CMY 127 FINALE EKSAMEN / FINAL EXAMINATION AFDELING B / SECTION B

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PRTMNT MI PRTMNT O MISTRY MY 127 INL KSMN / INL XMINTION TUM / T: 20 November 2012 KSMINTOR: Prof. WJ Schoeman XMINRS: Prof. M Potgieter Prof R Vleggaar Mrs astleman TY / TIM: 3 ure / hours r.

1 PRTMNT MI PRTMNT O MISTRY MY 127 INL KSMN / INL XMINTION TUM / T: 20 November 2012 KSMINTOR: Prof. WJ Schoeman XMINRS: Prof. M Potgieter Prof R Vleggaar Mrs astleman TY / TIM: 3 ure / hours r. P oleman PUNT / MRKS: 100 KSTRN / XTRNL: r L Pilcher fdeling / Section : 66 Mr N de eer fdeling / Section : 36 LING / STION INSTRUKSIS 1. eantwoord die volgende vrae op die rekenaar- antwoordblad. 2. Gebruik slegs kant 2 van die antwoordblad. 3. Slegs een antwoord per vraag is toelaatbaar. 4. Geen punte word oorweeg vir onduidelike antwoorde nie. it is u verantwoordelikheid op te sorg dat die antwoordblad leesbaar is vir die optiese merkleser. lle instruksies is op die antwoordvorm aangebring. 5. ie puntetoekenning per vraag mag varieer en word by elke vraag aangedui. 6. ntwoorde word nie negatief nagesien nie. 7. Vir berekeninge moet die numeriese inligting van die aangehegte Periodieke tabel gebruik word. INSTRUTIONS 1. nswer the following questions on the computer answer sheet. 2. Use only side 2 of the answer sheet. 3. Only one answer per question is allowed. 4. No marks are considered for unclear answers. It is your responsibility to ensure that the answer sheet is readable by the optical mark reader. ll instructions are provided on the answer sheet. 5. The allocation of marks per question may vary, but is indicated at each question. 6. nswers are not marked negatively. 7. The numerical information from the attached Periodic Table must be used for calculations. Vraag 1 Merk opsie J van Vraag 1 op u rekenaarantwoordblad. it is slegs vir kontroledoeleindes en verseker dat u kant 2 van die antwoordblad gebruik. Vraag 2 Merk opsie van Vraag 2 om te bevestig dat u u registrasienommer op die rekenaarantwoordblad in die boonste horisontale ry blokkies geskryf het, en dat u elke syfer daarvan vertikaal korrek gekodeer het. Question 1 Mark option J of Question 1 on your computer answer sheet. This is for control purposes only and ensures that you use side 2 of the answer sheet. Question 2 Mark option of Question 2 to confirm that you have written your student number in the horizontal row of boxes at the top of the answer sheet and that you have correctly coded each digit vertically. Vraag 3 [2] ie oplosbaarheid van Pbr 2 in water is 4.33 g in 1.0 L by 25. Wat is die waarde van K sp van Pbr 2? 1.6 x x x x Nie een van die bogenoemde nie. Question 3 [2] The solubility of Pbr 2 in water is 4.33 g in 1.0 L at 25. What is the value of K sp for Pbr 2? 1.6 x x x x None of the above. Page 1 of 8

2 Vraag 4 [2] Vir watter een van die volgende reaksies is die waarde van r o gelyk aan f o vir die produk? Xe (g) (g) Xe 4 (g) 4 (g) + 2 l 2 (g) 2 l 2 (l) + 2 l (g) N 2 (g) + O 3 (g) N 2 O 3 (g) 2 O (g) + O 2 (g) 2 O 2 (g) (diamant) + O 2 (g) O 2 (g) Question 4 [2] or which one of the following reactions is the value of r o equal to f o for the product? Xe (g) (g) Xe 4 (g) 4 (g) + 2 l 2 (g) 2 l 2 (l) + 2 l (g) N 2 (g) + O 3 (g) N 2 O 3 (g) 2 O (g) + O 2 (g) 2 O 2 (g) (diamond) + O 2 (g) O 2 (g) Vrae 5 en 6 verwys na byskrifte 1 tot 5 in die volgende skets wat drie 1-fluoro-2-propanol molekules verteenwoordig: Questions 5 and 6 refer to the labels 1 to 5 in the following drawing which represents three 1-fluoro-2-propanol molecules: Vraag 5 [2] Watter een van die aangeduide interaksies verteenwoordig nie n intermolekulêre krag nie? tot 5 verteenwoordig almal intermolekulêre kragte. G Nie een van 1 tot 5 verteenwoordig n intermolekulêre krag nie. Question 5 [2] Which one of the indicated interactions does not represent an intermolecular force? ll of 1 to 5 represent intermolecular forces. G Not one of 1 to 5 represents an intermolecular force. Vraag 6 [2] Watter een van die aangeduide interaksies verteenwoordig n dispersiekrag? tot 5 verteenwoordig almal dispersiekragte. G Nie een van 1 tot 5 verteenwoordig n dispersiekrag nie. Question 6 [2] Which one of the indicated interactions represents a dispersion force? ll of 1 to 5 represent dispersion forces. G Not one of 1 to 5 represents a dispersion force. Page 2 of 8

3 Vraag 7 [2] Watter een van die volgende faseveranderinge is eksotermies? verdamping sublimasie kondensasie smelting Nie een van bogenoemde nie. Vraag 8 [2] In watter een van die volgende gevalle neem die entropie van die sisteem toe? sublimasie kondensasie kristallisasie deposisie In al hierdie gevalle neem die entropie toe. In al hierdie gevalle neem die entropie af. Vraag 9 [2] ie oplosbaarheid van suurstof in water by 25 en 1.0 atm is g/l. Wat is die oplosbaarheid van suurstof, in g/l, in water by 3.0 atm en 25? Nie een van bogenoemde nie. Vraag 10 [2] Watter van die volgende konsentrasie-eenhede verander met temperatuur? molariteit massapersentasie molbreuk molaliteit al die bogenoemde Nie een van bogenoemde nie. Vraag 11 [2] Verbinding X, 8 11 ro 2, bevat geen drievoudbindings nie, maar reageer tog met 1 ekwivalent 2 om verbinding Y met molekulere formule 8 13 ro 2 te lewer. Wat kan oor die struktuur afgelei word? Question 7 [2] Which one of the following phase changes is exothermic? evaporation sublimation condensation melting None of the above. Question 8 [2] In which one of the following cases does the entropy of the system increase? sublimation condensation crystallisation deposition The entropy increases in all these cases. The entropy decreases in all these cases. Question 9 [2] The solubility of oxygen gas in water at 25 o and 1.0 atm is g/l. What is the solubility of oxygen, in g/l, in water at 3.0 atm and 25 o? None of the above. Question 10 [2] Which of the following concentration units varies with temperature? molarity mass percent mole fraction molality all of the above None of the above. Question 11 [2] ompound X, 8 11 ro 2, contains no triple bonds but reacts with one equivalent of 2 to give Y with molecular formula 8 13 ro 2. What can be deduced about the structure of X? X bevat 3 dubbelbindings X bevat 2 ringe en 1 dubbelbinding X bevat 1 ring en 2 dubbelbindings X bevat 3 ringe nie moontlik om enigiets oor die struktuur af te lei nie X has 3 double bonds X has 2 rings and 1 double bond X has 1 ring and 2 double bonds X has 3 rings not possible to deduce anything about the structure Page 3 of 8

4 Vraag 12 [2] Watter van die volgende verbindings is chiraal? Question 12 [2] Which of the following compounds is (are) chiral? Slegs 1 Slegs 2 Slegs 3 Slegs 4 Slegs G I J l die verbindings Only 1 Only 2 Only 3 Only 4 Only G I J ll of the compounds Vraag 13 [3] Klopidogrel, die aktiewe bestanddeel van Plaviks, word gebruik om bloedklonte te inhibeer. Gebruik die ahn- Ingold-Prelog reëls om die prioriteitsvolgorde van die vier substituente op die stereogeniese sentrum van hoog na laag te bepaal en sodoende die absolute konfigurasie van hierdie chirale middel toe te ken. Question 13 [3] lopidogrel, the active ingredient of Plavix, is used to inhibit blood clots. Use ahn-ingold-prelog sequence rules to prioritise the four substituents on the stereogenic centre from high to low and hence assign the absolute configuration of this chiral drug. Page 4 of 8

5 Vraag 14 [2] Wat is die stereochemiese verwantskap tussen die volgende twee verbindings? Question 14 [2] What is the stereochemical relationship between the following two compounds? Konformere onformers nantiomere nantiomers iastereomere iastereomers Konstitusionele isomere onstitutional isomers Identies in dieselfde konformasie Identical in the same conformation Nie een van bogenoemde nie None of the above Vraag 15 [2] ie naam van die volgende verbinding is Question 15 [2] The name of the following compound is β--mannose β--mannose α-l-galaktopiranose α-l-galactopyranose β-l-galaktofuranose β-l-galactofuranose Isopropiel β--mannopiranosied Isopropyl β--mannopyranoside Isopropiel β--mannofuranose Isopropyl β--mannofuranose Isopropiel β--glukopiranosied Isopropyl β--glucopyranoside Vraag 16 [2] cstasy is n onwettige stimulant wat hallusinering kan veroorsaak. ie funksionele groepe in die verbinding is Question 16 [2] cstasy is an illegal stimulant drug that can cause hallucinations. The functional groups in this compound are eter, primêre amien, aromatiese ring ether, primary amine, aromatic ring eter, amied, aromatiese ring ether, amide, aromatic ring hemiasetaal, amied, aromatiese ring hemiacetal, amide, aromatic ring hemiasetaal, aromatiese ring, sekondêre amien hemiacetal, aromatic ring, secondary amine asetaal, aromatiese ring, primêre amien acetal, aromatic ring, primary amine asetaal, aromatiese ring, sekondêre amien acetal, aromatic ring, secondary amine G eter, sekondêre amien, aromatiese ring G ether, secondary amine, aromatic ring Nie een van bogenoemde nie None of the above. Page 5 of 8

6 Vraag 17 (3 punte) Verskaf die volledige IUP naam vir die volgende verbinding: Question 17 [3] Provide the complete IUP name for the following compound G I 1-feniel-1,6-sikloheptadieen-4-tiol 1-bensiel-4-tio-1,6-sikloheptadieen 2-feniel-6-tio-1,3-sikloheptadieen 2-bensiel-1,3-sikloheptadieen-6-tiol 4-feniel-3,5-sikloheptadieentiol 5-bensiel-3,5-sikloheptadieentiol 2-bensiel-6-sulfaniel-1,3-sikloheptadieen. 4-bensiel-3,5-sikloheptadieentiol. Nie een van bogenoemde nie. G I 1-phenyl-1,6-cycloheptadiene-4-thiol 1-benzyl-4-thio-1,6-cycloheptadiene 2-phenyl-6-thio-1,3-cycloheptadiene 2-benzyl-1,3-cycloheptadiene-6-thiol 4-phenyl-3,5-cycloheptadienethiol 5-benzyl-3,5-cycloheptadienethiol 2-benzyl-6-sulfanyl-1,3-cycloheptadiene 4-benzyl-3,5-cycloheptadienethiol None of the above Vraag 18 [2] Kies die reagens wat die beste opbrengs van die produk in die volgende reaksie sal lewer. Question 18 [2] hoose the reagent that will give the best yield of the product in the following reaction. Nal, 2 SO 4 SOl 2 l (aq) l (g) 2, Pd- l 2 G i. Na 4, ii. l P, 2 l 2 I gl, N 4 O Vraag 19 [2] Kies n geskikte stel reagense vir die volgende omskakeling: Nal, 2 SO 4 SOl 2 l (aq) l (g) 2, Pd- l 2 G i. Na 4, ii. l P, 2 l 2 I gl, N 4 O Question 19 [2] Select a suitable reagent system for the following transformation: ro 3, 2 SO 4 SOl 2 3 O + 2 SO 4 2, Pd- 2, Lindlar catalyst G i. Na 4, ii. 3 O + P, 2 l 2 I gno 3, N 4 O ro 3, 2 SO 4 SOl 2 3 O + 2 SO 4 2, Pd- 2, Lindlar catalyst G i. Na 4, ii. 3 O + P, 2 l 2 I gno 3, N 4 O Page 6 of 8

7 Standard Reduction Potentials in queous, cidic or asic Solution at 25 Standaard Reduksie Potensiale in Waterige, Suur- of asiese Oplossing by Reduction alf-reaction / Reduksie alf-reaksie (V)* 2 (g) + 2 e 2 (aq) O2 (aq) + 2 3O + (aq) + 2 e 4 2O (l) PbO2 (s) + SO (aq) + 4 3O + (aq) + 2 e PbSO4 (s) + 6 2O (l) MnO (aq) + 8 3O + (aq) + 5 e Mn 2+ (aq) O (l) u 3+ (aq) + 3 e u (s) l2 (g) + 2 e 2 l (aq) r2o7 2- (aq) O + (aq) + 6 e 2 r 3+ (aq) O (l) O2 (g) + 4 3O + (aq) + 4 e 6 2O (l) r2 (l) + 2 e 2 r (aq) NO (aq) + 4 3O + (aq) + 3 e NO (g) + 6 2O (l) Ol (aq) + 2O (l) + 2 e l (aq) + 2 O (aq) g 2+ (aq) + 2 e g (l) g + (aq) + e g (s) g + (aq) + 2 e 2 g (l) e 3+ (aq) + e e 2+ (aq) I2 (s) + 2 e 2 I (aq) O2 (g) + 2 2O (l) + 4 e 4 O (aq) u 2+ (aq) + 2 e u (s) Sn 4+ (aq) + 2 e Sn 2+ (aq) (aq) + 2 e 2 (g) O + (aq) + 2 e 2 (g) + 2 2O (l) 0.00 Pb 2+ (aq) + 2 e Pb (s) Sn 2+ (aq) + 2 e Sn (s) Ni 2+ (aq) + 2 e Ni (s) V 3+ (aq) + e V 2+ (aq) PbSO4 (s) + 2 e Pb (s) + SO (aq) d 2+ (aq) + 2 e d (s) e 2+ (aq) + 2 e e (s) Zn 2+ (aq) + 2 e Zn (s) O (l) + 2 e 2 (g) + 2 O (aq) [Zn(N)4] 2- (aq) + 2 e Zn (s) + 4 N (aq) l 3+ (aq) + 3 e l (s) Mg 2+ (aq) + 2 e Mg (s) Na + (aq) + e Na (s) K + (aq) + e K (s) Li + (aq) + e Li (s) *Versus the standard hydrogen electrode / Teen die standaard waterstofelektrode 2 4 Page 7 of 8

8 Li Na K Rb s r e Mg a Sr a Ra Sc Y La c Ti Zr f Rf V Nb Ta b I PRIOIK TL VN I LMNT T PRIOI TL O T LMNTS 24 r Mo W Sg Mn Tc Re h e Ru Os s o Rh Ir Mt Ni Pd Pt s u g u Rg Zn d g n l Ga In Tl Si Ge Sn Pb N P s Sb i O S Se Te Po l r I t e Ne r Kr Xe Rn e Th Pr Pa Nd U Pm Np Sm Pu u m Gd m Tb k y f o s r m Tm Md Yb No Lu Lr Vergelykings / quations = = = = = Χ Π= = Δ=K Δ=+ =Δ = 1 1 = Δ Δ = = Δ Δ Δ =Δ +Δ = = Δ =Δ Δ Δ =Δ + Δ = RTK = Δ = = Q = Q 25 = K=2.303K Q=2.303Q Konstante / onstants R = L atm mol 1 K 1 = J mol 1 K 1 = kpa L mol -1 K -1 = mm g L mol -1 K -1 = x 10 4 mol 1 of/or x 10 4 J V 1 mol 1 = x = K ( 2 O(l)) = J g 1 K 1 ( 2 O(s)) = 2.06 J g 1 K 1 ( 2 O(g)) = 1.86 J g 1 K 1 =6.02 =40.65 Omsettingsfaktore / onversion actors 1 L = 10 3 m 3 = 1 dm 3 1 bar = x 10 5 Pa 1 = 1 mp 1 sec 1 J = cal = 1 Pa m 3 = 1 m 2 kg s 2 = 1 V = 1 Watt 1 sec 1 atm = x 10 5 N m 2 = x 10 5 Pa = 760 mm g = 760 torr unksionele groepe in prioriteitsvolgorde / Priority order of functional groups karboksielsuur > ester > aldehied > ketoon > alkohol > tiol > amien > alkeen > alkyn > alkaan >> eter; halied carboxylic acid > ester > aldehyde > ketone > alcohol > thiol > amine > alkene > alkyne > alkane >> ether; halide Page 8 of 8

8. Relax and do well.

8. Relax and do well. EM 1515.001-006 Exam II John II. Gelder March 5, 2002 Name TA's Name Section INSTRUTIONS: 1. This examination consists of a total of 8 different pages. The last three pages include a periodic table, a