CHEMISTRY 213 XMAS 04 1 ANSWER ON THE GREEN COMPUTER ANSWER SHEET PROVIDED USING A PENCIL CHOICES MAY BE USED MORE THAN ONCE
|
|
- Natalie Bell
- 5 years ago
- Views:
Transcription
1 CHEMISTRY 213 XMAS 04 1 ANSWER ON THE GREEN COMPUTER ANSWER SHEET PROVIDED USING A PENCIL CHOICES MAY BE USED MORE THAN ONCE Using the molecules: A: CH 3 CH CHCO 2 CH 3 B: CH 3 CO 2 CH CHCH 3 C: CH 3 CH 2 NH CH 2 CH 3 D: N CH 2CH 3 CH 3 CH 2 E: CHO F: CHO CH 2 CH 3 OH H G: H H: HO H H and using the band frequencies (cm -1 ): a) 3400 b) c) 2750 d) 1760 e) 1735 f) 1725 g) 1705 h) 1695 i) 960 j) 700 Which infrared band frequency present in the first mentioned molecule, would most easily enable you to distinguish it from the second molecule 1 B from A 2 C from D 3 E from F 4 G from H 5 E from A 6 G from E Using the electronic transitions: a) F6F * b) c) F6B * d) n6b * e) n6f * f) B6F * g) L6M, charge transfer h) d6d and using the wavelengths (nm): a) 185 b) 210 c) 285 d) 320 e) 450 f) 650 g) 850 or molar absorptivities h) 10 i) 10 2 j) >10 3 Ferrocene (= di(cyclopentadienyl)iron) is a very bright orange 7 What type of transition causes this 8 Where would the absorption be (nm) 9 What would be its molar absorptivity 10 * Where (nm) is the B 2 6B 2 transition of CH 2 =CH-CO-CH 3 (MVK) 11 Then, what type of transition is the 320nm absorption of MVK 12 What would be its molar absorptivity
2 CHEMISTRY 213 XMAS After a drunk blew thru a breathalyser solution of bright orange potassium dichromate, the visible spectrum obtained at around 770nm showed an ε of about 0.5. Which type of transition from those on the previous page must the absorption centered at 770 nm arise from. Structures A-J: ICH 2 CH 2 CH 2 CH 2 Cl BrCH 2 CH 2 CH 2 CH 2 Br CH 3 SCH 2 CH 2 SCH 3 A B C C 4 H 9 -CO-O-CO-C 4 H 9 SH Br N OCH 3 D E F G P(OCH 3 ) 3 CH 3 (CH 2 ) 20 CHCl 2 CH 3 CHF 2 H I J In their mass spectra, which of structures A-J 14 would show an M-127 peak 15 would show an 11% M+1 peak 16 would show an M+2 peak, about 8% of the M+ peak 17 would show strong M and M+2 peaks, in a 3:1 ratio
3 CHEMISTRY 213 XMAS 04 3 GHB and Rohypnol are two of the date rape drugs and have the structure: 7 6 CH 3 OH N O O 2 N N COOH 13 F GHB Rohypnol using the proton chemical shift values: a) 1 b) 1.5 c) 2.3 d) 3 e) 4 f) 6.6 g) 7.2 h) 7.8 i) 10 j) What is the chemical shift of proton 1 19 What is the chemical shift of proton 3 20 What is the chemical shift of proton 4 (the COOH) 21 What is the chemical shift of proton 5 22 What is the chemical shift of proton 7 using the carbon chemical shift values: a) 15 b) 25 c) 40 d) 65 e) 105 f) 115 g) 130 h) 150 i) 170 j) What is the chemical shift of carbon 1 24 What is the chemical shift of carbon 2 25 What is the chemical shift of carbon 4 26 What is the chemical shift of carbon 6 27 What is the chemical shift of carbon 7 28 What is the chemical shift of carbon 8 29 What is the chemical shift of carbon 11 using the coupling constant (J) values (Hz): a) 0 b) 2 c) 4 d) 7 e) 12 f) 18 g) 36 h) 72 i) 136 j) What is the J value between protons 2 and 3 31 What is the J value between protons 12 and What is the J value between proton 10 and F
4 CHEMISTRY 213 XMAS OH 3 COOH 4 GHB 7 6 CH 3 N O 5 8 O 2 N N 13 F Rohypnol 9 Using the multiplicities: a) s b) d c) t d) q e) 5 lines f) 6 lines g) t of t h) d of d i) d of t j) d of d of d In the 500 MHz proton spectrum 33 What is the multiplicity of the protons 2 Assuming you can see $ 1 Hz couplings 34 What would be the multiplicity of proton 5 35 What would be the multiplicity of proton 10 In the proton coupled carbon spectrum (consider only 1 J couplings) 36 What is the multiplicity of carbon 9 37 What is the multiplicity of carbon 5 38 What is the multiplicity of carbon 7 39 What is the multiplicity of carbon 4 40 What is the likely spin system of the 3 protons of the benzene ring containing proton 5 at 500 MHz a) A 3 b) AA A c) ABC d) ABX e) A 2 X f) AA X g) AMX h) AA B i) A 2 B 41 How large is the M+1 peak in rohypnol relative to the Molecular ion a) 1% b) 2% c) 5% d) 8% e) 18% f) 26% g) 30% h) 35% i) 50% j) 100%
5 CHEMISTRY 213 XMAS 04 5 Using the following frequencies (Hz): a) 4.7 x 10 8 b) 5 x 10 8 c) 5.3 x 10 8 d) 5.3 x 10 9 e) 4.7 x f) 1 x g) 7.5 x h) 1 x i) 7 x j) 3 x At what frequency will the alcohol-oh of GHB absorb ir radiation 43 What resonance frequency would be used to detect the F of rohypnol, assuming the same instrument as Questions (γ F = 0.94γ H ) 44 Some airports are proposing to scan passengers using a frequency of Hz; what is the energy of a mole of airport photons (J mole -1 ) a) to b) to c) 10-9 to d) 10-3 to 10-4 e) 0 to 10 f) g) 10 4 to 10 5 h) 2 x 10 6 i) 3 x j) 2 x The molecule H 2 N-C/N is found in space Some of its relevant ir frequencies are at (cm -1 ) a) 3550 b) 3270 c) 2260 d) 1580 e) 1100 f) 700 g) Which corresponds to the C/N stretch 46 Which is the symmetrical N-H stretch 47 Which is the C-N stretch 48 Which is the N-H bend 49 How many fundamental frequencies are there: a) 7 b) 8 c) 9 d) 10 e) 13 f) 39 g) 44 h) 48 i) 49 j) 54
6 CHEMISTRY 213 XMAS 04 6 Some of the equations we have used this term are: E J = h 2 J(J+1)/8π 2 I ν = (1/2π)(k/μ) 1/2 ν = (γ/2π)b o N U /N L = e -ΔE/RT I = m 1 m 2 r 2 /(m 1 +m 2 ) Using the choices (cm -1 ) a) 20 b) 40 c) 60 d) 80 e) 120 f) 160 g) 200 h) 240 i) 320 j) If in the microwave spectra of H 2 O, the energy of the 1st line = 40 cm -1, what (in cm -1 ) will be the energy of the transition from E 1 to E 2 (E 0 = lowest energy level). 51 What (in cm -1 ) will be the energy of the 5th level, E The centre of the fundamental band for CO is at 2144 cm -1, and the spacing between the first two lines in the P branch of the rotational spectrum is 4 cm -1. What will be the frequency (cm -1 ) of the third line in the R branch a) 2128 b) 2132 c) 2136 d) 2140 e) 2144 f) 2148 g) 2152 h) 2156 i) 2160 j) In Question 52, what will be the frequency of the transition from v=0, J=2 to v=1, J=3 a) 2104 b) 2120 c) 2128 d) 2136 e) 2152 f) 2156 g) 2168 h) 2174 i) 2182 j) In Question 52, where would the first hotline of CO be a) 1068 b) 1072 c) 1076 d) 2140 e) 2150 f) 2190 g) 3216 h) 4260 i) 4288 j) In Question 52, what is the zero point energy for the C/O bond in J mol -1 a) 10-3 to 10-4 b) 10-2 to 10-3 c) 0.1 to 10-2 d) 0.1 to1 e) 1 to 100 f) 10 2 to 10 3 g) 10 3 to 10 4 h) 10 4 to 10 5 i) 10 5 to 10 6 j) 250
7 CHEMISTRY 213 XMAS If the H- 35 Cl stretching frequency occurs at 2990 cm -1, what would be the most reasonable value for the first overtone for the H-Cl stretch (cm -1 ) a) 8970 b) 6080 c) 5980 d) 5880 e) 3090 f) 2990 g) 2890 h) 1545 i) 1495 j) Where then would you expect the H- 37 Cl stretch to be observed (cm -1 ) a) 2143 b) 1500 c) 1495 d) 1490 e) 1447 f) 2990 g) 3016 h) 3350 i) 3677 j) If the spin quantum number for D is 1, how will the 1 H NMR spectrum of CHDCl 2 appear a) 1:2:1 triplet b) 1:1:1 triplet c) 1:3:3:1 quartet d) 1:1:1:1 quartet e) 1:4:1 triplet f) 1:1 doublet g) 1:3:1 triplet h) 3:1 doublet i) 1:3 doublet j) singlet Using a) singlet b) doublet c) triplet d) quartet e) d of quartets f) sextet g) septet h) nonet i) t of septets j) d of septets How will the CH signal of (CH 3 ) 2 CHNH 2 in its 1 H spectrum appear 59 at room temperature 60 at low temperature 61 How will the OH signal of (CH 3 ) 2 CHCOOH appear at room temperature
8 CHEMISTRY 213 XMAS 04 8 The following data may be useful in the next few questions NUCLEUS (all have I=1/2) 1 H 13 C 11 B 19 F 31 P 195 Pt 29 Si MAGNETOGYRIC RATIO (() % ABUNDANCE If 195 Pt nuclei resonate at 66.7 MHz on a 7 Tesla instrument, at what frequency (MHz) would 11 B nuclei resonate on this instrument a) 300 b) 278 c) 100 d) 98 e) 66.7 f) 55.6 g) 44.5 h) 22.2 i) 11 j) 9.9 If one had a sample of pure 195 PtF(CH 3 )Cl 2 63 What would be the width (Hz) of the signal in the platinum spectrum if the protons are NOT decoupled. [Assume 1 J PtF =500Hz, 2 J PtH =100Hz] a) 1800 b) 1500 c) 1200 d) 0 e) 150 f) 300 g) 450 h) 600 i) 800 j) If this sample was run on a 500MHz (proton) instrument, how many ppm would the most downfield line lie from the most upfield line [ 3 J FH =20Hz] a) 0.36 b) 0.34 c) 0.32 d) 0.30 e) 0.28 f) 0.26 g) 0.24 h) 0.22 i) 0.20 j) If one had a spectrometer which could measure all three nuclei on the same probe using the same magnetic field strength, in which order would the nuclei appear to resonate as the frequency of the probe was increased a) Pt<F<H b) Pt>F>H c) F<Pt<H d) F>Pt>H e) F<H<Pt f) F>H>Pt 66 If an proton appeared at 1050Hz downfield from TMS on a 300 MHz spectrometer Which of the following is this hydrogen most likely to be a) -COOH b) CH 3 -CH 3 c) -CHO d) Ar-H e) =CH 2 f) CH 2 I 2 g) (CH 3 ) 2 O h) (CH 3 ) 2 C=O i) CH 3 NH 2 j) H-OH 67 If two protons are coupled with J=7 Hz, what minimum difference in chemical shift must they have to appear first order at 360 MHz. Choices (ppm) a) 0.07 b) 0.11 c) 0.19 d) 0.28 e) 0.53 f) 0.83 g) 0.92 h) 1.06 i) 1.49 j) 1.88
9 CHEMISTRY 213 XMAS 04 9 Note the data at top of page 8 For the compound: A F 1 CH 3 3 Si H OCH 2 F 2 B making the normal assumptions about H-H coupling constants and low abundance nuclei, and using the choices (dqt means doublet of quartets of triplets) a) ddd b) tddd c) dddd d) qddtd e) ddqdt f) ddddt g) qddt h) tddq i) qttd j) dddtd 68 How would the 1 H spectrum of methyl protons 1 appear 69 How would the 29 Si spectrum appear 70 How would the 19 F spectrum of fluorines B appear using the choices (Hz) a) 2000 b) 200 c) 50 d) 10 e) 7 f) 2 g) 0 71 What value do you expect for the H(1)-H(2) coupling 72 What value do you expect for the H(1)-H(3) coupling 73 What value do you expect for the H(1)-F(A)coupling 74 What value do you expect for the F(A)-H(3) coupling 75 What value do you expect for the Si-H(3) coupling For F PPh 3 Pt Ph 3 P F 76 How would the Pt spectrum appear a) s b) d c) t d) dd e) ddd f) dddd g) ddt h) q i) tt j) 5 lines 77 What will be the intensity of the lines for one of the P in the 31 P NMR spectrum a) 1 b) 1:1 c) 1:1:1 d) 1:2:1 e) 1:4:1 f) 1:2:1:1:2:1 g) 3 1:2:1:4:8:4:1:2:1 h) 1:1:4:4:1:1 i) 1:2:1:2:4:2:1:2:1 j) H1:1:1:4:4:4:1:1: F Cl 2 5 FCH 2 CH 2 F H 3 P F Cl Pt Pt F Cl Cl F PH H 4
10 CHEMISTRY 213 XMAS J1 J2 J3 Answer using the following a = magnetically and chemically equivalent b = magnetically but NOT chemically equivalent c = chemically but NOT magnetically equivalent d = neither chemically nor magnetically equivalent 78 In molecule J1, H-3 and H-4 are 79 In molecule J2, F-1 and F-4 are 80 In molecule J2, H-2 and H-3 are 81 In molecule J3 {not 195 Pt}, F-3 and F-4 are 82 In molecule J3 {not 195 Pt}, P-1 and P-6 are 83 In molecule J3 {both 195 Pt}, Pt-2 and Pt-5 are The molecule M has 4 protons and 4 carbons. The 1 H- 1 H COSY and 13 C- 1 H HETCOR spectra are shown on the next page. 84 What is the connectivity in molecule M a) C 1 H A -C 2 H B -C 3 H C -C 4 H D b) C 4 H A -C 2 H B -C 1 H D -C 3 H C c) C 3 H D -C 1 H B -C 4 H C -C 2 H A d) C 2 H B -C 3 H D -C 1 H A -C 4 H C e) C 4 H C -C 1 H B -C 3 H A -C 2 H D f) C 1 H B -C 4 H C -C 3 H A -C 2 H D g) C 2 H D -C 4 H C -C 1 H A -C 3 H B h) C 1 H C -C 4 H B -C 2 H A -C 3 H D
11 CHEMISTRY 213 XMAS COSY A B C D A B C D HETCOR A B C D C-1 C-2 C-3 C-4
12 CHEMISTRY 213 XMAS THE OBJECTIVE IN THE FOLLOWING QUESTIONS IS TO SOLVE THE STRUCTURES. THERE ARE SOME QUESTIONS TO ANSWER ON THE GREEN COMPUTER SHEETS; YOU WILL DRAW YOUR SOLUTION TO EACH STRUCTURE ON THE YELLOW SHEETS. WORK SPACE IS PROVIDED AFTER EACH QUESTION, THIS WILL NOT BE MARKED; ONLY GIVE YOUR FINAL ANSWER ON THE YELLOW SHEETS, giving more than one answer leads to penalties. COMPOUND P (has only one type of functional group): C 8 H 12 O 2 85 How many DBE has compound P a) 0 b) 1 c) 2 d) 3 e) 4 f) 5 The 1 H NMR spectrum showed peaks at δ 3.3 (s), 2.3 (s) and 1.0 (s) in a 1:2:3 ratio. 13 C NMR * 200 (s) 42 (t) 38 (s) 30 (t) 15 (q) IR : two peaks close to 1715 cm -1 as only significant peaks 86 What functional group(s) must be present in P a) acid b) ester c) 2 aldehydes d) 2 ethers e) 2 ketones f) aldehyde/ketone g) ether/ketone h) ether/aldehyde i) alcohol/ketone DRAW YOUR STRUCTURE FOR COMPOUND P ON THE YELLOW SHEET IN THE PLACE PROVIDED.
13 CHEMISTRY 213 XMAS WORK SPACE - THIS WILL NOT BE MARKED
14 CHEMISTRY 213 XMAS Compound Q: C 8 H 14 O 2 87 How many DBE has compound Q a) 0 b) 1 c) 2 d) 3 e) 4 f) 5 13 C NMR * 168 (s) 137 (s) 125 (t) 65 (t) 30 (t) 27(q) 23(t) 14 (q) The IR and 300 MHz 1 H NMR spectra are given below: cm -1 only one band at ~900 is relevant multiplicities s s t s 5 6 t
15 CHEMISTRY 213 XMAS What functional group is present in Q a) alcohol b) ketone c) aldehyde d) ether e) alcohol-ketone f) alcohol-aldehyde g) ether-ketone h)ether-aldehyde i) acid j) ester DRAW YOUR STRUCTURE FOR COMPOUND Q ON THE YELLOW SHEET IN THE PLACE PROVIDED WORK SPACE - THIS WILL NOT BE MARKED
16 CHEMISTRY 213 XMAS Compound R: This gave in its high resolution mass spectrum its molecular ion at m/e (±0.013). The compound was known to contain chlorine. 35 Cl = Mass data for the CHNO containing fraction is given below: C H N O Mass C H N O Mass WRITE THE FORMULA FOR COMPOUND R ON THE YELLOW SHEET IN THE PLACE PROVIDED - you may need some of the data below! 89 How many DBE has compound R a) 0 b) 0.5 c) 1 d) 2 e) 3 f) 4 g) 5 h) 6 i) 7 13 C NMR spectrum : * 172 (s) 152 (d) 121 (d) 34 (t) 23 (t) 14 (q) The IR Spectrum and 1 H NMR spectrum are shown below cm -1
17 CHEMISTRY 213 XMAS multiplicities dt d q 6 t DRAW YOUR STRUCTURE FOR COMPOUND R ON THE YELLOW SHEET IN THE PLACE PROVIDED WORK SPACE - THIS WILL NOT BE MARKED
18 CHEMISTRY 213 XMAS Compound S: C 3 H 6 F 2 O 90 How many DBE has compound S a) 0 b) 0.5 c) 1 d) 2 e) 3 f) 4 g) 5 h) 6 i) 7 j) 8 IR Spectrum: 3400 cm -1 Assume below that dt means J for d > J for t 13 C NMR * 83 (dt)(t when F decoupled), 70(dt)(d when F decoupled) The 1 H NMR spectrum is shown below. The peak at δ 3.2 exchanges with D 2 O Multiplicities: ddd* t5 s * the smaller couplings overlap DRAW YOUR STRUCTURE FOR COMPOUND S ON THE YELLOW SHEET IN THE PLACE PROVIDED
19 CHEMISTRY 213 XMAS WORK SPACE - THIS WILL NOT BE MARKED
20 CHEMISTRY 213 XMAS Compound T: C 10 H 14 ClN 91 How many DBE has compound T a) 0 b) 1 c) 2 d) 3 e) 4 f) 5 g) 6 h) 7 i) 8 j) 9 Compound T showed a uv band at ~265 nm (, > 10 3 ) 13 C NMR * 146(s) 132(s) 127(s) 126(s) 125(d) 119(d) 24(t) 22(t) 14(q) 13(q) IR spectrum: ~3400 cm -1 1 H NMR spectrum: Multiplicities: d d s q q t t The singlet at δ 3.8 exchanges with D 2 O From the information above, the general structure of T can be determined, but not necessarily which isomer!
21 CHEMISTRY 213 XMAS Use the following to determine which isomer is T. 13 C additivity constants for calculating 13 C chemical shifts in aromatics X C-X ortho-c meta-c para-c Cl alkyl ~ N< When a long range C-H HETCOR (3 bond) experiment was carried out, cross peaks were found for the protons at δ 2.4 with the C s at δ 146 and 125, while for the protons at δ 2.7, cross peaks were seen with the C s at δ 146 and 132. DRAW YOUR STRUCTURE FOR COMPOUND T ON THE YELLOW SHEET IN THE PLACE PROVIDED WORK SPACE - not marked
22 CHEMISTRY 213 XMAS WORK SPACE - not marked end
23 UNIVERSITY OF VICTORIA FINAL EXAMINATION, DECEMBER 2004 CHEMISTRY F01 PRACTICAL SPECTROSCOPY TIME: 3 HOURS INSTRUCTOR: Dr Reg Mitchell THERE ARE 22 PAGES + THIS COVER SHEET + YELLOW SHEET [NOTE PAGES ARE PRINTED BOTH SIDES] ANSWER QUESTIONS 1-91 [1 mark each] ON THE GREEN COMPUTER SHEET WITH A PENCIL DRAW YOUR STRUCTURES FOR COMPOUNDS P, Q, R, S AND T AND GIVE THE FORMULA FOR R ON THE YELLOW SHEETS PROVIDED [P (12 marks), Q (12), R (12), S (14), T (18), formula of R = 1 mark][total marks = 160] MAKE SURE YOUR NAME AND REGISTRATION NUMBER ARE ON BOTH THE GREEN COMPUTER SHEET AND THE YELLOW ANSWER SHEET - DO THIS NOW MAKE SURE THERE ARE 22 PAGES OF QUESTIONS - NOTE THEY ARE PRINTED ON BOTH SIDES! ELECTRONIC CALCULATORS ARE PERMITTED, BUT MUST NOT CONTAIN STORED PROGRAMS OR FORMULAE DATA YOU MAY NEED: c = 3 x 10 8 m s -1 h = 6.6 x J s N = 6 x k = 1.38 x J K -1 R = 8.3 J K -1
24 FINAL EXAMINATION, DECEMBER 2004 YELLOW ANSWER SHEET CHEMISTRY F01 PRACTICAL SPECTROSCOPY LAST NAME: FIRST NAME AND INITIAL: REGISTRATION NUMBER: GIVE ONLY YOUR FINAL STRUCTURES ON THIS SHEET, SPACE FOR ROUGH WORK IS PROVIDED ON THE QUESTION SHEET. Part marks will be given for partial structures or partly correct structures; do NOT give all the detail as to how you derived the structure. MAKE SURE YOU SHOW ALL ATOMS INCLUDING HYDROGENS IN YOUR FINAL STRUCTURE MARKS FROM THIS SHEET [/69] = STRUCTURE FOR COMPOUND P [12 MARKS]
25 STRUCTURE FOR COMPOUND Q [12 MARKS] FORMULA FOR COMPOUND R [1 MARK] = STRUCTURE FOR COMPOUND R [12 MARKS] STRUCTURE FOR COMPOUND S [14 MARKS] STRUCTURE FOR COMPOUND T [18 MARKS]
UNIVERSITY OF VICTORIA FINAL EXAMINATION, DECEMBER 2008 CHEMISTRY A01 PRACTICAL SPECTROSCOPY
UNIVERSITY OF VICTORIA FINAL EXAMINATION, DECEMBER 2008 CEMISTRY 213 - A01 PRACTICAL SPECTROSCOPY TIME: 3 OURS INSTRUCTOR: Dr Reg Mitchell IN TIS EXAM TERE SOULD BE 26 WITE PAGES (check this) (which includes
More informationCHEM Chapter 13. Nuclear Magnetic Spectroscopy (Homework) W
CHEM 2423. Chapter 13. Nuclear Magnetic Spectroscopy (Homework) W Short Answer 1. For a nucleus to exhibit the nuclear magnetic resonance phenomenon, it must be magnetic. Magnetic nuclei include: a. all
More informationCHEM 213 FALL 2018 MIDTERM EXAM 2 - VERSION A
CEM 213 FALL 2018 MIDTERM EXAM 2 - VERSIN A Answer multiple choice questions on the green computer sheet provided with a PENCIL. Be sure to encode both your NAME and Registration Number (V#). You will
More informationCHEM 213 FALL 2016 MIDTERM EXAM 2 - VERSION A
CHEM 213 FALL 2016 MIDTERM EXAM 2 - VERSIN A Answer multiple choice questions on the green computer sheet provided with a PENCIL. Be sure to encode both your NAME and Registration Number (V#). You will
More informationPrinciples of Molecular Spectroscopy: Electromagnetic Radiation and Molecular structure. Nuclear Magnetic Resonance (NMR)
Principles of Molecular Spectroscopy: Electromagnetic Radiation and Molecular structure Nuclear Magnetic Resonance (NMR) !E = h" Electromagnetic radiation is absorbed when the energy of photon corresponds
More informationORGANIC - CLUTCH CH ANALYTICAL TECHNIQUES: IR, NMR, MASS SPECT
!! www.clutchprep.com CONCEPT: PURPOSE OF ANALYTICAL TECHNIQUES Classical Methods (Wet Chemistry): Chemists needed to run dozens of chemical reactions to determine the type of molecules in a compound.
More informationOAT Organic Chemistry - Problem Drill 19: NMR Spectroscopy and Mass Spectrometry
OAT Organic Chemistry - Problem Drill 19: NMR Spectroscopy and Mass Spectrometry Question No. 1 of 10 Question 1. Which statement concerning NMR spectroscopy is incorrect? Question #01 (A) Only nuclei
More informationChem 213 Final 2012 Detailed Solution Key for Structures A H
Chem 213 Final 2012 Detailed Solution Key for Structures A H COMPOUND A on Exam Version A (B on Exam Version B) C 8 H 6 Cl 2 O 2 DBE = 5 (aromatic + 1) IR: 1808 cm 1 suggests an acid chloride since we
More informationSpectroscopy in Organic Chemistry. Types of Spectroscopy in Organic
Spectroscopy in Organic Chemistry Spectroscopy Spectrum dealing with light, or more specifically, radiation Scope to see Organic Spectroscopy therefore deals with examining how organic molecules interact
More informationChapter 15 Lecture Outline
Organic Chemistry, First Edition Janice Gorzynski Smith University of Hawaii Chapter 5 Lecture Outline Introduction to NMR Two common types of NMR spectroscopy are used to characterize organic structure:
More informationNMR = Nuclear Magnetic Resonance
NMR = Nuclear Magnetic Resonance NMR spectroscopy is the most powerful technique available to organic chemists for determining molecular structures. Looks at nuclei with odd mass numbers or odd number
More information4) protons experience a net magnetic field strength that is smaller than the applied magnetic field.
1) Which of the following CANNOT be probed by an spectrometer? See sect 15.1 Chapter 15: 1 A) nucleus with odd number of protons & odd number of neutrons B) nucleus with odd number of protons &even number
More informationAnswers to Assignment #5
Answers to Assignment #5 A. 9 8 l 2 5 DBE (benzene + 1 DBE) ( 9 2(9)+2-9 8+1+1 = 10 ˆ 5 DBE) nmr pattern of two doublets of equal integration at δ7.4 and 7.9 ppm means the group (the δ7.9 shift) IR band
More informationORGANIC - CLUTCH CH ANALYTICAL TECHNIQUES: IR, NMR, MASS SPECT
!! www.clutchprep.com CONCEPT: PURPOSE OF ANALYTICAL TECHNIQUES Classical Methods (Wet Chemistry): Chemists needed to run dozens of chemical reactions to determine the type of molecules in a compound.
More information4) protons experience a net magnetic field strength that is smaller than the applied magnetic field.
1) Which of the following CANNOT be probed by an NMR spectrometer? See sect 15.1 Chapter 15: 1 A) nucleus with odd number of protons & odd number of neutrons B) nucleus with odd number of protons &even
More informationPaper 12: Organic Spectroscopy
Subject Chemistry Paper No and Title Module No and Title Module Tag Paper 12: Organic Spectroscopy 31: Combined problem on UV, IR, 1 H NMR, 13 C NMR and Mass - Part III CHE_P12_M31 TABLE OF CONTENTS 1.
More informationChapter 14. Nuclear Magnetic Resonance Spectroscopy
Organic Chemistry, Second Edition Janice Gorzynski Smith University of Hawai i Chapter 14 Nuclear Magnetic Resonance Spectroscopy Prepared by Rabi Ann Musah State University of New York at Albany Copyright
More informationExperiment 11: NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY
Experiment 11: NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY Purpose: This is an exercise to introduce the use of nuclear magnetic resonance spectroscopy, in conjunction with infrared spectroscopy, to determine
More informationThe resonance frequency of the H b protons is dependent upon the orientation of the H a protons with respect to the external magnetic field:
Spin-Spin Splitting in Alkanes The signal arising from a proton or set of protons is split into (N+1) lines by the presence of N adjacent nuclei Example 1: Bromoethane The resonance frequency of the H
More informationORGANIC - BROWN 8E CH NUCLEAR MAGNETIC RESONANCE.
!! www.clutchprep.com CONCEPT: 1 H NUCLEAR MAGNETIC RESONANCE- GENERAL FEATURES 1 H (Proton) NMR is a powerful instrumental method that identifies protons in slightly different electronic environments
More information7a. Structure Elucidation: IR and 13 C-NMR Spectroscopies (text , , 12.10)
2009, Department of Chemistry, The University of Western Ontario 7a.1 7a. Structure Elucidation: IR and 13 C-NMR Spectroscopies (text 11.1 11.5, 12.1 12.5, 12.10) A. Electromagnetic Radiation Energy is
More informationNMR Nuclear Magnetic Resonance Spectroscopy p. 83. a hydrogen nucleus (a proton) has a charge, spread over the surface
NMR Nuclear Magnetic Resonance Spectroscopy p. 83 a hydrogen nucleus (a proton) has a charge, spread over the surface a spinning charge produces a magnetic moment (a vector = direction + magnitude) along
More informationCHEM311 FALL 2005 Practice Exam #3
EM311 FALL 2005 Practice Exam #3 Instructions: This is a multiple choice / short answer practice exam. For the multiple-choice questions, there may be more than one correct answer. If so, then circle as
More information4) protons experience a net magnetic field strength that is smaller than the applied magnetic field.
1) Which of the following CANNOT be probed by an spectrometer? See sect 16.1 Chapter 16: 1 A) nucleus with odd number of protons & odd number of neutrons B) nucleus with odd number of protons &even number
More information- 1/2. = kb o = hνν + 1/2. B o increasing magnetic field strength. degenerate at B o = 0
NMR EXPERIMENT When magnetically active nuclei are placed into an external magnetic field, the magnetic fields align themselves with the external field into two orientations. During the experiment, electromagnetic
More informationChapter 9. Nuclear Magnetic Resonance. Ch. 9-1
Chapter 9 Nuclear Magnetic Resonance Ch. 9-1 1. Introduction Classic methods for organic structure determination Boiling point Refractive index Solubility tests Functional group tests Derivative preparation
More informationExperiment 2 - NMR Spectroscopy
Experiment 2 - NMR Spectroscopy OBJECTIVE to understand the important role of nuclear magnetic resonance spectroscopy in the study of the structures of organic compounds to develop an understanding of
More informationNuclear Magnetic Resonance Spectroscopy
13 Nuclear Magnetic Resonance Spectroscopy Solutions to In-Text Problems 13.1 (b) Apply Eq. 13.2b with = 360 MHz. chemical shift in Hz = δ = (4.40)(360) = 1584 Hz 13.2 (b) Follow the same procedure used
More information11. Proton NMR (text , 12.11, 12.12)
2009, Department of Chemistry, The University of Western Ontario 11.1 11. Proton NMR (text 12.6 12.9, 12.11, 12.12) A. Proton Signals Like 13 C, 1 H atoms have spins of ±½, and when they are placed in
More informationNUCLEAR MAGNETIC RESONANCE AND INTRODUCTION TO MASS SPECTROMETRY
NUCLEAR MAGNETIC RESONANCE AND INTRODUCTION TO MASS SPECTROMETRY A STUDENT SHOULD BE ABLE TO: 1. Identify and explain the processes involved in proton ( 1 H) and carbon-13 ( 13 C) nuclear magnetic resonance
More information4) protons experience a net magnetic field strength that is smaller than the applied magnetic field.
1) Which of the following CANNOT be probed by an spectrometer? See sect 16.1 Chapter 16: 1 A) nucleus with odd number of protons & odd number of neutrons B) nucleus with odd number of protons &even number
More informationProton NMR. Four Questions
Proton NMR Four Questions How many signals? Equivalence Where on spectrum? Chemical Shift How big? Integration Shape? Splitting (coupling) 1 Proton NMR Shifts Basic Correlation Chart How many 1 H signals?
More informationInstrumental Chemical Analysis
L15 Page1 Instrumental Chemical Analysis Nuclear Magnetic Resonance Dr. Ahmad Najjar Philadelphia University Faculty of Pharmacy Department of Pharmaceutical Sciences 1 st semester, 2017/2018 Nuclear Magnetic
More informationPaper 12: Organic Spectroscopy
Subject hemistry Paper No and Title Module No and Title Module Tag Paper 12: Organic Spectroscopy 34: ombined problem on UV, IR, 1 H NMR, 13 NMR and Mass- Part 6 HE_P12_M34 TABLE OF ONTENTS 1. Learning
More informationObjective 4. Determine (characterize) the structure of a compound using IR, NMR, MS.
Objective 4. Determine (characterize) the structure of a compound using IR, NMR, MS. Skills: Draw structure IR: match bond type to IR peak NMR: ID number of non-equivalent H s, relate peak splitting to
More informationNMR Spectroscopy. Chapter 19
NMR Spectroscopy Chapter 19 Nuclear Magnetic Resonance spectroscopy is a powerful analytical technique used to characterize organic molecules by identifying carbon-hydrogen frameworks within molecules.
More informationLecture 11. IR Theory. Next Class: Lecture Problem 4 due Thin-Layer Chromatography
Lecture 11 IR Theory Next Class: Lecture Problem 4 due Thin-Layer Chromatography This Week In Lab: Ch 6: Procedures 2 & 3 Procedure 4 (outside of lab) Next Week in Lab: Ch 7: PreLab Due Quiz 4 Ch 5 Final
More informationCM Chemical Spectroscopy and Applications. Final Examination Solution Manual AY2013/2014
NANYANG TECHNOLOGICAL UNIVERSITY DIVISION OF CHEMISTRY AND BIOLOGICAL CHEMISTRY SCHOOL OF PHYSICAL & MATHEMATICAL SCIENCES CM 3011 - Chemical Spectroscopy and Applications Final Examination Solution Manual
More information4. NMR spectra. Interpreting NMR spectra. Low-resolution NMR spectra. There are two kinds: Low-resolution NMR spectra. High-resolution NMR spectra
1 Interpreting NMR spectra There are two kinds: Low-resolution NMR spectra High-resolution NMR spectra In both cases the horizontal scale is labelled in terms of chemical shift, δ, and increases from right
More informationOrganic Chemistry 321 Workshop: Spectroscopy NMR-IR Problem Set
Organic Chemistry 321 Workshop: Spectroscopy NMR-IR Problem Set 1. Draw an NMR spectrum for each of the following compounds. Indicate each peak by a single vertical line (for example, a quartet would be
More informationORGANIC - EGE 5E CH UV AND INFRARED MASS SPECTROMETRY
!! www.clutchprep.com CONCEPT: IR SPECTROSCOPY- FREQUENCIES There are specific absorption frequencies in the functional group region that we should be familiar with EXAMPLE: What are the major IR absorptions
More informationChapter 13 Spectroscopy
hapter 13 Spectroscopy Infrared spectroscopy Ultraviolet-Visible spectroscopy Nuclear magnetic resonance spectroscopy Mass Spectrometry 13.1 Principles of Molecular Spectroscopy: Electromagnetic Radiation
More informationStructure solving based on IR, UV-Vis, MS, 1 H and 13 C NMR spectroscopic data. Problem solving session
Structure solving based on IR, UV-Vis, MS, 1 H and 13 C NMR spectroscopic data Problem solving session S. SANKARARAMAN DEPARTMENT OF CHEMISTRY INDIAN INSTITUTE OF TECHNOLOGY MADRAS CHENNAI 600036 sanka@iitm.ac.in
More informationTuesday, January 13, NMR Spectroscopy
NMR Spectroscopy NMR Phenomenon Nuclear Magnetic Resonance µ A spinning charged particle generates a magnetic field. A nucleus with a spin angular momentum will generate a magnetic moment (μ). If these
More informationUsing NMR and IR Spectroscopy to Determine Structures Dr. Carl Hoeger, UCSD
Using NMR and IR Spectroscopy to Determine Structures Dr. Carl Hoeger, UCSD The following guidelines should be helpful in assigning a structure from NMR (both PMR and CMR) and IR data. At the end of this
More informationModule 20: Applications of PMR in Structural Elucidation of Simple and Complex Compounds and 2-D NMR spectroscopy
Subject Chemistry Paper No and Title Module No and Title Module Tag Paper 12: Organic Spectroscopy Module 20: Applications of PMR in Structural Elucidation of Simple and Complex Compounds and 2-D NMR spectroscopy
More informationNuclear spin and the splitting of energy levels in a magnetic field
Nuclear spin and the splitting of energy levels in a magnetic field Top 3 list for 13 C NMR Interpretation 1. Symmetry 2. Chemical Shifts 3. Multiplicity 13 C NMR of C 3 O 1 NMR of C 3 O 13 C NMR of C
More informationNuclear Magnetic Resonance H-NMR Part 1 Introduction to NMR, Instrumentation, Sample Prep, Chemical Shift. Dr. Sapna Gupta
Nuclear Magnetic Resonance H-NMR Part 1 Introduction to NMR, Instrumentation, Sample Prep, Chemical Shift Dr. Sapna Gupta Introduction NMR is the most powerful tool available for organic structure determination.
More informationIR, MS, UV, NMR SPECTROSCOPY
CHEMISTRY 318 IR, MS, UV, NMR SPECTROSCOPY PROBLEM SET All Sections CHEMISTRY 318 IR, MS, UV, NMR SPECTROSCOPY PROBLEM SET General Instructions for the 318 Spectroscopy Problem Set Consult the Lab Manual,
More informationDepartment of Chemistry SUNY/Oneonta. Chem Organic Chemistry I
Department of Chemistry SUNY/Oneonta Chem 221 - Organic Chemistry I Examination #4 - ANSWERS - December 11, 2000 Answer to question #32 corrected 12/13/00, 8:30pm. INSTRUCTIONS This examination is in multiple
More informationPAPER No. 12: ORGANIC SPECTROSCOPY. Module 19: NMR Spectroscopy of N, P and F-atoms
Subject Chemistry Paper No and Title Module No and Title Module Tag Paper 12: Organic Spectroscopy CHE_P12_M19_e-Text TABLE OF CONTENTS 1. Learning Outcomes 2. 15 N NMR spectroscopy 3. 19 F NMR spectroscopy
More informationChapter 13: Molecular Spectroscopy
Chapter 13: Molecular Spectroscopy Electromagnetic Radiation E = hν h = Planck s Constant (6.63 x 10-34 J. s) ν = frequency (s -1 ) c = νλ λ = wavelength (nm) Energy is proportional to frequency Spectrum
More informationNUCLEAR MAGNETIC RESONANCE SPECTROSCOPY
NMR Spectroscopy 1 NULEAR MAGNETI RESONANE SPETROSOPY Involves interaction of materials with the low-energy radiowave region of the electromagnetic spectrum Origin of Spectra Theory All nuclei possess
More informationThe Final Learning Experience
Chemistry 416 Spectroscopy Fall Semester 1997 Dr. Rainer Glaser The Final Learning Experience Monday, December 15, 1997 3:00-5:00 pm Name: Answer Key Maximum Question 1 (Combination I) 20 Question 2 (Combination
More informationE35 SPECTROSCOPIC TECHNIQUES IN ORGANIC CHEMISTRY
E35 SPECTRSCPIC TECNIQUES IN RGANIC CEMISTRY Introductory Comments. These notes are designed to introduce you to the basic spectroscopic techniques which are used for the determination of the structure
More informationOther problems to work: 3-Chloropentane (diastereotopic H s), 1- chloropentane.
Let s look at some specific examples. Dichloroacetaldehyde, l 2 HHO, has two inequivalent toms, H1 and H2. We expect to see two resonances, one at around δ 10.5 ppm and one around δ 5.5 ppm. (The H2 resonance
More information16.1 Introduction to NMR. Spectroscopy
16.1 Introduction to NMR What is spectroscopy? Spectroscopy NUCLEAR MAGNETIC RESNANCE (NMR) spectroscopy may be the most powerful method of gaining structural information about organic compounds. NMR involves
More information16.1 Introduction to NMR Spectroscopy. Spectroscopy. Spectroscopy. Spectroscopy. Spectroscopy. Spectroscopy 4/11/2013
What is spectroscopy? NUCLEAR MAGNETIC RESONANCE (NMR) spectroscopy may be the most powerful method of gaining structural information about organic compounds. NMR involves an interaction between electromagnetic
More informationNMR spectra of some simple molecules. Effect of spinning: averaging field inhomogeneity (nmr1.pdf pg 2)
NMR spectra of some simple molecules Effect of spinning: averaging field inhomogeneity (nmr1.pdf pg 2) N S H 0 H o Because the protons have a magnetic field associated with them, the field changes as across
More informationBasic Concepts of NMR: Identification of the Isomers of C 4 O 2. by 1 H NMR Spectroscopy
Basic Concepts of NM: Identification of the Isomers of C H 8 O by H NM Spectroscopy Objectives NM spectroscopy is a powerful tool in determining the structure of compounds. Not only is it able to give
More informationLook for absorption bands in decreasing order of importance:
1. Match the following to their IR spectra (30 points) Look for absorption bands in decreasing order of importance: a e a 2941 1716 d f b 3333 c b 1466 1.the - absorption(s) between 3100 and 2850 cm-1.
More informationHWeb27 ( ; )
HWeb27 (9.1-9.2; 9.12-9.18) 28.1. Which of the following cannot be determined about a compound by mass spectrometry? [a]. boiling point [b]. molecular formula [c]. presence of heavy isotopes (e.g., 2 H,
More informationCHEMISTRY Organic Chemistry Laboratory II Spring 2019 Lab #5: NMR Spectroscopy
Team Members: Unknown # CHEMISTRY 244 - Organic Chemistry Laboratory II Spring 2019 Lab #5: NMR Spectroscopy Purpose: You will learn how to predict the NMR data for organic molecules, organize this data
More informationCH 3. mirror plane. CH c d
CAPTER 20 Practice Exercises 20.1 The index of hydrogen deficiency is two. The structural possibilities include two double bonds, a double do 20.3 (a) As this is an alkane, it contains only C and and has
More informationWilliam H. Brown & Christopher S. Foote
Requests for permission to make copies of any part of the work should be mailed to:permissions Department, Harcourt Brace & Company, 6277 Sea Harbor Drive, Orlando, Florida 32887-6777 William H. Brown
More informationOrganic Chemistry II (CHE ) Examination I February 11, Name (Print legibly): Key. Student ID#:
rganic hemistry II (HE 232-001) Examination I February 11, 2009 Name (Print legibly): Key (last) (first) Student ID#: PLEASE observe the following: You are allowed to have scratch paper (provided by me),
More informationNMRis the most valuable spectroscopic technique for organic chemists because it maps the carbon-hydrogen framework of a molecule.
Chapter 13: Nuclear magnetic resonance spectroscopy NMRis the most valuable spectroscopic technique for organic chemists because it maps the carbon-hydrogen framework of a molecule. 13.2 The nature of
More informationQuímica Orgânica I. Nuclear Magnetic Resonance Spectroscopy (I) Ciências Farmacêuticas Bioquímica Química AFB QO I 2007/08 1 AFB QO I 2007/08 2
Química Orgânica I Ciências Farmacêuticas Bioquímica Química AFB QO I 2007/08 1 Nuclear Magnetic Resonance Spectroscopy (I) AFB QO I 2007/08 2 1 Adaptado de: Organic Chemistry, 6th Edition; L. G. Wade,
More informationUnit 2 Organic Chemistry. 2.3 Structural Analysis Part 2:
CFE ADVANCED HIGHER Unit 2 Organic Chemistry 2.3 Structural Analysis Part 2: Mass Spectroscopy Infra-red Spectroscopy NMR Proton Spectroscopy Answers to Questions in Notes Learning Outcomes Exam Questions
More informationORGANIC - EGE 5E CH NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY
!! www.clutchprep.com CONCEPT: PURPOSE OF ANALYTICAL TECHNIQUES Classical Methods (Wet Chemistry): Chemists needed to run dozens of chemical reactions to determine the type of molecules in a compound.
More informationNuclear Magnetic Resonance Spectroscopy: Tools for Structure Determination
Nuclear Magnetic Resonance Spectroscopy: Tools for Structure Determination Chung-Ming Sun Department of Applied Chemistry National Chiao Tung University Hualien 300, Taiwan Introduction NMR (Nuclear Magnetic
More informationCH Exam #4 (Take Home) Date Due: 11/25,26/2013
CH2710 - Exam #4 (Take Home) Date Due: 11/25,26/2013 Section I - Multiple Choice - Choose the BEST answer from the choices given and place the letter of you choice in the space provided. 1. Energy absorbed
More informationStructure Determination: Nuclear Magnetic Resonance Spectroscopy
Structure Determination: Nuclear Magnetic Resonance Spectroscopy Why This Chapter? NMR is the most valuable spectroscopic technique used for structure determination More advanced NMR techniques are used
More informationChapter 14 Spectroscopy
hapter 14 Spectroscopy There are four major analytical techniques used for identifying the structure of organic molecules 1. Nuclear Magnetic Resonance or NMR is the single most important technique for
More informationIntroduction. The analysis of the outcome of a reaction requires that we know the full structure of the products as well as the reactants
Introduction The analysis of the outcome of a reaction requires that we know the full structure of the products as well as the reactants Spectroscopy and the Electromagnetic Spectrum Unlike mass spectrometry,
More informationInfrared Spectroscopy
Infrared Spectroscopy Introduction Spectroscopy is an analytical technique which helps determine structure. It destroys little or no sample. The amount of light absorbed by the sample is measured as wavelength
More informationClosed book exam, no books, notebooks, notes, etc. allowed. However, calculators, rulers, and molecular model sets are permitted.
Massachusetts Institute of Technology Organic Chemistry 5.13 Friday, September 26, 2003 Prof. Timothy F. Jamison Hour Exam #1 Name (please both print and sign your name) Official Recitation Instructor
More information1. neopentyl benzene. 4 of 6
I. 1 H NMR spectroscopy A. Theory 1. The protons and neutrons in atomic nuclei spin, as does the nucleus itself 2. The circulation of nuclear charge can generate a nuclear magnetic moment, u, along the
More informationUnit 3 Organic Chemistry. 3.3 Structural Analysis Part 2:
Unit 3 Organic Chemistry 3.3 Structural Analysis Part 2: Mass Spectroscopy Infra-red Spectroscopy NMR Proton Spectroscopy Answers to Questions in Notes Learning Outcomes Exam Questions & Answers MODIFIED
More information13.24: Mass Spectrometry: molecular weight of the sample
hapter 13: Spectroscopy Methods of structure determination Nuclear Magnetic Resonances (NMR) Spectroscopy (Sections 13.3-13.19) Infrared (IR) Spectroscopy (Sections 13.20-13.22) Ultraviolet-visible (UV-Vis)
More informationCHAPTER 3 SOLUTIONS TO EXERCISES
CHAPTER 3 SOLUTIONS TO EXERCISES Solution 3.1. 600.13 MHz 1 H spectrum (CDCl3): 6.921 (tt, J = 7.3, 1.1 Hz, 1H). The chemical shift is taken from the central line: 4153.66 Hz / 600.13 MHz = 6.9213 ppm.
More informationCHEM311 FALL 2005 Practice Exam #3
CHEM311 FALL 2005 Practice Exam #3 Instructions: This is a multiple choice / short answer practice exam. For the multiple-choice questions, there may be more than one correct answer. If so, then circle
More informationC h a p t e r S i x t e e n: Nuclear Magnetic Resonance Spectroscopy. An 1 H NMR FID of ethanol
0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0 2.2 2.4 2.6 2.8 3.0 3.2 3.4 3.6 C h a p t e r S i x t e e n: Nuclear Magnetic Resonance Spectroscopy An 1 NMR FID of ethanol Note: Problems with italicized numbers
More informationLecture 2 nmr Spectroscopy
Lecture 2 nmr Spectroscopy Pages 427 430 and Chapter 13 Molecular Spectroscopy Molecular spectroscopy: the study of the frequencies of electromagnetic radiation that are absorbed or emitted by substances
More informationJanuary 30, 2018 Chemistry 328N
Lecture 4 Some More nmr January 30, 2018 Tricks for solving unknowns Review. Empirical formula is lowest common denominator ratio of atomic composition From Homework: unknown has an empirical formula of
More informationCHEM 242 NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY CHAP 14B ASSIGN
CHEM 242 NUCLEAR MAGNETIC RESNANCE SPECTRSCPY CHAP 14B ASSIGN 1. A proton NMR spectrum is observed to contain following the pattern below; what do you conclude? A. This must be a quartet that is part of
More informationYale Chemistry 800 MHz Supercooled Magnet. Nuclear Magnetic Resonance
Yale Chemistry 800 Mz Supercooled Magnet Nuclear Magnetic Resonance B o Atomic nuclei in The absence of a magnetic field Atomic nuclei in the presence of a magnetic field α spin - with the field β spin
More informationThe Use of NMR Spectroscopy
Spektroskopi Molekul Organik (SMO): Nuclear Magnetic Resonance (NMR) Spectroscopy All is adopted from McMurry s Organic Chemistry The Use of NMR Spectroscopy Used to determine relative location of atoms
More informationAQA A2 CHEMISTRY TOPIC 4.10 ORGANIC SYNTHESIS AND ANALYSIS TOPIC 4.11 STRUCTURE DETERMINATION BOOKLET OF PAST EXAMINATION QUESTIONS
AQA A2 CHEMISTRY TOPIC 4.10 ORGANIC SYNTHESIS AND ANALYSIS TOPIC 4.11 STRUCTURE DETERMINATION BOOKLET OF PAST EXAMINATION QUESTIONS 1 1. Consider the following reaction sequence. CH 3 CH 3 CH 3 Step 1
More information1.1 Is the following molecule aromatic or not aromatic? Give reasons for your answer.
Page 1 QUESTION ONE 1.1 Is the following molecule aromatic or not aromatic? Give reasons for your answer. 1.2 List four criteria which compounds must meet in order to be considered aromatic. Page 2 QUESTION
More informationChapter 13 Structure t Determination: Nuclear Magnetic Resonance Spectroscopy
John E. McMurry www.cengage.com/chemistry/mcmurry Chapter 13 Structure t Determination: ti Nuclear Magnetic Resonance Spectroscopy Revisions by Dr. Daniel Holmes MSU Paul D. Adams University of Arkansas
More informationInfrared Spectroscopy: Identification of Unknown Substances
Infrared Spectroscopy: Identification of Unknown Substances Suppose a white powder is one of the four following molecules. How can they be differentiated? H N N H H H H Na H H H H H A technique that is
More informationNuclear Spin States. NMR Phenomenon. NMR Instrumentation. NMR Active Nuclei. Nuclear Magnetic Resonance
Nuclear Magnetic Resonance NMR Phenomenon µ A spinning charged particle generates a magnetic field. A nucleus with a spin angular momentum will generate a magnetic moment (!). E Nuclear Spin States aligned
More informationYour Name: Question 1. 2D-NMR: C 6 H 10 O 2. (20 points)
Question 1. 2D-NMR: C 6 H 10 O 2. (20 points) Integrations show signals 3H 1 & 5, 2H for signal 4, and 1H each for signals 2 and 3. - Draw the structure. - Assign the hydrogens to signals 1 5 (that is,
More informationModule 13: Chemical Shift and Its Measurement
Subject Chemistry Paper No and Title Module No and Title Module Tag Paper 12: Organic Spectroscopy CHE_P12_M13_e-Text TABLE OF CONTENTS 1. Learning Outcomes 2. Introduction 3. Shielding and deshielding
More informationSTRUCTURE ELUCIDATION BY INTEGRATED SPECTROSCOPIC METHODS
Miscellaneous Methods UNIT 14 STRUCTURE ELUCIDATION BY INTEGRATED SPECTROSCOPIC METHODS Structure 14.1 Introduction Objectives 14.2 Molecular Formula and Index of Hydrogen Deficiency 14.3 Structural Information
More informationORGANIC - BROWN 8E CH INFRARED SPECTROSCOPY.
!! www.clutchprep.com CONCEPT: PURPOSE OF ANALYTICAL TECHNIQUES Classical Methods (Wet Chemistry): Chemists needed to run dozens of chemical reactions to determine the type of molecules in a compound.
More informationExam (6 pts) Show which starting materials are used to produce the following Diels-Alder products:
Exam 1 Name CHEM 212 1. (18 pts) Complete the following chemical reactions showing all major organic products; illustrate proper stereochemistry where appropriate. If no reaction occurs, indicate NR :
More informationPractice Exam 2 Answer
Chemistry 60 (Reich) SECND UR EXAM Thur. April 4, 20 Practice Exam 2 Answer Question/Points R-0F /2 R-0G /20 R-0 /0 R-0I /2 R-0J /20 Total /00 i 9 Average 6 Median 0 AB BC 0 CD 40 Name Grading Distribution
More informationChapter 13: Nuclear Magnetic Resonance (NMR) Spectroscopy direct observation of the H s and C s of a molecules
hapter 13: Nuclear Magnetic Resonance (NMR) Spectroscopy direct observation of the s and s of a molecules Nuclei are positively charged and spin on an axis; they create a tiny magnetic field + + Not all
More information