do ot ope this exam util you are told to do so.. Do ot write your ame aywhere o this exam. 3. This exam has 3 pages icludig

More information

What Is Required? You need to determine the hydronium ion concentration in an aqueous solution. K w = [H 3 O + ][OH ] =

What Is Required? You need to determine the hydronium ion concentration in an aqueous solution. K w = [H 3 O + ][OH ] = Calculatig the [H3O + ] or [OH ] i Aqueous Solutio (Studet textbook page 500) 11. The cocetratio of hydroxide ios, OH (aq), i a solutio at 5C is 0.150 /. Determie the cocetratio of hydroium ios, H 3 O

More information

A B A B. 2. Homolytic Bond Dissociation Energies (DH ) 1. Introduction: How Radicals Form and How They React Heterolysis

A B A B. 2. Homolytic Bond Dissociation Energies (DH ) 1. Introduction: How Radicals Form and How They React Heterolysis hapter 10 Radical Reactios reated by Professor William Tam & Dr. Phillis hag h. 10-1 About The Authors These Powerpoit Lecture Slides were created ad prepared by Professor William Tam ad his wife Dr. Phillis

More information

Name:. Correct Questions = Wrong Questions =.. Unattempt Questions = Marks =

Name:. Correct Questions = Wrong Questions =.. Unattempt Questions = Marks = Name:. Correct Questions = Wrong Questions =.. Unattempt Questions = Marks = 1. Which anion forms the smallest number of insoluble salts? (A) Cl - (B) NO 3 - (C) CO 3 2- (D) SO 4 2-2. Which piece of apparatus

More information

Wind Energy Explained, 2 nd Edition Errata

Wind Energy Explained, 2 nd Edition Errata Wid Eergy Explaied, d Editio Errata This summarizes the ko errata i Wid Eergy Explaied, d Editio. The errata ere origially compiled o July 6, 0. Where possible, the chage or locatio of the chage is oted

More information

NUCLEATION 7.1 INTRODUCTION 7.2 HOMOGENEOUS NUCLEATION Embryos and nuclei CHAPTER 7

NUCLEATION 7.1 INTRODUCTION 7.2 HOMOGENEOUS NUCLEATION Embryos and nuclei CHAPTER 7 CHAPER 7 NUCLEAION 7.1 INRODUCION I this text, we focus our attetio o crystallie solids that form from the melt. he process begis with the creatio of a cluster of atoms of crystallie structure, which may

More information

What is Physical Chemistry. Physical Chemistry for Chemical Engineers CHEM251. Basic Characteristics of a Gas

What is Physical Chemistry. Physical Chemistry for Chemical Engineers CHEM251. Basic Characteristics of a Gas 7/6/0 hysical Chemistry for Chemical Egieers CHEM5 What is hysical Chemistry hysical Chemistry is the study of the uderlyig physical priciples that gover the properties ad behaviour of chemical systems

More information

Chapter 17. Equilibrium

Chapter 17. Equilibrium Chapter 17 Equilibrium collision model (17.1) Chapter 17 Review p.541 Key Terms activation energy (Ea) (17.) catalyst (17.) enzyme (17.) equilibrium (17.3) Chemical equilibrium (17.3) law of chemical equilibrium

More information

MOTION. The easy stuff; The gaseous state - Translational motion. The crystalline state - Oscillations about a Mean position.

MOTION. The easy stuff; The gaseous state - Translational motion. The crystalline state - Oscillations about a Mean position. The easy stuff; MOTION The gaseous state - Traslatioal motio The crystallie state - Oscillatios about a Mea positio The hard stuff; The liquid state - Coupled motios MOTION IN POLYMERS LARGE SCALE MOTION

More information

II.1 EQUILIBRIUM REVERSIBLE REACTIO2S

II.1 EQUILIBRIUM REVERSIBLE REACTIO2S II.1 EQUILIBRIUM REVERSIBLE REACTIO2S Many reactions can go in reverse and have separate activation energies. Reactants Products or Reactants Products Reactants form Products Products form Reactants Example:

More information

Page 1. Name: _1)

Page 1. Name: _1) Name: _1) 4) 5) 6) 7) 8) 9) 1) 626 1 Page 1 What Greek philosopher as the first perso to propose the idea that matter is made of tiy idividual particles called atoms? A) Democritus C) Dalto B) Bohr D)

More information

CAREER POINT. Major Test (AIEEE Pattern) (MT-1) Take Home PHYSICS, CHEMISTRY & MATHEMATICS HINTS & SOLUTIONS

CAREER POINT. Major Test (AIEEE Pattern) (MT-1) Take Home PHYSICS, CHEMISTRY & MATHEMATICS HINTS & SOLUTIONS CAREER PINT PHYSICS, CHEMISTRY & MATHEMATICS HINTS & SLUTINS PHYSICS. [] Path differece correspodig to th maima is λ.[] so correspodig phase differece is 0 π.. [] U µc v T µ. [] µ i.e., a µ g. [] r B

More information

EGN 3353C Fluid Mechanics

EGN 3353C Fluid Mechanics Chapter 7: DIMENSIONAL ANALYSIS AND MODELING Lecture 3 dimesio measure of a physical quatity ithout umerical values (e.g., legth) uit assigs a umber to that dimesio (e.g., meter) 7 fudametal dimesios from

More information

CHAPTER 5 GASES. Questions

CHAPTER 5 GASES. Questions CHAER 5 GASES Questios 0. Molecules i the codesed phases (liquids ad solids) are very close together. Molecules i the gaseous phase are very far apart. A sample of gas is mostly empty space. herefore,

More information

1990 AL Chemistry paper II marking scheme

1990 AL Chemistry paper II marking scheme 1990 AL Chemistry paper II marking scheme 1.(a)(i) According to the equation: A 2 (g) + 3B 2 (g) 2AB 3 (g) 4 mol of AB 3 will consume 2 mol of A 2 & 6 mol of B 2. Therefore at equilibrium: [B 2 ] = (12-6)

More information

ANSWERS, HINTS & SOLUTIONS PART TEST I PAPER-2 ANSWERS KEY

ANSWERS, HINTS & SOLUTIONS PART TEST I PAPER-2 ANSWERS KEY AITS-PT-I (Paper-)-PCM-JEE(Advaced)/8 FIITJEE JEE(Advaced)-8 ANSWERS, HINTS & SOLUTIONS PART TEST I PAPER- ANSWERS KEY Q. No. PHYSICS Q. No. CHEMISTRY Q. No. MATHEMATICS ALL INDIA TEST SERIES. D. B 7.

More information

4.2 Module 2: Polymers and Synthesis

4.2 Module 2: Polymers and Synthesis 4.2 Module 2: Polymers ad Sythesis 4.2.1 Amio Acids ad hirality Geeral structure of a α amio acid 2 2 The group ca be a variety of differet thigs depedig o what amio acid it is. The alpha i α amio acid

More information

CHEMISTRY Summer Assignment Solutions 2013

CHEMISTRY Summer Assignment Solutions 2013 Atoms ad Molecules 1. Determie the missig values for each atom listed. 55 5M 1 Number of protos 5 Number of electros 4 Number of eutros 30 Atomic umber 5 Atomic mass 55 75 3 33 As Number of protos 33 Number

More information

Answer Key, Problem Set 7 Full

Answer Key, Problem Set 7 Full Chemistry Mies, Fall 07 Aswer Key, Problem Set 7 Full. NT;. 5.43; 3. 5.56; 4. 5.3; 5. 5.7; 6. 5.9; 7. NT; 8. 5.0; 9. 5.49; 0. 5.89 & 5.90;. NT3;. 5.70; 3. 5.9 & 5.9; 4. NT4 -----------------------------------------

More information

c) Explain the observations in terms of the DYNAMIC NATURE of the equilibrium system.

c) Explain the observations in terms of the DYNAMIC NATURE of the equilibrium system. Chemical Equilibrium - Part A: 1. At 25 o C and 101.3 kpa one mole of hydrogen gas and one mol of chlorine gas are reacted in a stoppered reaction vessel. After a certain time, three gases are detected

More information

(c) Write, but do not evaluate, an integral expression for the volume of the solid generated when R is

(c) Write, but do not evaluate, an integral expression for the volume of the solid generated when R is Calculus BC Fial Review Name: Revised 7 EXAM Date: Tuesday, May 9 Remiders:. Put ew batteries i your calculator. Make sure your calculator is i RADIAN mode.. Get a good ight s sleep. Eat breakfast. Brig:

More information

Name:. Correct Questions = Wrong Questions =.. Unattempt Questions = Marks =

Name:. Correct Questions = Wrong Questions =.. Unattempt Questions = Marks = Name:. Correct Questions = Wrong Questions =.. Unattempt Questions = Marks = 1. Which salt is colorless? (A) KMn 4 (B) BaS 4 (C) Na 2 Cr 4 (D) CoCl 2 2. Which 0.10 M aqueous solution exhibits the lowest

More information

Chapter 4. Fourier Series

Chapter 4. Fourier Series Chapter 4. Fourier Series At this poit we are ready to ow cosider the caoical equatios. Cosider, for eample the heat equatio u t = u, < (4.) subject to u(, ) = si, u(, t) = u(, t) =. (4.) Here,

More information

Physics Oct Reading

Physics Oct Reading Physics 301 21-Oct-2002 17-1 Readig Fiish K&K chapter 7 ad start o chapter 8. Also, I m passig out several Physics Today articles. The first is by Graham P. Collis, August, 1995, vol. 48, o. 8, p. 17,

More information

Lecture #1 Nasser S. Alzayed.

Lecture #1 Nasser S. Alzayed. Lecture #1 Nasser S. Alzayed alzayed@ksu.edu.sa Chapter 6: Free Electro Fermi Gas Itroductio We ca uderstad may physical properties of metals, ad ot oly of the simple metals, i terms of the free electro

More information

NATIONAL STANDARD EXAMINATION IN CHEMISTRY ANSWER KEYS SET No. C C 2. C 3. D 4. A & C 5. A 6. D 7. D 8. C 9. C 10. A 11. C 12. B 13.

NATIONAL STANDARD EXAMINATION IN CHEMISTRY ANSWER KEYS SET No. C C 2. C 3. D 4. A & C 5. A 6. D 7. D 8. C 9. C 10. A 11. C 12. B 13. NATINAL STANDARD EXAMINATIN IN CEMISTRY 2018-19 ANSWER KEYS SET No. C 321 1. C 2. C 3. D 4. A & C 5. A 6. D 7. D 8. C 9. C 10. A 11. C 12. B 13. A 14. B 15. B 16. C 17. D 18. B 19. C 20. A 21. D 22. A

More information

Bohr s Atomic Model Quantum Mechanical Model

Bohr s Atomic Model Quantum Mechanical Model September 7, 0 - Summary - Itroductio to Atomic Theory Bohr s Atomic Model Quatum Mechaical Model 3- Some Defiitio 3- Projects Temperature Pressure Website Subject Areas Plasma is a Mixture of electros,

More information