PHY2054 Exam 1 Formula Sheet
|
|
- Janis Carroll
- 5 years ago
- Views:
Transcription
1 Instucto: Field/Mitselmakhe PHYSICS DPATMNT PHY 54 Final am Apil 3, 6 Name (PINT, last, fist): Signatue: On my hono, I have neithe given no eceived unauthoized aid on this eamination. YOU TST NUMB IS TH 5-DIGIT NUMB AT TH TOP OF ACH PAG. DICTIONS () Code you test numbe on you answe sheet (use 76 8 fo the 5-digit numbe). Code you name on you answe sheet. DAKN CICS COMPTY. Code you student numbe on you answe sheet. () Pint you name on this sheet and sign it also. (3) Do all scatch wok anywhee on this eam that you like. At the end of the test, this eam pintout is to be tuned in. No cedit will be given without both answe sheet and pintout with scatch wok most questions demand. (4) Blacken the cicle of you intended answe completely, using a # pencil o blue o black ink. Do not make any stay maks o the answe sheet may not ead popely. (5) The answes ae ounded off. Choose the closest to eact. Thee is no penalty fo guessing. >>>>>>>>WHN YOU FINISH <<<<<<<< Hand in the answe sheet sepaately. Constants ǫ = 8.85 F/m m e = 9. 3 kg m p = m n =.67 7 kg e =.6 9 C k = N m /C µ =.56 7 H/m N A = 6. 3 atoms/mole c = 3 8 m/s milli = 3 mico = 6 nano = 9 pico =
2 PHY54 am Fomula Sheet ectos & Quadatic Fomula a = a ˆ ayyˆ azzˆ b = bˆ byyˆ bzzˆ Magnitudes: a = a ay az b = b by bz Scala Poduct: a b = ab ab ab = ab cosθ (θ = angle between a and b ) Quadatic Fomula: if b c= lectostatic Foce (vecto): lectic Field (at q due to q): y y z z a then = ( b± b 4ac) /(a) lectostatic Foce and lectic Field qq F = k ˆ ( = distance between chage q and chage q, units = N) k = /(4πε ) = N m /C ε = C /(N m ) q = F / q = k ˆ (units = N/C = /m) d = da lectic Flu (though the infinitesimal suface aea da): (units = Nm /C) ecto Aea (diected aea): A= Anˆ (whee nˆ = nomal to the suface) Gauss aw: Φ = S Q da= A= S enclosed ε Φ (Q enclosed = chage enclosed) Gauss aw: Net flu though closed suface S = the chage enclosed by suface S divided by ε lectic Potential and Potential negy lectic Potential negy: wok done against a constant field in moving chage q a distance d along staight line path fom A to B, U = UB UA = q d (units = J) lectic Potential: Wok done pe unit chage against a constant field in moving chage q a distance d along staight line path fom A to B, = U / q = d (units = J/C = ) lectic Potential (distance fom a point chage q): lectic Potential negy (N point chages): N U = i= N q qi ( ) = k N point chages: ( ) = k Stoed lectic Potential negy (N conductos with chage Q i and electic potential i ): q i i Capacitance (definition): C = Q/ o C = Q/ (units = C/ = F) Paallel Plate Capacito with Dielectic κ: negy Density of the lectic Field: u ε C =κε A/ d = (units = J/m 3 ) lectic Cuent and Cicuits dq Cuent (though diected aea A): I = = nqvdift A (units = C/s = A, n is the numbe of chaged paticles q dt pe unit volume, v dift is the aveage velocity of the chaged paticles). Ohm s aw: = I, = ρ / A (esistance units = /A = Ω) Powe (supplied by MF ε): P = εi Powe (dissipated in esisto ): P = I (units = J/s = W) t /τ C Cicuits (chaging capacito C though esisto with MF ε): Qt ( ) = εc( e ) C Cicuits (dischaging capacito C with initial chage Q though esisto ): C Cicuits (time constant):τ = C (units = Ω F = s), U Qt ( ) = Qe = i= whee i is the electic potential at q i due to the othe chages t /τ N i= i Q i i
3 PHY54 am Fomula Sheet ectos a = a ˆ a yˆ y azzˆ b = bˆ byyˆ bzzˆ Coss Poduct Magbitude: a b = ab sinθab c = a b = ( ab ab ) ˆ ( ab ab ) yˆ ( ab ab ) zˆ Coss Poduct ecto: F y z z y z z lectomagnetic Foce = F F = q qv B F = q F = qv B lectmagnetic Foce (vecto): M B B ( = distance between chage Q and chage q, v = velocity of chage q, = velocity of chage Q) F Qq = k ˆ (units = N) F B Qq = k v c ˆ y y (units = N) k = /(4πε ) N m /C ε C /(N m ) k B = k/c =µ /(4π) -7 Tm/A µ 4π -7 Tm/A c 3 8 m/s (speed of light) lectic and Magnetic Field (due to Q): Magnetic Field (due to cuent I in length dl of wie): negy Density (lectic & Magnetic Field): Q Q = k ˆ (N/C = /m) B= k ˆ B I db= kb dl ˆ u ε ub = B µ F B = I B (units = N) µ = NIA (units = A m ) A= Anˆ Toque: τ =µ B Magnetic Foce (on a long staight wie caying cuent I): Magnetic Dipole Moment: Ampee s aw: B B dl = B l= µ C C Infinite Staight Wie: BI pep I enclosed (N/(C m/s) = T) (units = N/(C m/s) = T) = (units = J/m 3 ) (closed loop) Magnetic Field (amples) B = k / Cente of a Cicula Cuent oop: lectomagnetic Induction, Cicuits, C Cicuits, AC Cicuits Φ = B A= BAcosθ B A Magnetic Flu (unifom B, suface A): B = dφ Faaday s aw of Induction: ε = B (ε = induced emf, units = ) dt d cos( ωt) ate of Change with Time: = ω sin( ωt) dt di Inducto (inductance units = H): = (potential diffeence) dt Cicuits (time constant):τ = / (units = H/Ω = s) Cicuits (MF ε, esisto, Inducto, swich closed at t = ): I( t) Oscillating C Cicuit (no esistance): pep B units = Tm = Wb U = I = ε ( e t /τ (units = N m) B = π kb I / (stoed enegy) ) / = Q / C I (stoed enegy) ω= / C U tot Oscillating C Cicuit (no esistance): f = ω/π (fequency of oscillations in Hz) AC Cicuit Impedance (ε(t) = εmasin(ωtφ), X =, X = ω, XC = /ωc): Z = ε AC Cicuit Maimum Cuent & Aveage Powe: ma Ima = Pave = Imaε max / Z Z AC Cicuit MS Cuent & oltage: I ms = I ma / ε ms =ε ma / X ( X X ) C
4 ick s ectues: Speed in acuum: Closed Cuve PHY54 Final am Fomula Sheet Ampee s aw (complete) dφ B dl = µ Ienclosed µ ε Tetbook: B l= µ Ienclosed µ ε dt (, t) = B(, t) = B ma ma Wavelength in Medium: λ n = n Poynting ecto: S = B, µ Intensity: Closed Cuve lectomagnetic Plane Wave sin( k ωt) yˆ sin( k ωt) zˆ (, t) = cb(, t) Φ t ω c c= = fλ = Speed in Medium (n = inde of efaction): v n = < c k µ ε n λ (λ = Wavelength in acuum, n = inde of efaction) S = S = B= = µ µ c P powe P powe ms cbms cb I = S = = = = = (units = W/m ) A µ c µ µ c µ A (units = W/m ) Intensity Tansmitted by a Poloize: I = I (andom) I = I cos θ (polaized) elativistic Dopple Shift (f = fequency at est with souce, λ = wavelength at est with souce, fλ = c) β β λ away = λ f away = f β = / c β β Souce Moving Away fom Obseve: Souce Moving Towad the Obseve: Snell s aw: λ towad = β β = λ f towad = f β / c β β ( = elative velocity) ( = elative velocity) eflection & efaction n sinθ = n sinθ Total Intenal eflection in Medium (): sin c =n / n tanθ B =n n Bewste s Angle in Medium (): Mios & Thin ens Spheical Mios ( = adius of cuvatue): f = / Object and Image Position (mios & thin lens): = f p q q Magnification (mios & thin lens): m=, h = m h p eflection in Medium off Medium : (phase shift n > n ) (lateal shift n > n ) Maimal Constuctive: (phase shift) Maimal Destuctive: (phase shift) ) / θ (n < n ) eflection & Intefeence φ = π (phase shift n < n ) φ = l = φ / k = λ / (lateal shift n < n ) l= φ = πm (lateal shift) l=mλ m=, ±, ±, φ = π ( m (lateal shift) l= ( m ) λ m=, ±, ±, Wavelength (in m): λ Wavenumbe (in m - ): k = π/λ Angula Fequence (in ad/s): ω = πf Fequency (in Hz): f Peiod (in s): T = /f f = focal length (> concave, < conve) p = objct distance q = image distance (> eal, < vitual) h = object height h' = image height m = magnification (> upight, < inveted) Intensity: (ma constuctive) I = I I II (ma destuctive) I = I I II Single-Slit Minima: d sinθ = mλ esolving Powe (lens diamete D: θ.λ / D Double-Slit (and gating): (ma constuctive) d sin θ = mλ (ma destuctive) d sinθ = ( m ) λ
5 . Thee point paticles lie on the. Chage Q is at = d, chage Q is at = d, and chage Q 3 is at = d, as shown in the figue. If Q = q and Q = q, and if the net electic field fom the thee chages is zeo at the oigin (i.e., = y = ), what is Q 3? y-ais Q Q Q 3 d d d () 4q () 8q (3) 4q (4) 8q (5) q. Thee point paticles lie on the. Chage Q is at = d, chage Q is at = d, and chage Q 3 is at = d, as shown in the figue. If Q = q and Q = 3q, and if the net electic field fom the thee chages is zeo at the oigin (i.e., = y = ), what is Q 3? y-ais Q Q Q 3 d d d () 8q () 4q (3) 4q (4) 8q (5) q 3. Thee point paticles lie on the. Chage Q is at = d, chage Q is at = d, and chage Q 3 is at = d, as shown in the figue. If Q = q and Q = q, and if the net electic field fom the thee chages is zeo at the oigin (i.e., = y = ), what is Q 3? y-ais Q Q Q 3 d d d () 4q () 4q (3) 8q (4) 8q (5) q 4. Conside a cube of sides = m as shown in the figue, and suppose that a non-unifom electic field is pesent and is given by (,y) = aˆ byŷ, whee a = 4 /m and b = /m ae constants. The -component of the electic field is y (y) = by. What is the net electic chage (in nanoc) contained within the cube? O y-ais z-ais ().4 ().83 (3) 4.5 (4) 5.67 (5) Conside a cube of sides = m as shown in the figue, and suppose that a non-unifom electic field is pesent and is given by (,y) = aˆ byŷ, whee a = 6 /m and b = /m ae constants. The -component of the electic field is y (y) = by. What is the net electic chage (in nanoc) contained within the cube? O y-ais z-ais ().83 ().4 (3) 4.5 (4) 5.67 (5) Conside a cube of sides = m as shown in the figue, and suppose that a non-unifom electic field is pesent and is given by (,y) = aˆ byŷ, whee a = 8 /m and b = /m ae constants. The -component of the electic field is y (y) = by. What is the net electic chage (in nanoc) contained within the cube? O y-ais z-ais () 4.5 ().4 (3).83 (4) 5.67 (5) 7.8
6 7. How much electic enegy (in micoj) is stoed by a solid spheical conducto with a chage of nc and a adius of. m? () 4.8 () 49.8 (3).4 (4) 8.9 (5) How much electic enegy (in micoj) is stoed by a solid spheical conducto with a chage of nc and a adius of.3 m? () 49.8 () 4.8 (3).4 (4) 8.9 (5) How much electic enegy (in micoj) is stoed by a solid spheical conducto with a chage of nc and a adius of.4 m? ().4 () 4.8 (3) 49.8 (4) 8.9 (5) A positively chaged paticle with a chage to mass atio q/m =. C/kg is taveling to the ight along the. At = it entes an ideal paallel plate capacito though a small hole with speed = 8 m/s as shown in the figue. The plates of the capacito have aea A = m and lie in the y-z plane. The plate at = caies chage Q and the plate at = d caies chage Q. If Q = 8.85µC and d = 5 cm, what is the speed (in m/s) of the paticle when it eits the capacito though the small hole at = d? y-ais -Q Q d () 5. (). (3) 4.9 (4).4 (5) 6.3. A positively chaged paticle with a chage to mass atio q/m =. C/kg is taveling to the ight along the. At = it entes an ideal paallel plate capacito though a small hole with speed = 8 m/s as shown in the figue. The plates of the capacito have aea A = m and lie in the y-z plane. The plate at = caies chage Q and the plate at = d caies chage Q. If Q = 8.85µC and d = 5 cm, what is the speed (in m/s) of the paticle when it eits the capacito though the small hole at = d? y-ais -Q Q d (). () 5. (3) 4.9 (4).4 (5) 6.3. A positively chaged paticle with a chage to mass atio q/m =.3 C/kg is taveling to the ight along the. At = it entes an ideal paallel plate capacito though a small hole with speed = 8 m/s as shown in the figue. The plates of the capacito have aea A = m and lie in the y-z plane. The plate at = caies chage Q and the plate at = d caies chage Q. If Q = 8.85µC and d = 5 cm, what is the speed (in m/s) of the paticle when it eits the capacito though the small hole at = d? y-ais -Q Q d () 4.9 () 5. (3). (4).4 (5) An electon (chage e =.6 9 C) is undegoing unifom cicula motion with a adius = 8 m and constant angula velocity. How many evolutions pe second must the electon undego in ode to poduce a magnetic field at the cente of the cicle with a magnitude of.8µt? ().59 () 3.8 (3) 4.77 (4) 8.45 (5) 6.89
7 An electon (chage e =.6 9 C) is undegoing unifom cicula motion with a adius = 8 m and constant angula velocity. How many evolutions pe second must the electon undego in ode to poduce a magnetic field at the cente of the cicle with a magnitude of.6µt? () 3.8 ().59 (3) 4.77 (4) 8.45 (5) An electon (chage e =.6 9 C) is undegoing unifom cicula motion with a adius = 8 m and constant angula velocity. How many evolutions pe second must the electon undego in ode to poduce a magnetic field at the cente of the cicle with a magnitude of.4µt? () 4.77 ().59 (3) 3.8 (4) 8.45 (5) At time t = a chaged paticle with speed v and a chage to mass atio of.5 C/kg entes a egion though a slit and tavels pependicula to a unifom magnetic field (pointing out of the page) as shown in the figue. If the paticle hits the bottom wall a distance d fom the slit at t = 3.4 s, what is the magnitude of the magnetic field (in T)? B-out v d (). ().5 (3). (4). (5). 7. At time t = a chaged paticle with speed v and a chage to mass atio of. C/kg entes a egion though a slit and tavels pependicula to a unifom magnetic field (pointing out of the page) as shown in the figue. If the paticle hits the bottom wall a distance d fom the slit at t = 3.4 s, what is the magnitude of the magnetic field (in T)? B-out v d ().5 (). (3). (4). (5). 8. At time t = a chaged paticle with speed v and a chage to mass atio of 5. C/kg entes a egion though a slit and tavels pependicula to a unifom magnetic field (pointing out of the page) as shown in the figue. If the paticle hits the bottom wall a distance d fom the slit at t = 3.4 s, what is the magnitude of the magnetic field (in T)? B-out v d (). (). (3).5 (4). (5). 9. Conside the cicuit shown in the figue. Initially the inducto has no magnetic stoed enegy and the switch is closed at t =. Immediately afte the switch is closed the cuent though the Ω esisto is I shot and a long time afte the switch is closed (i.e., steady state) the cuent is I long. If I long = 4I shot, what is the esistance (in Ω)? () 6 () (3) 4 (4) 4 (5) ε Ω. Conside the cicuit shown in the figue. Initially the inducto has no magnetic stoed enegy and the switch is closed at t =. Immediately afte the switch is closed the cuent though the Ω esisto is I shot and a long time afte the switch is closed (i.e., steady state) the cuent is I long. If I long = 6I shot, what is the esistance (in Ω)? () () 6 (3) 4 (4) 4 (5) ε Ω
8 . Conside the cicuit shown in the figue. Initially the inducto has no magnetic stoed enegy and the switch is closed at t =. Immediately afte the switch is closed the cuent though the Ω esisto is I shot and a long time afte the switch is closed (i.e., steady state) the cuent is I long. If I long = 8I shot, what is the esistance (in Ω)? () 4 () 6 (3) (4) 4 (5) ε Ω. Conside an oscillating C cicuit consisting of a capacito with C = mf, no esistance, and an unknown inducto as shown in the figue. If the fequency of the oscillations is.383 Hz and the maimum cuent duing the oscillations is.4 A, what is the stoed magnetic enegy (in J) in the inducto when the stoed electgic enegy in the capacito is J? C Q I () 8 () 7 (3) 6 (4) 5 (5) 3. Conside an oscillating C cicuit consisting of a capacito with C = mf, no esistance, and an unknown inducto as shown in the figue. If the fequency of the oscillations is.383 Hz and the maimum cuent duing the oscillations is.4 A, what is the stoed magnetic enegy (in J) in the inducto when the stoed electgic enegy in the capacito is 3 J? C Q I () 7 () 8 (3) 6 (4) 5 (5) 4. Conside an oscillating C cicuit consisting of a capacito with C = mf, no esistance, and an unknown inducto as shown in the figue. If the fequency of the oscillations is.383 Hz and the maimum cuent duing the oscillations is.4 A, what is the stoed magnetic enegy (in J) in the inducto when the stoed electgic enegy in the capacito is 4 J? C Q I () 6 () 8 (3) 7 (4) 5 (5) 5. Two Q point chages and two Q point chages ae placed at the cones of a squae with sides of length as shown in the figue. If Q = 6. nc and =.5 m, what is the electic potential diffeence = (in ) between the point P on the side of the squae at the midpoint of the line between the two positive chages and the point P at the cente of the squae? Q Q P P Q Q () 477 () 636 (3) 795 (4) 3 (5) What is the electic potential enegy (in µj) of the chage configuation in the pevious poblem? ().83 () 3.5 (3) 5.9 (4).83 (5) Two Q point chages and two Q point chages ae placed at the cones of a squae with sides of length as shown in the figue. If Q = 8. nc and =.5 m, what is the electic potential diffeence = (in ) between the point P on the side of the squae at the midpoint of the line between the two positive chages and the point P at the cente of the squae? Q Q P P Q Q () 636 () 477 (3) 795 (4) 3 (5) 897
9 8. What is the electic potential enegy (in µj) of the chage configuation in the pevious poblem? () 3.5 ().83 (3) 5.9 (4).83 (5) Two Q point chages and two Q point chages ae placed at the cones of a squae with sides of length as shown in the figue. If Q =. nc and =.5 m, what is the electic potential diffeence = (in ) between the point P on the side of the squae at the midpoint of the line between the two positive chages and the point P at the cente of the squae? Q Q P P Q Q () 795 () 477 (3) 636 (4) 3 (5) What is the electic potential enegy (in µj) of the chage configuation in the pevious poblem? () 5.9 ().83 (3) 5.9 (4).83 (5) A unifom electic field pointing out of the page, as shown in the figue, is confined to a cicula egion of adius = 3 m and vaies with time accoding to (t) = bt, whee b is a constant (i.e., it vaies linealy with time). If b = 3 /(m s), what is the magnitude of the induced magnetic field (in pt) at the point P at = 3 m fom the cente at time t = 5 s? -out P ().5 (). (3).5 (4). (5) A unifom electic field pointing out of the page, as shown in the figue, is confined to a cicula egion of adius = 6 m and vaies with time accoding to (t) = bt, whee b is a constant (i.e., it vaies linealy with time). If b = 3 /(m s), what is the magnitude of the induced magnetic field (in pt) at the point P at = 6 m fom the cente at time t = 5 s? -out P (). ().5 (3).5 (4). (5) A unifom electic field pointing out of the page, as shown in the figue, is confined to a cicula egion of adius = 9 m and vaies with time accoding to (t) = bt, whee b is a constant (i.e., it vaies linealy with time). If b = 3 /(m s), what is the magnitude of the induced magnetic field (in pt) at the point P at = 9 m fom the cente at time t = 5 s? -out P ().5 ().5 (3). (4). (5) A solid conducting sphee with oute adius has a a spheical hole at its cente with adius. At the cente of the hole thee is a point chage of Q = 5 nc, as shown in the figue. If thee is no net chage on the conducto and =. m, what is the magnitude of the electic field (in /m) at the oute suface of the conducto? Q () 8.9 () 4.9 (3) 7. (4) zeo (5),3.8
10 35. A solid conducting sphee with oute adius has a a spheical hole at its cente with adius. At the cente of the hole thee is a point chage of Q = 5 nc, as shown in the figue. If thee is no net chage on the conducto and =.3 m, what is the magnitude of the electic field (in /m) at the oute suface of the conducto? Q () 4.9 () 8.9 (3) 7. (4) zeo (5) A solid conducting sphee with oute adius has a a spheical hole at its cente with adius. At the cente of the hole thee is a point chage of Q = 5 nc, as shown in the figue. If thee is no net chage on the conducto and =.4 m, what is the magnitude of the electic field (in /m) at the oute suface of the conducto? Q () 7. () 8.9 (3) 4.9 (4) zeo (5), Conside the cicuit consisting of two MF s and two esistos shown in the figue. If ǫ =, ǫ = 3, and =, what is the atio of cuent I (though esisto ) to cuent I (though esisto )? Namely, what is I /I? I I ε ε () 6 () 4 (3) (4) 3 (5) Conside the cicuit consisting of two MF s and two esistos shown in the figue. If ǫ =, ǫ = 4, and =, what is the atio of cuent I (though esisto ) to cuent I (though esisto )? Namely, what is I /I? I I ε ε () 4 () 6 (3) (4) 3 (5) Conside the cicuit consisting of two MF s and two esistos shown in the figue. If ǫ =, ǫ = 6, and =, what is the atio of cuent I (though esisto ) to cuent I (though esisto )? Namely, what is I /I? I I ε ε () () 6 (3) 4 (4) 3 (5) 5 4. Conside two equally chaged conducting sphees. Sphee # has a adius of and chage Q and sphee # has adius and chage Q. Initially the two sphees ae isolated (i.e., they ae a lage distance apat, ) and the total stoed enegy of the system is 9 J. The two conducting sphees ae then connected by a long thin wie and afte the system comes to equilibium, the wie is emoved. What is the new total stoed enegy of the system (in J)? Conducting sphee # Conducting sphee # () 8 () 6 (3) 4 (4) 4 (5) 9
11 4. Conside two equally chaged conducting sphees. Sphee # has a adius of and chage Q and sphee # has adius and chage Q. Initially the two sphees ae isolated (i.e., they ae a lage distance apat, ) and the total stoed enegy of the system is 8 J. The two conducting sphees ae then connected by a long thin wie and afte the system comes to equilibium, the wie is emoved. What is the new total stoed enegy of the system (in J)? Conducting sphee # Conducting sphee # () 6 () 8 (3) 4 (4) 4 (5) 9 4. Conside two equally chaged conducting sphees. Sphee # has a adius of and chage Q and sphee # has adius and chage Q. Initially the two sphees ae isolated (i.e., they ae a lage distance apat, ) and the total stoed enegy of the system is 7 J. The two conducting sphees ae then connected by a long thin wie and afte the system comes to equilibium, the wie is emoved. What is the new total stoed enegy of the system (in J)? Conducting sphee # Conducting sphee # () 4 () 8 (3) 6 (4) 4 (5) Two ockets A and B ae both tavelling in the diection at the same constant speed of and both emit adio waves at a est fequency of MHz to communicate with an obseve O at est on the as shown in the figue. If obseve O must tune his adio to 8 MHz in ode to get a clea signal fom the ocket A, what is the speed of ocket A (in m/s)? ocket A Obseve O at est ocket B ().65 8 ().8 8 (3) (4).95 8 (5) In the pevious poblem, what is the fequency that obseve O must tune his adio in ode to get a clea signal fom ocket B? () 5 MHz () MHz (3) 45 MHz (4) 5 MHz (5) 55 MHz 45. Two ockets A and B ae both tavelling in the diection at the same constant speed of and both emit adio waves at a est fequency of 4 MHz to communicate with an obseve O at est on the as shown in the figue. If obseve O must tune his adio to 8 MHz in ode to get a clea signal fom the ocket A, what is the speed of ocket A (in m/s)? ocket A Obseve O at est ocket B ().8 8 ().65 8 (3) (4).95 8 (5) In the pevious poblem, what is the fequency that obseve O must tune his adio in ode to get a clea signal fom ocket B? () MHz () 5 MHz (3) 45 MHz (4) 5 MHz (5) 55 MHz 47. Two ockets A and B ae both tavelling in the diection at the same constant speed of and both emit adio waves at a est fequency of 6 MHz to communicate with an obseve O at est on the as shown in the figue. If obseve O must tune his adio to 8 MHz in ode to get a clea signal fom the ocket A, what is the speed of ocket A (in m/s)? ocket A Obseve O at est ocket B () ().65 8 (3).8 8 (4).95 8 (5).65 7
12 48. In the pevious poblem, what is the fequency that obseve O must tune his adio in ode to get a clea signal fom ocket B? () 45 MHz () 5 MHz (3) MHz (4) 5 MHz (5) 55 MHz 49. The adiation powe P of the sun is W. If the intensity of the sun on the suface of a ocket ship that is eploing oute space is.69 kw/m, how fa is the ocket fom the sun? (). m ().6 m (3) 8.66 m (4).5 m (5) 4.6 m 5. The adiation powe P of the sun is W. If the intensity of the sun on the suface of a ocket ship that is eploing oute space is.76 kw/m, how fa is the ocket fom the sun? ().6 m (). m (3) 8.66 m (4).5 m (5) 4.6 m 5. The adiation powe P of the sun is W. If the intensity of the sun on the suface of a ocket ship that is eploing oute space is 4.4 kw/m, how fa is the ocket fom the sun? () 8.66 m (). m (3).6 m (4).5 m (5) 4.6 m 5. The optical system shown in the figue consists of two conveging lenses with equal focal lengths f = f = cm. A luminous object with a height h is placed cm in font of the fist lens. The second lens can slide along the pinciple ais and is located a vaiable distance fom the fist lens. At what value of (in cm) will the optical system poduce an inveted final oveall image with a height of h? Is the final image eal o vitual? ().5, vitual () 3.5, eal (3) 5., eal (4).5, eal (5) 3.5, vitual Object h ens f = cm cm ens f = cm 53. The optical system shown in the figue consists of two conveging lenses with equal focal lengths f = f = cm. A luminous object with a height h is placed cm in font of the fist lens. The second lens can slide along the pinciple ais and is located a vaiable distance fom the fist lens. At what value of(in cm) will the optical system poducean upightfinal oveallimage with a height of h? Is the final image eal o vitual? () 3.5, eal ().5, vitual (3) 5., eal (4).5, eal (5) 3.5, vitual Object h ens f = cm cm ens f = cm
13 54. The optical system shown in the figue consists of two conveging lenses with equal focal lengths f = f = cm. A luminous object with a height h is placed cm in font of the fist lens. The second lens can slide along the pinciple ais and is located a vaiable distance fom the fist lens. At what value of(in cm) will the optical system poducean upightfinal oveallimage with a height of h/? Is the final image eal o vitual? () 5., eal ().5, vitual (3) 3.5, eal (4).5, eal (5) 5., vitual Object h ens f = cm cm ens f = cm 55. Obseves A and B ae on opposite sides of a flat glass plate with thickness T and efactive inde n glass =.5 as shown in the figue. Obseve A is in the ai (n ai = ) and obseve B is unde wate (n wate =.33). The light is incident fom the left and obseve A sees the light that is eflected off the glass and obseve B sees the light that passes though the glass. What is the minimum thickness T of the glass plate (in nm) such that obseve A on the left sees maimum constuctive intefeence fo violet light with a vacuum wavelength of λ violet = 3 nm? Incident ight violet A n ai = n glass T violet B n wate =.33 () 5 () 3 (3) 5 (4) (5) In the pevious poblem, what is the minimum thickness T of the glass plate (in nm) such that obseve B on the ight sees maimum constuctive intefeence fo violet light with a vacuum wavelength of λ violet = 3 nm? () () 6 (3) 5 (4) 4 (5) Obseves A and B ae on opposite sides of a flat glass plate with thickness T and efactive inde n glass =.5 as shown in the figue. Obseve A is in the ai (n ai = ) and obseve B is unde wate (n wate =.33). The light is incident fom the left and obseve A sees the light that is eflected off the glass and obseve B sees the light that passes though the glass. What is the minimum thickness T of the glass plate (in nm) such that obseve A on the left sees maimum constuctive intefeence fo violet light with a vacuum wavelength of λ violet = 3 nm? Incident ight violet A n ai = n glass T violet B n wate =.33 () 3 () 5 (3) 5 (4) (5) In the pevious poblem, what is the minimum thickness T of the glass plate (in nm) such that obseve B on the ight sees maimum constuctive intefeence fo violet light with a vacuum wavelength of λ violet = 3 nm? () 6 () (3) 5 (4) 4 (5) Obseves A and B ae on opposite sides of a flat glass plate with thickness T and efactive inde n glass = 3. as shown in the figue. Obseve A is in the ai (n ai = ) and obseve B is unde wate (n wate =.33). The light is incident fom the left and obseve A sees the light that is eflected off the glass and obseve B sees the light that passes though the glass. What is the minimum thickness T of the glass plate (in nm) such that obseve A on the left sees maimum constuctive intefeence fo violet light with a vacuum wavelength of λ violet = 3 nm? Incident ight violet A n ai = n glass T violet B n wate =.33 () 5 () 5 (3) 3 (4) (5) 6
14 6. In the pevious poblem, what is the minimum thickness T of the glass plate (in nm) such that obseve B on the ight sees maimum constuctive intefeence fo violet light with a vacuum wavelength of λ violet = 3 nm? () 5 () (3) 6 (4) 4 (5) 5 TH FOOWING QUSTIONS, NUMBD IN TH OD OF THI APPAANC ON TH ABO IST, HA BN FAGGD AS CONTINUATION QUSTIONS: FOOWING GOUPS OF QUSTIONS WI B SCTD AS ON GOUP FOM ACH TYP TYP Q# S Q# S Q# S 3 TYP Q# S 4 Q# S 5 Q# S 6 TYP 3 Q# S 7 Q# S 8 Q# S 9 TYP 4 Q# S Q# S Q# S TYP 5 Q# S 3 Q# S 4 Q# S 5 TYP 6 Q# S 6 Q# S 7 Q# S 8 TYP 7 Q# S 9 Q# S Q# S TYP 8 Q# S Q# S 3 Q# S 4 TYP 9 Q# S 5 6 Q# S 7 8 Q# S 9 3 TYP Q# S 3 Q# S 3 Q# S 33 TYP Q# S 34 Q# S 35 Q# S 36 TYP Q# S 37 Q# S 38 Q# S 39 TYP 3 Q# S 4 Q# S 4 Q# S 4 TYP 4 Q# S Q# S Q# S TYP 5 Q# S 49 Q# S 5 Q# S 5 TYP 6
15 Q# S 5 Q# S 53 Q# S 54 TYP 7 Q# S Q# S Q# S 59 6
PHY2054 Exam 1 Formula Sheet
Instucto: Pofs. Fiel, Kotov PHYSICS DPARTMNT PHY 54 Final xam Decembe, 5 Name (PRINT, last, fist): Signatue: On m hono, I have neithe given noeceive unauthoize ai on this examination. YOUR TST NUMR IS
More informationCalculate the electric potential at B d2=4 m Calculate the electric potential at A d1=3 m 3 m 3 m
MTE : Ch 13 5:3-7pm on Oct 31 ltenate Exams: Wed Ch 13 6:3pm-8:pm (people attending the altenate exam will not be allowed to go out of the oom while othes fom pevious exam ae still aound) Thu @ 9:-1:3
More informationr r q Coulomb s law: F =. Electric field created by a charge q: E = = enclosed Gauss s law (electric flux through a closed surface): E ds σ ε0
Q E ds = enclosed ε S 0 08 Fomulae Sheet 1 q 1q q Coulomb s law: F =. Electic field ceated by a chage q: E = 4πε 4πε Pemittivity of fee space: 0 1 = 9 10 4πε 0 9 Newton mete / coulomb = 9 10 9 0 N m Q
More informationMAGNETIC FIELD INTRODUCTION
MAGNETIC FIELD INTRODUCTION It was found when a magnet suspended fom its cente, it tends to line itself up in a noth-south diection (the compass needle). The noth end is called the Noth Pole (N-pole),
More informationSAMPLE PAPER I. Time Allowed : 3 hours Maximum Marks : 70
SAMPL PAPR I Time Allowed : 3 hous Maximum Maks : 70 Note : Attempt All questions. Maks allotted to each question ae indicated against it. 1. The magnetic field lines fom closed cuves. Why? 1 2. What is
More informationPY208 Matter & Interactions Final Exam S2005
PY Matte & Inteactions Final Exam S2005 Name (pint) Please cicle you lectue section below: 003 (Ramakishnan 11:20 AM) 004 (Clake 1:30 PM) 005 (Chabay 2:35 PM) When you tun in the test, including the fomula
More informationPhys102 Second Major-182 Zero Version Monday, March 25, 2019 Page: 1
Monday, Mach 5, 019 Page: 1 Q1. Figue 1 shows thee pais of identical conducting sphees that ae to be touched togethe and then sepaated. The initial chages on them befoe the touch ae indicated. Rank the
More informationELECTROSTATICS::BHSEC MCQ 1. A. B. C. D.
ELETROSTATIS::BHSE 9-4 MQ. A moving electic chage poduces A. electic field only. B. magnetic field only.. both electic field and magnetic field. D. neithe of these two fields.. both electic field and magnetic
More information15 B1 1. Figure 1. At what speed would the car have to travel for resonant oscillations to occur? Comment on your answer.
Kiangsu-Chekiang College (Shatin) F:EasteHolidaysAssignmentAns.doc Easte Holidays Assignment Answe Fom 6B Subject: Physics. (a) State the conditions fo a body to undego simple hamonic motion. ( mak) (a)
More informationF = net force on the system (newton) F,F and F. = different forces working. E = Electric field strength (volt / meter)
All the Impotant Fomulae that a student should know fom. XII Physics Unit : CHAPTER - ELECTRIC CHARGES AND FIELD CHAPTER ELECTROSTATIC POTENTIAL AND CAPACITANCE S. Fomula No.. Quantization of chage Q =
More informationElectrostatics (Electric Charges and Field) #2 2010
Electic Field: The concept of electic field explains the action at a distance foce between two chaged paticles. Evey chage poduces a field aound it so that any othe chaged paticle expeiences a foce when
More information1 2 U CV. K dq I dt J nqv d J V IR P VI
o 5 o T C T F 9 T K T o C 7.5 L L T V VT Q mct nct Q F V ml F V dq A H k TH TC dt L pv nt Kt nt CV ideal monatomic gas 5 CV ideal diatomic gas w/o vibation V W pdv V U Q W W Q e Q Q e Canot H C T T S C
More informationExam 3, vers Physics Spring, 2003
1 of 9 Exam 3, ves. 0001 - Physics 1120 - Sping, 2003 NAME Signatue Student ID # TA s Name(Cicle one): Michael Scheffestein, Chis Kelle, Paisa Seelungsawat Stating time of you Tues ecitation (wite time
More informationev dm e evd 2 m e 1 2 ev2 B) e 2 0 dm e D) m e
. A paallel-plate capacito has sepaation d. The potential diffeence between the plates is V. If an electon with chage e and mass m e is eleased fom est fom the negative plate, its speed when it eaches
More informationPhys 1215, First Test. September 20, minutes Name:
Phys 115, Fist Test. Septembe 0, 011 50 minutes Name: Show all wok fo maximum cedit. Each poblem is woth 10 points. k =.0 x 10 N m / C ε 0 = 8.85 x 10-1 C / N m e = 1.60 x 10-1 C ρ = 1.68 x 10-8 Ω m fo
More informationA moving charged particle creates a magnetic field vector at every point in space except at its position.
1 Pat 3: Magnetic Foce 3.1: Magnetic Foce & Field A. Chaged Paticles A moving chaged paticle ceates a magnetic field vecto at evey point in space ecept at its position. Symbol fo Magnetic Field mks units
More informationPhys-272 Lecture 17. Motional Electromotive Force (emf) Induced Electric Fields Displacement Currents Maxwell s Equations
Phys-7 Lectue 17 Motional Electomotive Foce (emf) Induced Electic Fields Displacement Cuents Maxwell s Equations Fom Faaday's Law to Displacement Cuent AC geneato Magnetic Levitation Tain Review of Souces
More information$ i. !((( dv vol. Physics 8.02 Quiz One Equations Fall q 1 q 2 r 2 C = 2 C! V 2 = Q 2 2C F = 4!" or. r ˆ = points from source q to observer
Physics 8.0 Quiz One Equations Fall 006 F = 1 4" o q 1 q = q q ˆ 3 4" o = E 4" o ˆ = points fom souce q to obseve 1 dq E = # ˆ 4" 0 V "## E "d A = Q inside closed suface o d A points fom inside to V =
More informationChapter 22: Electric Fields. 22-1: What is physics? General physics II (22102) Dr. Iyad SAADEDDIN. 22-2: The Electric Field (E)
Geneal physics II (10) D. Iyad D. Iyad Chapte : lectic Fields In this chapte we will cove The lectic Field lectic Field Lines -: The lectic Field () lectic field exists in a egion of space suounding a
More informationPhysics 2212 GH Quiz #2 Solutions Spring 2016
Physics 2212 GH Quiz #2 Solutions Sping 216 I. 17 points) Thee point chages, each caying a chage Q = +6. nc, ae placed on an equilateal tiangle of side length = 3. mm. An additional point chage, caying
More informationSchool of Electrical and Computer Engineering, Cornell University. ECE 303: Electromagnetic Fields and Waves. Fall 2007
School of Electical and Compute Engineeing, Conell Univesity ECE 303: Electomagnetic Fields and Waves Fall 007 Homewok 8 Due on Oct. 19, 007 by 5:00 PM Reading Assignments: i) Review the lectue notes.
More informationPotential Energy. The change U in the potential energy. is defined to equal to the negative of the work. done by a conservative force
Potential negy The change U in the potential enegy is defined to equal to the negative of the wok done by a consevative foce duing the shift fom an initial to a final state. U = U U = W F c = F c d Potential
More informationEM-2. 1 Coulomb s law, electric field, potential field, superposition q. Electric field of a point charge (1)
EM- Coulomb s law, electic field, potential field, supeposition q ' Electic field of a point chage ( ') E( ) kq, whee k / 4 () ' Foce of q on a test chage e at position is ee( ) Electic potential O kq
More informationUniversity of Illinois at Chicago Department of Physics. Electricity & Magnetism Qualifying Examination
E&M poblems Univesity of Illinois at Chicago Depatment of Physics Electicity & Magnetism Qualifying Examination Januay 3, 6 9. am : pm Full cedit can be achieved fom completely coect answes to 4 questions.
More information16.1 Permanent magnets
Unit 16 Magnetism 161 Pemanent magnets 16 The magnetic foce on moving chage 163 The motion of chaged paticles in a magnetic field 164 The magnetic foce exeted on a cuent-caying wie 165 Cuent loops and
More information17.1 Electric Potential Energy. Equipotential Lines. PE = energy associated with an arrangement of objects that exert forces on each other
Electic Potential Enegy, PE Units: Joules Electic Potential, Units: olts 17.1 Electic Potential Enegy Electic foce is a consevative foce and so we can assign an electic potential enegy (PE) to the system
More informationGauss Law. Physics 231 Lecture 2-1
Gauss Law Physics 31 Lectue -1 lectic Field Lines The numbe of field lines, also known as lines of foce, ae elated to stength of the electic field Moe appopiately it is the numbe of field lines cossing
More informationSolutions. V in = ρ 0. r 2 + a r 2 + b, where a and b are constants. The potential at the center of the atom has to be finite, so a = 0. r 2 + b.
Solutions. Plum Pudding Model (a) Find the coesponding electostatic potential inside and outside the atom. Fo R The solution can be found by integating twice, 2 V in = ρ 0 ε 0. V in = ρ 0 6ε 0 2 + a 2
More informationPhysics 313 Practice Test Page 1. University Physics III Practice Test II
Physics 313 Pactice Test Page 1 Univesity Physics III Pactice Test II This pactice test should give you a ough idea of the fomat and oveall level of the Physics 313 exams. The actual exams will have diffeent
More informationFARADAY'S LAW. dates : No. of lectures allocated. Actual No. of lectures 3 9/5/09-14 /5/09
FARADAY'S LAW No. of lectues allocated Actual No. of lectues dates : 3 9/5/09-14 /5/09 31.1 Faaday's Law of Induction In the pevious chapte we leaned that electic cuent poduces agnetic field. Afte this
More informationMark answers in spaces on the answer sheet
Mak answes in spaces 31-43 on the answe sheet PHYSICS 1 Summe 005 EXAM 3: July 5 005 9:50pm 10:50pm Name (pinted): ID Numbe: Section Numbe: INSTRUCTIONS: Some questions ae one point, othes ae two points,
More informationReview of Potential Energy. The Electric Potential. Plotting Fields and Potentials. Electric Potential of a Point Charge
eview of Potential negy Potential enegy U() can be used to descibe a consevative foce. efeence point (U) can be chosen fo convenience. Wok done by F : W F d s F d (1D) Change in P.. : U U f U i W Foce
More informationPhys 222 Sp 2009 Exam 1, Wed 18 Feb, 8-9:30pm Closed Book, Calculators allowed Each question is worth one point, answer all questions
Phys Sp 9 Exam, Wed 8 Feb, 8-9:3pm Closed Book, Calculatos allowed Each question is woth one point, answe all questions Fill in you Last Name, Middle initial, Fist Name You ID is the middle 9 digits on
More informationElectromagnetism Physics 15b
lectomagnetism Physics 15b Lectue #20 Dielectics lectic Dipoles Pucell 10.1 10.6 What We Did Last Time Plane wave solutions of Maxwell s equations = 0 sin(k ωt) B = B 0 sin(k ωt) ω = kc, 0 = B, 0 ˆk =
More informationChapter 23: GAUSS LAW 343
Chapte 23: GAUSS LAW 1 A total chage of 63 10 8 C is distibuted unifomly thoughout a 27-cm adius sphee The volume chage density is: A 37 10 7 C/m 3 B 69 10 6 C/m 3 C 69 10 6 C/m 2 D 25 10 4 C/m 3 76 10
More information(Sample 3) Exam 1 - Physics Patel SPRING 1998 FORM CODE - A (solution key at end of exam)
(Sample 3) Exam 1 - Physics 202 - Patel SPRING 1998 FORM CODE - A (solution key at end of exam) Be sue to fill in you student numbe and FORM lette (A, B, C) on you answe sheet. If you foget to include
More informationSEE LAST PAGE FOR SOME POTENTIALLY USEFUL FORMULAE AND CONSTANTS
Cicle instucto: Moow o Yethiaj Name: MEMORIL UNIVERSITY OF NEWFOUNDLND DEPRTMENT OF PHYSICS ND PHYSICL OCENOGRPHY Final Eam Phsics 5 Winte 3:-5: pil, INSTRUCTIONS:. Do all SIX (6) questions in section
More informationPHY 213. General Physics II Test 2.
Univesity of Kentucky Depatment of Physics an Astonomy PHY 3. Geneal Physics Test. Date: July, 6 Time: 9:-: Answe all questions. Name: Signatue: Section: Do not flip this page until you ae tol to o so.
More informationCHAPTER 25 ELECTRIC POTENTIAL
CHPTE 5 ELECTIC POTENTIL Potential Diffeence and Electic Potential Conside a chaged paticle of chage in a egion of an electic field E. This filed exets an electic foce on the paticle given by F=E. When
More informationCHAPTER 10 ELECTRIC POTENTIAL AND CAPACITANCE
CHAPTER 0 ELECTRIC POTENTIAL AND CAPACITANCE ELECTRIC POTENTIAL AND CAPACITANCE 7 0. ELECTRIC POTENTIAL ENERGY Conside a chaged paticle of chage in a egion of an electic field E. This filed exets an electic
More informationFaraday s Law. Faraday s Law. Faraday s Experiments. Faraday s Experiments. Magnetic Flux. Chapter 31. Law of Induction (emf( emf) Faraday s Law
Faaday s Law Faaday s Epeiments Chapte 3 Law of nduction (emf( emf) Faaday s Law Magnetic Flu Lenz s Law Geneatos nduced Electic fields Michael Faaday discoeed induction in 83 Moing the magnet induces
More informationMagnetic Field. Conference 6. Physics 102 General Physics II
Physics 102 Confeence 6 Magnetic Field Confeence 6 Physics 102 Geneal Physics II Monday, Mach 3d, 2014 6.1 Quiz Poblem 6.1 Think about the magnetic field associated with an infinite, cuent caying wie.
More informationChapter 22 Problems. Problems Chapter 22 Page 1 of 3
Chapte 22 Poblems Poblem 1: A +15 micoc chage is located 40 cm fom a +3.0 micoc chage. The magnitude of the electostatic foce on the lage chage and on the smalle chage (in N) is, espectively. Poblem 2:
More informationPrepared by: M. S. KumarSwamy, TGT(Maths) Page - 1 -
Pepaed by: M. S. KumaSwamy, TGT(Maths) Page - - ELECTROSTATICS MARKS WEIGHTAGE 8 maks QUICK REVISION (Impotant Concepts & Fomulas) Chage Quantization: Chage is always in the fom of an integal multiple
More informationWelcome to Physics 272
Welcome to Physics 7 Bob Mose mose@phys.hawaii.edu http://www.phys.hawaii.edu/~mose/physics7.html To do: Sign into Masteing Physics phys-7 webpage Registe i-clickes (you i-clicke ID to you name on class-list)
More informatione = 1.60 x 10 ε 0 = 8.85 x C 2 / Nm 2 V i...) F a = m Power =
Equations: 1 1 Constants: q q v v F = k F = qe e = 1.6 x 1-19 C q 1 q 1 9 E = k = k = = 9 1 Nm / C 4πε 4 πε Φ = E da Φ V Total v v q = E da = = V f V i = W q enclosed ε = E ds U e V = q q V V V V = k E
More informationCurrent, Resistance and
Cuent, Resistance and Electomotive Foce Chapte 25 Octobe 2, 2012 Octobe 2, 2012 Physics 208 1 Leaning Goals The meaning of electic cuent, and how chages move in a conducto. What is meant by esistivity
More information18.1 Origin of Electricity 18.2 Charged Objects and Electric Force
1 18.1 Oigin of lecticity 18. Chaged Objects and lectic Foce Thee ae two kinds of electic chage: positive and negative. The SI unit of electic chage is the coulomb (C). The magnitude of the chage on an
More informationGauss s Law: Circuits
Gauss s Law: Cicuits Can we have excess chage inside in steady state? E suface nˆ A q inside E nˆ A E nˆ A left _ suface ight _ suface q inside 1 Gauss s Law: Junction Between two Wies n 2
More informationLook over Chapter 22 sections 1-8 Examples 2, 4, 5, Look over Chapter 16 sections 7-9 examples 6, 7, 8, 9. Things To Know 1/22/2008 PHYS 2212
PHYS 1 Look ove Chapte sections 1-8 xamples, 4, 5, PHYS 111 Look ove Chapte 16 sections 7-9 examples 6, 7, 8, 9 Things To Know 1) What is an lectic field. ) How to calculate the electic field fo a point
More informationFlux. Area Vector. Flux of Electric Field. Gauss s Law
Gauss s Law Flux Flux in Physics is used to two distinct ways. The fist meaning is the ate of flow, such as the amount of wate flowing in a ive, i.e. volume pe unit aea pe unit time. O, fo light, it is
More informationELECTROMAGNETISM (CP2)
Revision Lectue on ELECTROMAGNETISM (CP) Electostatics Magnetostatics Induction EM Waves based on pevious yeas Pelims questions State Coulomb s Law. Show how E field may be defined. What is meant by E
More informationChapter 31 Faraday s Law
Chapte 31 Faaday s Law Change oving --> cuent --> agnetic field (static cuent --> static agnetic field) The souce of agnetic fields is cuent. The souce of electic fields is chage (electic onopole). Altenating
More informationObjects usually are charged up through the transfer of electrons from one object to the other.
1 Pat 1: Electic Foce 1.1: Review of Vectos Review you vectos! You should know how to convet fom pola fom to component fom and vice vesa add and subtact vectos multiply vectos by scalas Find the esultant
More informationConventional Paper-I (a) Explain the concept of gradient. Determine the gradient of the given field: ( )
EE-Conventional Pape-I IES-013 www.gatefoum.com Conventional Pape-I-013 1. (a) Eplain the concept of gadient. Detemine the gadient of the given field: V ρzsin φ+ z cos φ+ρ What is polaization? In a dielectic
More informationCh 30 - Sources of Magnetic Field! The Biot-Savart Law! = k m. r 2. Example 1! Example 2!
Ch 30 - Souces of Magnetic Field 1.) Example 1 Detemine the magnitude and diection of the magnetic field at the point O in the diagam. (Cuent flows fom top to bottom, adius of cuvatue.) Fo staight segments,
More informationAdvanced Subsidiary GCE (H157) Advanced GCE (H557) Physics B (Advancing Physics) Data, Formulae and Relationships Booklet
Advanced Subsidiay GCE (H57) Advanced GCE (H557) Physics B (Advancing Physics) Data, Fomulae and Relationships Booklet The infomation in this booklet is fo the use of candidates following the Advanced
More informationGM r. v = For Newton s third law, the forces in the action/reaction pair always act on different objects
SAT Physics Mechanics The dot poduct of two vectos: A B = AB cos θ The coss poduct of vectos: A B = AB sin θˆn. The magnitude of the coss poduct is equal to the aea of the paallelogam. We use the ight
More informationFaraday s Law (continued)
Faaday s Law (continued) What causes cuent to flow in wie? Answe: an field in the wie. A changing magnetic flux not only causes an MF aound a loop but an induced electic field. Can wite Faaday s Law: ε
More information21 MAGNETIC FORCES AND MAGNETIC FIELDS
CHAPTER 1 MAGNETIC ORCES AND MAGNETIC IELDS ANSWERS TO OCUS ON CONCEPTS QUESTIONS 1. (d) Right-Hand Rule No. 1 gives the diection of the magnetic foce as x fo both dawings A and. In dawing C, the velocity
More informationFields and Waves I Spring 2005 Homework 8. Due: 3 May 2005
Fields and Waves I Sping 005 Homewok 8 Tansmission Lines Due: 3 May 005. Multiple Choice (6) a) The SWR (standing wave atio): a) is a measue of the match between the souce impedance and line impedance
More informationAlgebra-based Physics II
lgebabased Physics II Chapte 19 Electic potential enegy & The Electic potential Why enegy is stoed in an electic field? How to descibe an field fom enegetic point of view? Class Website: Natual way of
More informationElectromagnetic Waves
Chapte 32 Electomagnetic Waves PowePoint Lectues fo Univesity Physics, Twelfth Edition Hugh D. Young and Roge A. Feedman Lectues by James Pazun Modified P. Lam 8_11_2008 Topics fo Chapte 32 Maxwell s equations
More informationVoltage ( = Electric Potential )
V-1 of 10 Voltage ( = lectic Potential ) An electic chage altes the space aound it. Thoughout the space aound evey chage is a vecto thing called the electic field. Also filling the space aound evey chage
More informationPhysics NYB problem set 5 solution
Physics NY poblem set 5 solutions 1 Physics NY poblem set 5 solution Hello eveybody, this is ED. Hi ED! ED is useful fo dawing the ight hand ule when you don t know how to daw. When you have a coss poduct
More informationChapter 22 The Electric Field II: Continuous Charge Distributions
Chapte The lectic Field II: Continuous Chage Distibutions A ing of adius a has a chage distibution on it that vaies as l(q) l sin q, as shown in Figue -9. (a) What is the diection of the electic field
More informationPhysics 2112 Unit 14
Physics 2112 Unit 14 Today s Concept: What Causes Magnetic Fields d 0I ds ˆ 2 4 Unit 14, Slide 1 You Comments Can you give a summay fo eveything we use the ight hand ule fo? Wasn't too clea on this topic.
More information? this lecture. ? next lecture. What we have learned so far. a Q E F = q E a. F = q v B a. a Q in motion B. db/dt E. de/dt B.
PHY 249 Lectue Notes Chapte 32: Page 1 of 12 What we have leaned so fa a a F q a a in motion F q v a a d/ Ae thee othe "static" chages that can make -field? this lectue d/? next lectue da dl Cuve Cuve
More information(r) = 1. Example: Electric Potential Energy. Summary. Potential due to a Group of Point Charges 9/10/12 1 R V(r) + + V(r) kq. Chapter 23.
Eample: Electic Potential Enegy What is the change in electical potential enegy of a eleased electon in the atmosphee when the electostatic foce fom the nea Eath s electic field (diected downwad) causes
More information[Griffiths Ch.1-3] 2008/11/18, 10:10am 12:00am, 1. (6%, 7%, 7%) Suppose the potential at the surface of a hollow hemisphere is specified, as shown
[Giffiths Ch.-] 8//8, :am :am, Useful fomulas V ˆ ˆ V V V = + θ+ φ ˆ and v = ( v ) + (sin θvθ ) + v θ sinθ φ sinθ θ sinθ φ φ. (6%, 7%, 7%) Suppose the potential at the suface of a hollow hemisphee is specified,
More information( )( )( ) ( ) + ( ) ( ) ( )
3.7. Moel: The magnetic fiel is that of a moving chage paticle. Please efe to Figue Ex3.7. Solve: Using the iot-savat law, 7 19 7 ( ) + ( ) qvsinθ 1 T m/a 1.6 1 C. 1 m/s sin135 1. 1 m 1. 1 m 15 = = = 1.13
More informationPHYS 2135 Exam I February 13, 2018
Exam Total /200 PHYS 2135 Exam I Febuay 13, 2018 Name: Recitation Section: Five multiple choice questions, 8 points each Choose the best o most nealy coect answe Fo questions 6-9, solutions must begin
More informationPhysics Spring 2012 Announcements: Mar 07, 2012
Physics 00 - Sping 01 Announcements: Ma 07, 01 HW#6 due date has been extended to the moning of Wed. Ma 1. Test # (i. Ma ) will cove only chaptes 0 and 1 All of chapte will be coveed in Test #4!!! Test
More informationReview for Midterm-1
Review fo Midtem-1 Midtem-1! Wednesday Sept. 24th at 6pm Section 1 (the 4:10pm class) exam in BCC N130 (Business College) Section 2 (the 6:00pm class) exam in NR 158 (Natual Resouces) Allowed one sheet
More informationPHYS 1444 Lecture #5
Shot eview Chapte 24 PHYS 1444 Lectue #5 Tuesday June 19, 212 D. Andew Bandt Capacitos and Capacitance 1 Coulom s Law The Fomula QQ Q Q F 1 2 1 2 Fomula 2 2 F k A vecto quantity. Newtons Diection of electic
More information06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions )
06 - ROTATIONAL MOTION Page ) A body A of mass M while falling vetically downwads unde gavity beaks into two pats, a body B of mass ( / ) M and a body C of mass ( / ) M. The cente of mass of bodies B and
More informationANTENNAS. Vector and Scalar Potentials. Maxwell's Equations. D = εe. For a linear, homogeneous, isotropic medium µ and ε are contant.
ANTNNAS Vecto and Scala Potentials Maxwell's quations jωb J + jωd D ρ B (M) (M) (M3) (M4) D ε B Fo a linea, homogeneous, isotopic medium and ε ae contant. Since B, thee exists a vecto A such that B A and
More informationClass XII - Physics Wave Optics Chapter-wise Problems. Chapter 10
Class XII - Physics Wave Optics Chapte-wise Poblems Answes Chapte (c) (a) 3 (a) 4 (c) 5 (d) 6 (a), (b), (d) 7 (b), (d) 8 (a), (b) 9 (a), (b) Yes Spheical Spheical with huge adius as compaed to the eath
More informationTHE MAGNETIC FIELD. This handout covers: The magnetic force between two moving charges. The magnetic field, B, and magnetic field lines
EM 005 Handout 7: The Magnetic ield 1 This handout coes: THE MAGNETIC IELD The magnetic foce between two moing chages The magnetic field,, and magnetic field lines Magnetic flux and Gauss s Law fo Motion
More informationClass 2. Lesson 1 Stationary Point Charges and Their Forces. Basic Rules of Electrostatics. Basic Rules of Electrostatics
Lesson 1 Stationay Point Chages and Thei Foces Class Today we will: lean the basic chaacteistics o the electostatic oce eview the popeties o conductos and insulatos lean what is meant by electostatic induction
More informationFI 2201 Electromagnetism
FI 2201 Electomagnetism Alexande A. Iskanda, Ph.D. Physics of Magnetism and Photonics Reseach Goup Electodynamics ELETROMOTIVE FORE AND FARADAY S LAW 1 Ohm s Law To make a cuent flow, we have to push the
More information( ) Make-up Tests. From Last Time. Electric Field Flux. o The Electric Field Flux through a bit of area is
Mon., 3/23 Wed., 3/25 Thus., 3/26 Fi., 3/27 Mon., 3/30 Tues., 3/31 21.4-6 Using Gauss s & nto to Ampee s 21.7-9 Maxwell s, Gauss s, and Ampee s Quiz Ch 21, Lab 9 Ampee s Law (wite up) 22.1-2,10 nto to
More informationFARADAY'S LAW dt
FAADAY'S LAW 31.1 Faaday's Law of Induction In the peious chapte we leaned that electic cuent poduces agnetic field. Afte this ipotant discoey, scientists wondeed: if electic cuent poduces agnetic field,
More information( ) ( )( ) ˆ. Homework #8. Chapter 27 Magnetic Fields II.
Homewok #8. hapte 7 Magnetic ields. 6 Eplain how ou would modif Gauss s law if scientists discoveed that single, isolated magnetic poles actuall eisted. Detemine the oncept Gauss law fo magnetism now eads
More informationToday s Plan. Electric Dipoles. More on Gauss Law. Comment on PDF copies of Lectures. Final iclicker roll-call
Today s Plan lectic Dipoles Moe on Gauss Law Comment on PDF copies of Lectues Final iclicke oll-call lectic Dipoles A positive (q) and negative chage (-q) sepaated by a small distance d. lectic dipole
More informationChapter 21: Gauss s Law
Chapte : Gauss s Law Gauss s law : intoduction The total electic flux though a closed suface is equal to the total (net) electic chage inside the suface divided by ε Gauss s law is equivalent to Coulomb
More informationA new force Magnetic force. Today. Force Fields: A disturbance of space. The correspondence of a loop of current and magnet.
Today A new foce Magnetic foce Announcements HW#6 and HW#7 ae both due Wednesday Mach 18th. Thanks to my being WAY behind schedule, you 2nd exam will be a take-home exam! Stay tuned fo details Even if
More informationElecto Magnetism iot Savat s Law and Ampee s Cicuital Law 1. A cuent is flowing due noth along a powe line. The diection of the magnetic field above it, neglecting the eath s field is: (1) Noth () East
More informationUniversity Physics (PHY 2326)
Chapte Univesity Physics (PHY 6) Lectue lectostatics lectic field (cont.) Conductos in electostatic euilibium The oscilloscope lectic flux and Gauss s law /6/5 Discuss a techniue intoduced by Kal F. Gauss
More informationChapter 26: Magnetism: Force and Field
Chapte 6: Magnetism: Foce and Field Magnets Magnetism Magnetic foces Magnetism Magnetic field of Eath Magnetism Magnetism Magnetic monopoles? Pehaps thee exist magnetic chages, just like electic chages.
More informationForce and Work: Reminder
Electic Potential Foce and Wok: Reminde Displacement d a: initial point b: final point Reminde fom Mechanics: Foce F if thee is a foce acting on an object (e.g. electic foce), this foce may do some wok
More informationReview for 2 nd Midterm
Review fo 2 nd Midtem Midtem-2! Wednesday Octobe 29 at 6pm Section 1 N100 BCC (Business College) Section 2 158 NR (Natual Resouces) Allowed one sheet of notes (both sides) and calculato Coves Chaptes 27-31
More informationDEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS
DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS TSOKOS LESSON 10-1 DESCRIBING FIELDS Essential Idea: Electic chages and masses each influence the space aound them and that influence can be epesented
More informationModule 05: Gauss s s Law a
Module 05: Gauss s s Law a 1 Gauss s Law The fist Maxwell Equation! And a vey useful computational technique to find the electic field E when the souce has enough symmety. 2 Gauss s Law The Idea The total
More informationUnit 7: Sources of magnetic field
Unit 7: Souces of magnetic field Oested s expeiment. iot and Savat s law. Magnetic field ceated by a cicula loop Ampèe s law (A.L.). Applications of A.L. Magnetic field ceated by a: Staight cuent-caying
More informationPhysics 107 TUTORIAL ASSIGNMENT #8
Physics 07 TUTORIAL ASSIGNMENT #8 Cutnell & Johnson, 7 th edition Chapte 8: Poblems 5,, 3, 39, 76 Chapte 9: Poblems 9, 0, 4, 5, 6 Chapte 8 5 Inteactive Solution 8.5 povides a model fo solving this type
More informationSources of Magnetic Fields (chap 28)
Souces of Magnetic Fields (chap 8) In chapte 7, we consideed the magnetic field effects on a moving chage, a line cuent and a cuent loop. Now in Chap 8, we conside the magnetic fields that ae ceated by
More information, and the curve BC is symmetrical. Find also the horizontal force in x-direction on one side of the body. h C
Umeå Univesitet, Fysik 1 Vitaly Bychkov Pov i teknisk fysik, Fluid Dynamics (Stömningsläa), 2013-05-31, kl 9.00-15.00 jälpmedel: Students may use any book including the textbook Lectues on Fluid Dynamics.
More information3. Magnetostatic fields
3. Magnetostatic fields D. Rakhesh Singh Kshetimayum 1 Electomagnetic Field Theoy by R. S. Kshetimayum 3.1 Intoduction to electic cuents Electic cuents Ohm s law Kichoff s law Joule s law Bounday conditions
More informationPhysics 2020, Spring 2005 Lab 5 page 1 of 8. Lab 5. Magnetism
Physics 2020, Sping 2005 Lab 5 page 1 of 8 Lab 5. Magnetism PART I: INTRODUCTION TO MAGNETS This week we will begin wok with magnets and the foces that they poduce. By now you ae an expet on setting up
More information