Section 5.2: Calorimetry and Enthalpy Tutorial 1 Practice, page 297

Size: px
Start display at page:

Download "Section 5.2: Calorimetry and Enthalpy Tutorial 1 Practice, page 297"

Transcription

1 Sectio 52: Calorietry ad Ethalpy Tutorial 1 Practice, page Give: V 60 L ; T iitial 25 C ; T fial 75 C; d H2O(l) H2O(l) 100 g/l Required: theral eergy required, q Aalysis: q cδt Solutio: Step 1: Deterie the ass of water, Vd 100 g 60 L 1 L 60 g Step 2: Deterie the chage i teperature, ΔT Δ T T T fial iitial 75 C 25 C c 418 J/(g C) ; H2O(l) Δ T 50 C Step 3: Calculate the quatity of theral eergy, q q cδt 418 J (60 g ) (50 C ) g C q 13 kj Stateet: The quatity of theral eergy required is 13 kj 2 Give: ethylee glycol 40 kg ; c ethylee glycol 35 J/(g C) ; q 250 kj Required: chage i teperature, ΔT Aalysis: q cδt Solutio: Step 1: Covert quatities to the appropriate uits 3 40 kg g q 250 kj 250!10 3 J Step 2: Rearrage q cδt to ve for ΔT q cδt q Δ T c J 3 35 J (40 10 g ) g C Δ T 18 C Stateet: The teperature chage of the utio was 18 C Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-1

2 3 Give: V HCl(aq) 500 L ; V NaOH(aq) 750 L; T iitial 202 C; T fial 256 C Required: quatity of eergy trasferred, q Aalysis: q cδt Solutio: Step 1: Deterie the total volue of HCl(aq) ad NaOH(aq), V V V + V HCl(aq) NaOH(aq) 500 L L V 1250 L Step 2: Deterie the total ass of two utios, Sice the utio cotais dilute HCl(aq) ad NaOH(aq), the desity ad heat capacity are assued to be the sae as those for water Vd 100 g 1250 L 1 L 1250 g Step 3: Deterie the chage i teperature, ΔT Δ T T T fial iitial 256 C 202 C Δ T 54 C Step 4: Calculate the quatity of eergy trasferred, q q cδt 418 J (1250 g ) (54 C ) g C q 2800 J Stateet: The quatity of eergy trasferred is 2800 J, or 28 kj Sice the teperature of the surroudigs (liquid water i the calorieter) icreased, the reactio was exotheric Mii Ivestigatio: Theral Eergy Trasfer i a Coffee-Cup Calorieter, page 297 Aswers ay vary Saple aswers: ass of water i calorieter g ass of aluiu block 8980 g teperature of aluiu block teperature of hot water bath 800 C fial teperature of water i calorieter 278 C iitial teperature of tap water 198 C A Give: g ; T iitial 198 C; T fial 278 C Required: quatity of theral eergy gaied by the water, q Aalysis: q cδt Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-2

3 Solutio: Step 1: Deterie the chage i teperature, ΔT Δ T T T fial iitial 278 C 198 C Δ T 80 C Step 2: Calculate the quatity of theral eergy gaied by the water, q q cδt 418 J (10000 g ) (80 C ) g C q 3300 J Stateet: The quatity of theral eergy gaied by the water is 3300 J, or 33 kj B Give: Al(s) 8980 g; T iitial 800 C; T fial 278 C ; c Al(s) 0900 J/(g C) Required: quatity of theral eergy trasferred to or fro aluiu, q Aalysis: q cδt Solutio: Step 1: Deterie the chage i teperature, ΔT Δ T T T fial iitial 278 C 800 C Δ T 522 C Step 2: Calculate the quatity of theral eergy trasferred to or fro aluiu, q q cδt 0900 J (8980 g ) ( 522 C) g C q 4220 J Stateet: Sice the value of q is egative, eergy is trasferred fro aluiu to water, ad the quatity trasferred is 4220 J, or 422 kj C Aswers ay vary Saple aswer: There is a differece of about 09 kj i the aswers to A ad B The differece could be due to assuptios or experietal errors D Aswers ay vary Saple aswer: Experietal errors iclude theral eergy lost to the togs, to the air o trasfer fro hot to cold water, to the theroeter, to the calorieter, or to the air above the water aluiu ixture The ivestigatio could be iproved by takig ito accout the teperature chages ad thus eergy trasferred to the theroeter, togs, ad calorieter Other iproveets would be icreasig the isulatio of calorieter ad faster trasfer fro hot to cold water Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-3

4 Tutorial 2 Practice, page Give: 500 g ; Δ H 440 kj/ol H2O(l) Required: ethalpy chage, Aalysis: Δ H Δ H Δ H Solutio: Step 1: Calculate the aout of water i 500 g, M 1802 g/ol M 500 g 1802 g/ol ol (2 extra digits carried) HO(l) 2 Step 2: Solve for the chage i ethalpy, Δ H Δ H HO(l) ΔH kj (27747 ol ) 1 ol Δ H 122 kj Stateet: The ethalpy chage expected whe 500 g of water orizes is 122 kj 2 Give: Na 2SO4g 10H2O(l) 250 kg; Δ Hr 780 kj/ol Required: ethalpy chage, Δ H Aalysis: Δ H ΔH Na2SO4g 10H2O(l) r Solutio: Step 1: Calculate the aout of salt i 250 kg, Na2 SO 4 i10h 2 O(l) M Na2 SO 4 i10h 2 O(l) g/ol Na2 SO 4 i10h 2 O(l) Na 2 SO 4 i10h 2 O(l) M Na2 SO 4 i10h 2 O(l) Na2 SO 4 i10h 2 O(l) 250!103 g g/ol ol (2 extra digits carried) Step 2: Solve for the chage i ethalpy, Δ H!H!H Na2 SO 4 i10h 2 O(l) r # "780 kj & (77582 ol ) $ % 1 ol ' (!H "605 kj Stateet: The chage i ethalpy whe 250 kg of Glauber s salt eters the id state is 605 kj Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-4

5 3 Give: Δ H 1000 kj ; Δ H 157 kj/ol Required: ass of propae, Aalysis: Δ H Δ H Solutio: Step 1: Rearrage Δ H ΔH ΔH Δ H Δ H Δ H to ve for the aout of propae, 1000 kj 157 kj /ol ol (2 extra digits carried) Step 2: Covert aout of propae ito ass, M 4411 g/ol M M 4411 g (63694 ol ) 1 ol CH (l) 281 g 3 8 Stateet: The ass of propae that would orize as a result of absorbig 1000 kj of eergy is 281 g 4 Give: 400 g ; V 1000 L; Δ T 106 C Required: olar ethalpy of disutio, Δ H Aalysis: q cδt; Δ H Δ H Solutio: Step 1: Deterie the ass of water, Vd 100 g 1000 L 1 L 100 g Step 2: Deterie the quatity of theral eergy absorbed by the water, q q cδt 418 J (100 g ) (106 C ) g C q J (2 extra digits carried) This is the quatity of eergy released, Δ H, whe 400 g of is disved Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-5

6 Step 3: Covert ass of ito aout, M 4000 g/ol M 400 g 4000 g/ol 0100 ol Step 4: Rearrage Δ H Δ H to ve for the olar ethalpy of disutio, Δ H Sice eergy is released, Δ H for the reactio is egative; Δ H J Δ H ΔH ΔH Δ H J 0100 ol Δ H J/ol Stateet: The olar ethalpy of disutio of sodiu hydroxide is J/ol, or 443 kj/ol Tutorial 3 Practice, page (a) Solutio: Step 1: Write the balaced cheical equatio without the eergy ter 2 C 2 H 2 (g) + 5 O 2 (g) 4 CO 2 (g) + 2 H 2 O(g) Step 2: Write the balaced cheical equatio for the cobustio of 1 ol C 2 H 2 (g) C 2 H 2 (g) O 2(g) 2 CO 2 (g) + H 2 O(g) Step 3: Sice the ethalpy chage has a egative value, the cobustio reactio of ethye is exotheric Sice a exotheric reactio releases eergy, place the eergy ter o the right side of the equatio C 2 H 2 (g) O 2(g) 2 CO 2 (g) + H 2 O(g) kj Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-6

7 (b) Draw the reactio coordiates with the x-axis labelled Reactio progress ad the y- axis labelled Potetial eergy, Ep (kj) Sice the reactio is exotheric, the products will have lower potetial eergy tha the reactats Poit the arrow fro reactats dowward to products Write the reactats o the upper left-had side of the graph ad the products o the lower right-had side of the graph Iclude the ΔH of the reactio This process is cobustio, so ΔH is ΔH c 2 (a) Sice the teperature of the surroudigs decreases, the reactio is edotheric (b) Draw the reactio coordiates with the x-axis labelled Reactio progress ad the y- axis labelled Potetial eergy, Ep (kj) Sice the reactio is edotheric, the products will have greater potetial eergy tha the reactats Poit the arrow fro reactats upward to products Write the reactats o the lower left-had side of the graph ad the products o the upper right-had side of the graph Iclude the ΔH of the reactio This process is disutio, so ΔH is ΔH (c) A therocheical equatio for the reactio is: HO NH 4 NO 3 (s) kj 2 NH 4 NO 3 (aq) 3 (a) The correspodig therocheical equatio for the reactio depicted by the potetial eergy diagra is: C 2 H 5 OH(l) C 2 H 5 OH(g) H 386 kj (b) The correspodig therocheical equatio for the reactio depicted by the potetial eergy diagra is: C 8 H 18 (l) O 2(g) 8 CO 2 (g) + 9 H 2 O(l) H c 5074 kj Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-7

8 + 4 Give: [Ag (aq)] [Cl (aq)] 0100 ol/l ; utio 1000 g; T iitial 226 C; T fial 234 C ; c 418 J/(g C) Required: olar ethalpy of reactio, Δ Hr Aalysis: q cδt; Δ H Δ Hr Solutio: Step 1: Deterie the chage i teperature of the utio, ΔT Δ T T T fial iitial 234 C 226 C Δ T 08 C Step 2: Calculate the quatity of theral eergy for the reactio, q q cδt 418 J (1000 g ) (08 C ) g C q 334 J (2 extra digits carried) This is the quatity of eergy released, Δ H Sice there is a icrease i teperature, the reactio is exotheric, ad Δ H is egative; Δ H 334 J Step 3: Deterie the aout of AgCl(s) fored i the 100 L utio, AgCl(s) AgCl(s) AgCl(s) + Ag (aq) 0100 ol 500 L 1000 L 0005 ol Step 4: Rearrage Δ H r Δ H ΔH AgCl(s) ΔH Δ H r AgCl(s) r Δ H Δ H to ve for the ethalpy of foratio for 1 ol AgCl(s), r 334 J 0005 ol Δ H r J/ol Stateet: The theral eergy that accopaies the foratio of AgCl(s) is J/ol or 70 kj/ol of AgCl(s) fored Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-8

9 Sectio 52 Questios, page Specific heat capacity is the quatity of theral eergy required to raise the teperature of 1 g of a substace by 1 C The specific heat capacity of water, 418 J/(g C), is higher tha that of aluiu, 0900 J/(g C) Whe the sae ass of aluiu ad water were heated to the sae teperature, the water would have ore theral eergy ad take loger to dissipate the excess eergy, whereas aluiu would have less theral eergy ad take less tie to cool dow Therefore, the aluiu foil ca be safely reoved usig your figers, but touchig the iside of the potato results i a serious bur 2 The burig of gaie ito carbo dioxide ad water is a cobustio reactio, which is a exotheric process The syste releases eergy ad the surroudigs absorb eergy Therefore, the sig of q syste is egative (eergy released), the sig for ΔH is also egative (exotheric process), ad the sig of q surroudigs is positive (eergy absorbed) 3 (a) Fro the balaced equatio, the ethalpy chage of 891 kj is for the foratio of 2 oles of water Calculate the ethalpy chage, H, for 1 ole: 891 kj Δ H 2 Δ H 446 kj So, the ethalpy chage for each ole of water fored is 446 kj (b) Fro the balaced equatio, the ethalpy chage of 891 kj is for the foratio of 1 ole of carbo dioxide So, the ethalpy chage for each ole of carbo dioxide fored is also 891 kj (c) Fro the balaced equatio, the ethalpy chage of 891 kj is for 2 oles of oxyge reacted Calculate the ethalpy chage, H, for 1 ole: 891 kj Δ H 2 Δ H 446 kj So, the ethalpy chage for each ole of oxyge reacted is 446 kj 4 Give: 200 g ; Δ H kj/ol ; V 125 L; Δ Tiitial 200 C Required: fial teperature, Δ Tfial c T Aalysis: Δ H Δ H ; q Δ Solutio: Step 1: Covert ass of NH 4 Cl(s) ito aout, M 5350 g/ol M 200 g 5350 g/ol ol (2 extra digits carried) H2O(l) Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-9

10 Step 2: Calculate the ethalpy chage for the reactio, Δ H ΔH Δ H 148 kj ( ol ) 1 ol Δ H kj (2 extra digits carried) Sice Δ H is positive, theral eergy is absorbed fro the surroudigs So, the chage i theral eergy of the surroudig water, q, is egative; q kj Step 3: Deterie the ass of water, Vd 100 g 125 L 1 L 125 g Step 4: Rearrage q cδt to ve for the teperature chage, Δ T q cδt q Δ T c J 1 1 (125 g )(418 J g C ) Δ T 106 C Step 5: Calculate the fial teperature, Δ T fial Δ T T T fial fial T Δ T + T iitial iitial 106 C C Tfial 94 C Stateet: The fial teperature observed whe 200 g of aoiu chloride is added to 125 L water at 200 C is 94 C 5 (a) Draw the reactio coordiates with the x-axis labelled Reactio progress ad the y-axis labelled Potetial eergy, Ep (kj) Sice the reactio is edotheric, the products will have greater potetial eergy tha the reactats Poit the arrow fro reactats upward to products Write the reactats o the lower left-had side of the graph ad the products o the upper right-had side of the graph Iclude the ΔH of the reactio This process is foratio, so ΔH is ΔH f Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-10

11 (b) Draw the reactio coordiates with the x-axis labelled Reactio progress ad the y- axis labelled Potetial eergy, Ep (kj) Sice the reactio is exotheric, the products will have lower potetial eergy tha the reactats Poit the arrow fro reactats dowward to products Write the reactats o the upper left-had side of the graph ad the products o the lower right-had side of the graph Iclude the ΔH of the reactio This process is cobustio, so ΔH is ΔH c 6 (a) A therocheical equatio for the cobustio for propae is: C 3 H 8 (g) + 5 O 2 (g) 3 CO 2 (g) + 4 H 2 O(l) ΔH 2220 kj (b) A therocheical equatio for the separatio of atos i the chlorie olecule is: Cl 2 (g) 2 Cl(g) ΔH 243 kj (c) A therocheical equatio for the foratio of iro(iii) oxide fro its eleets is: 2 Fe(s) O 2(g) Fe 2 O 3 (s) ΔH 824 kj (d) A therocheical equatio for the decopositio of hydroge chloride ito its eleets is: HCl(g) 1 2 H 2(g) Cl 2(g) ΔH 93 kj 7 (a) A therocheical equatio for the foratio of 1 ol of copper(ii) chloride fro its eleets is: Cu(s) + Cl 2 (g) CuCl 2 (s) kj (b) A therocheical equatio for the coversio of graphite to diaod is: C graphite (s) + 20 kj C diaod (s) (c) A therocheical equatio for the decopositio of silver chloride ito its eleets is: AgCl(s) kj Ag(s) Cl 2(g) Copyright 2012 Nelso Educatio Ltd Chapter 5: Therocheistry 52-11

Section 7.4: Calculations Involving Limiting Reagents

Section 7.4: Calculations Involving Limiting Reagents Sectio 7.4: Calculatios Ivolvig Limitig Reagets Tutorial 1 Practice, page 33 1. Give:.3 mol ;.0 mol HNO = 3 Required: amout of water, NaCO = 3 O H Solutio: Step 1. List the give values ad the required

More information

Copyright 2012 Nelson Education Ltd. Chapter 5: Thermochemistry 5-2

Copyright 2012 Nelson Education Ltd. Chapter 5: Thermochemistry 5-2 Chapter 5 Review, pages 338 339 Kowledge 1. (d). (d) 3. (a) 4. (d) 5. (b) 6. (c) 7. (a) 8. (a) 9. False. The law of coservatio of eergy states that the eergy of a system is always costat. 10. True 11.

More information

Answer Key, Problem Set 1, Written

Answer Key, Problem Set 1, Written Cheistry 1 Mies, Sprig, 018 Aswer Key, Proble Set 1, Writte 1. 14.3;. 14.34 (add part (e): Estiate / calculate the iitial rate of the reactio); 3. NT1; 4. NT; 5. 14.37; 6. 14.39; 7. 14.41; 8. NT3; 9. 14.46;

More information

Copyright 2011 Nelson Education Ltd. Chapter 7: Stoichiometry in Chemical Reactions 7-2

Copyright 2011 Nelson Education Ltd. Chapter 7: Stoichiometry in Chemical Reactions 7-2 Chapter 7 Review, pages 346 351 Kowledge 1. (d) 2. (a) 3. (c) 4. (a) 5. (b) 6. (a) 7. (b) 8. (d) 9. (d) 10. (c) 11. False. The value that would coplete the ratio below is 18. 3? = 7 42 12. False. The coefficiets

More information

Heat Capacity: measures the ability of the substance to pick up heat

Heat Capacity: measures the ability of the substance to pick up heat Calorietry: easures flow of heat across boundaries Heat Capacity: easures the ability of the substance to pick up heat Heat capacity under constant pressure, C p euals the aount of heat reuired to raise

More information

Molar mass, M, of the empirical formula C 4 H 9 : M 4M 9M g/mol g/mol g/mol

Molar mass, M, of the empirical formula C 4 H 9 : M 4M 9M g/mol g/mol g/mol olar ass,, of the unknown gas: n 10.00 g 0.088037 ol 113.16057 g/ ol olar ass,, of the epirical forula C 4 H 9 : 4 9 C4H9 C H 4 12.01 g/ol 9 1.01 g/ol 57.13 g/ol Ratio of olar asses: 113.16057 g/ol 1.9807

More information

Chapter 11 REVIEW. Part 1

Chapter 11 REVIEW. Part 1 produces soe hydroelectricity. This involves energy conversions fro potential energy of water (above the da) to kinetic energy (falling water and spinning turbine) to electrical energy. Coal accounts for

More information

What Is Required? You need to find the molar concentration, c, of the ions in a solution of ammonium phosphate.

What Is Required? You need to find the molar concentration, c, of the ions in a solution of ammonium phosphate. Chemistry 11 Solutios Sectio 9.2 Solutio Stoichiometry Solutios for Practice Problems Studet Editio page 417 11. Practice Problem (page 417) If 8.5 g of pure ammoium phosphate, (NH 4 ) 3 PO 4 (s), is dissolved

More information

Physical bases of dental material science

Physical bases of dental material science Physical bases of detal aterial sciece The ioizatio eergy of the sodiu ato is 496 kj/ol. How large eergy is ecessary i ev to ioize oe ato? The ioizatio eergy of a sigle ato: E i 19 496000 19 8,7 10 ε i

More information

Physical Chemistry I for Biochemists. Lecture 2 (1/12/11) Yoshitaka Ishii. Gas Ch. 1 Non-Ideal Gas (Ch 1 & Raff p21-41) Announcement

Physical Chemistry I for Biochemists. Lecture 2 (1/12/11) Yoshitaka Ishii. Gas Ch. 1 Non-Ideal Gas (Ch 1 & Raff p21-41) Announcement Physical Cheistry I for Biocheists Che340 Lecture (1/1/11) Yoshitaka Ishii Gas Ch. 1 No-Ideal Gas (Ch 1 & Raff p1-41) Aouceet HW 1 is due et Wedesday before the class (Fid HW1 at the web site) Attedace

More information

--Lord Kelvin, May 3rd, 1883

--Lord Kelvin, May 3rd, 1883 Whe you ca measure what you are speakig about ad express it i umbers, you kow somethig about it; but whe you caot measure it, whe you caot express it i umbers, you kowledge is of a meager ad usatisfactory

More information

CHAPTER 11. Practice Questions (a) OH (b) I. (h) NH 3 CH 3 CO 2 (j) C 6 H 5 O - (k) (CH 3 ) 3 N conjugate pair

CHAPTER 11. Practice Questions (a) OH (b) I. (h) NH 3 CH 3 CO 2 (j) C 6 H 5 O - (k) (CH 3 ) 3 N conjugate pair CAPTER 11 Practice Questios 11.1 (a) O (b) I (c) NO 2 (d) 2 PO 4 (e) 2 PO 4 (f) 3 PO 4 (g) SO 4 (h) N 3 (i) C 3 CO 2 (j) C 6 5 O - (k) (C 3 ) 3 N 11.3 cojugate pair PO 3 4 (aq) C 3 COO(aq) PO 2 4 (aq)

More information

Material Balances on Reactive Processes F&R

Material Balances on Reactive Processes F&R Material Balaces o Reactive Processes F&R 4.6-4.8 What does a reactio do to the geeral balace equatio? Accumulatio = I Out + Geeratio Cosumptio For a reactive process at steady-state, the geeral balace

More information

1. Collision Theory 2. Activation Energy 3. Potential Energy Diagrams

1. Collision Theory 2. Activation Energy 3. Potential Energy Diagrams Chemistry 12 Reactio Kietics II Name: Date: Block: 1. Collisio Theory 2. Activatio Eergy 3. Potetial Eergy Diagrams Collisio Theory (Kietic Molecular Theory) I order for two molecules to react, they must

More information

CHEE 221: Chemical Processes and Systems

CHEE 221: Chemical Processes and Systems CHEE 221: Chemical Processes ad Systems Module 3. Material Balaces with Reactio Part a: Stoichiometry ad Methodologies (Felder & Rousseau Ch 4.6 4.8 ot 4.6c ) Material Balaces o Reactive Processes What

More information

Enthalpy changes practice qs

Enthalpy changes practice qs Enthalpy changes practice qs Q1. The combustion of hydrocarbons is an important source of energy. Define the term standard enthalpy of combustion. (i) Write an equation for the complete combustion of ethane,

More information

Solutions to Equilibrium Practice Problems

Solutions to Equilibrium Practice Problems Solutios to Equilibrium Practice Problems Chem09 Fial Booklet Problem 1. Solutio: PO 4 10 eq The expressio for K 3 5 P O 4 eq eq PO 4 10 iit 1 M I (a) Q 1 3, the reactio proceeds to the right. 5 5 P O

More information

Equation (4) has 2 mol of water on the reactant side, while the desired equation has 6 mol. Multiply equation (4) and its ΔH by the factor 3:

Equation (4) has 2 mol of water on the reactant side, while the desired equation has 6 mol. Multiply equation (4) and its ΔH by the factor 3: Section 5.4: Hess s Law Tutorial 1 Practice, page 317 1. (a) Solution: The desired equation is: 2 N 2 (g) + 6 H 2 O(g) 3 O 2 (g) + 4 NH 3 (g) (1) NH 3 (g) 1 2 N 2(g) + 3 2 H 2(g) H = 46 kj (2) 2 H 2 (g)

More information

CHEM 1105 S10 March 11 & 14, 2014

CHEM 1105 S10 March 11 & 14, 2014 CHEM 1105 S10 March 11 & 14, 2014 Today s topics: Thermochemistry (Chapter 6) Basic definitions Calorimetry Enthalpy Thermochemical equations Calculating heats of reaction Hess s Law Energy and Heat Some

More information

Name ID# Section # CH 1020 EXAM 3 Spring Form A

Name ID# Section # CH 1020 EXAM 3 Spring Form A Name ID# Sectio # CH 1020 EXAM 3 Sprig 2016 - Form A Fill i your ame, ID#, ad sectio o this test booklet. Fill i ad bubble i your ame, ID# (bubble 0 for C ), ad sectio o the scatro form. For questio #60

More information

Unit 5. Gases (Answers)

Unit 5. Gases (Answers) Uit 5. Gases (Aswers) Upo successful completio of this uit, the studets should be able to: 5. Describe what is meat by gas pressure.. The ca had a small amout of water o the bottom to begi with. Upo heatig

More information

Molecular Speeds. Real Gasses. Ideal Gas Law. Reasonable. Why the breakdown? P-V Diagram. Using moles. Using molecules

Molecular Speeds. Real Gasses. Ideal Gas Law. Reasonable. Why the breakdown? P-V Diagram. Using moles. Using molecules Kinetic Theory of Gases Connect icroscopic properties (kinetic energy and oentu) of olecules to acroscopic state properties of a gas (teperature and pressure). P v v 3 3 3 But K v and P kt K v kt Teperature

More information

Nernst Equation. Nernst Equation. Electric Work and Gibb's Free Energy. Skills to develop. Electric Work. Gibb's Free Energy

Nernst Equation. Nernst Equation. Electric Work and Gibb's Free Energy. Skills to develop. Electric Work. Gibb's Free Energy Nerst Equatio Skills to develop Eplai ad distiguish the cell potetial ad stadard cell potetial. Calculate cell potetials from kow coditios (Nerst Equatio). Calculate the equilibrium costat from cell potetials.

More information

Department of Chemistry University of Texas at Austin

Department of Chemistry University of Texas at Austin Electrochemical Cells II Supplemetal Worksheet All the electrochemical cells o this worksheet are the same oes o the first Electrochemical Cells worksheet. To make the work o this worksheet easier, refer

More information

Check Your Solution The units for amount and concentration are correct. The answer has two significant digits and seems reasonable.

Check Your Solution The units for amount and concentration are correct. The answer has two significant digits and seems reasonable. Act o Your Strategy Amout i moles,, of Ca(CH 3 COO) 2 (aq): CaCH3COO 2 c V 0.40 mol/ L 0.250 L 0.10 mol Molar mass, M, of Ca(CH 3 COO) 2 (s): M 1 M 4 M 6 M 4M Ca CH COO 3 2 Ca C H O 1 40.08 g/mol 4 12.01

More information

Chapter 14: Chemical Equilibrium

Chapter 14: Chemical Equilibrium hapter 14: hemical Equilibrium 46 hapter 14: hemical Equilibrium Sectio 14.1: Itroductio to hemical Equilibrium hemical equilibrium is the state where the cocetratios of all reactats ad products remai

More information

Chapter 3. Thermochemistry: Energy Flow and Chemical Change. 5.1 Forms of Energy and Their Interconversion

Chapter 3. Thermochemistry: Energy Flow and Chemical Change. 5.1 Forms of Energy and Their Interconversion Chapter 3 Thermochemistry: Energy Flow and Chemical Change 5.1 Forms of Energy and Their Interconversion 5.2 Enthalpy: Chemical Change at Constant Pressure 5.3 Calorimetry: Measuring the Heat of a Chemical

More information

CHEM 305 Solutions for assignment #2

CHEM 305 Solutions for assignment #2 CHEM 05 Solutions for assignent #. (a) Starting fro C C show that C C Substitute the result into the original expression for C C : C C (b) Using the result fro (a), evaluate C C for an ideal gas. a. Both

More information

(02) WMP/Jun10/CHEM2

(02) WMP/Jun10/CHEM2 Energetics 2 Section A Answer all the questions in the spaces provided. 1 An equation for the equilibrium reaction between hydrogen, iodine and hydrogen iodide is shown below. H 2 (g) + I 2 (g) 2HI(g)

More information

13 Energetics Answers to end-of-chapter questions

13 Energetics Answers to end-of-chapter questions Pages 253 254 Questions 1 2 [e] Always label a Hess s law diagram with either ΔH or the values of ΔH. ΔH f (C 2 H 4 ) + ΔH f (H 2 O) + ΔH r = ΔH f (C 2 H 5 OH) +52.3 + ( 286) + ΔH r = 278 ΔH r = 278 52.3

More information

Guided Notes and Practice- Topi 5.1: Calorimetry and Enthalpy Calculations

Guided Notes and Practice- Topi 5.1: Calorimetry and Enthalpy Calculations Name: Date: Pd: Guided Notes and Practice- Topi 5.1: Calorimetry and Enthalpy Calculations Endothermic vs. Exothermic 1. Label each ΔH value as being exothermic or endothermic. Thermochemical Equations

More information

Energetics. Exothermic and endothermic reactions

Energetics. Exothermic and endothermic reactions 5 Energetics Exothermic and endothermic reactions As we saw in the previous chapter, chemical reactions involve the breaking and making of bonds. It requires energy to break bonds, and energy is given

More information

3.2.1 Energetics. Calorimetry. 121 minutes. 120 marks. Page 1 of 19

3.2.1 Energetics. Calorimetry. 121 minutes. 120 marks. Page 1 of 19 3..1 Energetics Calorimetry 11 minutes 10 marks Page 1 of 19 Q1. A 50.0 cm 3 sample of a 0.00 mol dm 3 solution of silver nitrate was placed in a polystyrene beaker. An excess of powdered zinc was added

More information

What Is Required? You need to find the ph at a certain point in the titration using hypobromous acid and potassium hydroxide solutions.

What Is Required? You need to find the ph at a certain point in the titration using hypobromous acid and potassium hydroxide solutions. 104. A chemist titrated 35.00 ml of a 0.150 mol/l solutio of hypobromous acid, HBrO(aq), K a = 2.8 10 9. Calculate the resultig ph after the additio of 15.00 ml of 0.1000 mol/l sodium hydroxide solutio,

More information

I affirm that I have never given nor received aid on this examination. I understand that cheating in the exam will result in a grade F for the class.

I affirm that I have never given nor received aid on this examination. I understand that cheating in the exam will result in a grade F for the class. Che340 hysical Cheistry for Biocheists Exa 3 Apr 5, 0 Your Nae _ I affir that I have never given nor received aid on this exaination. I understand that cheating in the exa will result in a grade F for

More information

CPT 17. XI-LJ (Date: ) PHYSICS CHEMISTRY MATHEMATICS 1. (B) 31. (A) 61. (A) 2. (B) 32. (B) 62. (C) 3. (D) 33. (D) 63. (B) 4. (B) 34.

CPT 17. XI-LJ (Date: ) PHYSICS CHEMISTRY MATHEMATICS 1. (B) 31. (A) 61. (A) 2. (B) 32. (B) 62. (C) 3. (D) 33. (D) 63. (B) 4. (B) 34. CPT-7 / XI-LJ / NARAYANA I I T A C A D E M Y CPT 7 XI-LJ (Date:.0.7) CODE XI-LJ PHYSICS CHEMISTRY MATHEMATICS. (B). (A) 6. (A). (B). (B) 6. (C). (D). (D) 6. (B). (B). (C) 6. (C) 5. (D) 5. (C) 65. (A) 6.

More information

5.1 Energy Changes in Chemical and Nuclear Reactions

5.1 Energy Changes in Chemical and Nuclear Reactions Figure 1 Our use of fossil fuels is usustaiable. New sources of gree, sustaiable eergy are eeded to meet the world s growig demad. 5.1 Eergy Chages i Chemical ad Nuclear Reactios Our ability to haress

More information

LESSON 2: SIMPLIFYING RADICALS

LESSON 2: SIMPLIFYING RADICALS High School: Workig with Epressios LESSON : SIMPLIFYING RADICALS N.RN.. C N.RN.. B 5 5 C t t t t t E a b a a b N.RN.. 4 6 N.RN. 4. N.RN. 5. N.RN. 6. 7 8 N.RN. 7. A 7 N.RN. 8. 6 80 448 4 5 6 48 00 6 6 6

More information

KOH(aq) + HNO 3 (aq) KNO 3 (aq) + H 2 O(l) A 52 B 26 C +26 D +52. (Total for Question = 1 mark) 2 Calculate the enthalpy change, in kj mol _ 1

KOH(aq) + HNO 3 (aq) KNO 3 (aq) + H 2 O(l) A 52 B 26 C +26 D +52. (Total for Question = 1 mark) 2 Calculate the enthalpy change, in kj mol _ 1 1 When 0.1 mol of aqueous potassium hydroxide was added to 0.1 mol of nitric acid, 5200 J were transferred to the surroundings. What is the enthalpy change, in kj mol 1, for this reaction? 52 26 C +26

More information

2. What is a measure of the average kinetic energy of particles? (A) heat capacity (B) molar enthalpy (C) specific heat (D) temperature

2. What is a measure of the average kinetic energy of particles? (A) heat capacity (B) molar enthalpy (C) specific heat (D) temperature Thermochemistry #1 Chemistry 3202 Name: 1. Classify the following systems as open or closed a) glass of cold water b) a gel filled freezer pack c) a burning candle d) a fluorescent lightbulb e) hot water

More information

3.2.1 Energetics. Enthalpy Change. 263 minutes. 259 marks. Page 1 of 41

3.2.1 Energetics. Enthalpy Change. 263 minutes. 259 marks. Page 1 of 41 ..1 Energetics Enthalpy Change 6 minutes 59 marks Page 1 of 41 Q1. (a) Define the term standard molar enthalpy of formation, ΔH f. (b) State Hess s law. (c) Propanone, CO, burns in oxygen as shown by the

More information

10/23/10. Thermodynamics and Kinetics. Chemical Hand Warmers

10/23/10. Thermodynamics and Kinetics. Chemical Hand Warmers 10/23/10 CHAPTER 6 Thermochemistry 6-1 Chemical Hand Warmers Most hand warmers work by using the heat released from the slow oxidation of iron 4 Fe(s) + 3 O2(g) 2 Fe2O3(s) The amount your hand temperature

More information

Chemistry 104 Chapter 17 Summary and Review Answers

Chemistry 104 Chapter 17 Summary and Review Answers Chemistry 104 Chapter 17 Summary ad Review Aswers 1. You eed to make a buffer with a ph of 4.80. You have 0.150 M sodium hydroxide, 0.150 M acetic acid ad 0.150 M sodium bicarboate. What do you do? (Make

More information

The chemical potential energy of a substance is known as its ENTHALPY and has the symbol H.

The chemical potential energy of a substance is known as its ENTHALPY and has the symbol H. Enthalpy Changes The chemical potential energy of a substance is known as its ENTHALPY and has the symbol H. During chemical reactions, the enthalpy can increase or decrease. The change in enthalpy during

More information

Chapter 5 Practice Multiple Choice & Free

Chapter 5 Practice Multiple Choice & Free Name Response 1. A system has an increase in internal energy, E, of 40 kj. If 20 kj of work, w, is done on the system, what is the heat change, q? a) +60 kj d) -20 kj b) +40 kj e) -60 kj c) +20 kj 2. Which

More information

Additional Calculations: 10. How many joules are required to change the temperature of 80.0 g of water from 23.3 C to 38.8 C?

Additional Calculations: 10. How many joules are required to change the temperature of 80.0 g of water from 23.3 C to 38.8 C? Additional Calculations: 10. How many joules are required to change the temperature of 80.0 g of water from 23.3 C to 38.8 C? q = m C T 80 g (4.18 J/gC)(38.8-23.3C) = 5183 J 11. A piece of metal weighing

More information

Chapter 8. Thermochemistry

Chapter 8. Thermochemistry Chapter 8 Thermochemistry Copyright 2001 by Harcourt, Inc. All rights reserved. Requests for permission to make copies of any part of the work should be mailed to the following address: Permissions Department,

More information

The Advanced Placement Examination in Chemistry. Part II - Free Response Questions & Answers 1970 to Electrochemistry

The Advanced Placement Examination in Chemistry. Part II - Free Response Questions & Answers 1970 to Electrochemistry The Advaced Placemet Examiatio i Chemistry Part II - Free Respose Questios & Aswers 970 to 005 Electrochemistry Teachers may reproduce this publicatio, i whole or i part, i limited prit quatities for o-commercial,

More information

So by applying Hess s law a = ΔH + b And rearranged ΔH = a - b

So by applying Hess s law a = ΔH + b And rearranged ΔH = a - b 3.12 Hess s Law Hess s law states that total enthalpy change for a reaction is independent of the route by which the chemical change takes place Hess s law is a version of the first law of thermodynamics,

More information

2 nd Semester Study Guide 2017

2 nd Semester Study Guide 2017 Chemistry 2 nd Semester Study Guide 2017 Name: KEY Unit 6: Chemical Reactions and Balancing 1. Draw the remaining product 2. Write a balanced equation for the following reaction: The reaction between sodium

More information

TERMS AND DEFINITIONS IN THERMOCHEMISTRY

TERMS AND DEFINITIONS IN THERMOCHEMISTRY (v.2.0 16/3/90 8hrs.) TERMS AND DEFINITIONS IN THERMOCHEMISTRY (v.2.1 12/4/90 2hrs.) 1) ENTHALPY CHANGE ( H) This is the same as the heat change involved in a process (provided the initial and final states

More information

Homework #4 Chapter 17

Homework #4 Chapter 17 oework #4 hapter 17 roperties o Solutios 1. a) NO(s) + (aq) + NO - (aq) ) NaSO4(s) Na + (aq) + SO4 - (aq) c) Al(NO)(s) Al + (aq) + NO - (aq) d) SrBr(s) Sr + (aq) + Br - (aq) e) KlO4(s) K + (aq) + lo4 -

More information

DETERMINING AND USING H

DETERMINING AND USING H DETERMINING AND USING H INTRODUCTION CHANGES IN CHEMISTRY Chemistry is the science that studies matter and the changes it undergoes. Changes are divided into two categories: physical and chemical. During

More information

A. 2.5 B. 5.0 C. 10. D. 20 (Total 1 mark) 2. Consider the following reactions. N 2 (g) + O 2 (g) 2NO(g) 2NO 2 (g) 2NO(g) + O 2 (g)

A. 2.5 B. 5.0 C. 10. D. 20 (Total 1 mark) 2. Consider the following reactions. N 2 (g) + O 2 (g) 2NO(g) 2NO 2 (g) 2NO(g) + O 2 (g) 1. When 100 cm 3 of 1.0 mol dm 3 HCl is mixed with 100 cm 3 of 1.0 mol dm 3 NaOH, the temperature of the resulting solution increases by 5.0 C. What will be the temperature change, in C, when 50 cm 3 of

More information

Thermodynamics I. Prep Session

Thermodynamics I. Prep Session Thermodynamics I Prep Session Dr. John I. Gelder Department of Chemistry Oklahoma State University Stillwater, OK 74078 john.gelder@okstate.edu http://intro.chem.okstate.edu 12/5/09 1 Thermo I Prep Session

More information

Chapter 2. Asymptotic Notation

Chapter 2. Asymptotic Notation Asyptotic Notatio 3 Chapter Asyptotic Notatio Goal : To siplify the aalysis of ruig tie by gettig rid of details which ay be affected by specific ipleetatio ad hardware. [1] The Big Oh (O-Notatio) : It

More information

Enthalpy and Internal Energy

Enthalpy and Internal Energy Enthalpy and Internal Energy H or ΔH is used to symbolize enthalpy. The mathematical expression of the First Law of Thermodynamics is: ΔE = q + w, where ΔE is the change in internal energy, q is heat and

More information

Name Period ALGEBRA II Chapter 1B and 2A Notes Solving Inequalities and Absolute Value / Numbers and Functions

Name Period ALGEBRA II Chapter 1B and 2A Notes Solving Inequalities and Absolute Value / Numbers and Functions Nae Period ALGEBRA II Chapter B ad A Notes Solvig Iequalities ad Absolute Value / Nubers ad Fuctios SECTION.6 Itroductio to Solvig Equatios Objectives: Write ad solve a liear equatio i oe variable. Solve

More information

Thermochemistry: Part of Thermodynamics

Thermochemistry: Part of Thermodynamics Thermochemistry: Part of Thermodynamics Dr. Vickie M. Williamson @vmwilliamson Student Version 1 Chemical Thermodynamics! Thermodynamics: study of the energy changes associated with physical and chemical

More information

33. a. Heat is absorbed from the water (it gets colder) as KBr dissolves, so this is an endothermic process.

33. a. Heat is absorbed from the water (it gets colder) as KBr dissolves, so this is an endothermic process. 31. This is an endothermic reaction so heat must be absorbed in order to convert reactants into products. The high temperature environment of internal combustion engines provides the heat. 33. a. Heat

More information

UNIFIED COUNCIL. An ISO 9001: 2015 Certified Organisation NATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION (UPDATED)

UNIFIED COUNCIL. An ISO 9001: 2015 Certified Organisation NATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION (UPDATED) UNIFIED COUNCIL A ISO 900: 05 Certified Orgaisatio NATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION (UPDATED) CLASS - (PCM) Questio Paper Code : UN6 KEY A C A B 5 B 6 D 7 C 8 A 9 B 0 D A C B B 5 C 6 D

More information

Chapter 8. Thermochemistry 강의개요. 8.1 Principles of Heat Flow. 2) Magnitude of Heat Flow. 1) State Properties. Basic concepts : study of heat flow

Chapter 8. Thermochemistry 강의개요. 8.1 Principles of Heat Flow. 2) Magnitude of Heat Flow. 1) State Properties. Basic concepts : study of heat flow 강의개요 Basic concepts : study of heat flow Chapter 8 Thermochemistry Calorimetry : experimental measurement of the magnitude and direction of heat flow Thermochemical Equations Copyright 2005 연세대학교이학계열일반화학및실험

More information

Thermochemistry: Heat and Chemical Change

Thermochemistry: Heat and Chemical Change Thermochemistry: Heat and Chemical Change 1 Heat or Thermal Energy (q) Heat is a form of energy Is heat the same as temperature? Heat flows between two objects at different temperatures. Hot Cold 2 Chemical

More information

Chapter 6. Thermochemistry

Chapter 6. Thermochemistry Chapter 6. Thermochemistry 1 1. Terms to Know: thermodynamics thermochemistry energy kinetic energy potential energy heat heat vs. temperature work work of expanding gases work of expanding gases under

More information

(g) burns according to this reaction? D) CH 4 (g) + 2O 2 (g) CO 2 (g) + 2H 2 O(l)

(g) burns according to this reaction? D) CH 4 (g) + 2O 2 (g) CO 2 (g) + 2H 2 O(l) Name: 7171-1 - Page 1 1) In a chemical reaction, the difference between the potential energy of the products and the potential energy of the reactants is defined as the A) heat of reaction B) ionization

More information

IB Topics 5 & 15 Multiple Choice Practice

IB Topics 5 & 15 Multiple Choice Practice IB Topics 5 & 15 Multiple Choice Practice 1. Which statement is correct for this reaction? Fe 2O 3 (s) + 3CO (g) 2Fe (s) + 3CO 2 (g) ΔH = 26.6 kj 13.3 kj are released for every mole of Fe produced. 26.6

More information

Kinetics of Complex Reactions

Kinetics of Complex Reactions Kietics of Complex Reactios by Flick Colema Departmet of Chemistry Wellesley College Wellesley MA 28 wcolema@wellesley.edu Copyright Flick Colema 996. All rights reserved. You are welcome to use this documet

More information

( ) (( ) ) ANSWERS TO EXERCISES IN APPENDIX B. Section B.1 VECTORS AND SETS. Exercise B.1-1: Convex sets. are convex, , hence. and. (a) Let.

( ) (( ) ) ANSWERS TO EXERCISES IN APPENDIX B. Section B.1 VECTORS AND SETS. Exercise B.1-1: Convex sets. are convex, , hence. and. (a) Let. Joh Riley 8 Jue 03 ANSWERS TO EXERCISES IN APPENDIX B Sectio B VECTORS AND SETS Exercise B-: Covex sets (a) Let 0 x, x X, X, hece 0 x, x X ad 0 x, x X Sice X ad X are covex, x X ad x X The x X X, which

More information

CHAPTER 6: Chemical Energetics

CHAPTER 6: Chemical Energetics CHAPTER 6: Chemical Energetics 6.1 Enthalpy Changes 6.2 Standard Enthalpy Changes 6.3 Hess' Law 6.4 Bond Energy Learning outcomes: (a) explain that some chemical reactions are accompanied by energy changes,

More information

Things you should know when you leave Discussion today:

Things you should know when you leave Discussion today: Chem 101 2016 Discussion #10 Chapter 7 TF s name: Discussion Day/Time: Things you should know when you leave Discussion today: Enthalpy of the reaction Δ rxn H o Calculating ΔrH of the reaction by using

More information

National 5 Summary Notes

National 5 Summary Notes North Berwick High School Departent of Physics National 5 Suary Notes Unit 3 Energy National 5 Physics: Electricity and Energy 1 Throughout the Course, appropriate attention should be given to units, prefixes

More information

2 nd Semester Study Guide 2016

2 nd Semester Study Guide 2016 Chemistry 2 nd Semester Study Guide 2016 Name: Unit 6: Chemical Reactions and Balancing 1. Draw the remaining product 2. Write a balanced equation for the following reaction: The reaction between sodium

More information

Thermochemistry: Energy Flow and Chemical Reactions

Thermochemistry: Energy Flow and Chemical Reactions Thermochemistry: Energy Flow and Chemical Reactions Outline thermodynamics internal energy definition, first law enthalpy definition, energy diagrams, calorimetry, theoretical calculation (heats of formation

More information

Review Sheet for Final Exam

Review Sheet for Final Exam Sheet for ial To study for the exam, we suggest you look through the past review sheets, exams ad homework assigmets, ad idetify the topics that you most eed to work o. To help with this, the table give

More information

Chapter 6. Chemical Reactions. Sodium reacts violently with bromine to form sodium bromide.

Chapter 6. Chemical Reactions. Sodium reacts violently with bromine to form sodium bromide. Chapter 6 Chemical Reactions Sodium reacts violently with bromine to form sodium bromide. Evidence of Chemical Reactions Chemical Equations Reactants Products Reactant(s): Substance(s) present before the

More information

Thermochemistry. Energy. 1st Law of Thermodynamics. Enthalpy / Calorimetry. Enthalpy of Formation

Thermochemistry. Energy. 1st Law of Thermodynamics. Enthalpy / Calorimetry. Enthalpy of Formation THERMOCHEMISTRY Thermochemistry Energy 1st Law of Thermodynamics Enthalpy / Calorimetry Hess' Law Enthalpy of Formation The Nature of Energy Kinetic Energy and Potential Energy Kinetic energy is the energy

More information

Lecture 20 - Wave Propagation Response

Lecture 20 - Wave Propagation Response .09/.093 Fiite Eleet Aalysis of Solids & Fluids I Fall 09 Lecture 0 - Wave Propagatio Respose Prof. K. J. Bathe MIT OpeCourseWare Quiz #: Closed book, 6 pages of otes, o calculators. Covers all aterials

More information

Name: Section: Score: /10 PRE LABORATORY ASSIGNMENT EXPERIMENT 7

Name: Section: Score: /10 PRE LABORATORY ASSIGNMENT EXPERIMENT 7 Name: Section: Score: /10 PRE LABORATORY ASSIGNMENT EXPERIMENT 7 1. Is the sign of Δ r H for an exothermic reaction positive or negative? Why? 2. When 4.21 grams of potassium hydroxide are added to 250.

More information

(g) Fe(OH) 3 : ; (h) Cr(NO 3 ) 3 : ; (c) Chromium(III) sulfate: ; (h) Dinitrogen tetroxide:

(g) Fe(OH) 3 : ; (h) Cr(NO 3 ) 3 : ; (c) Chromium(III) sulfate: ; (h) Dinitrogen tetroxide: 1. Name each of the following compounds: (a) Ca(OCl) 2 : ; (b) (NH 4 ) 3 PO 4 : ; (c) K 2 Cr 2 O 7 : ; (d) HBrO 2 : ; (e) PF 5 : ; (f) B 2 O 3 : ; (g) Fe(OH) 3 : ; (h) Cr(NO 3 ) 3 : ; (i) Na 2 C 2 O 4

More information

Practice Packet Unit 3: Phase Changes & Heat

Practice Packet Unit 3: Phase Changes & Heat Regents Chemistry: Practice Packet Unit 3: Phase Changes & Heat Name: Assess Yourself: Lesson 1: Lesson 2: Lesson 3: Lesson 4: Vocab: 1 Review (Things you need to know in order to understand the new stuff

More information

Revision Topic 1: Number and algebra

Revision Topic 1: Number and algebra Revisio Topic : Number ad algebra Chapter : Number Differet types of umbers You eed to kow that there are differet types of umbers ad recogise which group a particular umber belogs to: Type of umber Symbol

More information

Law of conservation of energy: energy cannot be created or destroyed, only transferred One object to another One type of energy to another

Law of conservation of energy: energy cannot be created or destroyed, only transferred One object to another One type of energy to another ch6blank Page 1 Chapter 6: Thermochemistry Thermochemistry: study of the relationships between chemistry and energy Energy: capacity to do work Work:result of a force acting over a certain distance, one

More information

Chemistry 30: Thermochemistry. Practice Problems

Chemistry 30: Thermochemistry. Practice Problems Name: Period: Chemistry 30: Thermochemistry Practice Problems Date: Heat and Temperature 1. Pretend you are doing a scientific study on the planet Earth. a. Name three things in the system you are studying.

More information

ChemGGuru. Questions & Answer CHEMISTRY

ChemGGuru. Questions & Answer CHEMISTRY CAREER PIT JEE Mai lie Paper JEE Mai lie Exam 09 [Memory Based Paper] Q. Which of the followig is amphoteric i ature As. [] ` Questios & Aswer th Jauary 09 Shift - I CHEMISTRY Mg(H ( Be(H Ca(H Sr(H Q.

More information

Section 7.2: Equilibrium Law and the Equilibrium Constant Tutorial 1 Practice, page (a) 2 CO 2 (g) #!!"

Section 7.2: Equilibrium Law and the Equilibrium Constant Tutorial 1 Practice, page (a) 2 CO 2 (g) #!! Section 7.: Equilibrium Law and the Equilibrium Constant Tutorial Practice, page 4. (a) CO (g) #!!"! CO(g) + O (g) Products: CO(g); O (g) Reactant: CO (g) [CO [O Equilibrium law equation: [CO (b) Cl (g)

More information

Unit 13 Kinetics & Equilibrium Page 1 of 14 Chemistry Kinetics, Entropy, Equilibrium, LeChatelier s Principle, K, Unit 13 Quiz: Unit 13 Test:

Unit 13 Kinetics & Equilibrium Page 1 of 14 Chemistry Kinetics, Entropy, Equilibrium, LeChatelier s Principle, K, Unit 13 Quiz: Unit 13 Test: Unit 13 Kinetics & Equilibrium Page 1 of 14 Chemistry Kinetics, Entropy, Equilibrium, LeChatelier s Principle, K, Unit 13 Quiz: Unit 13 Test: Final Project: VOCABULARY: 1 Chemical equilibrium 2 equilibrium

More information

Name. Practice Test 2 Chemistry 111

Name. Practice Test 2 Chemistry 111 Name Practice Test 2 Chemistry 111 1) In the aqueous reaction of K 2 SO 4 (aq) + Ba(NO 3 ) 2 (aq) BaSO 4 (s) + 2KNO 3 (aq), which ions are the spectator ions? A) Ba 2+ 2- and SO 4 B) Ba 2+ and K + C) Ba

More information

Chemical Kinetics CHAPTER 14. Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop. CHAPTER 14 Chemical Kinetics

Chemical Kinetics CHAPTER 14. Chemistry: The Molecular Nature of Matter, 6 th edition By Jesperson, Brady, & Hyslop. CHAPTER 14 Chemical Kinetics Chemical Kietics CHAPTER 14 Chemistry: The Molecular Nature of Matter, 6 th editio By Jesperso, Brady, & Hyslop CHAPTER 14 Chemical Kietics Learig Objectives: Factors Affectig Reactio Rate: o Cocetratio

More information

LC Oscillations. di Q. Kirchoff s loop rule /27/2018 1

LC Oscillations. di Q. Kirchoff s loop rule /27/2018 1 L Oscillatios Kirchoff s loop rule I di Q VL V L dt ++++ - - - - L 3/27/28 , r Q.. 2 4 6 x 6.28 I. f( x) f( x).. r.. 2 4 6 x 6.28 di dt f( x) Q Q cos( t) I Q si( t) di dt Q cos( t) 2 o x, r.. V. x f( )

More information

All Excuses must be taken to 233 Loomis before 4:15, Monday, April 30.

All Excuses must be taken to 233 Loomis before 4:15, Monday, April 30. Miscellaeous Notes The ed is ear do t get behid. All Excuses must be take to 233 Loomis before 4:15, Moday, April 30. The PHYS 213 fial exam times are * 8-10 AM, Moday, May 7 * 8-10 AM, Tuesday, May 8

More information

Thermochemistry. Chapter 6. Concept Check 6.1. Concept Check 6.2. Solution

Thermochemistry. Chapter 6. Concept Check 6.1. Concept Check 6.2. Solution Chapter 6 Thermochemistry Concept Check 6.1 A solar-powered water pump has photovoltaic cells on protruding top panels. These cells collect energy from sunlight, storing it momentarily in a battery, which

More information

Thermochemistry is the study of the relationships between chemical reactions and energy changes involving heat.

Thermochemistry is the study of the relationships between chemical reactions and energy changes involving heat. CHEM134- F18 Dr. Al- Qaisi Chapter 06: Thermodynamics Thermochemistry is the study of the relationships between chemical reactions and energy changes involving heat. Energy is anything that has the capacity

More information

DETERMINATION OF NATURAL FREQUENCY AND DAMPING RATIO

DETERMINATION OF NATURAL FREQUENCY AND DAMPING RATIO Hasa G Pasha DETERMINATION OF NATURAL FREQUENCY AND DAMPING RATIO OBJECTIVE Deterie the atural frequecy ad dapig ratio for a aluiu catilever bea, Calculate the aalytical value of the atural frequecy ad

More information

Ch 10 Practice Problems

Ch 10 Practice Problems Ch 10 Practice Problems 1. Which of the following result(s) in an increase in the entropy of the system? I. (See diagram.) II. Br 2(g) Br 2(l) III. NaBr(s) Na + (aq) + Br (aq) IV. O 2(298 K) O 2(373 K)

More information

Announcements, Nov. 19 th

Announcements, Nov. 19 th Aoucemets, Nov. 9 th Lecture PRS Quiz topic: results Chemical through Kietics July 9 are posted o the course website. Chec agaist Kietics LabChec agaist Kietics Lab O Fial Exam, NOT 3 Review Exam 3 ad

More information

EN40: Dynamics and Vibrations. Final Examination Friday May : 2pm-5pm

EN40: Dynamics and Vibrations. Final Examination Friday May : 2pm-5pm EN4: Dyaics ad Vibratios Fial Exaiatio Friday May 8 15: p-5p School of Egieerig Brow Uiversity NAME: Geeral Istructios No collaboratio of ay kid is peritted o this exaiatio. You ay brig double sided pages

More information

AP Chapter 6: Thermochemistry Name

AP Chapter 6: Thermochemistry Name AP Chapter 6: Thermochemistry Name Warm-Ups (Show your work for credit) Date 1. Date 2. Date 3. Date 4. Date 5. Date 6. Date 7. Date 8. AP Chapter 6: Thermochemistry 2 Warm-Ups (Show your work for credit)

More information

SPEC/4/PHYSI/SPM/ENG/TZ0/XX PHYSICS PAPER 1 SPECIMEN PAPER. 45 minutes INSTRUCTIONS TO CANDIDATES

SPEC/4/PHYSI/SPM/ENG/TZ0/XX PHYSICS PAPER 1 SPECIMEN PAPER. 45 minutes INSTRUCTIONS TO CANDIDATES SPEC/4/PHYSI/SPM/ENG/TZ0/XX PHYSICS STANDARD LEVEL PAPER 1 SPECIMEN PAPER 45 miutes INSTRUCTIONS TO CANDIDATES Do ot ope this examiatio paper util istructed to do so. Aswer all the questios. For each questio,

More information

CH 101 Fall 2018 Discussion #8 Chapter 6 Your name: TF s name: Discussion Day/Time: Things you should know when you leave Discussion today:

CH 101 Fall 2018 Discussion #8 Chapter 6 Your name: TF s name: Discussion Day/Time: Things you should know when you leave Discussion today: CH 101 Fall 2018 Discussion #8 Chapter 6 Your name: TF s name: Discussion Day/Time: Things you should know when you leave Discussion today: Precipitation Reaction & Solubility Solubility of Ionic compounds

More information

Thermochemistry HW. PSI Chemistry

Thermochemistry HW. PSI Chemistry Thermochemistry HW PSI Chemistry Name Energy 1) Objects can possess energy as: (a) endothermic energy (b) potential energy A) a only B) b only C) c only D) a and c E) b and c (c) kinetic energy 2) The

More information