Chapter 5 Worked Solutions to the Problems
|
|
- William Hamilton
- 5 years ago
- Views:
Transcription
1 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd pter 5 Worked Solutions to te Problems Hints. Strt by writing formul for te re of tringle. Note tt tere re two possible ngles. Now knowing te ngle nd two sides, find te tird side - wi rule pplies ere?. Drw digrm mke sure tt you ve it rigt. Join nd M, nd join E nd M. Now tere re lot of rigt ngles nd rigt-ngled tringles. Introdue one more by joining M to te side on te opposite side of te squre. Now everyting n be done using trigonometri rtios. 3. Drw mp of te pilot s trip. Hve te diretion of nort pointing towrds te top of te pge. Drw in te intended route - te one e sould ve tken. Drw in te new pt e needs to tke. You will ve tringle. 4. gin drw digrm sowing were te two bots re wen tey re on teir voyges. lulte nd mrk te position of bot t 6 pm in te fternoon. Drw in te vetor from one bot to te oter. lulte te lengt of te vetor nd ek if it is long enoug. 5.. Put equl to n ngle in wi is te rigt ngle in rigt ngled tringle b. Drw in te perpendiulr from, it s lengt. Relte, nd. 6. Use te digrm in question 5 but wit te perpendiulr oming down from. Ten pply te definition of os nd os nd you ll find lengts wi togeter mke te side. Now in ft if or is obtuse (between 90 or 80 ) ten tere s subtrtion involved, beuse ltoug te plus sign remins, eiter os or os is negtive. You n see tis by drwing tringle wit or obtuse. 7. Join te entre of te irle to e of te verties of te exgon. You ve 6 tringles. re tey identil? Do tey ve property for wi we ve speil nme? Find teir re, nd ten use little lgebr finises it off. 8. Drw "side-on" digrm wit te metres vertil segment representing te position of te piture nd noter point metre below orresponding to te level of te eye of te person. Ten drw lines from te person's eye position to te top nd bottom of te piture segment. Tese lines mke ngles wit te orizontl line from te piture to te eye, te ngle between tem ving to be 0. Using te definition of te tngent of n ngle you n express te orizontl distne in two wys e involving n unknown ngle. So n eqution for te ngle my be found. Find n pproximte solution of tis eqution, nd te distne from te piture n be lulted from tis.
2 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd 9.. Te sum of te two smll tringles res equls te re of te lrge one. Use tis nd pply some simple lgebr. b. Te rtios in prt () re osines. 0. You ve n equilterl tringle nd segments wit ngle 60 t te entre. Express te given re in terms of tese elements nd do some lgebr to get te required formul.. You need to remember te geometri properties of irles, tngents, rdii nd prllel lines. Te lengt required is te sum of four piees. Tere is q missing from te formul for belt lengt, it sould be: belt lengt π( + b) + θ( b) + osθ.. Te digrm for tis problem is relly te sme s tt used in problem 8 nd te sme formule my be used. Te mnipultions nd te objetive re different but te bsis of te problem is te sme.
3 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd pter 5 Worked Solutions to te Problems. Tink: Tere re two tringles tt meet te stted onditions. We will solve tem seprtely. For e I n find using n re formul. I ten know two sides nd te inluded ngle, so I n ten find side using te osine rule. m 85 m re bsin re sin b sin or m 85 m 8 m 8 m Now we solve bot tringles. b + bos os Te lengt of te 3 rd side of te tringle is 5.6 m. b + bos os Te lengt of te 3 rd side of te tringle is 5.5 m.. Tink: Let te side of te squre be 6 units, so lengts M, DE nd E re ll wole numbers. Let EM x. Drw EF prllel to. I n find FEM nd ED using trig rtios. One I know tose I n find te required ngle. step. Find FEM. opp tnφ dj tnfem 6 FEM tn 6 F M 3 6 x E 4 D 3
4 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd step. Find ED. opp tnφ dj 6 tned 4 6 ED tn 4 step 3. Find x. Sine DEF is rigt ngle, 6 x 90 (tn + tn ) '40'' 3. Tink: In order to find te bering from to we need to first find. I know two sides nd te inluded ngle so I n use te osine rule to find. I n ten use te sine rule to find. Ten I n find te bering. step. Find os N D 400 km 50 km 0 0 step. Find. sin sin sin sin 400sin sin or 54. It is obvious from te digrm tt is step 3. Find te bering. is on bering of 00. Sine D 54., te bering of D is 54. 4
5 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd 4. Tink: t 6 p.m., te first sip s trvelled 48 km wile te seond sip s trvelled 36 km. From te digrm, I need to find. I know two sides nd te inluded ngle so I n use te osine rule. N 48 km + b bos os0 69. Sine te rnge of rdio ommunition is 75 km, te sips will be ble to ommunite t 6 p.m km 5. Tink: ompring te two formuls, tey bot ve ommon ftor of ½b. Terefore I need to sow tt sin. I strt by drwing digrms.. In te digrm longside,. ut lso opp sin yp sin sin b ut sin Te two re formuls re equivlent for ny rigt-ngled tringle. b. In te digrm longside, D is drwn perpendiulr to. From tringle D, opp sin yp sin Te two re formuls re equivlent for ny tringle. D b 5
6 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd 6. We sll prove insted b os + os (sme ting, just different lbels for te verties nd sides). In te digrm longside te bse onsists of two prts, D nd D. D is te bse of te rigt ngled tringle wit nd ypotenuse. D is te bse of te rigt-ngled tringle wit nd ypotenuse. So nd so nd nd so D os D os D os D os D b Now D + D b, so we ve os+ os b s required. 7. Te irle n be tougt of s six ongruent setors. One of te urved blue res equls te re of setor minus te re of te tringle formed by te two rdii nd te ord. Te required re required is six times tis. Now te re of te irle is: re πr π(7) 49 π sq metres. We ten lulte te re of e tringle: re bsin 7 sin(60 ) 7 metres 7 metres 60 0 O Te exgon onsists of six tringles, so te re of te exgon equls 3 re Finlly, lulte te re of te irle minus te re of te exgon: re 49π 49 49( π ) 6.63 sq.metres 6
7 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd 8. P metres Q metre L E Tere re two solutions, toug only seems fesible for person wit norml eyesigt. Let ngle LEQ equl θ If te ngle of viewing is 0 π /9, ten PEL θ +π /9. Sine QL metre, pplying te definition of te tngent of n ngle to tringle QLE, we ve QL/LE tn(θ), so LE QL/tn(θ) /tn(θ). Now te sme rgument pplied to tringle PLE gives LE PL/tn(θ + π/9) 3/tn(θ + π/9). Tus te ngle θ (i.e. QEL) stisfies te eqution 3 tnθ tn( θ + π /9) We nnot solve tis eqution nlytilly, so we will solve it grpilly. Te grp of 3 y tnθ tn( θ + π /9) ppers below. Te grp uts te x xis t x 0. nd. For x 0., LE is pproximtely 4.9 metres, wile for x, LE is pproximtely.64 metres. Te ltter is surely too lose, so we onlude tt te person sould stnd bout 5 metres from te piture. 7
8 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd 9.. Now d sinθ so d sinθ Similrly e sinφ so e sinφ d θ φ N b e Now we will use re sin b to find te re of te tree tringles. re sin( ) θ + φ re N d sinθ re N e sinφ We see tt re ren + ren so sin( θ + φ) sinθ + sinφ {substitute} sin( θ + φ) sinθ + sinφ {multiply troug by } sin( θ + φ) sinθ sinφ + sin( θ + φ) sinθ + sinφ b. Now from te digrm osφ nd osθ. Substituting sin( θ + φ) osφsinθ + osθ sinφ {divide troug by } Re-writing sin( θ + φ) sinθ osφ + sinφosθ 8
9 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd 0. Look t te digrm below, on te left. Te spe mrked by te points, nd onsists of entrl equilterl tringle nd tree ongruent segments. We need to find ll of tese res. Te lengts,, re ll equl to te rdii of te irle, r. Sine is n equilterl tringle ll its ngles re 60. Tus te re of te tringle (ll te re V) is V r sin60 r r 4 Te re of e segment equls te re of te setor minus te re of te tringle. Sine te setor is one-sixt of irle of rdius r, we n find n expression for re G: π G πr r 6 6 so te re of te segment, S, is given by S G V π 3 r r 6 4 π 3 ( ) r 6 4 Te re we re to evlute equls te re of te blk tringle plus 3 times te re of setor, i.e. V + 3S Tus 3 π 3 V + 3S r + 3( r ( )) π 3 r ( + 3( )) π r ( ) π r ( + ) 4 9
10 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd 3 π 3 r ( + 3( )) π 3 r ( ) Te required re is given by: re π 3 r ( ). Tere is n error in te question in te book. Te belt lengt in tis problem is given by ( + b)p + ( - b)q +osq. Note te extr ftor θ. In te digrm bove, te lengt of O, te lengt of OP, nd te lengt of P b. euse te belt is wrpped round e pulley nd te lengts nd D re surely strigt, e of nd D re tngents to te irles wi represent te pulleys. euse is tngent to e irle, te rdii O nd P re perpendiulr to. Tis mens tt O nd P re prllel. To find te lengt of te belt we need to find te lengts of te two strigt line segments, nd D, nd two irulr rs, speifilly, te longer r from to, nd te sorter r from to D. Te key to finding tese lengts is to drw line from P to O prllel to s sown in te digrm. Ten, sine te tngents nd rdii re perpendiulr, te qudrilterl PF is retngle. pplying Pytgors teorem to tringle OFP we n find te lengt of FP nd terefore. Wen tis is done we will know te lengts of ll te 0
11 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd strigt line segments in te digrm, so we just need to find te lengts of te irulr rs. To find te lengts of te irulr rs we need to know te ngles subtended by te rs nd D t te entre of te irle, i.e. we need to know te ngles O nd PD. From te geometry, one we know one ngle in te digrm we n find ny of tem. If we let ngle FPO be q, sine OF - b b we ve sinθ. y symmetry ngle PE is lf te ngle PD. lso, beuse FP is rigt ngle, ngles FPO nd PE sum to 90. Tus ngle PE p/ - q nd ngle PD p - q. Finlly we need te reflex ngle P. Te obtuse ngle P equls te obtuse ngle PD (tese being orresponding ngles of trnsversl utting prllel lines). Tus te reflex ngle P p - (p - q) p + q. Now to omplete te problem, belt lengt ( ) + longer r + sorter r D. Now FP nd from tringle FPO, FP ( b) + or FP os θ, so FP osθ Sine te r of irle equls te produt of te ngle t te entre nd te rdius, we ve longer r ( π+ θ) nd sorter r D ( π- θ ) b tus finlly belt lengt ( π + θ) + ( π θ) b+ osθ nd tis n be rerrnged to give belt lengt π( + b) + θ( b) + osθ. Looking t te digrm te distne d is lbelled, but it doesn t pper in te nswer, so tis suggests tt te vlue of d will be prt of te solution. Now we n relte to te lengts nd d sine te ground nd te liff re te sides in rigt ngled tringle Similrly we n relte, d nd t+.
12 Mtemtis for Queenslnd, Yer Mtemtis, Grpis lultor ppro 00. Kiddy olger, Rex oggs, Rond Frger, Jon elwrd If te definition of te tngent of n ngle is pplied to, we ve tn d Similrly pplying te formul to we ve t+ tn d So d tn nd substituting for d in te seond eqution gives t tn + tn We now simplify te bove expression. First be bring te term tn into te numertor of te rigt side ( to divide by frtion invert te frtion nd multiply ). We ve ( t+ ) tn tn Now multiplying e side by gives tn t+ tn ( ) nd dividing bot sides by tn gives tn ( t ) tn + tn nd ten t tn Finlly ftoring out gives te quoted formul. tn t tn
Trigonometry. cosθ. sinθ tanθ. Mathletics Instant Workbooks. Copyright
Student Book - Series K- sinθ tnθ osθ Mtletis Instnt Workooks Copyrigt Student Book - Series K Contents Topis Topi - Nming te sides of rigt-ngled tringle Topi 2 - Te trigonometri rtios Topi 3 - Using lultor
More information4.3 The Sine Law and the Cosine Law
4.3 Te Sine Lw nd te osine Lw Te ee Tower is te tllest prt of nd s rliment uildings. ronze mst, wi flies te ndin flg, stnds on top of te ee Tower. From point 25 m from te foot of te tower, te ngle of elevtion
More informationSection 2.1 Special Right Triangles
Se..1 Speil Rigt Tringles 49 Te --90 Tringle Setion.1 Speil Rigt Tringles Te --90 tringle (or just 0-60-90) is so nme euse of its ngle mesures. Te lengts of te sies, toug, ve very speifi pttern to tem
More informationMATHEMATICS PAPER & SOLUTION
MATHEMATICS PAPER & SOLUTION Code: SS--Mtemtis Time : Hours M.M. 8 GENERAL INSTRUCTIONS TO THE EXAMINEES:. Cndidte must write first is / er Roll No. on te question pper ompulsorily.. All te questions re
More informationGreen s Theorem. (2x e y ) da. (2x e y ) dx dy. x 2 xe y. (1 e y ) dy. y=1. = y e y. y=0. = 2 e
Green s Theorem. Let be the boundry of the unit squre, y, oriented ounterlokwise, nd let F be the vetor field F, y e y +, 2 y. Find F d r. Solution. Let s write P, y e y + nd Q, y 2 y, so tht F P, Q. Let
More informationPrecalculus Notes: Unit 6 Law of Sines & Cosines, Vectors, & Complex Numbers. A can be rewritten as
Dte: 6.1 Lw of Sines Syllus Ojetie: 3.5 Te student will sole pplition prolems inoling tringles (Lw of Sines). Deriing te Lw of Sines: Consider te two tringles. C C In te ute tringle, sin In te otuse tringle,
More information*GMT62* *20GMT6201* Mathematics. Unit T6 Paper 2 (With calculator) Higher Tier [GMT62] MONDAY 11 JUNE 3.00 pm 4.15 pm. 1 hour 15 minutes.
entre Numer ndidte Numer Mtemtis Generl ertifite Seondry Edution 0 Unit T6 Pper (Wit lultor) Higer Tier [GMT6] MONDAY JUNE 3.00 pm4.5 pm *GMT6* *GMT6* TIME our 5 minutes. INSTRUTIONS TO ANDIDATES Write
More informationPythagorean Theorem and Trigonometry
Ptgoren Teorem nd Trigonometr Te Ptgoren Teorem is nient, well-known, nd importnt. It s lrge numer of different proofs, inluding one disovered merin President Jmes. Grfield. Te we site ttp://www.ut-te-knot.org/ptgors/inde.stml
More informationTrigonometry Revision Sheet Q5 of Paper 2
Trigonometry Revision Sheet Q of Pper The Bsis - The Trigonometry setion is ll out tringles. We will normlly e given some of the sides or ngles of tringle nd we use formule nd rules to find the others.
More informationLESSON 11: TRIANGLE FORMULAE
. THE SEMIPERIMETER OF TRINGLE LESSON : TRINGLE FORMULE In wht follows, will hve sides, nd, nd these will e opposite ngles, nd respetively. y the tringle inequlity, nd..() So ll of, & re positive rel numers.
More informationPYTHAGORAS THEOREM,TRIGONOMETRY,BEARINGS AND THREE DIMENSIONAL PROBLEMS
PYTHGORS THEOREM,TRIGONOMETRY,ERINGS ND THREE DIMENSIONL PROLEMS 1.1 PYTHGORS THEOREM: 1. The Pythgors Theorem sttes tht the squre of the hypotenuse is equl to the sum of the squres of the other two sides
More informationGM1 Consolidation Worksheet
Cmridge Essentils Mthemtis Core 8 GM1 Consolidtion Worksheet GM1 Consolidtion Worksheet 1 Clulte the size of eh ngle mrked y letter. Give resons for your nswers. or exmple, ngles on stright line dd up
More informationPythagoras Theorem. The area of the square on the hypotenuse is equal to the sum of the squares on the other two sides
Pythgors theorem nd trigonometry Pythgors Theorem The hypotenuse of right-ngled tringle is the longest side The hypotenuse is lwys opposite the right-ngle 2 = 2 + 2 or 2 = 2-2 or 2 = 2-2 The re of the
More informationActivities. 4.1 Pythagoras' Theorem 4.2 Spirals 4.3 Clinometers 4.4 Radar 4.5 Posting Parcels 4.6 Interlocking Pipes 4.7 Sine Rule Notes and Solutions
MEP: Demonstrtion Projet UNIT 4: Trigonometry UNIT 4 Trigonometry tivities tivities 4. Pythgors' Theorem 4.2 Spirls 4.3 linometers 4.4 Rdr 4.5 Posting Prels 4.6 Interloking Pipes 4.7 Sine Rule Notes nd
More informationUse of Trigonometric Functions
Unit 03 Use of Trigonometric Functions 1. Introduction Lerning Ojectives of tis UNIT 1. Lern ow te trigonometric functions re relted to te rtios of sides of rigt ngle tringle. 2. Be le to determine te
More informationMaintaining Mathematical Proficiency
Nme Dte hpter 9 Mintining Mthemtil Profiieny Simplify the epression. 1. 500. 189 3. 5 4. 4 3 5. 11 5 6. 8 Solve the proportion. 9 3 14 7. = 8. = 9. 1 7 5 4 = 4 10. 0 6 = 11. 7 4 10 = 1. 5 9 15 3 = 5 +
More informationComparing the Pre-image and Image of a Dilation
hpter Summry Key Terms Postultes nd Theorems similr tringles (.1) inluded ngle (.2) inluded side (.2) geometri men (.) indiret mesurement (.6) ngle-ngle Similrity Theorem (.2) Side-Side-Side Similrity
More informationChapter 2 Differentiation
Cpter Differentition. Introduction In its initil stges differentition is lrgely mtter of finding limiting vlues, wen te vribles ( δ ) pproces zero, nd to begin tis cpter few emples will be tken. Emple..:
More informationMATHEMATICS AND STATISTICS 1.6
MTHMTIS N STTISTIS 1.6 pply geometri resoning in solving prolems ternlly ssessed 4 redits S 91031 inding unknown ngles When finding the size of unknown ngles in figure, t lest two steps of resoning will
More informationTrigonometry and Constructive Geometry
Trigonometry nd Construtive Geometry Trining prolems for M2 2018 term 1 Ted Szylowie tedszy@gmil.om 1 Leling geometril figures 1. Prtie writing Greek letters. αβγδɛθλµπψ 2. Lel the sides, ngles nd verties
More informationSimilar Right Triangles
Geometry V1.noteook Ferury 09, 2012 Similr Right Tringles Cn I identify similr tringles in right tringle with the ltitude? Cn I identify the proportions in right tringles? Cn I use the geometri mens theorems
More informationGeometry of the Circle - Chords and Angles. Geometry of the Circle. Chord and Angles. Curriculum Ready ACMMG: 272.
Geometry of the irle - hords nd ngles Geometry of the irle hord nd ngles urriulum Redy MMG: 272 www.mthletis.om hords nd ngles HRS N NGLES The irle is si shpe nd so it n e found lmost nywhere. This setion
More informationMAT 1275: Introduction to Mathematical Analysis
1 MT 1275: Intrdutin t Mtemtil nlysis Dr Rzenlyum Slving Olique Tringles Lw f Sines Olique tringles tringles tt re nt neessry rigt tringles We re ging t slve tem It mens t find its si elements sides nd
More informationA P P E N D I X POWERS OF TEN AND SCIENTIFIC NOTATION A P P E N D I X SIGNIFICANT FIGURES
A POWERS OF TEN AND SCIENTIFIC NOTATION In science, very lrge nd very smll deciml numbers re conveniently expressed in terms of powers of ten, some of wic re listed below: 0 3 0 0 0 000 0 3 0 0 0 0.00
More informationApril 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then.
pril 8, 2017 Mth 9 Geometry Solving vetor prolems Prolem Prove tht if vetors nd stisfy, then Solution 1 onsider the vetor ddition prllelogrm shown in the Figure Sine its digonls hve equl length,, the prllelogrm
More informationTopics Covered: Pythagoras Theorem Definition of sin, cos and tan Solving right-angle triangles Sine and cosine rule
Trigonometry Topis overed: Pythgors Theorem Definition of sin, os nd tn Solving right-ngle tringles Sine nd osine rule Lelling right-ngle tringle Opposite (Side opposite the ngle θ) Hypotenuse (Side opposite
More informationNaming the sides of a right-angled triangle
6.2 Wht is trigonometry? The word trigonometry is derived from the Greek words trigonon (tringle) nd metron (mesurement). Thus, it literlly mens to mesure tringle. Trigonometry dels with the reltionship
More informationMath Week 5 concepts and homework, due Friday February 10
Mt 2280-00 Week 5 concepts nd omework, due Fridy Februry 0 Recll tt ll problems re good for seeing if you cn work wit te underlying concepts; tt te underlined problems re to be nded in; nd tt te Fridy
More informationSection 4.7 Inverse Trigonometric Functions
Section 7 Inverse Trigonometric Functions 89 9 Domin: 0, q Rnge: -q, q Zeros t n, n nonnegtive integer 9 Domin: -q, 0 0, q Rnge: -q, q Zeros t, n non-zero integer Note: te gr lso suggests n te end-bevior
More informationPROPERTIES OF TRIANGLES
PROPERTIES OF TRINGLES. RELTION RETWEEN SIDES ND NGLES OF TRINGLE:. tringle onsists of three sides nd three ngles lled elements of the tringle. In ny tringle,,, denotes the ngles of the tringle t the verties.
More information3.1 Review of Sine, Cosine and Tangent for Right Angles
Foundtions of Mth 11 Section 3.1 Review of Sine, osine nd Tngent for Right Tringles 125 3.1 Review of Sine, osine nd Tngent for Right ngles The word trigonometry is derived from the Greek words trigon,
More informationExam 1 Review Solutions
Exam Review Solutions Please also review te old quizzes, and be sure tat you understand te omework problems. General notes: () Always give an algebraic reason for your answer (graps are not sufficient),
More informationm A 1 1 A ! and AC 6
REVIEW SET A Using sle of m represents units, sketh vetor to represent: NON-CALCULATOR n eroplne tking off t n ngle of 8 ± to runw with speed of 6 ms displement of m in north-esterl diretion. Simplif:
More information2. There are an infinite number of possible triangles, all similar, with three given angles whose sum is 180.
SECTION 8-1 11 CHAPTER 8 Setion 8 1. There re n infinite numer of possile tringles, ll similr, with three given ngles whose sum is 180. 4. If two ngles α nd β of tringle re known, the third ngle n e found
More informationNon Right Angled Triangles
Non Right ngled Tringles Non Right ngled Tringles urriulum Redy www.mthletis.om Non Right ngled Tringles NON RIGHT NGLED TRINGLES sin i, os i nd tn i re lso useful in non-right ngled tringles. This unit
More informationCHENG Chun Chor Litwin The Hong Kong Institute of Education
PE-hing Mi terntionl onferene IV: novtion of Mthemtis Tehing nd Lerning through Lesson Study- onnetion etween ssessment nd Sujet Mtter HENG hun hor Litwin The Hong Kong stitute of Edution Report on using
More informationMathematics. Area under Curve.
Mthemtics Are under Curve www.testprepkrt.com Tle of Content 1. Introduction.. Procedure of Curve Sketching. 3. Sketching of Some common Curves. 4. Are of Bounded Regions. 5. Sign convention for finding
More informationm m m m m m m m P m P m ( ) m m P( ) ( ). The o-ordinte of the point P( ) dividing the line segment joining the two points ( ) nd ( ) eternll in the r
CO-ORDINTE GEOMETR II I Qudrnt Qudrnt (-.+) (++) X X - - - 0 - III IV Qudrnt - Qudrnt (--) - (+-) Region CRTESIN CO-ORDINTE SSTEM : Retngulr Co-ordinte Sstem : Let X' OX nd 'O e two mutull perpendiulr
More information1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
1 PYTHAGORAS THEOREM 1 1 Pythgors Theorem In this setion we will present geometri proof of the fmous theorem of Pythgors. Given right ngled tringle, the squre of the hypotenuse is equl to the sum of the
More informationHYPERBOLA. AIEEE Syllabus. Total No. of questions in Ellipse are: Solved examples Level # Level # Level # 3..
HYPERBOLA AIEEE Sllus. Stndrd eqution nd definitions. Conjugte Hperol. Prmetric eqution of te Hperol. Position of point P(, ) wit respect to Hperol 5. Line nd Hperol 6. Eqution of te Tngent Totl No. of
More informationMath 20C Multivariable Calculus Lecture 5 1. Lines and planes. Equations of lines (Vector, parametric, and symmetric eqs.). Equations of lines
Mt 2C Multivrible Clculus Lecture 5 1 Lines nd plnes Slide 1 Equtions of lines (Vector, prmetric, nd symmetric eqs.). Equtions of plnes. Distnce from point to plne. Equtions of lines Slide 2 Definition
More informationCalculating Tank Wetted Area Saving time, increasing accuracy
Clulting Tnk Wetted Are ving time, inresing ur B n Jones, P.., P.E. C lulting wetted re in rtillfilled orizontl or vertil lindril or ellitil tnk n e omlited, deending on fluid eigt nd te se of te eds (ends)
More informationSECTION A STUDENT MATERIAL. Part 1. What and Why.?
SECTION A STUDENT MATERIAL Prt Wht nd Wh.? Student Mteril Prt Prolem n > 0 n > 0 Is the onverse true? Prolem If n is even then n is even. If n is even then n is even. Wht nd Wh? Eploring Pure Mths Are
More information3 Angle Geometry. 3.1 Measuring Angles. 1. Using a protractor, measure the marked angles.
3 ngle Geometry MEP Prtie ook S3 3.1 Mesuring ngles 1. Using protrtor, mesure the mrked ngles. () () (d) (e) (f) 2. Drw ngles with the following sizes. () 22 () 75 120 (d) 90 (e) 153 (f) 45 (g) 180 (h)
More informationSolutions to Problems Integration in IR 2 and IR 3
Solutions to Problems Integrtion in I nd I. For ec of te following, evlute te given double integrl witout using itertion. Insted, interpret te integrl s, for emple, n re or n verge vlue. ) dd were is te
More informationSection 1.3 Triangles
Se 1.3 Tringles 21 Setion 1.3 Tringles LELING TRINGLE The line segments tht form tringle re lled the sides of the tringle. Eh pir of sides forms n ngle, lled n interior ngle, nd eh tringle hs three interior
More informationBasic Angle Rules 5. A Short Hand Geometric Reasons. B Two Reasons. 1 Write in full the meaning of these short hand geometric reasons.
si ngle Rules 5 6 Short Hnd Geometri Resons 1 Write in full the mening of these short hnd geometri resons. Short Hnd Reson Full Mening ) se s isos Δ re =. ) orr s // lines re =. ) sum s t pt = 360. d)
More information2.1 ANGLES AND THEIR MEASURE. y I
.1 ANGLES AND THEIR MEASURE Given two interseting lines or line segments, the mount of rottion out the point of intersetion (the vertex) required to ring one into orrespondene with the other is lled the
More informationPreface. Here are a couple of warnings to my students who may be here to get a copy of what happened on a day that you missed.
Preface Here are my online notes for my course tat I teac ere at Lamar University. Despite te fact tat tese are my class notes, tey sould be accessible to anyone wanting to learn or needing a refreser
More informationMCH T 111 Handout Triangle Review Page 1 of 3
Hnout Tringle Review Pge of 3 In the stuy of sttis, it is importnt tht you e le to solve lgeri equtions n tringle prolems using trigonometry. The following is review of trigonometry sis. Right Tringle:
More informationLoudoun Valley High School Calculus Summertime Fun Packet
Loudoun Vlley High School Clculus Summertime Fun Pcket We HIGHLY recommend tht you go through this pcket nd mke sure tht you know how to do everything in it. Prctice the problems tht you do NOT remember!
More information15 - TRIGONOMETRY Page 1 ( Answers at the end of all questions )
- TRIGONOMETRY Pge P ( ) In tringle PQR, R =. If tn b c = 0, 0, then Q nd tn re the roots of the eqution = b c c = b b = c b = c [ AIEEE 00 ] ( ) In tringle ABC, let C =. If r is the inrdius nd R is the
More informationTHREE DIMENSIONAL GEOMETRY
MD THREE DIMENSIONAL GEOMETRY CA CB C Coordintes of point in spe There re infinite numer of points in spe We wnt to identif eh nd ever point of spe with the help of three mutull perpendiulr oordintes es
More informationAP Calculus BC Chapter 8: Integration Techniques, L Hopital s Rule and Improper Integrals
AP Clulus BC Chpter 8: Integrtion Tehniques, L Hopitl s Rule nd Improper Integrls 8. Bsi Integrtion Rules In this setion we will review vrious integrtion strtegies. Strtegies: I. Seprte the integrnd into
More information12.4 Similarity in Right Triangles
Nme lss Dte 12.4 Similrit in Right Tringles Essentil Question: How does the ltitude to the hpotenuse of right tringle help ou use similr right tringles to solve prolems? Eplore Identifing Similrit in Right
More informationPYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL:
PYTHAGORAS THEOREM 1 WHAT S IN CHAPTER 1? 1 01 Squres, squre roots nd surds 1 02 Pythgors theorem 1 03 Finding the hypotenuse 1 04 Finding shorter side 1 05 Mixed prolems 1 06 Testing for right-ngled tringles
More informationTwo Triads of Congruent Circles from Reflections
Forum Geometriorum Volume 8 (2008) 7 12. FRUM GEM SSN 1534-1178 Two Trids of ongruent irles from Refletions Qung Tun ui strt. Given tringle, we onstrut two trids of ongruent irles through the verties,
More informationProportions: A ratio is the quotient of two numbers. For example, 2 3
Proportions: rtio is the quotient of two numers. For exmple, 2 3 is rtio of 2 n 3. n equlity of two rtios is proportion. For exmple, 3 7 = 15 is proportion. 45 If two sets of numers (none of whih is 0)
More informationPerimeter and Area. Mathletics Instant Workbooks. Copyright
Perimeter nd Are Student Book - Series J- L B Mthletis Instnt Workooks Copyright Student Book - Series J Contents Topis Topi - Plne shpes Topi 2 - Perimeter of regulr shpes Topi 3 - Perimeter of irregulr
More informationContinuity and Differentiability Worksheet
Continuity and Differentiability Workseet (Be sure tat you can also do te grapical eercises from te tet- Tese were not included below! Typical problems are like problems -3, p. 6; -3, p. 7; 33-34, p. 7;
More informationSAINT IGNATIUS COLLEGE
SAINT IGNATIUS COLLEGE Directions to Students Tril Higher School Certificte 0 MATHEMATICS Reding Time : 5 minutes Totl Mrks 00 Working Time : hours Write using blue or blck pen. (sketches in pencil). This
More informationA LEVEL TOPIC REVIEW. factor and remainder theorems
A LEVEL TOPIC REVIEW unit C fctor nd reminder theorems. Use the Fctor Theorem to show tht: ) ( ) is fctor of +. ( mrks) ( + ) is fctor of ( ) is fctor of + 7+. ( mrks) +. ( mrks). Use lgebric division
More informationMathematics Extension 2
00 HIGHER SCHOOL CERTIFICATE EXAMINATION Mthemtics Etension Generl Instructions Reding time 5 minutes Working time hours Write using blck or blue pen Bord-pproved clcultors my be used A tble of stndrd
More informationNumbers and indices. 1.1 Fractions. GCSE C Example 1. Handy hint. Key point
GCSE C Emple 7 Work out 9 Give your nswer in its simplest form Numers n inies Reiprote mens invert or turn upsie own The reiprol of is 9 9 Mke sure you only invert the frtion you re iviing y 7 You multiply
More informationf (x)dx = f(b) f(a). a b f (x)dx is the limit of sums
Green s Theorem If f is funtion of one vrible x with derivtive f x) or df dx to the Fundmentl Theorem of lulus, nd [, b] is given intervl then, ording This is not trivil result, onsidering tht b b f x)dx
More informationSomething found at a salad bar
Nme PP Something found t sld r 4.7 Notes RIGHT TRINGLE hs extly one right ngle. To solve right tringle, you n use things like SOH-H-TO nd the Pythgoren Theorem. n OLIQUE TRINGLE hs no right ngles. To solve
More information3.4 Worksheet: Proof of the Chain Rule NAME
Mat 1170 3.4 Workseet: Proof of te Cain Rule NAME Te Cain Rule So far we are able to differentiate all types of functions. For example: polynomials, rational, root, and trigonometric functions. We are
More informationPrerequisite Knowledge Required from O Level Add Math. d n a = c and b = d
Prerequisite Knowledge Required from O Level Add Mth ) Surds, Indices & Logrithms Rules for Surds. b= b =. 3. 4. b = b = ( ) = = = 5. + b n = c+ d n = c nd b = d Cution: + +, - Rtionlising the Denomintor
More informationMTH 4-16a Trigonometry
MTH 4-16 Trigonometry Level 4 [UNIT 5 REVISION SECTION ] I cn identify the opposite, djcent nd hypotenuse sides on right-ngled tringle. Identify the opposite, djcent nd hypotenuse in the following right-ngled
More informationAndrew Ryba Math Intel Research Final Paper 6/7/09 (revision 6/17/09)
Andrew Ryb Mth ntel Reserch Finl Pper 6/7/09 (revision 6/17/09) Euler's formul tells us tht for every tringle, the squre of the distnce between its circumcenter nd incenter is R 2-2rR, where R is the circumrdius
More informationPart I: Study the theorem statement.
Nme 1 Nme 2 Nme 3 A STUDY OF PYTHAGORAS THEOREM Instrutions: Together in groups of 2 or 3, fill out the following worksheet. You my lift nswers from the reding, or nswer on your own. Turn in one pket for
More informationPythagoras theorem and surds
HPTER Mesurement nd Geometry Pythgors theorem nd surds In IE-EM Mthemtis Yer 8, you lernt out the remrkle reltionship etween the lengths of the sides of right-ngled tringle. This result is known s Pythgors
More informationF / x everywhere in some domain containing R. Then, + ). (10.4.1)
0.4 Green's theorem in the plne Double integrls over plne region my be trnsforme into line integrls over the bounry of the region n onversely. This is of prtil interest beuse it my simplify the evlution
More information6.5 Improper integrals
Eerpt from "Clulus" 3 AoPS In. www.rtofprolemsolving.om 6.5. IMPROPER INTEGRALS 6.5 Improper integrls As we ve seen, we use the definite integrl R f to ompute the re of the region under the grph of y =
More informationA-Level Mathematics Transition Task (compulsory for all maths students and all further maths student)
A-Level Mthemtics Trnsition Tsk (compulsory for ll mths students nd ll further mths student) Due: st Lesson of the yer. Length: - hours work (depending on prior knowledge) This trnsition tsk provides revision
More informationMathematics 10 Page 1 of 5 Properties of Triangle s and Quadrilaterals. Isosceles Triangle. - 2 sides and 2 corresponding.
Mthemtis 10 Pge 1 of 5 Properties of s Pthgoren Theorem 2 2 2 used to find the length of sides of right tringle Tpe of s nd Some s Theorems ngles s Slene Isoseles Equilterl ute - ll ngles re less thn 90
More informationLesson 2: The Pythagorean Theorem and Similar Triangles. A Brief Review of the Pythagorean Theorem.
27 Lesson 2: The Pythgoren Theorem nd Similr Tringles A Brief Review of the Pythgoren Theorem. Rell tht n ngle whih mesures 90º is lled right ngle. If one of the ngles of tringle is right ngle, then we
More informationStage 11 Prompt Sheet
Stge 11 rompt Sheet 11/1 Simplify surds is NOT surd ecuse it is exctly is surd ecuse the nswer is not exct surd is n irrtionl numer To simplify surds look for squre numer fctors 7 = = 11/ Mnipulte expressions
More informationLesson-5 PROPERTIES AND SOLUTIONS OF TRIANGLES
Leon-5 PROPERTIES ND SOLUTIONS OF TRINGLES Reltion etween the ide nd trigonometri rtio of the ngle of tringle In ny tringle, the ide, oppoite to the ngle, i denoted y ; the ide nd, oppoite to the ngle
More informationGEOMETRICAL PROPERTIES OF ANGLES AND CIRCLES, ANGLES PROPERTIES OF TRIANGLES, QUADRILATERALS AND POLYGONS:
GEOMETRICL PROPERTIES OF NGLES ND CIRCLES, NGLES PROPERTIES OF TRINGLES, QUDRILTERLS ND POLYGONS: 1.1 TYPES OF NGLES: CUTE NGLE RIGHT NGLE OTUSE NGLE STRIGHT NGLE REFLEX NGLE 40 0 4 0 90 0 156 0 180 0
More informationIn right-angled triangles the square on the side subtending the right angle is equal to the squares on the sides containing the right angle.
Mth 3329-Uniform Geometries Leture 06 1. Review of trigonometry While we re looking t Eulid s Elements, I d like to look t some si trigonometry. Figure 1. The Pythgoren theorem sttes tht if = 90, then
More informationCoimisiún na Scrúduithe Stáit State Examinations Commission
M 30 Coimisiún n Scrúduithe Stáit Stte Exmintions Commission LEAVING CERTIFICATE EXAMINATION, 005 MATHEMATICS HIGHER LEVEL PAPER ( 300 mrks ) MONDAY, 3 JUNE MORNING, 9:30 to :00 Attempt FIVE questions
More informationONLINE PAGE PROOFS. Trigonometry Kick off with CAS 12.2 Trigonometry 12.3 Pythagorean triads
12 12.1 Kik off with S 12.2 Trigonometry 12.3 Pythgoren trids Trigonometry 12.4 Three-dimensionl Pythgors theorem 12.5 Trigonometri rtios 12.6 The sine rule 12.7 miguous se of the sine rule 12.8 The osine
More information] dx (3) = [15x] 2 0
Leture 6. Double Integrls nd Volume on etngle Welome to Cl IV!!!! These notes re designed to be redble nd desribe the w I will eplin the mteril in lss. Hopefull the re thorough, but it s good ide to hve
More informationThe angle sum of a triangle is 180, as one angle is 90 the other two angles must add to 90. α + β = 90. Angles can be labelled;
Numercy Introuction to Trigonometry Pytgors Teorem n bsic Trigonometry use rigt ngle tringle structures. (Avnce Trigonometry uses non-rigt ngle tringles) Te ngle sum of tringle is 180, s one ngle is 90
More information*GMT41* *24GMT4101* Mathematics. Unit T4 (With calculator) Higher Tier [GMT41] WEDNESDAY 6 JUNE 9.15 am am. 2 hours.
entre Numer ndidte Numer Mtemtics Generl ertificte Secondry Eduction 0 Unit T4 (Wit clcultor) Higer Tier [GMT4] WEDNESDAY 6 JUNE 9.5 m.5 m *GMT4* *GMT4* TIME ours. INSTRUTIONS TO ANDIDATES Write your entre
More informationHS Pre-Algebra Notes Unit 9: Roots, Real Numbers and The Pythagorean Theorem
HS Pre-Alger Notes Unit 9: Roots, Rel Numers nd The Pythgoren Theorem Roots nd Cue Roots Syllus Ojetive 5.4: The student will find or pproximte squre roots of numers to 4. CCSS 8.EE.-: Evlute squre roots
More information5Trigonometric UNCORRECTED PAGE PROOFS. ratios and their applications
5Trigonometri rtios nd their pplitions 5.1 Kik off with CS 5.2 Trigonometry of right-ngled tringles 5.3 Elevtion, depression nd erings 5.4 The sine rule 5.5 The osine rule 5.6 rs, setors nd segments 5.7
More informationCHAPTER 4: DETERMINANTS
CHAPTER 4: DETERMINANTS MARKS WEIGHTAGE 0 mrks NCERT Importnt Questions & Answers 6. If, then find the vlue of. 8 8 6 6 Given tht 8 8 6 On epnding both determinnts, we get 8 = 6 6 8 36 = 36 36 36 = 0 =
More informationPrecalculus Notes: Unit 6 Law of Sines & Cosines, Vectors, & Complex Numbers. A can be rewritten as B
Date: 6.1 Law of Sines Syllaus Ojetie: 3.5 Te student will sole appliation prolems inoling triangles (Law of Sines). Deriing te Law of Sines: Consider te two triangles. a C In te aute triangle, sin and
More informationIndividual Group. Individual Events I1 If 4 a = 25 b 1 1. = 10, find the value of.
Answers: (000-0 HKMO Het Events) Creted y: Mr. Frnis Hung Lst udted: July 0 00-0 33 3 7 7 5 Individul 6 7 7 3.5 75 9 9 0 36 00-0 Grou 60 36 3 0 5 6 7 7 0 9 3 0 Individul Events I If = 5 = 0, find the vlue
More informationHigher Maths. Self Check Booklet. visit for a wealth of free online maths resources at all levels from S1 to S6
Higher Mths Self Check Booklet visit www.ntionl5mths.co.uk for welth of free online mths resources t ll levels from S to S6 How To Use This Booklet You could use this booklet on your own, but it my be
More informationNOT TO SCALE. We can make use of the small angle approximations: if θ á 1 (and is expressed in RADIANS), then
3. Stellr Prllx y terrestril stndrds, the strs re extremely distnt: the nerest, Proxim Centuri, is 4.24 light yers (~ 10 13 km) wy. This mens tht their prllx is extremely smll. Prllx is the pprent shifting
More informationLinear Inequalities: Each of the following carries five marks each: 1. Solve the system of equations graphically.
Liner Inequlities: Ech of the following crries five mrks ech:. Solve the system of equtions grphiclly. x + 2y 8, 2x + y 8, x 0, y 0 Solution: Considerx + 2y 8.. () Drw the grph for x + 2y = 8 by line.it
More informationQUESTION PAPER CODE 65/2/1 EXPECTED ANSWERS/VALUE POINTS SECTION - A SECTION - B. f (x) f (y) = w = codomain. sin sin 5
-.. { 8, 7} QUESTON AER ODE 6// EXETED ANSWERS/VALUE ONTS SETON - A 6.. Mrks.. k 7 6. tn ot 7. log or log 8.. Let, W. 6 i j 8 k. os SETON - B f nd both re even, f () f () f nd both re odd, f () f () f
More informationA sequence is a list of numbers in a specific order. A series is a sum of the terms of a sequence.
Core Module Revision Sheet The C exm is hour 30 minutes long nd is in two sections. Section A (36 mrks) 8 0 short questions worth no more thn 5 mrks ech. Section B (36 mrks) 3 questions worth mrks ech.
More informationPerimeter, area and volume
6 Perimeter, re nd volume Syllus topi M. Perimeter, re nd volume This topi will develop your skills to ompetently solve prolems involving perimeter, re, volume nd pity. Outomes Clulte the re of irles nd
More informationMath Lesson 4-5 The Law of Cosines
Mth-1060 Lesson 4-5 The Lw of osines Solve using Lw of Sines. 1 17 11 5 15 13 SS SSS Every pir of loops will hve unknowns. Every pir of loops will hve unknowns. We need nother eqution. h Drop nd ltitude
More informationSect 10.2 Trigonometric Ratios
86 Sect 0. Trigonometric Rtios Objective : Understnding djcent, Hypotenuse, nd Opposite sides of n cute ngle in right tringle. In right tringle, the otenuse is lwys the longest side; it is the side opposite
More information1 Review: Volumes of Solids (Stewart )
Lecture : Some Bic Appliction of Te Integrl (Stewrt 6.,6.,.,.) ul Krin eview: Volume of Solid (Stewrt 6.-6.) ecll: we d provided two metod for determining te volume of olid of revolution. Te rt w by dic
More information