EEN-E3003, Industrial drying and evaporation processes Equations, Mollier diagram, Thermodynamic properites of humid air, h,s diagram of water
|
|
- Carmel Washington
- 5 years ago
- Views:
Transcription
1 EEN-E3003, Industrial drying and evaporation processes Equations, Mollier diagra, Therodynaic properites of huid air, h,s diagra of water Therodynaics of huid air Air huidity [kg/kg da ] v x =, (1) da Total pressure [Pa] v = ass of water vapor [kg] da = ass of dry air [kg] ptot = pda + pv, (2) pda = partial pressure of dry air [Pa] pv = vapor pressure [Pa] The dependence beween the air huidity and partial vapor pressure p p - p v x = 0.622, (3) tot v pv = vapor pressure [Pa] ptot = total pressure [Pa] Figure is the ratio of olar asses of water vapor and dry air (Mw/Mda = 0.018/0.0289) An approxiation equation for vapor pressure [Pa] 11,78 (T - 372,79) v ' = p exp( ), (4) T - 43,15 p 0 T = teperature [K] p0 = 10 5 Pa
2 Relative huidity pv(t) j =, (5) p '(T) v pv (T) = vapor pressure at the teperature of T [Pa] pv (T) = saturated vapor pressure at the teperature of T [Pa] Enthalpy of huid air [kj/kg da ] h = hda + xhv, (6) hda = enthalpy of dry air [kj/kgda] x = air huidity [kg/kgda] hv = enthalpy of vapor [kj/kg] The enthalpy of huid air when average specific heat capacities are used [kj/kg da ] h = cpdat + x(cpvt ), (7) cpda = specific heat capacity of dry air [kj/(kg o C)] t = teperature [ o C] x = air huidity [kg/kgda] cpv = specific heat capacity of water vapor [kj/(kg o C)] An approxiation equation for vaporization heat of water [J/kg] lv = t (8) lv = vaporization heat [J/kg] t = teperature [ o C]
3 Definitions of oisture and dry solids contents Moisture content, wet basis w = w + w ds, (9) w = oisture content on wet basis [kg/kgtot] w = ass of water [kg] ds = ass of dry solids [kg] Moisture content, dry basis u = w, (10) ds u = oisture content on dry basis [kg/kgds] w = ass of water [kg] ds = ass of dry solids [kg] Dry solids content C + ds =, (11) ds w C = dry solids content [kgka/kgtot] w = ass of water [kg] ds = ass of dry solids [kg] The dependence between oisture contents calcualted on dry and wet basis u w = 1+ u (12) w u = 1- w. (13) u = oisture content, dry basis [kg/kgds] w = oisture content, wet basis [kg/kgtot]
4 Diffusion Diffusion flux of a coponent A [ol/( 2 s)] j A ca = -DAB, (14) Z DAB = diffusion coefficient [ 2 /s] ca = concentration of a coponent A [ol/ 3 ] Z = distance [] Net flux of a coponent A [ol/( 2 s)] J A ca = vc A - DAB, (15) Z v = average speed of particles [/s] DAB = diffusion coefficient/diffusivity [ 2 /s] ca = concentration of a coponent A [ol/ 3 ] Z = distance [] Fuller odel for diffusion coefficient [ 2 /s] D AB 1,75 T (1/M + 1/M ) = , (16) p[(σv + Σv A 1/3 A) 1/2 B 1/3 2 B) ] T = teperature [K] MA = olar ass of a coponent A [kg/ol] MB = olar ass of a coponent B [kg/ol] p = total pressure [Pa] SnA = atoic diffusion volue of water vapor = 12.7 SnB = atoic diffusion volue of dry air = 20.1 The effective diffusivity of water vapor D eff in a porous aterial [ 2 /s] D F =, (17) ψ eff D AB DAB = diffusion coefficient of water vapor in the air [ 2 /s]
5 F = porosity of aterial y = tortuosity The effective diffusivity of water vapor in porous aterial when the Knudsen diffusion coefficient is considered [ 2 /s] ( D ) D + ( D ) 1 eff F = AB k, (18) Ł ψ ł DAB = diffusion coefficient of water vapor in the air [ 2 /s] F = porosity of aterial y = tortuosity Dk = the Knudsen diffusion coefficient [ 2 /s] Capillary action Capillary pressure Dp c [Pa] Capillary rise 2γ Δp C = cos q, (19) R g = water tension [N/] R = radius of pore [] q = contact angle [ o ] 2g cosq Z = rgr, (20) Z = height of the water colun [] g = surface tension [N/] R = radius of pore [] q = contact angle [ o ] g = gravitational constant [9,81/s 2 ] r = density of liquid [kg/ 3 ]
6 The influence of capillary pressure on saturated vapor pressure [Pa] p v ' v 2γvM - cosθ rrt = p e, (21) pv = saturated vapor pressure on a flat surface [Pa] g = surface tension [N/] r = radius of a pore [] q = contact angle [ o ] R = gas constant [= J/(olK)] T = teperature [K] Penetration depth of liquid in porous aterial [] z = 2R g cosθ + (p 4η s - p o )R 2 t, (22) z = penetration depth [] g = surface tension [N/] R = radius of pore [] q = contact angle [ o ] ps = pressure of liquid in porous aterial [Pa] po = pressure of gas in porous aterial [Pa] h = dynaic viscocity [kg/s] t = tie [s] Calculating drying and evaporation rates Evaporation rate of water through a boundary layer fro a water surface [kg/( 2 s)] '' p p - p o o v = M H2O k cln, (23) RT p o - p v' ( t p) = evaporation rate [kg/( 2 s)] MH2O = olar ass of water 0.018kg/ol po = total pressure [Pa] R = gas constant = J/(olK) T = teperature of the boundary layer [K] kc = ass transfer coefficient [/s] pv = vapor pressure in the surroundings [Pa] pv (tp) = vapor pressure on the surface [Pa]
7 Energy balance of a oist particle that evaporates (unifor oisture and teperature distribution inside the particle is assued) dt cp = -''lva - α(t - t 0 )A, (24) dτ = ass of the particle (dry or oist) [kg] cp = specific heat capacity of the particle per dry of oist ass [J/(kg o C)] t = teperature [ o C] t = teperature of the particle [ o C] t0 = teperature of the surroundings [ o C] t = tie [s] = evaporation rate [kg/( 2 s)] lv = vaporization heat at t [J/kg] A = evaporation surface [ 2 ] a = heat transfer coefficient [W/ 2 K] Specific heat capacity of a oist particle [J(kgK)] cp = cpds + cpwu, (25) cpds = specific heat capacity of dry solids [J/(kg o C)] cpw = cpecific heat capacity of water [J/(kg o C)] u = oisture content on dry basis [kg/kgds] The analogy between heat and ass transfer k c α ρc 1-n = Le, (26) p kc = ass transfer coefficient [/s] a = heat transfer coefficient [W/( 2 K)] Le = Lewisi Nuebr = Pr/Sc rcp = rdacpda + rvcpv [J/( 3o C)], where rda = density of dry air at the teperature of boundary layer [kg/ 3 ] cpda = specific heat capacity of dry air at the teperature of boundary layer [J/(kg o C)] rv = density of vapor at the teperature of boundary layer [kg/ 3 ] cpv = specific heat capacity of vapor at the teperature of boundary layer [J/(kg o C)]
8 Diensioless nubers (drying/evaporation) Nusselt nuber : Reynolds nuber Prandtl nuber Sherwood nuber Schidt nuber a Nu = L l vl Re = ν (27a) (27b) μc p Pr = (27c) λ k cl Sh = D AB D AB (27d) n Sc = (27e) Lewis nuber Le = Pr/Sc, (27f) a = heat transfer coefficient [W/( 2 K)] L = characteristic length [] l = heat conductivity of vapor + dry air ixture in the boundary layer [W/] n = kineatic viscosity of vapor + dry air ixture in the boundary layer [ 2 /s] = dynaic viscosity of vapor + dry air ixture in the boundary layer [kg/s] cp = specific heat capacity of vapor + dry air ixture [kj/kg o C] DAB = diffusion coefficient of vapor + dry air ixture in the boundary layer [ 2 /s] kc = ass transfer coefficient [/s] Drying rate in the periof constant drying rate [kg/s] ev ( t o - t ) l ( t ) & = Aα, (28) v & ev = evaporation rate [kg/s] A = evaporation surface [ 2 ] a = heat transfer coefficient [W/( 2 K)] to = teperature of the surroundings (usually the air) [ o C] t = teperature of the particle [ o C] lv(t) = vaporization heat at the teperature of the particle [ o C]
9 Evaporation rate in the period of constant drying rate, when the state of drying gas changes [kg/s] v α ( t o1 - t )- ( t o2 - t ) ( t ) ( t o1 - t ) ln ( t - t ) & ev = A, (29) l o2 & ev = evaporation rate [kg/s] A = evaporation surface [ 2 ] a = heat transfer coefficient [W/( 2 K)] to1 = teperature of the drying gas at inlet [ o C] ti2 = teperature of the drying gas at outlet [ o C] t = teperature of the aterial/particles [ o C] lv(t) = vaporization heat at the teperature of the aterial/particles [ o C] Darcy s law [kg/( 2 s)] K p '' = -, (30) ν z = flux/ass flow rate of the fluid [kg/( 2 s)] K = pereability [ 2 ] u = kineatic viscosity [ 2 /s] p = pressure [Pa] z = distance [] Characteristic drying curve Drying tie for a plate when the charqacteristic drying curve is used [s] ut u cr Zρ dsu cr d(u/ucr ) τ = -, (31a) 2'' f(u/u ) o uo u cr cr t = drying tie [s] L = thickness of the plate [] rds = density of dry solids [kgds/ 3 ] ucr = critical oisture content [kg/kgds] o = evaporation rate in the period of constant drying rate [kg/ 2 s] uo = oisture content in the beginning of drying [kg/kgds] ut = oisture content in the end of drying [kg/kgds]
10 f(u/ucr) = characteristic drying curve Drying tie calculated using the characteristic drying curve when the drying rate in the period of constant drying is reported per ass of the particle/bed [s] u τ = - ut ucr cr ' o uo ucr d(u/u f(u/u cr cr ) ) (31b) t = drying tie [s] ucr = critical oisture content [kg/kgds] o = drying rate in the period of constant drying per ass of the particle/bed [kgh2o/(kgdss)] ut = oisture content in the end of drying [kg/kgds] f(u/ucr) = characteristic drying curve Drying tie calculated using the characteristic drying curve when the drying rate in the period of constant drying is reported per volue of the particle/bed [s] ρdsu τ = - ''' o cr ut u cr uo u cr d(u/u f(u/u cr cr ) ) (31c) t = drying tie [s] rka = density of dry solids of the particle/bed [kgds/ 3 ] ucr = kriittinen kosteussuhde [kg/kgka] ''' o = drying rate in the period of constant drying per volue of the particle/bed [kgh2o/(kgdss)] ut = oisture content in the end of drying [kg/kgds] f(u/ucr) = characteristic drying curve
11 Energy and ass balance of a dryer Mass balance over the drying chaber, when drying gas is air/other gas & ds (uin uout) = & da (xout xin), (32) & & ds da = ass flow rate of dry solids [kgds/s] = ass flow rate of dry air (drying gas) [kgda/s] uin = initial oisture content of the aterial [kg/kgds] uout = final oisture content of the aterial [kg/kgds] x out = absolute huidity of air (drying gas) after the drying chaber [kg/kg da] x in = absolute huidity of air (drying gas) after the drying chaber [kg/kg da] Energy balance over the drying chaber, when drying gas is air/other gas & ki (hin-hout) + & ds ( iin iout) + F + P - Q = 0, (33) & & ds da = ass flow rate of dry solids [kgds/s] = ass flow rate of dry air (drying gas) [kgda/s] hin = enthalpy of drying air/gas before the drying chaber [kj/kgda] hout = enthalpy of drying air/gas after the drying chaber [kj/kgda] iin = enthalpy of aterial before the drying chaber [kj/kgds] iout = enthalpy of aterial after the drying chaber [kj/kgds] F = excess heat into the drying chaber [kw] P = echanical work input into teh drying chaber [kw] Q = heat losses of the drying chaber [kw] Enthalpy of huid air in the energy balance [kj/kg da ] h = cpdat + x(cpvt ), (34) cpda = specific heat capacity of dry air [kj/(kg o C)] t = air teperature [ o C] x = absolute huidity of air [kg/kgda] cpv = specific heat capacity of vapor [kj/(kg o C)]
12 Entahlpy of oist aterial in the energy balance [kj/kg ds ] i = cpdst + ucpwt (35) cpds = specific heat capacity of dry solids [kj/kg o C] cpw = specific heat capacity of liquid water [kj/kg o C] u = oisture content of aterial [kg/kgds] t = teperature of the aterial [ o C] Eelctricity consuption of a fan Dp P = V & (36) h h s V & = Volue flow rate of drying gas just before the fan [ 3 /s] Dp = pressure difference over the fan [Pa] h = echanical efficiency of the fan [-] hs = isentropic efficiency of the fan [-] When superheated stea is used as a drying gas, enthalpy values for stae/condensate/water are taken fro stea tables. The enthalpy of aterial is calculated using Eg, (35) Desing of a dryer Length of the dryer for a continuous belt dryer & dsτ L = ρ ZW ds (37) L = lengthg of the dryer [] & ds = ass flow rate of dry solids [kgds/s ] t = residence tie of aterial in the dryer [s] Z = bed height [] W = width of the conveyor []
13 Drying of wood-based bioass Lower heating value (LHV) of oist bioass/fuel per vet basis [MJ/kg tot ] qwet,w = qi(1- w) 2.443w (38) qwet,w = LHV of oist bioass [MJ/kgtot] qi = LHV of copletely dry bioass/fuel [MJ/kgds] w = oisture content of bioass [% wb] Lower heating value (LHV) of oist bioass/fuel per dry basis [MJ/kg ds ] Fuel input [W] qwet,u = qi 2.443u (39) qwet,u= LHV of oist bioass/fuel [MJ/kgds] qi = LHV of copletely dry bioass/fuel [MJ/kgds] u = oisture content of bioass/fuel [% db] Φ fuel = & q (40) fuel fuel & fuel = ass flow rate of fuel [kgtot/s or kgds/s] qfuel = LHV of fuel [J/kgtot or J/kgds] Boiler efficiency Q Φ η - in loss b = = 1 (41) Φ fuel Φ fuel Qin = heat input fro the boiler into the cycle process [W] Ffuel = fuel input [W] Floss = heat losses fro the boiler into the surroundings [W]
14 Power-to-heat ratio of a CHP plant P a = Q (42) P = electricity production [W] Q = heat production [W] Efficiency of a CHP plant η CHP P + Q = (43) Φ fuel Ffuel = fuel input [W] P = electricity production [W] Q = heat production [W] Efficiency of a cycle process in a condensing power plant P Q t out h th = = 1-, (44) Qin Q in Pt = shaft power of a turbine [W] Qin = heat input fro the boiler into the cycle process [W] Qout = heat output fro the cycle process into the surroundings [W] Efficiency of a condensing power plant P η e = (45) Φ fuel P = electricity production after the generator [W] Fpa = fuel input [W]
15 The change of boiler losses as a result of drying when the outlet teperature of flue gases, the excess air factor and other heat losses reain the sae as in the case of oist bioass/fuel [W] loss2 loss1 fuel ( u 2 u 1 ) h fg Φ - Φ = & - (46) Floss2 = boiler losses for dry fuel [W] Floss1 = boiler losses for oist fuel [W] & fuel = ass flow rate of dry bioass/fuel [kgds/s] u2 = oisture content after drying [% d.b.] u1 = oisture content before drying [% w.b.] hsk = the outgoing enthalpy of flue gases [J/kg] Consuption of arginal fuel in a condensing power plant that cobusts bioass [W] P & & - q bio bio ar = (47) η thηbηgq ar q ar & ar = ass flow rate of arginal fuel [kg/s] hth = efficiency of cycle process [-] hb = boiler efficiency hg = efficiency of the generator qar = LHV of arginal fuel [J/kg] & = ass flow rate of bioass (oist or dry) [kg/s] bio qbio = LHV of bioass per kilogra of oist or dry fuel [MJ/kg] Consuption of arginal fuel in a CHP plant that cobusts bioass [W] Q + αq & & - q heat heat bio bio ar = (48) ηchpq ar q ar & ar = ass flow rate of bioass [kg/s] Qheat = heat production [W] a = power-to-heat ratio hchp = efficiency of the CHP plant (see Eq. (43)) & bio = ass flow rate of bioass (oist or dry) [kg/s] qbio = LHV of bioass per kilogra of oist or dry fuel [J/kg] qar = LHV of arginal fuel [J/kg]
16 Evaporators Dry solids content C = ds ds + w (49) ds = ass of dry solids in solution [kg] w = ass of water [kg] Mass flow rate of water evaporated in an evaporator [kg/s] & w = & feed C 1- Ł C 1 2 ł (50) & feed = ass flow rate of feed (incoing solution) [kg/s] C1 = dry solids content of feed [kgds/kgtot] C2 = dry solids content of concentrate [kgka/kgtot] Heat transfer rate through the evaporation surface [W] F = kadt (51) k = heat transfer coefficient [W/( 2 K)] A = heat transfer/evaporation surface [ 2 ] Dt = teperature difference between the heat source and solution [ o C] Heat transfer coefficient k for a plate [W/( 2 K)] 1 k = 1 α + s λ + δ λ s d α 2 (52) k = heat transfer coefficient [W/( 2 K)] a1 = convective heat transfer coefficient on the solution side [W/( 2 K)] a2 = convective heat transfer coefficient on side of heat source [W/( 2 K)] s = wall thickness [] ls = heat conductivity of the wall [W/(K)]
17 d = thickness of fouling layer [] l d = heat conductivity of the fouling layer [W/(K)] Electricity deand of a copressor [W] P = & Δh η (53a) Δh η is Δh =, (53b) is & = ass flow rate of gas through the copressor [kg/s] Dh = real enthalpy change of the gas over the copressor [J/kg] Dhis = change of enthalpy in isentropic copression [J/kg] his = isentropic efficiency h = echanical efficiency Enthalpies of water/stea/condensate fro the stea table can be used when energy balances are ade for evaporators if anything else is not entioned. The dependence between teperature and pressure for an ideal gas in an isentropic copression T 2 Ł T 1 = ł Ł p p 2 1 ł R Mcp (54) T2 = teperature after copression [K] T1 = teperature before copression [K] p2 = pressure after copression [Pa] p1 = pressure before copression [Pa] R = gas constant [8.314 J/(olK)] M = olar ass of gas [kg/ol] cp = average heat capacity of the gas over the copression process [J/kgK]
18 Boiling point elevation [ o C,K] Derived based on the equilibriu theory 2 RT ΔT = - (55) l v K ( T ) lna K DT = boiling poiont elevation [K] R = gas consatnt [8.314 J/(olK)] TK = boiling point of a pure water [K] lv = waporization heat of water at TK [J/ol] a = activity of water in solution Activity when aounts of substances of species are used n a = γ n w tot (56) g = activity coefficient [-] nw = ole aount of water in solution [ol] ntot = ole aount of the whole solution [ol] An experietal equation ΔTBPE = Kb * i * (57) Kb = constant [J/K] i = van t Hoff coefficient = olality [ol/kg] NPSH-value (Net Positive Suction Head) [] NPSH = Hstat + pi / (ρ g) ploss/ (ρ g) pn /(ρ g) (58) Hstat = static suction height [] pi = absolute pressure in a suction tank [Pa] Hpipe = pressure loss in a suction pipeline [] pn = vapor pressure at puping teperature [Pa] ρ = density of liquid [kg/ 3 ] g = gravity = /s 2 Hstat has a negative sign if the pup is above the water surface and a positive sign if it is situated below the water surface.
19 Average velocity of substance in a pipe [/s] v = 4V& 2 pd (59) V & = volue flow rate [ 3 /s] D = diaeter of a pipe [] Mass flow rate of leaking air & leaking Dp = V Dτ (60) Dp/Dt = pressure increase in a vessel with vacuu [bar/in] V = volue of the vessel [ 3 ] Other equations the ideal gas equation of state Consentration PV = nrt (61) p = pressure [Pa] V = volue [ 3 ] n = aount of substance [ol] R = gas constant [8.314 J/olK] T = teperature [K] c = n V (62) n = aount of substance [ol] V = volue [ 3 ] Molality n M = (63) n = aount of substance [ol] = ass [kg]
20 Diagras and tables on next pages
21 Mollier diagra of huid air
22 Kostean ilan terodynaaiset oinaisuudet
23
24 Specific heat capacities of dry air and vapor as function of teperature T [K] t [ C] c p,dry air [kj/kg C] c p, vapor [kj/kg C]
25
26
27
28
29
2002 University of Porto, Faculty of Engineering (FEUP)
Holberg H, Ahtila P. Drying phenoenon in a fixed bed under the bio fuel ulti stage drying. In: Oliveira A, Afonso C, Riffat S, editors. Proceedings of the st International Conference on Sustainable Energy
More informationI. Concepts and Definitions. I. Concepts and Definitions
F. Properties of a syste (we use the to calculate changes in energy) 1. A property is a characteristic of a syste that can be given a nuerical value without considering the history of the syste. Exaples
More informationDaniel López Gaxiola 1 Student View Jason M. Keith
Suppleental Material for Transport Process and Separation Process Principles Chapter Principles of Moentu Transfer and Overall Balances In fuel cells, the fuel is usually in gas or liquid phase. Thus,
More informationME 300 Thermodynamics II Exam 2 November 13, :00 p.m. 9:00 p.m.
ME 300 Therodynaics II Exa 2 Noveber 3, 202 8:00 p.. 9:00 p.. Nae: Solution Section (Circle One): Sojka Naik :30 a.. :30 p.. Instructions: This is a closed book/notes exa. You ay use a calculator. You
More informationFORMULA SHEET. General formulas:
FORMULA SHEET You may use this formula sheet during the Advanced Transport Phenomena course and it should contain all formulas you need during this course. Note that the weeks are numbered from 1.1 to
More informationTankExampleNov2016. Table of contents. Layout
Table of contents Task... 2 Calculation of heat loss of storage tanks... 3 Properties ambient air Properties of air... 7 Heat transfer outside, roof Heat transfer in flow past a plane wall... 8 Properties
More informationSustainable Power Generation Applied Heat and Power Technology. Equations, diagrams and tables
Sustainable Power Generation Applied Heat and Power Technology Equations, diagrams and tables 1 STEAM CYCLE Enthalpy of liquid water h = c p,liquid (T T ref ) T ref = 273 K (normal conditions). The specific
More informationDepartment of Mechanical Engineering ME 322 Mechanical Engineering Thermodynamics. Ideal Gas Mixtures II. Lecture 32
Departent of Mechanical Engineering ME 322 Mechanical Engineering Therodnaics Ideal Gas Mixtures II Lecture 32 The Gibbs Phase Rule The nuber of independent, intensive properties required to fix the state
More informationAnswers to assigned problems from Chapter 1
Answers to assigned probles fro Chapter 1 1.7. a. A colun of ercury 1 in cross-sectional area and 0.001 in height has a volue of 0.001 and a ass of 0.001 1 595.1 kg. Then 1 Hg 0.001 1 595.1 kg 9.806 65
More informationI affirm that I have never given nor received aid on this examination. I understand that cheating in the exam will result in a grade F for the class.
Che340 hysical Cheistry for Biocheists Exa 3 Apr 5, 0 Your Nae _ I affir that I have never given nor received aid on this exaination. I understand that cheating in the exa will result in a grade F for
More informationMAE 110A. Homework 6: Solutions 11/9/2017
MAE 110A Hoework 6: Solutions 11/9/2017 H6.1: Two kg of H2O contained in a piston-cylinder assebly, initially at 1.0 bar and 140 C undergoes an internally ersible, isotheral copression to 25 bar. Given
More informationln P 1 saturation = T ln P 2 saturation = T
More Tutorial at www.littledubdoctor.co Physical Cheistry Answer each question in the space provided; use back of page if extra space is needed. Answer questions so the grader can READILY understand your
More informationMolecular Speeds. Real Gasses. Ideal Gas Law. Reasonable. Why the breakdown? P-V Diagram. Using moles. Using molecules
Kinetic Theory of Gases Connect icroscopic properties (kinetic energy and oentu) of olecules to acroscopic state properties of a gas (teperature and pressure). P v v 3 3 3 But K v and P kt K v kt Teperature
More informationAll Excuses must be taken to 233 Loomis before 4:15, Monday, April 30.
Miscellaneous Notes he end is near don t get behind. All Excuses ust be taken to 233 Loois before 4:15, Monday, April 30. he PHYS 213 final exa ties are * 8-10 AM, Monday, May 7 * 8-10 AM, uesday, May
More informationHumidity parameters. Saturation (equilibrium) vapor pressure Condensation balances evaporation
uidity paraeters Saturation (equilibriu) vapor pressure Condensation balances evaporation Miing ratio & specific huidity Mass ratio of water vapor and air and water content and wet air. Dew point & frost
More informationTWO-DIMENSIONAL MATHEMATICAL MODEL FOR SIMULATION OF THE DRYING PROCESS OF THICK LAYERS OF NATURAL MATERIALS IN A CONVEYOR-BELT DRYER
THERMAL SCIENCE: Year 2017, Vol. 21, No. 3, pp. 1369-1378 1369 TWO-DIMENSIONAL MATHEMATICAL MODEL FOR SIMULATION OF THE DRYING PROCESS OF THICK LAYERS OF NATURAL MATERIALS IN A CONVEYOR-BELT DRYER by Duško
More informationModeling and Control of a Fluidised Bed Dryer
Modeling and Control of a Fluidised Bed Dryer J.A Villegas S.R. Duncan H.G. Wang W.Q. Yang R.S. Raghavan Department of Engineering Science, University of Oxford, Parks Road, Oxford OX 3PJ, UK, e-mail:
More informationWTS Table of contents. Layout
Table of contents Thermal and hydraulic design of shell and tube heat exchangers... 2 Tube sheet data... 4 Properties of Water and Steam... 6 Properties of Water and Steam... 7 Heat transfer in pipe flow...
More informationME 331 Homework Assignment #6
ME 33 Homework Assignment #6 Problem Statement: ater at 30 o C flows through a long.85 cm diameter tube at a mass flow rate of 0.020 kg/s. Find: The mean velocity (u m ), maximum velocity (u MAX ), and
More informationLevel 7 Post Graduate Diploma in Engineering Heat and mass transfer
9210-221 Level 7 Post Graduate Diploma in Engineering Heat and mass transfer 0 You should have the following for this examination one answer book non programmable calculator pen, pencil, drawing instruments
More informationConvective Mass Transfer
Convective Mass Transfer Definition of convective mass transfer: The transport of material between a boundary surface and a moving fluid or between two immiscible moving fluids separated by a mobile interface
More informationHeat processes. Heat exchange
Heat processes Heat exchange Heat energy transported across a surface from higher temperature side to lower temperature side; it is a macroscopic measure of transported energies of molecular motions Temperature
More informationQ1. For a given medium, the wavelength of a wave is:
Phys10 First Major-091 Zero Version Coordinator: M Sunday, Noveber 15, 009 Page: 1 Q1. For a given ediu, the wavelength of a wave is: A) inversely proportional to the frequency B) independent of the frequency
More informationTransport processes. 7. Semester Chemical Engineering Civil Engineering
Transport processes 7. Semester Chemical Engineering Civil Engineering 1 Course plan 1. Elementary Fluid Dynamics 2. Fluid Kinematics 3. Finite Control Volume nalysis 4. Differential nalysis of Fluid Flow
More informationTheory. Humidity h of an air-vapor mixture is defined as the mass ratio of water vapor and dry air,
Theory Background In a cooling tower with open water circulation, heat is removed from water because of the material and heat exchange between the water and the ambient air. The cooling tower is a special
More information1.1 Heat and Mass transfer in daily life and process/mechanical engineering Heat transfer in daily life: Heating Cooling Cooking
1. Introduction 1.1 Heat and Mass transfer in daily life and process/echanical engineering Heat transfer in daily life: Heating Cooling Cooking ransfer of heat along a teperature difference fro one syste
More information( ) = 9.03 lb m. mass of H lb m. O = lb m. = lb m. Determine density of aqueous KOH solu5on in lb m /gal. =
To detere the ass frac5ons of KOH and HO we need the ass of each coponent and the total ass of the solu5on. We are given the ass of pure KOH in 1 gallon of solu5on is 0.813 lb of KOH. We are also given
More informationPhys102 First Major-123 Zero Version Coordinator: xyz Sunday, June 30, 2013 Page: 1
Coordinator: xyz Sunday, June 30, 013 Page: 1 Q1. A string has a ass of 0.0 g and a length of 1.6. A sinusoidal wave is travelling on this string, and is given by: y (x,t) = 0.030 sin (0.30 x 80 t + 3π/)
More informationTemperature and Thermodynamics, Part II. Topics to be Covered
Teperature and Therodynaics, Part II Topics to be Covered Profiles of Teperature in the Boundary Layer Potential teperature Adiabatic Lapse Rate Theral Stratification 1/8/17 Why are We Interested in Theral
More information7.2 Sublimation. The following assumptions are made in order to solve the problem: Sublimation Over a Flat Plate in a Parallel Flow
7..1 Sublimation Over a Flat Plate in a Parallel Flow The following assumptions are made in order to solve the problem: 1.. 3. The flat plate is very thin and so the thermal resistance along the flat plate
More informationChapter 11: Heat Exchangers. Dr Ali Jawarneh Department of Mechanical Engineering Hashemite University
Chapter 11: Heat Exchangers Dr Ali Jawarneh Department of Mechanical Engineering Hashemite University Objectives When you finish studying this chapter, you should be able to: Recognize numerous types of
More informationEFFECT OF THE NON-CONDENSABLE GAS TYPE DURING CONDENSATION OF WATER VAPOR
THERMAL SCIENCE: Year 217, Vol. 21, No. 6A, pp. 2457-2468 2457 EFFECT OF THE NON-CONDENSABLE GAS TYPE DURING CONDENSATION OF WATER VAPOR by Kaoutar ZINE-DINE *, Youness EL HAMMAMI, Rachid MIR, Touria MEDIOUNI,
More informationT718. c Dr. Md. Zahurul Haq (BUET) HX: Energy Balance and LMTD ME 307 (2018) 2/ 21 T793
HX: Energy Balance and LMTD Dr. Md. Zahurul Haq Professor Department of Mechanical Engineering Bangladesh University of Engineering & Technology (BUET) Dhaka-000, Bangladesh http://zahurul.buet.ac.bd/
More informationDistillation. The Continuous Column. Learning Outcomes. Recap - VLE for Meth H 2 O. Gavin Duffy School of Electrical Engineering DIT Kevin Street
Distillation The Continuous Colun Gavin Duffy School of Electrical Engineering DIT Kevin Street Learning Outcoes After this lecture you should be able to.. Describe how continuous distillation works List
More information6. Laminar and turbulent boundary layers
6. Laminar and turbulent boundary layers John Richard Thome 8 avril 2008 John Richard Thome (LTCM - SGM - EPFL) Heat transfer - Convection 8 avril 2008 1 / 34 6.1 Some introductory ideas Figure 6.1 A boundary
More informationPhys102 First Major-143 Zero Version Coordinator: xyz Sunday, June 28, 2015 Page: 1
Coordinator: xyz Sunday, June 28, 2015 Page: 1 Q1. A transverse sinusoidal wave propagating along a stretched string is described by the following equation: y (x,t) = 0.350 sin [1.25x + 99.6t], where x
More informationChapter 5. Mass and Energy Analysis of Control Volumes
Chapter 5 Mass and Energy Analysis of Control Volumes Conservation Principles for Control volumes The conservation of mass and the conservation of energy principles for open systems (or control volumes)
More informationCircle one: School of Mechanical Engineering Purdue University ME315 Heat and Mass Transfer. Exam #2. April 3, 2014
Circle one: Div. 1 (12:30 pm, Prof. Choi) Div. 2 (9:30 am, Prof. Xu) School of Mechanical Engineering Purdue University ME315 Heat and Mass Transfer Exam #2 April 3, 2014 Instructions: Write your name
More informationPhys102 First Major-131 Zero Version Coordinator: xyz Saturday, October 26, 2013 Page: 1
Phys10 First Major-131 Zero Version Coordinator: xyz Saturday, October 6, 013 Page: 1 Q1. Under a tension τ, it takes s for a pulse to travel the length of a stretched wire. What tension is required for
More informationOutline. Definition and mechanism Theory of diffusion Molecular diffusion in gases Molecular diffusion in liquid Mass transfer
Diffusion 051333 Unit operation in gro-industry III Department of Biotechnology, Faculty of gro-industry Kasetsart University Lecturer: Kittipong Rattanaporn 1 Outline Definition and mechanism Theory of
More informationMECHANICS of FLUIDS INSTRUCTOR'S SOLUTIONS MANUAL TO ACCOMPANY FOURTH EDITION. MERLE C. POTTER Michigan State University DAVID C.
INSTRUCTOR'S SOLUTIONS MANUAL TO ACCOMPANY MECHANICS of FLUIDS FOURTH EDITION MERLE C. POTTER Michigan State University DAVID C. WIGGERT Michigan State University BASSEM RAMADAN Kettering University Contents
More informationPhys102 First Major-112 Zero Version Coordinator: Wednesday, March 07, 2012 Page: 1
Coordinator: Wednesday, March 07, 01 Page: 1 Q1. A transverse sinusoidal wave, travelling in the positive x direction along a string, has an aplitude of 0 c. The transverse position of an eleent of the
More information16.512, Rocket Propulsion Prof. Manuel Martinez-Sanchez Lecture 30: Dynamics of Turbopump Systems: The Shuttle Engine
6.5, Rocket Propulsion Prof. Manuel Martinez-Sanchez Lecture 30: Dynaics of Turbopup Systes: The Shuttle Engine Dynaics of the Space Shuttle Main Engine Oxidizer Pressurization Subsystes Selected Sub-Model
More information1. Basic state values of matter
1. Basic state values of matter Example 1.1 The pressure inside a boiler is p p = 115.10 5 Pa and p v = 9.44.10 4 Pa inside a condenser. Calculate the absolute pressure inside the boiler and condenser
More informationTHERMODYNAMICS, FLUID AND PLANT PROCESSES. The tutorials are drawn from other subjects so the solutions are identified by the appropriate tutorial.
THERMODYNAMICS, FLUID AND PLANT PROCESSES The tutorials are drawn from other subjects so the solutions are identified by the appropriate tutorial. THERMODYNAMICS TUTORIAL 2 THERMODYNAMIC PRINCIPLES SAE
More informationThe Research of Heat Transfer Area for 55/19 Steam Generator
Journal of Power and Energy Engineering, 205, 3, 47-422 Published Online April 205 in SciRes. http://www.scirp.org/journal/jpee http://dx.doi.org/0.4236/jpee.205.34056 The Research of Heat Transfer Area
More informationPotential Concept Questions
Potential Concept Questions Phase Diagrams Equations of State Reversible Processes Molecular Basis of Heat Capacity State Functions & Variables Temperature Joules Experiment for conversion of one form
More informationSolidification of Porous Material under Natural Convection by Three Phases Modeling
Solidification of Porous Material under Natural Convection by Three Phases Modeling Hassan Basirat Tabrizi, Meber, IAENG and F. Sadeghpour Abstract The perforance of natural convective flow over a rectangular
More informationFE Fluids Review March 23, 2012 Steve Burian (Civil & Environmental Engineering)
Topic: Fluid Properties 1. If 6 m 3 of oil weighs 47 kn, calculate its specific weight, density, and specific gravity. 2. 10.0 L of an incompressible liquid exert a force of 20 N at the earth s surface.
More informationQ1. The displacement of a string carrying a traveling sinusoidal wave is given by:
Coordinator: A. Mekki Saturday, Noveber, 008 Page: 1 Q1. The displaceent of a string carrying a traveling sinusoidal wave is given by: y( x, t) = y sin( kx ω t + ϕ). At tie t = 0 the point at x = 0 has
More informationThermodynamics Introduction and Basic Concepts
Thermodynamics Introduction and Basic Concepts by Asst. Prof. Channarong Asavatesanupap Mechanical Engineering Department Faculty of Engineering Thammasat University 2 What is Thermodynamics? Thermodynamics
More informationPhone: , For Educational Use. SOFTbank E-Book Center, Tehran. Fundamentals of Heat Transfer. René Reyes Mazzoco
8 Fundamentals of Heat Transfer René Reyes Mazzoco Universidad de las Américas Puebla, Cholula, Mexico 1 HEAT TRANSFER MECHANISMS 1.1 Conduction Conduction heat transfer is explained through the molecular
More informationThermodynamics I Chapter 2 Properties of Pure Substances
Thermodynamics I Chapter 2 Properties of Pure Substances Mohsin Mohd Sies Fakulti Kejuruteraan Mekanikal, Universiti Teknologi Malaysia Properties of Pure Substances (Motivation) To quantify the changes
More informationHeat Transfer Predictions for Carbon Dioxide in Boiling Through Fundamental Modelling Implementing a Combination of Nusselt Number Correlations
Heat Transfer Predictions for Carbon Dioxide in Boiling Through Fundamental Modelling Implementing a Combination of Nusselt Number Correlations L. Makaum, P.v.Z. Venter and M. van Eldik Abstract Refrigerants
More informationSummary of Dimensionless Numbers of Fluid Mechanics and Heat Transfer
1. Nusselt number Summary of Dimensionless Numbers of Fluid Mechanics and Heat Transfer Average Nusselt number: convective heat transfer Nu L = conductive heat transfer = hl where L is the characteristic
More informationOverall Heat Transfer Coefficient
Overall Heat Transfer Coefficient A heat exchanger typically involves two flowing fluids separated by a solid wall. Heat is first transferred from the hot fluid to the wall by convection, through the wall
More informationNUCLEAR THERMAL-HYDRAULIC FUNDAMENTALS
NUCLEAR THERMAL-HYDRAULIC FUNDAMENTALS Dr. J. Micael Doster Departent of Nuclear Engineering Nort Carolina State University Raleig, NC Copyrigted POER CYCLES Te analysis of Terodynaic Cycles is based alost
More informationQuestion 1. [14 Marks]
6 Question 1. [14 Marks] R r T! A string is attached to the dru (radius r) of a spool (radius R) as shown in side and end views here. (A spool is device for storing string, thread etc.) A tension T is
More informationModeling and Control of Moisture Content in a Batch Fluidized Bed Dryer Using Tomographic Sensor
28 American Control Conference Westin Seattle Hotel, Seattle, Washington, USA June 11-13, 28 ThC12.5 Modeling and Control of Moisture Content in a Batch Fluidized Bed Dryer Using Tomographic Sensor J.A
More informationModelling of the Through-air Bonding Process
Modelling of the Through-air Bonding Process M. Hossain 1, M. Acar, Ph.D. 2, W. Malalasekera 2 1 School of Engineering, The Robert Gordon University, Aberdeen, UNITED KINDOM 2 Mechanical and Manufacturing
More information(b) The heat transfer can be determined from an energy balance on the system
8-5 Heat is transferred to a iston-cylinder device wit a set of stos. e work done, te eat transfer, te exergy destroyed, and te second-law efficiency are to be deterined. Assutions e device is stationary
More informationThe First Law of Thermodynamics. By: Yidnekachew Messele
The First Law of Thermodynamics By: Yidnekachew Messele It is the law that relates the various forms of energies for system of different types. It is simply the expression of the conservation of energy
More informationME Thermodynamics I
Homework - Week 01 HW-01 (25 points) Given: 5 Schematic of the solar cell/solar panel Find: 5 Identify the system and the heat/work interactions associated with it. Show the direction of the interactions.
More informationLecture 44: Review Thermodynamics I
ME 00 Thermodynamics I Lecture 44: Review Thermodynamics I Yong Li Shanghai Jiao Tong University Institute of Refrigeration and Cryogenics 800 Dong Chuan Road Shanghai, 0040, P. R. China Email : liyo@sjtu.edu.cn
More informationfirst law of ThermodyNamics
first law of ThermodyNamics First law of thermodynamics - Principle of conservation of energy - Energy can be neither created nor destroyed Basic statement When any closed system is taken through a cycle,
More informationIf there is convective heat transfer from outer surface to fluid maintained at T W.
Heat Transfer 1. What are the different modes of heat transfer? Explain with examples. 2. State Fourier s Law of heat conduction? Write some of their applications. 3. State the effect of variation of temperature
More informationChapter 1: Basic Definitions, Terminologies and Concepts
Chapter : Basic Definitions, Terminologies and Concepts ---------------------------------------. UThermodynamics:U It is a basic science that deals with: -. Energy transformation from one form to another..
More informationCHEMICAL ENGINEERING THERMODYNAMICS. Andrew S. Rosen
CHEMICAL ENGINEERING THERMODYNAMICS Andrew S. Rosen SYMBOL DICTIONARY 1 TABLE OF CONTENTS Symbol Dictionary... 3 1. Measured Thermodynamic Properties and Other Basic Concepts... 5 1.1 Preliminary Concepts
More information2σ e s (r,t) = e s (T)exp( rr v ρ l T ) = exp( ) 2σ R v ρ l Tln(e/e s (T)) e s (f H2 O,r,T) = f H2 O
Formulas/Constants, Physics/Oceanography 4510/5510 B Atmospheric Physics II N A = 6.02 10 23 molecules/mole (Avogadro s number) 1 mb = 100 Pa 1 Pa = 1 N/m 2 Γ d = 9.8 o C/km (dry adiabatic lapse rate)
More informationChapter 4. Energy Analysis of Closed Systems
Chapter 4 Energy Analysis of Closed Systems The first law of thermodynamics is an expression of the conservation of energy principle. Energy can cross the boundaries of a closed system in the form of heat
More informationMODULE CODE: ENGG08021 INTRODUCTION TO THERMOFLUIDS. Date: 15 January 2016 Time: 10:00 12:00
School of Engineering & Computing Session 2015-16 Paisley Campus Trimester 1 MODULE CODE: ENGG08021 INTRODUCTION TO THERMOFLUIDS Date: 15 January 2016 Time: 10:00 12:00 Attempt FOUR QUESTIONS IN TOTAL
More informationTHE EFFECT OF SOLID PARTICLE SIZE UPON TIME AND SEDIMENTATION RATE
Bulletin of the Transilvania University of Braşov Series II: Forestry Wood Industry Agricultural Food Engineering Vol. 5 (54) No. 1-1 THE EFFECT OF SOLID PARTICLE SIZE UPON TIME AND SEDIMENTATION RATE
More informationEntropy and the Second Law of Thermodynamics
Entropy and the Second Law of Thermodynamics Reading Problems 7-1 7-3 7-88, 7-131, 7-135 7-6 7-10 8-24, 8-44, 8-46, 8-60, 8-73, 8-99, 8-128, 8-132, 8-1 8-10, 8-13 8-135, 8-148, 8-152, 8-166, 8-168, 8-189
More informationLectures on Applied Reactor Technology and Nuclear Power Safety. Lecture No 6
Lectures on Nuclear Power Safety Lecture No 6 Title: Introduction to Thermal-Hydraulic Analysis of Nuclear Reactor Cores Department of Energy Technology KTH Spring 2005 Slide No 1 Outline of the Lecture
More informationLAMINAR FLOW (Reynolds < 2320, parabolic velocity profile) Name symbol formula unit gravity g L L
file: Fluid Flow Calculator equations 14.pdf fro: Mark van Dijk revision: DEC 01 LAMINAR FLOW (Reynolds < 30, parabolic velocity profile) Nae sybol forula unit gravity g 9. 81 pipe length L elevation change
More informationLab 8. Lab-tray dryer
BAEN/CHEN-474 page 1 of 6 Student s Name: Factors influencing the drying rates in Objectives: 1.) To become familiar with the operation of a tray dryer 2.) To determine the psychrometric properties of
More informationAP Physics Thermodynamics Wrap-up
AP Physics herodynaics Wrap-up Here are your basic equations for therodynaics. here s a bunch of the. 3 his equation converts teperature fro Fahrenheit to Celsius. his is the rate of heat transfer for
More informationNumber of extra papers used if any
Last Nae: First Nae: Thero no. ME 00 Therodynaics 1 Fall 018 Exa 1 Circle your instructor s last nae Division 1 (7:0): Naik Division (1:0): Wassgren Division 6 (11:0): Sojka Division (9:0): Choi Division
More informationChapter 6. Using Entropy
Chapter 6 Using Entropy Learning Outcomes Demonstrate understanding of key concepts related to entropy and the second law... including entropy transfer, entropy production, and the increase in entropy
More informationNB1140: Physics 1A - Classical mechanics and Thermodynamics Problem set 2 - Forces and energy Week 2: November 2016
NB1140: Physics 1A - Classical echanics and Therodynaics Proble set 2 - Forces and energy Week 2: 21-25 Noveber 2016 Proble 1. Why force is transitted uniforly through a assless string, a assless spring,
More informationME 2322 Thermodynamics I PRE-LECTURE Lesson 23 Complete the items below Name:
Lesson 23 1. (10 pt) Write the equation for the thermal efficiency of a Carnot heat engine below: 1 L H 2. (10 pt) Can the thermal efficiency of an actual engine ever exceed that of an equivalent Carnot
More information( )( )( )( )( ) University of Washington Department of Chemistry Chemistry 452/456 Summer Quarter 2010
Hoework Assignent 4: Due at 5 p.. 7/9/ Text Probles: 6.4, 6.9, 6, 6.3 University o Washington Departent o Cheistry Cheistry 45/456 Suer Quarter P6.9) Jaes Watt once observed that a hard-working horse can
More informationSEM-2017(03HI MECHANICAL ENGINEERING. Paper II. Please read each of the following instructions carefully before attempting questions.
We RoU No. 700095 Candidate should write his/her Roll No. here. Total No. of Questions : 7 No. of Printed Pages : 7 SEM-2017(03HI MECHANICAL ENGINEERING Paper II Time ; 3 Hours ] [ Total Marks : 0 Instructions
More informationIntroduction to Heat and Mass Transfer. Week 12
Introduction to Heat and Mass Transfer Week 12 Next Topic Convective Heat Transfer» Heat and Mass Transfer Analogy» Evaporative Cooling» Types of Flows Heat and Mass Transfer Analogy Equations governing
More informationc Dr. Md. Zahurul Haq (BUET) Thermodynamic Processes & Efficiency ME 6101 (2017) 2 / 25 T145 = Q + W cv + i h 2 = h (V2 1 V 2 2)
Thermodynamic Processes & Isentropic Efficiency Dr. Md. Zahurul Haq Professor Department of Mechanical Engineering Bangladesh University of Engineering & Technology (BUET Dhaka-1000, Bangladesh zahurul@me.buet.ac.bd
More informationHeat and Mass Transfer in Tray Drying
Heat and Mass Transfer in Tray Drying Group # 11: Sami Marchand (GL), Chase Kairdolf (WR), Tiffany Robinson (OR) Instructor: Dr. Wetzel Objective: The objective of this experiment is to exhibit how accurately
More information) = slugs/ft 3. ) = lb ft/s. ) = ft/s
1. Make use of Tables 1. in the text book (See the last page in this assignent) to express the following quantities in SI units: (a) 10. in./in, (b) 4.81 slugs, (c).0 lb, (d) 7.1 ft/s, (e) 0.04 lb s/ft.
More informationDIMENSIONS AND UNITS
DIMENSIONS AND UNITS A dimension is the measure by which a physical variable is expressed quantitatively. A unit is a particular way of attaching a number to the quantitative dimension. Primary Dimension
More informationHEAT EXCHANGER. Objectives
HEAT EXCHANGER Heat exchange is an important unit operation that contributes to efficiency and safety of many processes. In this project you will evaluate performance of three different types of heat exchangers
More informationDr Ali Jawarneh. Hashemite University
Dr Ali Jawarneh Department of Mechanical Engineering Hashemite University Examine the moving boundary work or P d work commonly encountered in reciprocating devices such as automotive engines and compressors.
More informationCHEM 305 Solutions for assignment #2
CHEM 05 Solutions for assignent #. (a) Starting fro C C show that C C Substitute the result into the original expression for C C : C C (b) Using the result fro (a), evaluate C C for an ideal gas. a. Both
More informationKINETIC THEORY. Contents
KINETIC THEORY This brief paper on inetic theory deals with three topics: the hypotheses on which the theory is founded, the calculation of pressure and absolute teperature of an ideal gas and the principal
More informationBusiness. Professional application due Nov 17
Business Professional application due Nov 17 Need to estiate what elective courses you will take Mark how you fulfilled Math & Cheistry Major and Total GPA Fill out fors and spreadsheet Then eet with your
More informationAn introduction to thermodynamics applied to Organic Rankine Cycles
An introduction to thermodynamics applied to Organic Rankine Cycles By : Sylvain Quoilin PhD Student at the University of Liège November 2008 1 Definition of a few thermodynamic variables 1.1 Main thermodynamics
More informationQ1 Give answers to all of the following questions (5 marks each):
FLUID MECHANICS First Year Exam Solutions 03 Q Give answers to all of the following questions (5 marks each): (a) A cylinder of m in diameter is made with material of relative density 0.5. It is moored
More informationConsequences of Second Law of Thermodynamics. Entropy. Clausius Inequity
onsequences of Second Law of hermodynamics Dr. Md. Zahurul Haq Professor Department of Mechanical Engineering Bangladesh University of Engineering & echnology BUE Dhaka-000, Bangladesh zahurul@me.buet.ac.bd
More informationConsequences of Second Law of Thermodynamics. Entropy. Clausius Inequity
onsequences of Second Law of hermodynamics Dr. Md. Zahurul Haq Professor Department of Mechanical Engineering Bangladesh University of Engineering & echnology BUE Dhaka-000, Bangladesh zahurul@me.buet.ac.bd
More informationKinetic Molecular Theory of. IGL is a purely empirical law - solely the
Lecture -3. Kinetic Molecular Theory of Ideal Gases Last Lecture. IGL is a purely epirical law - solely the consequence of experiental obserations Explains the behaior of gases oer a liited range of conditions.
More informationExamination Heat Transfer
Examination Heat Transfer code: 4B680 date: 17 january 2006 time: 14.00-17.00 hours NOTE: There are 4 questions in total. The first one consists of independent sub-questions. If necessary, guide numbers
More informationPart 1 Principles of the Fluid Dynamic Design of Packed Columns for Gas/Liquid Systems
Part 1 Principles of the Fluid Dynamic Design of Packed Columns for Gas/Liquid Systems List of Symbols for Part 1 Formula Variables, Latin Letters a m 2 m 3 geometric surface area of packing per unit volume
More information