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1 Print of 1 2/3/ :12 AM On Monday, 2 Febrary :26 PM, Editor AJS <editor_ajs@rediffmail.com> wrote: Dear Prof. Uixit, I am glad to inform yo that yor paper entitled, Characterizations of the Pareto distribtion in the presence of otliers has been accepted for pblication in The Aligarh Jornal of Statistics. To expedite its pblication and also make it error free, the Editorial board of the AJS has decided that the accepted paper be sbmitted on a CD in the format given below*. It is, therefore, reqested to please send the paper as early as possible on a CD sing MS-Word alongwith a hard copy of it. Yor co-operation is solicited. With regards, Sincerely yors, (Prof. Qazi M. Ali) Editor *Paper size : A4 Line spacing : Single Font size : 11 Font style : Times New Roman Eqations : MS Eqation 3.0 Typing area : First page : 5.0 x 7.0 Other page: 5.0 x 8.0 Odd nmbered pages : Rnning title of the paper Even nmbered pages : Athors name Editor Aligarh Jornal of Statistics Dept. of Statistics & O.R. Aligarh Mslim University Aligarh , U.P. INDIA. Phone: editor_ajs@rediffmail.com Web site:
2 Characterizations of the Pareto distribtion in the presence of otliers U. J. Dixit 1 Department of Statistics, University of Mmbai, Mmbai-India M. Jabbari Nooghabi 2 Department of Statistics, Ferdowsi University of Mashhad, Mashhad-Iran Abstract Here we have given some characterizations for the Pareto distribtion in the presence of otliers. It is proved that a necessary and sfficient condition for f(x) to be a Pareto density fnction in the presence of otliers is that the statistics X (r) and X (s) X (1 r < s n) are independent. Frther, we have derived some another (r) characterizations of the Pareto distribtion in the presence of otliers. Key Words: Pareto distribtion, Power distribtion, Characterization, Order statistics, Otliers. 1 Introdction Ahsanllah and Kabir [2] proved that necessary and sfficient condition for f(x) to be a Pareto distribtion is that the statistics X (r) and X (s) X (r) (1 r < s n) are independent. Dallas [3] proved that for a cmlative distribtion fnction (CDF) G(y) (y β), if E(Y r Y > c) = E ( ) r Y c β holds then Y has a Pareto distribtion. In this paper, we assme that the random variables (X 1, X 2,..., X n ) are sch that k of them are distribted with probability density fnction (pdf) f 2 (x; α, β, ) = α()α, 0 < x, α > 0, β > 1, > 0, (1) xα+1 and remaining (n k) random variables are distribted as f 1 (x; α, ) = αα, 0 < x, α > 0. (2) xα+1 One shold note that two sets of the observation (i.e. k and n k) are independent. Bt X 1, X 2,..., X n are not independent becase of the model of otliers (for more details see [5, 7, 8]). Also, we may note that or assmptions are based of Dixit s model for 1 lhasdixit@yahoo.co.in 2 jabbarinm@yahoo.com, jabbarinm@m.ac.ir 1
3 the otliers problem and it is totaly different than the mixtre models which considers X 1, X 2,..., X n are independent. Here, we have extended the approaches of Ahsanllah and Kabir [2] and Dallas [3] for the homogenos case of the Pareto distribtion and derived some characterizations of the Pareto distribtion in the presence of otliers. 2 Prereqisite Reslts Assme that X (1) < X (2) <... < X (n) be the order statistics of a random sample of size n sch that k ot of n are coming from pdf f 2 (or CDF F 2 ) and the remaining (n k) follow the pdf f 1 (or CDF F 1 ). The CDF and pdf of r th (1 r n) order statistic are H X(r) (x) = n i=r m 6 j=m 5 C(k, j)[f 2 (x)] j [1 F 2 (x)] k j C(n k, i j)[f 1 (x)] i j [1 F 1 (x)] n k i+j, (3) where m 5 = max(0, i n + k) and m 6 = min(k, i) and m 2 h X(r) (x) = kf 2 (x) {C(k 1, j)[f 2 (x)] j [1 F 2 (x)] k j 1 C(n k, r 1 j) j=m 1 [F 1 (x)] r j 1 [1 F 1 (x)] n k r+j+1 } + (n k)f 1 (x) {C(k, j)[f 2 (x)] j j=m 3 [1 F 2 (x)] k j C(n k 1, r 1 j)[f 1 (x)] r j 1 [1 F 1 (x)] n k r+j }, (4) where m 1 = max(0, k + r n 1), m 2 = min(k 1, r 1), m 3 = max(0, k + r n), m 4 = min(k, r 1), respectively (for more details see [4, 5, 6, 8]). Frther, the joint CDF and pdf of (X (r), X (s) ) (1 r < s n) are H X(r),X (s) (x, y) = n j w 10 j=s i=r m=w 9 t 10 m 4 l=t 9 {C(k, m)c(k m, l)[f 2 (x)] m [F 2 (y) F 2 (x)] l [1 F 2 (y)] k m l C(n k, i m)c(n k i + m, j i l)[f 1 (x)] i m [F 1 (y) F 1 (x)] j i l [1 F 1 (y)] n k j+m+l }, (5) where w 9 = max(0, i n + k), w 10 = min(k, i), t 9 = max(0, j n + k m) and t 10 = min(k m, j i) and h X(r),X (s) (x, y) = k(k 1)f 2 (x)f 2 (y) w 2 j=w 1 t 2 i=t 1 {C(k 2, j)c(n k, r 1 j)[f 2 (x)] j [F 1 (x)] r 1 j C(k 2 j, i)c(n k r + j + 1, n s i)[1 F 2 (y)] i [1 F 1 (y)] n s i [F 2 (y) F 2 (x)] k j i 2 [F 1 (y) F 1 (x)] s r k+i+j+1 } + (n k)(n k 1)f 1 (x)f 1 (y) 2 w 4 j=w 3 t 4 i=t 3 {C(n k 2, j)c(k, r 1 j)
4 [F 1 (x)] j [F 2 (x)] r 1 j C(n k 2 j, i)c(k r + j + 1, n s i)[1 F 1 (y)] i [1 F 2 (y)] n s i [F 1 (y) F 1 (x)] n k 2 i j [F 2 (y) F 2 (x)] s r+k n+i+j+1 } + k(n k)f 1 (x)f 2 (y) w 6 j=w 5 t 6 i=t 5 {C(n k 1, j)c(k 1, r 1 j) [F 1 (x)] j [F 2 (x)] r 1 j C(n k j 1, i)c(k r + j, n s i)[1 F 1 (y)] i [1 F 2 (y)] n s i [F 1 (y) F 1 (x)] n k i j 1 [F 2 (y) F 2 (x)] s r n+k+i+j } + k(n k)f 2 (x)f 1 (y) w 8 j=w 7 t 8 i=t 7 {C(k 1, j)c(n k 1, r 1 j) [F 2 (x)] j [F 1 (x)] r 1 j C(k j 1, i)c(n k r + j, n s i)[1 F 2 (y)] i [1 F 1 (y)] n s i [F 2 (y) F 2 (x)] k i j 1 [F 1 (y) F 1 (x)] s r k+i+j }, (6) where w 1 = max(0, r n + k 1), w 2 = min(k 2, r 1), t 1 = max(0, k s + r j 1) and t 2 = min(k j 2, n s), w 3 = max(0, r k 1), w 4 = min(n k 2, r 1), t 3 = max(0, n s k + r j 1) and t 4 = min(n k j 2, n s), w 5 = max(0, r k), w 6 = min(n k 1, r 1), t 5 = max(0, n s k +r j 1), t 6 = min(n k j 1, n s), w 7 = max(0, r n + k), w 8 = min(k 1, r 1), t 7 = max(0, k s + r j 1), t 8 = min(k j 1, n s), respectively. One shold note that if k = 1 the joint pdf of (X (r), X (s) ) is given in Sinha [10]. Also, if we pt f 1 = f 2 and F 1 = F 2 then all pdfs and CDFs are redced to homogeneos cases. The following eqations are named as Pexider s eqations. and f(xy) = g(x) + h(y), (7) f(xy) = g(x)h(y). (8) For solving these eqations, the following Theorem has taken from Aczel [1] (Theorem 4. in p. 144) and Kczma [9] (Theorem in p. 358). Theorem 2.1. The general soltions, with f continos in a point of (7) and (8), respectively, both spposed for positive x and y, are and f(t) = c ln(αβt), g(t) = c ln(αt), h(t) = c ln(βt), (α > 0, β > 0, t > 0), (9) f(t) = abt c, g(t) = at c, h(t) = bt c, (t > 0), (10) respectively, spplemented with the following trivial soltions in case of (8). f(t) = 0, g(t) = 0, h(t) arbitrary, and f(t) = 0, g(t) arbitrary, h(t) = 0. (11) 3
5 3 Characterization of the Pareto distribtion in the presence of otliers Theorem 3.1. Let X be a random variable having an absoltely continos CDF F (x). A necessary and sfficient condition that X follows the Pareto distribtion in the presence of otliers as given by (1) and (2) is that for some r and s (1 r < s n) the statistics X (r) and X (s) X (r) are independent. Proof. Necessity: From (6) we can get the joint pdf of X (r) and X (s). Sbstitting U = X (r) and V = X (s) X (r) in (6), we can obtain the joint pdf of U and V as h U,V (, v) = h X(r),X (s) (, v). Then after some simplification (replace h U,V (, v) with h(, v)) h(, v) = α 2 α(n r+1) β αk v α(s n 1) 1 [1 v α ] s r 1 [ ( ) w2 α(r n 1) 1 k(k 1) t 2 α ] j [ ( ) α ] r 1 j A 1 β αj 1 1 j=w 1 i=t 1 [ ( ) w 4 + (n k)(n k 1)β α(r 1) t 4 α ] j [ ( ) α ] r 1 j A 2 β αj 1 1 j=w 3 i=t 3 [ ( ) w 6 + k(n k)β α(r 1) t 6 α ] j [ ( ) α ] r 1 j A 3 β αj 1 1 j=w 5 i=t 5 [ ( ) w 8 t 8 α ] j [ ( ) α ] r 1 j + k(n k) A 4 β αj 1 1 i=t 7, (12) j=w 7 where A 1 = C(k 2, j)c(n k, r 1 j)c(k 2 j, i)c(n k r + j + 1, n s i), A 2 = C(n k 2, j)c(k, r 1 j)c(n k 2 j, i)c(k r + j + 1, n s i), A 3 = C(n k 1, j)c(k 1, r 1 j)c(n k j 1, i)c(k r + j, n s i), (13) A 4 = C(k 1, j)c(n k 1, r 1 j)c(k j 1, i)c(n k r + j, n s i). Therefore, it establishes the independence of U and V. Sfficiency: Here we assme that U and V are independent. The joint pdf of U and V is h(, v) = k(k 1)f 2 ()f 2 (v) w 2 j=w 1 t 2 i=t 1 {A 1 [F 2 ()] j [F 1 ()] r 1 j [1 F 2 (v)] i 4
6 [1 F 1 (v)] n s i [F 2 (v) F 2 ()] k j i 2 [F 1 (v) F 1 ()] s r k+i+j+1 } + (n k)(n k 1)f 1 ()f 1 (v) w 4 j=w 3 t 4 i=t 3 {A 2 [F 1 ()] j [F 2 ()] r 1 j [1 F 1 (v)] i [1 F 2 (v)] n s i [F 1 (v) F 1 ()] n k 2 i j [F 2 (v) F 2 ()] s r+k n+i+j+1 } + k(n k)f 1 ()f 2 (v) w 6 j=w 5 t 6 i=t 5 {A 3 [F 1 ()] j [F 2 ()] r 1 j [1 F 1 (v)] i [1 F 2 (v)] n s i [F 1 (v) F 1 ()] n k i j 1 [F 2 (v) F 2 ()] s r n+k+i+j } + k(n k)f 2 ()f 1 (v) w 8 j=w 7 t 8 i=t 7 {A 4 [F 2 ()] j [F 1 ()] r 1 j [1 F 2 (v)] i [1 F 1 (v)] n s i [F 2 (v) F 2 ()] k i j 1 [F 1 (v) F 1 ()] s r k+i+j }, (14) where A 1, A 2, A 3 and A 4 are given in (13). By sing some elementary algebra we have h(, v) = k(k 1)f 2 ()f 2 (v)[f 1 ()] r 1 [1 F 1 (v)] n s [F 1 (v) F 1 ()] s r k+1 w 2 [F 2 (v) F 2 ()] k 2 t 2 j j [ F2 () 1 F1 () 1 F 2 (v) {A 1 i=t 1 F 1 () 1 F 2 () F 2 (v) F 2 () j=w 1 i j [ F1 (v) F 1 () F1 (v) F 1 () 1 F 1 (v) 1 F 1 () 1 F 2 () F 2 (v) F 2 () + (n k)(n k 1)f 1 ()f 1 (v)[f 2 ()] r 1 [1 F 2 (v)] n s [F 1 (v) F 1 ()] n k 2 w 4 [F 2 (v) F 2 ()] s r+k n+1 t 4 j j [ F1 () 1 F2 () 1 F 1 (v) {A 2 i=t 3 F 2 () 1 F 1 () F 1 (v) F 1 () i [ F2 (v) F 2 () 1 F 2 (v) j=w 3 1 F 1 () F 1 (v) F 1 () ] j } ] j j F2 (v) F 2 () } 1 F 2 () + k(n k)f 1 ()f 2 (v)[f 2 ()] r 1 [1 F 2 (v)] n s [F 1 (v) F 1 ()] n k 1 w 6 [F 2 (v) F 2 ()] s r+k n t 6 j j [ F1 () 1 F2 () 1 F 1 (v) {A 3 j=w 5 i=t 5 F 2 () 1 F 1 () F 1 (v) F 1 () i j [ ] j F2 (v) F 2 () F2 (v) F 2 () 1 F 1 () } 1 F 2 (v) 1 F 2 () F 1 (v) F 1 () + k(n k)f 2 ()f 1 (v)[f 1 ()] r 1 [1 F 1 (v)] n s [F 2 (v) F 2 ()] k 1 w 8 [F 1 (v) F 1 ()] s r k t 8 j j [ ] i F2 () 1 F1 () 1 F 2 (v) {A 4 j=w 7 i=t 7 F 1 () 1 F 2 () F 2 (v) F 2 () i j [ ] j F1 (v) F 1 () F1 (v) F 1 () 1 F 2 () }. (15) 1 F 1 (v) 1 F 1 () F 2 (v) F 2 () Also from (4) and after some simplification, the marginal pdf of U = X (r) is as h 1 (). h 1 () = [1 F 2 ()] k 1 [F 1 ()] r 1 [1 F 1 ()] n k r+1 D, (16) 5 ] i ] i ] i
7 where and D = kf 2 () m 2 j=m 1 B 1 + (n k)f 1 () j [ F2 () 1 F1 () F 1 () 1 F 2 () 1 F2 () m4 1 F 1 () j=m 3 B 2 ] j [ F2 () F 1 () B 1 = C(k 1, j)c(n k, r 1 j), B 2 = C(k, j)c(n k 1, r 1 j). ] j j 1 F1 (), 1 F 2 () (17) Therefore from independency of U and V, we can write h 2 (v) = h(, v) h 1 (), (18) where h 2 (v) is pdf of V. Letting p = p(, v) = 1 F 1(v) 1 F 1 () and q = q(, v) = 1 F 2(v) 1 F 2, we obtain () w 2 h 2 (v) = {k(k 1)p n s [1 p] s k r+1 [1 q] k 2 t 2 A 1 j=w 1 i=t 1 A 4 j=w 7 i=t 7 [ F2 () F 1 () ] j j 1 F1 () 1 F 2 () p i [1 p] i+j q i [1 q] i j f 2 () q v r 1 r 2 F2 () 1 F1 () + (n k)(n k 1) [1 p] n k 2 q n s [1 q] k+s r n+1 F 1 () 1 F 2 () w 4 t 4 j j F1 () 1 F2 () A 2 q i [1 q] i+j p i [1 p] i j f 1 () p j=w 3 i=t 3 F 2 () 1 F 1 () v r 1 r 2 F2 () 1 F1 () + k(n k) q n s [1 q] k+s r n [1 p] n k 1 F 1 () 1 F 2 () w 6 t 6 j j F1 () 1 F2 () A 3 p i [1 p] i j q i [1 q] i+j f 1 () q j=w 5 i=t 5 F 2 () 1 F 1 () v w 8 + k(n k)p n s [1 p] s k r [1 q] k 1 t 8 j j F2 () 1 F1 () F 1 () 1 F 2 () p i [1 p] i+j q i [1 q] i j f 2 () p v }D 1. (19) From the assmption, we know that U and V are independent. So h 2 (v) is independent of and by sing the lemma in Ahsanllah and Kabir [2] p = p(, v) = g 1 (v) and 6
8 q = q(, v) = g 2 (v) (we say fnctions of v only) and the remaining parts shold be constant. Therefore { 1 F1 (v) = [1 F 1 ()]g 1 (v),, 1 < v, > 0, (20) 1 F 2 (v) = [1 F 2 ()]g 2 (v),, 1 < v, > 0, β > 1. It is clear that these are version of Pexider s eqation. So from Theorem 2.1 we can solve them. Since F 1 (x) and F 2 (x) are CDFs continos for all x [, ) and x [, ), respectively. We may conclde that { 1 F1 (x) = c 1 x α, x, > 0, 1 F 2 (x) = c 2 x α, x, > 0, β > 1, (21) where c 1, c 2 and α are constant. After replacing these soltions in (19) and sing some simplification we get where h 2 (v) = αv α(n s+1) 1 [1 v α ] s r 1 H[c 2 D] 1, (22) w 2 H = k(k 1)c 2 t 2 A 1 j=w 1 i=t 1 w 4 + (n k)(n k 1)c 1 w 6 + k(n k)c 1 + k(n k)c 2 t 8 A 3 j=w 5 i=t 5 i=t 7 A 4 t 6 [ 1 c2 α 1 c 1 α t 4 A 2 j=w 3 i=t 3 [ 1 c2 α 1 c 1 α [ 1 c2 α 1 c 1 α ] j (c1 ) j c 2 [ 1 c2 α 1 c 1 α ] r 1 j (c1 ) r 2 j ] j (c1 ) j. c 2 c 2 ] r 1 j (c1 ) r 2 j We know that C(n, j) = 0 if j > n, then by sing some elementary algebra H[c 2 D] 1 = (n r)c(n r 1, n s) and the right side of (22) is only depend on v and it is pdf of V. Finally, from the property of CDF, α > 0, c 1 = α and c 2 = () α. Ths sfficiency is established and the proof is complete. Theorem 3.2. Let X be a random variable with CDF F (x) = bf 2 (x) + bf 1 (x) sch that F 1 (x) (x ) and F 2 (x) (x ) are CDFs, where b = k n, b = 1 b, > 0 and β > 1. If E(X α X > c) = be 2 ( Xc ) α + be ( ) Xc α 1, (23) holds for some α > 0 then F (x) is the Pareto distribtion in the presence of otliers. We assme that E(X α ) <. Proof. Proof is similar as given in Dallas [3]. In the process to prove the theorem, 7 c 2
9 we shold note that the soltion of the differential eqation cp (c) = γp (c) (P (c) = 1 F (c)) is P (c) = Ac α, where A is a constant, γ = αδ/(δ 1) > 0 and δ = b ( ) α X df 2 (x) + b ( X ) α df 1 (x). (24) Comparing the soltion with the assmption imply that A = b() α + b α and the proof is complete. 4 An actal example Here, we have given an example of motor insrance company from Dixit and Jabbari Nooghabi [7]. From the example, we know that the data follow the Preto distribtion in the presence of otliers. So by sing Theorem 3.1, we can check the sfficiency. Assming r = 3 and s = 12, we have x (r) =63000, and x (s) x (r) = So, sing the copla method and independent test by package copla in R, the reslt is as follows: Global Cramer-von Mises statistic: with p-vale Combined p-vales from the Mobis decomposition: from Fisher s rle, from Tippett s rle. Therefore, X (r) and X (s) X (r) are independent, becase of the p-vale is grater than 0.05, as significant level of the test. So, we can conclde that the data follow the Pareto distribtion in the presence of otliers. 5 Acknowledgements The athors are thankfl to the two referees for their valable comments and sggestions. This research was spported by a grant from Ferdowsi University of Mashhad, No. MS92299MEH. References [1] Aczel, J. (1966). Lectres on Fnctional Eqations and their Applications. Academic Press, New York. [2] Ahsanllah, M. and Kabir Ltfl A. B. M. (1973). A Characterization of the Pareto Distribtion. The Canadian Jornal of Statistics, 1(1), [3] Dallas, A. C. (1976). Characterizing the Pareto and power distribtions. Ann. Inst. Statist. Math., 28,
10 [4] Dixit, U. J. (1987). Characterization of the gamma distribtion in the presence of k otliers. Blletin Bombay Mathematical Colloqim, 4, [5] Dixit, U. J. (1989). Estimation of parameters of the Gamma Distribtion in the presence of Otliers. Commn. Statist. Theory and Meth., 18, [6] Dixit, U. J. (1994). Bayesian approach to prediction in the presence of otliers for Weibll distribtion, Metrika, 41, [7] Dixit, U. J. and Jabbari Nooghabi, M. (2011). Efficient estimation in the Pareto distribtion with the presence of otliers, Statistical Methodology, 8(4), [8] Dixit, U. J. and Jabbari Nooghabi, M. (2011). Efficient Estimation of the parameters of the Pareto Distribtion in the Presence of Otliers, Commnications of the Korean Statistical Society, 18(6), [9] Kczma M. (2008). An Introdction to the Theory of Fnctional Eqations and Ineqalities. Second edition, edited by Attila Gilányi, Birkhäser Verlag AG, Berlin. [10] Sinha, S. K. (1973). Distribtions of order statistics and estimation of mean life when an otlier may be present. The Canadian Jornal of Statistics, 1(1),
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