MEDICINAL CHEMISTRY I EXAM #1
|
|
- Belinda Griffith
- 5 years ago
- Views:
Transcription
1 MEDICIAL CEMISTRY I EXAM #1 1 September 28, 2007 ame SECTI A. Answer each question in this section by writing the letter corresponding to the best answer on the line provided (2 points each; 50 points total) 1. The compound shown below: I Is a cyclic urea II Is piperidine-2,5-dione III Is a cyclic imide 2. The compound illustrated below: C 3 I 3 C II III C 3 as cis-1,4-dimethyl groups as trans-1,2-dimethyl groups Is drawn in its lowest energy conformation 3. For the structures illustrated below: I Compound A has a larger pk a than 3 C C compound B II Compound A has a higher log P than compound B III The K a for Compound B is larger than the K a for Compound A
2 4. The compound illustrated below: I Is 1-Benzyl-4-benzoylisoquinoline II Is 1-Benzoyl-4-benzylisoquinoline III Is 4-Benzoylbenzo[a]isoquinoline 2 5. The compound illustrated below: I Is aromatic II as the lone pair of electrons (on the nitrogen), in the plane of the ring III Is non-aromatic 6. The compound shown below: 3 C I Is 2-2,7-dimethyl-5,6,7,10- tetrahydrooxecine C 3 II as two alkenes that have (E)- stereochemistry III Is antiaromatic
3 7. For the compounds illustrated below: C 3 C 3 I Compound A has four chiral centers II Compound A is a diastereomer of Compound B III Compound B is the enantiomer of Compound A 3 C C 3 3 C C The compound illustrated below: C 3 I Is 10-methylphenothiazine II as a conjugate acid with a pk a of 2 III Is 5-methylphenothiazine S 9. The compound illustrated below: I Is 50% ionized at p 12 II Is the conjugate base of 1,3,4,5-tetrahydro-2benzo[b]azepin-2-one III Is 100% ionized at p Consider the two structures shown below: F 3 C C 3 3 C C 3 I Compound A has a lower log P than Compound B II Compound B is a stronger base than Compound A III Compound A has a higher log P than Compound B
4 11. The compound shown below: I Contains an amine II Contains an imine III as a conjugate acid with a pk a = The compound illustrated below: I Is aromatic II Is a cation derived from 1,3,5-cycloheptatriene III Is 1-azepine 13. In the compound illustrated below: 3 C C 3 I The lone pair of electrons on the nitrogen is in a plane C C that is perpendicular to that which contains the two methyl 3 C groups attached to carbon. II The lone pair of electrons on the nitrogen is in the plane of the two methyl groups attached to carbon. III The carbon that is double bonded to both carbon and nitrogen has sp 2 hybridization 14. The compound illustrated below: C 3 C 3 I as an optical rotation of 0 2 C 2 4 C 2 2S,4S-2,4-dimethylpentane-1,5-diol II Is 2R,4R-2,4-dimethylpentane-1,5-diol III as the opposite optical rotation of
5 15. In the structure illustrated below: I The two carbonyl groups are in perpendicular planes II The spiro carbon (the carbon that is common to both rings) is sp hybridized III The two carbonyl groups are in the same plane The compound illustrated below: C I as 1S,4S stereochemistry II as a 3,4-dichlorophenyl substituent that is trans to a methylamino substituent III as 1R,4R stereochemistry 17. For the structures illustrated below: 2 I Compound A is a resonance structure of Compound B II Compound A is a tautomer of Compound B III Compounds A and B both have pk b values = For the two compounds illustrated below: I Compound B is a stronger base than compound A II Compound A is a stronger base than Compound B III Compound B has a conjugate acid with a pk a = 4
6 19. The compound illustrated below: C C C 3 Valine I II III Is D-Valine as S-stereochemistry Is L-Valine For the structures shown below: I Compound A is a weaker base than Compound B II Compound A is a stronger base than Compound B III The chlorine in Compound B stabilizes its conjugate acid form by resonance 21. In the compound illustrated below: I A is the Pro-R hydrogen II A and B are enantiotopic III B is the Pro-R hydrogen A B a) only 22. The structure shown below: I Is 2,7-Dimethyl-10-thioxanthene II Is 3,7-Dimethylphenothiazine 3 C S C 3 III Is 3,6-Dimethyl-9-thioxanthene
7 23. For the structures shown below: I Structure A is the anti- conformation of 1,2- dichloroethane II Structure B is the gauche conformation of 1,2- dichloroethane III Structure B is higher in energy than structure A The compound illustrated below: C 2 I Is 50% ionized at p 4 II Is 50% ionized at p 9 III Is 50% ionized at p For the compounds illustrated below: I Compound A has a pk b = 12 II Compound B has a pk b = 10 III The nitrogen of Compound A is sp 2 hybridized
8 SECTI B. 15 Points Total For the following pair of compounds assign the proper stereochemistry (R or S) at each chiral center in each molecule. Then indicate on the line the relationship of the compounds to each other by writing the word EATIMER, DIASTEREMER, R SAME CMPUD. (5 Points). 2 C C 2 C 2 Relationship 2. Assign the stereochemistry of the compound shown below by clearly writing the letter E- or Z- next to each assignable double bond, as appropriate. (2 Points). C C 2 3. The following compound is the sugar D-Idose. It has an optical rotation [ ] = Upon reaction with and SC 2 C 2 C 2 S the aldehyde group of D-Idose is converted into a dithioacetal and that compound hash a melting point of 141 C and an optical rotation [ ] = Indicate the absolute configuration at each chiral center of D-Idose (R or S). Then answer the questions below pertaining to Compound B. (8 Points). C C 2 C C 2 S S C 2 S S C 2 D-Idose Compound B D-Idose dithioacetal mp = 141 o C [ ] = o Dithioacetal of Compound B a) What is the relationship (enantiomer, diastereomer, or same compound) of Compound B to D-Idose? b) Would the optical rotation of Compound B be: +15.8, -15.8, +51.0, 0, or is there not enough information to determine it?
9 % of Maximal Response c) Explain your answer from question b). 9 d) If Compound B was allowed to react at its aldehyde group with and SC 2 C 2 C 2 S to form a dithioacetal would that compound have a melting point of: 141 C, -141 C, 0 C, or is there not enough information to determine what the melting point would be? SECTI C. For each of the following fill in the blank with the appropriate response. (5 Points). 1) Refer to the graph shown below and then write on the line provided which of the following statements is false? a) Drug A is less potent than Drug B b) Drug B has equal efficacy as Drug A c) Drug B is less potent than Drug A 100 A B 50 0 log dose 2) n the line provided write the letter of the phrase which BEST completes the following statement: The critical portion of the structure of a drug that binds to the receptor is called the a) hot spot b) pharmacophore c) active site. 3) n the line provided fill in the missing phrase. The four major steps in drug discovery are: a) Target identification and selection b) Target optimization c) Lead identification and d). 4) n the line provided write whether the following statement is True or False. A thiophene ring can be used as a bioisosteric replacement for a phenyl ring. 5) n the line provided write whether the following statement is True or False. The efficacy of a ew Chemical Entity (CE) is first evaluated during Phase II clinical trials.
10 10 SECTI D. For each of the following pairs of compounds circle the one that has the higher log P. (5 points). a) 3 C 3 C b) c) (C 3 ) 4 (C 3 ) 2 C 2 C 3 d) C 3 C 3 C 3 C 3 e) F F SECTI E. For each of the following systematic names, draw the correct chemical structure, including stereochemistry wherever indicated. Partial credit will be given but you will lose points for incorrect chemical symbols, hydrogens missing from heteroatoms, hydrogens missing from carbons labeled as C, and for having too many bonds to an atom. (25 Points) [1,4]Diazepino[1,2-a]indole, 2,3,4,5-tetrahydro-, Monohydrochloride
11 11 2. (E)-4-[2-Chloro-4-(4-methoxyphenyl)but-3-en-1-yl]morpholine 3. Butyl 3-Phenyl-3-(1-piperidinyl)propionate, (S)-enantiomer 4. 2-Amino-6-ethyl-5,6,7,8-tetrahydro-4-oxazolo[4,5-d]azepine 5. (Z)-3-[8-Chloro-5-dibenzo[b,f]azepin-10(11)-ylidene]-,-dimethylpropanamine
MEDICINAL CHEMISTRY I EXAM #1
MEDICIAL CEMISTRY I EXAM #1 1 September 30, 2005 ame SECTI A. Answer each question in this section by writing the letter corresponding to the best answer on the line provided (2 points each; 50 points
More informationPHARMACEUTICAL CHEMISTRY EXAM #1 Februrary 21, 2008
PHARMACEUTICAL CHEMISTRY EXAM #1 Februrary 21, 2008 1 Name SECTION B. Answer each question in this section by writing the letter corresponding to the best answer on the line provided (2 points each; 60
More informationCHEMpossible. 261 Exam 1 Review
CHEMpossible 261 Exam 1 Review A. Rank the following carboxylic acids from least acidic to most acidic: B. Draw the line-angle formulas for three acylic (non-cyclic) esters with the molecular formula C
More informationC. Correct! The abbreviation Ar stands for an aromatic ring, sometimes called an aryl ring.
Organic Chemistry - Problem Drill 05: Drawing Organic Structures No. 1 of 10 1. What does the abbreviation Ar stand for? (A) Acetyl group (B) Benzyl group (C) Aromatic or Aryl group (D) Benzoyl group (E)
More information5. Stereochemical Analysis. 7. Dipole Moments and Inductive versus Resonance Effects. 8. Types of isomers from a given formula. 9. Physical Properties
hem 201 Sample Midterm Beauchamp ame Problems Points redit 1. Functional Group omenclature (1 large structure) 2. Lewis Structures, Resonance, Formal harge 3. yclohexane onformations, 2 substituents, ewman
More informationCHEMISTRY 112A FALL 2015 EXAM 1 SEPTEMBER 27, 2016 NAME- WRITE BIG STUDENT ID: SECTION AND/OR GSI IF YOU ARE IN THE LABORATORY COURSE:
CHEMISTRY 112A FALL 2015 EXAM 1 SEPTEMBER 27, 2016 NAME- WRITE BIG STUDENT ID: SECTIN AND/R GSI IF YU ARE IN THE LABRATRY CURSE: You will have 75 minutes in which to work. BE NEAT! Non-legible structure
More informationChem 201 Sample Midterm Beauchamp
hem 201 Sample Midterm Beauchamp Exams are designed so that no one question will make or break you. The best strategy is to work steadily, starting with those problems you understand best. Partial credit
More informationCHEMISTRY 31 Name: KEY Exam #1 100 pts 1. (6 pts) Provide the complete IUPAC name for each of the following compounds:
CEMISTRY 31 ame: KEY Exam #1 100 pts 1. (6 pts) Provide the complete IUPAC name for each of the following compounds: (1S,3S)-1-bromo-3-butylcyclopentane 3,4-diethyl-2,2-dimethyloctane 1-cyclopropyl-2-methylcyclobutane
More informationKEY I. (28 points) i) NOTE: sp-hybridized carbanions make good nucleophiles for substitution reactions. Product A C C CH 3. Product B.
I. (8 points) Page 1 A. omplete the following as necessary NT: sp-hybridized carbanions make good nucleophiles for substitution reactions NaN N Na Na (optional) i equivalents of Product A Product B a)
More informationPLEASE DO NOT WRITE ON THE EXAM (EVEN YOUR NAME) UNTIL TOLD TO START! Student ID # CHEM 8A, Organic Chemistry EXAM 1 (300 points)
PLEASE D T WRITE TE EXAM (EVE YUR AME) UTIL TLD T START! UCSC, Binder ame Student ID # CEM 8A, rganic Chemistry EXAM (300 points) In each of the following problems, use your knowledge of organic chemistry
More information(1) Check to see if the two compounds are identical. (2) Recall the definitions of stereoisomers, conformational isomers, and constitutional isomers.
MCAT Organic Chemistry Problem Drill 04: Stereochemistry Question No. 1 of 10 Question 1. Determine the relationship of the molecules shown: O O Question #01 (A) Identical (B) Constitutional isomers (C)
More informationCHE 321 Summer 2010 Exam 2 Form Choose the structure(s) that represent cis-1-sec-butyl-4-methylcyclohexane. I II III
CE 321 Summer 2010 Exam 2 orm 2 Multiple Choice Questions: 60 points 1. Choose the structure(s) that represent cis-1-sec-butyl-4-methylcyclohexane. I II III (A) I only (B) II only (C) I and II only II
More informationOrganic Chemistry II KEY March 25, a) I only b) II only c) II & III d) III & IV e) I, II, III & IV
rganic Chemistry II KEY March 25, 2015 Exam 2: VERSIN A 1. Which of the following compounds will give rise to an aromatic conjugate base? E a) I only b) II only c) II & III d) III & IV e) I, II, III &
More informationThe wise does at once what the fool does at last.
hem 201 Midterm all, 2018 Beauchamp ame Problems Points redit 1. unctional Group omenclature (1 large structure) 30 2. esonance, ormal harge, Arrows 18 3. yclohexane onformations, ewman Projections 30
More informationCHCl (vinyl chloride, part of new car smell )
ame Key 1) (20 points) Draw a Lewis dot structure for each of the following molecules; show all lone pairs. Indicate the hybridization at all atoms except hydrogen, chlorine, and fluorine. (a) 2 (b) C
More informationCHEMISTRY 341. Final Exam Tuesday, December 16, Problem 1 15 pts Problem 9 8 pts. Problem 2 5 pts Problem pts
CEMISTRY 341 Final Exam Tuesday, December 16, 1997 Name NAID Problem 1 15 pts Problem 9 8 pts Problem 2 5 pts Problem 10 21 pts Problem 3 26 pts Problem 11 15 pts Problem 4 10 pts Problem 12 6 pts Problem
More information1. methyl 2. methylene 3. methine 4. primary 5. secondary 6. tertiary 7. quarternary 8. isopropyl
hem 201 Sample Midterm Beauchamp Exams are designed so that no one question will make or break you. The best strategy is to work steadily, starting with those problems you understand best. Make sure you
More informationChem Final Examination August 7, 2004
Chem 281 2004-2 Final Examination August 7, 2004 Name: Student Number: Note: You are allowed to use models for this exam. Notes, textbooks and calculators are strictly prohibited. Write your final answers
More informationChem 201 Midterm Winter, 2013 Beauchamp
hem 0 Midterm Winter, 0 Beauchamp Name Problems Points redit. Functional Group Nomenclature. Degrees of Unsaturation & Functional Groups or Various Nomenclature Terms. D structure, Functional Groups 0.
More informationCl 7 8 N 9 H 6 HS 4. 2-(5,5-dimethyl-3-chlorocyclopent-2-enyl)-5-oxo-6-methyl-7-cyanoheptyl 2-hydroxy-3,3-dimethyl-4-(1-mercapto-
hem 0 Sample Midterm Beauchamp Exams are designed so that no one question will make or break you. The best strategy is to work steadily, starting with those problems you understand best. Partial credit
More information(a) (10 points) Fill in any hydrogens not shown and indicate the molecular formula of the compound in the box provided.
1. Fundamentals (a) (10 points) Fill in any hydrogens not shown and indicate the molecular formula of the compound in the box provided. (b) (10 points) Draw a Lewis structure for each of the following
More informationHour Examination # 1
CHEM 2410 Organic Chemistry 1 Fall 2017 Exam # 1 Problem Booklet Page 1 of 11 CHEM 2410 Organic Chemistry 1 Fall 2017 Exam Booklet No. Instructors: Paul Bracher & Erin Whitteck Hour Examination # 1 Wednesday,
More informationChapter 25 Organic and Biological Chemistry
Chapter 25 Organic and Biological Chemistry Organic Chemistry The chemistry of carbon compounds. Carbon has the ability to form long chains. Without this property, large biomolecules such as proteins,
More information13. Free Radical Chemistry
hem 201 Study Session Final Beauchamp ame Problems Points redit 1. Functional Group omenclature (1 large structure) 2. Various possibilities: Types of Isomers, Degrees of Unsaturation, common nomenclature,
More informationProblems. 8. Stereochemical Analysis Physical Properties, Forces of Interaction Resonance, Curved Arrows, Formal Charge, Polarity 15
hem 201 Midterm Exam Winter, 2017 Beauchamp Name Problems Points 1. Functional Group Nomenclature (1 large structure) 30 2. Degrees of Unsaturation & Functional Groups (many different functional groups)
More information(c) The intermediate carbocation resulting from 3-bromobut-1-ene is resonance stabilized.
KT121 Sem II 09/10 SETIN B: 1.(a) Name of mechanism: E1 elimination. 7 marks (b) (i) + 3 3 3 (ii) + 3 (iii) l 8 marks (c) The intermediate carbocation resulting from 3-bromobut-1-ene is resonance stabilized.
More informationERRATA. p. 2 In the second line from the bottom, the expression should be , not
ERRATA Study Guide and Solutions Manual, Fifth Edition by Marc Loudon and Joseph G. Stowell to accompany Organic Chemistry, 5th Edition, by Marc Loudon Date of this release: May 2, 2011 Items marked with
More informationProblems Points Credit
Chem 201 Midterm Winter, 2018 Beauchamp ame Problems Points Credit 1. Functional Group omenclature (1 large structure) 30 2. Resonance, Formal Charge, Arrows 18 3. Properties of Atoms, Logic Arguments
More informationExperiment 8 Optical Isomers. In this experiment you will be given the opportunity to see the 3-dimensional aspects of
Experiment 8 Optical Isomers In this experiment you will be given the opportunity to see the 3-dimensional aspects of stereochemistry and optical isomers. Previously in class you were exposed to the concept
More informationERRATA. Chapter 1 p. 2 In the second line from the bottom, the expression should be , not
ERRATA Study Guide and Solutions Manual, Fifth Edition by Marc Loudon and Joseph G. Stowell to accompany Organic Chemistry, 5th Edition, by Marc Loudon Date of this release: January 12, 2015 Items marked
More informationExam 1 (Monday, July 6, 2015)
Chem 231 Summer 2015 Assigned Homework Problems Last updated: Friday, July 24, 2015 Problems Assigned from Essential Organic Chemistry, 2 nd Edition, Paula Yurkanis Bruice, Prentice Hall, New York, NY,
More informationCHEM 240: Survey of Organic Chemistry at North Dakota State University Midterm Exam 01 - Tue, 23 Sep 2014!! Name:! KEY!
EM 240: Survey of rganic hemistry at North Dakota State University Midterm Exam 01 - Tue, 23 Sep 2014!! Name:! KEY! Please read through each question carefully and answer in the spaces provided. A good
More informationEXAMINATION 1 Chemistry 3A SID #:
EXAMINATION hemistry A Name: Print first name before second! Use capital letters! SID #: Peter Vollhardt February, 08 GSI (if you are taking hem AL): Please provide the following information if applicable.
More information1. What are the respective hybridizations of the atoms numbered 1 to 4 in this compound?
CEM 331: Chapter 1/2: Structures (Atoms, Molecules, Bonding) 1. What are the respective hybridizations of the atoms numbered 1 to 4 in this compound? N C 2 C N C 2 C N 1 2 3 4 1: three sigma bonds and
More information2. 2D Lewis structure (large structure with possible formal charge) 20
hem 201 Final Fall, 2017 Beauchamp ame Problems Points redit 1. Functional Group omenclature (1 large structure) 30 2. 2D Lewis structure (large structure with possible formal charge) 20 3. yclohexane
More informationMore Nomenclature: Common Names for Selected Aromatic Groups. Aryl = Ar = aromatic group. It is a broad term, and includes any aromatic rings.
More Nomenclature: Common Names for Selected Aromatic Groups Phenyl group = or Ph = C 6 H 5 = Aryl = Ar = aromatic group. It is a broad term, and includes any aromatic rings. Benzyl = Bn = It has a -CH
More informationChapter 2: An Introduction to Organic Compounds
Chapter : An Introduction to Organic Compounds I. FUNCTIONAL GROUPS: Functional groups with similar structure/reactivity may be "grouped" together. A. Functional Groups With Carbon-Carbon Multiple Bonds.
More informationCHEM1902/ N-9 November 2014
CEM1902/4 2014-N-9 November 2014 The elimination of 2 O from alcohol A can form the isomeric alkenes B and C. Elimination of Br from the alkyl halide D can generate the same two alkenes. 7 Assign the absolute
More informationCHEM 341: Organic Chemistry I at North Dakota State University Midterm Exam 01 - Fri, Feb 10, 2012!! Name:!
CEM 341: rganic Chemistry I at North Dakota State University Midterm Exam 01 - Fri, Feb 10, 2012!! Name:! Please read through each question carefully and answer in the spaces provided. A good strategy
More informationChem 261 Dec 6, 2017
209 Chem 261 Dec 6, 2017 REVIEW: Example: K!! + 3 C + 3 C K tert-butoxide (an alkoxide) methanol tert-butanol pka = 16 pka = 19 methoxide stronger base stronger acid (lower pka, more acidic) weaker acid
More informationChemistry 250B Final Exam Answer Key December 19, 2008
Name: NSWER KEY 1 hemistry 250 Final Exam nswer Key ecember 19, 2008 Show non-zero formal charges on all atoms for all structures. There are 11 pages. 1. (42 pts) omplete the following reactions. Show
More informationExam (6 pts) Show which starting materials are used to produce the following Diels-Alder products:
Exam 1 Name CHEM 212 1. (18 pts) Complete the following chemical reactions showing all major organic products; illustrate proper stereochemistry where appropriate. If no reaction occurs, indicate NR :
More informationEXAMINATION 1 Chemistry 3A. Making up an I Grade If you are, please indicate the semester during which you took previous Chem 3A and the Instructor
1 EXAMINATION 1 Chemistry 3A Key Name: Print first name before second! Use capital letters! SID #: Peter Vollhardt February 28, 2017 GSI (if you are taking Chem 3AL): Please provide the following information
More informationStereochemistry Terminology for two pure isomeric compounds, both of which are chiral? A pair of stereoisomers
Name Last, irst STEECEMISTY This handout will help you understand stereoisomerism, naming conventions and relationships between stereoisomers. I hope that you will use this to help you study for exam 1.
More informationHour Examination # 1
CHEM 346 Organic Chemistry I Fall 2013 Hour Examination # 1 Solutions Key Page 1 of 15 CHEM 346 Organic Chemistry I (for Majors) Instructor: Paul J. Bracher Hour Examination # 1 Wednesday, September 25
More informationHomework 2 Organic Chemistry MCAT Review Summer 2012 Brent Iverson
omework rganic hemistry MAT eview ummer 0 ent Iverson . omplete the following two structures by adding appropriate numbers of lone pair electrons, atoms, and formal charges to the atoms in the boxes. You
More informationCalculate a rate given a species concentration change.
Kinetics Define a rate for a given process. Change in concentration of a reagent with time. A rate is always positive, and is usually referred to with only magnitude (i.e. no sign) Reaction rates can be
More informationDr. Steven Pedersen July 28, Chemistry 3A. Midterm 2
Dr. Steven Pedersen July 28, 2015 hemistry A Midterm 2 Student name: ANSWER KEY Student signature: Problem 1 Problem 2 Problem Problem 4 Problem 5 Problem 6 Problem 7 Total Points (16 pts) (4 pts) (2 pts)
More informationProblem Points Credit. 1. Nomenclature (one structure) 30
alifornia State Polytechnic University, Pomona 1 hem 2010 Midterm #2 Fall, 2018 Beauchamp ame KY (int your name legibly) oblem Points redit 1. omenclature (one structure) 30 2. xplain relative stabilities
More informationCHEM 343 Principles of Organic Chemistry II Summer Instructor: Paul J. Bracher. Quiz # 3. Monday, July 21 st, :30 a.m.
CHEM 343 Principles of Organic Chemistry II Summer 2014 Quiz # 3 Solutions Key Page 1 of 9 CHEM 343 Principles of Organic Chemistry II Summer 2014 Instructor: Paul J. Bracher Quiz # 3 Monday, July 21 st,
More informationLesson 4. Molecular Geometry and Isomers II. Lesson 4 CH 3 HO H OH
Lesson 4 Molecular Geometry and Isomers II 4 Lesson 4 3 O O 3 Organic Edge A. Structural Isomers (onstitutional Isomers) 1. Structural isomers are molecules that share the same molecular formula but differ
More informationFinal Exam Professor R. Hoenigman
I pledge to uphold the CU onor Code: CEM 3311-200 Fall 2006 Final Exam Professor. oenigman Average Score = 145 igh Score = 235 Low Score = 27 Signature Name (printed) Last four digits of your student ID
More information2.0 h; 240 points please print clearly Dr. Kathleen Nolta Signature. Problem Points Score GSI I 42 II 35 III 36 IV 46 V 42 VI 39 Total 240
hemistry 10 irst ame inal Examination Last ame.0 h; 0 points please print clearly Dr. Kathleen olta ignature UM ID # Problem Points core GI I II 5 III IV V VI 9 Total 0 Precision in drawing counts. heck
More informationCHEM 2430 Organic Chemistry I Fall Instructor: Paul Bracher. Final Examination
CHEM 2430 Organic Chemistry I Fall 2015 Final Exam Solutions Key Page 1 of 10 CHEM 2430 Organic Chemistry I Fall 2015 Instructor: Paul Bracher Final Examination Friday, December 11 th, 2015 12:00 1:50
More informationChemistry 14C Spring 2016 Final Exam Part B Page 1
hemistry 14 Spring 2016 Final Exam Part B Page 1 In lecture we discussed the possibility that the first cells may have been formed in boiling mud puddles, which have been shown (in the lab) to produce
More informationO N N. electrons in ring
ame I. ( points) Page 1 A. The compound shown below is a commonly prescribed antifungal drug. It belongs to a category of compounds known as triazoles. Analyze the geometry and other properties for various
More information"Friendship is one mind in two bodies." Mencius
California State Polytechnic University, Pomona 1 Fall, 2014 Midterm Exam Chem 314 Beauchamp Chem 314 Name Problem Points Credit 1. Nomenclature 30 2. 2D Lewis structures 20 3. 3D Structures, Formal Charge
More informationLearning Guide for Chapter 17 - Dienes
Learning Guide for Chapter 17 - Dienes I. Isolated, conjugated, and cumulated dienes II. Reactions involving allylic cations or radicals III. Diels-Alder Reactions IV. Aromaticity I. Isolated, Conjugated,
More information10. Amines (text )
2009, Department of Chemistry, The University of Western Ontario 10.1 10. Amines (text 10.1 10.6) A. Structure and omenclature Amines are derivatives of ammonia (H 3 ), where one or more H atoms has been
More informationForm 0 CHE321 Exam 1 9/26/2006
CE321 Exam 1 9/26/2006 Multiple Choice Questions. 60 points 1. Draw the two best contributing structures for methylimidate. To get you started a partial structure is given. C C C Choose the incorrect statement.
More informationChem 14C Lecture 2 Spring 2017 Final Part B Solutions Page 1
hem 14 Lecture 2 Spring 2017 Final Part B Solutions Page 1 Statistics: igh score, average, and low score will be posted on the course web site after exam grading is complete. Some questions have more than
More informationChapter 6. Isomers and Stereochemistry
Chapter 6. Isomers and Stereochemistry Learning objectives: 1. Differentiate chiral and achiral molecules. 2. Recognize and draw structural isomers (constitutional isomers), stereoisomers including enantiomers
More informationOrganic Chemistry II KEY March 27, 2013
rganic Chemistry II KEY March 27, 2013 Exam 2: VERSI C 1. Rank the dienophiles from most reactive to least reactive in the Diels Alder reaction (most>least) E I II III IV > II > III > IV b) III > I > II
More informationBenzene a remarkable compound. Chapter 14 Aromatic Compounds. Some proposed structures for C 6 H 6. Dimethyl substituted benzenes are called xylenes
Benzene a remarkable compound Chapter 14 Aromatic Compounds Discovered by Faraday 1825 Formula C 6 H 6 Highly unsaturated, but remarkably stable Whole new class of benzene derivatives called aromatic compounds
More informationChemistry 3719 Fall 2000 Exam 1 Name: KEY. Anti Gauche Eclipsed 1 Eclipsed 2
hemistry 3719 Fall 2000 Exam 1 Name: KEY This exam is worth 100 points and you have 50 minutes to complete it. You may use molecular models to help you with any of the problems. Good luck. 1. (8 pts) 1,2-Dibromoethane
More informationExam Analysis: Organic Chemistry, Midterm 1
Exam Analysis: Organic Chemistry, Midterm 1 1) TEST BREAK DOWN: There are three independent topics covered in the first midterm, which are hybridization, structure and isomerism, and resonance. The test
More informationOrganic Chemistry II KEY March 27, Which of the following reaction intermediates will form the fastest in the reaction below?
rganic Chemistry II KEY March 27, 2013 Exam 2: VERSI D 1. Which of the following reaction intermediates will form the fastest in the reaction below? C 1 equiv a 2 a) IV b) III c) II d) II & III e) I I.
More informationCHEM 261 HOME WORK Lecture Topics: MODULE 1: The Basics: Bonding and Molecular Structure Text Sections (N0 1.9, 9-11) Homework: Chapter 1:
CHEM 261 HOME WORK Lecture Topics: MODULE 1: The Basics: Bonding and Molecular Structure Atomic Structure - Valence Electrons Chemical Bonds: The Octet Rule - Ionic bond - Covalent bond How to write Lewis
More informationName: (Print your name) Chem Spring, Midterm 1
ame: (Print your name) hem 2010 Spring, 2019 Midterm 1 hem 2010 Midterm 1 Spring, 2019 Beauchamp ame Problems Points redit 1. Functional Group omenclature (1 large structure) 30 2. Lewis Structures, Resonance,
More informationStereochemistry. Based on McMurry s Organic Chemistry, 6 th edition
Stereochemistry Based on McMurry s Organic Chemistry, 6 th edition Stereochemistry! Some objects are not the same as their mirror images (technically, they have no plane of symmetry)! A right-hand glove
More informationCH 3 C 2 H 5. Tetrahedral Stereochemistry
Ch 5 Tetrahedral Stereochemistry Enantiomers - Two non-superimposable mirror image molecules - They are stereoisomers with the same atoms and bonds, but different spatial geometries. - The two molecules
More informationThree-Dimensional Structures of Drugs
Three-Dimensional Structures of Drugs Moore, T. (2016). Acids and Bases. Lecture presented at PHAR 422 Lecture in UIC College of Pharmacy, Chicago. Chiral drugs are sometimes sold as one enantiomer (pure
More information5. (6 pts) Show how the following compound can be synthesized from the indicated starting material:
Exam 2 Name CHEM 212 1. (36 pts) Complete the following chemical reactions showing all major organic products; illustrate proper stereochemistry where appropriate. If no reaction occurs, indicate NR :
More informationOrganic Chemistry 1 CHM 2210 Exam 2 (October 10, 2001)
Organic Chemistry 1 CM 2210 Exam 2 (October 10, 2001) Name (print): _ Signature: _ Student ID Number: _ There are 10 multiple choice problems (4 points each) on this exam. Record the answers to the multiple
More information"You can't go back and change the beginning, but you can start where you are and change the ending." C.S. Lewis. Chem 201 Midterm.
hem 201 Midterm Fall, 2017 Beauchamp ame Problems Points redit 1. Functional Group omenclature (1 large structure) 2. Types of Isomers, Degrees of Unsaturation or common nomenclature terms or functional
More informationBenzene and Aromaticity
Benzene and Aromaticity Why this Chapter? Reactivity of substituted aromatic compounds is tied to their structure Aromatic compounds provide a sensitive probe for studying relationship between structure
More informationProblems. 8. Stereochemical Analysis Physical Properties, Forces of Interaction Resonance, Curved Arrows, Formal Charge, Polarity 15
hem 0 Midterm Exam Winter, 07 eauchamp Name Problems Points. Functional Group Nomenclature ( large structure) 0. Degrees of Unsaturation & Functional Groups (many different functional groups) or Various
More informationUCSC, Binder. CHEM 8A, Organic Chemistry I Summer 18 EXAM 1 (300 points)
UCSC, Binder Name CEM 8A, rganic Chemistry I Summer 18 EXAM 1 (300 points) 1 (40) 2 (50) 3 (65) 4 (45) 5 (45) 6 (50) Total (300) % In each of the following problems, use your knowledge of organic chemistry
More informationChem 201 Final. Beauchamp
hem 201 Final Winter, 2018 Beauchamp ame KEY Problems Points redit 1. Functional Group omenclature (1 large structure) 0 2. Lewis tructures, esonance, Formal harge 18. yclohexane onformations, 2 substituents,
More informationORGANIC CHEMISTRY I MIDTERM TEST
Concordia University CEM 221 Winter 2005 Dr. C. Rogers, Section 02 --- MIDTERM TEST RGANIC CEMISTRY I MIDTERM TEST INSTRUCTINS: PLEASE READ TIS PAGE WILE WAITING T START YUR EXAM. This test paper includes
More informationSTEREOCHEMISTRY A STUDENT SHOULD BE ABLE TO:
A STUDENT SHOULD BE ABLE TO: STEREOCHEMISTRY 1. Determine the relationship between two given structures (which may be any of the kinds below). Also, define the following terms, and give examples of pairs
More informationFIRST HOUR EXAMINATION
Name: ANSWERS CEM 331 FIRST UR EXAMINATIN All answers should be written on the exam in the spaces provided. Clearly indicate your answers in the spaces provided. If I have to guess as to what or where
More informationExam. Name. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Exam Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) Which of the following statements is incorrect about benzene? 1) A) All of the carbon
More informationChem 2061 Final Exam. Fall Andy Aspaas, Instructor. Thursday, December 15, Instructions: Please print: Last name: First name:
Please print: Last name: First name: hem 2061 Final Exam Fall 2005 Andy Aspaas, Instructor Thursday, December 15, 2005 Instructions: You may start as soon as you arrive. The exam was designed to be finished
More informationCHEM 203 Exam 1. Name Multiple Choice Identify the letter of the choice that best completes the statement or answers the question.
CHEM 203 Exam 1 Name Multiple Choice Identify the letter of the choice that best completes the statement or answers the question. 1. Which of the following elements is a large percentage of both the earth's
More informationChapter 20. Amines. Nomenclature for amines. Aryl amines
Nomenclature for amines Chapter 20 Common names are widely used, named as alkylamines Systematic (IUPAC) nomenclature replaces the -e of the corresponding parent alkane with -amine Amines Simple secondary
More informationCHEMISTRY MIDTERM # 1 answer key February 12, 2009
CEMSTRY 313-01 MDTERM # 1 answer key February 12, 2009 Statistics: Average: 78 pts (78%); ighest: 97 pts (97%); Lowest: 43 pts (43%) umber of students performing at or above average: 28 (62%) umber of
More informationCHAPTER 5. Stereoisomers
CHAPTER 5 Stereoisomers We have already covered two kinds of isomerism: Constitutional Isomers (structural isomers) Stereoisomers Examples of Constitutional Isomers: Examples of Stereoisomers: Another
More informationCHE1502. Tutorial letter 201/1/2016. General Chemistry 1B. Semester 1. Department of Chemistry CHE1502/201/1/2016
CE1502/201/1/2016 Tutorial letter 201/1/2016 General Chemistry 1B CE1502 Semester 1 Department of Chemistry This tutorial letter contains the answers to the questions in assignment 1. FIRST SEMESTER: KEY
More information(S)-(-)-Dopa, used to treat Parkinson's disease, and its medically ineffective (R)-(+) enantiomer
C h a p t e r F i v e: Stereoisomerism N 2 2 N (S)-(-)-Dopa, used to treat Parkinson's disease, and its medically ineffective (R)-(+) enantiomer CM 321: Summary of Important Concepts YConcepts for Chapter
More informationThird Midterm Exam CHEM 255 Organic Chemistry I Prof. Bastin November 19, 2009
Third Midterm Exam CEM 255 Organic Chemistry I Prof. Bastin November 19, 2009 Name Section Provide CLEAR, CONCISE answers using unambiguous, carefully drawn structures and arrows for all of the appropriate
More informationCHEM 231 (Davis) Organic Chemistry FINAL EXAM May 15, YOUR NAME (Last, First, M.I.) DISCUSSION SECTION #53 (5 Points)
CHEM 231 (Davis) rganic Chemistry FINAL EXAM May 15, 2006 YUR NAME (Last, First, M.I.) DISCUSSIN SECTIN #53 (5 Points) Initial of last name Instructions Please fill in your name in the space above and
More informationChem 341 Jasperse Ch. 9 Handouts 1
Chem 341 Jasperse Ch. 9 andouts 1 Ch. 9 Stereochemistry Stereoisomers have the same condensed formulas and basic bonding sequence, but have different 3-dimensional shape and cannot be interconverted 9.1,2
More information12/27/2010. Chapter 14 Aromatic Compounds
Nomenclature of Benzene Derivatives Benzene is the parent name for some monosubstituted benzenes; the substituent name is added as a prefix Chapter 14 Aromatic Compounds For other monosubstituted benzenes,
More information75. A This is a Markovnikov addition reaction. In these reactions, the pielectrons in the alkene act as a nucleophile. The strongest electrophile will
71. B SN2 stands for substitution nucleophilic bimolecular. This means that there is a bimolecular rate-determining step. Therefore, the reaction will follow second-order kinetics based on the collision
More informationChemistry /002 Exam 1 Version Green. The Periodic Table
Name: Last First MI Chemistry 233-001/002 Exam 1 Version Green Fall 2018 Dr. J. sbourn Instructions: The first 13 questions of this exam should be answered on the provided Scantron. You must use a pencil
More informationName Date Class HYDROCARBONS
22.1 HYDROCARBONS Section Review Objectives Describe the relationship between number of valence electrons and bonding in carbon Define and describe alkanes Relate the polarity of hydrocarbons to their
More informationB. A transition state represents a maximum on the reaction path diagram and can be isolated.
Practice Hour Exam 2, Chemistry 2210, Organic Chemistry I 1. The most stable carbocation is: 2. Which of the following statements is true of transition states? A. A transition state represents a minimum
More informationORGANIC - CLUTCH CH AROMATICITY.
!! www.clutchprep.com CONCEPT: AROMATICTY INTRODUCTION Aromatic compounds display an unusual stability for their high level of electron density. Their high level of unsaturation should make them extremely
More informationNAME: SPRING 2015 MIDTERM
page 1 pts NAME: SPRING 2015 MIDTERM hemistry 231 Professor: Dr. Gergens take-home portion (DUE at the beginning of the period, 4/6) Do your best on this take-home portion of your mid-term. I may grade
More information