NARAYANA IIT ACADEMY INDIA Sec: Sr. IIT-IZ-CO SPARK Jee-Advanced Date: Time: 09:00 AM to 12:00 Noon 2015_P1 Max.Marks:264
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1 NARAYANA IIT ACADEMY INDIA Sec: S. IIT-IZ-CO SPARK Jee-Advanced Date: Time: 9: AM to : Noon 5_P Ma.Maks:64 KEY SHEET PHYSICS AD ACD AD C 4 CD 5 ACD 6 AD 7 ACD 8 A 9 A-RT; -S; C-P; D-Q A-PQRT; -QS; C-PQRS; D-PRT CHEMISTRY A A A AC 4 AC 5 AD 6 ACD 7 CD 8 D 9 A-PR; -R; C-PT; D-QS 4 A-S; -P; C-Q; D-R MATHS ACD 5 D 5 ACD 5 D 5 ACD 54 AC 55 AC A-PQ A-S 56 AD 57 D 58 AC 59 -PQ C-PR 6 -R C-Q D-PQS D-R
2 SOLUTIONS PHYSICS. Complete the pyamids OAD and O AD fo this C is the geometic cente. The closed Figue enclose 6q chage electic flu though all 6 faces is face q So n= 6q. Though each. mk 4mK mk mk sin mk...() mk cos 4 mk...() mk mk 4mk ( squaing and add and ) k k k.8.8 ev k k k.8.8 ev Enegy eleased = k k k.6.6 ev R E 4R 4G 4 p d E Gp p 4 E 4 4G 4 d E G S Potential inside the eath V V V V V V i i S S V E d E d R i R i 4 R / R R Gd G d R Sec: S. IIT-IZ Page
3 G R To escape fom field of eath G R V m mv 4 G R 4. Ans : Sol : sin ce F a & V cm cm Constaint equation V Fom L C E g l emains vetical V A A O V g U K l l mg MV I g l Ml mgl M 6 Ml ml Ml mgl l 5. Conceptual 7 6. g H Li 8.89 u 4 4 He He 8.56u m.86u E mev u Sec: S. IIT-IZ Page
4 =+7.5 Mev 7. Conceptual 8. Image fomation due to conve lens v cm 6 This image will act like a vetical object fo mio and afte eflection fom mio its image (shown by I ) will be fomed at 8cm below optical ais of conve lens. Fo concave lens, this image will be object at a position of 5cm below the lens fo final image fomed by concave lens. 5 5 f f Also f R R O 5 R 9. R 6 Smallest division on main scale cm.5cm 8 5 divisions of the venie scale = 4 divisions of the main scale =4.5 =.5cm.5 I division of venie scale. cm 5 Least count of vene = main scale divisions - venie scale divisions =.5.=.5cm Least count of scew gauge = pitch/ If pitch of the scew gauge is twice the least count of venie calipes then the least count of Sec: S. IIT-IZ Page 4
5 Scew gauge.5.5mm Also, least count of linea scale of scew gauge =.5cm=.5m pitch.5cm.cm mm mm Least Count.mm Hence (C ) is coect.. Conceptual. fom LCAM I I M I I m I a V I m d dv On integating V AndV t R fom LCAM and V f f t V V V g t. Electic field is discontinuous at the locations of chages Hence () 4. u f 5 V cm 5 Fom O to I intensity inceases and then deceases at = 9 cm and cm intensity is same (d) Radius at = cm is equal to adius of lens. 5. The no. of tuns in the spial coil. Pe u nit adial width ' n' Conside a concentic Sec: S. IIT-IZ Page 5 N b a ing of adius and adial thickness d. No. of tuns in that thickness N d. b a
6 The flu linked with that ing Emf induced d e b a T T N t d. cos N d.sin t b a dt T Total emf = b e a N cos b a T T b t d N b a cos t b a T T a b ab a cos t E N E cos t T T T E Cuent though the coil i R E i cos t R T T T Cuent will be ma when t,, T, 6. At a given tempeatue the aveage Kinetic enegy pe molecule is given (f/) kt which is same fo all Diatomic gases hence option (A) is coect. RMS velocity of gas molecules at same tempeatue is invesely Popotional to the squae oot of mola mass of gas hence option () is coect.. Fom gas law pv=nkt we Can see that option (D) is also coect. 7. Following fom the gaph in the question O<i< esistance of diode RD 5 fo i thee afte V. R D I (dynamic). Conside option (a). When I = A; RD 5 ; and V i 5 = 5 volt V Thee afte slope of ( since RD ) So option (a) coect. V i Option (b) slope fom gaph so it is coect Sec: S. IIT-IZ Page 6
7 Option c) when D V 5 V, V 5 V, V V till this value of V, V is linea thee afte V 5V ( emains constant) option ( c) is coect Option (D) when D V 5 V ; v 5 V; V V. Thee afte fo evey 5V ise of V, 5 v ise in V appeas so finally when V V, V 5V Option (d ) is coect. 8. Kma = E W T 4.5 W A T (TA.5) 4.7 W W WA =.95 ev de oglic wavelength h km A D D k A K K A TA = ev WA =.5 ev 9. Conceptual. W = 4. ev Sec: S. IIT-IZ Page 7
8 4. Key: 4 Solution : Fom A: C NH Fom : 5. Key: X= Y = C NH Cl 4 Z = Total 4 Solution : NO HSO4 4 Isoelectonic with N.O = 6. ANS: Sol: ' CHEMISTRY Cl cl R is Identical to p p p n, y, z Y, S, S,S n n n. 7. ANS; 5 G 8.5kj 85 j 85 Ecell Ecell H H.59Xp.9 p 5 8. ANS: Sol: m, mole =.g Gmw=.79=.5.86 i.5 c.5.. Key: A,, 4. a) Covalent chloides do not give test b) Due to moe solubility poduct some PbCl will emain in solution and black ppt will be fomed in second goup also duing qualitative analysis 4 d) osy ed ppt c) Cu CN 6. key: abcd Sec: S. IIT-IZ Page 8
9 Solution : NCERT 7. Ans : CD SOL : CONCEPTUAL 9. Key: A-p; b-; c-pt; d-qs Solution : Given pocesses ae involved in thei etaction pocesses. 4. Conceptual MATHS 4. f ( ) f ( ) 4. (i) y y k, y is divisible by y y (ii) k y is divisible by 6 y 6 y 4k 6 y 6 y 6 y y 6 y. 6 6y 4k 5y 8k 5y 5k k y is divisible by 6 6 6y 8k 5 6 y I 7 d = d d Put t Sec: S. IIT-IZ Page 9
10 7 7 t I d 45 d 45 t 7 6 ( ) I 45 I I d I 45 Hee fo =, f() is zeo which lies in [-, ) so if f() does not contain any value in [-, ), (-) should be cancelled k has a oot k. k = Fo k =, f [, ) 46 ( ) n n n let f an an an... a a a n n f '( ) na n a... a n n n f '( ) f '' n a n a... a f af '' ' f, f ', f ''( ) min value of k is n n n 47 Let P denotes the chances of single bacteia to die, then P. P. P P. P. P 4 4 P P 4P P P P P 5 P 48. MULTI CORRECT 49. conceptual 5. a ,,,, 4 5 Re so Re Sec: S. IIT-IZ Page
11 Re (b) = k k 7 Put = k 77 7 k (c) put = i k i i i i k k (d) put = 5. conceptual 5. : k ydy y d y d y d ydy y d d yd y d y d y dy yd y d y y d y y d y y d y Let tdt t t d dt dt dt log c 4 t 4 t t 4 log log t k t t 5. sin ( tan ), tan, tan, f g tan 5tan, Sec: S. IIT-IZ Page
12 fo i e fo.. tan 54. Let A a b c d, then a c b d a b c d = a b ac+bd= c d det A I a b 55. Conceptual 56. c d ad a d bc e 5 conside the function f()= 57. The paabolas ae y 4 sin ( sin ) and y 4 cos ( cos ), hence the locus is cos sin Key: (A)-p,q ()-p,q (C)-p, (D)-p,q,s 6. Key: (A)-s ()- (C)-q (D)- (A) tan A tan C sin Asin C cos AcosC () Similaly, Sec: S. IIT-IZ Page
13 So, ut (using ) Also, in an acute angled (Using ) ut So, Theefoe, So, The minimum value of Sec: S. IIT-IZ is 8. Page
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