ON SPACE-FILLING CURVES AND THE HAHN-MAZURKIEWICZ THEOREM
|
|
- Clement Thompson
- 5 years ago
- Views:
Transcription
1 ON SPACE-FILLING CURVES AND THE HAHN-MAZURKIEWICZ THEOREM A.P.M. KUPERS Abstract. These are otes for a Staford SUMO talk o space-fillig curves. We will look at a few examples ad the prove the Hah-Mazurkiewicz theorem. This theorem characterizes those subsets of Euclidea that are the image of the uit iterval. After a historical itroductio, we sped two sectios costructig space-fillig curves. I particular, we treat Peao s example because of its historical sigificace ad Lebesgue s example because of its relevace to the proof of the Hah-Mazurkiewicz theorem. This theorem is prove i the fourth sectio, with the exceptio of some poit-set topology lemma s that have bee delegated to the appedix. The first three sectios oly require basic kowledge of real aalysis, while the fourth sectio ad the appedix also require some kowledge of poit-set topology. The best referece for space-fillig curves is Saga s book [Sag94].. What are curves? The ed of the 9th cetury was a excitig time i mathematics. Aalysis had recetly bee put o rigorous footig by the combied effort of may great mathematicias, most importatly Cauchy ad Weierstrass. I particular, they defied cotiuity usig the well-kow ɛ,δ-defiitio: a fuctio f : R R is cotiuous if for every x R ad ɛ > 0, there exists a δ > 0, such that y x < δ implies f(y) f(x) < ɛ. We will be more iterested i curves: cotiuous fuctios f : [0, ] R. This defiitio was supposed to capture the ituitive idea of a ubroke curve, oe that ca be draw without liftig the pecil from the paper. Cotiuous curves should ot be the same as smooth curves, as they for example ca have corers. Though cotiuity might seem like the correct defiitio for this, it i fact admits mostrous curves: Weierstrass i 87 wrote dow a owhere differetiable cotiuous fuctio. By lookig at its graph i R, oe fids a curve havig corers everywhere! Shortly after this, i 878, Cator developed his theory of sets. Oe of the (the) shockig cosequeces was that R ad R had the same cardiality, i.e. the same umber of poits. This meas that there exists a bijectio betwee both sets, which Cator explicitely wrote dow. This result questioed ituitive ideas about the (rather elusive) cocept of dimesio ad a obvious questio after the previous discovery of badly-behaved curves was: Ca we fid a bijectio betwee R ad R which is cotiuous or maybe eve smooth? The aswer to this questio turs out to be o a 879 result by Netto somethig we will prove later this lecture. However, it remaied ope for more tha a decade whether it was also impossible to fid a surjective cotiuous map R R or, closely related, [0, ] [0, ]. Peao shocked the mathematical commuity i 890 by costructig a surjective cotiuous fuctio [0, ] [0, ], a space-fillig curve. It is pictured i figure. This result is historically importat for several reasos. Firstly, it made people realize how forgivig cotiuity is as a cocept ad that it does t always behave as oe ituitively would expect. For example, the space-fillig curves show it behaves badly with respect to dimesio or measure. Secodly, it made clear that result like the Jorda curve theorem ad ivariace of domai eed careful proofs, oe of the mai motivatios for the the ew subject of algebraic topology (back the called aalysis situs). I thik this makes space-fillig curves worthwhile to Date: February 8th 0. It is give by = a cos(b x) with a (0, ) ad b a odd iteger satisfyig ab > + π.
2 A.P.M. KUPERS Figure. The first, secod ad third iteratios f 0, f, f of the sequece defiig the Peao curve. kow about, eve though they are o loger a area of active research ad they hardly have ay applicatios i moder mathematics. If othig else, thikig about them will teach you some useful thigs about aalysis ad poit-set topology. I this lecture we ll costruct several examples, look at their properties ad ed with the Hah- Mazurkiewicz theorem which tells you exactly which subsets of R ca be image of a cotiuous map with domai [0, ].. Peao s curve We start by lookig at Peao s origial example. The mai tool used i its costructio is the theorem that a uiform limit of cotiuous fuctio is cotiuous: Theorem.. Let f be a sequece of cotiuous fuctios [0, ] [0, ] such that for η > 0 there is a N N havig the property that for all, m > N we have sup x [0,] f (x) f m (x) < η. The f(x) := lim f (x) exists for all x [0, ] ad is a cotiuous fuctio. Proof. Suppose we are give a x [0, ] ad ɛ > 0, the we wat to fid a δ > 0 such that y x < δ implies f(y) f(x) < ɛ. Note that for all N, f(y) f(x) f(y) f (y) + f (y) f (x) + f (x) f(x) By takig to be a sufficietly large umber N, we ca make two of the terms i the right had side be bouded by ɛ. By cotiuity of f N, we ca fid a δ > 0 such that y x < δ implies f N (y) f N (x) < ɛ. The if y x < δ we have f(y) f(x) f(y) f N (y) + f N (y) f N (x) + f N (x) f(x) ɛ + ɛ + ɛ = ɛ To get Peao s curve, we will defie a sequece of cotiuous curves f : [0, ] [0, ] that are uiformly coverget to a surjective fuctio. The previous theorem guaratees that this fuctio will i fact be cotiuous as well. We will get the f through a iterative procedure. The fuctios f are defied by dividig [0, ] ito 9 squares of equal size ad similarly dividig [0, ] ito 9 itervals of equal legth. It is clear what the i th iterval is, but the i th square is determied by the previous fuctio f by the order i which it reaches the squares. The i th iterval is the mapped ito the i th square i a piecewise liear maer. The basic shape of these piecewise liear segmets is that of f 0, give i figure. The ext iteratio is obtaied by replacig the piecewise liear segemets i each square with a smaller copy of f 0, matchig everythig up icely. Clearly each f is cotiuous, but also they become icreasigly close. Lemma.. For, m > N we have that sup x [0,] f (x) f m (x) < 9 mi(,m). Hece the sequece f is uiformly coverget. Proof. Without loss of geerality > m. To get from f m to f we oly modify f m withi each of the 9 m cubes. Withi such a cube, the poits that are furthest apart are i opposite corers ad their distace is 9 m.
3 ON SPACE-FILLING CURVES AND THE HAHN-MAZURKIEWICZ THEOREM The theorem about uiform covergece of cotiuous fuctios ow tells us that the followig defiitio makes sese. Defiitio.. The Peao curve is the cotiuous fuctio f : [0, ] [0, ] give by Lemma.4. The Peao is surjective. f(x) = lim f (x) Proof. Note that th iterate f of the Peao curve goes through the ceters of all of 9 squares. Hece ay poit (x, y) [0, ] is o more tha 9 away from a poit o f. Usig the uiform covergece, we see that there is a poit o the image of f that is less tha 9 away from (x, y). Hece (x, y) lies i the closure of the image of f. We will see i propositio 4. that the image of the iterval uder ay cotiuous fuctio is compact ad hece closed, as (x, y) i fact lies i the image of f. Though each of the f is ijective, the limit f is ot. This is will prove later, as a cosequece of oe of the itermediate results i the proof of the Hah-Mazurkiewicz theorem.. Lebesgue s curve We will ow give a secod costructio of a space-fillig curve, due to Lebesgue i 904. The ideas i this costructio will play a importat role i the proof of the Hah-Mazurkiewicz theorem, ad alog the way we ll meet a iterestig space kow as a Cator space. Lebesgue s curve will be clearly surjective, because it will be give by coectig the poit i the image of a surjective map from a subset of [0, ] by liear segmets. This subset is the Cator set: Defiitio.. Let C be the subset [0, ] by deletig all elemets that have a i their terary decimal expasio. Alteratively, C is give by the repeatedly removig middle thirds of itervals. Oe starts with C 0 = [0, ], C = [0, /] [/, ], etc., ad sets C = C. Lebesgue the defied the followig fuctio from C to [0, ] : ( ) 0. a l(0. (a )(a )(a )...) = a a a a 4 a 6... This is easily see to be surjective. We will show it is cotiuous. Lemma.. The fuctio l is cotiuous. Proof. We will prove that if y x < (i.e. our δ), the l(y) l(x) < + (i.e. our ɛ). The idea is to ote that if y x <, the the first terary decimals are the same. Hece the + first biary decimals of the x ad y-coordiate of l(x) are the same. This meas that they are o further that apart. Now Lebesgue exteds this fuctio liearly over the gaps i [0, ] left by the Cator set. We deote such a gap by (a, b ). A example is (/, /). We obtai l : [0, ] [0, ] as follows l(x) = { l(x) if x C (l(b ) l(a )) x a b a + l(a ) if x (a, b ) ([0, ]\C) We claim that this fuctio is cotiuous. Clearly it is cotiuous o the gaps (a, b ) i the complemet of the Cator set because it is liear there. It is however ot clear it cotiuous at the poits of the Cator set. However, by cotiuity of l ad the fact that liear iterpolatios do t get far from their edpoits, we will also be able to prove cotiuity there. Lemma.. The fuctio l is cotiuous.
4 4 A.P.M. KUPERS Figure. The first, secod ad third iteratios of a sequece covergig to hte Lebesgue curve. Proof. By the remarks above it suffices to prove cotiuity at x C. Sice C has empty iterior or equivaletly every poit is a boudary poit, there are three situatios: (i) x is both o the left ad the right a limit of poits i C, (ii) x borders a gap (a, b ) o the left, (iii) x borders a gap (a, b ) o the right. We will do the last case ad skip the first two, because they are very similar to the last case. We do t eed to worry about cotiuity from the right, as l is liear there. We ca take a δ satisfyig > δ > 0 ad such that if y < x ad y x < δ, the y lies i C or i a gap + (a k, b k ) such that a k x <. The idea is just to take δ a bit smaller tha + such that + [x, x δ] cotais a elemet of C. + The, if y C, the we kow that l(y) l(x) = l(y) l(x) < by the previous lemma. If y / C, the y lies i aother gap (a k, b k ) with x a k ad a k x <. That l(y) l(x) < + ow follows by the covexity of balls i Euclidea space: if the edpoits of a lie segmet lie i a ball, the the etire lie segmet lies i the ball. Alteratively, we ca simply estimate l(y) l(x) = (l(b k ) l(a k )) y a k + l(a k ) l(y) b k a k = ( l(b k ) l(y) (y a k ) + l(a k ) l(y) (b k y)) b k a k < ( b k a k (y a k + b k y)) = where we have used that (a k, b k ) [x, x] implies that l(b + k ) l(y) < ad similarly for l(a k ) l(y). There is a iterative costructio of Lebesgue s curve similar to Peao s curve. It is give i figure. 4. The Hah-Mazurkiewicz theorem I this sectio we prove the Hah-Mazurkiewicz theorem for subsets of Euclidea space. Defiitio 4.. A subset A of R is said to be compact if every sequece has a coverget subsequece with limit i A. Equivaletly, by Bolzao-Weierstrass, it is bouded ad closed. The set A is said to be coected if we ca t write it A = (U V ) A, where U ad V are o-empty disjoit ope subsets of R. Fially, it is said to be weakly locally-coected if for all a A ad η > 0 we ca fid a smaller ɛ > 0 such that x B ɛ (a), the x ad a lie i the same coected compoet of A B η (a). The last defiitio, that of weakly locally-coectedess, is i fact equivalet to the more widely used otio of locally-coectedess. However, weakly locally-coectedess at a poit is ot equivalet to locally-coectedess at that poit! This is prove i the appedix. Theorem 4.. A subset A R is the image of some cotiuous map f : [0, ] R if ad oly if it is compact, coected ad weakly locally-coected.
5 ON SPACE-FILLING CURVES AND THE HAHN-MAZURKIEWICZ THEOREM 5 We will split the proof ito two parts. The easier implicatio is that the image of a space-fillig curve is compact, coected ad locally-coected, i.e. that our coditios are ecessary. For the coverse we ll have to work a bit harder. The trick is to mimic Lebesgue s costructio i geeral, usig Hausdorff s theorem o the images of the Cator set. 4.. The coditios are ecessary. We will start by provig that the coditios of compactess, coectedess ad weakly locally-coectedess are ecessary. Propositio 4.. The image of a cotiuous map f : [0, ] R is compact, coected ad weakly locally-coected. Proof. Let s call the image A. Oe of the equivalet defiitios of beig compact is that every sequece i A has a coverget subsequece with limit i A. Let s prove this. Let a be a sequece i A, the by pickig a poit i each preimage of a a we get a sequece x i [0, ]. The iterval [0, ] is closed ad bouded, hece compact by Bolzao-Weierstrass. Thus there is a coverget subsequece x k i [0, ], with limit x. We claim that the a k coverge for f(x). But this is a direct cosequece of the cotiuity of f: it seds coverget sequeces to coverget sequeces. The image of a path-coected set is clearly path-coected. But path-coected implies coected, so A is i fact coected. For weakly locally-coectedess we have to a bit more careful. Suppose that for a A the coditio of weakly locally-coectedess fails. The we ca fid a ɛ > 0 ad η < ɛ with η 0 ad a B η (a) A such that a ad a do t lie i the same coected compoet of B ɛ (a). Note that by costructio the sequece {a } coverges to a. Pick a elemet x i the preimage of a. By compactess of [0, ] this has a coverget subsequece x k with limit x, which ecessarily is mapped to a. There is a δ > 0 such that y x < δ implies f(y) f(x) < ɛ. Take K sufficietly large such that x x K < δ. The the etire lie segmet [x K, x] (or [x, x K ], depedig o what makes sese), is mapped ito B ɛ (a) A ad hece a K ad a lie i the same coected compoet of B ɛ (a) A, cotradictig our assumptio o a K. This theorem is geeralized i poit-set topology, where oe proves that the image of ay compact, resp. coected, space is compact, resp. coected. 4.. Itermezzo: Netto s theorem. I the first part of the proof of the previous propositio, we actually proved the image of each closed subset B [0, ] uder a cotiuous map f : [0, ] R is closed. We will use this to prove that o space-fillig curve ca be ijective. This is kow as Netto s theorem. It is a special versio of the theorem that a cotiuous bijectio from a compact space to a Hausdorff space is homeomorphism. Propositio 4.4. A cotiuous surjective map f : [0, ] [0, ] ca ot be ijective. Proof. We claim that the iverse g := f : [0, ] [0, ] is cotiuous ad hece f is a homeomorphism (a cotiuous bijective fuctio with cotiuous iverse). Let C [0, ] be a closed subset. It is also bouded, so compact. We have that g (C) = f(c) ad every cotiuous fuctio seds compact sets to compact sets, as implicitly prove i propositio 4.. Every compact set i [0, ] is i particular closed. So g of closed sets are closed, hece by lookig at complemets uder g of ope sets we ca coclude that these are ope. Hece g = f is cotiuous. Coectedess is preserved by homeomorphisms, because if X ad Y are homeomorphic, a decompositio of oe of them ito a disjoit uio of o-empty ope sets ca be We ca fid a y it([0, ] ) whose preimage x is ot equal to 0 or. The the restrictio of f to [0, x) (x, ], gives a homeomorphism of the set [0, x) (x, ], havig two coected compoets, with the coected set [0, ] \{y}. This gives a cotradictio. 4.. Hausdorff s theorem ad a theorem o pathcoectedess. I this subsectio we will prove Hausdorff s theorem about the possible images i Euclidea space uder a cotiuous map of the Cator set. This was prove i 97 by Hausdorff ad idepedetly i 98 by Alexadroff. It says, i some sese, that the Cator set is the uiversal compact subset of Euclidea space of ay dimesio.
6 6 A.P.M. KUPERS Theorem 4.5. Every compact subset of R is a cotiuous image of the Cator set. Proof. Let A be our compact set. Cosider the cover of A give by B (a) for a A. By compactess there is a fiite subcover, which by duplicatig elemets of the cover if ecessary is of the form B (a i ) for i. Now cover A i = B (a i ) A by B / (a) for a B (a i ) A ad by duplicatig elemets of the fiitely may covers if ecessary we ca assume it has a fiite subcover B / (a i,j ) for i ad j with idepedet of i. We set A i,j = B / (a i,j ) B (a i ) A. Cotiue this procedure, makig the radius of the balls half as large each step. Notice that for a sequece k i {,..., i } we get a sequece of ested closed sets with radius goig to 0. This determies a uique elemet of A as follows: a is the uique elemet of i A k,k,...,k i. Sice we are dealig with icreasigly fie covers ad every elemet of A lies i some itersectio of elemets of the cover, we obtai each elemet of A this way. For coveiece, we defie a way of gettig from a sequece {a } N of 0, s to a sequece of umbers {K } N i {,..., i }. They are give by K = j= a j j, K = j= a j+ j ad i geeral by K i = i j= a j i j. We will defie a fuctio f : C A. It is give by f(0. (a )(a )(a )...) = uique elemet of i A K,K,...,K i This is surjective by the previous remark about every elemet lyig i a itersectio of some elemets of the cover. We also claim it is cotiuous. This is actually rather simple: if y x < + the the first digits i the terary expasio are equal. We ca fid a j such that j j+. Thus f(y) ad f(x) lie i the same A k,k,...,k j, which lies i a ball of radius. Hece f(y) f(x) < ad we coclude that f is cotiuous. k k We wat to costruct our space-fillig curve usig this map, by coectig usig paths i A over the gaps i the Cator set. However, to be able to do this we eed fid such paths ad show they ca be chose sufficietly short for poits i A that are close together. Let s make defiitios for these otios. Defiitio 4.6. We say that a subset A of R is path-coected if ay two poits ca be joied a cotiuous path with image i A. The subset A is said to be uiformly path-coected if for all ɛ > 0 there exists a η (0, ɛ) such that if a, a A satisfy a a < η, the there is a cotiuous path with image i B ɛ (a ) B ɛ (a) A coectig a ad a. Theorem 4.7. If A is compact, coected ad weakly locally-coected, it is path-coected ad uiformly path-coected. This is prove i the appedix The coditios are sufficiet. Now we ll combie Hausdorff s theorem ad our theorem o pathcoectedess to costruct a surjective map [0, ] A uder the coditios listed before. As said before, the idea is to copy the idea of Lebesgue s costructio of a space-fillig curve: use Hausdorff s theorem to get a surjective map from the Cator set ito A ad use our theorem o pathcoectedess to prove that we ca coect the image by paths our the gaps i the Cator set. Theorem 4.8. If A R is compact, coected ad weakly locally-coected, the there exists a surjective cotiuous fuctio f : [0, ] A. Proof. Sice A is compact, by Hausdorff s theorem there exists a cotiuous surjective fuctio g : C A. By uiformly path-coectedess, we ca fid a decreasig sequece of η such that a a < η implies that there is a cotiuous path with image i B / (a) B / (a ) A. By cotiuity of g ad compactess of C, we ca fid a decreasig sequece of δ > 0 such that y x < δ implies g(y) g(x) < η. If (a k, b k ) is a gap i C such that δ + b k a k < δ, the we ca fid a
7 ON SPACE-FILLING CURVES AND THE HAHN-MAZURKIEWICZ THEOREM 7 cotiuous path γ k : [a k, b k ] A such that γ k lies i B / (g(a k )) B / (g(b k )) A coectig g(a k ) to g(b k ). We defie f as follows: { g(x) if x C f(x) = γ k (x) if x (a k, b k ) ([0, ]\C) This fuctio is clearly cotiuous at all poits of ([0, ]\C) ad as before the poits x C comes i three types: (i) x is both o the left ad the right a limit of poits i C, (ii) x borders a gap (a, b ) o the left, (iii) x borders a gap (a, b ) o the right. Agai we will do the last case ad skip the first two, because they are very similar to the last case. Cotiuity from the right is obvious, as f is just a cotiuous path there. For cotiuity from the left pick δ > 0 satisfyig δ > δ > 0 ad such that if y < x ad y x < δ, the y C or it lies i a gap (a k, b k ) such that a k x < δ. If y C, the y x < η ad hece f(y) f(x) = g(y) g(x) η. If y / C, the y lies o a path that does t get further tha from g(x) ad hece f(y) f(x). So give a ɛ > 0 just take a N so that mi({η, }) < ɛ ad set δ = δ. The y x < δ implies f(y) f(x) < ɛ. Appedix A. Differet otios of local coectedess I this appedix we prove several relatios betwee differet otio of coectedess. Let s recall their defiitios. We will use ope sets istead of ope balls for coveiece, except i the defiitio about uiform path-coectedess, which eeds explicit ɛ s. Defiitio A.. () A subset A R is said to be weakly locally-coected if for all a A ad ope eighborhoods U of a i A we ca fid ope eighborhood V U cotaiig a such that x V, the x ad a lie i the same coected compoet of U. () The subset A is said to be uiformly weakly locally-coected if for all ɛ > 0 there exists a η (0, ɛ) such that if a, a A satisfy a a < η the a, a lie i the same coected compoet of B ɛ (a) B ɛ (a ) A. () A R is said to be locally coected if for all a A ad all ope eighborhoods U of a i A we ca fid a eighborhood V A of a which is coected. (4) A is said to be locally path-coected if for all a A ad all ope eighborhoods U of a i A we ca fid a eighborhood V A of a which is path-coected. (5) The subset A is said to be uiformly locally path-coected if for all ɛ > 0 there exists a η (0, ɛ) such that if a, a A both satisfy a a < η the there is a cotiuous path with image i B ɛ (a) B ɛ (a ) coectig a ad a. Lemma A.. The subspace A is weakly locally-coected if ad oly if it is locally coected. Proof. The implicatio is clear. For the implicatio, we claim that the coected compoets of all ope subsets of A are ope. For if this is true, the take V to be the coected compoet cotaiig a i U. Let C be a coected compoet of U. We will cover C by ope sets V c A, the the expressio C = ( c V c ) A shows it s ope ad we are doe. Pick c C ad a ope eighborhood V c of it such that U c U. Usig weakly locally-coectedess, take a smaller ope eighborhood V c such that if x V c, the c ad x lie i the same coected compoet of U c. I particular c ad x must the both lie i C. This meas that V c C ad we are doe. Lemma A.. Coected ad locally path-coected implies path-coected. path-coected implies locally path-coected. Uiformly locally Proof. Let s start with the first statemet. Let a A ad P a be the subset of A of all poits that ca be coected by a path to A. It is ope by locally path-coectedess. To see it is closed as well, use that beig coected be a path is a equivalece relatio, hece A = P ai. Hece the complemet of P a is ope ad thus P a is closed. A ope ad closed set is a coected compoet ad sice A was assumed coected, we coclude A = P a. The secod statemet is trivially true.
8 8 A.P.M. KUPERS Lemma A.4. If A is compact ad weakly locally-coected it is uiformly weakly locally-coected. Proof. Suppose that it is ot uiformly weakly locally-coected. The there exists a ɛ > 0, η i 0 ad a i a i < η i such that a i ad a i lie i differet coected compoets of B ɛ(a) B ɛ (a ) A. By compactess, we ca assume that a i ad a i coverge, ecessarily to the same elemet a. Now we apply weakly locally-coectedess at a to B ɛ (a): we get a η > 0 such that x B η (a) implies that x, a lie i the same coected compoet of B ɛ (a). Take i large eough such η i < η. The a i ad a i lie i the same coected compoet of B ɛ(a) at a ad hece lie i the same coected compoet. This gives a cotradictio. Theorem A.5. If A is compact, coected ad weakly locally-coected, it is path-coected, locally path-coected ad i fact uiformly locally path-coected. Proof. By the previous lemma s, it suffices to prove uiform locally path-coectedess. Take ɛ > 0 ad set ɛ k = ɛ 4. Take η k k to be umber comig out of uiformly weakly locally-coectedess for ɛ k ad set η = η. Let a, a A be such that a a < η. We claim that by coectedess we ca fid a ad a sequece of poits x () i for 0 i such that x () 0 = a, x () = a ad x () i x () i+ < η. This is because the set of poits i A that ca be coected by a η -chai of poits is both ope ad closed, hece equal to A. Each of the x () i lie the same coected compoet of B ɛ (x () i ) B ɛ (x () i+ ) A ad hece we ca fid ad sequeces x () i,j i B ɛ (x () i ) B ɛ (x () i+ ) A for 0 i, 0 j with x () i,0 = x() i ad x () i, = x () i+. Cotiue this process, gettig k ad x (k). i Let J [0, ] be the set of poits with biary expasio that ca be writte as for k i some i ad k. This is dese. The we defie g : J A by sedig to the poit of the k x (k) that i correspods to. This ca be checked to be cotiuous, sice η k < ɛ k ad the ɛ k go to zero. Hece g exteds to a cotiuous fuctio γ : [0, ] A. The image lies i A sice A is compact, hece closed. The oly thig left to check is that γ stays withi B ɛ (a) B ɛ (a) A. But it stays withi k= ɛ k < ɛ of a ad a by costructio. Refereces [Sag94] Has Saga, Space-fillig curves, Uiversitext Series, Spriger-Verlag, 994.
Lecture Notes for Analysis Class
Lecture Notes for Aalysis Class Topological Spaces A topology for a set X is a collectio T of subsets of X such that: (a) X ad the empty set are i T (b) Uios of elemets of T are i T (c) Fiite itersectios
More informationON SPACE-FILLING CURVES AND THE HAHN-MAZURKIEWICZ THEOREM
ON SPACE-FILLING CURVES AND THE HAHN-MAZURKIEWICZ THEOREM ALEXANDER KUPERS Abstract. These are notes on space-filling curves, looking at a few examples and proving the Hahn-Mazurkiewicz theorem. This theorem
More informationIf a subset E of R contains no open interval, is it of zero measure? For instance, is the set of irrationals in [0, 1] is of measure zero?
2 Lebesgue Measure I Chapter 1 we defied the cocept of a set of measure zero, ad we have observed that every coutable set is of measure zero. Here are some atural questios: If a subset E of R cotais a
More informationf n (x) f m (x) < ɛ/3 for all x A. By continuity of f n and f m we can find δ > 0 such that d(x, x 0 ) < δ implies that
Lecture 15 We have see that a sequece of cotiuous fuctios which is uiformly coverget produces a limit fuctio which is also cotiuous. We shall stregthe this result ow. Theorem 1 Let f : X R or (C) be a
More informationREAL ANALYSIS II: PROBLEM SET 1 - SOLUTIONS
REAL ANALYSIS II: PROBLEM SET 1 - SOLUTIONS 18th Feb, 016 Defiitio (Lipschitz fuctio). A fuctio f : R R is said to be Lipschitz if there exists a positive real umber c such that for ay x, y i the domai
More informationSequences and Series of Functions
Chapter 6 Sequeces ad Series of Fuctios 6.1. Covergece of a Sequece of Fuctios Poitwise Covergece. Defiitio 6.1. Let, for each N, fuctio f : A R be defied. If, for each x A, the sequece (f (x)) coverges
More informationSingular Continuous Measures by Michael Pejic 5/14/10
Sigular Cotiuous Measures by Michael Peic 5/4/0 Prelimiaries Give a set X, a σ-algebra o X is a collectio of subsets of X that cotais X ad ad is closed uder complemetatio ad coutable uios hece, coutable
More informationMath Solutions to homework 6
Math 175 - Solutios to homework 6 Cédric De Groote November 16, 2017 Problem 1 (8.11 i the book): Let K be a compact Hermitia operator o a Hilbert space H ad let the kerel of K be {0}. Show that there
More informationTheorem 3. A subset S of a topological space X is compact if and only if every open cover of S by open sets in X has a finite subcover.
Compactess Defiitio 1. A cover or a coverig of a topological space X is a family C of subsets of X whose uio is X. A subcover of a cover C is a subfamily of C which is a cover of X. A ope cover of X is
More informationChapter 6 Infinite Series
Chapter 6 Ifiite Series I the previous chapter we cosidered itegrals which were improper i the sese that the iterval of itegratio was ubouded. I this chapter we are goig to discuss a topic which is somewhat
More informationConvergence of random variables. (telegram style notes) P.J.C. Spreij
Covergece of radom variables (telegram style otes).j.c. Spreij this versio: September 6, 2005 Itroductio As we kow, radom variables are by defiitio measurable fuctios o some uderlyig measurable space
More information(A sequence also can be thought of as the list of function values attained for a function f :ℵ X, where f (n) = x n for n 1.) x 1 x N +k x N +4 x 3
MATH 337 Sequeces Dr. Neal, WKU Let X be a metric space with distace fuctio d. We shall defie the geeral cocept of sequece ad limit i a metric space, the apply the results i particular to some special
More informationMath 341 Lecture #31 6.5: Power Series
Math 341 Lecture #31 6.5: Power Series We ow tur our attetio to a particular kid of series of fuctios, amely, power series, f(x = a x = a 0 + a 1 x + a 2 x 2 + where a R for all N. I terms of a series
More informationFUNDAMENTALS OF REAL ANALYSIS by
FUNDAMENTALS OF REAL ANALYSIS by Doğa Çömez Backgroud: All of Math 450/1 material. Namely: basic set theory, relatios ad PMI, structure of N, Z, Q ad R, basic properties of (cotiuous ad differetiable)
More informationThe Borel hierarchy classifies subsets of the reals by their topological complexity. Another approach is to classify them by size.
Lecture 7: Measure ad Category The Borel hierarchy classifies subsets of the reals by their topological complexity. Aother approach is to classify them by size. Filters ad Ideals The most commo measure
More informationDefinition 4.2. (a) A sequence {x n } in a Banach space X is a basis for X if. unique scalars a n (x) such that x = n. a n (x) x n. (4.
4. BASES I BAACH SPACES 39 4. BASES I BAACH SPACES Sice a Baach space X is a vector space, it must possess a Hamel, or vector space, basis, i.e., a subset {x γ } γ Γ whose fiite liear spa is all of X ad
More information6.3 Testing Series With Positive Terms
6.3. TESTING SERIES WITH POSITIVE TERMS 307 6.3 Testig Series With Positive Terms 6.3. Review of what is kow up to ow I theory, testig a series a i for covergece amouts to fidig the i= sequece of partial
More informationThe Boolean Ring of Intervals
MATH 532 Lebesgue Measure Dr. Neal, WKU We ow shall apply the results obtaied about outer measure to the legth measure o the real lie. Throughout, our space X will be the set of real umbers R. Whe ecessary,
More informationProduct measures, Tonelli s and Fubini s theorems For use in MAT3400/4400, autumn 2014 Nadia S. Larsen. Version of 13 October 2014.
Product measures, Toelli s ad Fubii s theorems For use i MAT3400/4400, autum 2014 Nadia S. Larse Versio of 13 October 2014. 1. Costructio of the product measure The purpose of these otes is to preset the
More informationLecture XVI - Lifting of paths and homotopies
Lecture XVI - Liftig of paths ad homotopies I the last lecture we discussed the liftig problem ad proved that the lift if it exists is uiquely determied by its value at oe poit. I this lecture we shall
More informationMeasure and Measurable Functions
3 Measure ad Measurable Fuctios 3.1 Measure o a Arbitrary σ-algebra Recall from Chapter 2 that the set M of all Lebesgue measurable sets has the followig properties: R M, E M implies E c M, E M for N implies
More informationFall 2013 MTH431/531 Real analysis Section Notes
Fall 013 MTH431/531 Real aalysis Sectio 8.1-8. Notes Yi Su 013.11.1 1. Defiitio of uiform covergece. We look at a sequece of fuctios f (x) ad study the coverget property. Notice we have two parameters
More informationlim za n n = z lim a n n.
Lecture 6 Sequeces ad Series Defiitio 1 By a sequece i a set A, we mea a mappig f : N A. It is customary to deote a sequece f by {s } where, s := f(). A sequece {z } of (complex) umbers is said to be coverget
More informationRecitation 4: Lagrange Multipliers and Integration
Math 1c TA: Padraic Bartlett Recitatio 4: Lagrage Multipliers ad Itegratio Week 4 Caltech 211 1 Radom Questio Hey! So, this radom questio is pretty tightly tied to today s lecture ad the cocept of cotet
More informationMath 61CM - Solutions to homework 3
Math 6CM - Solutios to homework 3 Cédric De Groote October 2 th, 208 Problem : Let F be a field, m 0 a fixed oegative iteger ad let V = {a 0 + a x + + a m x m a 0,, a m F} be the vector space cosistig
More informationIntegrable Functions. { f n } is called a determining sequence for f. If f is integrable with respect to, then f d does exist as a finite real number
MATH 532 Itegrable Fuctios Dr. Neal, WKU We ow shall defie what it meas for a measurable fuctio to be itegrable, show that all itegral properties of simple fuctios still hold, ad the give some coditios
More informationAnalytic Continuation
Aalytic Cotiuatio The stadard example of this is give by Example Let h (z) = 1 + z + z 2 + z 3 +... kow to coverge oly for z < 1. I fact h (z) = 1/ (1 z) for such z. Yet H (z) = 1/ (1 z) is defied for
More information2 Banach spaces and Hilbert spaces
2 Baach spaces ad Hilbert spaces Tryig to do aalysis i the ratioal umbers is difficult for example cosider the set {x Q : x 2 2}. This set is o-empty ad bouded above but does ot have a least upper boud
More informationMAS111 Convergence and Continuity
MAS Covergece ad Cotiuity Key Objectives At the ed of the course, studets should kow the followig topics ad be able to apply the basic priciples ad theorems therei to solvig various problems cocerig covergece
More informationInfinite Sequences and Series
Chapter 6 Ifiite Sequeces ad Series 6.1 Ifiite Sequeces 6.1.1 Elemetary Cocepts Simply speakig, a sequece is a ordered list of umbers writte: {a 1, a 2, a 3,...a, a +1,...} where the elemets a i represet
More informationPRELIM PROBLEM SOLUTIONS
PRELIM PROBLEM SOLUTIONS THE GRAD STUDENTS + KEN Cotets. Complex Aalysis Practice Problems 2. 2. Real Aalysis Practice Problems 2. 4 3. Algebra Practice Problems 2. 8. Complex Aalysis Practice Problems
More informationChapter 3. Strong convergence. 3.1 Definition of almost sure convergence
Chapter 3 Strog covergece As poited out i the Chapter 2, there are multiple ways to defie the otio of covergece of a sequece of radom variables. That chapter defied covergece i probability, covergece i
More informationAssignment 5: Solutions
McGill Uiversity Departmet of Mathematics ad Statistics MATH 54 Aalysis, Fall 05 Assigmet 5: Solutios. Let y be a ubouded sequece of positive umbers satisfyig y + > y for all N. Let x be aother sequece
More information1 Introduction. 1.1 Notation and Terminology
1 Itroductio You have already leared some cocepts of calculus such as limit of a sequece, limit, cotiuity, derivative, ad itegral of a fuctio etc. Real Aalysis studies them more rigorously usig a laguage
More informationMAT1026 Calculus II Basic Convergence Tests for Series
MAT026 Calculus II Basic Covergece Tests for Series Egi MERMUT 202.03.08 Dokuz Eylül Uiversity Faculty of Sciece Departmet of Mathematics İzmir/TURKEY Cotets Mootoe Covergece Theorem 2 2 Series of Real
More informationMetric Space Properties
Metric Space Properties Math 40 Fial Project Preseted by: Michael Brow, Alex Cordova, ad Alyssa Sachez We have already poited out ad will recogize throughout this book the importace of compact sets. All
More informationFinal Solutions. 1. (25pts) Define the following terms. Be as precise as you can.
Mathematics H104 A. Ogus Fall, 004 Fial Solutios 1. (5ts) Defie the followig terms. Be as recise as you ca. (a) (3ts) A ucoutable set. A ucoutable set is a set which ca ot be ut ito bijectio with a fiite
More informationAxioms of Measure Theory
MATH 532 Axioms of Measure Theory Dr. Neal, WKU I. The Space Throughout the course, we shall let X deote a geeric o-empty set. I geeral, we shall ot assume that ay algebraic structure exists o X so that
More information5 Many points of continuity
Tel Aviv Uiversity, 2013 Measure ad category 40 5 May poits of cotiuity 5a Discotiuous derivatives.............. 40 5b Baire class 1 (classical)............... 42 5c Baire class 1 (moder)...............
More informationMathematical Methods for Physics and Engineering
Mathematical Methods for Physics ad Egieerig Lecture otes Sergei V. Shabaov Departmet of Mathematics, Uiversity of Florida, Gaiesville, FL 326 USA CHAPTER The theory of covergece. Numerical sequeces..
More informationSeunghee Ye Ma 8: Week 5 Oct 28
Week 5 Summary I Sectio, we go over the Mea Value Theorem ad its applicatios. I Sectio 2, we will recap what we have covered so far this term. Topics Page Mea Value Theorem. Applicatios of the Mea Value
More informationUniversity of Colorado Denver Dept. Math. & Stat. Sciences Applied Analysis Preliminary Exam 13 January 2012, 10:00 am 2:00 pm. Good luck!
Uiversity of Colorado Dever Dept. Math. & Stat. Scieces Applied Aalysis Prelimiary Exam 13 Jauary 01, 10:00 am :00 pm Name: The proctor will let you read the followig coditios before the exam begis, ad
More informationBoundaries and the James theorem
Boudaries ad the James theorem L. Vesely 1. Itroductio The followig theorem is importat ad well kow. All spaces cosidered here are real ormed or Baach spaces. Give a ormed space X, we deote by B X ad S
More informationTopologie. Musterlösungen
Fakultät für Mathematik Sommersemester 2018 Marius Hiemisch Topologie Musterlösuge Aufgabe (Beispiel 1.2.h aus Vorlesug). Es sei X eie Mege ud R Abb(X, R) eie Uteralgebra, d.h. {kostate Abbilduge} R ud
More informationRiesz-Fischer Sequences and Lower Frame Bounds
Zeitschrift für Aalysis ud ihre Aweduge Joural for Aalysis ad its Applicatios Volume 1 (00), No., 305 314 Riesz-Fischer Sequeces ad Lower Frame Bouds P. Casazza, O. Christese, S. Li ad A. Lider Abstract.
More informationLesson 10: Limits and Continuity
www.scimsacademy.com Lesso 10: Limits ad Cotiuity SCIMS Academy 1 Limit of a fuctio The cocept of limit of a fuctio is cetral to all other cocepts i calculus (like cotiuity, derivative, defiite itegrals
More informationMath 299 Supplement: Real Analysis Nov 2013
Math 299 Supplemet: Real Aalysis Nov 203 Algebra Axioms. I Real Aalysis, we work withi the axiomatic system of real umbers: the set R alog with the additio ad multiplicatio operatios +,, ad the iequality
More informationProperties of Fuzzy Length on Fuzzy Set
Ope Access Library Joural 206, Volume 3, e3068 ISSN Olie: 2333-972 ISSN Prit: 2333-9705 Properties of Fuzzy Legth o Fuzzy Set Jehad R Kider, Jaafar Imra Mousa Departmet of Mathematics ad Computer Applicatios,
More informationMathematical Foundations -1- Sets and Sequences. Sets and Sequences
Mathematical Foudatios -1- Sets ad Sequeces Sets ad Sequeces Methods of proof 2 Sets ad vectors 13 Plaes ad hyperplaes 18 Liearly idepedet vectors, vector spaces 2 Covex combiatios of vectors 21 eighborhoods,
More informationChapter 7 Isoperimetric problem
Chapter 7 Isoperimetric problem Recall that the isoperimetric problem (see the itroductio its coectio with ido s proble) is oe of the most classical problem of a shape optimizatio. It ca be formulated
More informationSolution. 1 Solutions of Homework 1. Sangchul Lee. October 27, Problem 1.1
Solutio Sagchul Lee October 7, 017 1 Solutios of Homework 1 Problem 1.1 Let Ω,F,P) be a probability space. Show that if {A : N} F such that A := lim A exists, the PA) = lim PA ). Proof. Usig the cotiuity
More informationABOUT CHAOS AND SENSITIVITY IN TOPOLOGICAL DYNAMICS
ABOUT CHAOS AND SENSITIVITY IN TOPOLOGICAL DYNAMICS EDUARD KONTOROVICH Abstract. I this work we uify ad geeralize some results about chaos ad sesitivity. Date: March 1, 005. 1 1. Symbolic Dyamics Defiitio
More informationMath 451: Euclidean and Non-Euclidean Geometry MWF 3pm, Gasson 204 Homework 3 Solutions
Math 451: Euclidea ad No-Euclidea Geometry MWF 3pm, Gasso 204 Homework 3 Solutios Exercises from 1.4 ad 1.5 of the otes: 4.3, 4.10, 4.12, 4.14, 4.15, 5.3, 5.4, 5.5 Exercise 4.3. Explai why Hp, q) = {x
More informationAdvanced Analysis. Min Yan Department of Mathematics Hong Kong University of Science and Technology
Advaced Aalysis Mi Ya Departmet of Mathematics Hog Kog Uiversity of Sciece ad Techology September 3, 009 Cotets Limit ad Cotiuity 7 Limit of Sequece 8 Defiitio 8 Property 3 3 Ifiity ad Ifiitesimal 8 4
More informationLecture 2. The Lovász Local Lemma
Staford Uiversity Sprig 208 Math 233A: No-costructive methods i combiatorics Istructor: Ja Vodrák Lecture date: Jauary 0, 208 Origial scribe: Apoorva Khare Lecture 2. The Lovász Local Lemma 2. Itroductio
More informationLecture 3 The Lebesgue Integral
Lecture 3: The Lebesgue Itegral 1 of 14 Course: Theory of Probability I Term: Fall 2013 Istructor: Gorda Zitkovic Lecture 3 The Lebesgue Itegral The costructio of the itegral Uless expressly specified
More informationA Proof of Birkhoff s Ergodic Theorem
A Proof of Birkhoff s Ergodic Theorem Joseph Hora September 2, 205 Itroductio I Fall 203, I was learig the basics of ergodic theory, ad I came across this theorem. Oe of my supervisors, Athoy Quas, showed
More informationMcGill University Math 354: Honors Analysis 3 Fall 2012 Solutions to selected problems
McGill Uiversity Math 354: Hoors Aalysis 3 Fall 212 Assigmet 3 Solutios to selected problems Problem 1. Lipschitz fuctios. Let Lip K be the set of all fuctios cotiuous fuctios o [, 1] satisfyig a Lipschitz
More informationSequence A sequence is a function whose domain of definition is the set of natural numbers.
Chapter Sequeces Course Title: Real Aalysis Course Code: MTH3 Course istructor: Dr Atiq ur Rehma Class: MSc-I Course URL: wwwmathcityorg/atiq/fa8-mth3 Sequeces form a importat compoet of Mathematical Aalysis
More informationNotes #3 Sequences Limit Theorems Monotone and Subsequences Bolzano-WeierstraßTheorem Limsup & Liminf of Sequences Cauchy Sequences and Completeness
Notes #3 Sequeces Limit Theorems Mootoe ad Subsequeces Bolzao-WeierstraßTheorem Limsup & Limif of Sequeces Cauchy Sequeces ad Completeess This sectio of otes focuses o some of the basics of sequeces of
More informationA COUNTABLE SPACE WITH AN UNCOUNTABLE FUNDAMENTAL GROUP
A COUNTABLE SPACE WITH AN UNCOUNTABLE FUNDAMENTAL GROUP JEREMY BRAZAS AND LUIS MATOS Abstract. Traditioal examples of spaces that have ucoutable fudametal group (such as the Hawaiia earrig space) are path-coected
More informationMachine Learning Theory Tübingen University, WS 2016/2017 Lecture 12
Machie Learig Theory Tübige Uiversity, WS 06/07 Lecture Tolstikhi Ilya Abstract I this lecture we derive risk bouds for kerel methods. We will start by showig that Soft Margi kerel SVM correspods to miimizig
More informationM17 MAT25-21 HOMEWORK 5 SOLUTIONS
M17 MAT5-1 HOMEWORK 5 SOLUTIONS 1. To Had I Cauchy Codesatio Test. Exercise 1: Applicatio of the Cauchy Codesatio Test Use the Cauchy Codesatio Test to prove that 1 diverges. Solutio 1. Give the series
More informationLecture 4: Grassmannians, Finite and Affine Morphisms
18.725 Algebraic Geometry I Lecture 4 Lecture 4: Grassmaias, Fiite ad Affie Morphisms Remarks o last time 1. Last time, we proved the Noether ormalizatio lemma: If A is a fiitely geerated k-algebra, the,
More informationSequences. Notation. Convergence of a Sequence
Sequeces A sequece is essetially just a list. Defiitio (Sequece of Real Numbers). A sequece of real umbers is a fuctio Z (, ) R for some real umber. Do t let the descriptio of the domai cofuse you; it
More information3. Sequences. 3.1 Basic definitions
3. Sequeces 3.1 Basic defiitios Defiitio 3.1 A (ifiite) sequece is a fuctio from the aturals to the real umbers. That is, it is a assigmet of a real umber to every atural umber. Commet 3.1 This is the
More informationLecture 2: April 3, 2013
TTIC/CMSC 350 Mathematical Toolkit Sprig 203 Madhur Tulsiai Lecture 2: April 3, 203 Scribe: Shubhedu Trivedi Coi tosses cotiued We retur to the coi tossig example from the last lecture agai: Example. Give,
More informationMA131 - Analysis 1. Workbook 2 Sequences I
MA3 - Aalysis Workbook 2 Sequeces I Autum 203 Cotets 2 Sequeces I 2. Itroductio.............................. 2.2 Icreasig ad Decreasig Sequeces................ 2 2.3 Bouded Sequeces..........................
More informationA NOTE ON INVARIANT SETS OF ITERATED FUNCTION SYSTEMS
Acta Math. Hugar., 2007 DOI: 10.1007/s10474-007-7013-6 A NOTE ON INVARIANT SETS OF ITERATED FUNCTION SYSTEMS L. L. STACHÓ ad L. I. SZABÓ Bolyai Istitute, Uiversity of Szeged, Aradi vértaúk tere 1, H-6720
More informationHOMEWORK #4 - MA 504
HOMEWORK #4 - MA 504 PAULINHO TCHATCHATCHA Chapter 2, problem 19. (a) If A ad B are disjoit closed sets i some metric space X, prove that they are separated. (b) Prove the same for disjoit ope set. (c)
More informationReal Numbers R ) - LUB(B) may or may not belong to B. (Ex; B= { y: y = 1 x, - Note that A B LUB( A) LUB( B)
Real Numbers The least upper boud - Let B be ay subset of R B is bouded above if there is a k R such that x k for all x B - A real umber, k R is a uique least upper boud of B, ie k = LUB(B), if () k is
More informationMath 508 Exam 2 Jerry L. Kazdan December 9, :00 10:20
Math 58 Eam 2 Jerry L. Kazda December 9, 24 9: :2 Directios This eam has three parts. Part A has 8 True/False questio (2 poits each so total 6 poits), Part B has 5 shorter problems (6 poits each, so 3
More informationBeurling Integers: Part 2
Beurlig Itegers: Part 2 Isomorphisms Devi Platt July 11, 2015 1 Prime Factorizatio Sequeces I the last article we itroduced the Beurlig geeralized itegers, which ca be represeted as a sequece of real umbers
More informationTERMWISE DERIVATIVES OF COMPLEX FUNCTIONS
TERMWISE DERIVATIVES OF COMPLEX FUNCTIONS This writeup proves a result that has as oe cosequece that ay complex power series ca be differetiated term-by-term withi its disk of covergece The result has
More information7 Sequences of real numbers
40 7 Sequeces of real umbers 7. Defiitios ad examples Defiitio 7... A sequece of real umbers is a real fuctio whose domai is the set N of atural umbers. Let s : N R be a sequece. The the values of s are
More informationMath 220A Fall 2007 Homework #2. Will Garner A
Math 0A Fall 007 Homewor # Will Garer Pg 3 #: Show that {cis : a o-egative iteger} is dese i T = {z œ : z = }. For which values of q is {cis(q): a o-egative iteger} dese i T? To show that {cis : a o-egative
More informationExercises 1 Sets and functions
Exercises 1 Sets ad fuctios HU Wei September 6, 018 1 Basics Set theory ca be made much more rigorous ad built upo a set of Axioms. But we will cover oly some heuristic ideas. For those iterested studets,
More informationArchimedes - numbers for counting, otherwise lengths, areas, etc. Kepler - geometry for planetary motion
Topics i Aalysis 3460:589 Summer 007 Itroductio Ree descartes - aalysis (breaig dow) ad sythesis Sciece as models of ature : explaatory, parsimoious, predictive Most predictios require umerical values,
More informationMA131 - Analysis 1. Workbook 3 Sequences II
MA3 - Aalysis Workbook 3 Sequeces II Autum 2004 Cotets 2.8 Coverget Sequeces........................ 2.9 Algebra of Limits......................... 2 2.0 Further Useful Results........................
More informationLecture 6: Integration and the Mean Value Theorem. slope =
Math 8 Istructor: Padraic Bartlett Lecture 6: Itegratio ad the Mea Value Theorem Week 6 Caltech 202 The Mea Value Theorem The Mea Value Theorem abbreviated MVT is the followig result: Theorem. Suppose
More informationDupuy Complex Analysis Spring 2016 Homework 02
Dupuy Complex Aalysis Sprig 206 Homework 02. (CUNY, Fall 2005) Let D be the closed uit disc. Let g be a sequece of aalytic fuctios covergig uiformly to f o D. (a) Show that g coverges. Solutio We have
More informationA NOTE ON LEBESGUE SPACES
Volume 6, 1981 Pages 363 369 http://topology.aubur.edu/tp/ A NOTE ON LEBESGUE SPACES by Sam B. Nadler, Jr. ad Thelma West Topology Proceedigs Web: http://topology.aubur.edu/tp/ Mail: Topology Proceedigs
More informationSolutions to Math 347 Practice Problems for the final
Solutios to Math 347 Practice Problems for the fial 1) True or False: a) There exist itegers x,y such that 50x + 76y = 6. True: the gcd of 50 ad 76 is, ad 6 is a multiple of. b) The ifiimum of a set is
More informationSequences A sequence of numbers is a function whose domain is the positive integers. We can see that the sequence
Sequeces A sequece of umbers is a fuctio whose domai is the positive itegers. We ca see that the sequece 1, 1, 2, 2, 3, 3,... is a fuctio from the positive itegers whe we write the first sequece elemet
More information62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 +
62. Power series Defiitio 16. (Power series) Give a sequece {c }, the series c x = c 0 + c 1 x + c 2 x 2 + c 3 x 3 + is called a power series i the variable x. The umbers c are called the coefficiets of
More information6 Integers Modulo n. integer k can be written as k = qn + r, with q,r, 0 r b. So any integer.
6 Itegers Modulo I Example 2.3(e), we have defied the cogruece of two itegers a,b with respect to a modulus. Let us recall that a b (mod ) meas a b. We have proved that cogruece is a equivalece relatio
More information1 Lecture 2: Sequence, Series and power series (8/14/2012)
Summer Jump-Start Program for Aalysis, 202 Sog-Yig Li Lecture 2: Sequece, Series ad power series (8/4/202). More o sequeces Example.. Let {x } ad {y } be two bouded sequeces. Show lim sup (x + y ) lim
More informationA constructive analysis of convex-valued demand correspondence for weakly uniformly rotund and monotonic preference
MPRA Muich Persoal RePEc Archive A costructive aalysis of covex-valued demad correspodece for weakly uiformly rotud ad mootoic preferece Yasuhito Taaka ad Atsuhiro Satoh. May 04 Olie at http://mpra.ub.ui-mueche.de/55889/
More informationSequences, Series, and All That
Chapter Te Sequeces, Series, ad All That. Itroductio Suppose we wat to compute a approximatio of the umber e by usig the Taylor polyomial p for f ( x) = e x at a =. This polyomial is easily see to be 3
More informationEmpirical Processes: Glivenko Cantelli Theorems
Empirical Processes: Gliveko Catelli Theorems Mouliath Baerjee Jue 6, 200 Gliveko Catelli classes of fuctios The reader is referred to Chapter.6 of Weller s Torgo otes, Chapter??? of VDVW ad Chapter 8.3
More informationIntroduction to Probability. Ariel Yadin. Lecture 2
Itroductio to Probability Ariel Yadi Lecture 2 1. Discrete Probability Spaces Discrete probability spaces are those for which the sample space is coutable. We have already see that i this case we ca take
More informationComplex Analysis Spring 2001 Homework I Solution
Complex Aalysis Sprig 2001 Homework I Solutio 1. Coway, Chapter 1, sectio 3, problem 3. Describe the set of poits satisfyig the equatio z a z + a = 2c, where c > 0 ad a R. To begi, we see from the triagle
More information7.1 Convergence of sequences of random variables
Chapter 7 Limit Theorems Throughout this sectio we will assume a probability space (, F, P), i which is defied a ifiite sequece of radom variables (X ) ad a radom variable X. The fact that for every ifiite
More informationA sequence of numbers is a function whose domain is the positive integers. We can see that the sequence
Sequeces A sequece of umbers is a fuctio whose domai is the positive itegers. We ca see that the sequece,, 2, 2, 3, 3,... is a fuctio from the positive itegers whe we write the first sequece elemet as
More informationChapter 0. Review of set theory. 0.1 Sets
Chapter 0 Review of set theory Set theory plays a cetral role i the theory of probability. Thus, we will ope this course with a quick review of those otios of set theory which will be used repeatedly.
More informationMATH 413 FINAL EXAM. f(x) f(y) M x y. x + 1 n
MATH 43 FINAL EXAM Math 43 fial exam, 3 May 28. The exam starts at 9: am ad you have 5 miutes. No textbooks or calculators may be used durig the exam. This exam is prited o both sides of the paper. Good
More informationb i u x i U a i j u x i u x j
M ath 5 2 7 Fall 2 0 0 9 L ecture 1 9 N ov. 1 6, 2 0 0 9 ) S ecod- Order Elliptic Equatios: Weak S olutios 1. Defiitios. I this ad the followig two lectures we will study the boudary value problem Here
More informationSeries III. Chapter Alternating Series
Chapter 9 Series III With the exceptio of the Null Sequece Test, all the tests for series covergece ad divergece that we have cosidered so far have dealt oly with series of oegative terms. Series with
More informationMATH 205 HOMEWORK #2 OFFICIAL SOLUTION. (f + g)(x) = f(x) + g(x) = f( x) g( x) = (f + g)( x)
MATH 205 HOMEWORK #2 OFFICIAL SOLUTION Problem 2: Do problems 7-9 o page 40 of Hoffma & Kuze. (7) We will prove this by cotradictio. Suppose that W 1 is ot cotaied i W 2 ad W 2 is ot cotaied i W 1. The
More informationSequences I. Chapter Introduction
Chapter 2 Sequeces I 2. Itroductio A sequece is a list of umbers i a defiite order so that we kow which umber is i the first place, which umber is i the secod place ad, for ay atural umber, we kow which
More information