Truss Topology Optimization under Constraints. on Number of Different Design Variables
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1 Truss Topology Optimization under Constraints on Number of Different Design Variables Yoshihiro Kanno (Tokyo Institute of Technology) (University of Tokyo) June 11, 2015
2 constraint on # of different design variables a new modeling of design constraints optimal standardization / optimal grouping a global optimization approach MISOCP (mixed-integer second-order cone programming)
3 second-order cone programming SOCP: Min. c x s. t. p i x+q i c i A i x (i=1,...,m) nonlinear convex optimization primal-dual interior-point method SOC: s 0 s s 12 s 11
4 MISOCP (= mixed-integer second-order cone programming) integrality + SOC: Min. c x s. t. p i x+q i c i A i x (i=1,...,m) x 1,..., x r {0, 1} x r+1,..., x n R some discrete variables & some continuous variables relax x j {0, 1} as 0 x j 1 SOCP solvable with, e.g., a branch-and-bound method
5 MISOCP (= mixed-integer second-order cone programming) integrality + SOC: Min. c x s. t. p i x+q i c i A i x (i=1,...,m) x 1,..., x r {0, 1} x r+1,..., x n R some discrete variables & some continuous variables relax x j {0, 1} as 0 x j 1 SOCP solvable with, e.g., a branch-and-bound method higher modeling ability than MILP well-developed solvers commercial: CPLEX, Gurobi Optimizer, XPRESS non-commercial: SCIP [Achterberg 09]
6 m-i prog. in structural optimization m-i linear prog.: continuum, absence (0) or presence (1) of elements [Stolpe & Svanberg 03] truss, discrete c.-s. areas [Rasmussen & Stolpe 08] [Mela 14] tensegrity (cable strut structure) [K. 12, 13] m-i nonlinear prog.: truss, discrete c.-s. areas [Achtziger & Stolpe 07] [Cerveira, Agra, Bastos & Gromicho 13] [Stolpe 14] truss, continuous c.-s. areas [Ringertz 86] [Ohsaki & Katoh 05] link mechanism [Stolpe & Kawamoto 05] m-i quadratic prog.: truss, discrete c.-s. areas [Achtziger & Stolpe 09]
7 motivation: truss optimization conventional compliance optimization:
8 motivation: truss optimization conventional compliance optimization: (almost) all members have different cross-sectional areas 29 members have 25 different c-s areas practically unrealistic
9 motivation: truss optimization conventional compliance optimization: opt. sol. w/ uniform c-s areas: high manufacturability new constraint: # of different c-s areas n uniform n=1
10 uniformity constraint (n = 1) two decisions: Determine whether member e exists or vanishes. Determine the opt. val. for the common c-s area. [combinatorial] [continuous] Both are addressed simultaneously.
11 uniformity constraint (n = 1) two decisions: Determine whether member e exists or vanishes. Determine the opt. val. for the common c-s area. [combinatorial] [continuous] x 1,..., x m : member c-s areas additional variables: t 1,...,t m {0, 1}, y R
12 uniformity constraint (n = 1) two decisions: Determine whether member e exists or vanishes. Determine the opt. val. for the common c-s area. [combinatorial] [continuous] x 1,..., x m : member c-s areas additional variables: t 1,...,t m {0, 1}, y R y if t e = 1 [exists] x e = 0 if t e = 0 [vanishes] reformulation to linear inequalities: 0 x e x max t e x e y x max (1 t e ) y Ris a continuous design variable. x max : a constant (upr. bd. for x e )
13 generalization: up to n different values two decisions: Determine optimal values for c-s areas, y 1,...,y n. Determine which x e chooses out of 0, y 1,...,y n.
14 generalization: up to n different values two decisions: Determine optimal values for c-s areas, y 1,...,y n. Determine which x e chooses out of 0, y 1,...,y n. 0-1 variables s e1,..., s en {0, 1} : selection among y 1,...,y n x e = y j s e j = 1 t e {0, 1} : existence/absence of member e t e = s e1 + + s en reformulation to linear inequalities: 0 x e x max t e x e y j x max (1 s e j ) y 1,...,y n Rare continuous design variables
15 meaning of the constraints example: n=2 opt. sol.
16 meaning of the constraints example: n=2 Members are divided into... set (A): Members whose c-s areas are 0. set (B): Members whose c-s areas are y 1. set (C): Members whose c-s areas are y 2. two factors: To which set member e belongs? What are the optimal values for y 1 & y 2? [optimal grouping] [optimal sizing]
17 for compliance optimization... conventional compliance optim.: Min. (compliance) s. t. (vol. cstr.), (c-s area 0)
18 for compliance optimization... conventional compliance optim.: Min. (compliance) s. t. (vol. cstr.), (c-s area 0) (compliance) = 2 (complementary energy) cstr.: force-balance eq. SOCP [Ben-Tal & Nemiroviski 01] [Jarre, Kočvara & Zowe 98]
19 for compliance optimization... conventional compliance optim.: Min. (compliance) s. t. (vol. cstr.), (c-s area 0) (compliance) = 2 (complementary energy) cstr.: force-balance eq. SOCP [Ben-Tal & Nemiroviski 01] [Jarre, Kočvara & Zowe 98] compliance optim. w/ cstr. on # of different c-s areas MISOCP (!) It can be solved globally.
20 basis: SOCP for compliance optimization SOCP formulation: Min. 2(w 1 + +w m ) [ ] s. t. w e + x e we x e 2le /Eq e m q e b e = f, (vol. cstr.) e=1 ( ) [Jarre, Kočvara & Zowe 98] [Ben-Tal & Nemiroviski 01] variables: x e : c-s area, q e : axial force, w e : complementary strain energy If x e > 0, ( ) w e 1 l e q 2 e 2 Ex e i.e., def. of complementary strain energy.
21 ex. 200-bar truss 4 m 2 m continuous optim. ground structure
22 ex. 200-bar truss continuous optim. n = 1 : uniform
23 ex. 200-bar truss continuous optim. n = 1 : uniform n=2: two groups n=3: three groups
24 ex. 200-bar truss continuous optim J n = 1 : uniform Areas (mm 2 ) n Obj. (J) y 1 y 2 y 3 Time (s) # of 0-1 vrbs Member standardization is realized with small increase of opt. val.
25 ex. cantilever truss (N X, N Y )=(6, 4), n=1 (N X, N Y )=(6, 4), n=2 (N X, N Y ) n # of membs. # of 0-1 vrbs. Time (s) (6, 4) (6, 4) (7, 4) (7, 4) ,015.8 (5, 6) ,778.5 (6, 6) ,850.6 (< 7 h)
26 ex. cantilever truss (N X, N Y )=(7, 4), n=1 (N X, N Y )=(7, 4), n=2 (N X, N Y ) n # of membs. # of 0-1 vrbs. Time (s) (6, 4) (6, 4) (7, 4) (7, 4) ,015.8 (5, 6) ,778.5 (6, 6) ,850.6 (< 7 h)
27 ex. cantilever truss (N X, N Y )=(5, 6), n=1 (N X, N Y )=(6, 6), n=1 (N X, N Y ) n # of membs. # of 0-1 vrbs. Time (s) (6, 4) (6, 4) (7, 4) (7, 4) ,015.8 (5, 6) ,778.5 (6, 6) ,850.6 (< 7 h)
28 a by-product MISOCP is efficient for discrete truss optimization,......compared with MILP/MIQP. (!) MILP [Rasmussen & Stolpe 08] & MIQP [Achtziger & Stolpe 09] can handle, e.g., stress cstr.
29 a by-product MISOCP is efficient for discrete truss optimization,......compared with MILP/MIQP. (!) MILP [Rasmussen & Stolpe 08] & MIQP [Achtziger & Stolpe 09] can handle, e.g., stress cstr. comparison: Choose c.-s. areas as x 1,..., x m {0, ξ 1, ξ 2,..., ξ r }, w/o cstr. on # of different c-s areas compliance optim. m=200, r=1, 2, 3: MISOCP<20 s vs. MILP, MIQP>24 h MILP & MIQP use big-m. Relaxation of MISOCP has nonlinear (convex) constraints.
30 ex.) 200-bar truss: discrete optimization x e {0, 1000} x e {0, 1050} x e {0, 1100}
31 ex.) 200-bar truss: discrete optimization x e {0, 1000} x e {0, 1050} x e {0, 1100} x e {0, 700, 1400} x e {0, 600, 1200, 1800} x e {0, 400, 800, 1200} Choose c-s areas from a set of predetermined values. The # of different c-s areas is (certainly) small, but......the opt. sol. highly depends on the predetermined values.
32 ex.) 200-bar truss: discrete optimization x e {0, 120, 240,...,1875} : 16 candidate values w/ cstr. on # of different c-s areas n=1 n=2 n=3 n Time (s) (< 9 min)
33 ex.) 200-bar truss: discrete optimization x e {0, 125, 250,...,1800} : 16 candidate values w/ cstr. on # of different c-s areas n=1 n=2 n=3 n Time (s) (< 20 min)
34 conclusions constraint on # of different design variables Determine optimal values used for c-s areas, y 1,...,y n. [continuous] Determine which to choose among 0, y 1,...,y n for member e. [combinatorial] linear ineq. with 0-1 variables compliance optimization of a truss MISOCP (mixed-integer second-order cone programming) integer variables + nonlinear convex constraints global optimization a branch-and-cut method (existing solvers) For discrete optimization,... MISOCP is more efficient than MILP/MIQP.
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