Self-study Notes Module 7 (Optional Material)
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1 Self-study Notes Module 7 (Optional Material) Dichotomous Dependent Variable A dichotomous dependent variable has just two possible values. The two values represent two mutually exclusive categories of behavior such as agreeing or disagreeing with a particular statement, passing or failing a test, or showing or not showing some behavioral characteristic. The psychologist selects one of the two categories (e.g., agreeing, passing, showing a symptom) to represent the outcome of interest. The proportion of people in the study population have the outcome of interest is represented by the Gree letter π. (The symbol π is used here to represent a population proportion and should not be confused with the irrational number 3.14 that is frequently used in mathematics.) One-group Design A population proportion can be estimated from a random sample of size n. The sample proportion n π = i=1 y i /n (7.1) is an estimate of π where y i = 0 or 1. Participants who have the outcome of interest (e.g., agreeing, passing, showing a symptom) are assigned a y-score of 1, and participants who do not have the outcome of interest (e.g., not agreeing, failing, not showing a symptom) are assigned a y-score of 0. Note that a sample proportion is simply the number of participants who have the trait of interest (denoted as f) divided by the sample size, so that Equation 7.1 also can be written as π = f/n. The estimated standard error of π is SE π = π (1 π )/n (7.2) From Equation 7.2, it is clear that increasing the sample size will decrease the value of the standard error. Small values of SE π indicate that the sample proportion (Equation 7.1) is liely to be similar to the population proportion. The estimated standard error by itself may not be an interesting value to interpret, but SE π can be combined with π to compute a confidence interval for π which does have an important interpretation. An approximate 100(1 α)% confidence interval for π is π ± z α/2 SE π (7.3) where z α/2 is a two-sided critical z-value. 1
2 Example 7.1. About 16,000 students at CSULB purchase a meal plan. The Director of Food Services wants to now the proportion of these 16,000 students who are satisfied with the quality of the food. A random sample of 300 students was obtained. All 300 students were contacted by or phone and ased if they were satisfied or dissatisfied with the quality of the food. In the sample of 300 students, 120 said they were satisfied. A 95% confidence interval for π, the proportion of all 16,000 students who would have said they are satisfied with the food quality, is computed below π = 120/300 = 0.40 SE π = 0.4(0.6)/300 = upper 95% limit = (0.0283) = lower 95% limit = (0.0283) = The Director can be 95% confident that between 34.5% and 45.5% of the 16,000 students are satisfied with the food quality. Note that a proportion multiplied by 100 can be interpreted as a percentage. Two-group Experiment In a two-group experiment, π 1 is the proportion of all people in the study population who would have the specified outcome assuming they had all received Treatment 1, and π 2 is the proportion of all people in the study population who would have the specified outcome assuming they had all received Treatment 2. A measure of effect size in a twogroup experiment is π 1 π 2. In a two-group experiment, π 1 is estimated from a sample of size n1 in group 1 and π 2 is estimated from sample of size n2 in group 2. The following sample proportion in group j is an estimate of π j π j = n j y i=1 ij /n j (7.4) where yij = 1 if participant i in group j has the outcome of interest; otherwise yij = 0. Note that the numerator of Equation 7.4 is the number of participants in group j who have the specified outcome. This frequency count is denoted as fj so that π j = fj/nj. Confidence Interval for π 1 π 2 An approximate 100(1 α)% confidence interval for π 1 π 2 is π 1 π 2 ± z α/2 SE π 1 π 2 (7.5) π 1 (1 π 1 ) π 2 (1 π 2 ) where SE π 1 π 2 = +. n 1 n 2 2
3 Example 7.2. A random sample of 200 participants was obtained from a volunteer pool of about 3,000 undergraduate students, and the sample was randomized into two groups of equal size. All participants were ased to sit quietly in a small room for two hours. The participants in group 1 also were told that the experiment would examine the effects of stimulus deprivation and were ased to sign a consent form indicating a possibility of psychological harm. Participants in group 2 were simply told that they were a control group. All participants were shown a button to push if they needed to exit the room before the end of the experiment. The button for group 1 participants was labeled panic button. The button for group 2 participants had no label. In group 1, f 1 = 57 participants pressed the button. In group 2, f 2 = 15 participants pressed the button. The 95% confidence interval for π 1 π 2 was [0.300, 0.540] and indicates that the proportion of the 3,000 students who would have pressed the button under the fear instructions would be to greater than if they had received the neutral instruction. Hypothesis Testing In a two-group study, the null hypotheses H0: π 1 = π 2 may be tested using the following test statistic X 2 = n [ f 1 (n 2 f 2 ) f 2 (n 1 f 1 ) n 2 ]2 /[n 1 n 2 (f 1 + f 2 )(n f 1 f 2 )] (7.6) where n = n 1 + n 2. The test of H0: π 1 = π 2 based on Equation 7.6 is called a chi-square test of independence. If X 2 > z 2 α/2, then H0 is rejected. Alternatively, statistical pacages will report the p-value associated with the obtained X 2 value, and H0 is rejected if the p- value is small (e.g., less than.05). If H0 is rejected, then the sample estimate of π 1 π 2 determines which alternative hypothesis to accept. For instance, if H0 is rejected and π 1 π 2 > 0, then π 1 π 2 > 0 is accepted. If the chi-square and p-value results are reported in a research report, APA guidelines now require psychologists to supplement those results with a confidence interval for a measure of effect size, such as π 1 π 2. One-factor Experiments In a one-factor experiment with levels of the independent variable, the null hypothesis of equal population proportions is H0: π 1 = π 2 = = π. A chi-square test of independence (a more general version of Equation 7.6) may be used to test H0, but this test suffers from the same problems as the test for equal population means described previously for the one-way ANOVA because we now that H0 will be false in virtually any real study. Thus, an experiment that leads to the conclusion that H0 should be rejected does not provide the type of information that can be used to support a theory or advance nowledge. Unlie the test of H0: π 1 = π 2 = = π, tests of all pairwise comparisons using Equation 7.6 with a Bonferroni adjusted α or confidence intervals for all pairwise comparisons using Equation 7.5 with a Bonferroni adjusted α provide useful information. The confidence interval for a linear contrast of population proportions described below will also provide useful information. 3
4 An approximate 100(1 α)% confidence interval for 2 j=1 c j π j ± z α/2 c j 2 where j=1 c j π j(1 π j) n j j=1 π j(1 π j) j=1 c j π j is n j (7.7) is the estimated standard error of the linear contrast of sample proportions. Bonferroni simultaneous confidence intervals are obtained by replacing α with α* = α/v in Equation 7.7 where v is the number of confidence intervals to be examined. Example 7.3. A random sample of 180 participants was obtained from a volunteer pool of about 4,500 undergraduate students at UC Davis. The 180 participants were randomized into three groups of equal size. All 180 participants were shown a video clip that showed a man robbing a jewelry store. All participants were then shown a photo lineup of three men, one of which was the robber. In the lineup shown to group 1, both innocent men looed very different than the robber. In the lineup shown to group 2, one innocent man looed similar to the robber and one looed very different than the robber. In the lineup shown to group 3, both innocent men looed similar to the robber. The proportion of participants who correctly identified the robber in the 3- photo lineup was 0.433, 0.400, and in groups 1, 2, and 3, respectively. The psychologist has developed a theory that will be supported if π 1 is similar to π 2 and π 3 > (π 1 + π 2 )/2. Larger values of π 3 (π 1 + π 2 )/2 provide greater support for the theory. Bonferroni 95% simultaneous confidence intervals are shown below. Contrast Estimate SE Lower Limit Upper Limit π 1 π π 3 (π 1 + π 2 )/ Let π j represent the proportion of all 4,500 undergraduates who would have correctly identified the robber under condition j. The psychologist can be 95% confident that π 3 is to larger than (π 1 + π 2 )/2 and that π 1 is at most smaller or at most larger than π 2. These results support for the psychologist s theory, but a larger sample will be needed to more accurately determine the similarity of π 1 and π 2. Two-factor Experiments In a 2 2 factorial experiment, the population proportions under each of the four treatment combinations are shown below. Factor A Factor B b 1 b 2 a 1 π 11 π 12 a 2 π 21 π 22 4
5 The main effects, interaction effect, and simple main effects, defined in terms of population proportions, are shown below along with the contrast coefficients. Equation 7.7 may be used to obtain confidence intervals for any of these effects. c 1 c 2 c 3 c 4 A: ½ ½ -½ -½ (π 11 + π 12 )/2 (π 21 + π 22 )/2 B: ½ -½ ½ -½ (π 11 + π 21 )/2 (π 12 + π 22 )/2 AB: π 11 π 12 π 21 + π 22 A at b1: π 11 π 21 A at b2: π 12 π 22 B at a1: π 11 π 12 B at a2: π 21 π 22 Example 7.4. A mail order company has about 400,000 customers. A new web page that includes customer ratings of each product has been developed but is more expensive to maintain than the current version. The company wants to compare the effectiveness of the two web pages before deciding which web page to use. In addition to comparing the two web pages, the company also wants to assess the effectiveness of a $20 coupon. A random sample of 2,000 customers was obtained and randomized into four groups of equal size. All 2,000 sample customers were contacted by . Customers in groups 1 and 2 were given a lin to the new web site that included product ratings, and customers in groups 3 and 4 were given a lin to the currently used web page. Customers in groups 1 and 3 were given a $20 coupon, and customers in groups 2 and 4 did not receive the coupon. The number of sample customers who made a purchase within the next 60 days was determined for each of four groups and the data are given below. Group 1 Group 2 Group 3 Group 4 f 11 = 42 f 12 = 61 f 21 = 73 f 22 = 94 The 95% confidence interval for the interaction effect was [-0.055, 0.064]. This interaction effect was determined to be small and main effects were examined next. The 95% confidence interval for the main effect of web page was [-0.094, ], indicating that the proportion of the 400,000 customers who would mae a purchase from the new web site would be to greater than with the old web site. The 95% confidence interval for the main effect of the $20 coupon was [-0.070, ], indicating that the proportion of the 400,000 customers who would mae a purchase after receiving a $20 coupon would be to greater than without the coupon. Non-experimental Designs The confidence interval for π 1 π 2 (Equation 7.5), the confidence interval for j=1 c j π j (Equation 7.7), and the chi-square test of independence also can be applied to nonexperimental designs where participants are classified into two groups according to some preexisting characteristic, such as freshman/sophomore, democrat/republican, 5
6 and male/female, rather than being randomly assigned to treatment conditions. In nonexperimental designs, an observed relation between the independent variable and the dichotomous dependent variable cannot be interpreted as a causal relation because the relation may be due to one or more unmeasured variables (i.e., confounding variables) that are related to both the dependent variable and the independent variable. The interpretation of the population proportions is not the same in experimental and non-experimental designs. Specifically, in a non-experimental design π j is the proportion of all people in the study subpopulation who belong to category j (e.g., male, democrat, freshman) and have the specified outcome. Within-subjects Experiments The analysis of within-subjects designs is more complicated with a dichotomous dependent variable than with a quantitative dependent variable. The simplest case where each participant is measured under two treatment conditions will be considered here. With two dichotomous measurements (coded 1 or 2 with 1 indicating the presence of the outcome) there are four possible response patterns in a 2-treatment study, as shown below: Treatment 1: Treatment 2: π 11 π 12 π 21 π 22 where π ij is the proportion of people in the study population who would have an i response (i = 1 or 2) for Treatment 1 and a j response (j = 1 or 2) for Treatment 2. For example, π 21 is the proportion of people in the study population who would not have exhibited the outcome under Treatment 1 (i = 2) but would have exhibited the outcome under Treatment 2 (j = 1). The two parameters of primary interest are π 1 = π 11 + π 12 and π 2 = π 11 + π 21 where π 1 is the proportion of people in the study population who would have a measurement 1 response of 1 and π 2 is the proportion of people in the study population who would have a measurement 2 response of 1. Assuming no carryover effect, π 1 π 2 has the same interpretation in a two-level within-subjects experiment as in a two-group betweensubjects experiment. In a random sample of size n, the estimates of the population proportions are π ij =f ij /n, π 1 = π 11 + π 12, and π 2 = π 11 + π 21. An approximate 100(1 α)% confidence interval for π 1 π 2 is 6
7 π 1 π 2 ± z α/2 SE π 1 π 2 (7.8) where SE π 1 π 2= [π 21 + π 12 (π 21 π 12 ) 2 ]/n is the estimated standard error of π 1 π 2 in a within-subjects design. Note that π 1 π 2 = (π 11 + π 12 ) (π 11 + π 21 ) = π 12 π 21 so that Equation 7.8 may be computed using only the estimates of π 12 and π 21. SPSS does not compute Equation 7.8 but it does provide a test of H0: π 1 = π 2 called the McNemar test. The McNemar test rejects H0 if the test statistic (f 12 f 21 ) 2 /(f 12 + f 21 ) is 2 greater than z α/2 (or alternatively if the p-value for the test statistic is less than α). Recall that in a within-subjects experiment with a quantitative dependent variable, the correlation between the measurements determines the magnitude of the standard error with larger correlations resulting in a smaller standard error. It is not obvious from the standard error in Equation 7.8 how the association between the two dichotomous measures affects the value of the standard error. After some tedious algebra, it can be shown that SE π 1 π 2= [π 21 + π 12 (π 21 π 12 ) 2 ]/n can be re-expressed as SE π 1 π 2 = π 1 (1 π 1 ) n + π 2 (1 π 2 ) n 2ρ 12 π 1(1 π 1)π 2(1 π 2) n (7.9) where ρ 12 is the sample Pearson correlation between the two dichotomous measurements. When a Pearson correlation is computed from two dichotomous variables it is usually referred to as a phi coefficient. It is clear from Equation 7.9 that the value of SE π 1 π 2 in a within-subjects experiment is determined by the magnitude of the correlation between the two dichotomous measurements. In typical within-subject experiment, the correlation between the two dichotomous measures is a positive value, and consequently SE π 1 π 2 will usually be smaller for a within-subjects experiment than for a corresponding between-subjects experiment. Example 7.5. A random sample of 40 participants was obtained from a volunteer pool of undergraduate students. One by one, each participant was brought into a room with 15 other students (who were actually woring with the experimenter and were acting out rehearsed roles). The group discussed the pros and cons of providing military aid to a particular country. As rehearsed, none the arguments given by the 15 students were very convincing. The discussion leader ased for a show of hands of those in favor of providing military aid and, as rehearsed, 14 of the 15 students raised their hands. Before leaving the meeting, everyone was ased to write their vote (yes or no) on piece of paper and place it in a box as they left the room. Each participant was measured twice their public vote and their private vote. The sample data are shown below. 7
8 Public vote: Y Y N N Private vote: Y N Y N The value of π 1 π 2 can be thought of as the effect of social pressure. The 95% confidence interval for π 1 π 2 was (26/40 4/40) ± 1.96 [ (.65.1) 2 ]/40 = [.343,.757], indicating that the proportion of all college students in the study population who would vote with the majority would be.343 to.757 greater when voting publicly than privately. Logistic Regression Model The multiple linear regression model in Module 5 is appropriate when the response variable is quantitative. If the response variable is dichotomous, the following logistic regression model can be used y i = θ i 1 + θ i + e i (7.10) where y i is a dichotomous response variable with values 0 and 1, θ i = exp(β 0 + β 1 x 1i + β 2 x 2i + + β q x qi ) is the log-odds of person i having the outcome, e i is the prediction θ error for person i, and i is the probability of person i having the outcome. The slope 1 + θ i coefficient β j describes the change in log-odds of the outcome associated with a 1-point increase in x j, controlling for all other predictor varaibles in the model. Logistic regression programs will also report an estimate of exp(β j ) which describes the multiplicative change in the odds of the outcome associated with a 1-point increase in x j, controlling for all other predictor variables in the model. The value 100[exp(β j ) 1]% describes the percent change in the odds of the outcome associated with a 1-point increase in x j, controlling for all other predictor variables in the model. To better understand the interpretation of a slope coefficient, it is necessary to understand the definition of an odds. The odds of some outcome is defined as the probability of the outcome divided by 1 minus the probability of the outcome. For example, if the probability of the outcome is.8, then the odds of the outcome is.8/(1.8) = 4. Probabilities are usually more easily interpreted than odds. The estimated probability of the outcome for participant i is θ i 1+ θ i where θ i = exp(β 0 + β 1x 1i + β 2x 2i + + β qx qi ). It is often informative to examine the estimated probability of the outcome for low, moderate, and high values of one predictor variable with the values of all other predictor variables set at their mean value. 8
9 The parameter estimates (β 0, β 1,, β q) and their standard errors do not have simple formulas. These estimates and their standard errors can be obtained using logistic regression computer programs. These programs will compute the following approximate 100(1 α)% confidence interval for β j β j ± z α/2 SE β j (7.11) and an approximate 100(1 α)% exponentiating the lower and upper limits of Equation confidence interval for exp(β j ) is obtained by Example 7.5. A random sample of 200 graduating psychology majors seeing employment was obtained and all participants agreed to report their employment status six months after graduation. The number of months of wor experience (x 1 ) and GPA in psychology courses (x 2 ) was determined for all 200 participants at the time of graduation. Employment status (employed = 1, not employed = 0) six months after graduation was determined for all 200 participants. 95% confidence intervals for β j and 100[exp(β j 1)]% are given below. β j 95% Lower Limit 95% Upper Limit 100[exp(β j) 1]% 95% Lower Limit 95% Upper Limit Wor Experience % 0.90% 7.14% Psychology GPA % 6.93% 17.23% The psychologist can be 95% confident that a 1-month increase in wor experience, controlling for psychology GPA, is associated with a 0.90% to 7.14% increase in the odds of being employed. The psychologist can be 95% confident that a 1-point increase in psychology GPA, controlling for wor experience, is associated with a 6.93% to 17.23% increase in the odds of being employed. The estimated probabilities of employment for x 1 = 0, 12, and 24 months of wor experience, assuming a psychology GPA of x 2 = 3.20, are given below. Months of Wor Experience Estimated Probability of Employment The estimated probabilities of employment for psychology GPAs of x 2 = 2.6, 3.2, and 3.8, assuming 12 months of wor experience, are given below. Psychology GPA Estimated Probability of Employment The above estimated probabilities of employment for different values of wor experience and psychology GPA provide a useful description of how strongly wor experience and psychology GPA are related to the probability of employment. 9
10 Sample Size Requirements The sample size requirement to estimate π with desired confidence and precision is approximately n = 4[π (1 π )](z α/2 /w) 2 (7.12) where w is the desired width of the 100(1 )% confidence interval and π is a planning value for π. In situations where the psychologist has no idea about the liely value of π, the planning value can be set to.5, which maximizes the term in square bracets and gives a sample size requirement that is larger than needed to obtain the desired width. The psychologist will often have a range of plausible values for π, and using the value within the plausible range that is closest to.5 will give a conservatively large sample size requirement. Example 7.6. A psychologist is woring with a public policy group to help design an advertisement that will persuade voters to support a ¼ cent sales tax increase. The sales tax will be used fund a new a psychological support program for adolescents who have entered the criminal justice system as first-time offenders. Before spending 2 million dollars to air the advertisement on TV, the psychologist wants to assess its persuasiveness using a random sample of registered voters. The psychologist decided to set π =.5 and wants a 95% confidence interval for π to have a width of.15. The required sample size is n = 4[.5(1.5)](1.96/0.15) 2 = The sample size requirement per group to estimate π 1 π 2 in a two-group design with desired confidence and precision is approximately n j = 4[π 1(1 π 1) + π 2(1 π 2)](z α/2 /w) 2 (7.13) where π j is a planning value for π j. Example 7.7. Thousands of people are currently serving prison terms because they confessed to crimes they did not commit. A psychologist is trying to understand why people mae false confessions and is planning a study to determine if college students can be pressured into confessing to a minor crime they did not commit. Participants will be randomly sampled from a volunteer pool and then randomized into two groups of equal size with group 1 serving as a control condition. Using information about false confessions from the literature, the psychologist sets π 1 =.05 and π 2 =.15. The psychologist would lie to obtain a 95% confidence interval for π 1 π 2 that has a width of 0.1. The sample size requirement per group is approximately n j = 4[.05(.95) +.15(.85)](1.96/0.1) 2 =
11 The sample size requirement per group to estimate and precision is approximately j=1 c j π j with desired confidence n j = 4[ j=1 c 2 j π j(1 π j) ](z α/2 /w) 2. (7.14) Example 7.8. A 2 2 factorial experiment is planned in which college student participants will indicate if they would or would not seriously consider purchasing a new type of smart phone. The participants will be randomized into four groups and each will be given a new smart phone to try for 30 days. The smart phones were standard size or oversized (Factor A) and had one of two different user interfaces (Factor B). From preliminary mareting research, the planning values for π 11, π 12, π 21, and π 22 were set to.1,.2,.2, and.3, respectively. The psychologist wants the 95% confidence intervals for each main effect to have a width of about 0.1. Applying Equation 7.12 gives the following approximate sample size per group n j = 4[.1(.9)/4 +.2(.8)/4 +.2(.8)/4 +.3(.7)/4](1.96/0.1) 2 = The sample size requirement to estimate π 1 π 2 in a within-subjects design with desired confidence and precision is approximately n = 4[π 1(1 π 1) + π 2(1 π 2) 2ρ 12 π 1π 2(1 π 1)(1 π 2)](z α/2 /w) 2 (7.15) where ρ 12 is a planning value of the phi coefficient. Setting ρ 12 equal to the smallest value within a range of plausible values suggested by prior research or expert opinion will give a conservatively large sample size requirement. Example 7.9. A study is planned in which community college students are given $20 and are then ased if they would lie to play two different games. In the first game, they must bet $10 in a coin flip where they will either win another $12 or lose their $10. In the second game, they must bet $5 in a coin flip where they will either win another $6 or lose their $5. Each participant can choose to play both games, only the $10 game, only the $5 game, or neither game. Based on results from a pilot study, the psychologist sets π 1=.35 (the expected proportion of students who will play the $5 game), π 2=.25 (the expected proportion of students who will play the $10 game), and ρ 12 =.6. The sample size required to estimate π 1 π 2 with 95% confidence and width of 0.1 is n = 4[.25(.75) +.35(.65) 2(.6) (. 25)(. 35)(.75)(.65)](1.96/0.1) 2 = Assumptions The confidence intervals (Equations 7.3, 7.5, 7.7, 7.8), the chi-square test of independence (Equation 7.6), and the McNemar test assume random sampling and independence among participants. The test and confidence intervals, which are given in most statistics texts, are called large-sample methods because the coverage probability of the confidence interval is guaranteed to be close to 1 α and the directional error probability of the statistical tests are guaranteed to be close to α/2 only in large samples. 11
12 In recent years, simple alternatives to Equations 7.3, 7.5, 7.7, and 7.8 have been developed that perform well in small samples. An alternative to Equation 7.3 is the following Agresti-Coull confidence interval π ± z α/2 SE π (7.3-alt) where SE π = π (1 π )/(n + 4) and π = (f + 2)/(n + 4). An alternative to Equation 7.5 is the following Agresti-Caffo confidence interval π 1 π 2 ± z α/2 SE π 1 π 2 where SE π 1 π 2 = π 1 (1 π 1 ) n π 2 (1 π 2 ) n (7.5-alt) and π j = (f j + 1)/(n j + 2). An alternative to Equation 7.7 is the following Price-Bonett confidence interval j=1 c j π j ± z α/2 SE cj π j j=1 (7.7-alt) where SE j=1 cj π j 2 π j(1 π j) = j=1 c, j n j + 4/m π j = (f j + 2/m)/(n j + 4/m), and m is the number of nonzero c j values. An alternative to Equation 7.8 is the following Bonett-Price confidence interval π 1 π 2 ± z α/2 SE π 1 π 2 (7.8-alt) where SE π 1 π 2= [π 21 + π 12 (π 21 π 12 ) 2 ] n+2 and π ij = (f ij + 1)/(n + 2). 12
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