CAREER POINT. Major Test (AIEEE Pattern) (MT-1) Take Home PHYSICS, CHEMISTRY & MATHEMATICS HINTS & SOLUTIONS

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1 CAREER PINT PHYSICS, CHEMISTRY & MATHEMATICS HINTS & SLUTINS PHYSICS. [] Path differece correspodig to th maima is λ.[] so correspodig phase differece is 0 π.. [] U µc v T µ. [] µ i.e., a µ g. [] r B < r A P V ( γ ) λ glass λwater λ glass mbv qb R ( γ ) T P(V V ) ( γ ) a µw B λ water aµ g aµ w mav < qb. [] y a si (ωt k) or y 0. si π vt λ V or y 0. si π t λ λ 0 or y 0. si π t 0 0 or y 0. si π t 0 A PV ( γ ) 7. [ ] Nuclear force of attractio betwee ay two ucleos (, p p, p ) is same. The differece Major Test (AIEEE Patter) 0 (MT-) Take Home comes up oly due to electrostatic force of repulsio betwee two protos. F F F. As F < F > F F F > F 8. [] 9. [] Gravitatioal force is actio reactio force. 0. [] K.E. W (gravity bauace force Resistace force) 0 mv mgh vd w g w. [] Power of the system decreases due to separatio betwee the leses so the focal legth icreases.. [] P AT ad A r P r T Now, T' T, r' r Hece P' P P.[] Here, spherometer is used.. [] V G V H. [] V G V H 7V CAREER PINT, CP Tower, Road No., IPIA, Kota (Raj.), Ph: Page # G A Ω Ω V A Ω H A V A 7Ω Ω A

2 . [] Photoelectric curret itesity of icidet light. Therefore, the graph is a straight lie havig positive slope passig through origi. 7. [] 8. [] mv k µmg v 7. m/s 9. [] φ BAN φ µ 0 N i NA l µ φ 0 N ia l 0. [] V L V c & V R V 0 V 0 Hece i. A 00. [] C v for Hydroge. []. [] C v for water vapour R, C v for helium R R R R [C v ] mi C p C v R R 7 X AJ for balace. R JB AJ Iitially, 8 00 AJ AJ ' fially 8 00 AJ ' AJ' AJ 0 cm L R R 7 R R R 7. [] (E) R ( NE) R ( N) 8 N N t ms T t (m) s T. [] mg(r r). mr ω mv v Put rω v ad ω' ( R r). [] V a by cz dv a d dv by dv cz dz E (a î by ĵ cz kˆ ) At 0, y 0, z 0. Work q (v v ) 0 (. c) 0 0 C a. 0 a 0 7. [] V 0 a y c() b a 0 C a 0 0 0y 0 y 8. [] Potetial at each cap E E L A C C C C D B R NE From A to D CAREER PINT, CP Tower, Road No., IPIA, Kota (Raj.), Ph: Page #

3 V A E E 0 V A E D to B 8. [] N N NH (NH ) S selective NaN HCl Diazoteatio reductio N H NN Cl H N 0 E E VB V B E 9.[] A lives closer to the school tha B [] v g 0 m/s v T v 0 m/s bg vb vbg vg 0 0 v bt CHEMISTRY. [] Fe Si FeSi 0 0 m/s. [] F 0, H 0., Cl 0, Cl 8. [] [Ne] s (Mg) [Ne] s (Na) [Ne] s p (Cl) [Ne] s p (P). []. [] Use P V T PV T. [] P( g) Cl(g) PCl(g) 7. [] Dichromate test Alc. H CH CH CH CH oi.ozoolysis N 9. [] H C I Ca CaC H C H H C 0. [] (NH ) S specifically reduces oe out of two N groups [selective reductio] hc. [] E E λ. [] At. wt. sp. heat.. [] eq. of Na C. H eq. of HCl. [] At. mass of K 9 gm/mol 9 0 kg/mol Z bcc a earest distace r.å. 0 0 m 0 (. 0 ) a m m Z N A usig d, d 900 kg/m a E / RT. [] K Ae a. [] For hydrolysis of B ; K H K w 0 Kb [] If more tha fuctioal group directly attached with C-chai tha they all are eclude from paret C-chai ad used special suffi. H C CH CH CH CH CH CH 8. [] NH NH I, M N NH I N NH N I, M CAREER PINT, CP Tower, Road No., IPIA, Kota (Raj.), Ph: Page #

4 I ad M group decrease basicity of moosubstituted alie. Hece all (o, m ad p) is less basic tha ailie rtho derivative is the least basic due to (ortho effect) steric hidrace. Amog m ad p derivative m-will be more basic tha p-due to oly I effect. 9.[] Cis ad tras isomers also diasteromers 0.[] Solubility of A miimum (for graph) Solubility K H Maimum K H A,.[] Aq. AgN N,H ) Aode :- H H e ( (Ag, H ) Cathode :- Ag e Ag [H ] at aode, ph, ph Aq. LiCl (Cl, H ) Aode :- Cl Cl e (Li, H ) Cathode :- H e H [H ] at cathode, ph.[] Eplaatio is correct reaso for statemet.[].[] Correct statemet II- Cl is a oidizig aget. It bleaches the articles by oidatio permaetly i presece of moisture..[] Statemet II is a correct eplaatio for statemet-i.[] [Cr(NH ) Cl ] gives two geometrical isomers fac (whe all the similar ligads occupy the same face of a octahedro) ad mer (the other isomer of the compoud) 7.[] M(aa) type show optical isomerism. aa symmetrical bidetete ligad 8.[] Rate stability of carbocatio formed 9.[] 0.[] N is a deactivatig gp, makes the compoud less reactive. MATHEMATICS.[] lim... ( ) b. [] lim lim, > 0, < 0 0, 0 value is ( 0) 0 ( 0) Rage {0, } f ( ) d (b ) si (b ) Area fuctio f ( ) d ( ) si ( ) differetiatig f() si ( ) ( ). cos ( ). [] Let α be commo root, the aα cα b 0 aα bα c 0 (c b) α c b α / Puttig α, a b c 0. [] 0 ; i 0 0 ; i N 9 C CAREER PINT, CP Tower, Road No., IPIA, Kota (Raj.), Ph: Page #

5 a K ak a K ak a. [] Q P K a Α a a, PQ diameter of the circle. [] Let E deote the evet of travellig by trai ad E deote travellig by plae. P(E ), P(E ) a 0 0 a a a 7. [] Y y (X ) m P(E E ) P(E ) P(E ) 7. [] Let a studet gets marks out of 0. He gets marks out of 0. Hece, mea is also multiplied by. Mea [] ( a r r b ). r r ( a b ) a r b r LHS ( a b ). ( a b ) a b a r b r r r (a.b ) r Q a. b 0 a b 9. [] ( A B) ( A B) B 70. [] (0,) (U) (A B) AB AC AB AC a (K a) K a C (a,0) A(a,k) P (,y) G my whe m take let Y 0 X my d hece (my ) ( y ) y y d Now put y v dv ( v ) v v d v v dv v v v d v v vdv d v l ( v ) l c l v c, y c 7. [] log (a b) (c d) (a b) ( c d) ( a b) ( c d) Now ( a b)( c d) a b c d 8 CAREER PINT, CP Tower, Road No., IPIA, Kota (Raj.), Ph: Page #

6 7. [] Let α, β ω, γ ω f () a b c f (ω) a bω cω f (ω ) a bω cω f (α) f (β) f (γ) f () f(ω) f(ω ) (a b c) (a b c ab bc ca) a b c abc a b c b c a f (α) f (β) f(γ) c a b 7. [] ( ). ( ) ( 9) 0 7. [] (~p q) ~ r p (F F) F T F F T F T F 7. [] Circle For ellipse c a m b m ( m ) m m m m ± 77. [] Area of ABC with A(z), B (iz), C(z iz) z 00 z 00 z [] a (a d) y a d 0 a( y ) d (y ) 0 always passes through itersectio of y 0 ad y 0 ie, y 79. [] cetre (0, 0) r ( m) y 0 ( m) p r ( m) ( m) 0 m R 80. [] f () ; ; < 0 ; > 0 ; 0 clearly f () is cotiuous but ot differetiable at 0 8. [] y d Now y d y d 8. [] Solvig curves d a y d y as they are orthogoal a y a a / a ± from () d y a y y 0 CAREER PINT, CP Tower, Road No., IPIA, Kota (Raj.), Ph: Page #

7 8. [] f '() si π. π π { ve. si π For icrease si π > 0 kπ < π < (k ) π, k k 8. [] 0 A S A 0 0 Let the school be at a distace from A (with 0 studets) the D 0 0 (0 ) D will be least ad equal to 000 if 0 school should be built at A 8. [] cos ( y) y 0 y Hece si & cos four solutios b cos 8. [] a si d we ca ow use by. parts method or f '() f () d. f() ( asi ) Q a b c a r b r c r ( a. b b. c c. a ) 0 ( a. b b. c c. a ) 0 ( a. b b. c c. a ) 7 By a b r b c r r c a { } ( 7) 8 i.e. statemet (I) ad (II) are true ad statemet (II) is also a correct eplaatio of statemet (I) 89. [] p (α, β, γ) py q rz s q y s z p r...() ( / p) ( / r) DR'S, p, r pr, r, p Q A plae through the poit (α, β, γ) ad perpedicular to the lie () is rp ( α) r (y β) p (z γ) 0 ad lie () is the symmetrical form of the give lie statemet (I) is false ad statemet (II) is true. 90. [] I - Icorrect II correct [] (I) X M.D. i (II) formula of mea deviatio by mea i i so statemet I is true. statemet II is wrog. 88. [] a r, b r ad c r a b r b c r r c a ( a r b r c r ) ( a. b b. c c. a )...() i CAREER PINT, CP Tower, Road No., IPIA, Kota (Raj.), Ph: Page # 7

JEE(Advanced) 2018 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 20 th MAY, 2018)

JEE(Advanced) 2018 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 20 th MAY, 2018) JEE(Advaced) 08 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 0 th MAY, 08) PART- : JEE(Advaced) 08/Paper- SECTION. For ay positive iteger, defie ƒ : (0, ) as ƒ () j ta j j for all (0, ). (Here, the iverse