1. Find the equation of a line passing through point (5, -2) with slope ¾. (State your answer in slope-int. form)

Size: px
Start display at page:

Download "1. Find the equation of a line passing through point (5, -2) with slope ¾. (State your answer in slope-int. form)"

Transcription

1 INTRO TO CALCULUS REVIEW FINAL EXAM NAME: DATE: A. Equations of Lines (Review Chapter) y = m + b (Slope-Intercept Form) A + By = C (Stanar Form) y y = m( ) (Point-Slope Form). Fin the equation of a line passing through point (5, -) with slope ¾. (State your answer in slope-int. form). Fin the equation of the line passing through the points (-, ) an (, -4). (State your answer in stanar form). Fin an equation for a line parallel an an equation for a line perpenicular to the line 4 y = an passing through the point (, 4). Write your answers in stanar form. B. Solving Equations (Review Chapter).) Quaratics try to solve by factoring or quaratic formula..) Rational Epressions multiply each term by the LCD to einate fractions..) Raical Equations Isolate the raical first, then uno root by squaring both sies ( ), cubing both sies ( ), etc. Solve each equation for all real values of = = = = + ( + )( ) = 7 C. Domain an Range (Review Chapter) Domain the set of -values for a relation or function. Range the set of y -values for a relation or function. Determine the omain an range for each. 9. = 0. =. + = + +

2 D. Limits (Chapter ) To evaluate its try:.) Direct Substitution.) Test values that approach..) Try to factor an cancel any common factors E. The Derivative (Chapter ).) Definition of the Derivative f '( ) = Δ 0 f ( + Δ) Δ.) Power Rule: f() = a n f () = na n-.) Prouct Rule: f() = g() h() f () = g() h () + h() g () 4.) Quotient Rule: f() = g( ) h( ) f () = h( ) g' ( ) g( ) h' ( ) [ h( ) ] 5.) (sin ) = cos 6.) (cos ) = sin *In orer for a function to have a erivative on any open interval (a, b), then the function must be continuous on (a, b) an not have any sharp points on (a, b). E: Function is not ifferentiable at = (Sharp point) Function is not ifferentiable at = 0 (Not continuous.)

3 8. Fin f () using the efinition of the erivative. f() = + For #9 0, fin the erivative using any metho. 9. = 0. =. + =. =. f() = ( )( + + ) 4. f() = cos( ) 5. f() = sin + sin 6. f() = cos 7. + y = y + y = 6 9. y = cos (4) 0. f () =. Fin f () if f() = + sin. Fin the slope of the line tangent to the curve f() = ( )( ) at (0, ).. Fin the equation of the line tangent to the curve = at (, 4)

4 4. Fin the point(s) where the graph of f() = + has a tangent line with slope = 0. F. Etrema an Critical Values (Chapter ) First Derivative Test: If f () > 0, the function is increasing. If f () < 0, the function is ecreasing. If f () = 0, the function is constant. Secon Derivative Test: : If f () > 0, the function is concave up. If f () < 0, the function is concave own. If f () = 0, the function is linear (no concavity). Asymptotes: a.) Vertical Asymptotes Set enominator = 0 an solve for. coefficient of highest in num. b.) Horizontal Asymptotes Fin highest power of. HA = y = coefficient of highest in en. c.) Oblique (Slant) Asymptotes) Long ivision an rop the remainer. (Only occurs if the egree of the numerator is eactly one larger than the egree of the enominator.) 5. Determine the intervals where f() = ¼ is increasing. 6. Fin all mas, mins, an inflection points of f() = Determine the intervals where f() = is concave own. 8. Fin all asymptotes. a.) = b.) = Fin the ifferential, y. a.) y = b.) y = sin +

5 G. Integration (Chapter 4) Rules for Integration: n+ n. = + C n + n. k = k n. sin = cos + C 4. cos = sin + C 5. = F( b) F( a) b a Problems. Evaluate each integral ( + ) sin cos 44. ( 4 ) 45. ( + ) 0 cos 46. sin 47. sin

6 H. Logarithmic an Eponential Functions (Chapter 5) Properties of Logarithms ln() = 0 log a = 0 lnab = lna + lnb logab = loga + logb ln a = lna lnb b ln(a n ) = nlna loga n = nloga log a = loga logb b Derivative of ln: (ln ) = has to be greater than 0 (lnu) = u u must be greater than 0 u Integral of ln: = ln + c u u = u = lnu + c u Derivative of e (e ) = e (eu ) = e u u Integrative e e = e + c e u u = e u + c Derivative for base other than e (a ) = (lna)a (log ) = a (ln a) u (au ) = (lna)a u (log u) = u a (ln a)u Integral of base other than e a = a lna + c a u u = au lna + c

7 Fin the erivative. f () = ln( + ). f () = ln( +) + ln( 4). f () = ln ( + 4) ( ) 4. f () = ln 5. f () = e 4 6. f () = e 7. f () = 5 8. f () = f () = log ( ) 0. f () = log 4 (6 + ). f () = log 4 +. f () = 0 Fin the Integral. e 5 (6) sin + cos

8 ( +.5) 7. e + ( +) ( )

THEOREM: THE CONSTANT RULE

THEOREM: THE CONSTANT RULE MATH /MYERS/ALL FORMULAS ON THIS REVIEW MUST BE MEMORIZED! DERIVATIVE REVIEW THEOREM: THE CONSTANT RULE The erivative of a constant function is zero. That is, if c is a real number, then c 0 Eample 1:

More information

Math 1271 Solutions for Fall 2005 Final Exam

Math 1271 Solutions for Fall 2005 Final Exam Math 7 Solutions for Fall 5 Final Eam ) Since the equation + y = e y cannot be rearrange algebraically in orer to write y as an eplicit function of, we must instea ifferentiate this relation implicitly

More information

102 Problems Calculus AB Students Should Know: Solutions. 18. product rule d. 19. d sin x. 20. chain rule d e 3x2) = e 3x2 ( 6x) = 6xe 3x2

102 Problems Calculus AB Students Should Know: Solutions. 18. product rule d. 19. d sin x. 20. chain rule d e 3x2) = e 3x2 ( 6x) = 6xe 3x2 Problems Calculus AB Stuents Shoul Know: Solutions. + ) = + =. chain rule ) e = e = e. ) =. ) = ln.. + + ) = + = = +. ln ) =. ) log ) =. sin ) = cos. cos ) = sin. tan ) = sec. cot ) = csc. sec ) = sec

More information

Section The Chain Rule and Implicit Differentiation with Application on Derivative of Logarithm Functions

Section The Chain Rule and Implicit Differentiation with Application on Derivative of Logarithm Functions Section 3.4-3.6 The Chain Rule an Implicit Differentiation with Application on Derivative of Logarithm Functions Ruipeng Shen September 3r, 5th Ruipeng Shen MATH 1ZA3 September 3r, 5th 1 / 3 The Chain

More information

Exam 3 Review. Lesson 19: Concavity, Inflection Points, and the Second Derivative Test. Lesson 20: Absolute Extrema on an Interval

Exam 3 Review. Lesson 19: Concavity, Inflection Points, and the Second Derivative Test. Lesson 20: Absolute Extrema on an Interval Exam 3 Review Lessons 17-18: Relative Extrema, Critical Numbers, an First Derivative Test (from exam 2 review neee for curve sketching) Critical Numbers: where the erivative of a function is zero or unefine.

More information

Final Exam Study Guide and Practice Problems Solutions

Final Exam Study Guide and Practice Problems Solutions Final Exam Stuy Guie an Practice Problems Solutions Note: These problems are just some of the types of problems that might appear on the exam. However, to fully prepare for the exam, in aition to making

More information

Unit #6 - Families of Functions, Taylor Polynomials, l Hopital s Rule

Unit #6 - Families of Functions, Taylor Polynomials, l Hopital s Rule Unit # - Families of Functions, Taylor Polynomials, l Hopital s Rule Some problems an solutions selecte or aapte from Hughes-Hallett Calculus. Critical Points. Consier the function f) = 54 +. b) a) Fin

More information

A. Incorrect! The letter t does not appear in the expression of the given integral

A. Incorrect! The letter t does not appear in the expression of the given integral AP Physics C - Problem Drill 1: The Funamental Theorem of Calculus Question No. 1 of 1 Instruction: (1) Rea the problem statement an answer choices carefully () Work the problems on paper as neee (3) Question

More information

Flash Card Construction Instructions

Flash Card Construction Instructions Flash Car Construction Instructions *** THESE CARDS ARE FOR CALCULUS HONORS, AP CALCULUS AB AND AP CALCULUS BC. AP CALCULUS BC WILL HAVE ADDITIONAL CARDS FOR THE COURSE (IN A SEPARATE FILE). The left column

More information

Table of Contents Derivatives of Logarithms

Table of Contents Derivatives of Logarithms Derivatives of Logarithms- Table of Contents Derivatives of Logarithms Arithmetic Properties of Logarithms Derivatives of Logarithms Example Example 2 Example 3 Example 4 Logarithmic Differentiation Example

More information

(a 1 m. a n m = < a 1/N n

(a 1 m. a n m = < a 1/N n Notes on a an log a Mat 9 Fall 2004 Here is an approac to te eponential an logaritmic functions wic avois any use of integral calculus We use witout proof te eistence of certain limits an assume tat certain

More information

The Explicit Form of a Function

The Explicit Form of a Function Section 3 5 Implicit Differentiation The Eplicit Form of a Function The normal way we see function notation has f () on one sie of an equation an an epression in terms of on the other sie. We know the

More information

Lecture 4 : General Logarithms and Exponentials. a x = e x ln a, a > 0.

Lecture 4 : General Logarithms and Exponentials. a x = e x ln a, a > 0. For a > 0 an x any real number, we efine Lecture 4 : General Logarithms an Exponentials. a x = e x ln a, a > 0. The function a x is calle the exponential function with base a. Note that ln(a x ) = x ln

More information

The derivative of a constant function is 0. That is,

The derivative of a constant function is 0. That is, NOTES : DIFFERENTIATION RULES Name: LESSON. DERIVATIVE OF POLYNOMIALS AND EXPONENTIAL FUNCTIONS Date: Perio: Mrs. Nguyen s Initial: Eample : Prove f ( ) 4 is not ifferentiable at. Practice Problems: Fin

More information

x = c of N if the limit of f (x) = L and the right-handed limit lim f ( x)

x = c of N if the limit of f (x) = L and the right-handed limit lim f ( x) Limit We say the limit of f () as approaches c equals L an write, lim L. One-Sie Limits (Left an Right-Hane Limits) Suppose a function f is efine near but not necessarily at We say that f has a left-hane

More information

DERIVATIVES: LAWS OF DIFFERENTIATION MR. VELAZQUEZ AP CALCULUS

DERIVATIVES: LAWS OF DIFFERENTIATION MR. VELAZQUEZ AP CALCULUS DERIVATIVES: LAWS OF DIFFERENTIATION MR. VELAZQUEZ AP CALCULUS THE DERIVATIVE AS A FUNCTION f x = lim h 0 f x + h f(x) h Last class we examine the limit of the ifference quotient at a specific x as h 0,

More information

Math 180, Exam 2, Fall 2012 Problem 1 Solution. (a) The derivative is computed using the Chain Rule twice. 1 2 x x

Math 180, Exam 2, Fall 2012 Problem 1 Solution. (a) The derivative is computed using the Chain Rule twice. 1 2 x x . Fin erivatives of the following functions: (a) f() = tan ( 2 + ) ( ) 2 (b) f() = ln 2 + (c) f() = sin() Solution: Math 80, Eam 2, Fall 202 Problem Solution (a) The erivative is compute using the Chain

More information

The Natural Logarithm

The Natural Logarithm The Natural Logarithm -28-208 In earlier courses, you may have seen logarithms efine in terms of raising bases to powers. For eample, log 2 8 = 3 because 2 3 = 8. In those terms, the natural logarithm

More information

Make graph of g by adding c to the y-values. on the graph of f by c. multiplying the y-values. even-degree polynomial. graph goes up on both sides

Make graph of g by adding c to the y-values. on the graph of f by c. multiplying the y-values. even-degree polynomial. graph goes up on both sides Reference 1: Transformations of Graphs an En Behavior of Polynomial Graphs Transformations of graphs aitive constant constant on the outsie g(x) = + c Make graph of g by aing c to the y-values on the graph

More information

Chapter 1. Functions, Graphs, and Limits

Chapter 1. Functions, Graphs, and Limits Review for Final Exam Lecturer: Sangwook Kim Office : Science & Tech I, 226D math.gmu.eu/ skim22 Chapter 1. Functions, Graphs, an Limits A function is a rule that assigns to each objects in a set A exactly

More information

Inverse Functions. Review from Last Time: The Derivative of y = ln x. [ln. Last time we saw that

Inverse Functions. Review from Last Time: The Derivative of y = ln x. [ln. Last time we saw that Inverse Functions Review from Last Time: The Derivative of y = ln Last time we saw that THEOREM 22.0.. The natural log function is ifferentiable an More generally, the chain rule version is ln ) =. ln

More information

x f(x) x f(x) approaching 1 approaching 0.5 approaching 1 approaching 0.

x f(x) x f(x) approaching 1 approaching 0.5 approaching 1 approaching 0. Engineering Mathematics 2 26 February 2014 Limits of functions Consier the function 1 f() = 1. The omain of this function is R + \ {1}. The function is not efine at 1. What happens when is close to 1?

More information

The derivative of a constant function is 0. That is,

The derivative of a constant function is 0. That is, NOTES 3: DIFFERENTIATION RULES Name: Date: Perio: LESSON 3. DERIVATIVE OF POLYNOMIALS AND EXPONENTIAL FUNCTIONS Eample : Prove f ( ) 6 is not ifferentiable at 4. Practice Problems: Fin f '( ) using the

More information

Math Honors Calculus I Final Examination, Fall Semester, 2013

Math Honors Calculus I Final Examination, Fall Semester, 2013 Math 2 - Honors Calculus I Final Eamination, Fall Semester, 2 Time Allowed: 2.5 Hours Total Marks:. (2 Marks) Find the following: ( (a) 2 ) sin 2. (b) + (ln 2)/(+ln ). (c) The 2-th Taylor polynomial centered

More information

x f(x) x f(x) approaching 1 approaching 0.5 approaching 1 approaching 0.

x f(x) x f(x) approaching 1 approaching 0.5 approaching 1 approaching 0. Engineering Mathematics 2 26 February 2014 Limits of functions Consier the function 1 f() = 1. The omain of this function is R + \ {1}. The function is not efine at 1. What happens when is close to 1?

More information

TOTAL NAME DATE PERIOD AP CALCULUS AB UNIT 4 ADVANCED DIFFERENTIATION TECHNIQUES DATE TOPIC ASSIGNMENT /6 10/8 10/9 10/10 X X X X 10/11 10/12

TOTAL NAME DATE PERIOD AP CALCULUS AB UNIT 4 ADVANCED DIFFERENTIATION TECHNIQUES DATE TOPIC ASSIGNMENT /6 10/8 10/9 10/10 X X X X 10/11 10/12 NAME DATE PERIOD AP CALCULUS AB UNIT ADVANCED DIFFERENTIATION TECHNIQUES DATE TOPIC ASSIGNMENT 0 0 0/6 0/8 0/9 0/0 X X X X 0/ 0/ 0/5 0/6 QUIZ X X X 0/7 0/8 0/9 0/ 0/ 0/ 0/5 UNIT EXAM X X X TOTAL AP Calculus

More information

The Explicit Form of a Function

The Explicit Form of a Function Section 3 5 Implicit Differentiation The Eplicit Form of a Function Function Notation requires that we state a function with f () on one sie of an equation an an epression in terms of on the other sie

More information

23 Implicit differentiation

23 Implicit differentiation 23 Implicit ifferentiation 23.1 Statement The equation y = x 2 + 3x + 1 expresses a relationship between the quantities x an y. If a value of x is given, then a corresponing value of y is etermine. For

More information

3.6. Implicit Differentiation. Implicitly Defined Functions

3.6. Implicit Differentiation. Implicitly Defined Functions 3.6 Implicit Differentiation 205 3.6 Implicit Differentiation 5 2 25 2 25 2 0 5 (3, ) Slope 3 FIGURE 3.36 The circle combines the graphs of two functions. The graph of 2 is the lower semicircle an passes

More information

Solutions to Practice Problems Tuesday, October 28, 2008

Solutions to Practice Problems Tuesday, October 28, 2008 Solutions to Practice Problems Tuesay, October 28, 2008 1. The graph of the function f is shown below. Figure 1: The graph of f(x) What is x 1 + f(x)? What is x 1 f(x)? An oes x 1 f(x) exist? If so, what

More information

Chapter 2 Derivatives

Chapter 2 Derivatives Chapter Derivatives Section. An Intuitive Introuction to Derivatives Consier a function: Slope function: Derivative, f ' For each, the slope of f is the height of f ' Where f has a horizontal tangent line,

More information

Calculus I Sec 2 Practice Test Problems for Chapter 4 Page 1 of 10

Calculus I Sec 2 Practice Test Problems for Chapter 4 Page 1 of 10 Calculus I Sec 2 Practice Test Problems for Chapter 4 Page 1 of 10 This is a set of practice test problems for Chapter 4. This is in no way an inclusive set of problems there can be other types of problems

More information

Solutions Exam 4 (Applications of Differentiation) 1. a. Applying the Quotient Rule we compute the derivative function of f as follows:

Solutions Exam 4 (Applications of Differentiation) 1. a. Applying the Quotient Rule we compute the derivative function of f as follows: MAT 4 Solutions Eam 4 (Applications of Differentiation) a Applying the Quotient Rule we compute the derivative function of f as follows: f () = 43 e 4 e (e ) = 43 4 e = 3 (4 ) e Hence f '( ) 0 for = 0

More information

ARAB ACADEMY FOR SCIENCE TECHNOLOGY AND MARITIME TRANSPORT

ARAB ACADEMY FOR SCIENCE TECHNOLOGY AND MARITIME TRANSPORT ARAB ACADEMY FOR SCIENCE TECHNOLOGY AND MARITIME TRANSPORT Course: Math For Engineering Winter 8 Lecture Notes By Dr. Mostafa Elogail Page Lecture [ Functions / Graphs of Rational Functions] Functions

More information

Math 210 Midterm #1 Review

Math 210 Midterm #1 Review Math 20 Miterm # Review This ocument is intene to be a rough outline of what you are expecte to have learne an retaine from this course to be prepare for the first miterm. : Functions Definition: A function

More information

Computing Derivatives Solutions

Computing Derivatives Solutions Stuent Stuy Session Solutions We have intentionally inclue more material than can be covere in most Stuent Stuy Sessions to account for groups that are able to answer the questions at a faster rate. Use

More information

Summer Mathematics Prep

Summer Mathematics Prep Summer Mathematics Prep Entering Calculus Chesterfield County Public Schools Department of Mathematics SOLUTIONS Domain and Range Domain: All Real Numbers Range: {y: y } Domain: { : } Range:{ y : y 0}

More information

d dx [xn ] = nx n 1. (1) dy dx = 4x4 1 = 4x 3. Theorem 1.3 (Derivative of a constant function). If f(x) = k and k is a constant, then f (x) = 0.

d dx [xn ] = nx n 1. (1) dy dx = 4x4 1 = 4x 3. Theorem 1.3 (Derivative of a constant function). If f(x) = k and k is a constant, then f (x) = 0. Calculus refresher Disclaimer: I claim no original content on this ocument, which is mostly a summary-rewrite of what any stanar college calculus book offers. (Here I ve use Calculus by Dennis Zill.) I

More information

Fall 2016: Calculus I Final

Fall 2016: Calculus I Final Answer the questions in the spaces provie on the question sheets. If you run out of room for an answer, continue on the back of the page. NO calculators or other electronic evices, books or notes are allowe

More information

Lecture 6: Calculus. In Song Kim. September 7, 2011

Lecture 6: Calculus. In Song Kim. September 7, 2011 Lecture 6: Calculus In Song Kim September 7, 20 Introuction to Differential Calculus In our previous lecture we came up with several ways to analyze functions. We saw previously that the slope of a linear

More information

Chapter 1 Overview: Review of Derivatives

Chapter 1 Overview: Review of Derivatives Chapter Overview: Review of Derivatives The purpose of this chapter is to review the how of ifferentiation. We will review all the erivative rules learne last year in PreCalculus. In the net several chapters,

More information

1 Lecture 20: Implicit differentiation

1 Lecture 20: Implicit differentiation Lecture 20: Implicit ifferentiation. Outline The technique of implicit ifferentiation Tangent lines to a circle Derivatives of inverse functions by implicit ifferentiation Examples.2 Implicit ifferentiation

More information

Derivatives and Its Application

Derivatives and Its Application Chapter 4 Derivatives an Its Application Contents 4.1 Definition an Properties of erivatives; basic rules; chain rules 3 4. Derivatives of Inverse Functions; Inverse Trigonometric Functions; Hyperbolic

More information

Differentiability, Computing Derivatives, Trig Review. Goals:

Differentiability, Computing Derivatives, Trig Review. Goals: Secants vs. Derivatives - Unit #3 : Goals: Differentiability, Computing Derivatives, Trig Review Determine when a function is ifferentiable at a point Relate the erivative graph to the the graph of an

More information

SECTION 3.2 THE PRODUCT AND QUOTIENT RULES 1 8 3

SECTION 3.2 THE PRODUCT AND QUOTIENT RULES 1 8 3 SECTION 3.2 THE PRODUCT AND QUOTIENT RULES 8 3 L P f Q L segments L an L 2 to be tangent to the parabola at the transition points P an Q. (See the figure.) To simplify the equations you ecie to place the

More information

Section 7.1: Integration by Parts

Section 7.1: Integration by Parts Section 7.1: Integration by Parts 1. Introuction to Integration Techniques Unlike ifferentiation where there are a large number of rules which allow you (in principle) to ifferentiate any function, the

More information

f(x) f(a) Limit definition of the at a point in slope notation.

f(x) f(a) Limit definition of the at a point in slope notation. Lesson 9: Orinary Derivatives Review Hanout Reference: Brigg s Calculus: Early Transcenentals, Secon Eition Topics: Chapter 3: Derivatives, p. 126-235 Definition. Limit Definition of Derivatives at a point

More information

Outline. MS121: IT Mathematics. Differentiation Rules for Differentiation: Part 1. Outline. Dublin City University 4 The Quotient Rule

Outline. MS121: IT Mathematics. Differentiation Rules for Differentiation: Part 1. Outline. Dublin City University 4 The Quotient Rule MS2: IT Mathematics Differentiation Rules for Differentiation: Part John Carroll School of Mathematical Sciences Dublin City University Pattern Observe You may have notice the following pattern when we

More information

Math 106 Exam 2 Topics. du dx

Math 106 Exam 2 Topics. du dx The Chain Rule Math 106 Exam 2 Topics Composition (g f)(x 0 ) = g(f(x 0 )) ; (note: we on t know what g(x 0 ) is.) (g f) ought to have something to o with g (x) an f (x) in particular, (g f) (x 0 ) shoul

More information

QF101: Quantitative Finance September 5, Week 3: Derivatives. Facilitator: Christopher Ting AY 2017/2018. f ( x + ) f(x) f(x) = lim

QF101: Quantitative Finance September 5, Week 3: Derivatives. Facilitator: Christopher Ting AY 2017/2018. f ( x + ) f(x) f(x) = lim QF101: Quantitative Finance September 5, 2017 Week 3: Derivatives Facilitator: Christopher Ting AY 2017/2018 I recoil with ismay an horror at this lamentable plague of functions which o not have erivatives.

More information

Summer Review Packet for Students Entering AP Calculus BC. Complex Fractions

Summer Review Packet for Students Entering AP Calculus BC. Complex Fractions Summer Review Packet for Students Entering AP Calculus BC Comple Fractions When simplifying comple fractions, multiply by a fraction equal to 1 which has a numerator and denominator composed of the common

More information

3.2 Differentiability

3.2 Differentiability Section 3 Differentiability 09 3 Differentiability What you will learn about How f (a) Might Fail to Eist Differentiability Implies Local Linearity Numerical Derivatives on a Calculator Differentiability

More information

Learning Target: I can sketch the graphs of rational functions without a calculator. a. Determine the equation(s) of the asymptotes.

Learning Target: I can sketch the graphs of rational functions without a calculator. a. Determine the equation(s) of the asymptotes. Learning Target: I can sketch the graphs of rational functions without a calculator Consider the graph of y= f(x), where f(x) = 3x 3 (x+2) 2 a. Determine the equation(s) of the asymptotes. b. Find the

More information

Implicit Differentiation and Inverse Trigonometric Functions

Implicit Differentiation and Inverse Trigonometric Functions Implicit Differentiation an Inverse Trigonometric Functions MATH 161 Calculus I J. Robert Buchanan Department of Mathematics Summer 2018 Explicit vs. Implicit Functions 0.5 1 y 0.0 y 2 0.5 3 4 1.0 0.5

More information

Review of Differentiation and Integration for Ordinary Differential Equations

Review of Differentiation and Integration for Ordinary Differential Equations Schreyer Fall 208 Review of Differentiation an Integration for Orinary Differential Equations In this course you will be expecte to be able to ifferentiate an integrate quickly an accurately. Many stuents

More information

Math Implicit Differentiation. We have discovered (and proved) formulas for finding derivatives of functions like

Math Implicit Differentiation. We have discovered (and proved) formulas for finding derivatives of functions like Math 400 3.5 Implicit Differentiation Name We have iscovere (an prove) formulas for fining erivatives of functions like f x x 3x 4x. 3 This amounts to fining y for 3 y x 3x 4x. Notice that in this case,

More information

First Order Linear Differential Equations

First Order Linear Differential Equations LECTURE 8 First Orer Linear Differential Equations We now turn our attention to the problem of constructing analytic solutions of ifferential equations; that is to say,solutions that can be epresse in

More information

Solutions to Math 41 Second Exam November 4, 2010

Solutions to Math 41 Second Exam November 4, 2010 Solutions to Math 41 Secon Exam November 4, 2010 1. (13 points) Differentiate, using the metho of your choice. (a) p(t) = ln(sec t + tan t) + log 2 (2 + t) (4 points) Using the rule for the erivative of

More information

( 3x +1) 2 does not fit the requirement of the power rule that the base be x

( 3x +1) 2 does not fit the requirement of the power rule that the base be x Section 3 4A: The Chain Rule Introuction The Power Rule is state as an x raise to a real number If y = x n where n is a real number then y = n x n-1 What if we wante to fin the erivative of a variable

More information

016A Homework 10 Solution

016A Homework 10 Solution 016A Homework 10 Solution Jae-young Park November 2, 2008 4.1 #14 Write each expression in the form of 2 kx or 3 kx, for a suitable constant k; (3 x 3 x/5 ) 5, (16 1/4 16 3/4 ) 3x Solution (3 x 3 x/5 )

More information

Differentiability, Computing Derivatives, Trig Review

Differentiability, Computing Derivatives, Trig Review Unit #3 : Differentiability, Computing Derivatives, Trig Review Goals: Determine when a function is ifferentiable at a point Relate the erivative graph to the the graph of an original function Compute

More information

Higher. Further Calculus 149

Higher. Further Calculus 149 hsn.uk.net Higher Mathematics UNIT 3 OUTCOME 2 Further Calculus Contents Further Calculus 49 Differentiating sinx an cosx 49 2 Integrating sinx an cosx 50 3 The Chain Rule 5 4 Special Cases of the Chain

More information

( ) ( ) x. The exponential function f(x) with base b is denoted by x

( ) ( ) x. The exponential function f(x) with base b is denoted by x Page of 7 Eponential and Logarithmic Functions Eponential Functions and Their Graphs: Section Objectives: Students will know how to recognize, graph, and evaluate eponential functions. The eponential function

More information

Math 115 Section 018 Course Note

Math 115 Section 018 Course Note Course Note 1 General Functions Definition 1.1. A function is a rule that takes certain numbers as inputs an assigns to each a efinite output number. The set of all input numbers is calle the omain of

More information

MATH section 3.4 Curve Sketching Page 1 of 29

MATH section 3.4 Curve Sketching Page 1 of 29 MATH section. Curve Sketching Page of 9 The step by step procedure below is for regular rational and polynomial functions. If a function contains radical or trigonometric term, then proceed carefully because

More information

L43-Mon-12-Dec-2016-Rev-Cpt-4-for-Final-HW44-and-Rev-Cpt-5-for-Final-HW45 Page 27. L43-Mon-12-Dec-2016-Rev-Cpt-4-HW44-and-Rev-Cpt-5-for-Final-HW45

L43-Mon-12-Dec-2016-Rev-Cpt-4-for-Final-HW44-and-Rev-Cpt-5-for-Final-HW45 Page 27. L43-Mon-12-Dec-2016-Rev-Cpt-4-HW44-and-Rev-Cpt-5-for-Final-HW45 L43-Mon-1-Dec-016-Rev-Cpt-4-for-Final-HW44-and-Rev-Cpt-5-for-Final-HW45 Page 7 L43-Mon-1-Dec-016-Rev-Cpt-4-HW44-and-Rev-Cpt-5-for-Final-HW45 L43-Mon-1-Dec-016-Rev-Cpt-4-for-Final-HW44-and-Rev-Cpt-5-for-Final-HW45

More information

Lesson 5.6 Exercises, pages

Lesson 5.6 Exercises, pages Lesson 5.6 Eercises, pages 05 0 A. Approimate the value of each logarithm, to the nearest thousanth. a) log 9 b) log 00 Use the change of base formula to change the base of the logarithms to base 0. log

More information

(a) 82 (b) 164 (c) 81 (d) 162 (e) 624 (f) 625 None of these. (c) 12 (d) 15 (e)

(a) 82 (b) 164 (c) 81 (d) 162 (e) 624 (f) 625 None of these. (c) 12 (d) 15 (e) Math 2 (Calculus I) Final Eam Form A KEY Multiple Choice. Fill in the answer to each problem on your computer-score answer sheet. Make sure your name, section an instructor are on that sheet.. Approimate

More information

February 21 Math 1190 sec. 63 Spring 2017

February 21 Math 1190 sec. 63 Spring 2017 February 21 Math 1190 sec. 63 Spring 2017 Chapter 2: Derivatives Let s recall the efinitions an erivative rules we have so far: Let s assume that y = f (x) is a function with c in it s omain. The erivative

More information

by using the derivative rules. o Building blocks: d

by using the derivative rules. o Building blocks: d Calculus for Business an Social Sciences - Prof D Yuen Eam Review version /9/01 Check website for any poste typos an upates Eam is on Sections, 5, 6,, 1,, Derivatives Rules Know how to fin the formula

More information

Review Guideline for Final

Review Guideline for Final Review Guideline for Final Here is the outline of the required skills for the final exam. Please read it carefully and find some corresponding homework problems in the corresponding sections to practice.

More information

Exam 2 Answers Math , Fall log x dx = x log x x + C. log u du = 1 3

Exam 2 Answers Math , Fall log x dx = x log x x + C. log u du = 1 3 Exam Answers Math -, Fall 7. Show, using any metho you like, that log x = x log x x + C. Answer: (x log x x+c) = x x + log x + = log x. Thus log x = x log x x+c.. Compute these. Remember to put boxes aroun

More information

3.7 Implicit Differentiation -- A Brief Introduction -- Student Notes

3.7 Implicit Differentiation -- A Brief Introduction -- Student Notes Fin these erivatives of these functions: y.7 Implicit Differentiation -- A Brief Introuction -- Stuent Notes tan y sin tan = sin y e = e = Write the inverses of these functions: y tan y sin How woul we

More information

MA Midterm Exam 1 Spring 2012

MA Midterm Exam 1 Spring 2012 MA Miterm Eam Spring Hoffman. (7 points) Differentiate g() = sin( ) ln(). Solution: We use the quotient rule: g () = ln() (sin( )) sin( ) (ln()) (ln()) = ln()(cos( ) ( )) sin( )( ()) (ln()) = ln() cos(

More information

Calculus BC Section II PART A A GRAPHING CALCULATOR IS REQUIRED FOR SOME PROBLEMS OR PARTS OF PROBLEMS

Calculus BC Section II PART A A GRAPHING CALCULATOR IS REQUIRED FOR SOME PROBLEMS OR PARTS OF PROBLEMS Calculus BC Section II PART A A GRAPHING CALCULATOR IS REQUIRED FOR SOME PROBLEMS OR PARTS OF PROBLEMS. An isosceles triangle, whose base is the interval from (0, 0) to (c, 0), has its verte on the graph

More information

5. Find the slope intercept equation of the line parallel to y = 3x + 1 through the point (4, 5).

5. Find the slope intercept equation of the line parallel to y = 3x + 1 through the point (4, 5). Rewrite using rational eponents. 2 1. 2. 5 5. 8 4 4. 4 5. Find the slope intercept equation of the line parallel to y = + 1 through the point (4, 5). 6. Use the limit definition to find the derivative

More information

Rational Functions 4.5

Rational Functions 4.5 Math 4 Pre-Calculus Name Date Rational Function Rational Functions 4.5 g ( ) A function is a rational function if f ( ), where g ( ) and ( ) h ( ) h are polynomials. Vertical asymptotes occur at -values

More information

Section 3.1/3.2: Rules of Differentiation

Section 3.1/3.2: Rules of Differentiation : Rules of Differentiation Math 115 4 February 2018 Overview 1 2 Four Theorem for Derivatives Suppose c is a constant an f, g are ifferentiable functions. Then 1 2 3 4 x (c) = 0 x (x n ) = nx n 1 x [cf

More information

d dx But have you ever seen a derivation of these results? We ll prove the first result below. cos h 1

d dx But have you ever seen a derivation of these results? We ll prove the first result below. cos h 1 Lecture 5 Some ifferentiation rules Trigonometric functions (Relevant section from Stewart, Seventh Eition: Section 3.3) You all know that sin = cos cos = sin. () But have you ever seen a erivation of

More information

Differential Calculus Definitions, Rules and Theorems

Differential Calculus Definitions, Rules and Theorems Precalculus Review Differential Calculus Definitions, Rules an Teorems Sara Brewer, Alabama Scool of Mat an Science Functions, Domain an Range f: X Y a function f from X to Y assigns to eac x X a unique

More information

You should also review L Hôpital s Rule, section 3.6; follow the homework link above for exercises.

You should also review L Hôpital s Rule, section 3.6; follow the homework link above for exercises. BEFORE You Begin Calculus II If it has been awhile since you ha Calculus, I strongly suggest that you refresh both your ifferentiation an integration skills. I woul also like to remin you that in Calculus,

More information

Section 5.1 Determine if a function is a polynomial function. State the degree of a polynomial function.

Section 5.1 Determine if a function is a polynomial function. State the degree of a polynomial function. Test Instructions Objectives Section 5.1 Section 5.1 Determine if a function is a polynomial function. State the degree of a polynomial function. Form a polynomial whose zeros and degree are given. Graph

More information

Day 4: Motion Along a Curve Vectors

Day 4: Motion Along a Curve Vectors Day 4: Motion Along a Curve Vectors I give my stuents the following list of terms an formulas to know. Parametric Equations, Vectors, an Calculus Terms an Formulas to Know: If a smooth curve C is given

More information

AP Calculus Prep Session Handout. Integral Defined Functions

AP Calculus Prep Session Handout. Integral Defined Functions AP Calculus Prep Session Handout A continuous, differentiable function can be epressed as a definite integral if it is difficult or impossible to determine the antiderivative of a function using known

More information

f(x + h) f(x) f (x) = lim

f(x + h) f(x) f (x) = lim Introuction 4.3 Some Very Basic Differentiation Formulas If a ifferentiable function f is quite simple, ten it is possible to fin f by using te efinition of erivative irectly: f () 0 f( + ) f() However,

More information

All work must be shown in this course for full credit. Unsupported answers may receive NO credit.

All work must be shown in this course for full credit. Unsupported answers may receive NO credit. AP Calculus.1 Worksheet Day 1 All work must be shown in this course for full credit. Unsupported answers may receive NO credit. 1. The only way to guarantee the eistence of a it is to algebraically prove

More information

Summary: Differentiation

Summary: Differentiation Techniques of Differentiation. Inverse Trigonometric functions The basic formulas (available in MF5 are: Summary: Differentiation ( sin ( cos The basic formula can be generalize as follows: Note: ( sin

More information

cosh x sinh x So writing t = tan(x/2) we have 6.4 Integration using tan(x/2) 2t 1 + t 2 cos x = 1 t2 sin x =

cosh x sinh x So writing t = tan(x/2) we have 6.4 Integration using tan(x/2) 2t 1 + t 2 cos x = 1 t2 sin x = 6.4 Integration using tan/ We will revisit the ouble angle ientities: sin = sin/ cos/ = tan/ sec / = tan/ + tan / cos = cos / sin / tan = = tan / sec / tan/ tan /. = tan / + tan / So writing t = tan/ we

More information

MATH2231-Differentiation (2)

MATH2231-Differentiation (2) -Differentiation () The Beginnings of Calculus The prime occasion from which arose my iscovery of the metho of the Characteristic Triangle, an other things of the same sort, happene at a time when I ha

More information

dx dx [x2 + y 2 ] = y d [tan x] + tan x = 2x + 2y = y sec 2 x + tan x dy dy = tan x dy dy = [tan x 2y] dy dx = 2x y sec2 x [1 + sin y] = sin(xy)

dx dx [x2 + y 2 ] = y d [tan x] + tan x = 2x + 2y = y sec 2 x + tan x dy dy = tan x dy dy = [tan x 2y] dy dx = 2x y sec2 x [1 + sin y] = sin(xy) Math 7 Activit: Implicit & Logarithmic Differentiation (Solutions) Implicit Differentiation. For each of the following equations, etermine x. a. tan x = x 2 + 2 tan x] = x x x2 + 2 ] = tan x] + tan x =

More information

Implicit Differentiation. Lecture 16.

Implicit Differentiation. Lecture 16. Implicit Differentiation. Lecture 16. We are use to working only with functions that are efine explicitly. That is, ones like f(x) = 5x 3 + 7x x 2 + 1 or s(t) = e t5 3, in which the function is escribe

More information

Implicit Differentiation

Implicit Differentiation Implicit Differentiation Implicit Differentiation Using the Chain Rule In the previous section we focuse on the erivatives of composites an saw that THEOREM 20 (Chain Rule) Suppose that u = g(x) is ifferentiable

More information

Differentiation Rules Derivatives of Polynomials and Exponential Functions

Differentiation Rules Derivatives of Polynomials and Exponential Functions Derivatives of Polynomials an Exponential Functions Differentiation Rules Derivatives of Polynomials an Exponential Functions Let s start with the simplest of all functions, the constant function f(x)

More information

Exam 2 Review Solutions

Exam 2 Review Solutions Exam Review Solutions 1. True or False, an explain: (a) There exists a function f with continuous secon partial erivatives such that f x (x, y) = x + y f y = x y False. If the function has continuous secon

More information

Math Chapter 2 Essentials of Calculus by James Stewart Prepared by Jason Gaddis

Math Chapter 2 Essentials of Calculus by James Stewart Prepared by Jason Gaddis Math 231 - Chapter 2 Essentials of Calculus by James Stewart Prepare by Jason Gais Chapter 2 - Derivatives 21 - Derivatives an Rates of Change Definition A tangent to a curve is a line that intersects

More information

1/100 Range: 1/10 1/ 2. 1) Constant: choose a value for the constant that can be graphed on the coordinate grid below.

1/100 Range: 1/10 1/ 2. 1) Constant: choose a value for the constant that can be graphed on the coordinate grid below. Name 1) Constant: choose a value or the constant that can be graphed on the coordinate grid below a y Toolkit Functions Lab Worksheet thru inverse trig ) Identity: y ) Reciprocal: 1 ( ) y / 1/ 1/1 1/ 1

More information

Internet Mat117 Formulas and Concepts. d(a, B) = (x 2 x 1 ) 2 + (y 2 y 1 ) 2. ( x 1 + x 2 2., y 1 + y 2. (x h) 2 + (y k) 2 = r 2. m = y 2 y 1 x 2 x 1

Internet Mat117 Formulas and Concepts. d(a, B) = (x 2 x 1 ) 2 + (y 2 y 1 ) 2. ( x 1 + x 2 2., y 1 + y 2. (x h) 2 + (y k) 2 = r 2. m = y 2 y 1 x 2 x 1 Internet Mat117 Formulas and Concepts 1. The distance between the points A(x 1, y 1 ) and B(x 2, y 2 ) in the plane is d(a, B) = (x 2 x 1 ) 2 + (y 2 y 1 ) 2. 2. The midpoint of the line segment from A(x

More information

Linear and quadratic approximation

Linear and quadratic approximation Linear an quaratic approximation November 11, 2013 Definition: Suppose f is a function that is ifferentiable on an interval I containing the point a. The linear approximation to f at a is the linear function

More information

Final Exam: Sat 12 Dec 2009, 09:00-12:00

Final Exam: Sat 12 Dec 2009, 09:00-12:00 MATH 1013 SECTIONS A: Professor Szeptycki APPLIED CALCULUS I, FALL 009 B: Professor Toms C: Professor Szeto NAME: STUDENT #: SECTION: No ai (e.g. calculator, written notes) is allowe. Final Exam: Sat 1

More information

Chapter 3 Definitions and Theorems

Chapter 3 Definitions and Theorems Chapter 3 Definitions an Theorems (from 3.1) Definition of Tangent Line with slope of m If f is efine on an open interval containing c an the limit Δy lim Δx 0 Δx = lim f (c + Δx) f (c) = m Δx 0 Δx exists,

More information