Equations of 2-body motion

Size: px
Start display at page:

Download "Equations of 2-body motion"

Transcription

1 Equation of -body motion The fundamental eqn. of claical atodynamic i Newton Law of Univeal Gavitation: F g = Gm i i i ˆ i (1) We ae inteeted in atellite in obit about ingle planet, o (1) educe to the -body fom: F = G m ˆ () whee F i the gavitational foce on the atellite and i it poition vecto elative to the cente of the planet. We can ue Newton nd Law to get id of m : m F = m & = G & + G = 0 3 ˆ (3) Thi eqn can be olved, leading to the eqn of the atellite obit:

2 = a(1 - e ) 1 + e coθ and to Keple nd Law: ( & θ ) 0 d = dt (4) (5) Eqn (4) ay the atellite obit i a conic ection with the planet at one focu; we ll ee that the type of conic ection depend on the eccenticity, e, of the obit. An impotant conequence of thi i that the obit, planet and atellite-cente ae confined to a plane (the obital plane ) fo -body motion. The quantity ( θ & ) i the angula momentum, o (5) i a tatement of the conevation of angula momentum. Enegy- & θ = contant h (6) Gavity i a conevative field, theefoe the total enegy of the atellite:

3 KE o: E + PE = 1 v G m v G m 1 = contant (7) Notice that the PE pat of the enegy, a defined hee, i zeo fo at infinity, and negative fo anything le. Alo, E i eally the enegy pe unit ma. Thu: - only object that each with ome exce velocity (ie. that ecape the planet) have poitive value fo E. - object that can baely each (ie. whoe v 0 a ) have E=0. - object in bound (ie. cloed) obit have E < 0. Now we e eady to look at obit hape. Obit and enegy- The the negative-enegy, cloed obit obviouly have to be ellipe. Thee coepond to value of

4 e between 0 and 1. The cae of e=0 educe eqn (4) to = a (a being the emi-majo axi); the pecial cae of a cicula obit. The othe pecial cae, e=1 coepond to an ellipe with an infinite emi-majo axi (ty it and ee) a.k.a., a paabola. The paabola epeent a citical cae; e>0 obit coepond to hypebolic obit, which in pacecaft tem ae ecape obit. Cicula obit- Notice that, accoding to (5), both the adiu (thu altitude) and the angula velocity of a atellite in an elliptical obit vay with time; atellite move lowe the moe ditant they ae fom thei pimay and (5) goven how. Thi i vey bad fo imaging!

5 The ed dot ae poition of a atellite obitting the oigin, at fixed time inteval. The fact that the yellow tiangle all have equal aea i a conequence of (5). BUT, (5) alo ay that if i contant, o i the angula velocity. Thi i a big eaon why cicula obit ae pefeed fo almot all planetay emote ening application. Phyic 101 fact: The acceleation of an object moving in a cicle at contant angula velocity i: & v = cic ˆ But accoding to (3): & = G ˆ

6 thu: v cic = G (8) Thi equation give the peed of any object in cicula obit at adiu about a pimay. Hee ae ome example: (1) EOS-1 Tea i in low cicula obit (LEO) at an altitude of ~700 km o ~ 7080 km. It peed elative to Eath cente at thi altitude i 7.5 km/. The cicumfeence of thi obit i 44,500 km, o Tea peiod (T) i 44,500/7.5 = 5933 (1h 39min). () Geoynchonou atellite obit Eath in a cicle once each day. Solving: = geo geo π v T and v geo = G imultaneouly, and plugging in geo T = 4h one find that Eath GEO i at an altitude of 36,000 km ( geo = 4,400 km) and v geo = 3.1 km/ (notice how much malle thi i than the velocity of Tea, in LEO). When placed ove the equato, geoynch ae tationay ove one point on Eath uface, o they ae geotationay. Thee ae ton of emote ening (e.g. weathe) and comm at in thee obit. Obital element- In addition to an oigin, 6 numbe ae needed to pecify an obit. In the Cateian cae, we would need 3 poition component and 3 velocity component. An altenative, and much moe intuitive et ae called the obital element. We aleady have of thee: Semi-majo axi and eccenticity decibe the hape of the elliptical obit. But we till need to pecify it' oientation in pace:

7 "N" = node, "P" = peiapi, "S" = pimay body. Thee angle take cae of thi: the "longitude of the acending node" (Ω), the "inclination" (i) and the "agument of peiapi" (ω). Note that: - pefectly cicula obit would have no apide, theefoe ω would be undefined; howeve eal obit ae neve pefect...

8 - fom example () above that planeto-tationay atellite mut have inclination of zeo (theefoe Ω and ω ae undefined). - the highet latitude a atellite eache i equal to it' inclination; fo example, pola obitting atellite... (3) The vat majoity of emote ening atellite ae put in nea-pola LEO, fo a numbe of eaon: a. Highly inclined atellite can cove the actic/antactic. b. They can obeve mid- and low-latitude eveal time a day, with coveage of mot aea evey -10 day, depending on wathwidth, latitude, obit detail... One day' woth of a pola LEO atellite' coveage. c. They can be obitted o that they pa ove the day ide of the planet at the ame time evey day... A high- i atellite obitting a pheical planet.... and one obitting an oblate planet. a LEO i looely defined a an obit with apogee le than ~000 km in altitude.

9 Thi i becaue eal planet ae oblate. Thi hape caue the obit plane of inclined atellite (including planet!) to pece: J R E Ω = 3π co( i) adian pe obit. a ( 1 e ) Fo Eath, J = The obit chaacteitic a and i can be "tuned" (e i eentially zeo) o that the peceion ate i 1/365th of a degee pe Eathday. Thi why ton of Eath atellite (e.g. Tea, Aqua) have altitude ~700 km and i = ~98 o. (4) a' oblatene i ~ i geate than Eath' and it' adiu ~3390 km. To put a Global Suveyo in a "pm", un-ynchonou LO, GS' aeocentic obit i inclined at 9.9 o to a' equato, at an altitude of ~380 km. (5) The Hubble Space Telecope obit at alt. = 560 km, i = 8.5 o ; it' obit pecee about Eath at a highe ate, and in the oppoite diection than thoe of Tea and Aqua. The lat obital element i a time index; afte all, we alo need to know whee in it' obit the atellite i. A common one i the "time of peiapi paage". Launching atellite and pace pobe- -Launch ite nea the equato ae pefeed, becaue you can launch into mot pogade inclination of obit fom thee. -You alo get a boot of ~05. km/ of " v" fom the Eath' pin -Retogade obit (i > 90 o )alway equie an outof-plane maneuve which i vey expenive, vwie.

10 Inteplanetay tanfe- Pobe to othe planet obviouly have to get fom Eath to thei detination. Thi poce can be boken down into 4 tep: Eath ecape, tanfe (a.k.a. cuie phae ), planetay endezvou, and obit inetion o landing. Each of thee tep equie the expenditue of v. To leave Eath: E = 0 = 1 v ec G eath v = ec G eath = ~11. km/. Thi tep only get u clea of Eath and into a helio-centic obit eentially the ame a Eath, with a heliocentic velocity: v = o G R un eath-un = 9.8 km/. The next tep i getting into a 'tanfe' obit. Obviouly, the tanfe obit ha to inteect both the pacecaft' oiginal obit and the obit of the planetay taget. It alo ha to be planned o that when the pacecaft aive at it' taget' obit, the planet i, in fact, thee.

11 The mot efficient tanfe obit i called the Hohmann Tanfe: Hohmann tanfe (dahed) to upeio planet (left) and infeio planet (ight). (6) A lage numbe of pobe have been ent to a; afte Eath-ecape mot ae put on baically Hohmann tajectoie to a. To poceed we need thi Peliminay Fact: Combining eqn (4), (6), (7), it can be hown that E G a = (9) which elate the enegy of an obit to it ize. Applying eqn (9) and (7) to the peihelion of an Eath-a Hohmann obit: E = G eath-un un + ma-un = 1 v 1 G un eath-un Thi can be olved fo v 1 which tun out to be about 3.7 km/. Thu the pacecaft mut be given a v of ~3 km/. Exactly the ame method can be ued to find the peed of a in it obit (4.1 km/), and the peed of the pacecaft when it eache a (1.5 km/). Thi mean that, when the pacecaft eache a' obit, a i actually 'catching up to' it. Thu to endezvou with a it need about.6 km/ moe peed, fo a total of ~5.6 km/ jut fo the tanfe (not including the >11. km/ equied to ecape Eath). (7) To ente matian obit about a pobe mut loe moe peed till, othewie it will imply decibe a hypebolic path aound a and "e-

12 ecape". To actually land on a it ha to loe the equivalent of a' ecape velocity of ~5 km/. Theefoe, it take a total of at leat 1.8 km/ of v to land a pobe on a. Not all of thi ha to be via ocket buning, howeve. Note that thee ARE othe planet in the ola ytem... Alo, notice that obit inetion o landing actually equie de-celeation, elative to a... Gavity ait- -Caini, eenge Gavity aited tajectoie of Caini (left) and eenge (ight). Baking into obit o landing- -Reto-ocket -Aeobaking: agellan, a Global Suveyo -Paachute: Viking, a Rove, Huygen -Impact: Pathfinde, a Exploation Rove

AE 245 homework #9 solutions

AE 245 homework #9 solutions AE 245 homewok #9 olution Tim Smith 13 Apil 2000 1 Poblem1 In the Apollo miion fom the Eath to the Moon, the Satun thid tage povided the tan-luna inetion bun that tanfeed the Apollo pacecaft fom a low

More information

m1 m2 M 2 = M -1 L 3 T -2

m1 m2 M 2 = M -1 L 3 T -2 GAVITATION Newton s Univesal law of gavitation. Evey paticle of matte in this univese attacts evey othe paticle with a foce which vaies diectly as the poduct of thei masses and invesely as the squae of

More information

KEPLER S LAWS AND PLANETARY ORBITS

KEPLER S LAWS AND PLANETARY ORBITS KEPE S AWS AND PANETAY OBITS 1. Selected popeties of pola coodinates and ellipses Pola coodinates: I take a some what extended view of pola coodinates in that I allow fo a z diection (cylindical coodinates

More information

Chapter 19 Webassign Help Problems

Chapter 19 Webassign Help Problems Chapte 9 Webaign Help Poblem 4 5 6 7 8 9 0 Poblem 4: The pictue fo thi poblem i a bit mileading. They eally jut give you the pictue fo Pat b. So let fix that. Hee i the pictue fo Pat (a): Pat (a) imply

More information

LECTURE 14. m 1 m 2 b) Based on the second law of Newton Figure 1 similarly F21 m2 c) Based on the third law of Newton F 12

LECTURE 14. m 1 m 2 b) Based on the second law of Newton Figure 1 similarly F21 m2 c) Based on the third law of Newton F 12 CTU 4 ] NWTON W O GVITY -The gavity law i foulated fo two point paticle with ae and at a ditance between the. Hee ae the fou tep that bing to univeal law of gavitation dicoveed by NWTON. a Baed on expeiental

More information

Test 2 phy a) How is the velocity of a particle defined? b) What is an inertial reference frame? c) Describe friction.

Test 2 phy a) How is the velocity of a particle defined? b) What is an inertial reference frame? c) Describe friction. Tet phy 40 1. a) How i the velocity of a paticle defined? b) What i an inetial efeence fae? c) Decibe fiction. phyic dealt otly with falling bodie. d) Copae the acceleation of a paticle in efeence fae

More information

AY 7A - Fall 2010 Section Worksheet 2 - Solutions Energy and Kepler s Law

AY 7A - Fall 2010 Section Worksheet 2 - Solutions Energy and Kepler s Law AY 7A - Fall 00 Section Woksheet - Solutions Enegy and Keple s Law. Escape Velocity (a) A planet is obiting aound a sta. What is the total obital enegy of the planet? (i.e. Total Enegy = Potential Enegy

More information

Paths of planet Mars in sky

Paths of planet Mars in sky Section 4 Gavity and the Sola System The oldest common-sense view is that the eath is stationay (and flat?) and the stas, sun and planets evolve aound it. This GEOCENTRIC MODEL was poposed explicitly by

More information

AST 121S: The origin and evolution of the Universe. Introduction to Mathematical Handout 1

AST 121S: The origin and evolution of the Universe. Introduction to Mathematical Handout 1 Please ead this fist... AST S: The oigin and evolution of the Univese Intoduction to Mathematical Handout This is an unusually long hand-out and one which uses in places mathematics that you may not be

More information

HW6 Physics 311 Mechanics

HW6 Physics 311 Mechanics HW6 Physics 311 Mechanics Fall 015 Physics depatment Univesity of Wisconsin, Madison Instucto: Pofesso Stefan Westehoff By Nasse M. Abbasi June 1, 016 Contents 0.1 Poblem 1.........................................

More information

ASTR 3740 Relativity & Cosmology Spring Answers to Problem Set 4.

ASTR 3740 Relativity & Cosmology Spring Answers to Problem Set 4. ASTR 3740 Relativity & Comology Sping 019. Anwe to Poblem Set 4. 1. Tajectoie of paticle in the Schwazchild geomety The equation of motion fo a maive paticle feely falling in the Schwazchild geomety ae

More information

Ch 13 Universal Gravitation

Ch 13 Universal Gravitation Ch 13 Univesal Gavitation Ch 13 Univesal Gavitation Why do celestial objects move the way they do? Keple (1561-1630) Tycho Bahe s assistant, analyzed celestial motion mathematically Galileo (1564-1642)

More information

Newton s Laws, Kepler s Laws, and Planetary Orbits

Newton s Laws, Kepler s Laws, and Planetary Orbits Newton s Laws, Keple s Laws, and Planetay Obits PROBLEM SET 4 DUE TUESDAY AT START OF LECTURE 28 Septembe 2017 ASTRONOMY 111 FALL 2017 1 Newton s & Keple s laws and planetay obits Unifom cicula motion

More information

Solutions Practice Test PHYS 211 Exam 2

Solutions Practice Test PHYS 211 Exam 2 Solution Pactice Tet PHYS 11 Exam 1A We can plit thi poblem up into two pat, each one dealing with a epaate axi. Fo both the x- and y- axe, we have two foce (one given, one unknown) and we get the following

More information

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun Chapte 12 Gavitation PowePoint Lectues fo Univesity Physics, Twelfth Edition Hugh D. Young and Roge A. Feedman Lectues by James Pazun Modified by P. Lam 5_31_2012 Goals fo Chapte 12 To study Newton s Law

More information

= 4 3 π( m) 3 (5480 kg m 3 ) = kg.

= 4 3 π( m) 3 (5480 kg m 3 ) = kg. CHAPTER 11 THE GRAVITATIONAL FIELD Newton s Law of Gavitation m 1 m A foce of attaction occus between two masses given by Newton s Law of Gavitation Inetial mass and gavitational mass Gavitational potential

More information

Announcements. Description Linear Angular position x θ displacement x θ rate of change of position v x ω x = = θ average rate of change of position

Announcements. Description Linear Angular position x θ displacement x θ rate of change of position v x ω x = = θ average rate of change of position Announcement In the lectue link Look o tet 1 beakdown liting the topic o the quetion. Look o m umma o topic o the eam. We ll ue it on the eiew net Tueda. Look o a lit o baic phic act eleant o thi eam.

More information

KEPLER S LAWS OF PLANETARY MOTION

KEPLER S LAWS OF PLANETARY MOTION EPER S AWS OF PANETARY MOTION 1. Intoduction We ae now in a position to apply what we have leaned about the coss poduct and vecto valued functions to deive eple s aws of planetay motion. These laws wee

More information

Radius of the Moon is 1700 km and the mass is 7.3x 10^22 kg Stone. Moon

Radius of the Moon is 1700 km and the mass is 7.3x 10^22 kg Stone. Moon xample: A 1-kg stone is thown vetically up fom the suface of the Moon by Supeman. The maximum height fom the suface eached by the stone is the same as the adius of the moon. Assuming no ai esistance and

More information

Gravity. David Barwacz 7778 Thornapple Bayou SE, Grand Rapids, MI David Barwacz 12/03/2003

Gravity. David Barwacz 7778 Thornapple Bayou SE, Grand Rapids, MI David Barwacz 12/03/2003 avity David Bawacz 7778 Thonapple Bayou, and Rapid, MI 495 David Bawacz /3/3 http://membe.titon.net/daveb Uing the concept dicued in the peceding pape ( http://membe.titon.net/daveb ), I will now deive

More information

Chapter 13: Gravitation

Chapter 13: Gravitation v m m F G Chapte 13: Gavitation The foce that makes an apple fall is the same foce that holds moon in obit. Newton s law of gavitation: Evey paticle attacts any othe paticle with a gavitation foce given

More information

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE

MODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE VISUAL PHYSICS ONLIN MODUL 5 ADVANCD MCHANICS GRAVITATIONAL FILD: MOTION OF PLANTS AND SATLLITS SATLLITS: Obital motion of object of mass m about a massive object of mass M (m

More information

Homework Set 4 Physics 319 Classical Mechanics. m m k. x, x, x, x T U x x x x l 2. x x x x. x x x x

Homework Set 4 Physics 319 Classical Mechanics. m m k. x, x, x, x T U x x x x l 2. x x x x. x x x x Poble 78 a) The agangian i Hoewok Set 4 Phyic 319 Claical Mechanic k b) In te of the cente of a cooinate an x x1 x x1 x xc x x x x x1 xc x xc x x x x x1 xc x xc x, x, x, x T U x x x x l 1 1 1 1 1 1 1 1

More information

Chapter 13 Gravitation

Chapter 13 Gravitation Chapte 13 Gavitation In this chapte we will exploe the following topics: -Newton s law of gavitation, which descibes the attactive foce between two point masses and its application to extended objects

More information

AP Physics Centripetal Acceleration

AP Physics Centripetal Acceleration AP Phyic Centipetal Acceleation All of ou motion tudie thu fa hae dealt with taight-line tuff. We haen t dealt with thing changing diection duing thei tael. Thi type of motion i called angula motion. A

More information

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once.

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once. Honos Physics Fall, 2016 Cicula Motion & Toque Test Review Name: M. Leonad Instuctions: Complete the following woksheet. SHOW ALL OF YOUR WORK ON A SEPARATE SHEET OF PAPER. 1. Detemine whethe each statement

More information

Rotational Kinetic Energy

Rotational Kinetic Energy Add Impotant Rotational Kinetic Enegy Page: 353 NGSS Standad: N/A Rotational Kinetic Enegy MA Cuiculum Famewok (006):.1,.,.3 AP Phyic 1 Leaning Objective: N/A, but olling poblem have appeaed on peviou

More information

Between any two masses, there exists a mutual attractive force.

Between any two masses, there exists a mutual attractive force. YEAR 12 PHYSICS: GRAVITATION PAST EXAM QUESTIONS Name: QUESTION 1 (1995 EXAM) (a) State Newton s Univesal Law of Gavitation in wods Between any two masses, thee exists a mutual attactive foce. This foce

More information

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11.

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11. NSWRS - P Physics Multiple hoice Pactice Gavitation Solution nswe 1. m mv Obital speed is found fom setting which gives v whee M is the object being obited. Notice that satellite mass does not affect obital

More information

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and Exta notes fo cicula motion: Cicula motion : v keeps changing, maybe both speed and diection ae changing. At least v diection is changing. Hence a 0. Acceleation NEEDED to stay on cicula obit: a cp v /,

More information

Experiment 09: Angular momentum

Experiment 09: Angular momentum Expeiment 09: Angula momentum Goals Investigate consevation of angula momentum and kinetic enegy in otational collisions. Measue and calculate moments of inetia. Measue and calculate non-consevative wok

More information

Mon , (.12) Rotational + Translational RE 11.b Tues.

Mon , (.12) Rotational + Translational RE 11.b Tues. Mon..-.3, (.) Rotational + Tanlational RE.b Tue. EP0 Mon..4-.6, (.3) Angula Momentum & Toque RE.c Tue. Wed..7 -.9, (.) Toque EP RE.d ab Fi. Rotation Coue Eval.0 Quantization, Quiz RE.e Mon. Review fo Final

More information

Math Notes on Kepler s first law 1. r(t) kp(t)

Math Notes on Kepler s first law 1. r(t) kp(t) Math 7 - Notes on Keple s fist law Planetay motion and Keple s Laws We conside the motion of a single planet about the sun; fo simplicity, we assign coodinates in R 3 so that the position of the sun is

More information

History of Astronomy - Part II. Tycho Brahe - An Observer. Johannes Kepler - A Theorist

History of Astronomy - Part II. Tycho Brahe - An Observer. Johannes Kepler - A Theorist Histoy of Astonomy - Pat II Afte the Copenican Revolution, astonomes stived fo moe obsevations to help bette explain the univese aound them Duing this time (600-750) many majo advances in science and astonomy

More information

Chap 5. Circular Motion: Gravitation

Chap 5. Circular Motion: Gravitation Chap 5. Cicula Motion: Gavitation Sec. 5.1 - Unifom Cicula Motion A body moves in unifom cicula motion, if the magnitude of the velocity vecto is constant and the diection changes at evey point and is

More information

Circular motion. Objectives. Physics terms. Assessment. Equations 5/22/14. Describe the accelerated motion of objects moving in circles.

Circular motion. Objectives. Physics terms. Assessment. Equations 5/22/14. Describe the accelerated motion of objects moving in circles. Cicula motion Objectives Descibe the acceleated motion of objects moving in cicles. Use equations to analyze the acceleated motion of objects moving in cicles.. Descibe in you own wods what this equation

More information

PHYS Dynamics of Space Vehicles

PHYS Dynamics of Space Vehicles PHYS 4110 - Dynamics of Space Vehicles Chapte 3: Two Body Poblem Eath, Moon, Mas, and Beyond D. Jinjun Shan, Pofesso of Space Engineeing Depatment of Eath and Space Science and Engineeing Room 55, Petie

More information

OSCILLATIONS AND GRAVITATION

OSCILLATIONS AND GRAVITATION 1. SIMPLE HARMONIC MOTION Simple hamonic motion is any motion that is equivalent to a single component of unifom cicula motion. In this situation the velocity is always geatest in the middle of the motion,

More information

GRAVITATION. Thus the magnitude of the gravitational force F that two particles of masses m1

GRAVITATION. Thus the magnitude of the gravitational force F that two particles of masses m1 GAVITATION 6.1 Newton s law of Gavitation Newton s law of gavitation states that evey body in this univese attacts evey othe body with a foce, which is diectly popotional to the poduct of thei masses and

More information

Central Force Motion

Central Force Motion Cental Foce Motion Cental Foce Poblem Find the motion of two bodies inteacting via a cental foce. Examples: Gavitational foce (Keple poblem): m1m F 1, ( ) =! G ˆ Linea estoing foce: F 1, ( ) =! k ˆ Two

More information

B. Spherical Wave Propagation

B. Spherical Wave Propagation 11/8/007 Spheical Wave Popagation notes 1/1 B. Spheical Wave Popagation Evey antenna launches a spheical wave, thus its powe density educes as a function of 1, whee is the distance fom the antenna. We

More information

Lecture 1a: Satellite Orbits

Lecture 1a: Satellite Orbits Lectue 1a: Satellite Obits Outline 1. Newton s Laws of Motion 2. Newton s Law of Univesal Gavitation 3. Calculating satellite obital paametes (assuming cicula motion) Scala & Vectos Scala: a physical quantity

More information

Physics: Work & Energy Beyond Earth Guided Inquiry

Physics: Work & Energy Beyond Earth Guided Inquiry Physics: Wok & Enegy Beyond Eath Guided Inquiy Elliptical Obits Keple s Fist Law states that all planets move in an elliptical path aound the Sun. This concept can be extended to celestial bodies beyond

More information

Perhaps the greatest success of his theory of gravity was to successfully explain the motion of the heavens planets, moons, &tc.

Perhaps the greatest success of his theory of gravity was to successfully explain the motion of the heavens planets, moons, &tc. AP Phyic Gavity Si Iaac Newton i cedited with the dicovey of gavity. Now, of coue we know that he didn t eally dicove the thing let face it, people knew about gavity fo a long a thee have been people.

More information

Gravitation. AP/Honors Physics 1 Mr. Velazquez

Gravitation. AP/Honors Physics 1 Mr. Velazquez Gavitation AP/Honos Physics 1 M. Velazquez Newton s Law of Gavitation Newton was the fist to make the connection between objects falling on Eath and the motion of the planets To illustate this connection

More information

Gaia s Place in Space

Gaia s Place in Space Gaia s Place in Space The impotance of obital positions fo satellites Obits and Lagange Points Satellites can be launched into a numbe of diffeent obits depending on thei objectives and what they ae obseving.

More information

Determining solar characteristics using planetary data

Determining solar characteristics using planetary data Detemining sola chaacteistics using planetay data Intoduction The Sun is a G-type main sequence sta at the cente of the Sola System aound which the planets, including ou Eath, obit. In this investigation

More information

F 12. = G m m 1 2 F 21 = F 12. = G m 1m 2. Review. Physics 201, Lecture 22. Newton s Law Of Universal Gravitation

F 12. = G m m 1 2 F 21 = F 12. = G m 1m 2. Review. Physics 201, Lecture 22. Newton s Law Of Universal Gravitation Physics 201, Lectue 22 Review Today s Topics n Univesal Gavitation (Chapte 13.1-13.3) n Newton s Law of Univesal Gavitation n Popeties of Gavitational Foce n Planet Obits; Keple s Laws by Newton s Law

More information

Welcome to Aerospace Engineering

Welcome to Aerospace Engineering Welcome to Aeospace Engineeing DESIGN-CENTERED INTRODUCTION TO AEROSPACE ENGINEERING Notes 9 Topics 1. Couse Oganization. Today's Deams in Vaious Speed Ranges 3. Designing a Flight Vehicle: Route Map of

More information

Section 25 Describing Rotational Motion

Section 25 Describing Rotational Motion Section 25 Decibing Rotational Motion What do object do and wh do the do it? We have a ve thoough eplanation in tem of kinematic, foce, eneg and momentum. Thi include Newton thee law of motion and two

More information

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature)

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature) a = c v 2 Recap Centipetal acceleation: m/s 2 (towads cente of cuvatue) A centipetal foce F c is equied to keep a body in cicula motion: This foce poduces centipetal acceleation that continuously changes

More information

AMM PBL Members: Chin Guan Wei p Huang Pengfei p Lim Wilson p Yap Jun Da p Class: ME/MS803M/AM05

AMM PBL Members: Chin Guan Wei p Huang Pengfei p Lim Wilson p Yap Jun Da p Class: ME/MS803M/AM05 AMM PBL Membes: Chin Guan Wei p3674 Huang Pengfei p36783 Lim Wilson p36808 Yap Jun Da p36697 Class: MEMS803MAM05 The common values that we use ae: G=6.674 x 0 - m 3 kg - s - Radius of Eath ()= 637km [Fom

More information

AE 423 Space Technology I Chapter 2 Satellite Dynamics

AE 423 Space Technology I Chapter 2 Satellite Dynamics AE 43 Space Technology I Chapte Satellite Dynamic.1 Intoduction In thi chapte we eview ome dynamic elevant to atellite dynamic and we etablih ome of the baic popetie of atellite dynamic.. Dynamic of a

More information

Central Force Problem. Central Force Motion. Two Body Problem: Center of Mass Coordinates. Reduction of Two Body Problem 8.01 W14D1. + m 2. m 2.

Central Force Problem. Central Force Motion. Two Body Problem: Center of Mass Coordinates. Reduction of Two Body Problem 8.01 W14D1. + m 2. m 2. Cental oce Poblem ind the motion of two bodies inteacting via a cental foce. Cental oce Motion 8.01 W14D1 Examples: Gavitational foce (Keple poblem): 1 1, ( ) G mm Linea estoing foce: ( ) k 1, Two Body

More information

GRAVITATION. Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., New Delhi -18 PG 1

GRAVITATION. Einstein Classes, Unit No. 102, 103, Vardhman Ring Road Plaza, Vikas Puri Extn., New Delhi -18 PG 1 Einstein Classes, Unit No. 0, 0, Vahman Ring Roa Plaza, Vikas Pui Extn., New Delhi -8 Ph. : 96905, 857, E-mail einsteinclasses00@gmail.com, PG GRAVITATION Einstein Classes, Unit No. 0, 0, Vahman Ring Roa

More information

6.4 Period and Frequency for Uniform Circular Motion

6.4 Period and Frequency for Uniform Circular Motion 6.4 Peiod and Fequency fo Unifom Cicula Motion If the object is constained to move in a cicle and the total tangential foce acting on the total object is zeo, F θ = 0, then (Newton s Second Law), the tangential

More information

Physics 111. Ch 12: Gravity. Newton s Universal Gravity. R - hat. the equation. = Gm 1 m 2. F g 2 1. ˆr 2 1. Gravity G =

Physics 111. Ch 12: Gravity. Newton s Universal Gravity. R - hat. the equation. = Gm 1 m 2. F g 2 1. ˆr 2 1. Gravity G = ics Announcements day, embe 9, 004 Ch 1: Gavity Univesal Law Potential Enegy Keple s Laws Ch 15: Fluids density hydostatic equilibium Pascal s Pinciple This week s lab will be anothe physics wokshop -

More information

Static Electric Fields. Coulomb s Law Ε = 4πε. Gauss s Law. Electric Potential. Electrical Properties of Materials. Dielectrics. Capacitance E.

Static Electric Fields. Coulomb s Law Ε = 4πε. Gauss s Law. Electric Potential. Electrical Properties of Materials. Dielectrics. Capacitance E. Coulomb Law Ε Gau Law Electic Potential E Electical Popetie of Mateial Conducto J σe ielectic Capacitance Rˆ V q 4πε R ρ v 2 Static Electic Field εe E.1 Intoduction Example: Electic field due to a chage

More information

Universal Gravitation

Universal Gravitation Add Ipotant Univeal Gavitation Pae: 7 Note/Cue Hee Unit: Dynaic (oce & Gavitation Univeal Gavitation Unit: Dynaic (oce & Gavitation NGSS Standad: HS-PS-4 MA Cuiculu aewok (00:.7 AP Phyic Leanin Objective:.B..,.B..,

More information

Chap13. Universal Gravitation

Chap13. Universal Gravitation Chap13. Uniesal Gaitation Leel : AP Physics Instucto : Kim 13.1 Newton s Law of Uniesal Gaitation - Fomula fo Newton s Law of Gaitation F g = G m 1m 2 2 F21 m1 F12 12 m2 - m 1, m 2 is the mass of the object,

More information

ω = θ θ o = θ θ = s r v = rω

ω = θ θ o = θ θ = s r v = rω Unifom Cicula Motion Unifom cicula motion is the motion of an object taveling at a constant(unifom) speed in a cicula path. Fist we must define the angula displacement and angula velocity The angula displacement

More information

Physics 181. Assignment 4

Physics 181. Assignment 4 Physics 181 Assignment 4 Solutions 1. A sphee has within it a gavitational field given by g = g, whee g is constant and is the position vecto of the field point elative to the cente of the sphee. This

More information

Midterm Exam #2, Part A

Midterm Exam #2, Part A Physics 151 Mach 17, 2006 Midtem Exam #2, Pat A Roste No.: Scoe: Exam time limit: 50 minutes. You may use calculatos and both sides of ONE sheet of notes, handwitten only. Closed book; no collaboation.

More information

TRAVELING WAVES. Chapter Simple Wave Motion. Waves in which the disturbance is parallel to the direction of propagation are called the

TRAVELING WAVES. Chapter Simple Wave Motion. Waves in which the disturbance is parallel to the direction of propagation are called the Chapte 15 RAVELING WAVES 15.1 Simple Wave Motion Wave in which the ditubance i pependicula to the diection of popagation ae called the tanvee wave. Wave in which the ditubance i paallel to the diection

More information

Solving Problems of Advance of Mercury s Perihelion and Deflection of. Photon Around the Sun with New Newton s Formula of Gravity

Solving Problems of Advance of Mercury s Perihelion and Deflection of. Photon Around the Sun with New Newton s Formula of Gravity Solving Poblems of Advance of Mecuy s Peihelion and Deflection of Photon Aound the Sun with New Newton s Fomula of Gavity Fu Yuhua (CNOOC Reseach Institute, E-mail:fuyh945@sina.com) Abstact: Accoding to

More information

Math Section 4.2 Radians, Arc Length, and Area of a Sector

Math Section 4.2 Radians, Arc Length, and Area of a Sector Math 1330 - Section 4. Radians, Ac Length, and Aea of a Secto The wod tigonomety comes fom two Geek oots, tigonon, meaning having thee sides, and mete, meaning measue. We have aleady defined the six basic

More information

Lecture 22. PE = GMm r TE = GMm 2a. T 2 = 4π 2 GM. Main points of today s lecture: Gravitational potential energy: Total energy of orbit:

Lecture 22. PE = GMm r TE = GMm 2a. T 2 = 4π 2 GM. Main points of today s lecture: Gravitational potential energy: Total energy of orbit: Lectue Main points of today s lectue: Gavitational potential enegy: Total enegy of obit: PE = GMm TE = GMm a Keple s laws and the elation between the obital peiod and obital adius. T = 4π GM a3 Midtem

More information

Honors Classical Physics I

Honors Classical Physics I Hono Claical Phyic I PHY141 Lectue 9 Newton Law of Gavity Pleae et you Clicke Channel to 1 9/15/014 Lectue 9 1 Newton Law of Gavity Gavitational attaction i the foce that act between object that have a

More information

Circular Orbits. and g =

Circular Orbits. and g = using analyse planetay and satellite motion modelled as unifom cicula motion in a univesal gavitation field, a = v = 4π and g = T GM1 GM and F = 1M SATELLITES IN OBIT A satellite is any object that is

More information

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Department. Problem Set 10 Solutions. r s

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Department. Problem Set 10 Solutions. r s MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Depatment Physics 8.033 Decembe 5, 003 Poblem Set 10 Solutions Poblem 1 M s y x test paticle The figue above depicts the geomety of the poblem. The position

More information

V V The circumflex (^) tells us this is a unit vector

V V The circumflex (^) tells us this is a unit vector Vecto Vecto have Diection and Magnitude Mike ailey mjb@c.oegontate.edu Magnitude: V V V V x y z vecto.pptx Vecto Can lo e Defined a the oitional Diffeence etween Two oint 3 Unit Vecto have a Magnitude

More information

Escape Velocity. GMm ] B

Escape Velocity. GMm ] B 1 PHY2048 Mach 31, 2006 Escape Velocity Newton s law of gavity: F G = Gm 1m 2 2, whee G = 667 10 11 N m 2 /kg 2 2 3 10 10 N m 2 /kg 2 is Newton s Gavitational Constant Useful facts: R E = 6 10 6 m M E

More information

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N Chapte answes Heinemann Physics 4e Section. Woked example: Ty youself.. GRAVITATIONAL ATTRACTION BETWEEN SMALL OBJECTS Two bowling balls ae sitting next to each othe on a shelf so that the centes of the

More information

Rotational Motion. Lecture 6. Chapter 4. Physics I. Course website:

Rotational Motion. Lecture 6. Chapter 4. Physics I. Course website: Lectue 6 Chapte 4 Physics I Rotational Motion Couse website: http://faculty.uml.edu/andiy_danylov/teaching/physicsi Today we ae going to discuss: Chapte 4: Unifom Cicula Motion: Section 4.4 Nonunifom Cicula

More information

FI 2201 Electromagnetism

FI 2201 Electromagnetism FI Electomagnetim Aleande A. Ikanda, Ph.D. Phyic of Magnetim and Photonic Reeach Goup ecto Analyi CURILINEAR COORDINAES, DIRAC DELA FUNCION AND HEORY OF ECOR FIELDS Cuvilinea Coodinate Sytem Cateian coodinate:

More information

r cos, and y r sin with the origin of coordinate system located at

r cos, and y r sin with the origin of coordinate system located at Lectue 3-3 Kinematics of Rotation Duing ou peious lectues we hae consideed diffeent examples of motion in one and seeal dimensions. But in each case the moing object was consideed as a paticle-like object,

More information

Describing Circular motion

Describing Circular motion Unifom Cicula Motion Descibing Cicula motion In ode to undestand cicula motion, we fist need to discuss how to subtact vectos. The easiest way to explain subtacting vectos is to descibe it as adding a

More information

Radian and Degree Measure

Radian and Degree Measure CHAT Pe-Calculus Radian and Degee Measue *Tigonomety comes fom the Geek wod meaning measuement of tiangles. It pimaily dealt with angles and tiangles as it petained to navigation, astonomy, and suveying.

More information

Objective Notes Summary

Objective Notes Summary Objective Notes Summay An object moving in unifom cicula motion has constant speed but not constant velocity because the diection is changing. The velocity vecto in tangent to the cicle, the acceleation

More information

Fall 2004/05 Solutions to Assignment 5: The Stationary Phase Method Provided by Mustafa Sabri Kilic. I(x) = e ixt e it5 /5 dt (1) Z J(λ) =

Fall 2004/05 Solutions to Assignment 5: The Stationary Phase Method Provided by Mustafa Sabri Kilic. I(x) = e ixt e it5 /5 dt (1) Z J(λ) = 8.35 Fall 24/5 Solution to Aignment 5: The Stationay Phae Method Povided by Mutafa Sabi Kilic. Find the leading tem fo each of the integal below fo λ >>. (a) R eiλt3 dt (b) R e iλt2 dt (c) R eiλ co t dt

More information

10. Universal Gravitation

10. Universal Gravitation 10. Univesal Gavitation Hee it is folks, the end of the echanics section of the couse! This is an appopiate place to complete the study of mechanics, because with his Law of Univesal Gavitation, Newton

More information

Spring 2001 Physics 2048 Test 3 solutions

Spring 2001 Physics 2048 Test 3 solutions Sping 001 Physics 048 Test 3 solutions Poblem 1. (Shot Answe: 15 points) a. 1 b. 3 c. 4* d. 9 e. 8 f. 9 *emembe that since KE = ½ mv, KE must be positive Poblem (Estimation Poblem: 15 points) Use momentum-impulse

More information

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s 1. A stone falls fom a platfom 18 m high. When will it hit the gound? (a) 1.74 s (b) 1.83 s (c) 1.9 s (d).01 s Constant acceleation D = v 0 t + ½ a t. Which, if any, of these foces causes the otation of

More information

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS LSN 10-: MOTION IN A GRAVITATIONAL FIELD Questions Fom Reading Activity? Gavity Waves? Essential Idea: Simila appoaches can be taken in analyzing electical

More information

Chapter 12. Kinetics of Particles: Newton s Second Law

Chapter 12. Kinetics of Particles: Newton s Second Law Chapte 1. Kinetics of Paticles: Newton s Second Law Intoduction Newton s Second Law of Motion Linea Momentum of a Paticle Systems of Units Equations of Motion Dynamic Equilibium Angula Momentum of a Paticle

More information

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session.

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session. - 5 - TEST 1R This is the epeat vesion of TEST 1, which was held duing Session. This epeat test should be attempted by those students who missed Test 1, o who wish to impove thei mak in Test 1. IF YOU

More information

Mechanics Physics 151

Mechanics Physics 151 Mechanics Physics 151 Lectue 5 Cental Foce Poblem (Chapte 3) What We Did Last Time Intoduced Hamilton s Pinciple Action integal is stationay fo the actual path Deived Lagange s Equations Used calculus

More information

Rotational Motion. Every quantity that we have studied with translational motion has a rotational counterpart

Rotational Motion. Every quantity that we have studied with translational motion has a rotational counterpart Rotational Motion & Angula Momentum Rotational Motion Evey quantity that we have studied with tanslational motion has a otational countepat TRANSLATIONAL ROTATIONAL Displacement x Angula Position Velocity

More information

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK.

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK. AP Physics C Sping, 2017 Cicula-Rotational Motion Mock Exam Name: Answe Key M. Leonad Instuctions: (92 points) Answe the following questions. SHOW ALL OF YOUR WORK. ( ) 1. A stuntman dives a motocycle

More information

Chapter. s r. check whether your calculator is in all other parts of the body. When a rigid body rotates through a given angle, all

Chapter. s r. check whether your calculator is in all other parts of the body. When a rigid body rotates through a given angle, all conveted to adians. Also, be sue to vanced to a new position (Fig. 7.2b). In this inteval, the line OP has moved check whethe you calculato is in all othe pats of the body. When a igid body otates though

More information

e.g: If A = i 2 j + k then find A. A = Ax 2 + Ay 2 + Az 2 = ( 2) = 6

e.g: If A = i 2 j + k then find A. A = Ax 2 + Ay 2 + Az 2 = ( 2) = 6 MOTION IN A PLANE 1. Scala Quantities Physical quantities that have only magnitude and no diection ae called scala quantities o scalas. e.g. Mass, time, speed etc. 2. Vecto Quantities Physical quantities

More information

Revision Guide for Chapter 11

Revision Guide for Chapter 11 Revision Guide fo Chapte 11 Contents Revision Checklist Revision Notes Momentum... 4 Newton's laws of motion... 4 Wok... 5 Gavitational field... 5 Potential enegy... 7 Kinetic enegy... 8 Pojectile... 9

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion constant speed Pick a point in the objects motion... What diection is the velocity? HINT Think about what diection the object would tavel if the sting wee cut Unifom Cicula Motion

More information

HW Solutions # MIT - Prof. Please study example 12.5 "from the earth to the moon". 2GmA v esc

HW Solutions # MIT - Prof. Please study example 12.5 from the earth to the moon. 2GmA v esc HW Solutions # 11-8.01 MIT - Pof. Kowalski Univesal Gavity. 1) 12.23 Escaping Fom Asteoid Please study example 12.5 "fom the eath to the moon". a) The escape velocity deived in the example (fom enegy consevation)

More information

F(r) = r f (r) 4.8. Central forces The most interesting problems in classical mechanics are about central forces.

F(r) = r f (r) 4.8. Central forces The most interesting problems in classical mechanics are about central forces. 4.8. Cental foces The most inteesting poblems in classical mechanics ae about cental foces. Definition of a cental foce: (i) the diection of the foce F() is paallel o antipaallel to ; in othe wods, fo

More information

Chapter 5: Uniform Circular Motion

Chapter 5: Uniform Circular Motion Chapte 5: Unifom Cicula Motion Motion at constant speed in a cicle Centipetal acceleation Banked cuves Obital motion Weightlessness, atificial gavity Vetical cicula motion Centipetal Foce Acceleation towad

More information

Chapter 6. NEWTON S 2nd LAW AND UNIFORM CIRCULAR MOTION

Chapter 6. NEWTON S 2nd LAW AND UNIFORM CIRCULAR MOTION Chapte 6 NEWTON S nd LAW AND UNIFORM CIRCULAR MOTION Phyic 1 1 3 4 ting Quetion: A ball attached to the end of a ting i whiled in a hoizontal plane. At the point indicated, the ting beak. Looking down

More information

Mechanics and Special Relativity (MAPH10030) Assignment 3

Mechanics and Special Relativity (MAPH10030) Assignment 3 (MAPH0030) Assignment 3 Issue Date: 03 Mach 00 Due Date: 4 Mach 00 In question 4 a numeical answe is equied with pecision to thee significant figues Maks will be deducted fo moe o less pecision You may

More information

Circular Motion. Mr. Velazquez AP/Honors Physics

Circular Motion. Mr. Velazquez AP/Honors Physics Cicula Motion M. Velazquez AP/Honos Physics Objects in Cicula Motion Accoding to Newton s Laws, if no foce acts on an object, it will move with constant speed in a constant diection. Theefoe, if an object

More information

Chapter 2: Basic Physics and Math Supplements

Chapter 2: Basic Physics and Math Supplements Chapte 2: Basic Physics and Math Supplements Decembe 1, 215 1 Supplement 2.1: Centipetal Acceleation This supplement expands on a topic addessed on page 19 of the textbook. Ou task hee is to calculate

More information