! = Chemical Engineering Class 35 page 1. I. Non-Newtonian Fluids - Overview A. Simple Classifications of Fluids 1. Shear-Dependent Fluids.

Size: px
Start display at page:

Download "! = Chemical Engineering Class 35 page 1. I. Non-Newtonian Fluids - Overview A. Simple Classifications of Fluids 1. Shear-Dependent Fluids."

Transcription

1 Chemical Egieerig 74 - Class 5 page I. No-Newtoia Fluids - Overview A. Simple Classificatios of Fluids. Shear-epedet Fluids a. Newtoia obeys Newtos Law of viscosity) µ!! = µ dv x dy dv /dy x dv /dy x c. Pseudoplastic molecules lie up oce flow begis)! dv /dy x " dv /dy x Ca be fit with the Power Law " = dvx dy d. ilatat particle suspesios collide whe flow begis)! dv /dy x " dv /dy x O with other models emider: Graduate texts write Newto s Law as τ = -µ dv x /dy e. More complex models i) Powell-Eyrig Model based o Eyrigs theories of the molecular structure of liquids) " = A dv x dy + B sih C dv x ) dy ii) Ellis Model purely empirical)! = A + B! dv x C dy iii) eier-phillipoff Model purely empirical) B A " = A + + " /C) dv x dy iv) For each of these, the three arbitrary costats A, B, ad C) are adjusted to fit the data.

2 Chemical Egieerig 74 - Class 5 page. Time-epedet Fluids heopectic! Thixotropic { { motio causes aggregatio or uravelig of molecules motio causes re-coilig or fragmetig of molecules time a. The chages occur mostly withi the first 6 secods b. escriptio of these fluids is extremely difficult.. Viscoelastic Fluids a. Exhibit elastic recovery from deformatios which occur durig flow b. Also exhibit plastic permaet) deformatio c. Modeled usig simple sprig-dashpot elemets ad combiatios of those elemets Maxwell Elemet Kelvi or Voigt Elemet B. Observatios. No-Newtoia behavior is usually see whe the fluid is composed of small carrier molecules ad larger suspeded molecules or particles. a. Bigham Fluids: Coal slurries, grai slurries, sewage sludge b. Pseudoplastic Fluids: Polymer melts, paper pulp suspesios, pigmet suspesios c. ilatat Fluids: Starch suspesios, mica suspesios, quicksad d. Thixotropic Fluids: Mayoaise, drillig mud, pait, ik e. heopectic Fluids: Gypsum suspesios i water, vaadium petoxide sols f. Viscoelastic Fluids: Polymeric liquids g. Other: Yield Pseudoplastic Fluid: Blood. No-Newtoia fluids exhibit lamiar ad turbulet flow regimes, with a trasitio betwee those regimes.. Equatios for Newtoia fluids cat be used, because there is o sigle value of viscosity for such fluids. e.g. Ca t calculate the eyolds umber usig the Newtoia defiitio

3 Chemical Egieerig 74 - Class 5 page 4. We ofte talk about a apparet viscosity η) where! = " dv x dy a. For example for a power-law fluid " = K dv x dy ) ) so, for such a fluid " = K dv x dy ) ) b. The apparet viscosity varies with shear rate, as plotted o page. II. escribig No-Newtoia Lamiar Flow i Horizotal Cylidrical Pipes A. escribig the Wall Shear Stress all fluids). As i Class 6, we ca begi with the Equatio of Motio to derive " rz = P P ) + gsi + r 4) L *. For horizotal pipes " rz = r P P L = r. At the wall " w = dp 4 which has a egative value, because it acts i the z directio) B. Velocity Profile ad Flowrate. For lamiar flow, we could itroduce the rheological equatio ito The Equatio of Motio or ito Equatio 5) above) ad itegrate to get v z r). Example: For a Power-Law fluid, Çegel s covetio for shear stress gives " rz = K dv z dr dp = K " dv z ) dr Combiig with Equatio 5), itegratig, ad applyig the o-slip coditio gives v z = "dp + + K + " r 7) The volumetric flow rate becomes Q = "dp ) 4K 8 +) 5) 6) 8)

4 Chemical Egieerig 74 - Class 5 page 4 Ad, fially see the Appedices to these otes), + +)! = ad " = ) +) 9). For other types of o-newtoia fluids, the math ofte becomes very complex. C. How ca we apply these cocepts to typical pipeflow data -dp/ vs. v avg )? A Geeral Approach, Usig Newtoia Fluids i Lamiar Flow as a Model. The velocity profile for a Newtoia fluid is " v z = v max r " = v avg r ). So the shear rate is. At the wall " = dv z dr = v avg r! w = 4v avg = 8v avg = 4v avgr ) 4. For a Newtoia fluid, a short-had way to write Newto s Law is! w = µ " w ) 5. But so plottig τ w vs. 8v avg " w = 4 dp gives a straight lie of slope = µ from Equatio 6)! w = 8v avg from Equatio ) So plottig dp 4 vs 8v avg for various diameters gives a straight lie of slope = µ 6. No-Newtoia fluids ca be plotted o that same plot gives a geeralized way of represetig all fluids i lamiar flow). ad Bigham ) 4 )!dp Pseudoplastic Newtoia ilatat 8v avg

5 Chemical Egieerig 74 - Class 5 page 5. How do we desig flow systems for a Power-Law fluid i lamiar flow?. From Equatio 8, Solvig for pressure drop: "dp V = "dp ) 4K 8 +) = V 8 +) ) 4K * " P " P L But the mechaical eergy equatio uses P/ρ, so P " P P = " P ) L L = " + V 8 +)., - * /. Fially, from the mechaical eergy equatio for a horizotal pipe, 4KL P " P = " w f. So for lamiar pipe flow of a power-law fluid, w f = V 8 +) " 4KL ) which ca be used with the mechaical eergy equatio for ay applicable pipig system.

6 Chemical Egieerig 74 - Class 5 page 6 Appedix β for a Power-Law Fluid i Lamiar Pipe Flow Q = v da = " dp ) ** see Equatio 8 of these otes) 4K + // where v da = // ) + + * + "dp K = " dp ) K + ) + * + " r + + r,.. r dr d -. + r dr ) + + " r ) r dr = + " + r + + r + ) r dr which, after some math, gives So v "" da = dp * K ) = + r " + = 4+ = 4+ = " 4 dp ) 4K * +) ) + r ) 4 + ) 4+ +) + +) + + r4+ ) 4 + ) ) see Equatio 7 of these otes) 4 + = 4+ " v 4 dp ) + da Fially, " = A [ v da] = 4K * + dp ) 6 + 4K * + ) +) ) = + +

7 Chemical Egieerig 74 - Class 5 page 7 Appedix α for a Power-Law Fluid i Lamiar Pipe Flow Q = v da = " dp ) ** see Equatio 8 of these otes) 4K + // where v da = // ) + + * + "dp K = " dp ) K + ) + + " r +,.. r dr d -. + r r dr ) + * see Equatio 7 of these otes) + + " r ) r dr = + " + r r + " r + ) r dr which, after some math, gives So v "" da = dp * K ) = + r " + r+ + = 5+ " 5+ + = 5+ " + + = 5+ = " 5 dp ) 4K * +) r " " ) +) 4 + ) 5 + ) 5+ +) ) +) 4 + ) 5 + ) ) ) 5 + ) 5 + " r5+ Fially, " = A v 5 dp ) + da [ v da] = 4 4K * + dp ) 9 + 4K * + ) +) 5 + ) ) = +) +) 5 + )

8 Chemical Egieerig 74 - Class 6 page I. More O No-Newtoia Lamiar Flow i Horizotal Cylidrical Pipes A. etermiig Values of the heological Parameters. We ca measure flow rate ad pressure drop through a pipelie... So how do we determie the values of rheological parameters?. We ca show appedix for these otes) that, for all o-newtoia fluids where γ w = dv z dr w γ w = ξ 4 + dlξ ) 4 dlτ w, ξ = 8v avg, ad τ w = 4 dp. Equatio, called the abiowitsch-mooey equatio, works for most timeidepedet o-newtoia fluids i lamiar flow i cylidrical pipes. a. From data of flow rate ad pressure drop, ξ ad τ w ca be calculated for each coditio data poit) b. A plot of l τ w vs. l ξ will produce d lτ w dlξ which ca be iserted ito the right-had bracket of Equatio. c. The wall shear rate ca the be determied for each data poit. d. Equatio suggests that d l τ w d l ξ provides importat iformatio. 4. The values of rheologic parameters ca also be foud from plots ivolvig τ w ad ξ. a. For Newtoia fluids, d l τ w d l ξ =. i) Why is this so? Hit: How does τ w deped o ξ? To fid out... How does τ w deped o γ? How does γ deped o ξ? γ w = dv z dr = 8v avg = ξ Now, you fiish the story.) ii) So, what kid of plot of the data would tell us µ?

9 Chemical Egieerig 74 - Class 6 page b. For Power-Law fluids, dlτ w dlξ = i) Why is this so? Hit: How does τ w deped o ξ? To fid out... How does τ w deped o γ? How does γ deped o ξ? τ w = K dv z = K γ w dr w τ γ w = w K = dp 4K V = dp π π 4K = γ 8 +) w 8 +) 8 + γ w = ) V 4V = 8 + = 8v avg π π 4 Now, you fiish the story.) = ξ 4 ii) So, what kid of plot of the data would tell us? iii) Would all data sets all pipe diameters, etc.) give the same value of? iv) Oce we kow the value of, ca we determie the value of K? How? v) What are the uits of K?

10 Chemical Egieerig 74 - Class 6 page c. For other No-Newtoias fluids, d lτ w may be a simple fuctio, ad we may be dlξ able to do the same kid of aalysis to determie values of rheologic parameters. B. Whe oes Flow Become No-Lamiar?. For Newtoia fluids: whe eyolds Number vρ/µ) > ~. But, for o-newtoia fluids, there is o µ.. For horizotal, cylidrical pipes, earragig 4. For Power-Law Fluids f = 4 ΔP ρ = f L v ΔP L 8 ρv = τ w ) 8 ρv ) a. By defiitio τ w = K γ w ) = K 8v avg + K 8v avg approximate derivatio) 4) 4 b. We ca substitute ito Equatio to obtai f K 8v 8 ρv 5) c. Fially, if we assume that for lamiar flow, f 64/e from Newtoia fluid) e K 8v 64 8 ρv ρv K8 6) d. It turs out that whe this Geeralized eyolds umber for Power-Law Fluids) exceeds ~, the flow of Power-Law fluids departs from lamiar behavior. dp 4 Lamiar egio 8v avg Turbulet egio l dp 4 Lamiar egio l 8v avg Turbulet egio e. Cautio: The locatio of the turbulet break-off poit i the above graph varies with pipe diameter. 5. For other kids of fluids, Equatios 4-6 ca be re-derived for the particular fluid i questio, resultig i a special formulatio of the eyolds umber for that fluid.

11 Chemical Egieerig 74 - Class 6 page 4 II. escribig No-Newtoia Turbulet Flow i Horizotal Cylidrical Pipes A. Empirical Frictio-Factor Charts Are Used The followig gives f Faig = f arcy /4 for Power-Law Fluids. From N. de Nevers, Fluid Mechaics, Addiso Wesley, 97.).5. Newtoia =.4 =.6 =.8 =. =.5 =.6 = eyolds umber as defied by Equatio 6 B. The solid lies i the above graph are for slurries ad some polymer solutios. From the data of odge ad Metzer, AIChE J. 5:89, 959.) C. The dotted lies are for some polymer solutios ad polymer melts, particularly those which show viscoelastic behavior like rubber cemet), which suppress turbulece From the data of Shaver ad Merrill, AIChE J. 5:8, 959.). With these fluids, much less turbulece is see, ad frictio is reduced.. Apparetly, the log molecules of these fluids absorb eergy ad damp out turbulet fluctuatios.. Tiy amouts as little as. wt) of such polymers i water reduce frictio Such pressure-loss-reductio additives are commoly used i the idustry e.g. the petroleum idustry).. The frictio factor from the above graph is used i a similar way as for Newtoia fluid w f = 4f L/ v /, used i the mechaical eergy equatio as always).

12 Chemical Egieerig 74 - Class 6 page 5 Appedix - erivatio of the abiowitsch-mooey Equatio. From the defiitio of the volumetric flow rate. But x dy = xy y dx V = π v r dθ dr = π v r dr A), ad if we let dy = r dr so y = r ), the V = π vr r= r= r= r dv r= r= = π r dv A) r=. We ca write this as V dv = π r dr = π r dr γ dr A) 4. From the last class, τ rz = r dp ad τ w = dp 4 so r = τ ad dr = dτ A4) τ w τ w 5. Substitutig ito Equatio A, V = π τ w γ τ dτ A5) 8τ w 6. Clearig the pre-itegral fractio o the right side τ w γ τ dτ = 8 V π τ w = 8v avg 4 τ w = 4 ξτ A6) w where we have defied ξ 8v avg b 7. Notig that d F x)dx = d [ Fb) Fa) ] a = F b) db F a) da, we take the derivatives of both sides of equatio A6) to obtai 4 ξτ w dτ w ) + 4 τ w dξ = γ w τ w dτ w 8. Fially, rearragig or where γ w = dv z dr w γ w = ξ dξ ξ τ w dτ w γ w = ξ 4 + dlξ 4 dlτ w, ξ = 8v avg, ad τ w = 4 dp A7) A8) A9)

Chemical Engineering 374

Chemical Engineering 374 Chemical Egieerig 374 Fluid Mechaics NoNewtoia Fluids Outlie 2 Types ad properties of o-newtoia Fluids Pipe flows for o-newtoia fluids Velocity profile / flow rate Pressure op Frictio factor Pump power

More information

The Generalized Newtonian Fluid - Isothermal Flows Constitutive Equations! Viscosity Models! Solution of Flow Problems!

The Generalized Newtonian Fluid - Isothermal Flows Constitutive Equations! Viscosity Models! Solution of Flow Problems! The Geeralized Newtoia Fluid - Isothermal Flows Costitutive Equatios! Viscosity Models! Solutio of Flow Problems! 0.53/2.34! Sprig 204! MIT! Cambridge, MA 0239! Geeralized Newtoia Fluid Simple Shear Flow

More information

Chapter 10: Power Series

Chapter 10: Power Series Chapter : Power Series 57 Chapter Overview: Power Series The reaso series are part of a Calculus course is that there are fuctios which caot be itegrated. All power series, though, ca be itegrated because

More information

On the Blasius correlation for friction factors

On the Blasius correlation for friction factors O the Blasius correlatio for frictio factors Trih, Khah Tuoc Istitute of Food Nutritio ad Huma Health Massey Uiversity, New Zealad K.T.Trih@massey.ac.z Abstract The Blasius empirical correlatio for turbulet

More information

CHAPTER 10 INFINITE SEQUENCES AND SERIES

CHAPTER 10 INFINITE SEQUENCES AND SERIES CHAPTER 10 INFINITE SEQUENCES AND SERIES 10.1 Sequeces 10.2 Ifiite Series 10.3 The Itegral Tests 10.4 Compariso Tests 10.5 The Ratio ad Root Tests 10.6 Alteratig Series: Absolute ad Coditioal Covergece

More information

Mechatronics. Time Response & Frequency Response 2 nd -Order Dynamic System 2-Pole, Low-Pass, Active Filter

Mechatronics. Time Response & Frequency Response 2 nd -Order Dynamic System 2-Pole, Low-Pass, Active Filter Time Respose & Frequecy Respose d -Order Dyamic System -Pole, Low-Pass, Active Filter R 4 R 7 C 5 e i R 1 C R 3 - + R 6 - + e out Assigmet: Perform a Complete Dyamic System Ivestigatio of the Two-Pole,

More information

MATH 1080: Calculus of One Variable II Fall 2017 Textbook: Single Variable Calculus: Early Transcendentals, 7e, by James Stewart.

MATH 1080: Calculus of One Variable II Fall 2017 Textbook: Single Variable Calculus: Early Transcendentals, 7e, by James Stewart. MATH 1080: Calculus of Oe Variable II Fall 2017 Textbook: Sigle Variable Calculus: Early Trascedetals, 7e, by James Stewart Uit 3 Skill Set Importat: Studets should expect test questios that require a

More information

Fluid Physics 8.292J/12.330J % (1)

Fluid Physics 8.292J/12.330J % (1) Fluid Physics 89J/133J Problem Set 5 Solutios 1 Cosider the flow of a Euler fluid i the x directio give by for y > d U = U y 1 d for y d U + y 1 d for y < This flow does ot vary i x or i z Determie the

More information

FINALTERM EXAMINATION Fall 9 Calculus & Aalytical Geometry-I Questio No: ( Mars: ) - Please choose oe Let f ( x) is a fuctio such that as x approaches a real umber a, either from left or right-had-side,

More information

Math 105: Review for Final Exam, Part II - SOLUTIONS

Math 105: Review for Final Exam, Part II - SOLUTIONS Math 5: Review for Fial Exam, Part II - SOLUTIONS. Cosider the fuctio f(x) = x 3 lx o the iterval [/e, e ]. (a) Fid the x- ad y-coordiates of ay ad all local extrema ad classify each as a local maximum

More information

Castiel, Supernatural, Season 6, Episode 18

Castiel, Supernatural, Season 6, Episode 18 13 Differetial Equatios the aswer to your questio ca best be epressed as a series of partial differetial equatios... Castiel, Superatural, Seaso 6, Episode 18 A differetial equatio is a mathematical equatio

More information

Linear Regression Demystified

Linear Regression Demystified Liear Regressio Demystified Liear regressio is a importat subject i statistics. I elemetary statistics courses, formulae related to liear regressio are ofte stated without derivatio. This ote iteds to

More information

CM3110 Transport Processes and Unit Operations I

CM3110 Transport Processes and Unit Operations I Lecture 0 F. Morriso CM30 9/8/06 CM30 Trasport Processes ad Uit Operatios I Fluid Mechaics No Newtoia fluids A Itroductio The Weisseberg effect is whe a viscoelastic, o Newtoia fluid will climb a rotatig

More information

Z - Transform. It offers the techniques for digital filter design and frequency analysis of digital signals.

Z - Transform. It offers the techniques for digital filter design and frequency analysis of digital signals. Z - Trasform The -trasform is a very importat tool i describig ad aalyig digital systems. It offers the techiques for digital filter desig ad frequecy aalysis of digital sigals. Defiitio of -trasform:

More information

MATH 31B: MIDTERM 2 REVIEW

MATH 31B: MIDTERM 2 REVIEW MATH 3B: MIDTERM REVIEW JOE HUGHES. Evaluate x (x ) (x 3).. Partial Fractios Solutio: The umerator has degree less tha the deomiator, so we ca use partial fractios. Write x (x ) (x 3) = A x + A (x ) +

More information

6.3 Testing Series With Positive Terms

6.3 Testing Series With Positive Terms 6.3. TESTING SERIES WITH POSITIVE TERMS 307 6.3 Testig Series With Positive Terms 6.3. Review of what is kow up to ow I theory, testig a series a i for covergece amouts to fidig the i= sequece of partial

More information

Name: Math 10550, Final Exam: December 15, 2007

Name: Math 10550, Final Exam: December 15, 2007 Math 55, Fial Exam: December 5, 7 Name: Be sure that you have all pages of the test. No calculators are to be used. The exam lasts for two hours. Whe told to begi, remove this aswer sheet ad keep it uder

More information

UNIFORM FLOW. U x. U t

UNIFORM FLOW. U x. U t UNIFORM FLOW if : 1) there are o appreciable variatios i the chael geometry (width, slope, roughess/grai size), for a certai legth of a river reach ) flow discharge does ot vary the, UNIFORM FLOW coditios

More information

SNAP Centre Workshop. Basic Algebraic Manipulation

SNAP Centre Workshop. Basic Algebraic Manipulation SNAP Cetre Workshop Basic Algebraic Maipulatio 8 Simplifyig Algebraic Expressios Whe a expressio is writte i the most compact maer possible, it is cosidered to be simplified. Not Simplified: x(x + 4x)

More information

3.2 Properties of Division 3.3 Zeros of Polynomials 3.4 Complex and Rational Zeros of Polynomials

3.2 Properties of Division 3.3 Zeros of Polynomials 3.4 Complex and Rational Zeros of Polynomials Math 60 www.timetodare.com 3. Properties of Divisio 3.3 Zeros of Polyomials 3.4 Complex ad Ratioal Zeros of Polyomials I these sectios we will study polyomials algebraically. Most of our work will be cocered

More information

1 Cabin. Professor: What is. Student: ln Cabin oh Log Cabin! Professor: No. Log Cabin + C = A Houseboat!

1 Cabin. Professor: What is. Student: ln Cabin oh Log Cabin! Professor: No. Log Cabin + C = A Houseboat! MATH 4 Sprig 0 Exam # Tuesday March st Sectios: Sectios 6.-6.6; 6.8; 7.-7.4 Name: Score: = 00 Istructios:. You will have a total of hour ad 50 miutes to complete this exam.. A No-Graphig Calculator may

More information

1 1 2 = show that: over variables x and y. [2 marks] Write down necessary conditions involving first and second-order partial derivatives for ( x0, y

1 1 2 = show that: over variables x and y. [2 marks] Write down necessary conditions involving first and second-order partial derivatives for ( x0, y Questio (a) A square matrix A= A is called positive defiite if the quadratic form waw > 0 for every o-zero vector w [Note: Here (.) deotes the traspose of a matrix or a vector]. Let 0 A = 0 = show that:

More information

A.1 Algebra Review: Polynomials/Rationals. Definitions:

A.1 Algebra Review: Polynomials/Rationals. Definitions: MATH 040 Notes: Uit 0 Page 1 A.1 Algera Review: Polyomials/Ratioals Defiitios: A polyomial is a sum of polyomial terms. Polyomial terms are epressios formed y products of costats ad variales with whole

More information

The z-transform. 7.1 Introduction. 7.2 The z-transform Derivation of the z-transform: x[n] = z n LTI system, h[n] z = re j

The z-transform. 7.1 Introduction. 7.2 The z-transform Derivation of the z-transform: x[n] = z n LTI system, h[n] z = re j The -Trasform 7. Itroductio Geeralie the complex siusoidal represetatio offered by DTFT to a represetatio of complex expoetial sigals. Obtai more geeral characteristics for discrete-time LTI systems. 7.

More information

Chapter 4. Fourier Series

Chapter 4. Fourier Series Chapter 4. Fourier Series At this poit we are ready to ow cosider the caoical equatios. Cosider, for eample the heat equatio u t = u, < (4.) subject to u(, ) = si, u(, t) = u(, t) =. (4.) Here,

More information

Most text will write ordinary derivatives using either Leibniz notation 2 3. y + 5y= e and y y. xx tt t

Most text will write ordinary derivatives using either Leibniz notation 2 3. y + 5y= e and y y. xx tt t Itroductio to Differetial Equatios Defiitios ad Termiolog Differetial Equatio: A equatio cotaiig the derivatives of oe or more depedet variables, with respect to oe or more idepedet variables, is said

More information

EE / EEE SAMPLE STUDY MATERIAL. GATE, IES & PSUs Signal System. Electrical Engineering. Postal Correspondence Course

EE / EEE SAMPLE STUDY MATERIAL. GATE, IES & PSUs Signal System. Electrical Engineering. Postal Correspondence Course Sigal-EE Postal Correspodece Course 1 SAMPLE STUDY MATERIAL Electrical Egieerig EE / EEE Postal Correspodece Course GATE, IES & PSUs Sigal System Sigal-EE Postal Correspodece Course CONTENTS 1. SIGNAL

More information

Appendix: The Laplace Transform

Appendix: The Laplace Transform Appedix: The Laplace Trasform The Laplace trasform is a powerful method that ca be used to solve differetial equatio, ad other mathematical problems. Its stregth lies i the fact that it allows the trasformatio

More information

HOMEWORK #10 SOLUTIONS

HOMEWORK #10 SOLUTIONS Math 33 - Aalysis I Sprig 29 HOMEWORK # SOLUTIONS () Prove that the fuctio f(x) = x 3 is (Riema) itegrable o [, ] ad show that x 3 dx = 4. (Without usig formulae for itegratio that you leart i previous

More information

Newtonian fluid. r L

Newtonian fluid. r L Newtoia fluid dy dv 1 4 ) ( R r L P R r v ) ( ( 1) rl P P r ) ( rl r x P = L Pr rl ) r ( P = 0 4 8LV PR Defiitio of a Newtoia Fluid F A yx du dy yx For Newtoia behaviour (1) is proportioal to ad a plot

More information

MATH 2411 Spring 2011 Practice Exam #1 Tuesday, March 1 st Sections: Sections ; 6.8; Instructions:

MATH 2411 Spring 2011 Practice Exam #1 Tuesday, March 1 st Sections: Sections ; 6.8; Instructions: MATH 411 Sprig 011 Practice Exam #1 Tuesday, March 1 st Sectios: Sectios 6.1-6.6; 6.8; 7.1-7.4 Name: Score: = 100 Istructios: 1. You will have a total of 1 hour ad 50 miutes to complete this exam.. A No-Graphig

More information

Optimally Sparse SVMs

Optimally Sparse SVMs A. Proof of Lemma 3. We here prove a lower boud o the umber of support vectors to achieve geeralizatio bouds of the form which we cosider. Importatly, this result holds ot oly for liear classifiers, but

More information

September 2012 C1 Note. C1 Notes (Edexcel) Copyright - For AS, A2 notes and IGCSE / GCSE worksheets 1

September 2012 C1 Note. C1 Notes (Edexcel) Copyright   - For AS, A2 notes and IGCSE / GCSE worksheets 1 September 0 s (Edecel) Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets September 0 Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets September 0 Copyright

More information

CHAPTER 8 SYSTEMS OF PARTICLES

CHAPTER 8 SYSTEMS OF PARTICLES CHAPTER 8 SYSTES OF PARTICLES CHAPTER 8 COLLISIONS 45 8. CENTER OF ASS The ceter of mass of a system of particles or a rigid body is the poit at which all of the mass are cosidered to be cocetrated there

More information

Lesson 10: Limits and Continuity

Lesson 10: Limits and Continuity www.scimsacademy.com Lesso 10: Limits ad Cotiuity SCIMS Academy 1 Limit of a fuctio The cocept of limit of a fuctio is cetral to all other cocepts i calculus (like cotiuity, derivative, defiite itegrals

More information

MATH 10550, EXAM 3 SOLUTIONS

MATH 10550, EXAM 3 SOLUTIONS MATH 155, EXAM 3 SOLUTIONS 1. I fidig a approximate solutio to the equatio x 3 +x 4 = usig Newto s method with iitial approximatio x 1 = 1, what is x? Solutio. Recall that x +1 = x f(x ) f (x ). Hece,

More information

(3) If you replace row i of A by its sum with a multiple of another row, then the determinant is unchanged! Expand across the i th row:

(3) If you replace row i of A by its sum with a multiple of another row, then the determinant is unchanged! Expand across the i th row: Math 50-004 Tue Feb 4 Cotiue with sectio 36 Determiats The effective way to compute determiats for larger-sized matrices without lots of zeroes is to ot use the defiitio, but rather to use the followig

More information

EDEXCEL NATIONAL CERTIFICATE UNIT 4 MATHEMATICS FOR TECHNICIANS OUTCOME 4 - CALCULUS

EDEXCEL NATIONAL CERTIFICATE UNIT 4 MATHEMATICS FOR TECHNICIANS OUTCOME 4 - CALCULUS EDEXCEL NATIONAL CERTIFICATE UNIT 4 MATHEMATICS FOR TECHNICIANS OUTCOME 4 - CALCULUS TUTORIAL 1 - DIFFERENTIATION Use the elemetary rules of calculus arithmetic to solve problems that ivolve differetiatio

More information

Problem Cosider the curve give parametrically as x = si t ad y = + cos t for» t» ß: (a) Describe the path this traverses: Where does it start (whe t =

Problem Cosider the curve give parametrically as x = si t ad y = + cos t for» t» ß: (a) Describe the path this traverses: Where does it start (whe t = Mathematics Summer Wilso Fial Exam August 8, ANSWERS Problem 1 (a) Fid the solutio to y +x y = e x x that satisfies y() = 5 : This is already i the form we used for a first order liear differetial equatio,

More information

TEACHER CERTIFICATION STUDY GUIDE

TEACHER CERTIFICATION STUDY GUIDE COMPETENCY 1. ALGEBRA SKILL 1.1 1.1a. ALGEBRAIC STRUCTURES Kow why the real ad complex umbers are each a field, ad that particular rigs are ot fields (e.g., itegers, polyomial rigs, matrix rigs) Algebra

More information

Time-Domain Representations of LTI Systems

Time-Domain Representations of LTI Systems 2.1 Itroductio Objectives: 1. Impulse resposes of LTI systems 2. Liear costat-coefficiets differetial or differece equatios of LTI systems 3. Bloc diagram represetatios of LTI systems 4. State-variable

More information

EXPERIMENT OF SIMPLE VIBRATION

EXPERIMENT OF SIMPLE VIBRATION EXPERIMENT OF SIMPLE VIBRATION. PURPOSE The purpose of the experimet is to show free vibratio ad damped vibratio o a system havig oe degree of freedom ad to ivestigate the relatioship betwee the basic

More information

Zeros of Polynomials

Zeros of Polynomials Math 160 www.timetodare.com 4.5 4.6 Zeros of Polyomials I these sectios we will study polyomials algebraically. Most of our work will be cocered with fidig the solutios of polyomial equatios of ay degree

More information

MATH301 Real Analysis (2008 Fall) Tutorial Note #7. k=1 f k (x) converges pointwise to S(x) on E if and

MATH301 Real Analysis (2008 Fall) Tutorial Note #7. k=1 f k (x) converges pointwise to S(x) on E if and MATH01 Real Aalysis (2008 Fall) Tutorial Note #7 Sequece ad Series of fuctio 1: Poitwise Covergece ad Uiform Covergece Part I: Poitwise Covergece Defiitio of poitwise covergece: A sequece of fuctios f

More information

A NOTE ON THE TOTAL LEAST SQUARES FIT TO COPLANAR POINTS

A NOTE ON THE TOTAL LEAST SQUARES FIT TO COPLANAR POINTS A NOTE ON THE TOTAL LEAST SQUARES FIT TO COPLANAR POINTS STEVEN L. LEE Abstract. The Total Least Squares (TLS) fit to the poits (x,y ), =1,,, miimizes the sum of the squares of the perpedicular distaces

More information

MATH 112: HOMEWORK 6 SOLUTIONS. Problem 1: Rudin, Chapter 3, Problem s k < s k < 2 + s k+1

MATH 112: HOMEWORK 6 SOLUTIONS. Problem 1: Rudin, Chapter 3, Problem s k < s k < 2 + s k+1 MATH 2: HOMEWORK 6 SOLUTIONS CA PRO JIRADILOK Problem. If s = 2, ad Problem : Rudi, Chapter 3, Problem 3. s + = 2 + s ( =, 2, 3,... ), prove that {s } coverges, ad that s < 2 for =, 2, 3,.... Proof. The

More information

NICK DUFRESNE. 1 1 p(x). To determine some formulas for the generating function of the Schröder numbers, r(x) = a(x) =

NICK DUFRESNE. 1 1 p(x). To determine some formulas for the generating function of the Schröder numbers, r(x) = a(x) = AN INTRODUCTION TO SCHRÖDER AND UNKNOWN NUMBERS NICK DUFRESNE Abstract. I this article we will itroduce two types of lattice paths, Schröder paths ad Ukow paths. We will examie differet properties of each,

More information

Sigma notation. 2.1 Introduction

Sigma notation. 2.1 Introduction Sigma otatio. Itroductio We use sigma otatio to idicate the summatio process whe we have several (or ifiitely may) terms to add up. You may have see sigma otatio i earlier courses. It is used to idicate

More information

ANALYSIS OF EXPERIMENTAL ERRORS

ANALYSIS OF EXPERIMENTAL ERRORS ANALYSIS OF EXPERIMENTAL ERRORS All physical measuremets ecoutered i the verificatio of physics theories ad cocepts are subject to ucertaities that deped o the measurig istrumets used ad the coditios uder

More information

An Introduction to Randomized Algorithms

An Introduction to Randomized Algorithms A Itroductio to Radomized Algorithms The focus of this lecture is to study a radomized algorithm for quick sort, aalyze it usig probabilistic recurrece relatios, ad also provide more geeral tools for aalysis

More information

BHW #13 1/ Cooper. ENGR 323 Probabilistic Analysis Beautiful Homework # 13

BHW #13 1/ Cooper. ENGR 323 Probabilistic Analysis Beautiful Homework # 13 BHW # /5 ENGR Probabilistic Aalysis Beautiful Homework # Three differet roads feed ito a particular freeway etrace. Suppose that durig a fixed time period, the umber of cars comig from each road oto the

More information

MIDTERM 3 CALCULUS 2. Monday, December 3, :15 PM to 6:45 PM. Name PRACTICE EXAM SOLUTIONS

MIDTERM 3 CALCULUS 2. Monday, December 3, :15 PM to 6:45 PM. Name PRACTICE EXAM SOLUTIONS MIDTERM 3 CALCULUS MATH 300 FALL 08 Moday, December 3, 08 5:5 PM to 6:45 PM Name PRACTICE EXAM S Please aswer all of the questios, ad show your work. You must explai your aswers to get credit. You will

More information

Problem 1. Problem Engineering Dynamics Problem Set 9--Solution. Find the equation of motion for the system shown with respect to:

Problem 1. Problem Engineering Dynamics Problem Set 9--Solution. Find the equation of motion for the system shown with respect to: 2.003 Egieerig Dyamics Problem Set 9--Solutio Problem 1 Fid the equatio of motio for the system show with respect to: a) Zero sprig force positio. Draw the appropriate free body diagram. b) Static equilibrium

More information

Boundary Element Method (BEM)

Boundary Element Method (BEM) Boudary Elemet Method BEM Zora Ilievski Wedesday 8 th Jue 006 HG 6.96 TU/e Talk Overview The idea of BEM ad its advatages The D potetial problem Numerical implemetatio Idea of BEM 3 Idea of BEM 4 Advatages

More information

Math 312 Lecture Notes One Dimensional Maps

Math 312 Lecture Notes One Dimensional Maps Math 312 Lecture Notes Oe Dimesioal Maps Warre Weckesser Departmet of Mathematics Colgate Uiversity 21-23 February 25 A Example We begi with the simplest model of populatio growth. Suppose, for example,

More information

Math 113 Exam 3 Practice

Math 113 Exam 3 Practice Math Exam Practice Exam 4 will cover.-., 0. ad 0.. Note that eve though. was tested i exam, questios from that sectios may also be o this exam. For practice problems o., refer to the last review. This

More information

Solutions to quizzes Math Spring 2007

Solutions to quizzes Math Spring 2007 to quizzes Math 4- Sprig 7 Name: Sectio:. Quiz a) x + x dx b) l x dx a) x + dx x x / + x / dx (/3)x 3/ + x / + c. b) Set u l x, dv dx. The du /x ad v x. By Itegratio by Parts, x(/x)dx x l x x + c. l x

More information

Lecture 7: Density Estimation: k-nearest Neighbor and Basis Approach

Lecture 7: Density Estimation: k-nearest Neighbor and Basis Approach STAT 425: Itroductio to Noparametric Statistics Witer 28 Lecture 7: Desity Estimatio: k-nearest Neighbor ad Basis Approach Istructor: Ye-Chi Che Referece: Sectio 8.4 of All of Noparametric Statistics.

More information

CALCULUS BASIC SUMMER REVIEW

CALCULUS BASIC SUMMER REVIEW CALCULUS BASIC SUMMER REVIEW NAME rise y y y Slope of a o vertical lie: m ru Poit Slope Equatio: y y m( ) The slope is m ad a poit o your lie is, ). ( y Slope-Itercept Equatio: y m b slope= m y-itercept=

More information

Signals & Systems Chapter3

Signals & Systems Chapter3 Sigals & Systems Chapter3 1.2 Discrete-Time (D-T) Sigals Electroic systems do most of the processig of a sigal usig a computer. A computer ca t directly process a C-T sigal but istead eeds a stream of

More information

The Pendulum. Purpose

The Pendulum. Purpose The Pedulum Purpose To carry out a example illustratig how physics approaches ad solves problems. The example used here is to explore the differet factors that determie the period of motio of a pedulum.

More information

Alternating Series. 1 n 0 2 n n THEOREM 9.14 Alternating Series Test Let a n > 0. The alternating series. 1 n a n.

Alternating Series. 1 n 0 2 n n THEOREM 9.14 Alternating Series Test Let a n > 0. The alternating series. 1 n a n. 0_0905.qxd //0 :7 PM Page SECTION 9.5 Alteratig Series Sectio 9.5 Alteratig Series Use the Alteratig Series Test to determie whether a ifiite series coverges. Use the Alteratig Series Remaider to approximate

More information

Similarity Solutions to Unsteady Pseudoplastic. Flow Near a Moving Wall

Similarity Solutions to Unsteady Pseudoplastic. Flow Near a Moving Wall Iteratioal Mathematical Forum, Vol. 9, 04, o. 3, 465-475 HIKARI Ltd, www.m-hikari.com http://dx.doi.org/0.988/imf.04.48 Similarity Solutios to Usteady Pseudoplastic Flow Near a Movig Wall W. Robi Egieerig

More information

11 Correlation and Regression

11 Correlation and Regression 11 Correlatio Regressio 11.1 Multivariate Data Ofte we look at data where several variables are recorded for the same idividuals or samplig uits. For example, at a coastal weather statio, we might record

More information

REGRESSION (Physics 1210 Notes, Partial Modified Appendix A)

REGRESSION (Physics 1210 Notes, Partial Modified Appendix A) REGRESSION (Physics 0 Notes, Partial Modified Appedix A) HOW TO PERFORM A LINEAR REGRESSION Cosider the followig data poits ad their graph (Table I ad Figure ): X Y 0 3 5 3 7 4 9 5 Table : Example Data

More information

a is some real number (called the coefficient) other

a is some real number (called the coefficient) other Precalculus Notes for Sectio.1 Liear/Quadratic Fuctios ad Modelig http://www.schooltube.com/video/77e0a939a3344194bb4f Defiitios: A moomial is a term of the form tha zero ad is a oegative iteger. a where

More information

ChE 471 Lecture 10 Fall 2005 SAFE OPERATION OF TUBULAR (PFR) ADIABATIC REACTORS

ChE 471 Lecture 10 Fall 2005 SAFE OPERATION OF TUBULAR (PFR) ADIABATIC REACTORS SAFE OPERATION OF TUBULAR (PFR) ADIABATIC REACTORS I a exothermic reactio the temperature will cotiue to rise as oe moves alog a plug flow reactor util all of the limitig reactat is exhausted. Schematically

More information

Chapter 2 The Solution of Numerical Algebraic and Transcendental Equations

Chapter 2 The Solution of Numerical Algebraic and Transcendental Equations Chapter The Solutio of Numerical Algebraic ad Trascedetal Equatios Itroductio I this chapter we shall discuss some umerical methods for solvig algebraic ad trascedetal equatios. The equatio f( is said

More information

Math 113 Exam 3 Practice

Math 113 Exam 3 Practice Math Exam Practice Exam will cover.-.9. This sheet has three sectios. The first sectio will remid you about techiques ad formulas that you should kow. The secod gives a umber of practice questios for you

More information

Theorem: Let A n n. In this case that A does reduce to I, we search for A 1 as the solution matrix X to the matrix equation A X = I i.e.

Theorem: Let A n n. In this case that A does reduce to I, we search for A 1 as the solution matrix X to the matrix equation A X = I i.e. Theorem: Let A be a square matrix The A has a iverse matrix if ad oly if its reduced row echelo form is the idetity I this case the algorithm illustrated o the previous page will always yield the iverse

More information

Ma 530 Introduction to Power Series

Ma 530 Introduction to Power Series Ma 530 Itroductio to Power Series Please ote that there is material o power series at Visual Calculus. Some of this material was used as part of the presetatio of the topics that follow. What is a Power

More information

2.4 - Sequences and Series

2.4 - Sequences and Series 2.4 - Sequeces ad Series Sequeces A sequece is a ordered list of elemets. Defiitio 1 A sequece is a fuctio from a subset of the set of itegers (usually either the set 80, 1, 2, 3,... < or the set 81, 2,

More information

62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 +

62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 + 62. Power series Defiitio 16. (Power series) Give a sequece {c }, the series c x = c 0 + c 1 x + c 2 x 2 + c 3 x 3 + is called a power series i the variable x. The umbers c are called the coefficiets of

More information

Boundary layer problem on conveyor belt. Gabriella Bognár University of Miskolc 3515 Miskolc-Egyetemváros, Hungary

Boundary layer problem on conveyor belt. Gabriella Bognár University of Miskolc 3515 Miskolc-Egyetemváros, Hungary Boudary layer problem o coveyor belt Gabriella Bogár Uiversity of Miskolc 355 Miskolc-Egyetemváros, Hugary e-mail: matvbg@ui-miskolc.hu Abstract: A techologically importat source of the boudary layer pheomeo

More information

2C09 Design for seismic and climate changes

2C09 Design for seismic and climate changes 2C09 Desig for seismic ad climate chages Lecture 02: Dyamic respose of sigle-degree-of-freedom systems I Daiel Grecea, Politehica Uiversity of Timisoara 10/03/2014 Europea Erasmus Mudus Master Course Sustaiable

More information

*X203/701* X203/701. APPLIED MATHEMATICS ADVANCED HIGHER Numerical Analysis. Read carefully

*X203/701* X203/701. APPLIED MATHEMATICS ADVANCED HIGHER Numerical Analysis. Read carefully X0/70 NATIONAL QUALIFICATIONS 006 MONDAY, MAY.00 PM.00 PM APPLIED MATHEMATICS ADVANCED HIGHER Numerical Aalysis Read carefully. Calculators may be used i this paper.. Cadidates should aswer all questios.

More information

NUMERICAL METHODS FOR SOLVING EQUATIONS

NUMERICAL METHODS FOR SOLVING EQUATIONS Mathematics Revisio Guides Numerical Methods for Solvig Equatios Page 1 of 11 M.K. HOME TUITION Mathematics Revisio Guides Level: GCSE Higher Tier NUMERICAL METHODS FOR SOLVING EQUATIONS Versio:. Date:

More information

The Riemann Zeta Function

The Riemann Zeta Function Physics 6A Witer 6 The Riema Zeta Fuctio I this ote, I will sketch some of the mai properties of the Riema zeta fuctio, ζ(x). For x >, we defie ζ(x) =, x >. () x = For x, this sum diverges. However, we

More information

Polynomial Functions and Their Graphs

Polynomial Functions and Their Graphs Polyomial Fuctios ad Their Graphs I this sectio we begi the study of fuctios defied by polyomial expressios. Polyomial ad ratioal fuctios are the most commo fuctios used to model data, ad are used extesively

More information

In algebra one spends much time finding common denominators and thus simplifying rational expressions. For example:

In algebra one spends much time finding common denominators and thus simplifying rational expressions. For example: 74 The Method of Partial Fractios I algebra oe speds much time fidig commo deomiators ad thus simplifyig ratioal epressios For eample: + + + 6 5 + = + = = + + + + + ( )( ) 5 It may the seem odd to be watig

More information

Chapter 5 Vibrational Motion

Chapter 5 Vibrational Motion Fall 4 Chapter 5 Vibratioal Motio... 65 Potetial Eergy Surfaces, Rotatios ad Vibratios... 65 Harmoic Oscillator... 67 Geeral Solutio for H.O.: Operator Techique... 68 Vibratioal Selectio Rules... 7 Polyatomic

More information

Now we are looking to find a volume of solid S that lies below a surface z = f(x,y) and R= ab, cd,,[a,b] is the interval over

Now we are looking to find a volume of solid S that lies below a surface z = f(x,y) and R= ab, cd,,[a,b] is the interval over Multiple Itegratio Double Itegrals, Volume, ad Iterated Itegrals I sigle variable calculus we looked to fid the area uder a curve f(x) bouded by the x- axis over some iterval usig summatios the that led

More information

SOLUTIONS TO EXAM 3. Solution: Note that this defines two convergent geometric series with respective radii r 1 = 2/5 < 1 and r 2 = 1/5 < 1.

SOLUTIONS TO EXAM 3. Solution: Note that this defines two convergent geometric series with respective radii r 1 = 2/5 < 1 and r 2 = 1/5 < 1. SOLUTIONS TO EXAM 3 Problem Fid the sum of the followig series 2 + ( ) 5 5 2 5 3 25 2 2 This series diverges Solutio: Note that this defies two coverget geometric series with respective radii r 2/5 < ad

More information

Chemical Engineering 374

Chemical Engineering 374 Chemical Egieerig 374 Fluid Mechaics NoNeoia Fluids Oulie 2 Types ad properies of o-neoia Fluids Pipe flos for o-neoia fluids Velociy profile / flo rae Pressure op Fricio facor Pump poer Rheological Parameers

More information

Math 116 Second Midterm November 13, 2017

Math 116 Second Midterm November 13, 2017 Math 6 Secod Midterm November 3, 7 EXAM SOLUTIONS. Do ot ope this exam util you are told to do so.. Do ot write your ame aywhere o this exam. 3. This exam has pages icludig this cover. There are problems.

More information

MATH2007* Partial Answers to Review Exercises Fall 2004

MATH2007* Partial Answers to Review Exercises Fall 2004 MATH27* Partial Aswers to Review Eercises Fall 24 Evaluate each of the followig itegrals:. Let u cos. The du si ad Hece si ( cos 2 )(si ) (u 2 ) du. si u 2 cos 7 u 7 du Please fiish this. 2. We use itegratio

More information

We will conclude the chapter with the study a few methods and techniques which are useful

We will conclude the chapter with the study a few methods and techniques which are useful Chapter : Coordiate geometry: I this chapter we will lear about the mai priciples of graphig i a dimesioal (D) Cartesia system of coordiates. We will focus o drawig lies ad the characteristics of the graphs

More information

Let us give one more example of MLE. Example 3. The uniform distribution U[0, θ] on the interval [0, θ] has p.d.f.

Let us give one more example of MLE. Example 3. The uniform distribution U[0, θ] on the interval [0, θ] has p.d.f. Lecture 5 Let us give oe more example of MLE. Example 3. The uiform distributio U[0, ] o the iterval [0, ] has p.d.f. { 1 f(x =, 0 x, 0, otherwise The likelihood fuctio ϕ( = f(x i = 1 I(X 1,..., X [0,

More information

Honors Calculus Homework 13 Solutions, due 12/8/5

Honors Calculus Homework 13 Solutions, due 12/8/5 Hoors Calculus Homework Solutios, due /8/5 Questio Let a regio R i the plae be bouded by the curves y = 5 ad = 5y y. Sketch the regio R. The two curves meet where both equatios hold at oce, so where: y

More information

Physics 116A Solutions to Homework Set #1 Winter Boas, problem Use equation 1.8 to find a fraction describing

Physics 116A Solutions to Homework Set #1 Winter Boas, problem Use equation 1.8 to find a fraction describing Physics 6A Solutios to Homework Set # Witer 0. Boas, problem. 8 Use equatio.8 to fid a fractio describig 0.694444444... Start with the formula S = a, ad otice that we ca remove ay umber of r fiite decimals

More information

Section A assesses the Units Numerical Analysis 1 and 2 Section B assesses the Unit Mathematics for Applied Mathematics

Section A assesses the Units Numerical Analysis 1 and 2 Section B assesses the Unit Mathematics for Applied Mathematics X0/70 NATIONAL QUALIFICATIONS 005 MONDAY, MAY.00 PM 4.00 PM APPLIED MATHEMATICS ADVANCED HIGHER Numerical Aalysis Read carefully. Calculators may be used i this paper.. Cadidates should aswer all questios.

More information

The picture in figure 1.1 helps us to see that the area represents the distance traveled. Figure 1: Area represents distance travelled

The picture in figure 1.1 helps us to see that the area represents the distance traveled. Figure 1: Area represents distance travelled 1 Lecture : Area Area ad distace traveled Approximatig area by rectagles Summatio The area uder a parabola 1.1 Area ad distace Suppose we have the followig iformatio about the velocity of a particle, how

More information

ECE-S352 Introduction to Digital Signal Processing Lecture 3A Direct Solution of Difference Equations

ECE-S352 Introduction to Digital Signal Processing Lecture 3A Direct Solution of Difference Equations ECE-S352 Itroductio to Digital Sigal Processig Lecture 3A Direct Solutio of Differece Equatios Discrete Time Systems Described by Differece Equatios Uit impulse (sample) respose h() of a DT system allows

More information

Precalculus MATH Sections 3.1, 3.2, 3.3. Exponential, Logistic and Logarithmic Functions

Precalculus MATH Sections 3.1, 3.2, 3.3. Exponential, Logistic and Logarithmic Functions Precalculus MATH 2412 Sectios 3.1, 3.2, 3.3 Epoetial, Logistic ad Logarithmic Fuctios Epoetial fuctios are used i umerous applicatios coverig may fields of study. They are probably the most importat group

More information

Chapter 6 Overview: Sequences and Numerical Series. For the purposes of AP, this topic is broken into four basic subtopics:

Chapter 6 Overview: Sequences and Numerical Series. For the purposes of AP, this topic is broken into four basic subtopics: Chapter 6 Overview: Sequeces ad Numerical Series I most texts, the topic of sequeces ad series appears, at first, to be a side topic. There are almost o derivatives or itegrals (which is what most studets

More information

U8L1: Sec Equations of Lines in R 2

U8L1: Sec Equations of Lines in R 2 MCVU U8L: Sec. 8.9. Equatios of Lies i R Review of Equatios of a Straight Lie (-D) Cosider the lie passig through A (-,) with slope, as show i the diagram below. I poit slope form, the equatio of the lie

More information

Properties and Tests of Zeros of Polynomial Functions

Properties and Tests of Zeros of Polynomial Functions Properties ad Tests of Zeros of Polyomial Fuctios The Remaider ad Factor Theorems: Sythetic divisio ca be used to fid the values of polyomials i a sometimes easier way tha substitutio. This is show by

More information

Math 12 Final Exam, May 11, 2011 ANSWER KEY. 2sinh(2x) = lim. 1 x. lim e. x ln. = e. (x+1)(1) x(1) (x+1) 2. (2secθ) 5 2sec2 θ dθ.

Math 12 Final Exam, May 11, 2011 ANSWER KEY. 2sinh(2x) = lim. 1 x. lim e. x ln. = e. (x+1)(1) x(1) (x+1) 2. (2secθ) 5 2sec2 θ dθ. Math Fial Exam, May, ANSWER KEY. [5 Poits] Evaluate each of the followig its. Please justify your aswers. Be clear if the it equals a value, + or, or Does Not Exist. coshx) a) L H x x+l x) sihx) x x L

More information

MATH 129 FINAL EXAM REVIEW PACKET (Revised Spring 2008)

MATH 129 FINAL EXAM REVIEW PACKET (Revised Spring 2008) MATH 9 FINAL EXAM REVIEW PACKET (Revised Sprig 8) The followig questios ca be used as a review for Math 9. These questios are ot actual samples of questios that will appear o the fial exam, but they will

More information

Chapter 7: Numerical Series

Chapter 7: Numerical Series Chapter 7: Numerical Series Chapter 7 Overview: Sequeces ad Numerical Series I most texts, the topic of sequeces ad series appears, at first, to be a side topic. There are almost o derivatives or itegrals

More information