The rotating Pulfrich effect derivation of equations
|
|
- Augustus Shields
- 5 years ago
- Views:
Transcription
1 The rotating Pulfrich effect erivation of equations RWD Nickalls, Department of Anaesthesia, Nottingham University Hospitals, City Hospital Campus, Nottingham, UK. 3 The rotating Pulfrich effect: erivation of equations The general case Determine m 1 m Determine m 1 + m Solve for x Solve for y The transition conition (φ/ε = 1) Viewing configurations Relate papers FROM: Nickalls RWD. Pulfrich geometry May 13, 2009
2 Chapter 3 The rotating Pulfrich effect: erivation of equations 1 Here we etail the erivation of the equations presente in the Appenix to the paper:- Nickalls RWD (1986). The rotating Pulfrich effect, an a new metho of etermining visual latency ifferences. Vision Research; 26, ( http: // ) 3.1 The general case Consier that the eyes (L, R; separation 2a) view an object P (the target) rotating clockwise about the center O with constant angular velocity ω. Let the eyes (L,R) be a istance from the center of rotation O such that the line LR is parallel to the y-axis (see Figure 3.1). If the target P is associate with angle θ, then let P lag behin P by angle φ (ue to a filter F in front of the right eye). The locus I of the apparent position is given by the intersection of the lines RP an LP. Let the lines RP an LP be given by where RP y = m 1 (x + ) a, (3.1) LP y = m 2 (x + ) + a, (3.2) m 1 = r sinθ + a r cosθ +, (3.3) r sin(θ φ) a m 2 = r cos(θ φ) +. (3.4) Solving these for x an y gives ( ) 2a x =, (3.5) m 1 m 2 ( ) m1 + m 2 y = a. (3.6) m 1 m
3 RWD Nickalls (2009) ROTATING PULFRICH EFFECT 6 Figure 3.1: Diagram (from above) showing the relative positions in the general case (see text) Determine m 1 m 2 m 1 m 2 = = ( ) ( ) r sinθ + a r sin(θ φ) a r cosθ + r cos(θ φ) + (r sinθ + a)r cos(θ φ) + } (r cosθ + )r sin(θ φ) a}. (r cosθ + )r cos(θ φ) + } Expaning an regrouping gives r 2 sinθ cos(θ φ) cosθ sin(θ φ)} + rsinθ sin(θ φ)} } m 1 m 2 = + arcosθ + cos(θ φ)} + 2a r 2 cosθ cos(θ φ) + rcosθ + cos(θ φ)} + 2. Since this simplifies to sinθ cos(θ φ) cosθ sin(θ φ) sinθ (θ φ)} sinφ m 1 m 2 = r2 sinφ + r2cos(θ φ/2)sin(φ/2)} + ar2cos(θ φ/2)cos(φ/2)} + 2a r 2 cosθ cos(θ φ) + rcosθ + cos(θ φ)} + 2, i.e., m 1 m 2 = r2 sinφ + 2r cos(θ φ/2)sin(φ/2) + 2ar cos(θ φ/2)cos(φ/2) + 2a r 2 cosθ cos(θ φ) + rcosθ + cos(θ φ)} + 2. (3.7)
4 RWD Nickalls (2009) ROTATING PULFRICH EFFECT Determine m 1 + m 2 m 1 + m 2 = = ( ) ( ) r sinθ + a r sin(θ φ) a + r cosθ + r cos(θ φ) + (r sinθ + a)r cos(θ φ) + } + (r cosθ + )r sin(θ φ) a}. (r cosθ + )r cos(θ φ) + } Expaning an regrouping gives r 2 sinθ cos(θ φ) + cosθ sin(θ φ)} + rsinθ + sin(θ φ)} } m 1 +m 2 = + arcos(θ φ) cosθ} r 2 cosθ cos(θ φ) + rcosθ + cos(θ φ)} + 2. Since sinθ cos(θ φ) + cosθ sin(θ φ) = sinθ + (θ φ)} = sin(2θ φ), this simplifies to r 2 sin(2θ φ) + r2sin(θ φ/2)cos(φ/2)} } m 1 +m 2 = + ar 2sin(θ φ/2)sin( φ/2)} r 2 cosθ cos(θ φ) + rcosθ + cos(θ φ)} + 2. Since sin( φ/2) = sin(φ/2) then an so we have 2sin(θ φ/2)sin( φ/2)} 2sin(θ φ/2)sin(φ/2), m 1 +m 2 = r2 sin(2θ φ) + r2sin(θ φ/2)cos(φ/2)} + ar2sin(θ φ/2)sin(φ/2)} r 2 cosθ cos(θ φ) + rcosθ + cos(θ φ)} + 2. Since sin(2θ φ) 2sin(θ φ/2)cos(θ φ/2) we can write 2r 2 sin(θ φ/2)cos(θ φ/2) + 2rsin(θ φ/2)cos(φ/2)} } m 1 +m 2 = + 2arsin(θ φ/2)sin(φ/2)} r 2 cosθ cos(θ φ) + rcosθ + cos(θ φ)} + 2, i.e., m 1 + m 2 = Solve for x From above we have 2r sin(θ φ/2)r cos(θ φ/2) + cos(φ/2) + asin(φ/2)} r 2 cosθ cos(θ φ) + rcosθ + cos(θ φ)} + 2. (3.8) ( ) 2a x = = 2a (m 1 m 2 ). m 1 m 2 m 1 m 2
5 RWD Nickalls (2009) ROTATING PULFRICH EFFECT 8 Substituting for (m 1 m 2 ), an after some manipulation, we eventually get x = 2ar2 cosθ cos(θ φ) r 2 sinφ + 2r cos(θ φ/2)acos(φ/2) sin(φ/2)} 2a + r 2. sinφ + 2r cos(θ φ/2)acos(φ/2) + sin(φ/2)} (3.9) Now we evelop 2ar 2 cosθ cos(θ φ) by expressing it in terms of cos(θ φ/2), using the following ientities: cosθ cos(θ φ) 1 cosφ + cos(2θ φ)}, 2 cos(2θ φ) 2cos 2 (θ φ/2) 1. Combining the two ientities 3.10 then gives 2ar 2 cosθ cos(θ φ) 2ar 2 cos 2 (θ φ/2) ar 2 + ar 2 cosφ, (3.10) which now allows us to substitute for cos(θ φ) in equation 3.9 an hence obtain x as a function of cos(θ φ/2) as follows } 2ar 2 cos 2 (θ φ/2) ar 2 + r 2 (acosφ sinφ) x = + 2r cos(θ φ/2)acos(φ/2) sin(φ/2)} 2a + r 2 sinφ + 2r cos(θ φ/2)acos(φ/2) + sin(φ/2)}. (3.11) Solve for y From above we have ( ) m1 + m 2 y = a. m 1 m 2 Substituting for (m 1 m 2 ) an (m 1 + m 2 ) we get ( ) 2r sin(θ φ/2)r cos(θ φ/2) + cos(φ/2) + asin(φ/2)} y = a r 2, sinφ + 2r cos(θ φ/2)sin(φ/2) + 2ar cos(θ φ/2)cos(φ/2) + 2a which after regrouping of terms gives y = 2ar sin(θ φ/2)r cos(θ φ/2) + cos(φ/2) + asin(φ/2)} 2a + r 2 sinφ + 2r cos(θ φ/2)acos(φ/2) + sin(φ/2)}. Finally, we expan r 2 sinφ 2r 2 sin(φ/2)cos(φ/2) an then ivie throughout by 2, to give y = ar sin(θ φ/2)r cos(θ φ/2) + cos(φ/2) + asin(φ/2)} a + r 2 sin(φ/2)cos(φ/2) + r cos(θ φ/2)acos(φ/2) + sin(φ/2)}. (3.12) Equations 3.11 & 3.12 are therefore the parametric equations of the path I, as θ increases from 0 to 360eg. When P rotates clockwise θ is consiere to be +ve; with anticlockwise rotation θ is consiere to be ve. Now equation 3.11 is quaratic in cos(θ φ/2) an so θ can be eliminate to give the Cartesian equation, by substituting the roots of equation 3.11 for cos(θ φ/2) into equation In the general case this gives rise to a complicate higher curve which is symmetric about the x-axis, as shown in figure 3.2 (from Nickalls, 1986). The two curves shown in figure 3.2 represent equations 3.11 an 3.12 for a range of values of the parameter φ/ε, with P rotating clockwise. When φ/ε < 1 then the Pulfrich construction (P x ) is also clockwise. When φ/ε > 1 then the locus is anti-clockwise. The special transition case, when φ/ε = 1, is iscusse in the next section.
6 RWD Nickalls (2009) ROTATING PULFRICH EFFECT 9 Figure 3.2: These graphs show the theoretical curves (Equations 3.11 an 3.12) inicating the preicte apparent paths associate with ifferent latency ifferences (i.e., with ifferent filters) while fixating a vertical ro, rotating clockwise in a horizontal circle, from a istance of 200 cm to the left of the centre, as in the arrangement shown in Fig. 3.1 (2a = 6 6 cm; ω = 45 1 rpm; ro is 20 cm from the centre; axes are in cm.) The parameter (latency ratio) is the latency ifference expresse as a multiple of that require to see transition uner these circumstances (7 msec). The +ve sign inicates that the filter is in front of the right eye; ve sign inicates the filter is in front of the left eye. Arrows inicate the irection of apparent rotation. Thick circle (latency ratio = 0) inicates the actual path of the rotating ro ( t = 0). The thick arc (latency ratio = +1) inicates the apparent path at transition ( t = 7 msec). Top: Latency ratios from 0 5 to +1, clockwise rotation. Bottom: Latency ratios from +1 to +2 5, anticlockwise rotation.
7 RWD Nickalls (2009) ROTATING PULFRICH EFFECT The transition conition (φ/ε = 1) This is the special transition case which is associate with the conition φ = ε. In this case the locus I is an arc of the circle LRO as shown in the following figure. Figure 3.3: Diagram (from above) showing the relative positions in the general case (see text). At transition I passes through the center O an so Substituting equation 3.13 into equation 3.11 gives an x = tan(φ/2) = a/ (3.13) (r 2 /)(a )sin 2 (θ φ/2) a r 2 + 2r a cos(θ φ/2), (3.14) (r/)(a )r cos(θ φ/2) + } a y = ±sin(θ φ/2) a r 2 + 2r. (3.15) a cos(θ φ/2) Eliminating θ from equations 3.14 an 3.15 gives ( a y ) = x + x, (3.16) which represents a circle passing through L,R an the origin O, where R = (a )/(2) as shown in the figure above. The equation can therefore be expresse in terms of R as follows. y 2 = x(2r + x).
8 RWD Nickalls (2009) ROTATING PULFRICH EFFECT 11 It is important to note that the path at transition is not necessarily the whole circle as, epening on the conitions, only part of the arc is mathematically real. The limits are foun by solving equation 3.15 for θ as follows. Conveniently equation 3.15 can be turne into a quaratic by using the ientity sin 2 (θ φ/2) 1 cos 2 (θ φ/2) which generates (r 2 /)(a )cos 2 (θ φ/2) 2xr } a cos(θ φ/2) x(a r 2 ) (r 2 /)(a = 0. ) Diviing throughout by the coefficient of cos 2 (θ φ/2) an rearranging we get ( ) 2x cos 2 (θ φ/2) r cos(θ φ/2) = x a r 2 + x a We can now use the metho of completing the square to solve the quaratic by aing the term (x/(r (a )) 2 to both sies as follows. which gives ( cos(θ φ/2) an so we have ( cos(θ φ/2) cos(θ φ/2) = x r a x ) 2 = ( r a x r a ) 2 + x r 2 + x a , ) 2 ( )( ) x x = r a , (x )( ) x x r a 2 + ± 2 r a (3.17) Now since from the geometry we have R 2 = a 2 + ( R) 2 then 2R = a2 + 2, an so finally we have (x ) ( x ) cos(θ φ/2) = x 2Rr 2 ± r R + 1. (3.18) It follows therefore that for equation 3.15 to yiel real solutions we nee the contents of each of the square-root terms to be 0, that is we nee /R 0 an ( ) x ( x ) r R + 1 0, for which we nee either ( ) x r or ( ) x r AND AND ( x 2R + 1 ) 0 ( x 2R + 1 ) 0,
9 RWD Nickalls (2009) ROTATING PULFRICH EFFECT 12 where, r, an R are of course all negative owing to our chosen coorinate system (centere at the center of rotation) an configuration (viewing from the left). However, x cannot be less than 2R (since the locus is the arc of the circle raius R), an so only the first conition is relevant for a real locus, i.e x r2 AND which is consistent with the single conition x 2R, Viewing configurations x r2. (3.19) There are three configurations which may now be consiere, epening on whether the points L,R are outsie the circle, on the circle, or insie the circle. In practice however, since the observer is outsie the circle of rotation, we nee only consier the case for which L,R lie outsie the circle ( a > r 2 ), i.e., r 2 ( a 2 > + 2 ), for which the conition x r 2 / is sufficient, as this is always consistent with x (a )/, an hence we have r 2 x 0. (3.20) 3.3 Relate papers The following relate papers aress the visual an/or geometric aspects of the rotating Pulfrich effect. They are all available from Nakamizo S, Nawae H, an Nickalls RWD (1998). Precision of the rotating Pulfrich technique for etermining visual latency ifference is significantly greater if viewing istance is varie, than if angular velocity is varie. Perception; 27 (Supplement), 97. (Abstracts of the 21st European Conference on Visual Perception; Oxfor, Englan; August 1998). com/abstract.cgi?i=v Nakamizo S, Nickalls RWD an Nawae H (2004). Visual latency ifference etermine by two rotating Pulfrich techniques. Swiss Journal of Psychology, 63, Nickalls RWD (1986). A line-an-conic theorem having a visual correlate. Mathematical Gazette; 70 (March), 27 29, (JSTOR). ick/papers/maths/lineanconic1986.pf Nickalls RWD (1996). The influence of target angular velocity on visual latency ifference etermine using the rotating Pulfrich effect. Vision Research; 36,
10 RWD Nickalls (2009) ROTATING PULFRICH EFFECT 13 Nickalls RWD (2000). A conic theorem generalise: irecte angles an applications. Mathematical Gazette; 84 (July), , (JSTOR). nickalls.org/ick/papers/maths/conicthm2000.pf Nickalls RWD, Kazachkov AR, Vasylevska Yu.V an Kalinin VV (2002). Motional visual illusions on-line. Proceeings of the 2002 International Conference on Information an Communication Technologies in Eucation (ICTE2002); Baajoz Spain; November 13 16, 2002; p (ISBN: Coleccion ). pf
Physics 505 Electricity and Magnetism Fall 2003 Prof. G. Raithel. Problem Set 3. 2 (x x ) 2 + (y y ) 2 + (z + z ) 2
Physics 505 Electricity an Magnetism Fall 003 Prof. G. Raithel Problem Set 3 Problem.7 5 Points a): Green s function: Using cartesian coorinates x = (x, y, z), it is G(x, x ) = 1 (x x ) + (y y ) + (z z
More informationS10.G.1. Fluid Flow Around the Brownian Particle
Rea Reichl s introuction. Tables & proofs for vector calculus formulas can be foun in the stanar textbooks G.Arfken s Mathematical Methos for Physicists an J.D.Jackson s Classical Electroynamics. S0.G..
More informationSolutions to Math 41 Second Exam November 4, 2010
Solutions to Math 41 Secon Exam November 4, 2010 1. (13 points) Differentiate, using the metho of your choice. (a) p(t) = ln(sec t + tan t) + log 2 (2 + t) (4 points) Using the rule for the erivative of
More informationTable of Common Derivatives By David Abraham
Prouct an Quotient Rules: Table of Common Derivatives By Davi Abraham [ f ( g( ] = [ f ( ] g( + f ( [ g( ] f ( = g( [ f ( ] g( g( f ( [ g( ] Trigonometric Functions: sin( = cos( cos( = sin( tan( = sec
More informationLecture XII. where Φ is called the potential function. Let us introduce spherical coordinates defined through the relations
Lecture XII Abstract We introuce the Laplace equation in spherical coorinates an apply the metho of separation of variables to solve it. This will generate three linear orinary secon orer ifferential equations:
More information1 Boas, p. 643, problem (b)
Physics 6C Solutions to Homework Set #6 Fall Boas, p. 643, problem 3.5-3b Fin the steay-state temperature istribution in a soli cyliner of height H an raius a if the top an curve surfaces are hel at an
More information12 th Annual Johns Hopkins Math Tournament Saturday, February 19, 2011
1 th Annual Johns Hopkins Math Tournament Saturay, February 19, 011 Geometry Subject Test 1. [105] Let D x,y enote the half-isk of raius 1 with its curve bounary externally tangent to the unit circle at
More informationShort Intro to Coordinate Transformation
Short Intro to Coorinate Transformation 1 A Vector A vector can basically be seen as an arrow in space pointing in a specific irection with a specific length. The following problem arises: How o we represent
More informationPure Further Mathematics 1. Revision Notes
Pure Further Mathematics Revision Notes June 20 2 FP JUNE 20 SDB Further Pure Complex Numbers... 3 Definitions an arithmetical operations... 3 Complex conjugate... 3 Properties... 3 Complex number plane,
More informationDay 4: Motion Along a Curve Vectors
Day 4: Motion Along a Curve Vectors I give my stuents the following list of terms an formulas to know. Parametric Equations, Vectors, an Calculus Terms an Formulas to Know: If a smooth curve C is given
More informationMark Scheme (Results) Summer 2008
Mark (Results) Summer 8 GCE GCE Mathematics (7/) Mark Eecel Limite. Registere in Englan an Wales No. 97 Registere Office: One9 High Holborn, Lonon WCV 7BH 7 Further Pure FP Mark Question. cos. (.8 ) Ma
More informationMath 1B, lecture 8: Integration by parts
Math B, lecture 8: Integration by parts Nathan Pflueger 23 September 2 Introuction Integration by parts, similarly to integration by substitution, reverses a well-known technique of ifferentiation an explores
More information1.4.3 Elementary solutions to Laplace s equation in the spherical coordinates (Axially symmetric cases) (Griffiths 3.3.2)
1.4.3 Elementary solutions to Laplace s equation in the spherical coorinates (Axially symmetric cases) (Griffiths 3.3.) In the spherical coorinates (r, θ, φ), the Laplace s equation takes the following
More informationMathematics. Circles. hsn.uk.net. Higher. Contents. Circles 1. CfE Edition
Higher Mathematics Contents 1 1 Representing a Circle A 1 Testing a Point A 3 The General Equation of a Circle A 4 Intersection of a Line an a Circle A 4 5 Tangents to A 5 6 Equations of Tangents to A
More information23 Implicit differentiation
23 Implicit ifferentiation 23.1 Statement The equation y = x 2 + 3x + 1 expresses a relationship between the quantities x an y. If a value of x is given, then a corresponing value of y is etermine. For
More information12.11 Laplace s Equation in Cylindrical and
SEC. 2. Laplace s Equation in Cylinrical an Spherical Coorinates. Potential 593 2. Laplace s Equation in Cylinrical an Spherical Coorinates. Potential One of the most important PDEs in physics an engineering
More informationCHAPTER 1. Chapter 1 Page 1.1. Problem 1.1: (a) Because the system is conservative, ΔE = 0 and ΔK = ΔU. G m 2. M kg.
Chapter Page. CHAPTER Problem.: (a) Because the system is conservative, ΔE = 0 an ΔK = ΔU M 5.970 4 kg G 6.670 m newton R 6.370 6 m kg ΔK= v e = MmG = Mm G r R r=r so, v e M G v e.84 km R sec (b) A circular
More informationG j dq i + G j. q i. = a jt. and
Lagrange Multipliers Wenesay, 8 September 011 Sometimes it is convenient to use reunant coorinates, an to effect the variation of the action consistent with the constraints via the metho of Lagrange unetermine
More informationThe derivative of a function f(x) is another function, defined in terms of a limiting expression: f(x + δx) f(x)
Y. D. Chong (2016) MH2801: Complex Methos for the Sciences 1. Derivatives The erivative of a function f(x) is another function, efine in terms of a limiting expression: f (x) f (x) lim x δx 0 f(x + δx)
More informationSection 7.2. The Calculus of Complex Functions
Section 7.2 The Calculus of Complex Functions In this section we will iscuss limits, continuity, ifferentiation, Taylor series in the context of functions which take on complex values. Moreover, we will
More informationALGEBRAIC LONG DIVISION
QUESTIONS: 2014; 2c 2013; 1c ALGEBRAIC LONG DIVISION x + n ax 3 + bx 2 + cx +d Used to find factors and remainders of functions for instance 2x 3 + 9x 2 + 8x + p This process is useful for finding factors
More informationUnit #4 - Inverse Trig, Interpreting Derivatives, Newton s Method
Unit #4 - Inverse Trig, Interpreting Derivatives, Newton s Metho Some problems an solutions selecte or aapte from Hughes-Hallett Calculus. Computing Inverse Trig Derivatives. Starting with the inverse
More informationMath 1272 Solutions for Spring 2005 Final Exam. asked to find the limit of the sequence. This is equivalent to evaluating lim. lim.
Math 7 Solutions for Spring 5 Final Exam ) We are gien an infinite sequence for which the general term is a n 3 + 5n n + n an are 3 + 5n aske to fin the limit of the sequence. This is equialent to ealuating
More informationAnalytic Scaling Formulas for Crossed Laser Acceleration in Vacuum
October 6, 4 ARDB Note Analytic Scaling Formulas for Crosse Laser Acceleration in Vacuum Robert J. Noble Stanfor Linear Accelerator Center, Stanfor University 575 San Hill Roa, Menlo Park, California 945
More informationPhysics 2212 K Quiz #2 Solutions Summer 2016
Physics 1 K Quiz # Solutions Summer 016 I. (18 points) A positron has the same mass as an electron, but has opposite charge. Consier a positron an an electron at rest, separate by a istance = 1.0 nm. What
More informationMATHEMATICS C1-C4 and FP1-FP3
MS WELSH JOINT EDUCATION COMMITTEE. CYD-BWYLLGOR ADDYSG CYMRU General Certificate of Eucation Avance Subsiiary/Avance Tystysgrif Aysg Gyffreinol Uwch Gyfrannol/Uwch MARKING SCHEMES SUMMER 6 MATHEMATICS
More informationExam 2 Review Solutions
Exam Review Solutions 1. True or False, an explain: (a) There exists a function f with continuous secon partial erivatives such that f x (x, y) = x + y f y = x y False. If the function has continuous secon
More informationMath 1271 Solutions for Fall 2005 Final Exam
Math 7 Solutions for Fall 5 Final Eam ) Since the equation + y = e y cannot be rearrange algebraically in orer to write y as an eplicit function of, we must instea ifferentiate this relation implicitly
More informationMultivariable Calculus: Chapter 13: Topic Guide and Formulas (pgs ) * line segment notation above a variable indicates vector
Multivariable Calculus: Chapter 13: Topic Guie an Formulas (pgs 800 851) * line segment notation above a variable inicates vector The 3D Coorinate System: Distance Formula: (x 2 x ) 2 1 + ( y ) ) 2 y 2
More informationand from it produce the action integral whose variation we set to zero:
Lagrange Multipliers Monay, 6 September 01 Sometimes it is convenient to use reunant coorinates, an to effect the variation of the action consistent with the constraints via the metho of Lagrange unetermine
More informationHomework 7 Due 18 November at 6:00 pm
Homework 7 Due 18 November at 6:00 pm 1. Maxwell s Equations Quasi-statics o a An air core, N turn, cylinrical solenoi of length an raius a, carries a current I Io cos t. a. Using Ampere s Law, etermine
More informationHyperbolic Systems of Equations Posed on Erroneous Curved Domains
Hyperbolic Systems of Equations Pose on Erroneous Curve Domains Jan Norström a, Samira Nikkar b a Department of Mathematics, Computational Mathematics, Linköping University, SE-58 83 Linköping, Sween (
More informationChapter 2 Lagrangian Modeling
Chapter 2 Lagrangian Moeling The basic laws of physics are use to moel every system whether it is electrical, mechanical, hyraulic, or any other energy omain. In mechanics, Newton s laws of motion provie
More informationEquations of lines in
Roberto s Notes on Linear Algebra Chapter 6: Lines, planes an other straight objects Section 1 Equations of lines in What ou nee to know alrea: The ot prouct. The corresponence between equations an graphs.
More informationTutorial Test 5 2D welding robot
Tutorial Test 5 D weling robot Phys 70: Planar rigi boy ynamics The problem statement is appene at the en of the reference solution. June 19, 015 Begin: 10:00 am En: 11:30 am Duration: 90 min Solution.
More informationExercise 1. Exercise 2.
Exercise. Magnitue Galaxy ID Ultraviolet Green Re Infrare A Infrare B 9707296462088.56 5.47 5.4 4.75 4.75 97086278435442.6.33 5.36 4.84 4.58 2255030735995063.64.8 5.88 5.48 5.4 56877420209795 9.52.6.54.08
More informationChapter 5 Trigonometric Functions of Angles
Chapter 5 Trigonometric Functions of Angles Section 3 Points on Circles Using Sine and Cosine Signs Signs I Signs (+, +) I Signs II (+, +) I Signs II (, +) (+, +) I Signs II (, +) (+, +) I III Signs II
More informationAppendix: Proof of Spatial Derivative of Clear Raindrop
Appenix: Proof of Spatial erivative of Clear Rainrop Shaoi You Robby T. Tan The University of Tokyo {yous,rei,ki}@cvl.iis.u-tokyo.ac.jp Rei Kawakami Katsushi Ikeuchi Utrecht University R.T.Tan@uu.nl Layout
More informationSolving the Schrödinger Equation for the 1 Electron Atom (Hydrogen-Like)
Stockton Univeristy Chemistry Program, School of Natural Sciences an Mathematics 101 Vera King Farris Dr, Galloway, NJ CHEM 340: Physical Chemistry II Solving the Schröinger Equation for the 1 Electron
More informationMath Notes on differentials, the Chain Rule, gradients, directional derivative, and normal vectors
Math 18.02 Notes on ifferentials, the Chain Rule, graients, irectional erivative, an normal vectors Tangent plane an linear approximation We efine the partial erivatives of f( xy, ) as follows: f f( x+
More informationAssignment 1. g i (x 1,..., x n ) dx i = 0. i=1
Assignment 1 Golstein 1.4 The equations of motion for the rolling isk are special cases of general linear ifferential equations of constraint of the form g i (x 1,..., x n x i = 0. i=1 A constraint conition
More informationG4003 Advanced Mechanics 1. We already saw that if q is a cyclic variable, the associated conjugate momentum is conserved, L = const.
G4003 Avance Mechanics 1 The Noether theorem We alreay saw that if q is a cyclic variable, the associate conjugate momentum is conserve, q = 0 p q = const. (1) This is the simplest incarnation of Noether
More information2.5 SOME APPLICATIONS OF THE CHAIN RULE
2.5 SOME APPLICATIONS OF THE CHAIN RULE The Chain Rule will help us etermine the erivatives of logarithms an exponential functions a x. We will also use it to answer some applie questions an to fin slopes
More informationCalculus I Sec 2 Practice Test Problems for Chapter 4 Page 1 of 10
Calculus I Sec 2 Practice Test Problems for Chapter 4 Page 1 of 10 This is a set of practice test problems for Chapter 4. This is in no way an inclusive set of problems there can be other types of problems
More informationVersion 1.0. klm. General Certificate of Education June Mathematics. Further Pure 3. Mark Scheme
Version.0 klm General Certificate of Eucation June 00 Mathematics MFP Further Pure Mark Scheme Mark schemes are prepare by the Principal Eaminer an consiere, together with the relevant questions, by a
More information1 Lecture 20: Implicit differentiation
Lecture 20: Implicit ifferentiation. Outline The technique of implicit ifferentiation Tangent lines to a circle Derivatives of inverse functions by implicit ifferentiation Examples.2 Implicit ifferentiation
More information3-D FEM Modeling of fiber/matrix interface debonding in UD composites including surface effects
IOP Conference Series: Materials Science an Engineering 3-D FEM Moeling of fiber/matrix interface eboning in UD composites incluing surface effects To cite this article: A Pupurs an J Varna 2012 IOP Conf.
More informationBLOW-UP FORMULAS FOR ( 2)-SPHERES
BLOW-UP FORMULAS FOR 2)-SPHERES ROGIER BRUSSEE In this note we give a universal formula for the evaluation of the Donalson polynomials on 2)-spheres, i.e. smooth spheres of selfintersection 2. Note that
More informationExam 1 Review SOLUTIONS
1. True or False (and give a short reason): Exam 1 Review SOLUTIONS (a) If the parametric curve x = f(t), y = g(t) satisfies g (1) = 0, then it has a horizontal tangent line when t = 1. FALSE: To make
More informationCalculus 4 Final Exam Review / Winter 2009
Calculus 4 Final Eam Review / Winter 9 (.) Set-up an iterate triple integral for the volume of the soli enclose between the surfaces: 4 an 4. DO NOT EVALUATE THE INTEGRAL! [Hint: The graphs of both surfaces
More informationThe choice of origin, axes, and length is completely arbitrary.
Polar Coordinates There are many ways to mark points in the plane or in 3-dim space for purposes of navigation. In the familiar rectangular coordinate system, a point is chosen as the origin and a perpendicular
More informationTutorial 1 Differentiation
Tutorial 1 Differentiation What is Calculus? Calculus 微積分 Differential calculus Differentiation 微分 y lim 0 f f The relation of very small changes of ifferent quantities f f y y Integral calculus Integration
More informationDifferentiation ( , 9.5)
Chapter 2 Differentiation (8.1 8.3, 9.5) 2.1 Rate of Change (8.2.1 5) Recall that the equation of a straight line can be written as y = mx + c, where m is the slope or graient of the line, an c is the
More informationVectors in two dimensions
Vectors in two imensions Until now, we have been working in one imension only The main reason for this is to become familiar with the main physical ieas like Newton s secon law, without the aitional complication
More informationSome functions and their derivatives
Chapter Some functions an their erivatives. Derivative of x n for integer n Recall, from eqn (.6), for y = f (x), Also recall that, for integer n, Hence, if y = x n then y x = lim δx 0 (a + b) n = a n
More informationPHY 114 Summer 2009 Final Exam Solutions
PHY 4 Summer 009 Final Exam Solutions Conceptual Question : A spherical rubber balloon has a charge uniformly istribute over its surface As the balloon is inflate, how oes the electric fiel E vary (a)
More informationPMT. Version 1.0. General Certificate of Education (A-level) January Mathematics MFP3. (Specification 6360) Further Pure 3.
Version.0 General Certificate of Eucation (A-level) January 0 Mathematics MFP (Specification 660) Further Pure Mark Scheme Mark schemes are prepare by the Principal Examiner an consiere, together with
More informationAn Approach for Design of Multi-element USBL Systems
An Approach for Design of Multi-element USBL Systems MIKHAIL ARKHIPOV Department of Postgrauate Stuies Technological University of the Mixteca Carretera a Acatlima Km. 2.5 Huajuapan e Leon Oaxaca 69000
More informationImplicit Differentiation
Implicit Differentiation Implicit Differentiation Using the Chain Rule In the previous section we focuse on the erivatives of composites an saw that THEOREM 20 (Chain Rule) Suppose that u = g(x) is ifferentiable
More informationMath 115 Section 018 Course Note
Course Note 1 General Functions Definition 1.1. A function is a rule that takes certain numbers as inputs an assigns to each a efinite output number. The set of all input numbers is calle the omain of
More informationPhysics 2212 GJ Quiz #4 Solutions Fall 2015
Physics 2212 GJ Quiz #4 Solutions Fall 215 I. (17 points) The magnetic fiel at point P ue to a current through the wire is 5. µt into the page. The curve portion of the wire is a semicircle of raius 2.
More informationTOEPLITZ AND POSITIVE SEMIDEFINITE COMPLETION PROBLEM FOR CYCLE GRAPH
English NUMERICAL MATHEMATICS Vol14, No1 Series A Journal of Chinese Universities Feb 2005 TOEPLITZ AND POSITIVE SEMIDEFINITE COMPLETION PROBLEM FOR CYCLE GRAPH He Ming( Λ) Michael K Ng(Ξ ) Abstract We
More informationFree rotation of a rigid body 1 D. E. Soper 2 University of Oregon Physics 611, Theoretical Mechanics 5 November 2012
Free rotation of a rigi boy 1 D. E. Soper 2 University of Oregon Physics 611, Theoretical Mechanics 5 November 2012 1 Introuction In this section, we escribe the motion of a rigi boy that is free to rotate
More information3.7 Implicit Differentiation -- A Brief Introduction -- Student Notes
Fin these erivatives of these functions: y.7 Implicit Differentiation -- A Brief Introuction -- Stuent Notes tan y sin tan = sin y e = e = Write the inverses of these functions: y tan y sin How woul we
More informationBoth the ASME B and the draft VDI/VDE 2617 have strengths and
Choosing Test Positions for Laser Tracker Evaluation an Future Stanars Development ala Muralikrishnan 1, Daniel Sawyer 1, Christopher lackburn 1, Steven Phillips 1, Craig Shakarji 1, E Morse 2, an Robert
More informationarxiv: v1 [math.dg] 5 Dec 2017
INTRINSIC REPRESENTATION CURVES arxiv:7.946v [ath.dg] 5 Dec 7 HECTOR EFREN GUERRERO MORA This paper is eicate to y brother. Abstract. The purpose of this article is to fin a faily of curves paraetrize
More informationDepartment of Physics University of Maryland College Park, Maryland. Fall 2005 Final Exam Dec. 16, u 2 dt )2, L = m u 2 d θ, ( d θ
Department of Physics University of arylan College Park, arylan PHYSICS 4 Prof. S. J. Gates Fall 5 Final Exam Dec. 6, 5 This is a OPEN book examination. Rea the entire examination before you begin to work.
More informationChapter 4. Electrostatics of Macroscopic Media
Chapter 4. Electrostatics of Macroscopic Meia 4.1 Multipole Expansion Approximate potentials at large istances 3 x' x' (x') x x' x x Fig 4.1 We consier the potential in the far-fiel region (see Fig. 4.1
More informationUnit #6 - Families of Functions, Taylor Polynomials, l Hopital s Rule
Unit # - Families of Functions, Taylor Polynomials, l Hopital s Rule Some problems an solutions selecte or aapte from Hughes-Hallett Calculus. Critical Points. Consier the function f) = 54 +. b) a) Fin
More informationStatics. There are four fundamental quantities which occur in mechanics:
Statics Mechanics isabranchofphysicsinwhichwestuythestate of rest or motion of boies subject to the action of forces. It can be ivie into two logical parts: statics, where we investigate the equilibrium
More informationLinear First-Order Equations
5 Linear First-Orer Equations Linear first-orer ifferential equations make up another important class of ifferential equations that commonly arise in applications an are relatively easy to solve (in theory)
More informationfv = ikφ n (11.1) + fu n = y v n iσ iku n + gh n. (11.3) n
Chapter 11 Rossby waves Supplemental reaing: Pelosky 1 (1979), sections 3.1 3 11.1 Shallow water equations When consiering the general problem of linearize oscillations in a static, arbitrarily stratifie
More information10.1 Curves Defined by Parametric Equation
10.1 Curves Defined by Parametric Equation 1. Imagine that a particle moves along the curve C shown below. It is impossible to describe C by an equation of the form y = f (x) because C fails the Vertical
More informationMath Review for Physical Chemistry
Chemistry 362 Spring 27 Dr. Jean M. Stanar January 25, 27 Math Review for Physical Chemistry I. Algebra an Trigonometry A. Logarithms an Exponentials General rules for logarithms These rules, except where
More informationMath 300 Winter 2011 Advanced Boundary Value Problems I. Bessel s Equation and Bessel Functions
Math 3 Winter 2 Avance Bounary Value Problems I Bessel s Equation an Bessel Functions Department of Mathematical an Statistical Sciences University of Alberta Bessel s Equation an Bessel Functions We use
More informationQubit channels that achieve capacity with two states
Qubit channels that achieve capacity with two states Dominic W. Berry Department of Physics, The University of Queenslan, Brisbane, Queenslan 4072, Australia Receive 22 December 2004; publishe 22 March
More informationLecture Wise Questions from 23 to 45 By Virtualians.pk. Q105. What is the impact of double integration in finding out the area and volume of Regions?
Lecture Wise Questions from 23 to 45 By Virtualians.pk Q105. What is the impact of double integration in finding out the area and volume of Regions? Ans: It has very important contribution in finding the
More informationCreated by T. Madas LINE INTEGRALS. Created by T. Madas
LINE INTEGRALS LINE INTEGRALS IN 2 DIMENSIONAL CARTESIAN COORDINATES Question 1 Evaluate the integral ( x + 2y) dx, C where C is the path along the curve with equation y 2 = x + 1, from ( ) 0,1 to ( )
More informationMath Implicit Differentiation. We have discovered (and proved) formulas for finding derivatives of functions like
Math 400 3.5 Implicit Differentiation Name We have iscovere (an prove) formulas for fining erivatives of functions like f x x 3x 4x. 3 This amounts to fining y for 3 y x 3x 4x. Notice that in this case,
More informationSection 2.7 Derivatives of powers of functions
Section 2.7 Derivatives of powers of functions (3/19/08) Overview: In this section we iscuss the Chain Rule formula for the erivatives of composite functions that are forme by taking powers of other functions.
More informationGoldstein Chapter 1 Exercises
Golstein Chapter 1 Exercises Michael Goo July 17, 2004 1 Exercises 11. Consier a uniform thin isk that rolls without slipping on a horizontal plane. A horizontal force is applie to the center of the isk
More information1 Applications of the Chain Rule
November 7, 08 MAT86 Week 6 Justin Ko Applications of the Chain Rule We go over several eamples of applications of the chain rule to compute erivatives of more complicate functions. Chain Rule: If z =
More informationThe Three-dimensional Schödinger Equation
The Three-imensional Schöinger Equation R. L. Herman November 7, 016 Schröinger Equation in Spherical Coorinates We seek to solve the Schröinger equation with spherical symmetry using the metho of separation
More informationSection 8.4 Plane Curves and Parametric Equations
Section 8.4 Plane Curves and Parametric Equations Suppose that x and y are both given as functions of a third variable t (called a parameter) by the equations x = f(t), y = g(t) (called parametric equations).
More informationPhysics Courseware Electromagnetism
Phsics Courseware Electromagnetism Electric potential Problem.- a) Fin the electric potential at points P, P an P prouce b the three charges Q, Q an Q. b) Are there an points where the electric potential
More informationCalculus of Variations
16.323 Lecture 5 Calculus of Variations Calculus of Variations Most books cover this material well, but Kirk Chapter 4 oes a particularly nice job. x(t) x* x*+ αδx (1) x*- αδx (1) αδx (1) αδx (1) t f t
More informationIntroduction to variational calculus: Lecture notes 1
October 10, 2006 Introuction to variational calculus: Lecture notes 1 Ewin Langmann Mathematical Physics, KTH Physics, AlbaNova, SE-106 91 Stockholm, Sween Abstract I give an informal summary of variational
More information4. Important theorems in quantum mechanics
TFY4215 Kjemisk fysikk og kvantemekanikk - Tillegg 4 1 TILLEGG 4 4. Important theorems in quantum mechanics Before attacking three-imensional potentials in the next chapter, we shall in chapter 4 of this
More informationRFSS: Lecture 4 Alpha Decay
RFSS: Lecture 4 Alpha Decay Reaings Nuclear an Raiochemistry: Chapter 3 Moern Nuclear Chemistry: Chapter 7 Energetics of Alpha Decay Geiger Nuttall base theory Theory of Alpha Decay Hinrance Factors Different
More informationDiagonalization of Matrices Dr. E. Jacobs
Diagonalization of Matrices Dr. E. Jacobs One of the very interesting lessons in this course is how certain algebraic techniques can be use to solve ifferential equations. The purpose of these notes is
More informationExam #2, Electrostatics
Exam #2, Electrostatics Prof. Maurik Holtrop Department of Physics PHYS 408 University of New Hampshire March 27 th, 2003 Name: Stuent # NOTE: There are 5 questions. You have until 9 pm to finish. You
More informationProblem Set 2: Solutions
UNIVERSITY OF ALABAMA Department of Physics an Astronomy PH 102 / LeClair Summer II 2010 Problem Set 2: Solutions 1. The en of a charge rubber ro will attract small pellets of Styrofoam that, having mae
More informationVIBRATIONS OF A CIRCULAR MEMBRANE
VIBRATIONS OF A CIRCULAR MEMBRANE RAM EKSTROM. Solving the wave equation on the isk The ynamics of vibrations of a two-imensional isk D are given by the wave equation..) c 2 u = u tt, together with the
More informationOptimization Notes. Note: Any material in red you will need to have memorized verbatim (more or less) for tests, quizzes, and the final exam.
MATH 2250 Calculus I Date: October 5, 2017 Eric Perkerson Optimization Notes 1 Chapter 4 Note: Any material in re you will nee to have memorize verbatim (more or less) for tests, quizzes, an the final
More informationFINAL EXAM 1 SOLUTIONS Below is the graph of a function f(x). From the graph, read off the value (if any) of the following limits: x 1 +
FINAL EXAM 1 SOLUTIONS 2011 1. Below is the graph of a function f(x). From the graph, rea off the value (if any) of the following its: x 1 = 0 f(x) x 1 + = 1 f(x) x 0 = x 0 + = 0 x 1 = 1 1 2 FINAL EXAM
More informationSTUDENT S COMPANIONS IN BASIC MATH: THE FOURTH. Trigonometric Functions
STUDENT S COMPANIONS IN BASIC MATH: THE FOURTH Trigonometric Functions Let me quote a few sentences at the beginning of the preface to a book by Davi Kammler entitle A First Course in Fourier Analysis
More informationImplicit Differentiation
Implicit Differentiation Thus far, the functions we have been concerne with have been efine explicitly. A function is efine explicitly if the output is given irectly in terms of the input. For instance,
More informationAgmon Kolmogorov Inequalities on l 2 (Z d )
Journal of Mathematics Research; Vol. 6, No. ; 04 ISSN 96-9795 E-ISSN 96-9809 Publishe by Canaian Center of Science an Eucation Agmon Kolmogorov Inequalities on l (Z ) Arman Sahovic Mathematics Department,
More information) R 2. 2tR 2 R 2 +t 2 y = t2 R 2. x = R y, t 2 +R 2 R. 2uR2 R 2 +u 2 +v 2 2vR2. x = y = R z v = Ry, R z. z = u2 +v 2 R 2.
Homework. Solutions 1 a Write own explicit formulae expressing stereographic coorinates for n-imensional sphere x 1 +... + x n+1 of raius via coorinates x 1,..., x n+1 an vice versa. For simplicit ou ma
More informationLecture D16-2D Rigid Body Kinematics
J. Peraire 16.07 Dynamics Fall 2004 Version 1.2 Lecture D16-2D Rigid Body Kinematics In this lecture, we will start from the general relative motion concepts introduced in lectures D11 and D12, and then
More information