Paño Fijo M-Tres, con Poliamida de 15 Mediterránea RPT

Transcription

1 Cálculo del coefcente de transmsón térmca (f) Paño Fjo M-Tres, con Polamda de 15 Medterránea RPT Clente: Alcemar Cálculos realzados or Technoform BATEC Ibérca, s.l. Laa Cardona Tel: / Fax: Emal: Fecha: Resultados Ventana de rebatr RTP M-3 medante BISCO según norma EN ISO :2003 Ventana de rebatr RTP M-3 medante RADCON con Know-How TECHNOFORM f = 4,19 W/m 2 K f = 3,40 W/m 2 K En este nforme se detemna el coefcente de transmsón térmca (f) medante dos métodos de cálculo dferentes: A) Alcando la norma EN ISO :2003, y usando el software BISCO de la emresa Physbel. B) Alcando un método róo, know-how de Technoform, dónde se usa el software RADCON - tambén roedad de Physbel - y el valor fnal equvale aroxmadamente al resultado en el test de cálculo de nuestra HOT-BOX (La dferenca es de un 5%) según norma ISO/FDIS 12567:

2 Contendo Dbujo sstema A) medante BISCO según norma EN ISO :2003 Inut data BISCO Outut data BISCO Cálculo del coefcente de transmsón térmca (f) Isotermas Flujo de calor B) medante RADCON con Know-How TECHNOFORM Inut data RADCON Outut data RADCON Cálculo del coefcente de transmsón térmca (f) Dbujo sstema 2

3 A) medante BISCO según norma EN ISO :2003 Inut data BISCO Col. Name Tye CEN-rule Couled lambda es t h [W/mK] [-] [ C] [W/m²K] 8 alumnum MATERIAL nsulaton MATERIAL olyamd renf. MATERIAL EPDM MATERIAL tem. sensor 1 MATERIAL tem. sensor 2 MATERIAL tem. sensor 3 MATERIAL tem. sensor 4 MATERIAL exteror BC_SIMPL HE nteror (norma BC_SIMPL HI_NORML nteror (reduc BC_SIMPL HI_REDC cavty (CEN) EQIMAT CEN_VF_I NO cavty (CEN) EQIMAT CEN_VF_I NO cavty (CEN) EQIMAT CEN_VF_I NO cavty (CEN) EQIMAT CEN_VF_I NO cavty (CEN) EQIMAT CEN_VF_I NO cavty (CEN) EQIMAT CEN_VF_E NO cavty (CEN) EQIMAT CEN_VF_E NO cavty <3x3 mm2 MATERIAL cavty <2x2 mm2 MATERIAL cavty <1x1 mm2 MATERIAL Col. q ta hc qc tr C1 C2 C3 [W/m²] [ C] [W/m²K] [W/m] [ C] [-] [-] [-] Calculaton arameters Contour aroxmaton margn (trangulaton) = 0 xels 3

4 Iteraton cycles = 5 Recalculaton of CEN values (before each teraton cycle) Maxmum number of teratons (er teraton cycle) = Maxmum temerature dfference = C Max. heat flow dvergence for total object = % Max. heat flow dvergence for any node = 1 % Outut data BISCO Col. Name Tye tmn tmax ta flow n flow out [ C] [ C] [ C] [W/m] [W/m] 8 alumnum MATERIAL nsulaton MATERIAL olyamd renf. MATERIAL EPDM MATERIAL tem. sensor 1 MATERIAL tem. sensor 2 MATERIAL tem. sensor 3 MATERIAL tem. sensor 4 MATERIAL exteror BC_SIMPL nteror (norma BC_SIMPL nteror (reduc BC_SIMPL cavty (CEN) EQIMAT cavty (CEN) EQIMAT cavty (CEN) EQIMAT cavty (CEN) EQIMAT cavty (CEN) EQIMAT cavty (CEN) EQIMAT cavty (CEN) EQIMAT cavty <3x3 mm2 MATERIAL cavty <2x2 mm2 MATERIAL cavty <1x1 mm2 MATERIAL

5 Cálculo del coefcente de transmsón térmca (f) THERMAL TRANSMITTANCE ACCORDING TO ren Theory The thermal transmttance of a frame accordng to PrEN : f = L 2D l f * l and L 2 D = q l, tot θ wth: f : thermal transmttance of the wndow frame [W/m 2 K] Calculaton : thermal transmttance of the flankng anel [W/m 2 K] l : rojected wdth of the flankng anel [m] l f : rojected wdth of the wndow frame [m] L 2D : two-dmensonal coulng coeffcent [W/mK] q l,tot : total heat flow through the wndow frame and the flankng anel [W/m] θ : temerature dfference between nsde (θ) and outsde (θe) [K] Item: nut data: q l,tot = 10,39 W/m R se = 0,04 m 2 K/W θ e = 0,0 o C R s = 0,13 m 2 K/W θ = 20,0 o C d = 0,0180 m λ = 0,035 W/m*K = l = 1,461 W/m 2 K 0,190 m calculaton results: L 2D = 0,52 W/mK l f = 0,0576 m f = 4,20 W/m 2 K nut data usng the Physbel Software BISCO q l,tot : alhanumerc outut BISKO heat losses er boundary condton θ : nut data, surface boundary condtons: nsde temerature mnus outsde temerature : calculaton, usng the followng formula: 1 = + h e d + λ 1 h 1 wth: h e / h ext./nt. surface heat transfer coeff. [W/m 2 K] d thckness of layer [m] λ thermal conductvty of layer [W/mK] l / l f : nut data: dmensons of the tem PHYSIBEL Herweg 21 B-9990 Maldegem Belgum tel fax

6 Isotermas 6

7 Flujo de calor 7

8 B) medante RADCON con Know-How TECHNOFORM Inut data RADCON Col. Name Tye CEN-rule Couled lambda es t h [W/mK] [-] [ C] [W/m²K] 8 alumnum MATERIAL nsulaton MATERIAL olyamd renf. MATERIAL EPDM MATERIAL tem. sensor 1 MATERIAL tem. sensor 2 MATERIAL tem. sensor 3 MATERIAL nsulaton far MATERIAL tem. sensor 4 MATERIAL exteror BC_SKY NIHIL 174 nteror 1 BC_SKY NIHIL 182 nteror 2 BC_SKY NIHIL 190 nteror 3 BC_SKY NIHIL 214 cavty BC_FREE CEN_VF_I NO 215 cavty EQIMAT CEN_VF_I NO cavty EQIMAT CEN_VF_I NO cavty BC_FREE CEN_VF_I NO 218 cavty BC_FREE CEN_VF_I NO 240 cavty EQIMAT CEN_VF_E NO cavty EQIMAT CEN_VF_E NO cavty <3x3 mm2 MATERIAL cavty <2x2 mm2 MATERIAL cavty <1x1 mm2 MATERIAL Col. q ta hc qc tr C1 C2 C3 [W/m²] [ C] [W/m²K] [W/m] [ C] [-] [-] [-]

9 Calculaton arameters Contour aroxmaton margn (trangulaton) = 0 xels Iteraton cycles = 5 Nonlnear radaton Recalculaton of CEN values (before each teraton cycle) Smallest acceted vewfactor = Number of vsblty rays between radatve surfaces = 100 Black radaton heat transfer coeff. (lnear radaton) = 5.25 W/m²K Maxmum number of teratons (er teraton cycle) = Maxmum temerature dfference = C Max. heat flow dvergence for total object = % Max. heat flow dvergence for any node = 1 % Outut data RADCON Col. Name Tye tmn tmax ta flow n flow out [ C] [ C] [ C] [W/m] [W/m] 8 alumnum MATERIAL nsulaton MATERIAL olyamd renf. MATERIAL EPDM MATERIAL tem. sensor 1 MATERIAL tem. sensor 2 MATERIAL tem. sensor 3 MATERIAL nsulaton far MATERIAL tem. sensor 4 MATERIAL exteror BC_SKY nteror 1 BC_SKY nteror 2 BC_SKY nteror 3 BC_SKY cavty BC_FREE cavty EQIMAT cavty EQIMAT cavty BC_FREE cavty BC_FREE cavty EQIMAT cavty EQIMAT cavty <3x3 mm2 MATERIAL cavty <2x2 mm2 MATERIAL cavty <1x1 mm2 MATERIAL

10 Cálculo del coefcente de transmsón térmca (f) THERMAL TRANSMITTANCE ACCORDING TO ren Theory The thermal transmttance of a frame accordng to PrEN : f = L 2D l f * l and L 2 D = q l, tot θ wth: f : thermal transmttance of the wndow frame [W/m 2 K] Calculaton : thermal transmttance of the flankng anel [W/m 2 K] l : rojected wdth of the flankng anel [m] l f : rojected wdth of the wndow frame [m] L 2D : two-dmensonal coulng coeffcent [W/mK] q l,tot : total heat flow through the wndow frame and the flankng anel [W/m] θ : temerature dfference between nsde (θ) and outsde (θe) [K] Item: nut data: q l,tot = 9,310 W/m R se = 0,06 m 2 K/W θ e = 0,0 o C R s = 0,13 m 2 K/W θ = 20,0 o C d = 0,0180 m λ = 0,035 W/m*K = l = 1,420 W/m 2 K 0,190 m calculaton results: L 2D = 0,47 W/mK l f = 0,0576 m f = 3,40 W/m 2 K nut data usng the Physbel Software BISCO q l,tot : alhanumerc outut BISKO heat losses er boundary condton θ : nut data, surface boundary condtons: nsde temerature mnus outsde temerature : calculaton, usng the followng formula: 1 = + h e d + λ 1 h 1 wth: h e / h ext./nt. surface heat transfer coeff. [W/m 2 K] d thckness of layer [m] λ thermal conductvty of layer [W/mK] l / l f : nut data: dmensons of the tem PHYSIBEL Herweg 21 B-9990 Maldegem Belgum tel fax