Reflected spectrally negative stable processes and fractional Cauchy problems
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1 Reflected spectrally negative stable processes and fractional Cauchy problems 7th International Conference on Lévy Processes: Theory and Applications July 2013 Mark M. Meerschaert Department of Statistics and Probability Michigan State University Partially supported by NSF grant DMS
2 Abstract In this talk we will show how to explicitly compute the transition densities of a spectrally negative stable process with index greater than one, reflected at its infimum. First we derive the forward equation using the theory of sun-dual semigroups. The resulting forward equation is a boundary value problem on the positive half-line that involves a negative Riemann-Liouville fractional derivative in space, and a fractional reflecting boundary condition at the origin. Then we apply numerical methods to explicitly compute the transition density of this space-inhomogeneous Markov process, for any starting point, to any desired degree of accuracy. Finally, we discuss an application to fractional Cauchy problems, which involve a positive Caputo fractional derivative in time.
3 Co-authors Boris Baeumer, Maths & Stats, University of Otago, New Zealand Mihály Kovács, Maths & Stats, University of Otago, New Zealand René L. Schilling, Math Stochastics, TU Dresden, Germany Peter Straka, Mathematics, University of Manchester, UK Acknowledgments Zhen-Qing Chen, University of Washington Pierre Patie, Université Libre de Bruxelles Victor Rivero, Centro de Investigación en Matemáticas
4 New Books Stochastic Models for Fractional Calculus Mark M. Meerschaert and Alla Sikorskii De Gruyter Studies in Mathematics 43, 2012 Advanced graduate textbook (Introduction to Lévy processes and fractional calculus) ISBN Mathematical Modeling, 4th Edition Mark M. Meerschaert Academic Press, Elsevier, 2013 Advanced undergraduate / beginning graduate textbook (new sections on particle tracking and anomalous diffusion) ISBN
5 Reflected stable process Take a spectrally negative stable Lévy process Y t with E[e iky t ] = e t(ik)α for some 1 < α 2, and define the reflected process Z t = Y t inf{y s : 0 s t}. Then Z t 0 is a Markov process on the real line. The semigroup T t f(x) = E[f(Z t+s ) Z s = x] on the Banach space C (R) satisfies the Feller property T t f f := sup{ T t f(x) f(x) : x R} 0 as t 0.
6 Reflected stable sample path Stable process Y t (thin line) with α = 1.3 and reflected stable Z t (thick line). See Appendix for R code. Y t
7 Fractional Calculus Positive and negative Riemann-Liouville fractional integrals I α x f(x) := 1 Γ(α) I x α 1 f(x) := Γ(α) 0 f(x y)yα 1 dy = 1 Γ(α) 0 f(x+y)yα 1 dy = 1 Γ(α) x f(y)(x y)α 1 dy x f(y)(y x)α 1 dy Positive and negative Riemann-Liouville fractional derivatives Dx α dn f(x) := dx nin α x f(x) = D x α f(x) := dn d( x) nin α x 1 Γ(n α) dx n d n x ( 1)n f(x) = Γ(n α) dx n Positive Caputo fractional derivative α x f(x) := In α x d n dx nf(x) = 1 Γ(n α) x f(y)(x y)n α 1 dy d n x f(y)(y x)n α 1 dy 0 (x y)n 1 α f (n) (y)dy where α > 0 and n 1 < α < n. If α (1,2), then n = 2.
8 Forward equation for Y t The stable Lévy process Y t has pdf p(x,t) with Fourier transform so that ˆp(k,t) = e ikx p(x,t)dx = e t(ik)α = (ik)αˆp(k,t). tˆp(k,t) Since (ik) αˆf(k) is the Fourier transform of D x α f(x), we have t p(x,t) = Dα x p(x,t). This is the forward equation of the Markov process Y t. It describes the forward evolution of the pdf.
9 Forward semigroup and its generator The forward semigroup is defined by T t f(x) := E[f(x Y t)] = f(x y)p(y,t)dy. If X has pdf f(x) independent of Y t, X +Y t has density T t f(x). The generator of the forward semigroup T t is A f(x) := lim t 0 T t f(x) f(x) t since this expression has Fourier transform Then p(x,t) = T t lim t 0 e t(ik)αˆf(k) ˆf(k) t = D α x f(x) = (ik) αˆf(k). f(x) solves the Cauchy problem t p(x,t) = Dα xp(x,t); p(x,0) = f(x) for any f D(A ).
10 Backward semigroup The backward semigroup T t f(x) := E[f(x+Y t )] = f(x y)p( y,t)dy. If f(x) = I B (x) then T t f(x) = P[x+Y t B] with initial state x. Note p( y,t) has Fourier transform ˆp( k,t) = e t( ik)α Can show ( ik) αˆf(k) is the Fourier transform of D α x f(x) Then A = D α x is the backward generator of Y t Adjoint relation: For suitably nice functions Dα x f(x)g(x)dx = f(x)dα x g(x)dx. Easy to check using integration by parts.
11 Dual semigroups for Z t Backward semigroup T t f(x) := E[f(x+Z t )] on B := C [0, ). Dual semigroup T t on the dual space B := M b [0, ) of (signed) bounded Borel measures with the total variation norm. Then T t f(x)µ(dx) = f(x)[t t µ](dx) for f B and µ B and Af(x)µ(dx) = f(x)[a µ](dx) for f D(A) and µ D(A ). Sun-dual semigroup: B := {µ X : lim t 0 T t µ µ = 0} Needed because T t is not strongly continuous on B.
12 Backward generator for Z t Fourier transform methods are not useful on C [0, ). Bernyk, Dalang and Peskir (2011) compute Af(x) = x α f(x) for f C A := {f S b : x αf C [0, )}, where { S b := f C [0, ) : f C(0, ), f (x) = O(1) as x, f (x) = O(x α 2 ) as x 0, f C b (0, ), f (0+) = 0 Their proof uses the Lévy-Itô formula. } Patie and Simon (2012) extend to f (0+) 0, compute D(A). We show T t is analytic, and C A is a core. Proof: Show that λr(λ,a)g M g for g C [0, ) and Reλ > 0, where R(λ,A) is the resolvent.
13 Forward generator for Z t The sun-dual space B = M ac [0, ), all µ with Lebesgue density Sun-dual generator A f(x) = D α x f(x) similar to Y t, but here D(A ) = {f L 1 [0, ) : D x α f(x) L1 [0, ),D x α 1 f(0) = 0} Then the forward equation for the reflected stable process Z t is t p(x,t) = Dα yp(x,t); Dα 1 x p(0,t) = 0. Similar to Y t except for the reflecting boundary condition. This solves an open problem from Baeumer, M and Nane (2009) [What is the Markov process with this forward equation?]. For µ n B and µ B if µ n µ then T t µ n T t µ in B (vague convergence). Use to prove numerics converge when µ = δ x.
14 Adjoint calculations The backward/forward generators for Y t are adjoints: Y t : Dα x f(x)g(x)dx = f(x)dα x g(x)dx. Integrate by parts, use the definitions. The backward/forward generators for Z t are also adjoints: Z t : 0 Dα x f(x)g(x)dx = 0 f(x) α x g(x)dx. Integrate by parts, use the boundary condition D x α 1 g(x) = 0. Lesson: Adjoint of D α x depends on the space.
15 No-Flux Boundary Condition Since 1 = P(Z t 0) is constant for all t > 0, 0 = t P(Z t 0) = = = = 0 0 Dα x p(x,t)dx ( d 1 dx 0 0 = D α 1 x p(0,t). d t p(x,t)dx Γ(2 α) dx d dx Dα 1 x p(x,t)dx x p(y,t)(y x)1 α dy The boundary condition keeps all probability mass in [0, ). ) dx
16 Lévy-like Markov processes Patie and Simon (2012) show that Z t has backward generator x 1 α y 1 α x Af(x) = f (0) Γ(2 α) + 0 f (x y) Γ(2 α) dy. Integrate by parts to get the pseudo-differential operator form [f(x+y) f(x) yf Af(x) = b(x)f (x)+ (x) ] φ(x,dy). The drift coefficient b(x) = x 1 α /Γ(2 α) blows up as x 0. The jump intensity φ(x,dy) = α(α 1) Γ(2 α) y 1 α dyi( x < y < 0)+ α 1 Γ(2 α) x α δ x (dy) keeps negative jumps inside the state space [0, ). Compare Y t Lévy measure φ(dy) = α(α 1) Γ(2 α) y 1 α dyi(y < 0).
17 Reflected Brownian motion We show Z t+s given Z s = x has a smooth density y p(x,y,t). Reflected Brownian motion transition density solves the diffusion equation with a reflecting boundary condition y p(x,y,t) := lim y=0+ h 0+ p(x,y +h,t) p(x,y,t) = 0 h y=0 In the stable case, the reflecting boundary condition is D α 1 y p(x,y,t) y=0+ := lim h 0+ where w α k 1 h α 1 k=0 w α 1 k Γ(α+1) := ( 1)k k!γ(α k +1) p(x,y +kh,t) = 0 y=0 When α = 2, w α 1 0 = 1, w α 1 1 = 1, and w α 1 k = 0 for k > 1.
18 Reflected stable transition density Transition densities y p(x,y,t) with index α = 1.8 and initial state x = 0,1,2,4 (left to right) at times t = 0.5 (left), t = 1 (middle), and t = 2 (right). See Appendix for MATLAB code
19 Fractional Cauchy problems Suppose T t f(x) = E[f(X t ) X 0 = x] is a Feller semigroup Then p(x,t) = E[f(X Zt ) X 0 = x] solves the fractional Cauchy problem β t p(x,t) = Lp(x,t); p(x,0) = f(x) for any f D(L), when β = 1/α for some α (1,2). Proof: D t = inf{r > 0;Y r > t} is a β-stable subordinator whose inverse E t = inf{u > 0;D u > t} is also the supremum process (inverse of the inverse) of Y t. The result is known for the inverse stable subordinator E t. But Prop VI.3 in Bertoin (1996) implies E t = Z t in distribution.
20 Open problems General reflected stable processes (w/ drift) Compute forward generator Compute transition density Understand fractional boundary conditions Particle tracking codes
21 References 1. W. Arendt, C.J.K. Batty, M. Hieber and F. Neubrander (2011) Vector-valued Laplace Transforms and Cauchy Problems. 2nd ed., Birkhäuser, Basel. 2. B. Baeumer and M.M. Meerschaert (2001) Stochastic solutions for fractional Cauchy problems. Fract. Calc. Appl. Anal. 4, B. Baeumer, M.M. Meerschaert and E. Nane (2009) Space-time duality for fractional diffusion. J. Appl. Prob., 46, B. Baeumer, M. Kovcs, M.M. Meerschaert, R.L. Schilling, and P. Straka (2013) Reflected stable subordinators and their governing equations. Preprint at users/mcubed/duality-process.pdf 5. V. Bernyk, R.C. Dalang and G. Peskir (2011) Predicting the ultimate supremum of a stable Lévy process with no negative jumps. Ann. Probab., 39, J. Bertoin (1996) Lévy Processes. Cambridge University Press, Cambridge. 7. K. Itô and H. P. McKean (1963) Brownian motions on a half line. Illinois J. Math. 7, N. Jacob (1996) Pseudo-Differential Operators and Markov Processes Vol. 1. Imperial College Press, London. 9. M.M. Meerschaert and H.-P. Scheffler (2004) Limit theorems for continuous time random walks with infinite mean waiting times. J. Applied Probab. 41, P. Patie and T. Simon (2012) Intertwining certain fractional derivatives. Potential Anal. 36, R.L. Schilling (1998) Growth and Hölder conditions for the sample paths of Feller processes. Probab. Theor. Rel. Fields 112,
22 Duality and adjoints For a Markov process Z t with transition density p(x,y,t), let u(t,x) = T t u 0 (x) = v(t,y) = T t v 0 (x) = H(s,t) = = = v(s, y)u(t, y)dy p(x,y,s)v 0 (x)dx p(x,y,t)u 0 (y)dy p(x,y,t)v 0 (x)dx p(x,z,s+t)v 0 (x)u 0 (z)dxdz p(y,z,t)u 0 (z)dzdy Then H/ s = H/ t so Av(s, y)u(t, y)dy = s v(s,y)u(t,y)dy = v(s,y) t u(t,y)dy = v(s,y)a u(t,y)dy
23 R code for reflected stable sample path # Plot stable Y_t with characteristic function exp(t(ik)^a) # and the reflected stable process Z_t=Y_t-inf{Y_u:0<=u<=t} # # You need to install the fbasics package on your R platform. # Try Packages > Load package to see if fbasics is available. # If not then use Packages > Install package(s) library(fbasics) t=seq(1:1000) a=1.3 g=(abs(cos(pi*a/2)))^(1/a) y=rstable(t,alpha=a,beta=-1.0,gamma=g,delta=0.0,pm=1) Y=cumsum(y) Z=Y-cummin(Y) plot(t,y,type="l",ylim=c(min(y),max(z))) lines(t,z,lwd=2)
24 MATLAB code for reflected stable pdf %%% Matlab script to compute p(x,y,t) %% enter variables alpha=1.2; ymax=12; N=1200; t=[0,.5,1,2]; x=2; %% initialise parameters h=ymax/n; y=(h:h:ymax) ; u0=zeros(n,1);u0(floor(x/h)+1)=1/h; % initial condition %% Make Grunwald matrix w=ones(1,n+1); for k=1:n w(k+1)=w(k)*(k-alpha-1)/k; end w=w/h^alpha; M=spdiags(repmat(w,N,1),-1:1:N-1,N,N); %enter w s along diagonals M(1,:)=-cumsum(w(1:N)) ; %change first row for BC %% Solve ODE system [~,p]=ode113(@(t,u) M*u,t,u0);
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