SSC MAINS (MATHS) MOCK TEST-1 (SOLUTION)

Size: px
Start display at page:

Download "SSC MAINS (MATHS) MOCK TEST-1 (SOLUTION)"

Transcription

1 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI-09 SSC MINS (MTHS) MOCK TEST- (SOLUTION). (B) Order of surds re,,. LCM of, nd is. So, convert ec surd into surd of order > 0 >. (C) ( 9) ( 8) 0 8, 9 y y y 0 y y y 0 0 (y ) (y ) 0 y, Now y 8.() Difference ( ) Sum Te required nswer (D) Let two digit numer e 0 y y () 0y 0 y or, y 9 () From eq n () & () 9 nd y Te required numer (B) Te required reminder d r r were, d te first divisor r te first reminder r te second reminder 6 Te required reminder (B) LCM of nd 7 Now, divide 00 y nd te quotient otined is te required numer of numers Tus, tere re 8 numers. 7.() Let te middle numer e. ccording to question, (D) Te required nswer 9.(C) Let frction e /y Now y y 9 7y () nd y y y () Now, eqution () eqution () 7 nd y 6 8 Sort cut Te required nswer smller vlue 66 8 y 6 0.(C) Let numer e. < < 96 < < 0 Numer will e etween 96 nd 0. Since one prt of te numer is te squre of 6 it mens one fctor is 6 LCM of 6 nd 80 P ,

2 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI-09 Numer will e multiple of 80 i.e Te only vlue wic stisfies te condition is 980..(C) Let te tree consecutive numers e, nd respectively. Difference etween first nd tird numer.() Let numers e, y, z. Ten y nd y z y z y z 9 0 y z So, second numer 0 0.(C) Numer of one digit pges from to 9 9 Numer two digit pges from 0 to Numer of tree digit pges from to 00 0 Totl numer of required figures (9 ) (90 ) (0 ) 9.() Required numer LCM of, 0 nd LCMof,, nd HCF of, 0nd.(B) LCM of 6, 7, 8, 9 nd 0 0 Te gretest numer of si digits is Dividing y 0, we get 079 s reminder. Hence te numer divisile y 0 is Since 6, 7, 8 6, 9 7, 0 8 te reminder in ec cse is less tn te divisor y. Te required numer (D) LCM of,,6,8, 0,, 0 Required numer 0 K ; K is positive integer. ) 0 ( K ( 9 ) K ( 9 K) (K ) For every vlue of K, ( 7 K) is lwys divisile y. Pulting vlue of K equl to,,,, --- etc. in succession, we find tt numer8. Lest vlue of K wic will mke (K )divisile y is 8. Te required numer (B) `dsfsd0-p -P Numer of coins Vlue 7.7 P , (B) Silver Copper st nd Mi (C) leps of ound 6 leps of re. 0.(B) 7 leps of ound 6 7 leps of re rte of ound rte of re 8 I E S B (7 8) (000 0) 000 's income B's income B 8 000

3 .(B) 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI-09 7 (lengt) unit/r St nd 7 r r Let fter t time t 7t t 6 t t 6 t 8t t 8 rs t r 0 min.() Lmn Gopl Lst yer Lst yer Present Yer Lmn / Gopl 6 Present yer Lmn Gopl 6 8 Lmn's Slry 60 8 `600. () B's profit ` ` 9 's profit ` 9 ` 0 's profit per mont ` 0 B's profit per mont ` 9 Teir cpitls re proportionl to teir profit, 's cpitl B cptitl Difference etween teir cpitls 7, ut te ctul difference is 00. 's cpitl 0 ` 0.() Houses contining only one person 0 60% Houses contining only mle 60 0 % Houses contining only one femle 60 8%. (D) Present ge of usnd nd wife 6 yers Present ge of usnd, wife nd cild 0 60 yers Present ge of cild (60 6) yers 6. (B) Let son's ge e, ten Kml's ge 0 yers Kml's ge t te time of mrrige (0 6) yers. 0 (0 6) or or yers. 7.(D) Let Mrked price nd cost price y 6 96 y y Required % 8.(C) 0% % % st I mont nd mont On tis e gets ( ) 0 00 In I st mont (B) Rtio of prts 0% % P , Difference etween gretest nd smllest 76 ( 0) ` 0 0. () Let mount lent t % (000 ) `.(B) SI for yers ` 00 SI for yer ` CI for yers SI for yers Interest on st yer's SI

4 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI (C) 900 P P ` 000 ` 0 6 CI Difference `.08.(D) Pyment is qurterly, so r %, t 8 yers Required nswer.() 0% P.() 6.(B) 7.(B) ` Totl interest 60 0 ` 90 I 6% 6% II 8% fter tking out 0 litres of miture B B 0 0 Mke equl ecuse it is not cnging. Miture s initil quntity () 0 0 's quntity C B 0 8 Litre 8 B C 9 B, C, ( B C)'s dy work unit dy's work unit will tke 8 dys B will tke 6 dys C will tke 8 dys 8.() is times s fst s B. It mens if does work in dy ten B will do in dys. 60 Totl 60 dys B 9.(B) Required time 9 6 minutes 0.(B) Totl time 8.(C).(B) 8 60 ours ours min 8 ours min P Q R - Time tken y to rec R from P Time tken y B to rec Q nd return from Q to R km P , of totl time in trin ours Totl time in trin ours Totl time spent in ir 8 ours By ir, in rs distnce trvelled 00 Km in ours, distnce trvelled Km Distnce covered y trin km So, te required rtio 00

5 .(B) 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI-09 Let originl speed e km/our. ( ) ( ) 7 Km/our. () Let distnce etween Deli nd Knpur is. Let trin leving from Deli is nd from Knpur is B. 's speed 0m m B's speed pm 7m Km/our 7 Km/our Distnce covered y till 7 m Km / () / 7.(D) z z sin sin sin sin sin sin sin sin sin sin sin sin sin sin sin sin z sin sin z sin sin sin Remining Distnce Km Reltive speed Km/our 7 Time tken y ot trins to cover te distnce 7 ours ours min Te two trins will meet t 7 m our min 8 m.(c) tn tn ( B B) tn ( B) tn ( B) tn ( B) tn ( B). sin 90º 6.(D) Tke º y 8.() sin z sin cos z sin z cos sin z cosec cot sin y sin y y sin y sin y sin y sin sin cosy cos sin y sin cosy cos sin y sin cosy cos sin y sin cosy cos sin y sin cosy cos sin y tn tn y 9. (D) cosec y y ( y) / ( y ) / cot cosec / /. cot y y P ,

6 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI-09 cot cot y y y y cot y y 0.(C) ( cot cosec ) ( tn Sec ) Put º, (cot º cosec º) ( tnº sec º) ( ) ( ) ( ) ( ).(C) sin sin.. sin. cos ( sin sin ) cos sin cos cos cos cos 0 cos cos cos 0 cos (cos ) (cos ) 0 ( cos ) (cos ) 0 cos or.(d) sin º sin 0º sin º --- sin 8º sin 90º sin º sin 8º sin 0º sin 80º. () sin º sin 90º So, 8 9 tn 60 tn 60 θ θ 60 60m tn tn tn.(b) P , m Let speeds re nd 9 m/s lengt of I st trin m lengt of II nd trin 9 m Time to cross ec oter Sumof lengts Sumof speeds 9 70 sec.() P Q R I cn row from P to R in ours. I cn row from P to Q in ours. I cn row from P to Q nd ck in 0 ours. I cn row from Q to P in (0 ) 8 ours Hence in rowing wit te current, I tkes ours nd in rowing ginst te current, I tkes 8 ours. Te distnce is sme, terefore, down rte nd te up rte re inversely proportionl to te times. down rte up rte 8 speed of ot in still wter speed of river 6.(C) B C (mke B equl) In 0 m rce, cn et C y m. In m rce, cn et C y 9 m

7 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI-09 7.(C) Now, 8.(C) ( ) 9.(B) / / By compring 9 60.(C).. 8 Now, (B) If y z, y z, z y y z y y y y z y y z z z z (from given condition) 6.(B) c c c c c c c c c c c z y z c c c c c c c c c P ,

8 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI-09 c 68. (B) Boys Girls c 6.() Ceck troug options. Wen ( c) c c c c c c c c c c c c c c c c c c c (c) 6.(C) Let numers e 7 nd 7y, were nd y re co-primes. LCM of 7 nd 7y 7y ccording to te question, 7y 7 y nd y 7 or 7 nd y 6 First numer Second numer Sum of numers (C) ( 6) ( ) 0 6, ecuse cn't e considered 66.() ( ) 6 ( 6 6) 6 8 wic is divisile y () y y 7 y K y K y 7K ( y) ( y) 9 K K y 8 K 6 K 8 K K 68 8 % of oys in clss 60% 69.(B) Percentge of fmilies ving eiter cow or ufflo or ot % It mens % of fmilies do not ve eiter cow or ufflo Required numer of fmilies % of (D) Let totl votes 96 Vlid votes % % % % 0% of votes 7.(B) Rtio of cpitl investment B C,000 0,000,000 6 Let totl profit e. get 0% for mngement Remining profit 70% 7.() 000 s sre 0 70 % (BC) s sre % Wen, difference 0, ten totl profit Wen difference ` 00, ten totl profit 0 ` 000 0% % 0 o r 0,800 0% or 000 ` y K 7.(B) Present wort P P , T R

9 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI ` () ccording to question, M W B M D M D (M W B) 7 B D (B B B) 7 B D D 9 dy 7.(D) 76.(C) r O r C r r r D B OCD is equilterl tringle. COD 60º CBD 0º (Property) CB 90º BCP 80º 90º In CBP BCP CBP CPB 80º 90º 0º CPB 80º CPB 60º nd PB 60º N B T P 78. (*) 79.(B) VT DM V D T M 6 M M TM 6 CDM CBT CD BD CM TM CM 6 CM 6 TC CM TM 6 6 B P D C B C D is mid point of C P B D (Property) P B P B B M P PB B PB P 77.(C) D C If re TM, ten re MN re BPM 8 re MNP 8 re MTP TM TMP V T M B B 80.(C) sin cos 7 sin sin 7 sin sin 8 0 sin sin 0 sin 8 0 sin (sin ) (sin ) 0 ( sin ) ( sin ) 0 sin cot B D C T 6 (Given) P ,

10 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI (B) Let sides e,, (D) inrdius S 7 tn 60º S 6 0 Smllest ltitude will e on te longest side re of 6 re of regulr egon 6 8. (B) 6 D 0º 0 In DEC E 6 C sin 0º EC CD EC 0 EC cos 0º ED CD ED 0 ED In ECB EB BC EC EB 6 EB 6 EB EB BD ED EB BD 6 6. B ( ) m cm. Red; "Heigt nd se rdius of te cone re sme" of te question s "Heigt nd se rdius of te cone re respectively equl to te eigt nd se rdius of te cylinder" 8.(B) l 8 l 6 l r 8 cm cm l 89 l 7 cm Totl surfce re r r rl [ ] 0 cm 8.(D) R cm H cm BC DE D r B C R r r E P ,

11 86.() 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI-09 r Volume of frustrum (R r Rr) 0 7 ( r)( r r) ( r) ( r r) ( r) ( r r) r r r 0 r 0 cm 88. (B) Let Mn cn do unit work in dy, ten 0 men will do in 0 dys unit work. Dys Men Work Totl dys 0 89.() Rtio of efficiency B C Working togeter tey will empty in ours 9 units 9 E In 6 ours 0 min 0 ours, tey will. empty units B 6 BC D EDC BC m C l C B BC 8 m Lterl surfce re rl m 87.(B) re covered y roller in one revolution r cm Let totl re e 88% of 88 60,000 cm Totl cost of levelling.. 60,000 ` 0000 will empty te pool in (C) If (sin cos ), y (sin cos ) Now, y ours. (sin cos ) (sin cos ) sin cos sin cos sin cos sin cos 9.(C) Required nswer 0 (0 ) 60 lks 9.(D) Percentge vrition Model Model B Model C () Required difference % % % P ,

12 007, OUTRM LINES, ST FLOOR, OPPOSITE MUKHERJEE NGR POLICE STTION, DELHI lks (B) Required production 0 lks (C) Required nswer lks (D) % 60º % 60 º 60º 0 0% 6º 97.(B) % Totl cost ` 700 % of totl cost ` 700 ` (C) Difference in percent cost of inding nd cutting crges nd roylty (8 )% % % of totl cost ` 6000 % of totl cost ` 6000 ` (B) Difference in percent epenses on printing cost nd dvertisement crges ( 8)% 7% Now, %.6º 7%.6º 7 6.º.(B) Te required percentge 0 8.6% (ppro.) SSC MINS(MTHS) MOCK TEST- (NSWER KEY). (B). (C). (). (D). (B) 6. (B) 7. () 8. (B) 9. (C) 0. (C). (C). (). (C). (). (B) 6. (D) 7. (B) 8. (B) 9. (C) 0. (B). (B). (). (). (). (D) 6. (B) 7. (D) 8. (C) 9. (B) 0. (). (B). (C). (D). (). () 6. (C) 7. (B) 8. () 9. (B) 0. (B). (C). (B). (B). (). (C) 6. (D) 7. (D) 8. () 9. (D) 0. (C). (C). (D). (). (B). () 6. (C) 7. (C) 8. (C) 9. (B) 60. (C) 6. (B) 6. (B) 6. () 6. (C) 6. (C) 66. () 67. () 68. (B) 69. (B) 70. (D) 7. (B) 7. () 7. (B) 7. () 7. (D) 76. (C) 77. (C) 78. (*) 79. (B) 80. (C) 8. (D) 8. (B) 8. (B) 8. (B) 8. (D) 86. () 87. (B) 88. (B) 89. () 90. (C) 9. (C) 9. (D) 9. () 9. (B) 9. (C) 96. (D) 97. (B) 98. (C) 99. (B). (B) P ,

SSC Mains Mock Test 227 [Answer with Solution]

SSC Mains Mock Test 227 [Answer with Solution] SS Mins Mock Test 7 [nswer with Solution]. (D) E ccording to question, G 00 00 8 0 G GF, F D Let, GF GF Now, eterior ngle FGE FGE FEG Now, eterior ngle D In DE, + + 80º 80º 7 5º (ppro.). () I st digit

More information

1 (=0.5) I3 a 7 I4 a 15 I5 a (=0.5) c 4 N 10 1 (=0.5) N 6 A 52 S 2

1 (=0.5) I3 a 7 I4 a 15 I5 a (=0.5) c 4 N 10 1 (=0.5) N 6 A 52 S 2 Answers: (98-84 HKMO Finl Events) Creted by Mr. Frncis Hung Lst updted: December 05 Individul Events SI 900 I 0 I (=0.5) I 7 I4 5 I5 80 b 7 b b 5 b 6 b 8 b 4 c c 4 c 0 x (=0.5) c 4 N 0 d 9 d 5 d 5 y d

More information

LCM AND HCF. Type - I. Type - III. Type - II

LCM AND HCF. Type - I. Type - III. Type - II LCM AND HCF Type - I. The HCF nd LCM of two numbers re nd 9 respectively. Then the number of such pirs () 0 () () (SSC CGL Tier-I Exm. 0 Second Sitting). The product of two numbers 08 nd their HCF. The

More information

Minnesota State University, Mankato 44 th Annual High School Mathematics Contest April 12, 2017

Minnesota State University, Mankato 44 th Annual High School Mathematics Contest April 12, 2017 Minnesot Stte University, Mnkto 44 th Annul High School Mthemtics Contest April, 07. A 5 ft. ldder is plced ginst verticl wll of uilding. The foot of the ldder rests on the floor nd is 7 ft. from the wll.

More information

Each term is formed by adding a constant to the previous term. Geometric progression

Each term is formed by adding a constant to the previous term. Geometric progression Chpter 4 Mthemticl Progressions PROGRESSION AND SEQUENCE Sequence A sequence is succession of numbers ech of which is formed ccording to definite lw tht is the sme throughout the sequence. Arithmetic Progression

More information

15 - TRIGONOMETRY Page 1 ( Answers at the end of all questions )

15 - TRIGONOMETRY Page 1 ( Answers at the end of all questions ) - TRIGONOMETRY Pge P ( ) In tringle PQR, R =. If tn b c = 0, 0, then Q nd tn re the roots of the eqution = b c c = b b = c b = c [ AIEEE 00 ] ( ) In tringle ABC, let C =. If r is the inrdius nd R is the

More information

Chapter 2 Differentiation

Chapter 2 Differentiation Cpter Differentition. Introduction In its initil stges differentition is lrgely mtter of finding limiting vlues, wen te vribles ( δ ) pproces zero, nd to begin tis cpter few emples will be tken. Emple..:

More information

Trigonometric Functions

Trigonometric Functions Exercise. Degrees nd Rdins Chpter Trigonometric Functions EXERCISE. Degrees nd Rdins 4. Since 45 corresponds to rdin mesure of π/4 rd, we hve: 90 = 45 corresponds to π/4 or π/ rd. 5 = 7 45 corresponds

More information

Downloaded From:

Downloaded From: Downloded From: www.jsuniltutoril.weel.com UNIT-3 PAIR OF LINEAR EQUATIONS IN TWO VARIABLES Like the crest of pecock so is mthemtics t the hed of ll knowledge.. At certin time in deer prk, the numer of

More information

HYPERBOLA. AIEEE Syllabus. Total No. of questions in Ellipse are: Solved examples Level # Level # Level # 3..

HYPERBOLA. AIEEE Syllabus. Total No. of questions in Ellipse are: Solved examples Level # Level # Level # 3.. HYPERBOLA AIEEE Sllus. Stndrd eqution nd definitions. Conjugte Hperol. Prmetric eqution of te Hperol. Position of point P(, ) wit respect to Hperol 5. Line nd Hperol 6. Eqution of te Tngent Totl No. of

More information

10 If 3, a, b, c, 23 are in A.S., then a + b + c = 15 Find the perimeter of the sector in the figure. A. 1:3. A. 2.25cm B. 3cm

10 If 3, a, b, c, 23 are in A.S., then a + b + c = 15 Find the perimeter of the sector in the figure. A. 1:3. A. 2.25cm B. 3cm HK MTHS Pper II P. If f ( x ) = 0 x, then f ( y ) = 6 0 y 0 + y 0 y 0 8 y 0 y If s = ind the gretest vlue of x + y if ( x, y ) is point lying in the region O (including the boundry). n [ + (n )d ], then

More information

Level I MAML Olympiad 2001 Page 1 of 6 (A) 90 (B) 92 (C) 94 (D) 96 (E) 98 (A) 48 (B) 54 (C) 60 (D) 66 (E) 72 (A) 9 (B) 13 (C) 17 (D) 25 (E) 38

Level I MAML Olympiad 2001 Page 1 of 6 (A) 90 (B) 92 (C) 94 (D) 96 (E) 98 (A) 48 (B) 54 (C) 60 (D) 66 (E) 72 (A) 9 (B) 13 (C) 17 (D) 25 (E) 38 Level I MAML Olympid 00 Pge of 6. Si students in smll clss took n em on the scheduled dte. The verge of their grdes ws 75. The seventh student in the clss ws ill tht dy nd took the em lte. When her score

More information

A P P E N D I X POWERS OF TEN AND SCIENTIFIC NOTATION A P P E N D I X SIGNIFICANT FIGURES

A P P E N D I X POWERS OF TEN AND SCIENTIFIC NOTATION A P P E N D I X SIGNIFICANT FIGURES A POWERS OF TEN AND SCIENTIFIC NOTATION In science, very lrge nd very smll deciml numbers re conveniently expressed in terms of powers of ten, some of wic re listed below: 0 3 0 0 0 000 0 3 0 0 0 0.00

More information

USA Mathematical Talent Search Round 1 Solutions Year 21 Academic Year

USA Mathematical Talent Search Round 1 Solutions Year 21 Academic Year 1/1/21. Fill in the circles in the picture t right with the digits 1-8, one digit in ech circle with no digit repeted, so tht no two circles tht re connected by line segment contin consecutive digits.

More information

Alg. Sheet (1) Department : Math Form : 3 rd prep. Sheet

Alg. Sheet (1) Department : Math Form : 3 rd prep. Sheet Ciro Governorte Nozh Directorte of Eduction Nozh Lnguge Schools Ismili Rod Deprtment : Mth Form : rd prep. Sheet Alg. Sheet () [] Find the vlues of nd in ech of the following if : ) (, ) ( -5, 9 ) ) (,

More information

FORM FIVE ADDITIONAL MATHEMATIC NOTE. ar 3 = (1) ar 5 = = (2) (2) (1) a = T 8 = 81

FORM FIVE ADDITIONAL MATHEMATIC NOTE. ar 3 = (1) ar 5 = = (2) (2) (1) a = T 8 = 81 FORM FIVE ADDITIONAL MATHEMATIC NOTE CHAPTER : PROGRESSION Arithmetic Progression T n = + (n ) d S n = n [ + (n )d] = n [ + Tn ] S = T = T = S S Emple : The th term of n A.P. is 86 nd the sum of the first

More information

ICSE Board Class IX Mathematics Paper 4 Solution

ICSE Board Class IX Mathematics Paper 4 Solution ICSE Bord Clss IX Mthemtics Pper Solution SECTION A (0 Mrks) Q.. () Consider x y 6 5 5 x y 6 5 5 0 6 0 6 x y 6 50 8 5 6 7 6 x y 6 7 6 x y 6 x 7,y (b) Dimensions of the brick: Length (l) = 0 cm, bredth

More information

1. If * is the operation defined by a*b = a b for a, b N, then (2 * 3) * 2 is equal to (A) 81 (B) 512 (C) 216 (D) 64 (E) 243 ANSWER : D

1. If * is the operation defined by a*b = a b for a, b N, then (2 * 3) * 2 is equal to (A) 81 (B) 512 (C) 216 (D) 64 (E) 243 ANSWER : D . If * is the opertion defined by *b = b for, b N, then ( * ) * is equl to (A) 8 (B) 5 (C) 6 (D) 64 (E) 4. The domin of the function ( 9)/( ),if f( ) = is 6, if = (A) (0, ) (B) (-, ) (C) (-, ) (D) (, )

More information

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART I MULTIPLE CHOICE NO CALCULATORS 90 MINUTES

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART I MULTIPLE CHOICE NO CALCULATORS 90 MINUTES THE 08 09 KENNESW STTE UNIVERSITY HIGH SHOOL MTHEMTIS OMPETITION PRT I MULTIPLE HOIE For ech of the following questions, crefully blcken the pproprite box on the nswer sheet with # pencil. o not fold,

More information

Year 12 Trial Examination Mathematics Extension 1. Question One 12 marks (Start on a new page) Marks

Year 12 Trial Examination Mathematics Extension 1. Question One 12 marks (Start on a new page) Marks THGS Mthemtics etension Tril 00 Yer Tril Emintion Mthemtics Etension Question One mrks (Strt on new pge) Mrks ) If P is the point (-, 5) nd Q is the point (, -), find the co-ordintes of the point R which

More information

QUADRATIC EQUATIONS OBJECTIVE PROBLEMS

QUADRATIC EQUATIONS OBJECTIVE PROBLEMS QUADRATIC EQUATIONS OBJECTIVE PROBLEMS +. The solution of the eqution will e (), () 0,, 5, 5. The roots of the given eqution ( p q) ( q r) ( r p) 0 + + re p q r p (), r p p q, q r p q (), (d), q r p q.

More information

This chapter will show you. What you should already know. 1 Write down the value of each of the following. a 5 2

This chapter will show you. What you should already know. 1 Write down the value of each of the following. a 5 2 1 Direct vrition 2 Inverse vrition This chpter will show you how to solve prolems where two vriles re connected y reltionship tht vries in direct or inverse proportion Direct proportion Inverse proportion

More information

fractions Let s Learn to

fractions Let s Learn to 5 simple lgebric frctions corne lens pupil retin Norml vision light focused on the retin concve lens Shortsightedness (myopi) light focused in front of the retin Corrected myopi light focused on the retin

More information

Log1 Contest Round 3 Theta Individual. 4 points each 1 What is the sum of the first 5 Fibonacci numbers if the first two are 1, 1?

Log1 Contest Round 3 Theta Individual. 4 points each 1 What is the sum of the first 5 Fibonacci numbers if the first two are 1, 1? 008 009 Log1 Contest Round Thet Individul Nme: points ech 1 Wht is the sum of the first Fiboncci numbers if the first two re 1, 1? If two crds re drwn from stndrd crd deck, wht is the probbility of drwing

More information

SSC [PRE+MAINS] Mock Test 131 [Answer with Solution]

SSC [PRE+MAINS] Mock Test 131 [Answer with Solution] SS [PRE+MINS] Mock Test [nswe with Solution]. () Put 0 in the given epession we get, LHS 0 0. () Given. () Putting nd b in b + bc + c 0 we get, + c 0 c /, b, c / o,, b, c. () bc b c c b 0. b b b b nd hee,

More information

SSC (Tier-II) (Mock Test Paper - 2) [SOLUTION]

SSC (Tier-II) (Mock Test Paper - 2) [SOLUTION] SS (Tier-II) - 0 (Mock Test Paper - ) [SOLUTION]. () 7 7 7 7 7 8 8 7 8 7 7 9 R R 8 8 8. (D) Let the first odd integer the second odd integer + Difference between the squares of these two consecutive odd

More information

3 x x 3x x. 3x x x 6 x 3. PAKTURK 8 th National Interschool Maths Olympiad, h h

3 x x 3x x. 3x x x 6 x 3. PAKTURK 8 th National Interschool Maths Olympiad, h h PAKTURK 8 th Ntionl Interschool Mths Olmpid,.9. Q: Evlute 6.9. 6 6 6... 8 8...... Q: Evlute bc bc. b. c bc.9.9b.9.9bc Q: Find the vlue of h in the eqution h 7 9 7.. bc. bc bc. b. c bc bc bc bc......9 h

More information

Thomas Whitham Sixth Form

Thomas Whitham Sixth Form Thoms Whithm Sith Form Pure Mthemtics Unit C Alger Trigonometry Geometry Clculus Vectors Trigonometry Compound ngle formule sin sin cos cos Pge A B sin Acos B cos Asin B A B sin Acos B cos Asin B A B cos

More information

If C = 60 and = P, find the value of P. c 2 = a 2 + b 2 2abcos 60 = a 2 + b 2 ab a 2 + b 2 = c 2 + ab. c a

If C = 60 and = P, find the value of P. c 2 = a 2 + b 2 2abcos 60 = a 2 + b 2 ab a 2 + b 2 = c 2 + ab. c a Answers: (000-0 HKMO Finl Events) Creted : Mr. Frncis Hung Lst updted: 0 June 08 Individul Events I P I P I P I P 5 7 0 0 S S S S Group Events G G G G 80 00 0 c 8 c c c d d 6 d 5 d 85 Individul Event I.,

More information

Section 2.1 Special Right Triangles

Section 2.1 Special Right Triangles Se..1 Speil Rigt Tringles 49 Te --90 Tringle Setion.1 Speil Rigt Tringles Te --90 tringle (or just 0-60-90) is so nme euse of its ngle mesures. Te lengts of te sies, toug, ve very speifi pttern to tem

More information

PLK VICWOOD K.T. CHONG SIXTH FORM COLLEGE Form Six AL Physics Optical instruments

PLK VICWOOD K.T. CHONG SIXTH FORM COLLEGE Form Six AL Physics Optical instruments AL Pysics/pticl instruments/p.1 PLK VICW K.T. CHNG SIXTH FRM CLLEGE Form Six AL Pysics pticl Instruments pticl instruments Mgniying glss Microscope Rercting telescope Grting spectrometer Qulittive understnding

More information

MASTER CLASS PROGRAM UNIT 4 SPECIALIST MATHEMATICS WEEK 11 WRITTEN EXAMINATION 2 SOLUTIONS SECTION 1 MULTIPLE CHOICE QUESTIONS

MASTER CLASS PROGRAM UNIT 4 SPECIALIST MATHEMATICS WEEK 11 WRITTEN EXAMINATION 2 SOLUTIONS SECTION 1 MULTIPLE CHOICE QUESTIONS MASTER CLASS PROGRAM UNIT 4 SPECIALIST MATHEMATICS WEEK WRITTEN EXAMINATION SOLUTIONS FOR ERRORS AND UPDATES, PLEASE VISIT WWW.TSFX.COM.AU/MC-UPDATES SECTION MULTIPLE CHOICE QUESTIONS QUESTION QUESTION

More information

Problem Set 9. Figure 1: Diagram. This picture is a rough sketch of the 4 parabolas that give us the area that we need to find. The equations are:

Problem Set 9. Figure 1: Diagram. This picture is a rough sketch of the 4 parabolas that give us the area that we need to find. The equations are: (x + y ) = y + (x + y ) = x + Problem Set 9 Discussion: Nov., Nov. 8, Nov. (on probbility nd binomil coefficients) The nme fter the problem is the designted writer of the solution of tht problem. (No one

More information

Set 6 Paper 2. Set 6 Paper 2. 1 Pearson Education Asia Limited 2017

Set 6 Paper 2. Set 6 Paper 2. 1 Pearson Education Asia Limited 2017 Set 6 Pper Set 6 Pper. C. C. A. D. B 6. D 7. D 8. A 9. D 0. A. B. B. A. B. B 6. B 7. D 8. C 9. D 0. D. A. A. B. B. C 6. C 7. A 8. B 9. A 0. A. C. D. B. B. B 6. A 7. D 8. A 9. C 0. C. C. D. C. C. D Section

More information

Review Exercises for Chapter 4

Review Exercises for Chapter 4 _R.qd // : PM Pge CHAPTER Integrtion Review Eercises for Chpter In Eercises nd, use the grph of to sketch grph of f. To print n enlrged cop of the grph, go to the wesite www.mthgrphs.com... In Eercises

More information

Exam 1 Solutions (1) C, D, A, B (2) C, A, D, B (3) C, B, D, A (4) A, C, D, B (5) D, C, A, B

Exam 1 Solutions (1) C, D, A, B (2) C, A, D, B (3) C, B, D, A (4) A, C, D, B (5) D, C, A, B PHY 249, Fll 216 Exm 1 Solutions nswer 1 is correct for ll problems. 1. Two uniformly chrged spheres, nd B, re plced t lrge distnce from ech other, with their centers on the x xis. The chrge on sphere

More information

Adding and Subtracting Rational Expressions

Adding and Subtracting Rational Expressions 6.4 Adding nd Subtrcting Rtionl Epressions Essentil Question How cn you determine the domin of the sum or difference of two rtionl epressions? You cn dd nd subtrct rtionl epressions in much the sme wy

More information

Trigonometric Functions

Trigonometric Functions Trget Publictions Pvt. Ltd. Chpter 0: Trigonometric Functions 0 Trigonometric Functions. ( ) cos cos cos cos (cos + cos ) Given, cos cos + 0 cos (cos + cos ) + ( ) 0 cos cos cos + 0 + cos + (cos cos +

More information

CET MATHEMATICS 2013

CET MATHEMATICS 2013 CET MATHEMATICS VERSION CODE: C. If sin is the cute ngle between the curves + nd + 8 t (, ), then () () () Ans: () Slope of first curve m ; slope of second curve m - therefore ngle is o A sin o (). The

More information

A LEVEL TOPIC REVIEW. factor and remainder theorems

A LEVEL TOPIC REVIEW. factor and remainder theorems A LEVEL TOPIC REVIEW unit C fctor nd reminder theorems. Use the Fctor Theorem to show tht: ) ( ) is fctor of +. ( mrks) ( + ) is fctor of ( ) is fctor of + 7+. ( mrks) +. ( mrks). Use lgebric division

More information

Believethatyoucandoitandyouar. Mathematics. ngascannotdoonlynotyetbelieve thatyoucandoitandyouarehalfw. Algebra

Believethatyoucandoitandyouar. Mathematics. ngascannotdoonlynotyetbelieve thatyoucandoitandyouarehalfw. Algebra Believethtoucndoitndour ehlfwtherethereisnosuchthi Mthemtics ngscnnotdoonlnotetbelieve thtoucndoitndourehlfw Alger therethereisnosuchthingsc nnotdoonlnotetbelievethto Stge 6 ucndoitndourehlfwther S Cooper

More information

( ) Same as above but m = f x = f x - symmetric to y-axis. find where f ( x) Relative: Find where f ( x) x a + lim exists ( lim f exists.

( ) Same as above but m = f x = f x - symmetric to y-axis. find where f ( x) Relative: Find where f ( x) x a + lim exists ( lim f exists. AP Clculus Finl Review Sheet solutions When you see the words This is wht you think of doing Find the zeros Set function =, fctor or use qudrtic eqution if qudrtic, grph to find zeros on clcultor Find

More information

(e) if x = y + z and a divides any two of the integers x, y, or z, then a divides the remaining integer

(e) if x = y + z and a divides any two of the integers x, y, or z, then a divides the remaining integer Divisibility In this note we introduce the notion of divisibility for two integers nd b then we discuss the division lgorithm. First we give forml definition nd note some properties of the division opertion.

More information

SSC Mains Mock Test 226 [Answer with Solution]

SSC Mains Mock Test 226 [Answer with Solution] SS Mins Mock Test [nswe with Solution]. () Requied weight +.. () The sum of ges of the two olde plyes 0 + yes vege ge incesed months So, totl ge incesed months Sum of the ges of two new plyes yes + months

More information

Pre-Calculus TMTA Test 2018

Pre-Calculus TMTA Test 2018 . For the function f ( x) ( x )( x )( x 4) find the verge rte of chnge from x to x. ) 70 4 8.4 8.4 4 7 logb 8. If logb.07, logb 4.96, nd logb.60, then ).08..867.9.48. For, ) sec (sin ) is equivlent to

More information

Use of Trigonometric Functions

Use of Trigonometric Functions Unit 03 Use of Trigonometric Functions 1. Introduction Lerning Ojectives of tis UNIT 1. Lern ow te trigonometric functions re relted to te rtios of sides of rigt ngle tringle. 2. Be le to determine te

More information

List all of the possible rational roots of each equation. Then find all solutions (both real and imaginary) of the equation. 1.

List all of the possible rational roots of each equation. Then find all solutions (both real and imaginary) of the equation. 1. Mth Anlysis CP WS 4.X- Section 4.-4.4 Review Complete ech question without the use of grphing clcultor.. Compre the mening of the words: roots, zeros nd fctors.. Determine whether - is root of 0. Show

More information

Set 1 Paper 2. 1 Pearson Education Asia Limited 2017

Set 1 Paper 2. 1 Pearson Education Asia Limited 2017 . A. A. C. B. C 6. A 7. A 8. B 9. C. D. A. B. A. B. C 6. D 7. C 8. B 9. C. D. C. A. B. A. A 6. A 7. A 8. D 9. B. C. B. D. D. D. D 6. D 7. B 8. C 9. C. D. B. B. A. D. C Section A. A (68 ) [ ( ) n ( n 6n

More information

Mathematics. Area under Curve.

Mathematics. Area under Curve. Mthemtics Are under Curve www.testprepkrt.com Tle of Content 1. Introduction.. Procedure of Curve Sketching. 3. Sketching of Some common Curves. 4. Are of Bounded Regions. 5. Sign convention for finding

More information

Section 6: Area, Volume, and Average Value

Section 6: Area, Volume, and Average Value Chpter The Integrl Applied Clculus Section 6: Are, Volume, nd Averge Vlue Are We hve lredy used integrls to find the re etween the grph of function nd the horizontl xis. Integrls cn lso e used to find

More information

PRE-BOARD MATHEMATICS-1st (Held on 26 December 2017)

PRE-BOARD MATHEMATICS-1st (Held on 26 December 2017) P-B M 7-8 PRE-BOARD MATHEMATICS-st (Held n 6 Decemer 07) ANSWER KEY (FULL SYLLABUS) M.M : 80 Generl Instructins:. The questin pper cmprises f fur sectins, A, B, C & D.. All questins re cmpulsry.. Sectin

More information

Pre Regional Mathematical Olympiad, 2016 Delhi Region Set C

Pre Regional Mathematical Olympiad, 2016 Delhi Region Set C Pre Regionl Mthemticl Olympid, 06 Delhi Region Set C Mimum Mrks: 50 Importnt Note: The nswer to ech question is n integer between 0 nd 06. Ech Cndidte must write the finl nswer (in the spce provided) s,

More information

DEEPAWALI ASSIGNMENT

DEEPAWALI ASSIGNMENT DEEPWLI SSIGNMENT CLSS & DOPPE FO TGET IIT JEE Get Solution & Video Tutorils online www.mthsbysuhg.com Downlod FEE Study Pckges, Test Series from w ww.tekoclsses.com Bhopl : Phone : (0755) 00 000 Wishing

More information

MAT 1275: Introduction to Mathematical Analysis

MAT 1275: Introduction to Mathematical Analysis 1 MT 1275: Intrdutin t Mtemtil nlysis Dr Rzenlyum Slving Olique Tringles Lw f Sines Olique tringles tringles tt re nt neessry rigt tringles We re ging t slve tem It mens t find its si elements sides nd

More information

Form 5 HKCEE 1990 Mathematics II (a 2n ) 3 = A. f(1) B. f(n) A. a 6n B. a 8n C. D. E. 2 D. 1 E. n. 1 in. If 2 = 10 p, 3 = 10 q, express log 6

Form 5 HKCEE 1990 Mathematics II (a 2n ) 3 = A. f(1) B. f(n) A. a 6n B. a 8n C. D. E. 2 D. 1 E. n. 1 in. If 2 = 10 p, 3 = 10 q, express log 6 Form HK 9 Mthemtics II.. ( n ) =. 6n. 8n. n 6n 8n... +. 6.. f(). f(n). n n If = 0 p, = 0 q, epress log 6 in terms of p nd q.. p q. pq. p q pq p + q Let > b > 0. If nd b re respectivel the st nd nd terms

More information

Special Numbers, Factors and Multiples

Special Numbers, Factors and Multiples Specil s, nd Student Book - Series H- + 3 + 5 = 9 = 3 Mthletics Instnt Workooks Copyright Student Book - Series H Contents Topics Topic - Odd, even, prime nd composite numers Topic - Divisiility tests

More information

3.1 Review of Sine, Cosine and Tangent for Right Angles

3.1 Review of Sine, Cosine and Tangent for Right Angles Foundtions of Mth 11 Section 3.1 Review of Sine, osine nd Tngent for Right Tringles 125 3.1 Review of Sine, osine nd Tngent for Right ngles The word trigonometry is derived from the Greek words trigon,

More information

SSC MAINS (MATHS) MOCK TEST-14 (SOLUTION)

SSC MAINS (MATHS) MOCK TEST-14 (SOLUTION) SSC MINS (MTHS) MOCK TEST- (SOLUTION). () b c a a c b b c a a c b 0 a b c a b c. (C) y hours 8 min 8 60 5 hrs. b c a a a c b b a b c 0 c hours 0 min 0 60 0 hrs. (a b c) a b c 0 V V T T /5 0 / 6 5 6 5 a

More information

8Similarity UNCORRECTED PAGE PROOFS. 8.1 Kick off with CAS 8.2 Similar objects 8.3 Linear scale factors. 8.4 Area and volume scale factors 8.

8Similarity UNCORRECTED PAGE PROOFS. 8.1 Kick off with CAS 8.2 Similar objects 8.3 Linear scale factors. 8.4 Area and volume scale factors 8. 8.1 Kick off with S 8. Similr ojects 8. Liner scle fctors 8Similrity 8. re nd volume scle fctors 8. Review U N O R R E TE D P G E PR O O FS 8.1 Kick off with S Plese refer to the Resources t in the Prelims

More information

Pythagorean Theorem and Trigonometry

Pythagorean Theorem and Trigonometry Ptgoren Teorem nd Trigonometr Te Ptgoren Teorem is nient, well-known, nd importnt. It s lrge numer of different proofs, inluding one disovered merin President Jmes. Grfield. Te we site ttp://www.ut-te-knot.org/ptgors/inde.stml

More information

MATHEMATICS PART A. 1. ABC is a triangle, right angled at A. The resultant of the forces acting along AB, AC

MATHEMATICS PART A. 1. ABC is a triangle, right angled at A. The resultant of the forces acting along AB, AC FIITJEE Solutions to AIEEE MATHEMATICS PART A. ABC is tringle, right ngled t A. The resultnt of the forces cting long AB, AC with mgnitudes AB nd respectively is the force long AD, where D is the AC foot

More information

than 1. It means in particular that the function is decreasing and approaching the x-

than 1. It means in particular that the function is decreasing and approaching the x- 6 Preclculus Review Grph the functions ) (/) ) log y = b y = Solution () The function y = is n eponentil function with bse smller thn It mens in prticulr tht the function is decresing nd pproching the

More information

JEE(MAIN) 2015 TEST PAPER WITH SOLUTION (HELD ON SATURDAY 04 th APRIL, 2015) PART B MATHEMATICS

JEE(MAIN) 2015 TEST PAPER WITH SOLUTION (HELD ON SATURDAY 04 th APRIL, 2015) PART B MATHEMATICS JEE(MAIN) 05 TEST PAPER WITH SOLUTION (HELD ON SATURDAY 0 th APRIL, 05) PART B MATHEMATICS CODE-D. Let, b nd c be three non-zero vectors such tht no two of them re colliner nd, b c b c. If is the ngle

More information

Average Rate of Change (AROC) The average rate of change of y over an interval is equal to change in

Average Rate of Change (AROC) The average rate of change of y over an interval is equal to change in Averge Rte o Cnge AROC Te verge rte o cnge o y over n intervl is equl to b b y y cngein y cnge in. Emple: Find te verge rte o cnge o te unction wit rule 5 s cnges rom to 5. 4 4 6 5 4 0 0 5 5 5 5 & 4 5

More information

Geometric Sequences. Geometric Sequence a sequence whose consecutive terms have a common ratio.

Geometric Sequences. Geometric Sequence a sequence whose consecutive terms have a common ratio. Geometric Sequences Geometric Sequence sequence whose consecutive terms hve common rtio. Geometric Sequence A sequence is geometric if the rtios of consecutive terms re the sme. 2 3 4... 2 3 The number

More information

Math 113 Exam 1-Review

Math 113 Exam 1-Review Mth 113 Exm 1-Review September 26, 2016 Exm 1 covers 6.1-7.3 in the textbook. It is dvisble to lso review the mteril from 5.3 nd 5.5 s this will be helpful in solving some of the problems. 6.1 Are Between

More information

Coimisiún na Scrúduithe Stáit State Examinations Commission

Coimisiún na Scrúduithe Stáit State Examinations Commission M 30 Coimisiún n Scrúduithe Stáit Stte Exmintions Commission LEAVING CERTIFICATE EXAMINATION, 005 MATHEMATICS HIGHER LEVEL PAPER ( 300 mrks ) MONDAY, 3 JUNE MORNING, 9:30 to :00 Attempt FIVE questions

More information

7.1 Integral as Net Change and 7.2 Areas in the Plane Calculus

7.1 Integral as Net Change and 7.2 Areas in the Plane Calculus 7.1 Integrl s Net Chnge nd 7. Ares in the Plne Clculus 7.1 INTEGRAL AS NET CHANGE Notecrds from 7.1: Displcement vs Totl Distnce, Integrl s Net Chnge We hve lredy seen how the position of n oject cn e

More information

ARITHMETIC OPERATIONS. The real numbers have the following properties: a b c ab ac

ARITHMETIC OPERATIONS. The real numbers have the following properties: a b c ab ac REVIEW OF ALGEBRA Here we review the bsic rules nd procedures of lgebr tht you need to know in order to be successful in clculus. ARITHMETIC OPERATIONS The rel numbers hve the following properties: b b

More information

Farey Fractions. Rickard Fernström. U.U.D.M. Project Report 2017:24. Department of Mathematics Uppsala University

Farey Fractions. Rickard Fernström. U.U.D.M. Project Report 2017:24. Department of Mathematics Uppsala University U.U.D.M. Project Report 07:4 Frey Frctions Rickrd Fernström Exmensrete i mtemtik, 5 hp Hledre: Andres Strömergsson Exmintor: Jörgen Östensson Juni 07 Deprtment of Mthemtics Uppsl University Frey Frctions

More information

SSC TIER II (MATHS) MOCK TEST - 31 (SOLUTION)

SSC TIER II (MATHS) MOCK TEST - 31 (SOLUTION) 007, OUTRM LINES, ST FLOOR, OOSITE MUKHERJEE NGR OLIE STTION, DELHI-0009 SS TIER II (MTHS) MOK TEST - (SOLUTION). () We know tht x + y + z xyz (x + y + z) (x + y + z xy yz zx) (x + y + z)[(x + y + z) (xy

More information

Mathematics. Sample Question Paper. Class 10th. (Detailed Solutions) Mathematics Class X. 2. Given, equa tion is 4 5 x 5x

Mathematics. Sample Question Paper. Class 10th. (Detailed Solutions) Mathematics Class X. 2. Given, equa tion is 4 5 x 5x Sample Question Paper (Detailed Solutions Matematics lass 0t 4 Matematics lass X. Let p( a 6 a be divisible by ( a, if p( a 0. Ten, p( a a a( a 6 a a a 6 a 6 a 0 Hence, remainder is (6 a.. Given, equa

More information

Individual Events I3 a 10 I4. d 90 angle 57 d Group Events. d 220 Probability

Individual Events I3 a 10 I4. d 90 angle 57 d Group Events. d 220 Probability Answers: (98-8 HKMO Finl Events) Creted by: Mr. Frncis Hung Lst updted: 8 Jnury 08 I 800 I Individul Events I 0 I4 no. of routes 6 I5 + + b b 0 b b c *8 missing c 0 c c See the remrk 600 d d 90 ngle 57

More information

p-adic Egyptian Fractions

p-adic Egyptian Fractions p-adic Egyptin Frctions Contents 1 Introduction 1 2 Trditionl Egyptin Frctions nd Greedy Algorithm 2 3 Set-up 3 4 p-greedy Algorithm 5 5 p-egyptin Trditionl 10 6 Conclusion 1 Introduction An Egyptin frction

More information

03 Qudrtic Functions Completing the squre: Generl Form f ( x) x + x + c f ( x) ( x + p) + q where,, nd c re constnts nd 0. (i) (ii) (iii) (iv) *Note t

03 Qudrtic Functions Completing the squre: Generl Form f ( x) x + x + c f ( x) ( x + p) + q where,, nd c re constnts nd 0. (i) (ii) (iii) (iv) *Note t A-PDF Wtermrk DEMO: Purchse from www.a-pdf.com to remove the wtermrk Add Mths Formule List: Form 4 (Updte 8/9/08) 0 Functions Asolute Vlue Function Inverse Function If f ( x ), if f ( x ) 0 f ( x) y f

More information

A Discussion on Formulas of Seismic Hydrodynamic Pressure

A Discussion on Formulas of Seismic Hydrodynamic Pressure Interntionl Forum on Energy Environment Science nd Mterils (IFEESM 2017) A Discussion on Formuls of Seismic Hydrodynmic Pressure Liu Himing1 To Xixin2 1 Cin Mercnts Congqing Communiction Reserc & Design

More information

Section 4.7 Inverse Trigonometric Functions

Section 4.7 Inverse Trigonometric Functions Section 7 Inverse Trigonometric Functions 89 9 Domin: 0, q Rnge: -q, q Zeros t n, n nonnegtive integer 9 Domin: -q, 0 0, q Rnge: -q, q Zeros t, n non-zero integer Note: te gr lso suggests n te end-bevior

More information

Individual Contest. English Version. Time limit: 90 minutes. Instructions:

Individual Contest. English Version. Time limit: 90 minutes. Instructions: Elementry Mthemtics Interntionl Contest Instructions: Individul Contest Time limit: 90 minutes Do not turn to the first pge until you re told to do so. Write down your nme, your contestnt numer nd your

More information

SOLUTIONS TO CONCEPTS CHAPTER

SOLUTIONS TO CONCEPTS CHAPTER 1. m = kg S = 10m Let, ccelertion =, Initil velocity u = 0. S= ut + 1/ t 10 = ½ ( ) 10 = = 5 m/s orce: = = 5 = 10N (ns) SOLUIONS O CONCEPS CHPE 5 40000. u = 40 km/hr = = 11.11 m/s. 3600 m = 000 kg ; v

More information

Lesson-5 ELLIPSE 2 1 = 0

Lesson-5 ELLIPSE 2 1 = 0 Lesson-5 ELLIPSE. An ellipse is the locus of point which moves in plne such tht its distnce from fied point (known s the focus) is e (< ), times its distnce from fied stright line (known s the directri).

More information

12.1 Introduction to Rational Expressions

12.1 Introduction to Rational Expressions . Introduction to Rtionl Epressions A rtionl epression is rtio of polynomils; tht is, frction tht hs polynomil s numertor nd/or denomintor. Smple rtionl epressions: 0 EVALUATING RATIONAL EXPRESSIONS To

More information

Chapter 1: Logarithmic functions and indices

Chapter 1: Logarithmic functions and indices Chpter : Logrithmic functions nd indices. You cn simplify epressions y using rules of indices m n m n m n m n ( m ) n mn m m m m n m m n Emple Simplify these epressions: 5 r r c 4 4 d 6 5 e ( ) f ( ) 4

More information

*GMT41* *24GMT4101* Mathematics. Unit T4 (With calculator) Higher Tier [GMT41] WEDNESDAY 6 JUNE 9.15 am am. 2 hours.

*GMT41* *24GMT4101* Mathematics. Unit T4 (With calculator) Higher Tier [GMT41] WEDNESDAY 6 JUNE 9.15 am am. 2 hours. entre Numer ndidte Numer Mtemtics Generl ertificte Secondry Eduction 0 Unit T4 (Wit clcultor) Higer Tier [GMT4] WEDNESDAY 6 JUNE 9.5 m.5 m *GMT4* *GMT4* TIME ours. INSTRUTIONS TO ANDIDATES Write your entre

More information

Advanced Algebra & Trigonometry Midterm Review Packet

Advanced Algebra & Trigonometry Midterm Review Packet Nme Dte Advnced Alger & Trigonometry Midterm Review Pcket The Advnced Alger & Trigonometry midterm em will test your generl knowledge of the mteril we hve covered since the eginning of the school yer.

More information

SULIT /2 3472/2 Matematik Tambahan Kertas 2 2 ½ jam 2009 SEKOLAH-SEKOLAH MENENGAH ZON A KUCHING

SULIT /2 3472/2 Matematik Tambahan Kertas 2 2 ½ jam 2009 SEKOLAH-SEKOLAH MENENGAH ZON A KUCHING SULIT 1 347/ 347/ Mtemtik Tmbhn Kerts ½ jm 009 SEKOLAH-SEKOLAH MENENGAH ZON A KUCHING PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN MALAYSIA 009 MATEMATIK TAMBAHAN Kerts Du jm tig puluh minit JANGAN BUKA KERTAS

More information

2 b. , a. area is S= 2π xds. Again, understand where these formulas came from (pages ).

2 b. , a. area is S= 2π xds. Again, understand where these formulas came from (pages ). AP Clculus BC Review Chpter 8 Prt nd Chpter 9 Things to Know nd Be Ale to Do Know everything from the first prt of Chpter 8 Given n integrnd figure out how to ntidifferentite it using ny of the following

More information

Probability. b a b. a b 32.

Probability. b a b. a b 32. Proility If n event n hppen in '' wys nd fil in '' wys, nd eh of these wys is eqully likely, then proility or the hne, or its hppening is, nd tht of its filing is eg, If in lottery there re prizes nd lnks,

More information

Bridging the gap: GCSE AS Level

Bridging the gap: GCSE AS Level Bridging the gp: GCSE AS Level CONTENTS Chpter Removing rckets pge Chpter Liner equtions Chpter Simultneous equtions 8 Chpter Fctors 0 Chpter Chnge the suject of the formul Chpter 6 Solving qudrtic equtions

More information

7.1 Integral as Net Change Calculus. What is the total distance traveled? What is the total displacement?

7.1 Integral as Net Change Calculus. What is the total distance traveled? What is the total displacement? 7.1 Integrl s Net Chnge Clculus 7.1 INTEGRAL AS NET CHANGE Distnce versus Displcement We hve lredy seen how the position of n oject cn e found y finding the integrl of the velocity function. The chnge

More information

IMPORTANT QUESTIONS FOR INTERMEDIATE PUBLIC EXAMINATIONS IN MATHS-IB

IMPORTANT QUESTIONS FOR INTERMEDIATE PUBLIC EXAMINATIONS IN MATHS-IB ` K UKATP ALLY CE NTRE IMPORTANT QUESTIONS FOR INTERMEDIATE PUBLIC EXAMINATIONS IN MATHS-IB 7-8 FIITJEE KUKATPALLY CENTRE: # -97, Plot No, Opp Ptel Kunt Hud Prk, Vijngr Colon, Hderbd - 5 7 Ph: -66 Regd

More information

SUBJECT: MATHEMATICS ANSWERS: COMMON ENTRANCE TEST 2012

SUBJECT: MATHEMATICS ANSWERS: COMMON ENTRANCE TEST 2012 MOCK TEST 0 SUBJECT: MATHEMATICS ANSWERS: COMMON ENTRANCE TEST 0 ANSWERS. () π π Tke cos - (- ) then sin [ cos - (- )]sin [ ]/. () Since sin - + sin - y + sin - z π, -; y -, z - 50 + y 50 + z 50 - + +

More information

GEOMETRY Properties of lines

GEOMETRY Properties of lines www.sscexmtuto.com GEOMETRY Popeties of lines Intesecting Lines nd ngles If two lines intesect t point, ten opposite ngles e clled veticl ngles nd tey ve te sme mesue. Pependicul Lines n ngle tt mesues

More information

8Similarity ONLINE PAGE PROOFS. 8.1 Kick off with CAS 8.2 Similar objects 8.3 Linear scale factors. 8.4 Area and volume scale factors 8.

8Similarity ONLINE PAGE PROOFS. 8.1 Kick off with CAS 8.2 Similar objects 8.3 Linear scale factors. 8.4 Area and volume scale factors 8. 8.1 Kick off with S 8. Similr ojects 8. Liner scle fctors 8Similrity 8.4 re nd volume scle fctors 8. Review Plese refer to the Resources t in the Prelims section of your eookplus for comprehensive step-y-step

More information

A-Level Mathematics Transition Task (compulsory for all maths students and all further maths student)

A-Level Mathematics Transition Task (compulsory for all maths students and all further maths student) A-Level Mthemtics Trnsition Tsk (compulsory for ll mths students nd ll further mths student) Due: st Lesson of the yer. Length: - hours work (depending on prior knowledge) This trnsition tsk provides revision

More information

( β ) touches the x-axis if = 1

( β ) touches the x-axis if = 1 Generl Certificte of Eduction (dv. Level) Emintion, ugust Comined Mthemtics I - Prt B Model nswers. () Let f k k, where k is rel constnt. i. Epress f in the form( ) Find the turning point of f without

More information

Cat Solved Paper. Fresh Paper. No. of Questions : 50 Time : 40 min

Cat Solved Paper. Fresh Paper. No. of Questions : 50 Time : 40 min t Solved Pper Fresh Pper No. of Questions : 50 Time : 0 min Note Ech wrong nswer crry rd negtive mrk. irections for question number to 5 : nswer the questions independently of ech other. 9 6 5. The infinite

More information

HKDSE2018 Mathematics (Compulsory Part) Paper 2 Solution 1. B 4 (2 ) = (2 ) 2. D. α + β. x x. α β 3. C. h h k k ( 4 ) 6( 2 )

HKDSE2018 Mathematics (Compulsory Part) Paper 2 Solution 1. B 4 (2 ) = (2 ) 2. D. α + β. x x. α β 3. C. h h k k ( 4 ) 6( 2 ) HKDSE08 Mthemtics (Compulsory Prt) Pper Solution. B n+ 8 n+ 4 ( ) ( ) n+ n+ 6n+ 6n+ (6n+ ) (6n+ ). D α β x x α x β ( x) α x β β x α x + β x β ( α + β ) x β β x α + β. C 6 4 h h k k ( 4 ) 6( ) h k h + k

More information

Calculus AB. For a function f(x), the derivative would be f '(

Calculus AB. For a function f(x), the derivative would be f '( lculus AB Derivtive Formuls Derivtive Nottion: For function f(), the derivtive would e f '( ) Leiniz's Nottion: For the derivtive of y in terms of, we write d For the second derivtive using Leiniz's Nottion:

More information

1 ELEMENTARY ALGEBRA and GEOMETRY READINESS DIAGNOSTIC TEST PRACTICE

1 ELEMENTARY ALGEBRA and GEOMETRY READINESS DIAGNOSTIC TEST PRACTICE ELEMENTARY ALGEBRA nd GEOMETRY READINESS DIAGNOSTIC TEST PRACTICE Directions: Study the exmples, work the prolems, then check your nswers t the end of ech topic. If you don t get the nswer given, check

More information

First Semester Review Calculus BC

First Semester Review Calculus BC First Semester Review lculus. Wht is the coordinte of the point of inflection on the grph of Multiple hoice: No lcultor y 3 3 5 4? 5 0 0 3 5 0. The grph of piecewise-liner function f, for 4, is shown below.

More information