CPT 17. XI-LJ (Date: ) PHYSICS CHEMISTRY MATHEMATICS 1. (B) 31. (A) 61. (A) 2. (B) 32. (B) 62. (C) 3. (D) 33. (D) 63. (B) 4. (B) 34.
|
|
- Hugh Adams
- 5 years ago
- Views:
Transcription
1 CPT-7 / XI-LJ / NARAYANA I I T A C A D E M Y CPT 7 XI-LJ (Date:.0.7) CODE XI-LJ PHYSICS CHEMISTRY MATHEMATICS. (B). (A) 6. (A). (B). (B) 6. (C). (D). (D) 6. (B). (B). (C) 6. (C) 5. (D) 5. (C) 65. (A) 6. (B) 6. (B) 66. (A) 7. (D) 7. (A) 67. (C) 8. (C) 8. (B) 68. (D) 9. (B) 9. (C) 69. (D) 0. (B) 0. (B) 70. (D). (B). (B) 7. (B). (B). (D) 7. (B). (C). (B) 7. (C). (C). (C) 7. (B) 5. (B) 5. (C) 75. (A) 6. (C) 6. (A) 76. (D) 7. (C) 7. (D) 77. (C) 8. (A) 8. (C) 78. (A) 9. (D) 9. (D) 79. (A) 0. (B) 50. (C) 80. (C). (B) 5. (B) 8. (C). (B) 5. (B) 8. (D). (C) 5. (D) 8. (A). (C) 5. (D) 8. (A) 5. (D) 55. (A) 85. (B) 6. (A) 56. (A) 86. (A) 7. (C) 57. (A) 87. (B) 8. (D) 58. (A) 88. (B) 9. (B) 59. (B) 89. (C) 0. (D) 60. (D) 90. (A)
2 CPT-7 / XI-LJ /. (B) GM W U 0 R Hits & Solutio PHYSICS J. B α ωf ωi 60 rad / s t 5. At equator the value of g is iiu so it is profitable to purchase sugar at this positio.. Acceleratio due to gravity at height h is give by g 00 R g R h R R h 0 h 9 R. R g g R h 5. If P is the poit where et gravitatioal force is ero the F PA FPB G G ( d ) By solvig d For the give proble d D, earth, oo ad 8 So D D 8 D D d g d d 6. g g g d R R R R P F PA A B d 8 d F PB 7. (D) Gravitatioal field iside the hollow sphere is equal to ero 8. (C) At the poit P, we have I I 0 (because the gravitatioal field iside a shell is ero). Hece, I I 9. As dv I, if I 0 the V costat. d 0. Potetial icreases by 0 J / kg everywhere so it will be 0 5 5J / kg at P
3 CPT-7 / XI-LJ / G G G. Net potetial at origi V... r r r G G G 8 O 8. Work doe gh h / R, If h R the work doe gr R / R gr.. ω v v ; R; ω v R R. g ' g d R 5. Distace of ull poit d 6. By the law of coservatio of agular oetu I Iω ( I )ω Iω Agular velocity of syste ω I Iω I Rotatioal kietic eergy ( I I ) ω ( I I ) ω I I ω I Iω I ( Iω Iω ) ( I I ) 7. Iitial agular oetu of the syste Agular oetu of bullet before collisio L Mv...(i) let the rod rotates with agular velocity ω. Fial agular oetu of the syste By equatio (i) ad (ii) 8. L r p ˆi ˆj kˆ ML L ω M ω...(ii) L ML ML Mv ω or ω v / L 0ˆi ˆj ˆ k ˆj kˆ ad the X- ais is give by i 0 ˆj 0kˆ Dot product of these two vectors is ero i.e. agular oetu is perpedicular to X- ais. 9. Rotatioal kietic eergy I ω MR ω 0 (0.5) ( 0 ) 50 J. v M
4 CPT-7 / XI-LJ / v I R 0. Use d ( v A t ) L E L L. As, E I E L L E 9E E 800% of E [As L L 00%. L L ] gh gh. Velocity at the botto (v) gh. K R g siθ. a k R. (C) g si 0 o g k [As R Gravitatioal potetial at the surface of the earth ad GM R o θ 0 ] Gravitatioal potetial at 0 GM GM Potetial differece 0 R V R Workdoe i shiftig a body of kg fro the surface of the earth to ifiity. GM GM W V Workdoe per kg gr R R 5. (C) Gravitatioal field iside a shell is ero, but for poits outside it, the shell behaves as if whole of its ass is cocetrated at its cetre. 6. Iitial agular oetu of rig I ω MRω If four object each of ass, ad kept getly to the opposite eds of two perpedicular diaeters of the rig the fial agular oetu ( MR R ) ω' By the coservatio of agular oetu Iitial agular oetu Fial agular oetu M MR ω ( MR R ) ω' ω' ω. M G 8. GPE ( U ), use, U et U U U r k R 0 g siθ k g si 0 5 a g R 5 CHEMISTRY
5 CPT-7 / XI-LJ /. A Half eutraliatio acid salt [ ] [ ] P P P H H H Pk log log k k ati log P a H a Pk a P 0 0 a 5. [ salt] [ acid ] H. B Equilibriu shift i backward directio. D Isoelectric poit is the coditio, whe witterios or sol particles do ot ove uder the ifluece of electric field, i.e., they lose their charge.. C Maiu buffer capacity whe [salt] [acid] P H Pk a 5. C 6. B A buffer of H CO ad HCO is fored. 7. A ph logk a log [Salt] [Acid] log0 log [Sice K a K b 0 Give K b 0 0 K a 0 ] 8. B Miig of NH OH ad (NH ) SO gives a basic buffer. [NH ] poh pk b log ; pk a [NH OH] NH 9.6 pk.7 bnhoh log a 5 ; where a is illiole of [NH ] obtaied o iig. a 50 illiole of (NH ) SO 5 or, ole of (NH ) SO
6 CPT-7 / XI-LJ / 9. C (00 V ) ph pk a log ; let V be volue of beoic acid ad thus (00 V ) is V volue of beoate. 00 V.5. log V 00 V V V 00 L 0. B HI H I K a [H ][I ] [HI] K a K w K b 0 [I ] [HI] or [H ] 0 or ph 0 [H ]. B NH HCl i : will give NH NH Cl i : ratio.. D Buffer solutio. B Fid solubility for each separately by S K SP for MS ad ZS. 08S 5 K SP for Bi S ad S K SP for Ag S.. C Let S is the solubility of BaF i a solutio of BaNO, the K SP [Ba ][F ] ; the [F ] S; the [F ] S 5. C Presece of coo io decreases the solubility of salt. 6. A Presece of coo io decreases the solubility of salt. 7. D K SP of PbCl S (0.0) 0 6 I NaCl solutio for PbCl ; K SP [Pb ][Cl ] or, 0 6 [Pb ][0.] [Pb ] 0 M 6
7 CPT-7 / XI-LJ / 8. C 9. D 50. C S Ag S AgCl S Ag S AgBr S AgCrO K SP Also, S Ag K SP K SP M M M S M AgCrO This will give aiu value. Ksp Ba SO SO SO 7 MgCl NaOH Mg(OH) NaCl before reactio Thus, 0 illi-ole of Mg(OH) are fored. The product of [Mg ][OH ] 0 0 is therefore which is ore tha K SP of Mg(OH). Now solubility (S) of Mg(OH) ca be derived by K SP S. 0 S [OH ] S.8 0 K SP 5. B Due to coo io effect 5. B [Mg ][OH ] 5. D 5. D 0 ; 0 [OH ] or poh 5 ad thus ph 9 [OH ] Cα C K b.c K b C M 7
8 CPT-7 / XI-LJ / 55. A 56. A 57. A 58. A 59. B 60. D MX M X ; K SP (K SP ) / M X M X ; K SP MX M X ; K SP 7 K SP K SP 7 / / MATHEMATICS 6. Give a,b,c are i G.P, the Let these are a, ar, ar Now, give ab, a b ad bc 6, b c ab 6...( ) a b bc 8...( ) b c a ar ar Fro () 6 6. () a ar r ar ar ar Fro () 8 8 (5) ar ar r Fro () ad () r ad a 8 The a b c 0 6. Let A λ, h λ G AH λ a, b, are the roots of ( ) t λt λ 0 t a b t ab 0 or ( ) { ( )} λ ± λ λ t λ ± a: b ( ) : ( ) or ( ) : ( ) as is odd { ( )..... } 6. Multiply ad divide by ( a) i the give series ( ) ( ) 8
9 CPT-7 / XI-LJ / a a a... a α 00 a a a... a α 99 α a r β a H PQ P Q 67. If, y, are i G.P, the log, log y, log are i A.P. 68. Give a a 0 a 9d 9d d /9 the a a d / 7/ 9 d ', d ' (give h 0 ad h ) h0 h 5 7 Now, 6 d ' h7 h The h 7 therefore ah If a, a,.. a are i H.P, the,,..., a a a are i A.P. Now, let... a a a a a a d a a a a a a... d aa a a a a 70. d log d log d 5log ( d )( d )( d ) 5 d d 5log 5 5log ( d ) log y y 9
10 CPT-7 / XI-LJ / 7. Use A.M. > G.M for (a, b, c) The a b c > (abc) /..() Now ab c, a b c, a b c 5 are i A.P. (a, b, c, > 0) The, abc, a b c are also i A.P. abc a b c, (abc ) 0, abc, put abc i equatio () 7. t ( ) ( ) ( ) ( ) ( ) Give series t ( ) as ( ) 7. Let G, S 5 Ad r is coo ratio a The S r S, r / 5 r < r <, for Ifiite G.P. < < 5 0 < < 0 a, a, a, a are i HP 7.,,, a a a a are i AP λ ( say) a a a a a a a a a a a a a a a a a a a a a a a a a a or a a a a ( a a ) r a a r r 0
11 CPT-7 / XI-LJ / ( ) ( ) a a a a a a a a a a ar ar r a a a a Hece, is a root of 5 0 a b a a a a... a a ad ab g. g g. g... g. g ab ad h. a b a a a a a a... a b a b g g g g g g ab ab h Give log ( c a) log ( a c) log ( a b c) log ( a c) ( a b c) 77. ( c a) ( a c) ( a b c) ( c a ) ( a c )( a b c ) log log After solvig, ac b a c Hece, a, b, c are i H.P ( )( )( ) tr S say 8 r r ( ) ( )( ) tr S 8 ( )( ) ( ) t S S li li li r t r r ( ) ) r ( ) ( )( ) li r ( )( ) ( ) li ( )( ) d,e,f are i G.P. e df d e f λ λ 0 d df f 0 ( d f ) 0 f d Now, substitutig the value of i a b c 0 af b f a b c a b c i.e., c 0 0 or 0 d d d df f d e f a b c,, d e f are i HP
12 CPT-7 / XI-LJ / i j i ( i ) 79. j i i i j k i j i i i H ab H, a b a b a b, 8. ( )( ) ( ) ( )( ) H a b a (i) H a b a Siilarly, H b a b (ii) H b a b H a H b H a H b [ ] a a 5 a a 75 i ai [ a a ] AM of positive ubers G.M. of positive ubers ab ac bc ba ca cb 6 ( ) ( ) ( ) ( a b c ) a b c b c a c a b 6. abc l 6 8. I first 0 iutes, the uber of otes couted is a a a. Upto ters a c b b b b ab bc y ( ab ad y bc) 85.
13 CPT-7 / XI-LJ / ( ap b) ( bp c) ( cp d ) 0 ( ap b) ( bp c) ( cp d ) 0 b c d p a, b, c, d areig. P. a b c 86. ab a b A G 7 a b ab y b y a ad b a y y y a b y 88. Give (y ), (y a), (y ) are i H.P. 89.,, are i A.P. y (y a) y a y a y a a a, y a, a are i G.P. a ( ) d a ( ) d Subtractig : ( ) d d a T ( ) 90.,, a b c are i A.P. b a c b
Narayana IIT Academy
INDIA XI STD IIT_LJ Jee-Advaced Date: 08-0-08 Time: HS 0_P MODEL Max.Marks:80 KEY SHEET PHYSICS b a b 4 d 5 b 6 c 7 c 8 c 9 d 0 b a,b,c a,c b,c 4 a,c 5 b,c,d 6 5 7 8 4 9 0 6 CHEMISTY c c b 4 a 5 c 6 b
More informationQ. No. PHYSICS CHEMISTRY MATHEMATICS
AITS-CRT-I (Paper-)-PCM(Sol)-JEE(Advaced)/5 FIITJEE Studets From All Programs have bagged 4 i Top 00, 66 i Top 00 ad 74 i Top 500 All Idia Raks. FIITJEE Performace i JEE (Advaced), 04: 5 FIITJEE Studets
More informationNARAYANA IIT ACADEMY INDIA
NARAYANA IIT ACADEMY INDIA Sec: XI-IC SPARK CPT-5 Date: 6-0-07 TIME: 3 HOURS MAX MARKS:86 JEE-ADVANCED-06-P-Model KEY SHEET PHYSICS 3 4 5 6 7 8 9 0 d d b b d a, c d c, d b, d a,b,c,d 3 4 5 6 7 8 a c a,
More informationNARAYANA. XI-REG (Date: ) Physics Chemistry Mathematics
CPT-5 / XI-REG / 0..07 / Hits & Solutio CODE NARAYANA I I T / N E E T A C A D E M Y XI-REG XI-REG (Date: 0..07) Physics Chemistry Mathematics. 3. 6.. 3 3. 6. 3. 33. 63.. 3. 6. 5. 35. 65. 6. 3 36. 66. 7.
More informationANSWERS, HINTS & SOLUTIONS PART TEST I PAPER-2 ANSWERS KEY
AITS-PT-I (Paper-)-PCM-JEE(Advaced)/8 FIITJEE JEE(Advaced)-8 ANSWERS, HINTS & SOLUTIONS PART TEST I PAPER- ANSWERS KEY Q. No. PHYSICS Q. No. CHEMISTRY Q. No. MATHEMATICS ALL INDIA TEST SERIES. D. B 7.
More informationEngineering Mechanics Dynamics & Vibrations. Engineering Mechanics Dynamics & Vibrations Plane Motion of a Rigid Body: Equations of Motion
1/5/013 Egieerig Mechaics Dyaics ad Vibratios Egieerig Mechaics Dyaics & Vibratios Egieerig Mechaics Dyaics & Vibratios Plae Motio of a Rigid Body: Equatios of Motio Motio of a rigid body i plae otio is
More informationNarayana IIT Academy
-0-8_Sr. IIT_IZ_Ph-I_JEE-ADV_New Model-_P_GTA-9_Key&Sol s Narayaa IIT Academy INDIA Sec: Sr.IIT_IZ GTA-9 Date: -0-8 Time: 0:00 PM to 05:00 PM NEW Model-(P) Ma Marks: 64 KEY & SLUTINS MATHS AB ABC 3 AB
More informationMathematics Extension 2
004 HIGHER SCHOOL CERTIFICATE EXAMINATION Mathematics Etesio Geeral Istructios Readig time 5 miutes Workig time hours Write usig black or blue pe Board-approved calculators may be used A table of stadard
More informationNURTURE COURSE TARGET : JEE (MAIN) Test Type : ALL INDIA OPEN TEST TEST DATE : ANSWER KEY HINT SHEET. 1. Ans.
Test Type : LL INDI OPEN TEST Paper Code : 0000CT005 00 CLSSROOM CONTCT PROGRMME (cadeic Sessio : 05-06) NURTURE COURSE TRGET : JEE (MIN) 07 TEST DTE : - 0-06 NSWER KEY HINT SHEET Corporate Office : CREER
More informationSAFE HANDS & IIT-ian's PACE EDT-10 (JEE) SOLUTIONS
. If their mea positios coicide with each other, maimum separatio will be A. Now from phasor diagram, we ca clearly see the phase differece. SAFE HANDS & IIT-ia's PACE ad Aswer : Optio (4) 5. Aswer : Optio
More informationVERY SHORT ANSWER TYPE QUESTIONS (1 MARK)
VERY SHORT ANSWER TYPE QUESTIONS ( MARK). If th term of a A.P. is 6 7 the write its 50 th term.. If S = +, the write a. Which term of the sequece,, 0, 7,... is 6? 4. If i a A.P. 7 th term is 9 ad 9 th
More informationSTRAIGHT LINES & PLANES
STRAIGHT LINES & PLANES PARAMETRIC EQUATIONS OF LINES The lie "L" is parallel to the directio vector "v". A fixed poit: "( a, b, c) " o the lie is give. Positio vectors are draw from the origi to the fixed
More informationChapter 19. Solubility and Simultaneous Equilibria p
Chapter 19 Solubility and Simultaneous Equilibria p. 832 857 Solubility Product ) The product of molar concentrations of the constituent ions, each raised ot the power of its stoichiometric coefficients
More informationDe Moivre s Theorem - ALL
De Moivre s Theorem - ALL. Let x ad y be real umbers, ad be oe of the complex solutios of the equatio =. Evaluate: (a) + + ; (b) ( x + y)( x + y). [6]. (a) Sice is a complex umber which satisfies = 0,.
More informationChemistry 104 Chapter 17 Summary and Review Answers
Chemistry 104 Chapter 17 Summary ad Review Aswers 1. You eed to make a buffer with a ph of 4.80. You have 0.150 M sodium hydroxide, 0.150 M acetic acid ad 0.150 M sodium bicarboate. What do you do? (Make
More informationMechanical Vibrations
Mechaical Vibratios Cotets Itroductio Free Vibratios o Particles. Siple Haroic Motio Siple Pedulu (Approxiate Solutio) Siple Pedulu (Exact Solutio) Saple Proble 9. Free Vibratios o Rigid Bodies Saple Proble
More informationClassical Mechanics Qualifying Exam Solutions Problem 1.
Jauary 4, Uiversity of Illiois at Chicago Departmet of Physics Classical Mechaics Qualifyig Exam Solutios Prolem. A cylider of a o-uiform radial desity with mass M, legth l ad radius R rolls without slippig
More informationUNIT III: SOLUBILITY EQUILIBRIUM YEAR END REVIEW (Chemistry 12)
I. Multiple Choice UNIT III: SOLUBILITY EQUILIBRIUM YEAR END REVIEW (Chemistry 12) 1) Which one of the following would form an ionic solution when dissolved in water? A. I 2 C. Ca(NO 3 ) 2 B. CH 3 OH D.
More informationJEE ADVANCED 2013 PAPER 1 MATHEMATICS
Oly Oe Optio Correct Type JEE ADVANCED 0 PAPER MATHEMATICS This sectio cotais TEN questios. Each has FOUR optios (A), (B), (C) ad (D) out of which ONLY ONE is correct.. The value of (A) 5 (C) 4 cot cot
More informationNernst Equation. Nernst Equation. Electric Work and Gibb's Free Energy. Skills to develop. Electric Work. Gibb's Free Energy
Nerst Equatio Skills to develop Eplai ad distiguish the cell potetial ad stadard cell potetial. Calculate cell potetials from kow coditios (Nerst Equatio). Calculate the equilibrium costat from cell potetials.
More informationSystems of Particles: Angular Momentum and Work Energy Principle
1 2.003J/1.053J Dyamics ad Cotrol I, Sprig 2007 Professor Thomas Peacock 2/20/2007 Lecture 4 Systems of Particles: Agular Mometum ad Work Eergy Priciple Systems of Particles Agular Mometum (cotiued) τ
More informationANSWER KEY PHYSICS : GRAVITATION CHEMISTRY : VOLUMETRIC MATHEMATICS : LIMIT
MUMBAI / AKOLA / DELHI / KOLKATA / LUCKNOW / NASHIK / GOA / BOKARO / PUNE / NAGPUR IIT JEE: 09 TW TEST (ADV) DATE: 04/03/8 ANSWER KEY PHYSICS : GRAVITATION. (D). (A) 3. (B) 4. (B) 5. (C) 6. (ACD 7. (AD)
More informationSINGLE CORRECT ANSWER TYPE QUESTIONS: TRIGONOMETRY 2 2
Class-Jr.X_E-E SIMPLE HOLIDAY PACKAGE CLASS-IX MATHEMATICS SUB BATCH : E-E SINGLE CORRECT ANSWER TYPE QUESTIONS: TRIGONOMETRY. siθ+cosθ + siθ cosθ = ) ) ). If a cos q, y bsi q, the a y b ) ) ). The value
More informationCHAPTER 8 SYSTEMS OF PARTICLES
CHAPTER 8 SYSTES OF PARTICLES CHAPTER 8 COLLISIONS 45 8. CENTER OF ASS The ceter of mass of a system of particles or a rigid body is the poit at which all of the mass are cosidered to be cocetrated there
More information+ {JEE Advace 03} Sept 0 Name: Batch (Day) Phoe No. IT IS NOT ENOUGH TO HAVE A GOOD MIND, THE MAIN THING IS TO USE IT WELL Marks: 00. If A (α, β) = (a) A( α, β) = A( α, β) (c) Adj (A ( α, β)) = Sol : We
More information: ) 9) 6 PM, 6 PM
Physics 101 Sectio 3 Mar. 1 st : Ch. 7-9 review Ch. 10 Aoucemets: Test# (Ch. 7-9) will be at 6 PM, March 3 (6) Lockett) Study sessio Moday eveig at 6:00PM at Nicholso 130 Class Website: http://www.phys.lsu.edu/classes/sprig010/phys101-3/
More informationJ 10 J W W W W
PHYS 54 Practice Test 3 Solutios Sprig 8 Q: [4] A costat force is applied to a box, cotributig to a certai displaceet o the floor. If the agle betwee the force ad displaceet is 35, the wor doe b this force
More informationUNIFIED COUNCIL. An ISO 9001: 2015 Certified Organisation NATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION (UPDATED)
UNIFIED COUNCIL A ISO 900: 05 Certified Orgaisatio NATIONAL LEVEL SCIENCE TALENT SEARCH EXAMINATION (UPDATED) CLASS - (PCM) Questio Paper Code : UN6 KEY A C A B 5 B 6 D 7 C 8 A 9 B 0 D A C B B 5 C 6 D
More informationCHM 112 Dr. Kevin Moore
CHM 112 Dr. Kevin Moore Reaction of an acid with a known concentration of base to determine the exact amount of the acid Requires that the equilibrium of the reaction be significantly to the right Determination
More informationPhys 6303 Final Exam Solutions December 19, 2012
Phys 633 Fial Exam s December 19, 212 You may NOT use ay book or otes other tha supplied with this test. You will have 3 hours to fiish. DO YOUR OWN WORK. Express your aswers clearly ad cocisely so that
More informationECE Spring Prof. David R. Jackson ECE Dept. Notes 20
ECE 6341 Sprig 016 Prof. David R. Jackso ECE Dept. Notes 0 1 Spherical Wave Fuctios Cosider solvig ψ + k ψ = 0 i spherical coordiates z φ θ r y x Spherical Wave Fuctios (cot.) I spherical coordiates we
More information1. Which one of the following would form an ionic solution when dissolved in water? A. I2 C. Ca(NO3)2 B. CH3OH D. C12H22O11
Chemistry 12 Solubility Equilibrium Review Package Name: Date: Block: I. Multiple Choice 1. Which one of the following would form an ionic solution when dissolved in water? A. I2 C. Ca(NO3)2 B. CH3OH D.
More informationPROBLEM Copyright McGraw-Hill Education. Permission required for reproduction or display. SOLUTION. v 1 = 4 km/hr = 1.
PROLEM 13.119 35,000 Mg ocea lier has a iitial velocity of 4 km/h. Neglectig the frictioal resistace of the water, determie the time required to brig the lier to rest by usig a sigle tugboat which exerts
More informationSEQUENCES AND SERIES
9 SEQUENCES AND SERIES INTRODUCTION Sequeces have may importat applicatios i several spheres of huma activities Whe a collectio of objects is arraged i a defiite order such that it has a idetified first
More informationMathematics Extension 2
009 HIGHER SCHOOL CERTIFICATE EXAMINATION Mathematics Etesio Geeral Istructios Readig time 5 miutes Workig time hours Write usig black or blue pe Board-approved calculators may be used A table of stadard
More informationPHYS 321 Solutions to Practice Final (December 2002).
PHYS Solutios to Practice Fial (December ) Two masses, m ad m are coected by a sprig of costat k, leadig to the potetial V( r) = k( r ) r a) What is the Lagragia for this system? (Assume -dimesioal motio)
More informationMATH Exam 1 Solutions February 24, 2016
MATH 7.57 Exam Solutios February, 6. Evaluate (A) l(6) (B) l(7) (C) l(8) (D) l(9) (E) l() 6x x 3 + dx. Solutio: D We perform a substitutio. Let u = x 3 +, so du = 3x dx. Therefore, 6x u() x 3 + dx = [
More informationSEQUENCE AND SERIES NCERT
9. Overview By a sequece, we mea a arragemet of umbers i a defiite order accordig to some rule. We deote the terms of a sequece by a, a,..., etc., the subscript deotes the positio of the term. I view of
More informationREVIEW QUESTIONS Chapter 17
Chemistry 102 REVIEW QUESTIONS Chapter 17 1. A buffer is prepared by adding 20.0 g of acetic acid (HC 2 H 3 O 2 ) and 20.0 g of sodium acetate (NaC 2 H 3 O 2 ) in enough water to prepare 2.00 L of solution.
More information2D DSP Basics: Systems Stability, 2D Sampling
- Digital Iage Processig ad Copressio D DSP Basics: Systes Stability D Saplig Stability ty Syste is stable if a bouded iput always results i a bouded output BIBO For LSI syste a sufficiet coditio for stability:
More informationNARAYANA IIT ACADEMY INDIA XI -REG_Adv. Dt: Time: 09:00 AM to 12:00 Noon Max.Marks: 180
6..06 XI_Reg.ADV._Jee-Adv_03-Pkey & hits NARAYANA IIT ACADEMY INDIA XI -REG_Adv. Dt: 6--06 Time: 09:00 AM to :00 Noo Max.Marks: 80 KEY & SOLUTIONS PHYSICS CHEMISTRY MATHS C C 4 B A C 4 D 3 A 3 D 43 A 4
More informationSolutions to Equilibrium Practice Problems
Solutios to Equilibrium Practice Problems Chem09 Fial Booklet Problem 1. Solutio: PO 4 10 eq The expressio for K 3 5 P O 4 eq eq PO 4 10 iit 1 M I (a) Q 1 3, the reactio proceeds to the right. 5 5 P O
More informationDetermination of Amount of Acid by Back Titration. Experiment 4. Experiment 4
Determiatio of Amout of Acid by Back Titratio Experimet 4 Goal: Experimet 4 Determie amout of acid that ca be eutralized by a commercial atacid Method: React atacid tablet with excess stomach acid (HCl)
More informationDYNAMICS VECTOR MECHANICS FOR ENGINEERS: Mechanical Vibrations. Seventh Edition CHAPTER. Ferdinand P. Beer E. Russell Johnston, Jr.
Seveth Editio CHAPTER 9 VECTOR MECHANICS FOR ENGINEERS: DYNAMICS Ferdiad P. Beer E. Russell Johsto, Jr. Mechaical Vibratios Lecture Notes: J. Walt Oler Texas Tech Uiversity 003 The McGraw-Hill Copaies,
More informationANSWER KEY WITH SOLUTION PAPER - 2 MATHEMATICS SECTION A 1. B 2. B 3. D 4. C 5. B 6. C 7. C 8. B 9. B 10. D 11. C 12. C 13. A 14. B 15.
TARGET IIT-JEE t [ACCELERATION] V0 to V BATCH ADVANCED TEST DATE : - 09-06 ANSWER KEY WITH SOLUTION PAPER - MATHEMATICS SECTION A. B. B. D. C 5. B 6. C 7. C 8. B 9. B 0. D. C. C. A. B 5. C 6. D 7. A 8.
More informationProblem 1. Problem Engineering Dynamics Problem Set 9--Solution. Find the equation of motion for the system shown with respect to:
2.003 Egieerig Dyamics Problem Set 9--Solutio Problem 1 Fid the equatio of motio for the system show with respect to: a) Zero sprig force positio. Draw the appropriate free body diagram. b) Static equilibrium
More informationMATH spring 2008 lecture 3 Answers to selected problems. 0 sin14 xdx = x dx. ; (iv) x +
MATH - sprig 008 lecture Aswers to selected problems INTEGRALS. f =? For atiderivatives i geeral see the itegrals website at http://itegrals.wolfram.com. (5-vi (0 i ( ( i ( π ; (v π a. This is example
More informationBalancing. Rotating Components Examples of rotating components in a mechanism or a machine. (a)
alacig NOT COMPLETE Rotatig Compoets Examples of rotatig compoets i a mechaism or a machie. Figure 1: Examples of rotatig compoets: camshaft; crakshaft Sigle-Plae (Static) alace Cosider a rotatig shaft
More informationINMO-2018 problems and solutions
Pioeer Educatio The Best Way To Success INMO-018 proles ad solutios NTSE Olypiad AIPMT JEE - Mais & Advaced 1. Let ABC e a o-equilateral triagle with iteger sides. Let D ad E e respectively the id-poits
More information2) 3 π. EAMCET Maths Practice Questions Examples with hints and short cuts from few important chapters
EAMCET Maths Practice Questios Examples with hits ad short cuts from few importat chapters. If the vectors pi j + 5k, i qj + 5k are colliear the (p,q) ) 0 ) 3) 4) Hit : p 5 p, q q 5.If the vectors i j
More informationChapter 4. Fourier Series
Chapter 4. Fourier Series At this poit we are ready to ow cosider the caoical equatios. Cosider, for eample the heat equatio u t = u, < (4.) subject to u(, ) = si, u(, t) = u(, t) =. (4.) Here,
More informationNATIONAL SENIOR CERTIFICATE GRADE 12
NATIONAL SENIOR CERTIFICATE GRADE 1 MATHEMATICS P NOVEMBER 01 MARKS: 150 TIME: 3 hours This questio paper cosists of 13 pages, 1 diagram sheet ad 1 iformatio sheet. Please tur over Mathematics/P DBE/November
More informationJEE(Advanced) 2018 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 20 th MAY, 2018)
JEE(Advaced) 08 TEST PAPER WITH SOLUTION (HELD ON SUNDAY 0 th MAY, 08) PART- : JEE(Advaced) 08/Paper- SECTION. For ay positive iteger, defie ƒ : (0, ) as ƒ () j ta j j for all (0, ). (Here, the iverse
More informationLecture 20 - Wave Propagation Response
.09/.093 Fiite Eleet Aalysis of Solids & Fluids I Fall 09 Lecture 0 - Wave Propagatio Respose Prof. K. J. Bathe MIT OpeCourseWare Quiz #: Closed book, 6 pages of otes, o calculators. Covers all aterials
More informationProblem Cosider the curve give parametrically as x = si t ad y = + cos t for» t» ß: (a) Describe the path this traverses: Where does it start (whe t =
Mathematics Summer Wilso Fial Exam August 8, ANSWERS Problem 1 (a) Fid the solutio to y +x y = e x x that satisfies y() = 5 : This is already i the form we used for a first order liear differetial equatio,
More informationNATIONAL SENIOR CERTIFICATE GRADE 12
NATIONAL SENIOR CERTIFICATE GRADE MATHEMATICS P FEBRUARY/MARCH 04 MARKS: 50 TIME: 3 hours This questio paper cosists of 9 pages, diagram sheet ad iformatio sheet. Please tur over Mathematics/P DBE/Feb.
More informationStudent Worksheet for Buffers, Ksp, and Titrations
Student Worksheet for Attempt to work the following practice problems after working through the sample problems in the videos. Answers are given on the last page(s). Relevant Equations Keq= [C]c [D] d
More informationExam 2 CMSC 203 Fall 2009 Name SOLUTION KEY Show All Work! 1. (16 points) Circle T if the corresponding statement is True or F if it is False.
1 (1 poits) Circle T if the correspodig statemet is True or F if it is False T F For ay positive iteger,, GCD(, 1) = 1 T F Every positive iteger is either prime or composite T F If a b mod p, the (a/p)
More informationNotes 8 Singularities
ECE 6382 Fall 27 David R. Jackso Notes 8 Sigularities Notes are from D. R. Wilto, Dept. of ECE Sigularity A poit s is a sigularity of the fuctio f () if the fuctio is ot aalytic at s. (The fuctio does
More informationCAREER POINT. Major Test (AIEEE Pattern) (MT-1) Take Home PHYSICS, CHEMISTRY & MATHEMATICS HINTS & SOLUTIONS
CAREER PINT PHYSICS, CHEMISTRY & MATHEMATICS HINTS & SLUTINS PHYSICS. [] Path differece correspodig to th maima is λ.[] so correspodig phase differece is 0 π.. [] U µc v T µ. [] µ i.e., a µ g. [] r B
More informationSection 5.2: Calorimetry and Enthalpy Tutorial 1 Practice, page 297
Sectio 52: Calorietry ad Ethalpy Tutorial 1 Practice, page 297 1 Give: V 60 L ; T iitial 25 C ; T fial 75 C; d H2O(l) H2O(l) 100 g/l Required: theral eergy required, q Aalysis: q cδt Solutio: Step 1: Deterie
More informationThe type of limit that is used to find TANGENTS and VELOCITIES gives rise to the central idea in DIFFERENTIAL CALCULUS, the DERIVATIVE.
NOTES : LIMITS AND DERIVATIVES Name: Date: Period: Iitial: LESSON.1 THE TANGENT AND VELOCITY PROBLEMS Pre-Calculus Mathematics Limit Process Calculus The type of it that is used to fid TANGENTS ad VELOCITIES
More informationKISHORE VAIGYANIK PROTSAHAN YOJANA Date : Duration : 3 Hours Max. Marks : 160 STREAM - SB/SX
KISHORE VAIGYANIK PROTSAHAN YOJANA - 04 Date : 0--04 Duratio : Hours Max. Marks : 60 GENERAL INSTRUCTIONS STREAM - SB/SX The Test Booklet cosists of 0 questios. There are Two parts i the questio paper.
More informationFlight and Orbital Mechanics. Exams
1 Flight ad Orbital Mechaics Exas Exa AE2104-11: Flight ad Orbital Mechaics (2 Noveber 2012, 14.00 17.00) Please put your ae, studet uber ad ALL YOUR INITIALS o your work. Aswer all questios ad put your
More informationTitration a solution of known concentration, called a standard solution
Acid-Base Titrations Titration is a form of analysis in which we measure the volume of material of known concentration sufficient to react with the substance being analyzed. Titration a solution of known
More information[ 11 ] z of degree 2 as both degree 2 each. The degree of a polynomial in n variables is the maximum of the degrees of its terms.
[ 11 ] 1 1.1 Polyomial Fuctios 1 Algebra Ay fuctio f ( x) ax a1x... a1x a0 is a polyomial fuctio if ai ( i 0,1,,,..., ) is a costat which belogs to the set of real umbers ad the idices,, 1,...,1 are atural
More informationSalt Hydrolysis Problems
Salt Hydrolysis Problems Page 169 Salt Hydrolysis Problems 1) Write the Brønsted-Lowry reaction between the base CN! and the weak acid H 2 O. CN! + H 2 O W HCN + OH! 2) Write the Brønsted-Lowry reaction
More informationMathematics Extension 1
016 Bored of Studies Trial Eamiatios Mathematics Etesio 1 3 rd ctober 016 Geeral Istructios Total Marks 70 Readig time 5 miutes Workig time hours Write usig black or blue pe Black pe is preferred Board-approved
More informationCHAPTER - 9 SEQUENCES AND SERIES KEY POINTS A sequece is a fuctio whose domai is the set N of atural umbers. A sequece whose rage is a subset of R is called a real sequece. Geeral A.P. is, a, a + d, a
More informationPHY 181 Test 2 Practice Solutions Spring 2013
PHY 8 est Practice Solutios Sprig 3 Q: [4] costat et force F is applied to objects of icreasig ass. Which of the graphs describes the depedece of the objects acceleratio o the ass? a) b) c) C d) D Solutio:
More information7. A solution has the following concentrations: [Cl - ] = 1.5 x 10-1 M [Br - ] = 5.0 x 10-4 M
Solubility, Ksp Worksheet 1 1. How many milliliters of 0.20 M AlCl 3 solution would be necessary to precipitate all of the Ag + from 45ml of a 0.20 M AgNO 3 solution? AlCl 3(aq) + 3AgNO 3(aq) Al(NO 3)
More information3sin A 1 2sin B. 3π x is a solution. 1. If A and B are acute positive angles satisfying the equation 3sin A 2sin B 1 and 3sin 2A 2sin 2B 0, then A 2B
1. If A ad B are acute positive agles satisfyig the equatio 3si A si B 1 ad 3si A si B 0, the A B (a) (b) (c) (d) 6. 3 si A + si B = 1 3si A 1 si B 3 si A = cosb Also 3 si A si B = 0 si B = 3 si A Now,
More informationEquilibri acido-base ed equilibri di solubilità. Capitolo 16
Equilibri acido-base ed equilibri di solubilità Capitolo 16 The common ion effect is the shift in equilibrium caused by the addition of a compound having an ion in common with the dissolved substance.
More informationAIEEE 2004 (MATHEMATICS)
AIEEE 00 (MATHEMATICS) Importat Istructios: i) The test is of hours duratio. ii) The test cosists of 75 questios. iii) The maimum marks are 5. iv) For each correct aswer you will get marks ad for a wrog
More informationRAYLEIGH'S METHOD Revision D
RAYGH'S METHOD Revisio D B To Irvie Eail: toirvie@aol.co Noveber 5, Itroductio Daic sstes ca be characterized i ters of oe or ore atural frequecies. The atural frequec is the frequec at which the sste
More informationNarayana IIT/NEET Academy INDIA IIT_XI-IC_SPARK 2016_P1 Date: Max.Marks: 186
Narayaa IIT/NEET Academy INDIA IIT_XI-IC_SPARK 6_P Date: 5--8 Max.Marks: 86 KEY SHEET PHYSICS B B c 4 B 5 c 6 ac 7 ac 8 ac 9 ad abc bc acd ad 4 5 6 6 7 6 8 4 CHEMISTRY 9 c b c a a 4 bc 5 ab 6 abcd 7 ab
More informationResults of Final Exam
Results of Fial Exa # of studets 1 3 4 5 6 7 8 9 Grade Poits A >15 + 1-14 75-94 C + 7-74 C 45-69 D 35-44 F
More information5. Quantum Nature of the Nano-world ( Fundamental of. Quantum mechanics)
5. Quatu Nature of the Nao-world Fudaetal of What is the defiitio of aoaterials?? Quatu echaics i Origial: quatu size effect where the electroic properties of solids are altered with great reductios i
More informationLecture Presentation. Chapter 16. Aqueous Ionic Equilibrium. Sherril Soman Grand Valley State University Pearson Education, Inc.
Lecture Presentation Chapter 16 Aqueous Ionic Equilibrium Sherril Soman Grand Valley State University The Danger of Antifreeze Each year, thousands of pets and wildlife species die from consuming antifreeze.
More informationIclied Plae. A give object takes times as much time to slide dow a 45 0 rough iclied plae as it takes to slide dow a perfectly smooth 45 0 iclie. The coefficiet of kietic frictio betwee the object ad the
More informationDougherty Valley High School AP Chemistry Chapters 14 and 15 Test - Acid-Base Equilibria
Dougherty Valley High School AP Chemistry Chapters 14 and 15 Test - Acid-Base Equilibria This is a PRACTICE TEST. Complete ALL questions. Answers will be provided so that you may check your work. I strongly
More informationSolutions 4a (Chapter 4 problems)
Solutions 4a (Chapter 4 problems) Chem151 [Kua] 4.10 A balanced chemical equation must have equal numbers of atoms of each element on each side of the arrow. Balance each element in turn, beginning with
More informationToday. Homework 4 due (usual box) Center of Mass Momentum
Today Homework 4 due (usual box) Ceter of Mass Mometum Physics 40 - L 0 slide review Coservatio of Eergy Geeralizatio of Work-Eergy Theorem Says that for ay isolated system, the total eergy is coserved
More informationAcid-Base Equilibria and Solubility Equilibria Chapter 17
PowerPoint Lecture Presentation by J. David Robertson University of Missouri Acid-Base Equilibria and Solubility Equilibria Chapter 17 The common ion effect is the shift in equilibrium caused by the addition
More informationReview Problems for the Final
Review Problems for the Fial Math - 3 7 These problems are provided to help you study The presece of a problem o this hadout does ot imply that there will be a similar problem o the test Ad the absece
More informationEE Midterm Test 1 - Solutions
EE35 - Midterm Test - Solutios Total Poits: 5+ 6 Bous Poits Time: hour. ( poits) Cosider the parallel itercoectio of the two causal systems, System ad System 2, show below. System x[] + y[] System 2 The
More informationSolubility Multiple Choice. January Which of the following units could be used to describe solubility? A. g/s B. g/l C. M/L D.
Solubility Multiple Choice January 1999 14. Which of the following units could be used to describe solubility? A. g/s B. g/l C. M/L D. mol/s 15. Consider the following anions: When 10.0mL of 0.20M Pb(NO3)
More informationChapter 2 Motion and Recombination of Electrons and Holes
Chapter 2 Motio ad Recombiatio of Electros ad Holes 2.1 Thermal Eergy ad Thermal Velocity Average electro or hole kietic eergy 3 2 kt 1 2 2 mv th v th 3kT m eff 3 23 1.38 10 JK 0.26 9.1 10 1 31 300 kg
More informationChemGGuru. Questions & Answer CHEMISTRY
CAREER PIT JEE Mai lie Paper JEE Mai lie Exam 09 [Memory Based Paper] Q. Which of the followig is amphoteric i ature As. [] ` Questios & Aswer th Jauary 09 Shift - I CHEMISTRY Mg(H ( Be(H Ca(H Sr(H Q.
More informationNarayana IIT Academy
Narayaa IIT Academy INDIA XII_IC_SPARK JEE-MAIN Date: 3-7-7 Time : 3 Hours CPT -5 Ma Marks : 36 KEY SHEET PHYSICS ) B ) C 3) A 4) C 5) B 6) A 7) A 8) C 9) D ) A ) B ) C 3) D 4) B 5) A 6) A 7) C 8) C 9)
More informationHomework 6: Forced Vibrations Due Friday April 6, 2018
EN40: Dyais ad Vibratios Hoework 6: Fored Vibratios Due Friday April 6, 018 Shool of Egieerig Brow Uiversity 1. The vibratio isolatio syste show i the figure has 0kg, k 19.8 kn / 1.59 kns / If the base
More informationAcid-Base Equilibria and Solubility Equilibria
Acid-Base Equilibria and Solubility Equilibria Acid-Base Equilibria and Solubility Equilibria Homogeneous versus Heterogeneous Solution Equilibria (17.1) Buffer Solutions (17.2) A Closer Look at Acid-Base
More informationPolynomial and Rational Functions. Polynomial functions and Their Graphs. Polynomial functions and Their Graphs. Examples
Polomial ad Ratioal Fuctios Polomial fuctios ad Their Graphs Math 44 Precalculus Polomial ad Ratioal Fuctios Polomial Fuctios ad Their Graphs Polomial fuctios ad Their Graphs A Polomial of degree is a
More information( ) (( ) ) ANSWERS TO EXERCISES IN APPENDIX B. Section B.1 VECTORS AND SETS. Exercise B.1-1: Convex sets. are convex, , hence. and. (a) Let.
Joh Riley 8 Jue 03 ANSWERS TO EXERCISES IN APPENDIX B Sectio B VECTORS AND SETS Exercise B-: Covex sets (a) Let 0 x, x X, X, hece 0 x, x X ad 0 x, x X Sice X ad X are covex, x X ad x X The x X X, which
More informationMore About Chemical Equilibria
1 More About Chemical Equilibria Acid-Base & Precipitation Reactions Chapter 15 & 16 1 Objectives Chapter 15 Define the Common Ion Effect (15.1) Define buffer and show how a buffer controls ph of a solution
More informationName ID# Section # CH 1020 EXAM 3 Spring Form A
Name ID# Sectio # CH 1020 EXAM 3 Sprig 2016 - Form A Fill i your ame, ID#, ad sectio o this test booklet. Fill i ad bubble i your ame, ID# (bubble 0 for C ), ad sectio o the scatro form. For questio #60
More informationIonic Equilibria. weak acids and bases. salts of weak acids and bases. buffer solutions. solubility of slightly soluble salts
Ionic Equilibria weak acids and bases salts of weak acids and bases buffer solutions solubility of slightly soluble salts Arrhenius Definitions produce H + ions in the solution strong acids ionize completely
More informationSOLUTIONS Homogeeous mixture: Substaces which dissolve with each other thoroughly to form a uiform mixture is called homogeeous mixture. Eg: Water + Salt. Solutios: homogeeous mixture formed with two or
More informationSEQUENCES AND SERIES
Sequeces ad 6 Sequeces Ad SEQUENCES AND SERIES Successio of umbers of which oe umber is desigated as the first, other as the secod, aother as the third ad so o gives rise to what is called a sequece. Sequeces
More information] after equilibrium has been established?
Chemistry 1 Solubility Equilibrium onster Review 1. A saturated solution forms when a 0. 10 mol of salt is added to 10. L of water. The salt is A. Li S B. CuBr C. Zn( OH) ( ) D. NH CO 4. Consider the following
More information