Sum and difference formulae for sine and cosine. Elementary Functions. Consider angles α and β with α > β. These angles identify points on the
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1 Consider angles α and β with α > β. These angles identify points on the unit circle, P (cos α, sin α) and Q(cos β, sin β). Part 5, Trigonometry Lecture 5.1a, Sum and Difference Formulas Dr. Ken W. Smith Sam Houston State University 1 / 8 The distance between P and Q is, by the Pythagorean theorem, the square root of We can expand this out, algebraically, and get d(p Q) = (cos α cos β) + (sin α / 8 d(p Q) = (cos α cos α cos β +cos β)+(sin α sin α sin β +sin β). sin β). which we can rewrite (using the Pythagorean identity) as d(p Q) = cos α cos β sin α sin β 3 / 8 4 / 8
2 Let s rotate this picture clockwise through the angle β so that the point Q becomes Q (1, 0) lying on the x-axis. The point P rotates into the point P (cos(α β), sin(α β)) The distance from P to Q is the same as the distance from P to Q. 5 / 8 The distance from P to Q is the square root of d(p Q ) = (1 cos(α β)) +(sin(α β)) = 1 cos(α β)+cos (α β)+sin (α β)) = cos(α β). 6 / 8 Since the line segments P Q and P Q are congruent, then we know that d(p Q) = d(p Q ). 7 / 8 8 / 8
3 D = cos α cos β sin α sin β In mathematics, if we arrive at the same value through two different computations, we always have valuable information. Here we can equate d(p Q) and d(p Q ) and simplify. 9 / 8 10 / 8 D = cos(α β) So cos α cos β sin α sin β = cos(α β). We may divide both sides by and solve for cos(α β). cos(α β) = cos α cos β + sin α sin β This is an important result. We create a more memorable form of this equation if we replace β by β and use the fact that sine is an odd function while cosine is an even function. Write cos(α + β) = cos(α ( β)) and replace β by β in our equation for cos(α β) to see that cos(α + β) = cos α cos( β) + sin α sin( β) = cos α cos(β) sin α sin(β) This is an equation we want to record and use on a regular basis. cos(α + β) = cos α cos β sin α sin β (1) 11 / 8 1 / 8
4 If we note that sin(θ) = cos( π θ) (since sine and cosine are complementary functions!) then we can write sin(α + β) = cos( π (α + β)) = cos((π α) β). Using the sum-of-angles formula above, with regards to the angles π α and β, we have sin(α + β) = cos(( π α) β) Therefore we have a sum-of-angles equation for the sine function: sin(α + β) = sin α cos β + cos α sin β () If we need, we may replace β by β to create a difference equation: sin(α β) = sin α cos β cos α sin β = cos( π α) cos β + sin(π α) sin β = sin α cos β + cos α sin β. 13 / 8 14 / 8 I don t memorize these identities. (That s one reason I ve been attracted to mathematics if one understands the math, one doesn t need to memorize!) In the undergraduate classes that I teach at Sam Houston State University, I will provide students with the sum of angle formulas when they are needed. Here they are again: cos(α + β) = cos α cos β sin α sin β sin(α + β) = sin α cos β + cos α sin β 15 / 8 16 / 8
5 Sum and Difference Formulas Here they are as difference of angles In the next presentation, we will look at some applications of these sum and difference formulas. cos(α β) = cos α cos β+ sin α sin β (End) sin(α β) = sin α cos β cos α sin β 17 / 8 18 / 8 0 / 8 A reduction formula Let P (cos θ, sin θ) be a point on the terminal side of angle θ. Any point (a, b) on the line OP satisfies the equations cos θ = a, a +b sin θ = b. a +b Part 5, Trigonometry Lecture 5.1b, Applications of the Sum and Difference Formulas Dr. Ken W. Smith Sam Houston State University 19 / 8
6 A reduction formula By our sum-of-angles formulas, sin(x + θ) = sin x cos θ + cos x sin θ. a If we replace cos θ and sin θ by and sin θ = b a +b a, we get +b a sin(x + θ) = sin x + cos x b a sin a = x+b cos x +b a. +b a +b We clear the denominators by multiplying all sides by a + b. a sin x + b cos x = a + b sin(x + θ). (3) a sin x + b cos x = a + b sin(x + θ). This formula is useful for changing a linear combination of sine and cosine functions into just a sine function. For example, the function f(x) = sin x + 3 cos x can be rewritten as sin x + 3 cos x = sin(x + θ) where θ is the angle between the x-axis and the line from the origin to the point (1, 3). Since θ = π/3 in this problem, and since = =, we have sin x + 3 cos x = sin(x + π/3). 1 / 8 Sum and difference formulas for tangent / 8 Sum and difference formulae for tangent We know that tan(α + β) = sin(α+β) cos(α+β) so we may use our sum-of-angle formulas to create a formula for tan(α + β). A first pass gives tan(α + β) = sin(α+β) cos(α+β) = sin α cos β+cos α sin β cos α cos β sin α sin β But we would really like a sum-of-angles formula for tangent that is in terms of tan α and tan β. So let s divide both numerator and denominator by cos α cos β. tan(α + β) = tan α + tan β 1 tan α tan β. (4) tan(α + β) = tan α + tan β 1 tan α tan β. What if we wanted an equation for tan(α β)? Replace β by β and use the fact that tangent is an odd function to obtain tan(α β) = tan α tan β 1 + tan α tan β. 3 / 8 4 / 8
7 Some worked problems Compute the exact value of cos 75. Solution. Using the sum of angles formula for cosine and the fact that 75 = , we have cos 75 = cos( ) = cos 45 cos 30 sin 45 sin 30 = 3 1 = 6 4 Compute the exact value of sin 15. Solution. sin 15 = sin(45 30 ) = sin 45 cos 30 cos 45 sin 30 = 3 1 = 6 This answer looks familiar! (Notice that since 75 and 15 are complementary angles so the cosine of one angle is the sine of the other!) 4 5 / 8 6 / 8 Sum and Difference Formulas Find the tangent of 75. Solution. We could separately compute the sine and cosine of 75 using our sum-of-angle formulas (as we did on the last slides) or we could use the sum-of-angles formula for tangent and write 3 tan 75 = tan( ) = tan 45 + tan tan 30 tan 45 = ( 3 )(1) Multiplying numerator and denominator by 3 gives tan 75 = If we don t like the square roots in the denominator, we can multiply numerator and denominator by (the conjugate of the denominator) and find that tan 75 = ( )( ) = ( ) = ( ) = + 7 / In the next presentation, we will look at double angle and power reduction formulas. (End) 8 / 8
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