Where are the protons? Measuring and modelling proton equilibria in complex macromolecular systems.

Size: px
Start display at page:

Download "Where are the protons? Measuring and modelling proton equilibria in complex macromolecular systems."

Transcription

1 Frans Mulder PhD course Jyväskylä 2017 Where are the protons? Measuring and modelling proton equilibria in complex macromolecular systems. Frans Mulder Lecture 3 Application of NMR spectroscopy to study electrostatics 1

2 Acknowledgement Stina Lindman, Ingemar Andre and Sara Linse Biophysical hemistry, Lund University pk a values of ionizable groups in proteins are of interest as electrostatic interactions play an important role in functional aspects of proteins. The ability to assign a pk a to a specific ionizable group in a protein (based on its chemical shift) can aid in the mechanistic description of binding, catalysis, and other behaviour 2

3 net charge Asp, Glu Tyr & -term Lys N-term net charge Asp, Glu Tyr & -term Lys N-term Up- and down-shifted pka-values close to pi Up-shifted pka-values far above pi 3

4 Traditional NMR approaches to pka determination in proteins: - 1 H 1D - 1 H 2D TOSY Forman-Kay et al. (1992) Biochemistry 31, Isotope labeling for pk a values by NMR Lysine with 13-- ε Aspartate with 13-- β N O= + NH 3 N O= O O Glutamate with 13-- γ Uniform 15-N N O O N R O= O= 4

5 pk a values of lysines using 13 and 1 H 0.5 mm apo albindin D 9k (low salt) [Kesvatera et al. (1996), J Mol Biol 259, 828] The H()N experiment correlates amino 15 N chemical shift with H ε (Lys) correlates amino 15 N chemical shift with H δ (Arg) + 15 N ζ H 3 13 ζ 1 13 H ε 1 ε H ε 15 N ε 1 H ε 13 δ 1 13 H δ 1 δ H δ 5

6 The H()N experiment FKBP12, ph 7.0 [André, et al. JAS (2007).] The H()N experiment 6

7 The -TOSY(N)H experiment The -TOSY(N)H experiment 7

8 pk a values of lysines from the 15 N shift of the titrating group 15 N ζ (ppm) δ obs = (δ HA +δ A 10 (ph pk a ) ) (1+10 (ph pk a ) ) ph Henderson-Hasselbalch equation for NMR titrations of non-interacting sites [André, et al. JAS (2007).] 2 mm apo calmodulin in 100 mm Kl 8

9 pk a values of lysines from the 15 N shift of the titrating group Table 2. pk a Values of Lysine Residues in apo almodulin As Determined from N ξ or H ϵ at 25 in 100 mm Kl; K(x) Indicates That the Residue Is Not Assigned residue N ξ H ϵ N ξ + H ϵ K ( ( ( 0.02 K ( ( ( 0.04 K(3) ( ( ( 0.05 K(4) ( ( ( 0.02 K(5) ( ( ( 0.02 K(6) ( ( ( 0.02 K(7) ( ( ( 0.02 K(8) ( ( ( 0.03 remember, the model pk a = 10.4 [André, et al. JAS (2007).] ph-dependent stability to unfolding for the B1 domain of protein G PGB1-QDD β2 β1 β4 β3 Variant to ensure unprocessed protein ontains 2 extra negative charges, D8 and D37 Total of 12 side-chain carboxyl groups 9

10 olor coding according to pk a Model pk a : The H()O experiment correlates carboxyl 13 chemical shift with H β or H γ For Asp: O 13 γ OH 1 H β 1 H β 13 β N 13 α 13 [ Oda et. al, Biochemistry 33 (1994) 5275] 10

11 Spectrum at ph 5 good dispersion and sensitivity Spectra ph

12 Henderson-Hasselbalch equation: a Hill parameter is now necessary to fit the data Hill parameter to account for cooperativity δ obs = (δ HA +δ A 10 n h(ph pk a ) ) (1+10 n h(ph pk a ) ) pk a values of side-chain carboxyl groups at 0 M and 0.5 M Nal Glu pk a model =4.4 0M : M : 4.6 0M : M : 4.0 0M : M : 4.8 0M : M : 4.5 0M : M :

13 pk a values of side-chain carboxyl groups at 0 M and 0.5 M Nal: zoom in 0M : M : 3.8 pk a values continued Asp pk a model =4.0 0M : M : 4.6 0M : M : 3.2 0M : M : 4.1 0M : M : 6.1 0M : M : 4.0 0M : M : 3.8 0M : M :

14 Proton Binding apacitance (PB) Ø PB = first derivative of the titration curve with respect to ph Ø urve fitting with Hill-parameter cannot account for asymmetric titration curves PB and titration asymmetry Highly downshifted Slightly downshifted Slightly upshifted Highly upshifted 14

15 Low salt Salt dependence of Glu pka Derivative of titration curve explains cooperativity and negative-cooperativity High salt Titration behavior approaches model with addition of salt ooperativity of Asp Derivative of titration curves explain cooperativity and negative-cooperativity Low salt High salt Titration behavior approaches model with addition of salt 15

16 pk a values for Asp8 from 13 and 1 H chemical shifts Major differences between the two protons! pk a O: 4.9 pk a H β1 : 5.8 pk a H β2 : 4.7 arbonyl 13 shifts for Asp47 and Ala48 report pk a value of Asp47 carboxyl group pk a carboxyl group of D47: 3.1 pk a carbonyl group of D47: 3.2 pk a carbonyl group of A48:

17 arbonyl shifts report on hydrogen bonds pk a carboxyl group of E56: 3.8 pk a carbonyl group of K10: 3.8 How to calculate ph-dependent stability based on pk a values δδg i q U = ( ph ) = 2.3RT( q q ) δ i n (ph pk ) h 1 a i ph i q i U = i F 1 ph i n (pk ph) h a Experimental pka values for native state Denatured state treated as random coil and pk a values were calculated using a Gausssian chain model [ Zhou, PNAS 99 (2002), 3569] 17

18 pk a values explain ph-dependent stability Denaturation data ph dependent stability calculated from pk a values [ Lindman et. al, Biophys J. (2010) 99: ] onclusions -1 chemical shifts of 13 and 15 N in protein are specific and accurate reporters of side chain protonation states carefully designed NMR experiments can monitor the heteronuclear chemical shifts in 2D spectra with high sensitivity and good resolution site-specific protonation constants can be determined 18

19 onclusions -2 pk a values show that ph-dependent stability can be explained purely by electrostatics Electrostatic contributions to protein stability are small (but not to kinetics!) There is clear evidence of local electrostatic coupling between acidic side chains in PGB1, but not for basic side chains in apo am We directly detect - for the first time - asymmetry in the ph-dependent protonation of individual acidic groups in proteins as a result of the change in protein electrostatic energies with ph 19

Content : Properties of amino acids.. Separation and Analysis of Amino Acids

Content : Properties of amino acids.. Separation and Analysis of Amino Acids قسم الكيمياء الحيوية.دولت على سالمه د. استاذ الكيمياء الحيوية ٢٠١٥-٢٠١٤ المحاضرة الثانية 1 Content : Properties of amino acids.. Separation and Analysis of Amino Acids 2 3 Physical Properties of Amino

More information

Biochemistry. Biochemical Techniques. 01 Electrophoresis : Basic Concepts

Biochemistry. Biochemical Techniques. 01 Electrophoresis : Basic Concepts Description of Module Subject Name Paper Name 12 Module Name/Title 01 Electrophoresis: Basic Concept 1. Objectives 1.1 To understand basic concept of electrophoresis 1.2 To explain what determines charge

More information

Basic equations: effect of ph. Analyzing the ph dependence of enzymatic reactions may be useful: To understand the enzyme s function in the organism

Basic equations: effect of ph. Analyzing the ph dependence of enzymatic reactions may be useful: To understand the enzyme s function in the organism Basic equations: effect of ph Analyzing the ph dependence of enzymatic reactions may be useful: To understand the mechanism To understand the enzyme s function in the organism Stomach pepsin Liver Glucose-6-phosphatase

More information

المرحلة الثانية- قسم علوم الحياة الجامعة المستنصرية

المرحلة الثانية- قسم علوم الحياة الجامعة المستنصرية 1 Biochemistry Amino acids For nd year students, Biology Department, College of Sciences, Mustansiriyah University 018-019 الكيمياء حياتية ٢ االحماض االمينية المرحلة الثانية- قسم علوم الحياة الجامعة المستنصرية

More information

Biomolecules: lecture 9

Biomolecules: lecture 9 Biomolecules: lecture 9 - understanding further why amino acids are the building block for proteins - understanding the chemical properties amino acids bring to proteins - realizing that many proteins

More information

A. Two of the common amino acids are analyzed. Amino acid X and amino acid Y both have an isoionic point in the range of

A. Two of the common amino acids are analyzed. Amino acid X and amino acid Y both have an isoionic point in the range of Questions with Answers- Amino Acids & Peptides A. Two of the common amino acids are analyzed. Amino acid X and amino acid Y both have an isoionic point in the range of 5.0-6.5 (Questions 1-4) 1. Which

More information

NH 2. Biochemistry I, Fall Term Sept 9, Lecture 5: Amino Acids & Peptides Assigned reading in Campbell: Chapter

NH 2. Biochemistry I, Fall Term Sept 9, Lecture 5: Amino Acids & Peptides Assigned reading in Campbell: Chapter Biochemistry I, Fall Term Sept 9, 2005 Lecture 5: Amino Acids & Peptides Assigned reading in Campbell: Chapter 3.1-3.4. Key Terms: ptical Activity, Chirality Peptide bond Condensation reaction ydrolysis

More information

CHMI 2227 EL. Biochemistry I. Test January Prof : Eric R. Gauthier, Ph.D.

CHMI 2227 EL. Biochemistry I. Test January Prof : Eric R. Gauthier, Ph.D. CHMI 2227 EL Biochemistry I Test 1 26 January 2007 Prof : Eric R. Gauthier, Ph.D. Guidelines: 1) Duration: 55 min 2) 14 questions, on 7 pages. For 70 marks (5 marks per question). Worth 15 % of the final

More information

Potentiometric Titration of an Amino Acid. Introduction

Potentiometric Titration of an Amino Acid. Introduction NAME: Course: DATE Sign-Off: Performed: Potentiometric Titration of an Amino Acid Introduction In previous course-work, you explored the potentiometric titration of a weak acid (HOAc). In this experiment,

More information

BSc and MSc Degree Examinations

BSc and MSc Degree Examinations Examination Candidate Number: Desk Number: BSc and MSc Degree Examinations 2018-9 Department : BIOLOGY Title of Exam: Molecular Biology and Biochemistry Part I Time Allowed: 1 hour and 30 minutes Marking

More information

Content : Properties of amino acids.. Separation and Analysis of Amino Acids

Content : Properties of amino acids.. Separation and Analysis of Amino Acids قسم الكيمياء الحيوية.دولت على سالمه د استاذ الكيمياء الحيوية ٢٠١٥-٢٠١٤ المحاضرة الثانية Content : Properties of amino acids.. Separation and Analysis of Amino Acids 2 -3 A. Physical properties 1. Solubility:

More information

Chemistry Problem Set #9 Due on Thursday 11/15/18 in class.

Chemistry Problem Set #9 Due on Thursday 11/15/18 in class. Chemistry 391 - Problem Set #9 Due on Thursday 11/15/18 in class. Name 1. There is a real enzyme called cocaine esterase that is produced in bacteria that live at the base of the coca plant. The enzyme

More information

Practice Midterm Exam 200 points total 75 minutes Multiple Choice (3 pts each 30 pts total) Mark your answers in the space to the left:

Practice Midterm Exam 200 points total 75 minutes Multiple Choice (3 pts each 30 pts total) Mark your answers in the space to the left: MITES ame Practice Midterm Exam 200 points total 75 minutes Multiple hoice (3 pts each 30 pts total) Mark your answers in the space to the left: 1. Amphipathic molecules have regions that are: a) polar

More information

Water. Water participates in H-bonding with biomolecules.

Water. Water participates in H-bonding with biomolecules. Water Most biochemical reactions occur in an aqueous environment. Water is highly polar because of its bent geometry. Water is highly cohesive because of intermolecular hydrogen bonding. Water participates

More information

Properties of amino acids in proteins

Properties of amino acids in proteins Properties of amino acids in proteins one of the primary roles of DNA (but not the only one!) is to code for proteins A typical bacterium builds thousands types of proteins, all from ~20 amino acids repeated

More information

What binds to Hb in addition to O 2?

What binds to Hb in addition to O 2? Reading: Ch5; 158-169, 162-166, 169-174 Problems: Ch5 (text); 3,7,8,10 Ch5 (study guide-facts); 1,2,3,4,5,8 Ch5 (study guide-apply); 2,3 Remember Today at 5:30 in CAS-522 is the second chance for the MB

More information

K w. Acids and bases 8/24/2009. Acids and Bases 9 / 03 / Ionization of water. Proton Jumping Large proton and hydroxide mobility

K w. Acids and bases 8/24/2009. Acids and Bases 9 / 03 / Ionization of water. Proton Jumping Large proton and hydroxide mobility Chapter 2 Water Acids and Bases 9 / 03 / 2009 1. How is the molecular structure of water related to physical and chemical behavior? 2. What is a Hydrogen Bond? 3Wh 3. What are Acids Aid and db Bases? 4.

More information

Residual Charge Interactions in Unfolded Staphylococcal Nuclease Can Be Explained by the Gaussian-Chain Model

Residual Charge Interactions in Unfolded Staphylococcal Nuclease Can Be Explained by the Gaussian-Chain Model Biophysical Journal Volume 83 December 2002 2981 2986 2981 Residual Charge Interactions in Unfolded Staphylococcal Nuclease Can Be Explained by the Gaussian-Chain Model Huan-Xiang Zhou Department of Physics,

More information

Biochemistry Quiz Review 1I. 1. Of the 20 standard amino acids, only is not optically active. The reason is that its side chain.

Biochemistry Quiz Review 1I. 1. Of the 20 standard amino acids, only is not optically active. The reason is that its side chain. Biochemistry Quiz Review 1I A general note: Short answer questions are just that, short. Writing a paragraph filled with every term you can remember from class won t improve your answer just answer clearly,

More information

Buffer solutions المحاليل المنظمة

Buffer solutions المحاليل المنظمة Buffer solutions المحاليل المنظمة Presented by Dr. Mohammad Saadeh The requirements for the Pharmaceutical Biochemistry I Philadelphia University Faculty of pharmacy Understanding ph balance The human

More information

Amino Acids and Peptides

Amino Acids and Peptides Amino Acids Amino Acids and Peptides Amino acid a compound that contains both an amino group and a carboxyl group α-amino acid an amino acid in which the amino group is on the carbon adjacent to the carboxyl

More information

Other types of liquid chromatography

Other types of liquid chromatography Other types of liquid chromatography Objectives: After this discussion you should be able to: Define IEC Basic mechanism Relationship between net charge and isoelectric point (pi) Relationship between

More information

EXAM 1 Fall 2009 BCHS3304, SECTION # 21734, GENERAL BIOCHEMISTRY I Dr. Glen B Legge

EXAM 1 Fall 2009 BCHS3304, SECTION # 21734, GENERAL BIOCHEMISTRY I Dr. Glen B Legge EXAM 1 Fall 2009 BCHS3304, SECTION # 21734, GENERAL BIOCHEMISTRY I 2009 Dr. Glen B Legge This is a Scantron exam. All answers should be transferred to the Scantron sheet using a #2 pencil. Write and bubble

More information

Protein Structure Bioinformatics Introduction

Protein Structure Bioinformatics Introduction 1 Swiss Institute of Bioinformatics Protein Structure Bioinformatics Introduction Basel, 27. September 2004 Torsten Schwede Biozentrum - Universität Basel Swiss Institute of Bioinformatics Klingelbergstr

More information

NAME. EXAM I I. / 36 September 25, 2000 Biochemistry I II. / 26 BICH421/621 III. / 38 TOTAL /100

NAME. EXAM I I. / 36 September 25, 2000 Biochemistry I II. / 26 BICH421/621 III. / 38 TOTAL /100 EXAM I I. / 6 September 25, 2000 Biochemistry I II. / 26 BIH421/621 III. / 8 TOTAL /100 I. MULTIPLE HOIE (6 points) hoose the BEST answer to the question by circling the appropriate letter. 1. An amino

More information

BIOC 460 General Chemistry Review: Chemical Equilibrium, Ionization of H 2 O, ph, pk a

BIOC 460 General Chemistry Review: Chemical Equilibrium, Ionization of H 2 O, ph, pk a BIOC 460 General Chemistry Review: Chemical Equilibrium, Ionization of H 2 O, ph, pk a General Equilibrium: What are the UNITS of K eq? Example reactions: A --> B units of K eq? A --> B + C units of K

More information

CHEM 3653 Exam # 1 (03/07/13)

CHEM 3653 Exam # 1 (03/07/13) 1. Using phylogeny all living organisms can be divided into the following domains: A. Bacteria, Eukarya, and Vertebrate B. Archaea and Eukarya C. Bacteria, Eukarya, and Archaea D. Eukarya and Bacteria

More information

LS1a Fall 2014 Problem Set #2 Due Monday 10/6 at 6 pm in the drop boxes on the Science Center 2 nd Floor

LS1a Fall 2014 Problem Set #2 Due Monday 10/6 at 6 pm in the drop boxes on the Science Center 2 nd Floor LS1a Fall 2014 Problem Set #2 Due Monday 10/6 at 6 pm in the drop boxes on the Science Center 2 nd Floor Note: Adequate space is given for each answer. Questions that require a brief explanation should

More information

Biochemistry Prof. S. DasGupta Department of Chemistry Indian Institute of Technology Kharagpur. Lecture - 06 Protein Structure IV

Biochemistry Prof. S. DasGupta Department of Chemistry Indian Institute of Technology Kharagpur. Lecture - 06 Protein Structure IV Biochemistry Prof. S. DasGupta Department of Chemistry Indian Institute of Technology Kharagpur Lecture - 06 Protein Structure IV We complete our discussion on Protein Structures today. And just to recap

More information

CHAPTER 29 HW: AMINO ACIDS + PROTEINS

CHAPTER 29 HW: AMINO ACIDS + PROTEINS CAPTER 29 W: AMI ACIDS + PRTEIS For all problems, consult the table of 20 Amino Acids provided in lecture if an amino acid structure is needed; these will be given on exams. Use natural amino acids (L)

More information

A. Reaction Mechanisms and Catalysis (1) proximity effect (2) acid-base catalysts (3) electrostatic (4) functional groups (5) structural flexibility

A. Reaction Mechanisms and Catalysis (1) proximity effect (2) acid-base catalysts (3) electrostatic (4) functional groups (5) structural flexibility (P&S Ch 5; Fer Ch 2, 9; Palm Ch 10,11; Zub Ch 9) A. Reaction Mechanisms and Catalysis (1) proximity effect (2) acid-base catalysts (3) electrostatic (4) functional groups (5) structural flexibility B.

More information

THE UNIVERSITY OF MANITOBA. PAPER NO: _1_ LOCATION: 173 Robert Schultz Theatre PAGE NO: 1 of 5 DEPARTMENT & COURSE NO: CHEM / MBIO 2770 TIME: 1 HOUR

THE UNIVERSITY OF MANITOBA. PAPER NO: _1_ LOCATION: 173 Robert Schultz Theatre PAGE NO: 1 of 5 DEPARTMENT & COURSE NO: CHEM / MBIO 2770 TIME: 1 HOUR THE UNIVERSITY OF MANITOBA 1 November 1, 2016 Mid-Term EXAMINATION PAPER NO: _1_ LOCATION: 173 Robert Schultz Theatre PAGE NO: 1 of 5 DEPARTMENT & COURSE NO: CHEM / MBIO 2770 TIME: 1 HOUR EXAMINATION:

More information

R = J/mole K = cal/mole K = N A k B K a K b = K w

R = J/mole K = cal/mole K = N A k B K a K b = K w Chemistry 271 22XX Prof. Jason Kahn Your Name: University of Maryland, College Park Your SID #: General Chemistry and Energetics Exam II (100 points) You have 53 minutes for this exam. Your Section # or

More information

Supporting Information

Supporting Information Supporting Information Micelle-Triggered b-hairpin to a-helix Transition in a 14-Residue Peptide from a Choline-Binding Repeat of the Pneumococcal Autolysin LytA HØctor Zamora-Carreras, [a] Beatriz Maestro,

More information

Chemical Properties of Amino Acids

Chemical Properties of Amino Acids hemical Properties of Amino Acids Protein Function Make up about 15% of the cell and have many functions in the cell 1. atalysis: enzymes 2. Structure: muscle proteins 3. Movement: myosin, actin 4. Defense:

More information

12/6/12. Dr. Sanjeeva Srivastava IIT Bombay. Primary Structure. Secondary Structure. Tertiary Structure. Quaternary Structure.

12/6/12. Dr. Sanjeeva Srivastava IIT Bombay. Primary Structure. Secondary Structure. Tertiary Structure. Quaternary Structure. Dr. anjeeva rivastava Primary tructure econdary tructure Tertiary tructure Quaternary tructure Amino acid residues α Helix Polypeptide chain Assembled subunits 2 1 Amino acid sequence determines 3-D structure

More information

Rotamers in the CHARMM19 Force Field

Rotamers in the CHARMM19 Force Field Appendix A Rotamers in the CHARMM19 Force Field The people may be made to follow a path of action, but they may not be made to understand it. Confucius (551 BC - 479 BC) ( ) V r 1 (j),r 2 (j),r 3 (j),...,r

More information

Note that side chains serve as a) stabilizers of protein structure, b) reactive centers, and c) micro-environments. * + H 3 N-C-COOH H 2 N-C-COO -

Note that side chains serve as a) stabilizers of protein structure, b) reactive centers, and c) micro-environments. * + H 3 N-C-COOH H 2 N-C-COO - BIOCEMISTRY I AMINO ACIDS I. Amino Acid Structure One of the most important macromolecules (chains of distinct molecular units) in the biosphere is protein. Proteins are needed for catalysis, reaction,

More information

NMR parameters intensity chemical shift coupling constants 1D 1 H spectra of nucleic acids and proteins

NMR parameters intensity chemical shift coupling constants 1D 1 H spectra of nucleic acids and proteins Lecture #2 M230 NMR parameters intensity chemical shift coupling constants Juli Feigon 1D 1 H spectra of nucleic acids and proteins NMR Parameters A. Intensity (area) 1D NMR spectrum: integrated intensity

More information

Chapter 4: Amino Acids

Chapter 4: Amino Acids Chapter 4: Amino Acids All peptides and polypeptides are polymers of alpha-amino acids. lipid polysaccharide enzyme 1940s 1980s. Lipids membrane 1960s. Polysaccharide Are energy metabolites and many of

More information

Exam III. Please read through each question carefully, and make sure you provide all of the requested information.

Exam III. Please read through each question carefully, and make sure you provide all of the requested information. 09-107 onors Chemistry ame Exam III Please read through each question carefully, and make sure you provide all of the requested information. 1. A series of octahedral metal compounds are made from 1 mol

More information

NAME IV. /22. I. MULTIPLE CHOICE. (48 points; 2 pts each) Choose the BEST answer to the question by circling the appropriate letter.

NAME IV. /22. I. MULTIPLE CHOICE. (48 points; 2 pts each) Choose the BEST answer to the question by circling the appropriate letter. NAME Exam I I. /48 September 25, 2017 Biochemistry I II. / 4 BI/CH 421/621 III. /26 IV. /22 TOTAL /100 I. MULTIPLE CHOICE. (48 points; 2 pts each) Choose the BEST answer to the question by circling the

More information

Dissecting electrostatic interactions in Bacillus circulans xylanase through NMR-monitored ph titrations

Dissecting electrostatic interactions in Bacillus circulans xylanase through NMR-monitored ph titrations SUPPLEMENTARY MATERIAL Dissecting electrostatic interactions in Bacillus circulans xylanase through NMR-monitored ph titrations Lawrence P. McIntosh 1, Daigo Naito 1, Simon J. Baturin 1, Mark Okon 1, Manish

More information

Lecture 15: Enzymes & Kinetics. Mechanisms ROLE OF THE TRANSITION STATE. H-O-H + Cl - H-O δ- H Cl δ- HO - + H-Cl. Margaret A. Daugherty.

Lecture 15: Enzymes & Kinetics. Mechanisms ROLE OF THE TRANSITION STATE. H-O-H + Cl - H-O δ- H Cl δ- HO - + H-Cl. Margaret A. Daugherty. Lecture 15: Enzymes & Kinetics Mechanisms Margaret A. Daugherty Fall 2004 ROLE OF THE TRANSITION STATE Consider the reaction: H-O-H + Cl - H-O δ- H Cl δ- HO - + H-Cl Reactants Transition state Products

More information

Supporting Information for Lysozyme Adsorption in ph-responsive Hydrogel Thin-Films: The non-trivial Role of Acid-Base Equilibrium

Supporting Information for Lysozyme Adsorption in ph-responsive Hydrogel Thin-Films: The non-trivial Role of Acid-Base Equilibrium Electronic Supplementary Material (ESI) for Soft Matter. This journal is The Royal Society of Chemistry 215 Supporting Information for Lysozyme Adsorption in ph-responsive Hydrogel Thin-Films: The non-trivial

More information

Properties of Amino Acids

Properties of Amino Acids Biochemistry Department Date:19/9/ 2017 Properties of Amino Acids Prof.Dr./ FAYDA Elazazy Professor of Biochemistry and Molecular Biology 1 Intended Learning Outcomes (ILOs) By the end of this lecture,

More information

Electrostatic Contributions to the Thermodynamics of Ribonuclease P Protein Folding. Pamela Lynnette Mosley. Department of Chemistry Duke University

Electrostatic Contributions to the Thermodynamics of Ribonuclease P Protein Folding. Pamela Lynnette Mosley. Department of Chemistry Duke University Electrostatic Contributions to the Thermodynamics of Ribonuclease P Protein Folding by Pamela Lynnette Mosley Department of Chemistry Duke University Date: Approved: Terrence G. Oas, Supervisor Katherine

More information

Chemistry Chapter 22

Chemistry Chapter 22 hemistry 2100 hapter 22 Proteins Proteins serve many functions, including the following. 1. Structure: ollagen and keratin are the chief constituents of skin, bone, hair, and nails. 2. atalysts: Virtually

More information

1-How can we distinguish between D-amino acid and L-amino acid?

1-How can we distinguish between D-amino acid and L-amino acid? AMINO ACIDS (2) Questions from the previous lecture : 1-How can we distinguish between D-amino acid and L-amino acid? According to the location of the amino group in the amino acid, the R group is above,

More information

7.05 Spring 2004 February 27, Recitation #2

7.05 Spring 2004 February 27, Recitation #2 Recitation #2 Contact Information TA: Victor Sai Recitation: Friday, 3-4pm, 2-132 E-mail: sai@mit.edu ffice ours: Friday, 4-5pm, 2-132 Unit 1 Schedule Recitation/Exam Date Lectures covered Recitation #2

More information

Supporting Information

Supporting Information Supporting Information Boehr et al. 10.1073/pnas.0914163107 SI Text Materials and Methods. R 2 relaxation dispersion experiments. 15 NR 2 relaxation dispersion data measured at 1 H Larmor frequencies of

More information

Amino Acid Side Chain Induced Selectivity in the Hydrolysis of Peptides Catalyzed by a Zr(IV)-Substituted Wells-Dawson Type Polyoxometalate

Amino Acid Side Chain Induced Selectivity in the Hydrolysis of Peptides Catalyzed by a Zr(IV)-Substituted Wells-Dawson Type Polyoxometalate Amino Acid Side Chain Induced Selectivity in the Hydrolysis of Peptides Catalyzed by a Zr(IV)-Substituted Wells-Dawson Type Polyoxometalate Stef Vanhaecht, Gregory Absillis, Tatjana N. Parac-Vogt* Department

More information

G. GENERAL ACID-BASE CATALYSIS

G. GENERAL ACID-BASE CATALYSIS G. GENERAL ACID-BASE CATALYSIS Towards a Better Chemical Mechanism via Catalysis There are two types of mechanisms we ll be discussing this semester. Kinetic mechanisms are concerned with rate constants

More information

Dr. Diala Abu-Hassan, DDS, PhD Lecture 3 MD summer 2014

Dr. Diala Abu-Hassan, DDS, PhD Lecture 3 MD summer 2014 ph, DDS, PhD Dr.abuhassand@gmail.com Lecture 3 MD summer 2014 www.chem4kids.com 1 Outline ph Henderson-Hasselbalch Equation Monoprotic and polyprotic acids Titration 2 Measuring the acidity of solutions,

More information

Housekeeping. Housekeeping. Molecules of Life: Biopolymers

Housekeeping. Housekeeping. Molecules of Life: Biopolymers Molecules of Life: Biopolymers Dr. Dale Hancock D.Hancock@mmb.usyd.edu.au Room 377 Biochemistry building Housekeeping Answers to the practise calculations and a narration are on WebT. Access these through

More information

Titration curve of amino acids. BCH 312 [Practical]

Titration curve of amino acids. BCH 312 [Practical] Titration curve of amino acids BCH 312 [Practical] Titration curve Titration Curves are produced by monitoring the ph of a given volume of a sample solution after successive addition of acid or alkali.

More information

Effects of Chemical Exchange on NMR Spectra

Effects of Chemical Exchange on NMR Spectra Effects of Chemical Exchange on NMR Spectra Chemical exchange refers to any process in which a nucleus exchanges between two or more environments in which its NMR parameters (e.g. chemical shift, scalar

More information

Sequential Assignment Strategies in Proteins

Sequential Assignment Strategies in Proteins Sequential Assignment Strategies in Proteins NMR assignments in order to determine a structure by traditional, NOE-based 1 H- 1 H distance-based methods, the chemical shifts of the individual 1 H nuclei

More information

Lab 3: The titration of amino acids

Lab 3: The titration of amino acids Chemistry 123 Objective: Lab 3: The titration of amino acids Introduction: Alpha amino acids are the building blocks of proteins. Almost all proteins consist of various combinations of the same 20 amino

More information

NMR study of complexes between low molecular mass inhibitors and the West Nile virus NS2B-NS3 protease

NMR study of complexes between low molecular mass inhibitors and the West Nile virus NS2B-NS3 protease University of Wollongong Research Online Faculty of Science - Papers (Archive) Faculty of Science, Medicine and Health 2009 NMR study of complexes between low molecular mass inhibitors and the West Nile

More information

Chemical Exchange and Ligand Binding

Chemical Exchange and Ligand Binding Chemical Exchange and Ligand Binding NMR time scale Fast exchange for binding constants Slow exchange for tight binding Single vs. multiple binding mode Calcium binding process of calcium binding proteins

More information

Water: The Solvent for Biochemical Reactions

Water: The Solvent for Biochemical Reactions Chapter 2 Water: The Solvent for Biochemical Reactions 11 SUMMARY Section 2.1 Section 2.2 Section 2.3 Section 2.4 Water is a polar molecule, with a partial negative charge on the oxygen and partial positive

More information

Proton Acidity. (b) For the following reaction, draw the arrowhead properly to indicate the position of the equilibrium: HA + K + B -

Proton Acidity. (b) For the following reaction, draw the arrowhead properly to indicate the position of the equilibrium: HA + K + B - Proton Acidity A01 Given that acid A has a pk a of 15 and acid B has a pk a of 10, then: (a) Which of the two acids is stronger? (b) For the following reaction, draw the arrowhead properly to indicate

More information

Sequential resonance assignments in (small) proteins: homonuclear method 2º structure determination

Sequential resonance assignments in (small) proteins: homonuclear method 2º structure determination Lecture 9 M230 Feigon Sequential resonance assignments in (small) proteins: homonuclear method 2º structure determination Reading resources v Roberts NMR of Macromolecules, Chap 4 by Christina Redfield

More information

A prevalent intraresidue hydrogen bond stabilizes proteins

A prevalent intraresidue hydrogen bond stabilizes proteins Supplementary Information A prevalent intraresidue hydrogen bond stabilizes proteins Robert W. Newberry 1 & Ronald T. Raines 1,2 * 1 Department of Chemistry and 2 Department of Biochemistry, University

More information

Supporting information

Supporting information Electronic Supplementary Material (ESI) for New Journal of Chemistry. This journal is The Royal Society of Chemistry and the Centre National de la Recherche Scientifique 2015 Supporting information Influence

More information

+3 for pka = 14 pkb = 9.25 [+1 for the idea that pka and pkb are related.]

+3 for pka = 14 pkb = 9.25 [+1 for the idea that pka and pkb are related.] Chemistry 271, Section 21xx Your Name: Key University of Maryland, College Park Your SID #: General Chemistry and Energetics Prof. Jason Kahn Exam I (100 points total) March 11, 2009 You have 50 minutes

More information

Using NMR to study Macromolecular Interactions. John Gross, BP204A UCSF. Nov 27, 2017

Using NMR to study Macromolecular Interactions. John Gross, BP204A UCSF. Nov 27, 2017 Using NMR to study Macromolecular Interactions John Gross, BP204A UCSF Nov 27, 2017 Outline Review of basic NMR experiment Multidimensional NMR Monitoring ligand binding Structure Determination Review:

More information

1) Which of the following represents the breaking of a noncovalent interaction? Topic: The Nature of Noncovalent Interactions

1) Which of the following represents the breaking of a noncovalent interaction? Topic: The Nature of Noncovalent Interactions Multiple Choice Questions 1) Which of the following represents the breaking of a noncovalent interaction? A) hydrolysis of an ester B) dissolving of salt crystals C) ionization of water D) decomposition

More information

Protein Structure Marianne Øksnes Dalheim, PhD candidate Biopolymers, TBT4135, Autumn 2013

Protein Structure Marianne Øksnes Dalheim, PhD candidate Biopolymers, TBT4135, Autumn 2013 Protein Structure Marianne Øksnes Dalheim, PhD candidate Biopolymers, TBT4135, Autumn 2013 The presentation is based on the presentation by Professor Alexander Dikiy, which is given in the course compedium:

More information

Practice Final for Chem 104

Practice Final for Chem 104 Practice Final for Chem 104 These questions cover the material that will be covered on the Final Exam. The distribution of the questions is about the same as the Final Exam. The forms of the questions

More information

proteins Structural origins of ph-dependent chemical shifts in the B1 domain of protein G

proteins Structural origins of ph-dependent chemical shifts in the B1 domain of protein G proteins STRUCTURE O FUNCTION O BIOINFORMATICS Structural origins of ph-dependent chemical shifts in the B1 domain of protein G Jennifer H. Tomlinson, Victoria L. Green, Patrick J. Baker, and Mike P. Williamson*

More information

Packing of Secondary Structures

Packing of Secondary Structures 7.88 Lecture Notes - 4 7.24/7.88J/5.48J The Protein Folding and Human Disease Professor Gossard Retrieving, Viewing Protein Structures from the Protein Data Base Helix helix packing Packing of Secondary

More information

Section Week 3. Junaid Malek, M.D.

Section Week 3. Junaid Malek, M.D. Section Week 3 Junaid Malek, M.D. Biological Polymers DA 4 monomers (building blocks), limited structure (double-helix) RA 4 monomers, greater flexibility, multiple structures Proteins 20 Amino Acids,

More information

1. Amino Acids and Peptides Structures and Properties

1. Amino Acids and Peptides Structures and Properties 1. Amino Acids and Peptides Structures and Properties Chemical nature of amino acids The!-amino acids in peptides and proteins (excluding proline) consist of a carboxylic acid ( COOH) and an amino ( NH

More information

A) at equilibrium B) endergonic C) endothermic D) exergonic E) exothermic.

A) at equilibrium B) endergonic C) endothermic D) exergonic E) exothermic. CHEM 2770: Elements of Biochemistry Mid Term EXAMINATION VERSION A Date: October 29, 2014 Instructor: H. Perreault Location: 172 Schultz Time: 4 or 6 pm. Duration: 1 hour Instructions Please mark the Answer

More information

Chemical and Physical Properties of Organic Molecules

Chemical and Physical Properties of Organic Molecules Chemical and Physical Properties of Organic Molecules I.Elements A. Chemical symbols: C H O P S N C=carbon, H=hydrogen, O=oxygen, P=phosphorus, S=sulfur, N=nitrogen B. Top 3 Earth s surface = O, Si, Al

More information

Dental Biochemistry EXAM I

Dental Biochemistry EXAM I Dental Biochemistry EXAM I August 29, 2005 In the reaction below: CH 3 -CH 2 OH -~ ethanol CH 3 -CHO acetaldehyde A. acetoacetate is being produced B. ethanol is being oxidized to acetaldehyde C. acetaldehyde

More information

Chapter 2 Water: The Solvent for Biochemical Reactions

Chapter 2 Water: The Solvent for Biochemical Reactions Chapter 2 Water: The Solvent for Biochemical Reactions SUMMARY Section 2.1 Water is a polar molecule, with a partial negative charge on the oxygen and partial positive charges on the hydrogens. There are

More information

7.012 Problem Set 1. i) What are two main differences between prokaryotic cells and eukaryotic cells?

7.012 Problem Set 1. i) What are two main differences between prokaryotic cells and eukaryotic cells? ame 7.01 Problem Set 1 Section Question 1 a) What are the four major types of biological molecules discussed in lecture? Give one important function of each type of biological molecule in the cell? b)

More information

B O C 4 H 2 O O. NOTE: The reaction proceeds with a carbonium ion stabilized on the C 1 of sugar A.

B O C 4 H 2 O O. NOTE: The reaction proceeds with a carbonium ion stabilized on the C 1 of sugar A. hbcse 33 rd International Page 101 hemistry lympiad Preparatory 05/02/01 Problems d. In the hydrolysis of the glycosidic bond, the glycosidic bridge oxygen goes with 4 of the sugar B. n cleavage, 18 from

More information

Timescales of Protein Dynamics

Timescales of Protein Dynamics Timescales of Protein Dynamics From Henzler-Wildman and Kern, Nature 2007 Dynamics from NMR Show spies Amide Nitrogen Spies Report On Conformational Dynamics Amide Hydrogen Transverse Relaxation Ensemble

More information

General Chemistry and Energetics Your Section #: Exam I (100 points total) October 6, 2010

General Chemistry and Energetics Your Section #: Exam I (100 points total) October 6, 2010 Chemistry 271, Section 22xx Your Name: Prof. Jason Kahn University of Maryland, College Park Your SID #: General Chemistry and Energetics Your Section #: Exam I (100 points total) October 6, 2010 You have

More information

Electronic Supplementary Information

Electronic Supplementary Information Electronic Supplementary Information Multicomponent Hydrogels from Enantiomeric amino acid derivatives: Helical Nanofibers, Handedness and Self-Sorting Bimalendu Adhikari, Jayanta Nanda and Arindam Banerjee*

More information

Determination of Electrostatic Interaction Energies and Protonation State Populations in Enzyme Active Sites

Determination of Electrostatic Interaction Energies and Protonation State Populations in Enzyme Active Sites doi:10.1016/j.jmb.2007.09.070 J. Mol. Biol. (2008) 376, 269 287 Available online at www.sciencedirect.com Determination of Electrostatic Interaction Energies and Protonation State Populations in Enzyme

More information

It s the amino acids!

It s the amino acids! Catalytic Mechanisms HOW do enzymes do their job? Reducing activation energy sure, but HOW does an enzyme catalysis reduce the energy barrier ΔG? Remember: The rate of a chemical reaction of substrate

More information

Exam I Answer Key: Summer 2006, Semester C

Exam I Answer Key: Summer 2006, Semester C 1. Which of the following tripeptides would migrate most rapidly towards the negative electrode if electrophoresis is carried out at ph 3.0? a. gly-gly-gly b. glu-glu-asp c. lys-glu-lys d. val-asn-lys

More information

Solutions and Non-Covalent Binding Forces

Solutions and Non-Covalent Binding Forces Chapter 3 Solutions and Non-Covalent Binding Forces 3.1 Solvent and solution properties Molecules stick together using the following forces: dipole-dipole, dipole-induced dipole, hydrogen bond, van der

More information

Biochemistry 3100 Sample Problems Binding proteins, Kinetics & Catalysis

Biochemistry 3100 Sample Problems Binding proteins, Kinetics & Catalysis (1) Draw an approximate denaturation curve for a typical blood protein (eg myoglobin) as a function of ph. (2) Myoglobin is a simple, single subunit binding protein that has an oxygen storage function

More information

- Basic understandings: - Mapping interactions:

- Basic understandings: - Mapping interactions: NMR-lecture April 6th, 2009, FMP Berlin Outline: Christian Freund - Basic understandings: Relaxation Chemical exchange - Mapping interactions: -Chemical shift mapping (fast exchange) Linewidth analysis

More information

CONSTANT ph REPLICA EXCHANGE MOLECULAR DYNAMICS STUDY OF PROTEIN STRUCTURE AND DYNAMICS

CONSTANT ph REPLICA EXCHANGE MOLECULAR DYNAMICS STUDY OF PROTEIN STRUCTURE AND DYNAMICS CONSTANT ph REPLICA EXCHANGE MOLECULAR DYNAMICS STUDY OF PROTEIN STRUCTURE AND DYNAMICS By YILIN MENG A DISSERTATION PRESENTED TO THE GRADUATE SCHOOL OF THE UNIVERSITY OF FLORIDA IN PARTIAL FULFILLMENT

More information

4. The Michaelis-Menten combined rate constant Km, is defined for the following kinetic mechanism as k 1 k 2 E + S ES E + P k -1

4. The Michaelis-Menten combined rate constant Km, is defined for the following kinetic mechanism as k 1 k 2 E + S ES E + P k -1 Fall 2000 CH 595C Exam 1 Answer Key Multiple Choice 1. One of the reasons that enzymes are such efficient catalysts is that a) the energy level of the enzyme-transition state complex is much higher than

More information

Supporting Information

Supporting Information Supporting Information Allosteric communication disrupted by small molecule binding to the Imidazole glycerol phosphate synthase protein-protein interface. Ivan Rivalta*,#, George P. Lisi #, Ning-Shiuan

More information

Basic Principles of Protein Structures

Basic Principles of Protein Structures Basic Principles of Protein Structures Proteins Proteins: The Molecule of Life Proteins: Building Blocks Proteins: Secondary Structures Proteins: Tertiary and Quartenary Structure Proteins: Geometry Proteins

More information

Chapter 15 Acid-Base Equilibria

Chapter 15 Acid-Base Equilibria Chapter 15 Acid-Base Equilibria Acid-Base Equilibria 15.1 Solutions of Acids or Bases Containing a Common Ion A. Common Ion 1. Ion provided in solution by an aqueous acid (or base) as well as a salt a.

More information

Point: In an unbuffered, unprotected solution, a small addition of strong acid or base can cause a massive and dangerous shift in ph.

Point: In an unbuffered, unprotected solution, a small addition of strong acid or base can cause a massive and dangerous shift in ph. hem 210 Jasperse h 17 Handouts 1 h. 17 Additional Aqueous quilibria hapter 16 situations basically only involved one solute: strong or weak acid; strong or weak base; or ionic salt Real solutions often

More information

Acid-Base Equilibria (Chapter 10.) Problems: 2,3,6,13,16,18,21,30,31,33

Acid-Base Equilibria (Chapter 10.) Problems: 2,3,6,13,16,18,21,30,31,33 Acid-Base Equilibria (Chapter 10.) Problems: 2,3,6,13,16,18,21,30,31,33 Review acid-base theory and titrations. For all titrations, at the equivalence point, the two reactants have completely reacted with

More information

Supplement information

Supplement information Electronic Supplementary Material (ESI) for Physil Chemistry Chemil Physics. This journal is the Owner Societies 216 Supplement information Fullerenol C 6 (OH) 16 prevents amyloid fibrillization of Aβ

More information

Major Types of Association of Proteins with Cell Membranes. From Alberts et al

Major Types of Association of Proteins with Cell Membranes. From Alberts et al Major Types of Association of Proteins with Cell Membranes From Alberts et al Proteins Are Polymers of Amino Acids Peptide Bond Formation Amino Acid central carbon atom to which are attached amino group

More information

BCH 4053 Exam I Review Spring 2017

BCH 4053 Exam I Review Spring 2017 BCH 4053 SI - Spring 2017 Reed BCH 4053 Exam I Review Spring 2017 Chapter 1 1. Calculate G for the reaction A + A P + Q. Assume the following equilibrium concentrations: [A] = 20mM, [Q] = [P] = 40fM. Assume

More information