INSTRUCTOR: CEZAR LUPU. Problem 1. a) Let f(x) be a continuous function on [1, 2]. Prove that. nx 2 lim

Size: px
Start display at page:

Download "INSTRUCTOR: CEZAR LUPU. Problem 1. a) Let f(x) be a continuous function on [1, 2]. Prove that. nx 2 lim"

Transcription

1 WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (RIEMANN AND RIEMANN-STIELTJES INTEGRAL OF A SINGLE VARIABLE, INTEGRAL CALCULUS, FOURIER SERIES AND SPECIAL FUNCTIONS INSTRUCTOR: CEZAR LUPU Problem. Let f( be cotiuous fuctio o [, ]. Prove tht d =. + 4 b Let f( be cotiuous fuctio o [, ]. Prove tht d =. + 4 c Let f( be cotiuous fuctio o [, ]. Prove tht there eists β > such tht 3/ d = β f(. + 4 Uiversity of Pittsburgh Preiry Em, 6 Problem. Let f be C fuctio o [, ] such tht f( = d f for [, ]. Prove tht f(d 3. Uiversity of Missouri-Columbi Qulifyig Em, 995 Problem 3. Let f : [, ] R be cotiuous fuctio o [, ]. Prove tht f(t cos( t + 4 π dt = f(tdt. Problem 4. For ech N, let φ ( =. Suppose tht f( is cotiuous fuctio o [, ] which stisfies f(φ (d = f(φ m (d, for ll, m N. Prove tht f must be costt fuctio.

2 INSTRUCTOR: CEZAR LUPU Problem 5. Let f be cotiuous fuctio o [, ]. Prove tht tf( d = πf(. t + + t Ohio Stte Uiversity Qulifyig Em, 8 Problem 6. ( Let f C ([, ] such tht f( =. Prove tht f( ( / (f (. (b Let f C ([, ] such tht f( = f ( =. Prove tht f( ( / (f (. (c Let f C ([, ] such tht f( = f ( = f ( =. Prove tht f( ( / (f (. 3 Problem 7. Let f : [, ] R be cotiuously differetible, with f( =. Prove tht f where f = sup{ f(t : t }. (f ( d, Problem 8. ( Prove tht ( ( + e d = = (b Use prt ( to show tht = ( +. = ( + = log. Uiversity of Pittsburgh Preiry Em, 4 Problem 9. Prove tht, if f : [, ] R is cotiuous d f(d =

3 WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (RIEMANN AND RIEMANN-STIELTJES for ech iteger, the f o [, ]. Uiversity of Pittsburgh Preiry Em, 5 Problem. Suppose tht φ : [, b] R is differetible d f : (φ([, b] R is cotiuous. Prove the Leibiz rule: [ ] d φ( f(tdt = f(φ( φ (. d φ( Uiversity of Pittsburgh Preiry Em, 6 Problem. ( Prove tht if f : [, b] R is cotiuous, the ( log ep(f(d = sup f(. [,] (b Let f C([, ], R. Prove tht f( d = sup f(. [,b] Uiversity of Pittsburgh Preiry Em, 7 Problem. Let f : [, ] R be cotiuous fuctio. Show tht: ( (b (c (d f(d =. f( d = f(. f(d = f(. f( d = f(d. Problem 3. ( Let f : [, ] R be cotiuously differetible o [, ] d stisfy f( =. Show tht f( d 4 (f ( d. Uiversity of Pittsburgh Preiry Em, (b Let f, g C ([, b] such tht g(b =. Prove tht f (d = g (d = d f( =

4 4 INSTRUCTOR: CEZAR LUPU ( / ( / f(g(d (f ( + (g (. (c Let f d f be cotiuous o [, d f( = for. Show tht f (d f (d (f ( d. Berkeley Preiry Em, 995 Problem 4. [Riesz] Give u C([, ], defie f : [, ] R by f(tdt, (, ] f( = u(, = Prove tht ( / ( / f (d u (d. Uiversity of Pittsburgh Preiry Em, 3 Problem 5. Let f, g be two Riem itegrble fuctios o [, ] d h( = m{f(; g(} for [, ]. (i Prove tht h is Riem itegrble o [, ]. (ii Suppose tht {f } d {g } re two sequeces of Riem itegrble fuctios o [, ] such tht f ( f( d = Let h {f, g } for [, ] d N. Prove tht h ( h( d =. f ( f( d =. Uiversity of Pittsburgh Preiry Em, 3 Problem 6. ( Let f : [, ] [, be icresig fuctio. Show tht f k= ( k f(d f( f(. (b Let f : [, ] R be cotiuous fuctio tht is lso differetible o (, d the derivtive f is bouded o (,. Set M = sup f(t. Prove tht for ech <t< N oe hs

5 WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (RIEMANN AND RIEMANN-STIELTJES f j= ( j f(tdt M. Uiversity of Missouri-Columbi Qulifyig Em, 4 Problem 7. Let g : (, (, be cotiuously differetible fuctio with the property tht there eists two costts C > d M > such tht g( C d g ( M for ll >. Prove tht coverges. si g( d Uiversity of Missouri-Columbi Qulifyig Em, Problem 8. Let f : [, (, be cotiuous d periodic with period fuctio (i.e. f( + = f(, for ech, d defie Show tht F ( = f(tdt. t t t f( d = F (. Uiversity of Missouri-Columbi Qulifyig Em, 8 Problem 9. Suppose tht f : [, R is cotiuous o [,, differetible o (,, f( =, f (, for >. Show tht for, ( f(tdt f 3 (tdt. Uiversity of Missouri-Columbi Qulifyig Em, 7 Problem. ( Show tht if f : [, R is uiformly cotiuous d T f(tdt T eists d is fiite, the f( =. (b Let f : [, [, be mootoiclly decresig fuctio such tht Show tht f( =. f(d <.

6 6 INSTRUCTOR: CEZAR LUPU Uiversity of Missouri-Columbi Qulifyig Em, 5 Problem. Let f C ([, ] such tht f( = f( =. Show tht ( (f ( d f(d. Problem. ( Let (g be sequece of Riem itegrble fuctios from [, ] ito R such tht g ( for ll,. Defie G ( = g (tdt. Prove tht sequece of (G coverges uiformly. (b Let (f be sequece of rel vlued C fuctios o [, ] such tht, for ll, f (,, f (d =. Prove tht the sequece (f hs subsequece tht coverges uiformly i [, ]. (c Let (f be sequece of rel-vlued cotiuous fuctios defied o [, ] such tht f (y dy 3, for ll N. Defie g : [, ] R by g ( = + yf (ydy. Prove tht (g = cotis subsequece tht coverges uiformly. Problem 3. Evlute the followig itegrls: (i (ii (iii (iv (v (vi log + d. log( + d. rct d. log( d. log log( d. d. Uiversity of Licol-Nebrsk Qulifyig Em, 9

7 WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (RIEMANN AND RIEMANN-STIELTJES (vii (viii (i log + d. e d. e log d. Problem 4. Let f : [, ] R be cotiuous. Suppose tht f(g (d = for ech cotiuously differetible fuctio g : [, ] R stisfyig g( = = g(. Prove tht f must be the costt fuctio. Ohio Stte Uiversity Qulifyig Em, 5 Problem 5. Let the fuctio ϕ be cotiuous o [, ] with ϕ(d =, ϕ(d =. Prove tht there eists [, ] such tht ϕ( 4. Ohio Stte Uiversity Qulifyig Em, 4 Problem 6. Let f C ([, b]. Show tht there eist c, d (, b such tht d ( + b f(d = (b f + (b 3 f (c, 4 f( + f(b f(d = (b (b 3 f (d. Problem 7. Let f be cotiuously differetible fuctio o the itervl [, ] ito R. Suppose tht f(/ =. Show tht f( d f ( d. Ohio Stte Uiversity Qulifyig Em, Problem 8. Let f be rel-vlued cotiuous fuctio o [, ]. Prove tht d ( ep f(d ep(f(d,

8 8 INSTRUCTOR: CEZAR LUPU ( log f(d log f(d. Problem 9. [Frulli] Let f be rel vlued fuctio such tht f C([,, f( d the improper Riem itegrl coverges. Prove tht for ll > d b > we hve: f( f(b d = f( log b ɛ + ɛ. Applictios. Evlute the followig itegrls: (i (ii e e b d. rct(π rct d. Problem 3. ( Prove tht (b Prove tht π si + d = 4... ( ( +. rcsi = = c Deduce the Euler celebrted series, 3... ( 4... ( = = π 6. +, <. + Americ Mthemticl Mothly, 988 Problem 3. Let f : [, π] R be cotiuous fuctio such tht π f( si d =, for ll itegers. Is f is ideticlly zero? Problem 3. Let (φ = be sequece of oegtive Riem itegrble fuctios o [, ] which stisfy: (i φ (tdt = for ech.

9 WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (RIEMANN AND RIEMANN-STIELTJES (ii for every δ >, φ uiformly o [, δ] [δ, ]. ( Show tht if f : [, ] R is Riem itegrble d cotiuous t =, the (b Show tht φ (tf(tdt = f(. Problem 33. Evlute the it: e ( d = 4 3. Uiversity of New Meico Qulifyig Em, k= ( + k /k Problem 34. Let f : [, ] R be cotiuous fuctio such tht for ll [, ]. Show tht f(tdt, 3 f (tdt 3. Problem 35. Let [, ]. Show tht there is o cotiuous fuctio f : [, ] (, such tht f =, f =, f =. Problem 36. Let M = C([, ]. Defie d(, o M M by d(f, g = (f( g( d, = for f, g M. Prove tht (M, d is metric spce. Problem 37. Prove tht iff : [, ] R is cotiuous fuctio such tht

10 INSTRUCTOR: CEZAR LUPU e f(d = for ll =,,,..., the f( = for ll. Does the sme coclusio still hold true if f is odecresig? Problem 38. (i [Hermite-Hdmrd] Let f : [, b] R be cove fuctio. Show tht ( + b (b f (ii Show tht f(d (b f( + f(b. d k+ k f(d log k + log(k +, k, k+/ k / log d log k, k. (iii Cosider the sequece ( defied by = f(d log... log( log,. Show tht is icresig d log 5 4. (iv Prove tht 4 ( e 5 e ( e! e,. (v [Stirlig] Show tht! ( e π =. Problem 39. [Fejer] If f, g re cotiuous fuctios o R of period, the f(g(d = f(d g(d. Problem 4. ( [Poly] Show tht for f C([, b] C ([, b], f( = f(b =, f( d (b 4 sup f (. [,b] (b Show tht for f C([, b] C ([, b], f( = f(b =,

11 WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (RIEMANN AND RIEMANN-STIELTJES f( d (b 3 sup f (. [,b] ( + b Moreover, if f =, the the costt c be replced by 4. Problem 4. Let > d f( be cotiuously differetible o [, ]. Show tht f( f( d + f (d. Ohio Stte Uiversity Qulifyig Em, 99 Problem 4. [Wirtiger] Let f be twice differetible rel vlued fuctio o [, π], with π f(d = = f( = f(π =. Show tht π f ( k= π (f ( d. Problem 43. ( Let f : [, ] R be differetible, with f itegrble o [, ]. Show tht ( ( k f( f( f(d f =. Applictio. Evlute ( log k=. + k (b Let f : [, ] R be fuctio of clss C o [, ]. Show tht ( f(d ( k f = f ( f ( 4 k= Problem 44. Does there eist cotiuous rel-vlued fuctio f(,, such tht d for ll =,, 3, 4,...? f(d = f(d =,

12 INSTRUCTOR: CEZAR LUPU Problem 45. Evlute the followig: ( (b ( + e + e d. + ( log + ( α d, α (, ]. (c (d π π ( si. 4 ( = cos. + = Uiversity of Pittsburgh Preiry Em, (e (f ( ( s e /s ds, (,. ( d. + 4 = = Uiversity of Pittsburgh Preiry Em, 4 Problem 46. Let f be cotiuous rel-vlued fuctio o [, such tht ( f( + f(tdt eists d is fiite. Prove tht f( =. Problem 47. ( [Rogers-Holder] Let C([, ] deote the set of cotiuous relvlued fuctios o [, ]. Let p, q >, with p + q the ( f(g( d =. If f d g re i C([, ], /p ( /q f p (d g (d q. (b [Mikovski] Let p (,. For ech fuctio f C([, ], let f p := ( /p f(d. Prove tht f + g p f p + g p. Problem 48. [Hrdy] Show tht if f : [, R + is itegrble d p >, the oe hs

13 WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (RIEMANN AND RIEMANN-STIELTJES ( f(tdt p d ( p p f p (d. p Problem 49. Let (f be sequece of cotiuous fuctios defied from [, ] ito R such tht (f ( f m (d,, m. Let K : [, ] [, ]tor be cotiuous. Defie g : [, ] R by g ( = K(, yf (ydy. Prove tht the sequece g coverges uiformly. Problem 5. Let ϕ, ϕ,..., ϕ be oegtive cotiuous fuctios o [, ] such tht the it k ϕ (d eists for every k =,,.... Show tht the it f(ϕ (d eists for every cotiuous fuctio f o [, ]. Berkeley Preiry Em, 98 Problem 5. Suppose tht f : [, ] R hs cotiuous derivtive d tht f(d =. Show tht for every α (,, α f(d 8 sup f (. Putm Competitio (Problem A, 7 Problem 5. Let f : [, ] R be differetible fuctio with bouded derivtive. Show tht ( f (d Problem 53. ( Show tht f(d ( sup f (. e e t dt =.

14 4 INSTRUCTOR: CEZAR LUPU (b Prove tht Uiversity of Pittsburgh Preiry Emitio, 5 sup e e t dt =. Ohio Stte Qulifyig Em, Problem 54. Let f : [, R be bouded d cotiuous. Prove tht sup b b f(d sup f(. Ohio Stte Qulifyig Em, 3 Problem 55. Let f C([, ] d Prove tht f is odd fuctio. f(d = for ll itegers. Ohio Stte Qulifyig Em, 9 Problem 56. [v der Corput] Let φ C (, (recll tht this mes tht φ isifiitely differetible d φ is ideticlly i some eighborhood of d. Show tht for y turl umber N, there eists costt C N such tht e iλ φ( Cλ N, for ll λ >. Ohio Stte Qulifyig Em, 4 Problem 57. Suppose tht f : [, R is cotiuous. Prove tht if f(d eists (i short, for every α > d α + Problem 58. Show tht f(d coverges, the e α f(d = f(d. ( d = π. e α f(d coverges Ohio Stte Qulifyig Em,

MATH 104 FINAL SOLUTIONS. 1. (2 points each) Mark each of the following as True or False. No justification is required. y n = x 1 + x x n n

MATH 104 FINAL SOLUTIONS. 1. (2 points each) Mark each of the following as True or False. No justification is required. y n = x 1 + x x n n MATH 04 FINAL SOLUTIONS. ( poits ech) Mrk ech of the followig s True or Flse. No justifictio is required. ) A ubouded sequece c hve o Cuchy subsequece. Flse b) A ifiite uio of Dedekid cuts is Dedekid cut.

More information

Course 121, , Test III (JF Hilary Term)

Course 121, , Test III (JF Hilary Term) Course 2, 989 9, Test III (JF Hilry Term) Fridy 2d Februry 99, 3. 4.3pm Aswer y THREE questios. Let f: R R d g: R R be differetible fuctios o R. Stte the Product Rule d the Quotiet Rule for differetitig

More information

MAS221 Analysis, Semester 2 Exercises

MAS221 Analysis, Semester 2 Exercises MAS22 Alysis, Semester 2 Exercises Srh Whitehouse (Exercises lbelled * my be more demdig.) Chpter Problems: Revisio Questio () Stte the defiitio of covergece of sequece of rel umbers, ( ), to limit. (b)

More information

f(bx) dx = f dx = dx l dx f(0) log b x a + l log b a 2ɛ log b a.

f(bx) dx = f dx = dx l dx f(0) log b x a + l log b a 2ɛ log b a. Eercise 5 For y < A < B, we hve B A f fb B d = = A B A f d f d For y ɛ >, there re N > δ >, such tht d The for y < A < δ d B > N, we hve ba f d f A bb f d l By ba A A B A bb ba fb d f d = ba < m{, b}δ

More information

BRAIN TEASURES INDEFINITE INTEGRATION+DEFINITE INTEGRATION EXERCISE I

BRAIN TEASURES INDEFINITE INTEGRATION+DEFINITE INTEGRATION EXERCISE I EXERCISE I t Q. d Q. 6 6 cos si Q. Q.6 d d Q. d Q. Itegrte cos t d by the substitutio z = + e d e Q.7 cos. l cos si d d Q. cos si si si si b cos Q.9 d Q. si b cos Q. si( ) si( ) d ( ) Q. d cot d d Q. (si

More information

Convergence rates of approximate sums of Riemann integrals

Convergence rates of approximate sums of Riemann integrals Jourl of Approximtio Theory 6 (9 477 49 www.elsevier.com/locte/jt Covergece rtes of pproximte sums of Riem itegrls Hiroyuki Tski Grdute School of Pure d Applied Sciece, Uiversity of Tsukub, Tsukub Ibrki

More information

POWER SERIES R. E. SHOWALTER

POWER SERIES R. E. SHOWALTER POWER SERIES R. E. SHOWALTER. sequeces We deote by lim = tht the limit of the sequece { } is the umber. By this we me tht for y ε > 0 there is iteger N such tht < ε for ll itegers N. This mkes precise

More information

Math 104: Final exam solutions

Math 104: Final exam solutions Mth 14: Fil exm solutios 1. Suppose tht (s ) is icresig sequece with coverget subsequece. Prove tht (s ) is coverget sequece. Aswer: Let the coverget subsequece be (s k ) tht coverges to limit s. The there

More information

FOURIER SERIES PART I: DEFINITIONS AND EXAMPLES. To a 2π-periodic function f(x) we will associate a trigonometric series. a n cos(nx) + b n sin(nx),

FOURIER SERIES PART I: DEFINITIONS AND EXAMPLES. To a 2π-periodic function f(x) we will associate a trigonometric series. a n cos(nx) + b n sin(nx), FOURIER SERIES PART I: DEFINITIONS AND EXAMPLES To -periodic fuctio f() we will ssocite trigoometric series + cos() + b si(), or i terms of the epoetil e i, series of the form c e i. Z For most of the

More information

Convergence rates of approximate sums of Riemann integrals

Convergence rates of approximate sums of Riemann integrals Covergece rtes of pproximte sums of Riem itegrls Hiroyuki Tski Grdute School of Pure d Applied Sciece, Uiversity of Tsuku Tsuku Irki 5-857 Jp tski@mth.tsuku.c.jp Keywords : covergece rte; Riem sum; Riem

More information

Review of the Riemann Integral

Review of the Riemann Integral Chpter 1 Review of the Riem Itegrl This chpter provides quick review of the bsic properties of the Riem itegrl. 1.0 Itegrls d Riem Sums Defiitio 1.0.1. Let [, b] be fiite, closed itervl. A prtitio P of

More information

The Definite Integral

The Definite Integral The Defiite Itegrl A Riem sum R S (f) is pproximtio to the re uder fuctio f. The true re uder the fuctio is obtied by tkig the it of better d better pproximtios to the re uder f. Here is the forml defiitio,

More information

Sequence and Series of Functions

Sequence and Series of Functions 6 Sequece d Series of Fuctios 6. Sequece of Fuctios 6.. Poitwise Covergece d Uiform Covergece Let J be itervl i R. Defiitio 6. For ech N, suppose fuctio f : J R is give. The we sy tht sequece (f ) of fuctios

More information

n 2 + 3n + 1 4n = n2 + 3n + 1 n n 2 = n + 1

n 2 + 3n + 1 4n = n2 + 3n + 1 n n 2 = n + 1 Ifiite Series Some Tests for Divergece d Covergece Divergece Test: If lim u or if the limit does ot exist, the series diverget. + 3 + 4 + 3 EXAMPLE: Show tht the series diverges. = u = + 3 + 4 + 3 + 3

More information

UNIVERSITY OF BRISTOL. Examination for the Degrees of B.Sc. and M.Sci. (Level C/4) ANALYSIS 1B, SOLUTIONS MATH (Paper Code MATH-10006)

UNIVERSITY OF BRISTOL. Examination for the Degrees of B.Sc. and M.Sci. (Level C/4) ANALYSIS 1B, SOLUTIONS MATH (Paper Code MATH-10006) UNIVERSITY OF BRISTOL Exmitio for the Degrees of B.Sc. d M.Sci. (Level C/4) ANALYSIS B, SOLUTIONS MATH 6 (Pper Code MATH-6) My/Jue 25, hours 3 miutes This pper cotis two sectios, A d B. Plese use seprte

More information

We will begin by supplying the proof to (a).

We will begin by supplying the proof to (a). (The solutios of problem re mostly from Jeffrey Mudrock s HWs) Problem 1. There re three sttemet from Exmple 5.4 i the textbook for which we will supply proofs. The sttemets re the followig: () The spce

More information

Infinite Series Sequences: terms nth term Listing Terms of a Sequence 2 n recursively defined n+1 Pattern Recognition for Sequences Ex:

Infinite Series Sequences: terms nth term Listing Terms of a Sequence 2 n recursively defined n+1 Pattern Recognition for Sequences Ex: Ifiite Series Sequeces: A sequece i defied s fuctio whose domi is the set of positive itegers. Usully it s esier to deote sequece i subscript form rther th fuctio ottio.,, 3, re the terms of the sequece

More information

1 Tangent Line Problem

1 Tangent Line Problem October 9, 018 MAT18 Week Justi Ko 1 Tget Lie Problem Questio: Give the grph of fuctio f, wht is the slope of the curve t the poit, f? Our strteg is to pproimte the slope b limit of sect lies betwee poits,

More information

Chapter 5. The Riemann Integral. 5.1 The Riemann integral Partitions and lower and upper integrals. Note: 1.5 lectures

Chapter 5. The Riemann Integral. 5.1 The Riemann integral Partitions and lower and upper integrals. Note: 1.5 lectures Chpter 5 The Riem Itegrl 5.1 The Riem itegrl Note: 1.5 lectures We ow get to the fudmetl cocept of itegrtio. There is ofte cofusio mog studets of clculus betwee itegrl d tiderivtive. The itegrl is (iformlly)

More information

f(t)dt 2δ f(x) f(t)dt 0 and b f(t)dt = 0 gives F (b) = 0. Since F is increasing, this means that

f(t)dt 2δ f(x) f(t)dt 0 and b f(t)dt = 0 gives F (b) = 0. Since F is increasing, this means that Uiversity of Illiois t Ur-Chmpig Fll 6 Mth 444 Group E3 Itegrtio : correctio of the exercises.. ( Assume tht f : [, ] R is cotiuous fuctio such tht f(x for ll x (,, d f(tdt =. Show tht f(x = for ll x [,

More information

Advanced Calculus Test File Spring Test 1

Advanced Calculus Test File Spring Test 1 Advced Clculus Test File Sprig 009 Test Defiitios - Defie the followig terms.) Crtesi product of A d B.) The set, A, is coutble.) The set, A, is ucoutble 4.) The set, A, is ifiite 5.) The sets A d B re

More information

Ideas of Lebesgue and Perron Integration in Uniqueness of Fourier and Trigonometric Series By Ng Tze Beng

Ideas of Lebesgue and Perron Integration in Uniqueness of Fourier and Trigonometric Series By Ng Tze Beng Ides of Lebesgue d Perro Itegrtio i Uiqueess of Fourier d Trigoometric Series By Ng Tze Beg Tis rticle is bout te ides ledig to te uiqueess of coverget trigoometric series We loo t te ides ivolved we te

More information

Review of Sections

Review of Sections Review of Sectios.-.6 Mrch 24, 204 Abstrct This is the set of otes tht reviews the mi ides from Chpter coverig sequeces d series. The specific sectios tht we covered re s follows:.: Sequces..2: Series,

More information

is continuous at x 2 and g(x) 2. Oil spilled from a ruptured tanker spreads in a circle whose area increases at a

is continuous at x 2 and g(x) 2. Oil spilled from a ruptured tanker spreads in a circle whose area increases at a . Cosider two fuctios f () d g () defied o itervl I cotiig. f () is cotiuous t d g() is discotiuous t. Which of the followig is true bout fuctios f g d f g, the sum d the product of f d g, respectively?

More information

1. (25 points) Use the limit definition of the definite integral and the sum formulas to compute. [1 x + x2

1. (25 points) Use the limit definition of the definite integral and the sum formulas to compute. [1 x + x2 Mth 3, Clculus II Fil Exm Solutios. (5 poits) Use the limit defiitio of the defiite itegrl d the sum formuls to compute 3 x + x. Check your swer by usig the Fudmetl Theorem of Clculus. Solutio: The limit

More information

AN INEQUALITY OF GRÜSS TYPE FOR RIEMANN-STIELTJES INTEGRAL AND APPLICATIONS FOR SPECIAL MEANS

AN INEQUALITY OF GRÜSS TYPE FOR RIEMANN-STIELTJES INTEGRAL AND APPLICATIONS FOR SPECIAL MEANS RGMIA Reserch Report Collectio, Vol., No., 998 http://sci.vut.edu.u/ rgmi/reports.html AN INEQUALITY OF GRÜSS TYPE FOR RIEMANN-STIELTJES INTEGRAL AND APPLICATIONS FOR SPECIAL MEANS S.S. DRAGOMIR AND I.

More information

MATH 104: INTRODUCTORY ANALYSIS SPRING 2009/10 PROBLEM SET 8 SOLUTIONS. and x i = a + i. i + n(n + 1)(2n + 1) + 2a. (b a)3 6n 2

MATH 104: INTRODUCTORY ANALYSIS SPRING 2009/10 PROBLEM SET 8 SOLUTIONS. and x i = a + i. i + n(n + 1)(2n + 1) + 2a. (b a)3 6n 2 MATH 104: INTRODUCTORY ANALYSIS SPRING 2009/10 PROBLEM SET 8 SOLUTIONS 6.9: Let f(x) { x 2 if x Q [, b], 0 if x (R \ Q) [, b], where > 0. Prove tht b. Solutio. Let P { x 0 < x 1 < < x b} be regulr prtitio

More information

Approximate Integration

Approximate Integration Study Sheet (7.7) Approimte Itegrtio I this sectio, we will ler: How to fid pproimte vlues of defiite itegrls. There re two situtios i which it is impossile to fid the ect vlue of defiite itegrl. Situtio:

More information

Chapter 7 Infinite Series

Chapter 7 Infinite Series MA Ifiite Series Asst.Prof.Dr.Supree Liswdi Chpter 7 Ifiite Series Sectio 7. Sequece A sequece c be thought of s list of umbers writte i defiite order:,,...,,... 2 The umber is clled the first term, 2

More information

ANALYSIS HW 3. f(x + y) = f(x) + f(y) for all real x, y. Demonstration: Let f be such a function. Since f is smooth, f exists.

ANALYSIS HW 3. f(x + y) = f(x) + f(y) for all real x, y. Demonstration: Let f be such a function. Since f is smooth, f exists. ANALYSIS HW 3 CLAY SHONKWILER () Fid ll smooth fuctios f : R R with the property f(x + y) = f(x) + f(y) for ll rel x, y. Demostrtio: Let f be such fuctio. Sice f is smooth, f exists. The The f f(x + h)

More information

MATH 104: INTRODUCTORY ANALYSIS SPRING 2008/09 PROBLEM SET 10 SOLUTIONS. f m. and. f m = 0. and x i = a + i. a + i. a + n 2. n(n + 1) = a(b a) +

MATH 104: INTRODUCTORY ANALYSIS SPRING 2008/09 PROBLEM SET 10 SOLUTIONS. f m. and. f m = 0. and x i = a + i. a + i. a + n 2. n(n + 1) = a(b a) + MATH 04: INTRODUCTORY ANALYSIS SPRING 008/09 PROBLEM SET 0 SOLUTIONS Throughout this problem set, B[, b] will deote the set of ll rel-vlued futios bouded o [, b], C[, b] the set of ll rel-vlued futios

More information

HOMEWORK 1 1. P 229. # Then ; then we have. goes to 1 uniformly as n goes to infinity. Therefore. e x2 /n dx = = sin x.

HOMEWORK 1 1. P 229. # Then ; then we have. goes to 1 uniformly as n goes to infinity. Therefore. e x2 /n dx = = sin x. HOMEWORK 1 SHUANGLIN SHAO 1. P 229. # 7.1.2. Proof. (). Let f (x) x99 + 5. The x 66 + x3 f x 33 s goes to ifiity. We estimte the differece, f (x) x 33 5 x 66 + 3 5 x 66 5, for ll x [1, 3], which goes to

More information

B. Examples 1. Finite Sums finite sums are an example of Riemann Sums in which each subinterval has the same length and the same x i

B. Examples 1. Finite Sums finite sums are an example of Riemann Sums in which each subinterval has the same length and the same x i Mth 06 Clculus Sec. 5.: The Defiite Itegrl I. Riem Sums A. Def : Give y=f(x):. Let f e defied o closed itervl[,].. Prtitio [,] ito suitervls[x (i-),x i ] of legth Δx i = x i -x (i-). Let P deote the prtitio

More information

Infinite Sequences and Series. Sequences. Sequences { } { } A sequence is a list of number in a definite order: a 1, a 2, a 3,, a n, or {a n } or

Infinite Sequences and Series. Sequences. Sequences { } { } A sequence is a list of number in a definite order: a 1, a 2, a 3,, a n, or {a n } or Mth 0 Clculus II Ifiite Sequeces d Series -- Chpter Ifiite Sequeces d Series Mth 0 Clculus II Ifiite Sequeces d Series: Sequeces -- Chpter. Sequeces Mth 0 Clculus II Ifiite Sequeces d Series: Sequeces

More information

Second Mean Value Theorem for Integrals By Ng Tze Beng. The Second Mean Value Theorem for Integrals (SMVT) Statement of the Theorem

Second Mean Value Theorem for Integrals By Ng Tze Beng. The Second Mean Value Theorem for Integrals (SMVT) Statement of the Theorem Secod Me Vlue Theorem for Itegrls By Ng Tze Beg This rticle is out the Secod Me Vlue Theorem for Itegrls. This theorem, first proved y Hoso i its most geerlity d with extesio y ixo, is very useful d lmost

More information

2. Infinite Series 3. Power Series 4. Taylor Series 5. Review Questions and Exercises 6. Sequences and Series with Maple

2. Infinite Series 3. Power Series 4. Taylor Series 5. Review Questions and Exercises 6. Sequences and Series with Maple Chpter II CALCULUS II.4 Sequeces d Series II.4 SEQUENCES AND SERIES Objectives: After the completio of this sectio the studet - should recll the defiitios of the covergece of sequece, d some limits; -

More information

SOME SHARP OSTROWSKI-GRÜSS TYPE INEQUALITIES

SOME SHARP OSTROWSKI-GRÜSS TYPE INEQUALITIES Uiv. Beogrd. Publ. Elektroteh. Fk. Ser. Mt. 8 006 4. Avilble electroiclly t http: //pefmth.etf.bg.c.yu SOME SHARP OSTROWSKI-GRÜSS TYPE INEQUALITIES Zheg Liu Usig vrit of Grüss iequlity to give ew proof

More information

( ) dx ; f ( x ) is height and Δx is

( ) dx ; f ( x ) is height and Δx is Mth : 6.3 Defiite Itegrls from Riem Sums We just sw tht the exct re ouded y cotiuous fuctio f d the x xis o the itervl x, ws give s A = lim A exct RAM, where is the umer of rectgles i the Rectgulr Approximtio

More information

The Weierstrass Approximation Theorem

The Weierstrass Approximation Theorem The Weierstrss Approximtio Theorem Jmes K. Peterso Deprtmet of Biologicl Scieces d Deprtmet of Mthemticl Scieces Clemso Uiversity Februry 26, 2018 Outlie The Wierstrss Approximtio Theorem MtLb Implemettio

More information

( ) = A n + B ( ) + Bn

( ) = A n + B ( ) + Bn MATH 080 Test 3-SOLUTIONS Fll 04. Determie if the series is coverget or diverget. If it is coverget, fid its sum.. (7 poits) = + 3 + This is coverget geometric series where r = d

More information

WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (SEQUENCES OF FUNCTIONS, SERIES OF FUNCTIONS & POWER SERIES)

WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (SEQUENCES OF FUNCTIONS, SERIES OF FUNCTIONS & POWER SERIES) WORKSHEET FOR THE PRELIMINARY EXAMINATION-REAL ANALYSIS (SEQUENCES OF FUNCTIONS, SERIES OF FUNCTIONS & POWER SERIES) INSTRUCTOR: CEZAR LUPU Problem. Decide which of the following sequences of functions

More information

Riemann Integration. Chapter 1

Riemann Integration. Chapter 1 Mesure, Itegrtio & Rel Alysis. Prelimiry editio. 8 July 2018. 2018 Sheldo Axler 1 Chpter 1 Riem Itegrtio This chpter reviews Riem itegrtio. Riem itegrtio uses rectgles to pproximte res uder grphs. This

More information

Options: Calculus. O C.1 PG #2, 3b, 4, 5ace O C.2 PG.24 #1 O D PG.28 #2, 3, 4, 5, 7 O E PG #1, 3, 4, 5 O F PG.

Options: Calculus. O C.1 PG #2, 3b, 4, 5ace O C.2 PG.24 #1 O D PG.28 #2, 3, 4, 5, 7 O E PG #1, 3, 4, 5 O F PG. O C. PG.-3 #, 3b, 4, 5ce O C. PG.4 # Optios: Clculus O D PG.8 #, 3, 4, 5, 7 O E PG.3-33 #, 3, 4, 5 O F PG.36-37 #, 3 O G. PG.4 #c, 3c O G. PG.43 #, O H PG.49 #, 4, 5, 6, 7, 8, 9, 0 O I. PG.53-54 #5, 8

More information

Calculus II Homework: The Integral Test and Estimation of Sums Page 1

Calculus II Homework: The Integral Test and Estimation of Sums Page 1 Clculus II Homework: The Itegrl Test d Estimtio of Sums Pge Questios Emple (The p series) Get upper d lower bouds o the sum for the p series i= /ip with p = 2 if the th prtil sum is used to estimte the

More information

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11 SUTCLIFFE S NOTES: CALCULUS SWOKOWSKI S CHAPTER Ifiite Series.5 Altertig Series d Absolute Covergece Next, let us cosider series with both positive d egtive terms. The simplest d most useful is ltertig

More information

Important Facts You Need To Know/Review:

Important Facts You Need To Know/Review: Importt Fcts You Need To Kow/Review: Clculus: If fuctio is cotiuous o itervl I, the its grph is coected o I If f is cotiuous, d lim g Emple: lim eists, the lim lim f g f g d lim cos cos lim 3 si lim, t

More information

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11

SUTCLIFFE S NOTES: CALCULUS 2 SWOKOWSKI S CHAPTER 11 UTCLIFFE NOTE: CALCULU WOKOWKI CHAPTER Ifiite eries Coverget or Diverget eries Cosider the sequece If we form the ifiite sum 0, 00, 000, 0 00 000, we hve wht is clled ifiite series We wt to fid the sum

More information

{ } { S n } is monotonically decreasing if Sn

{ } { S n } is monotonically decreasing if Sn Sequece A sequece is fuctio whose domi of defiitio is the set of turl umers. Or it c lso e defied s ordered set. Nottio: A ifiite sequece is deoted s { } S or { S : N } or { S, S, S,...} or simply s {

More information

Certain sufficient conditions on N, p n, q n k summability of orthogonal series

Certain sufficient conditions on N, p n, q n k summability of orthogonal series Avilble olie t www.tjs.com J. Nolier Sci. Appl. 7 014, 7 77 Reserch Article Certi sufficiet coditios o N, p, k summbility of orthogol series Xhevt Z. Krsiqi Deprtmet of Mthemtics d Iformtics, Fculty of

More information

Final Solutions. 1. (25pts) Define the following terms. Be as precise as you can.

Final Solutions. 1. (25pts) Define the following terms. Be as precise as you can. Mathematics H104 A. Ogus Fall, 004 Fial Solutios 1. (5ts) Defie the followig terms. Be as recise as you ca. (a) (3ts) A ucoutable set. A ucoutable set is a set which ca ot be ut ito bijectio with a fiite

More information

Real Analysis Fall 2004 Take Home Test 1 SOLUTIONS. < ε. Hence lim

Real Analysis Fall 2004 Take Home Test 1 SOLUTIONS. < ε. Hence lim Real Aalysis Fall 004 Take Home Test SOLUTIONS. Use the defiitio of a limit to show that (a) lim si = 0 (b) Proof. Let ε > 0 be give. Defie N >, where N is a positive iteger. The for ε > N, si 0 < si

More information

MTH 146 Class 16 Notes

MTH 146 Class 16 Notes MTH 46 Clss 6 Notes 0.4- Cotiued Motivtio: We ow cosider the rc legth of polr curve. Suppose we wish to fid the legth of polr curve curve i terms of prmetric equtios s: r f where b. We c view the cos si

More information

Week 13 Notes: 1) Riemann Sum. Aim: Compute Area Under a Graph. Suppose we want to find out the area of a graph, like the one on the right:

Week 13 Notes: 1) Riemann Sum. Aim: Compute Area Under a Graph. Suppose we want to find out the area of a graph, like the one on the right: Week 1 Notes: 1) Riem Sum Aim: Compute Are Uder Grph Suppose we wt to fid out the re of grph, like the oe o the right: We wt to kow the re of the red re. Here re some wys to pproximte the re: We cut the

More information

Abel type inequalities, complex numbers and Gauss Pólya type integral inequalities

Abel type inequalities, complex numbers and Gauss Pólya type integral inequalities Mthemticl Commuictios 31998, 95-101 95 Abel tye iequlities, comlex umbers d Guss Póly tye itegrl iequlities S. S. Drgomir, C. E. M. Perce d J. Šude Abstrct. We obti iequlities of Abel tye but for odecresig

More information

Limit of a function:

Limit of a function: - Limit of fuctio: We sy tht f ( ) eists d is equl with (rel) umer L if f( ) gets s close s we wt to L if is close eough to (This defiitio c e geerlized for L y syig tht f( ) ecomes s lrge (or s lrge egtive

More information

Limits and an Introduction to Calculus

Limits and an Introduction to Calculus Nme Chpter Limits d Itroductio to Clculus Sectio. Itroductio to Limits Objective: I this lesso ou lered how to estimte limits d use properties d opertios of limits. I. The Limit Cocept d Defiitio of Limit

More information

UNIVERSITY OF CALICUT SCHOOL OF DISTANCE EDUCATION

UNIVERSITY OF CALICUT SCHOOL OF DISTANCE EDUCATION School Of Distce Eductio Questio Bk UNIVERSITY OF ALIUT SHOOL OF DISTANE EDUATION B.Sc MATHEMATIS (ORE OURSE SIXTH SEMESTER ( Admissio OMPLEX ANALYSIS Module- I ( A lytic fuctio with costt modulus is :

More information

Principles of Mathematical Analysis

Principles of Mathematical Analysis Ciro Uiversity Fculty of Scieces Deprtmet of Mthemtics Priciples of Mthemticl Alysis M 232 Mostf SABRI ii Cotets Locl Study of Fuctios. Remiders......................................2 Tylor-Youg Formul..............................

More information

Crushed Notes on MATH132: Calculus

Crushed Notes on MATH132: Calculus Mth 13, Fll 011 Siyg Yg s Outlie Crushed Notes o MATH13: Clculus The otes elow re crushed d my ot e ect This is oly my ow cocise overview of the clss mterils The otes I put elow should ot e used to justify

More information

Probability for mathematicians INDEPENDENCE TAU

Probability for mathematicians INDEPENDENCE TAU Probbility for mthemticis INDEPENDENCE TAU 2013 21 Cotets 2 Cetrl limit theorem 21 2 Itroductio............................ 21 2b Covolutio............................ 22 2c The iitil distributio does

More information

UNIFORM CONVERGENCE MA 403: REAL ANALYSIS, INSTRUCTOR: B. V. LIMAYE

UNIFORM CONVERGENCE MA 403: REAL ANALYSIS, INSTRUCTOR: B. V. LIMAYE UNIFORM CONVERGENCE MA 403: REAL ANALYSIS, INSTRUCTOR: B. V. LIMAYE 1. Pointwise Convergence of Sequence Let E be set nd Y be metric spce. Consider functions f n : E Y for n = 1, 2,.... We sy tht the sequence

More information

1.3 Continuous Functions and Riemann Sums

1.3 Continuous Functions and Riemann Sums mth riem sums, prt 0 Cotiuous Fuctios d Riem Sums I Exmple we sw tht lim Lower() = lim Upper() for the fuctio!! f (x) = + x o [0, ] This is o ccidet It is exmple of the followig theorem THEOREM Let f be

More information

[ 20 ] 1. Inequality exists only between two real numbers (not complex numbers). 2. If a be any real number then one and only one of there hold.

[ 20 ] 1. Inequality exists only between two real numbers (not complex numbers). 2. If a be any real number then one and only one of there hold. [ 0 ]. Iequlity eists oly betwee two rel umbers (ot comple umbers).. If be y rel umber the oe d oly oe of there hold.. If, b 0 the b 0, b 0.. (i) b if b 0 (ii) (iii) (iv) b if b b if either b or b b if

More information

3.7 The Lebesgue integral

3.7 The Lebesgue integral 3 Mesure d Itegrtio The f is simple fuctio d positive wheever f is positive (the ltter follows from the fct tht i this cse f 1 [B,k ] = for ll k, ). Moreover, f (x) f (x). Ideed, if x, the there exists

More information

Test Info. Test may change slightly.

Test Info. Test may change slightly. 9. 9.6 Test Ifo Test my chge slightly. Short swer (0 questios 6 poits ech) o Must choose your ow test o Tests my oly be used oce o Tests/types you re resposible for: Geometric (kow sum) Telescopig (kow

More information

4. When is the particle speeding up? Why? 5. When is the particle slowing down? Why?

4. When is the particle speeding up? Why? 5. When is the particle slowing down? Why? AB CALCULUS: 5.3 Positio vs Distce Velocity vs. Speed Accelertio All the questios which follow refer to the grph t the right.. Whe is the prticle movig t costt speed?. Whe is the prticle movig to the right?

More information

Riemann Integral and Bounded function. Ng Tze Beng

Riemann Integral and Bounded function. Ng Tze Beng Riem Itegrl d Bouded fuctio. Ng Tze Beg I geerlistio of re uder grph of fuctio, it is ormlly ssumed tht the fuctio uder cosidertio e ouded. For ouded fuctio, the rge of the fuctio is ouded d hece y suset

More information

Theorem 5.3 (Continued) The Fundamental Theorem of Calculus, Part 2: ab,, then. f x dx F x F b F a. a a. f x dx= f x x

Theorem 5.3 (Continued) The Fundamental Theorem of Calculus, Part 2: ab,, then. f x dx F x F b F a. a a. f x dx= f x x Chpter 6 Applictios Itegrtio Sectio 6. Regio Betwee Curves Recll: Theorem 5.3 (Cotiued) The Fudmetl Theorem of Clculus, Prt :,,, the If f is cotiuous t ever poit of [ ] d F is tiderivtive of f o [ ] (

More information

9.1 Sequences & Series: Convergence & Divergence

9.1 Sequences & Series: Convergence & Divergence Notes 9.: Cov & Div of Seq & Ser 9. Sequeces & Series: Covergece & Divergece A sequece is simply list of thigs geerted by rule More formlly, sequece is fuctio whose domi is the set of positive itegers,

More information

82A Engineering Mathematics

82A Engineering Mathematics Clss Notes 9: Power Series /) 8A Egieerig Mthetics Secod Order Differetil Equtios Series Solutio Solutio Ato Differetil Equtio =, Hoogeeous =gt), No-hoogeeous Solutio: = c + p Hoogeeous No-hoogeeous Fudetl

More information

lecture 16: Introduction to Least Squares Approximation

lecture 16: Introduction to Least Squares Approximation 97 lecture 16: Itroductio to Lest Squres Approximtio.4 Lest squres pproximtio The miimx criterio is ituitive objective for pproximtig fuctio. However, i my cses it is more ppelig (for both computtio d

More information

Remarks: (a) The Dirac delta is the function zero on the domain R {0}.

Remarks: (a) The Dirac delta is the function zero on the domain R {0}. Sectio Objective(s): The Dirc s Delt. Mi Properties. Applictios. The Impulse Respose Fuctio. 4.4.. The Dirc Delt. 4.4. Geerlized Sources Defiitio 4.4.. The Dirc delt geerlized fuctio is the limit δ(t)

More information

Archimedes - numbers for counting, otherwise lengths, areas, etc. Kepler - geometry for planetary motion

Archimedes - numbers for counting, otherwise lengths, areas, etc. Kepler - geometry for planetary motion Topics i Aalysis 3460:589 Summer 007 Itroductio Ree descartes - aalysis (breaig dow) ad sythesis Sciece as models of ature : explaatory, parsimoious, predictive Most predictios require umerical values,

More information

The final exam will take place on Friday May 11th from 8am 11am in Evans room 60.

The final exam will take place on Friday May 11th from 8am 11am in Evans room 60. Mth 104: finl informtion The finl exm will tke plce on Fridy My 11th from 8m 11m in Evns room 60. The exm will cover ll prts of the course with equl weighting. It will cover Chpters 1 5, 7 15, 17 21, 23

More information

b a 2 ((g(x))2 (f(x)) 2 dx

b a 2 ((g(x))2 (f(x)) 2 dx Clc II Fll 005 MATH Nme: T3 Istructios: Write swers to problems o seprte pper. You my NOT use clcultors or y electroic devices or otes of y kid. Ech st rred problem is extr credit d ech is worth 5 poits.

More information

Basic Limit Theorems

Basic Limit Theorems Bsic Limit Theorems The very "cle" proof of L9 usig L8 ws provided to me by Joh Gci d it ws this result which ispired me to write up these otes. Absolute Vlue Properties: For rel umbers x, d y x x if x

More information

MA123, Chapter 9: Computing some integrals (pp )

MA123, Chapter 9: Computing some integrals (pp ) MA13, Chpter 9: Computig some itegrls (pp. 189-05) Dte: Chpter Gols: Uderstd how to use bsic summtio formuls to evlute more complex sums. Uderstd how to compute its of rtiol fuctios t ifiity. Uderstd how

More information

Math 140B - Notes. Neil Donaldson. September 2, 2009

Math 140B - Notes. Neil Donaldson. September 2, 2009 Mth 40B - Notes Neil Doldso September 2, 2009 Itroductio This clss cotiues from 40A. The mi purpose of the clss is to mke bsic clculus rigorous.. Nottio We will observe the followig ottio throughout this

More information

Exploring the Rate of Convergence of Approximations to the Riemann Integral

Exploring the Rate of Convergence of Approximations to the Riemann Integral Explorig the Rte of Covergece of Approximtios to the Riem Itegrl Lus Owes My 7, 24 Cotets Itroductio 2. Prelimiries............................................. 2.2 Motivtio..............................................

More information

10.5 Test Info. Test may change slightly.

10.5 Test Info. Test may change slightly. 0.5 Test Ifo Test my chge slightly. Short swer (0 questios 6 poits ech) o Must choose your ow test o Tests my oly be used oce o Tests/types you re resposible for: Geometric (kow sum) Telescopig (kow sum)

More information

POINTWISE ASYMPTOTICS FOR ORTHONORMAL POLYNOMIALS AT THE ENDPOINTS OF THE INTERVAL VIA UNIVERSALITY

POINTWISE ASYMPTOTICS FOR ORTHONORMAL POLYNOMIALS AT THE ENDPOINTS OF THE INTERVAL VIA UNIVERSALITY POINTWISE ASYMPTOTICS FOR ORTHONORMAL POLYNOMIALS AT THE ENDPOINTS OF THE INTERVAL VIA UNIVERSALITY D S LUBINSKY A We show tht uiverslity its d bouds for orthoorml polyomils imply poitwise symptotics for

More information

Dedicated to Prof. J. Kurzweil on the occasion of his 80th birthday

Dedicated to Prof. J. Kurzweil on the occasion of his 80th birthday 131 (2006 MATHEMATICA BOHEMICA No. 3, 233 260 THE HENSTOCK-KURZWEIL APPROACH TO YOUNG INTEGRALS WITH INTEGRATORS IN BV ϕ Boopogkrog Vryu, Tu Seg Chew, Sigpore (Received September 8, 2005 Dedicted to Prof.

More information

0 otherwise. sin( nx)sin( kx) 0 otherwise. cos( nx) sin( kx) dx 0 for all integers n, k.

0 otherwise. sin( nx)sin( kx) 0 otherwise. cos( nx) sin( kx) dx 0 for all integers n, k. . Computtio of Fourier Series I this sectio, we compute the Fourier coefficiets, f ( x) cos( x) b si( x) d b, i the Fourier series To do this, we eed the followig result o the orthogolity of the trigoometric

More information

Taylor Polynomials. The Tangent Line. (a, f (a)) and has the same slope as the curve y = f (x) at that point. It is the best

Taylor Polynomials. The Tangent Line. (a, f (a)) and has the same slope as the curve y = f (x) at that point. It is the best Tylor Polyomils Let f () = e d let p() = 1 + + 1 + 1 6 3 Without usig clcultor, evlute f (1) d p(1) Ok, I m still witig With little effort it is possible to evlute p(1) = 1 + 1 + 1 (144) + 6 1 (178) =

More information

Content: Essential Calculus, Early Transcendentals, James Stewart, 2007 Chapter 1: Functions and Limits., in a set B.

Content: Essential Calculus, Early Transcendentals, James Stewart, 2007 Chapter 1: Functions and Limits., in a set B. Review Sheet: Chpter Cotet: Essetil Clculus, Erly Trscedetls, Jmes Stewrt, 007 Chpter : Fuctios d Limits Cocepts, Defiitios, Lws, Theorems: A fuctio, f, is rule tht ssigs to ech elemet i set A ectly oe

More information

THE NATIONAL UNIVERSITY OF IRELAND, CORK COLÁISTE NA hollscoile, CORCAIGH UNIVERSITY COLLEGE, CORK SUMMER EXAMINATION 2005 FIRST ENGINEERING

THE NATIONAL UNIVERSITY OF IRELAND, CORK COLÁISTE NA hollscoile, CORCAIGH UNIVERSITY COLLEGE, CORK SUMMER EXAMINATION 2005 FIRST ENGINEERING OLLSCOIL NA héireann, CORCAIGH THE NATIONAL UNIVERSITY OF IRELAND, CORK COLÁISTE NA hollscoile, CORCAIGH UNIVERSITY COLLEGE, CORK SUMMER EXAMINATION 2005 FIRST ENGINEERING MATHEMATICS MA008 Clculus d Lier

More information

MATH301 Real Analysis (2008 Fall) Tutorial Note #7. k=1 f k (x) converges pointwise to S(x) on E if and

MATH301 Real Analysis (2008 Fall) Tutorial Note #7. k=1 f k (x) converges pointwise to S(x) on E if and MATH01 Real Aalysis (2008 Fall) Tutorial Note #7 Sequece ad Series of fuctio 1: Poitwise Covergece ad Uiform Covergece Part I: Poitwise Covergece Defiitio of poitwise covergece: A sequece of fuctios f

More information

FACULTY OF MATHEMATICAL STUDIES MATHEMATICS FOR PART I ENGINEERING. Lectures

FACULTY OF MATHEMATICAL STUDIES MATHEMATICS FOR PART I ENGINEERING. Lectures FACULTY OF MATHEMATICAL STUDIES MATHEMATICS FOR PART I ENGINEERING Lectures MODULE 0 FURTHER CALCULUS II. Sequeces d series. Rolle s theorem d me vlue theorems 3. Tlor s d Mcluri s theorems 4. L Hopitl

More information

Lecture 15: Consequences of Continuity. Theorem Suppose a; b 2 R, a<b, and f :[a; b]! R. If f is continuous and s 2 R is

Lecture 15: Consequences of Continuity. Theorem Suppose a; b 2 R, a<b, and f :[a; b]! R. If f is continuous and s 2 R is Lecture 15: Cosequeces of Cotiuity 15.1 Itermediate Value Theorem The followig result is kow as the Itermediate Value Theorem. Theorem Suppose a; b 2 R, a

More information

Supplemental Handout #1. Orthogonal Functions & Expansions

Supplemental Handout #1. Orthogonal Functions & Expansions UIUC Physics 435 EM Fields & Sources I Fll Semester, 27 Supp HO # 1 Prof. Steve Errede Supplemetl Hdout #1 Orthogol Fuctios & Epsios Cosider fuctio f ( ) which is defied o the itervl. The fuctio f ( )

More information

MA541 : Real Analysis. Tutorial and Practice Problems - 1 Hints and Solutions

MA541 : Real Analysis. Tutorial and Practice Problems - 1 Hints and Solutions MA54 : Real Aalysis Tutorial ad Practice Problems - Hits ad Solutios. Suppose that S is a oempty subset of real umbers that is bouded (i.e. bouded above as well as below). Prove that if S sup S. What ca

More information

UNIVERSITY OF CALICUT SCHOOL OF DISTANCE EDUCATION. (2014 Admn. onwards) III Semester. B.Sc. Mathematics CORE COURSE CALCULUS AND ANALYTICAL GEOMETRY

UNIVERSITY OF CALICUT SCHOOL OF DISTANCE EDUCATION. (2014 Admn. onwards) III Semester. B.Sc. Mathematics CORE COURSE CALCULUS AND ANALYTICAL GEOMETRY UNIVERSITY OF CALICUT SCHOOL OF DISTANCE EDUCATION (0 Adm. owrds) III Semester B.Sc. Mthemtics CORE COURSE CALCULUS AND ANALYTICAL GEOMETRY Questio Bk & Aswer Key. l l () =... 0.00 b) 0 c). l d =... c

More information

A) is empty. B) is a finite set. C) can be a countably infinite set. D) can be an uncountable set.

A) is empty. B) is a finite set. C) can be a countably infinite set. D) can be an uncountable set. M.A./M.Sc. (Mathematics) Etrace Examiatio 016-17 Max Time: hours Max Marks: 150 Istructios: There are 50 questios. Every questio has four choices of which exactly oe is correct. For correct aswer, 3 marks

More information

BC Calculus Review Sheet

BC Calculus Review Sheet BC Clculus Review Sheet Whe you see the words. 1. Fid the re of the ubouded regio represeted by the itegrl (sometimes 1 f ( ) clled horizotl improper itegrl). This is wht you thik of doig.... Fid the re

More information

18.01 Calculus Jason Starr Fall 2005

18.01 Calculus Jason Starr Fall 2005 18.01 Clculus Jso Strr Lecture 14. October 14, 005 Homework. Problem Set 4 Prt II: Problem. Prctice Problems. Course Reder: 3B 1, 3B 3, 3B 4, 3B 5. 1. The problem of res. The ciet Greeks computed the res

More information

HIGHER SCHOOL CERTIFICATE EXAMINATION MATHEMATICS 3 UNIT (ADDITIONAL) AND 3/4 UNIT (COMMON) Time allowed Two hours (Plus 5 minutes reading time)

HIGHER SCHOOL CERTIFICATE EXAMINATION MATHEMATICS 3 UNIT (ADDITIONAL) AND 3/4 UNIT (COMMON) Time allowed Two hours (Plus 5 minutes reading time) HIGHER SCHOOL CERTIFICATE EXAMINATION 999 MATHEMATICS 3 UNIT (ADDITIONAL) AND 3/ UNIT (COMMON) Time llowed Two hours (Plus 5 miutes redig time) DIRECTIONS TO CANDIDATES Attempt ALL questios. ALL questios

More information

Basic Maths. Fiorella Sgallari University of Bologna, Italy Faculty of Engineering Department of Mathematics - CIRAM

Basic Maths. Fiorella Sgallari University of Bologna, Italy Faculty of Engineering Department of Mathematics - CIRAM Bsic Mths Fiorell Sgllri Uiversity of Bolog, Itly Fculty of Egieerig Deprtmet of Mthemtics - CIRM Mtrices Specil mtrices Lier mps Trce Determits Rk Rge Null spce Sclr products Norms Mtri orms Positive

More information

denominator, think trig! Memorize the following two formulas; you will use them often!

denominator, think trig! Memorize the following two formulas; you will use them often! 7. Bsic Itegrtio Rules Some itegrls re esier to evlute th others. The three problems give i Emple, for istce, hve very similr itegrds. I fct, they oly differ by the power of i the umertor. Eve smll chges

More information

FINAL EXAMINATION IN FOUNDATION OF ANALYSIS (TMA4225)

FINAL EXAMINATION IN FOUNDATION OF ANALYSIS (TMA4225) Norwegia Uiversity of Sciece ad Techology Departmet of Mathematical Scieces Page of 7 Cotact durig exam: Eugeia Maliikova (735) 52 57 FINAL EXAMINATION IN FOUNDATION OF ANALYSIS (TMA4225) Moday, December

More information

DEPARTMENT OF ELECTRICAL &ELECTRONICS ENGINEERING SIGNALS AND SYSTEMS. Assoc. Prof. Dr. Burak Kelleci. Spring 2018

DEPARTMENT OF ELECTRICAL &ELECTRONICS ENGINEERING SIGNALS AND SYSTEMS. Assoc. Prof. Dr. Burak Kelleci. Spring 2018 DEPARTMENT OF ELECTRICAL &ELECTRONICS ENGINEERING SIGNALS AND SYSTEMS Assoc. Prof. Dr. Bur Kelleci Sprig 8 OUTLINE The Z-Trsform The Regio of covergece for the Z-trsform The Iverse Z-Trsform Geometric

More information