NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12

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1 Want a tutor to help you ace ths exam? NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 1 PHYSICAL SCIENCES: PHYSICS (P1) FISIESE WETENSKAPPE: FISIKA (V1) FEBRUARY/MARCH/FEBRUARIE/MAART 013 MEMORANDUM MARKS/PUNTE: 150 Ths memorandum conssts o 18 pages. Herde memorandum bestaan ut 18 bladsye. Please turn over/blaa om asseble

2 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 DBE/Feb. Mar./Feb. Mrt. 013 SECTION A QUESTION 1/VRAAG X-rays/X-strale (1) 1. Momentum (1) 1.3 Huygens (prncple)/huygens (se begnsel) (1) 1.4 ampere/ampère (1) 1.5 Isolated/closed Geïsoleerde/geslote (1) [5] QUESTION /VRAAG.1 B (). A ().3 A ().4 D ().5 A ().6 D ().7 B ().8 A ().9 B ().10 C () [0] TOTAL SECTION A/TOTAAL AFDELING A: 5 Please turn over/blaa om asseble

3 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 3 DBE/Feb. Mar./Feb. Mrt. 013 SECTION B/AFDELING B QUESTION 3/VRAAG N downwards/awaarts () OPTION 1/OPSIE 1 Downward postve: Awaarts poste: v = v + a y v = 0 + (9,8)(0,8) v = 3,96 m s -1 downward /awaarts Downward negatve: Awaarts negate: v = v + a y v = 0 + (-9,8)(-0,8) v = -3,96 m s -1 v = 3,96 m s -1 downward /awaarts OPTION /OPSIE (E p + E k ) top/bo = (E p + Ek) bottom/onder mgh + 0 = 0 + ½mv (9,8)(0,8) = ½ v v = 3,96 m s -1 downward/awaarts Accept/Aanvaar: g or/o a Accept/Aanvaar: v = v + a x v = u + as Accept/Aanvaar: (U + K) top/bo = (U + K) bottom/onder (4) Please turn over/blaa om asseble

4 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 4 DBE/Feb. Mar./Feb. Mrt POSITIVE MARKING FROM QUESTION 3..1 POSITIEWE NASIEN VAN VRAAG 3..1 OPTION 1/OPSIE 1 Downward postve/awaarts poste: F net Δt = Δp OR F net Δt = m(v v ) (F app + mg)δt = Δp (-50 + (0,)(9,8)Δt = 0,(- 3,43 3,96) Δt = 0,03 s (3 x 10 - s) Downward negatve/awaarts negate: F net Δt = Δp OR F net Δt = m(v v ) (F app + mg)δt = Δp (50 - (0,)(9,8)Δt = 0,[3,43 (-3,96)] Δt = 0,03 s (3 x 10 - s) OPTION /OPSIE Downward postve/awaarts poste: F net = ma F app + mg = ma (-50 + (0,)(9,8) = 0,a a = -40, m s - both ormulae bede ormules : Substtuton: F app and v must have the same sgn. Substtuse: F app en v moet deselde tekens hê. Accept/Aanvaar: v = u + at v = v + a t v = v + a t -3,43 = 3,96 + (-40,) t Δt = 0,03 s (3 x 10 - s) Downward negatve/awaarts negate: F net = ma F app + mg = ma (50 (0,)(9,8) = 0,a a = 40, m s - both ormulae bede ormules v = v + a t 3,43 = -3,96 + (40,) t Δt = 0,03 s (3 x 10 - s) (4) Please turn over/blaa om asseble

5 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 5 DBE/Feb. Mar./Feb. Mrt POSITIVE MARKING FROM QUESTION 3.. POSITIEWE NASIEN VAN VRAAG 3.. OPTION/OPSIE 1 Ground as zero reerence and downward negatve: Grond as nulverwysng en awaarts negate: Crtera or graph/krtera vr graek: Correct shape (both curves) Korrekte vorm (bede krommes) Graph starts at y = 0,8 m at t = 0 s Graek begn by y = 0,8 m at t = 0 s Second maxmum heght at y = 0,6 m Tweede maksmum by y = 0,6 m s Contact tme shown as space on x axs between two curves. Kontaktyd aangetoon as spase op x-as tussen twee krommes. Tme at whch ball leaves the loor shown as t = 0,434 s. Tyd wanneer de bal de vloer verlaat getoon as t = 0,434 s. Marks/ Punte 0,8 Poston/Posse (m) 0,6 0 0,404 0,434 Tme/tyd(s) Please turn over/blaa om asseble

6 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 6 DBE/Feb. Mar./Feb. Mrt. 013 OPTION/OPSIE Ground as zero reerence and downward postve: Grond as nulverwysng en awaarts poste: Crtera or graph/krtera vr graek: Correct shape (both curves) Korrekte vorm (bede krommes) Graph starts at y = -0,8 m at t = 0 s Graek begn by y = -0,8 m at t = 0 s Second maxmum heght at y = -0,6 m Tweede maksmum by y = -0,6 m s Contact tme shown as space on x axs between two curves. Kontaktyd aangetoon as spase op x-as tussen twee krommes. Tme at whch ball leaves the loor shown as t = 0,434 s. Tyd wanneer de bal de vloer verlaat getoon as t = 0,434 s. Marks/ Punte Poston/Posse (m) -0,6 0 0,404 0,43 4 Tme/tyd(s) -0,8 (5) [15] Please turn over/blaa om asseble

7 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 7 DBE/Feb. Mar./Feb. Mrt. 013 QUESTION 4/VRAAG The total (lnear) momentum remans constant/s conserved n an solated/a closed system/the absence o external orces. De totale lneêre momentum bly konstant/behoue n 'n geïsoleerde ssteem/geslote ssteem/de awesghed van eksterne kragte. : The mark or 'closed/solated system' s only awarded used n conjuncton wth momentum. De punt vr 'geslote/geïsoleerde ssteem' word slegs toegeken nden saam met momentum gebruk. Accept: The total momentum beore a collson equals the total momentum ater a collson n a closed system. Aanvaar: De totale momentum voor 'n botsng s gelyk aan de totale momentum na 'n botsng n 'n geslote ssteem. 4. To the rght as postve/na regs as poste: Σ p beore/voor = Σ p ater/na (0,01)(300) + (1,99)(0) = (0,01 + 1,99)v v = 1,5 m s -1 () To the rght as negatve/na regs as negate: Σ p beore/voor = Σ p ater/na (0,01)(-300) + (1,99)(0) = (0,01 + 1,99)v v = -1,5 m s -1 v = 1,5 m s -1 Other ormulae/ander ormules: m 1 v 1 + m v = m 1 v 1 + m v or/o m 1 u 1 + m u = m 1 v 1 + m v or/o m 1 v 1 + m v = (m 1 + m )v : 3 I no ormula/prncple Max. 4 Inden geen ormule/begnsel Maks Inelastc/Onelastes Knetc energy s not conserved./knetese energe bly ne behoue ne. Inelastc/Onelastes Objects stck together/voorwerpe heg aan mekaar. Inelastc/Onelastes Structural damage to the block./strukturele skade aan blok. Inelastc/Onelastes There s deormaton to the block/bullet./daar s vervormng van de blok. Inelastc/Onelastes Energy converted to other orms such as sound and heat./energe word omgeskakel na ander vorms soos klank en htte. () (4) Please turn over/blaa om asseble

8 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 8 DBE/Feb. Mar./Feb. Mrt POSITIVE MARKING FROM QUESTION 4.. POSITIEF NASIEN VAN VRAAG 4.. Opton 1/Opse 1: W net = ΔK OR /OF F net xcos θ = 1 mv 1 mv (8)Δxcos180 = ()(0 1,5 ) x = 0,8 m 1 : Accept/Aanvaar: E k Opton /Opse : F net = ma (-8) = a a = - 4 m s - v = v + a x 0 = (1,5) + (-4) x x = 0,8 m Both ormulae Bede ormules : Accept/Aanvaar: v = v + a y v = u + as (4) [1] QUESTION 5/VRAAG The total mechancal energy remans constant/s conserved n an solated/closed system. De totale meganese energe bly konstant/bly behoue n 'n geïsoleerde/geslote ssteem The sum o the potental and knetc energy remans constant n an solated/closed system. De som van de potensële en knetese energes bly konstant n 'n geïsoleerde/geslote ssteem : The mark or 'closed/solated system' s only awarded used n conjuncton wth energy. De punt vr 'geslote/geïsoleerde ssteem' word slegs toegeken nden saam met energe gebruk. () Please turn over/blaa om asseble

9 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 9 DBE/Feb. Mar./Feb. Mrt Free-body dagram Accept/Aanvaar: Force dagram/kragtedagram Vrye kragtedagram w w w Accepted labels/aanvaarde benoemngs F g /F w /orce o Earth on boy/weght/39 N/mg/gravtatonal orce F g /F w /krag van Aarde op seun/gewg/39 N/mg/gravtasekrag (1) 5.. Free-body dagram Vrye kragtedagram N w Accept: Force dagram Aanvaar: Kragtedagram N w N w // w // w w Accepted labels/aanvaarde benoemngs w F g /F w /orce o Earth on grl/weght/15,6 N/mg/gravtatonal orce F g /F w /krag van Aarde op mese/gewg/15,6 N/mg/gravtasekrag F rcton /F /rcton F wrywng /F /F w /wrywng N F N /F normal /normal orce/orce o slde or surace on grl N (3) K + U = K + U OR mv (40)(9,8)(1,5) = (40)v v = 5,4 m s -1 + mgh = mv + mgh : Accept/Aanvaar E p & E k (4) Please turn over/blaa om asseble

10 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 10 DBE/Feb. Mar./Feb. Mrt Opton 1/Opse 1 W net = ΔK w xcos θ + xcos θ = mg xcos θ + xcos θ = 1 1 mv mv 1 1 mv mv 1 ()(9,8)(3)cos60 + (1,9)(3)cos180 = ()(v 0 ) v = 5,37 m s -1 Opton /Opse W net = ΔK w// xcos θ + xcos θ = ½ mv ½ mv 1 1 mgsn θ xcos θ + xcos θ = mv mv 1 ()(9,8)sn30 (3)cos0 + (1,9)(3)cos180 = ()(v 0 ) v = 5,37 m s -1 Opton 3/Opse 3 W net = ΔK mghcosθ + xcos θ = 1 mv 1 mv ()(9,8)(1,5)cos0 + (1,9)(3)cos180 = ()(v 0 ) v = 5,37 m s -1 Opton 4/Opse 4 W net = ΔK - U + W = K - (mgh mgh ) + W = K 1 Accept/ Aanvaar: y/ x Accept/ Aanvaar: y/ x Accept/ Aanvaar h/ y/ x Accept/ Aanvaar h/ y/ x 1 - (0 ()(9,8)(1,5) + (1,9)(3)cos180 = ()(v 0 ) v = 5,37 m s -1 (5) 5.5 Equal to/gelyk aan (1) [16] Please turn over/blaa om asseble

11 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 11 DBE/Feb. Mar./Feb. Mrt. 013 QUESTION 6/VRAAG The approachng observer (hgher ) passes the source at t = 6 s and moves away (lower ) rom the source. De naderende waarnemer (hoër ) beweeg verby de bron by t = 6 s en beweeg weg (laer ) van de bron a. (1) OPTION 1/OPSIE 1 Approachng observer: Naderende waarnemer: v ± v L v + vl L = s L = s v ± v s v vl 900 = (850) 340 v L = 0 m s -1 OPTION / OPSIE Observer movng away: Waarnemer beweeg weg: v ± v L v vl L = s L = s v ± v s v 340 vl 800 = (850) 340 v L = 0 m s -1 Notes: Any other Doppler ormula, e.g. v vl L = - Max. 3 v v 4 s Aantekennge: Enge ander Dopplerormule, bv. v vl L = - Maks. 3 v v 4 s (5) 6.. POSITIVE MARKING FROM QUESTION 6..1 POSITIEWE NASIEN van VRAAG 6..1 Opton 1/Opse 1: 1 Δx = v Δt + a t = (0)(6) + ½ (0) t x = 10 m Opton /Opse : Δx = vδ t = (0)(6) x = 10 m Accept/Aanvaar: s = ut / s = vt s = ut + Δy = v Δt 1 at + t 1 a (3) [9] Please turn over/blaa om asseble

12 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 1 DBE/Feb. Mar./Feb. Mrt. 013 QUESTION 7/VRAAG B (1) 7. Constructve ntererence Konstruktewe ntererense c = λ 3 x 10 8 = 4,54 x λ λ = 6,61 x 10-7 m 7.3. POSITIVE MARKING FROM QUESTION POSITIEWE NASIEN VAN VRAAG OPTION 1/OPSIE 1 1 centralband tan θ = screen dstance 1 (0,) tan θ = 1,5 θ = 3,81 mλ sn θ = a (1)(6,61 10 sn3,81 = a a = 9,95 x 10-6 m 7 ) Accept/Aanvaar v = λ Accept nal answer n range: 9,94 x10-6 to 9,95 x10-6 m Aanvaar nale antwoorde n de gebed: 9,94 x10-6 to 9,95 x10-6 m IF dstance s not hal o central band: Max 6 4 INDIEN astand ne helte van sentrale band s ne: Maks 6 4 () (3) OPTION /OPSIE 1 centralband tan θ = screen dstance 1 (0,) tan θ = 1,5 θ = 3,81 mλ sn θ = a ( 1)(6,61 10 sn(-3,81 ) = a a = 9,95 x 10-6 m 7 ) Accept nal answer n range: 9,94 x10-6 to 9,95 x10-6 m Aanvaar nale antwoorde n de gebed: 9,94 x10-6 to 9,95 x10-6 m IF dstance s not hal o central band: Max 6 4 INDIEN astand ne helte van sentrale band s ne: Maks 6 4 (6) 7.4 Decreases/Vermnder (1) [13] Please turn over/blaa om asseble

13 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 13 DBE/Feb. Mar./Feb. Mrt. 013 QUESTION 8/VRAAG Stores (electrc) charge/energy. Stoor (elektrese) ladng/energe. Releases (stored) charge nstantly/very ast. Stel (gestoorde) ladng onmddellk vry/bae vnng vry. (1) 8. The brghtness o the bulb decreases (gradually) untl t stops glowng/des. De helderhed van de gloelamp vermnder (geledelk). The bulb glows dmmer untl t stops glowng/des. De gloelamp gloe louer totdat dt ophou gloe/utbrand. (1) (V) (1) V (1) POSITIVE MARKING FROM QUESTION POSITIEWE NASIEN VAN VRAAG E = d V 1 = 3 5,4 10 =, x 10 3 V m -1 (, V m -1 ) (3) 8.4. POSITIVE MARKING FROM QUESTION POSITIEWE NASIEN VAN VRAAG F E = q, x 10 3 F = 19 1,6 10 F = 3,56 x N (3) ,4 mm 3,8 mm = 1,6 mm (1) Please turn over/blaa om asseble

14 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 14 DBE/Feb. Mar./Feb. Mrt POSITIVE MARKING FROM QUESTION 8.4. & POSITIEWE NASIEN VAN VRAAG 8.4. & W = FΔxcosθ = (3,56 x )(1,6 x 10-3 )cos 0 = 5,69 x J (4) [15] QUESTION 9/VRAAG Potental derence/potensaalverskl (1) 9.1. Temperature/Temperatuur Resstance/Weerstand (1) Current s drectly proportonal to potental derence. Stroom s drek eweredg aan potensaalverskl The rato o potental derence to current s constant. De verhoudng van potensaalverskl tot stroom s konstant. IF/INDIEN: Current s proportonal to potental derence. Stroom s eweredg aan potensaalverskl. () ,18 0 Gradent/m = = 0,36 0,5 0 1 R = =,78 Ω 0,36 : Accept any set o correct values rom the graph. Aanvaar enge stel waardes vana de graek. (4) = + Rp R1 R 1 1 = R p = 3,75 Ω (3) Please turn over/blaa om asseble

15 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 15 DBE/Feb. Mar./Feb. Mrt POSITIVE MARKING FROM QUESTION POSITIEWE NASIEN VAN VRAAG OPTION / OPSIE V p = I 10 Ω R = 0,6 x 10 = 6 V Any one V Enge een p I p = Rp 6 = 3,75 = 1,6 A Do not penalse or subscrpts. Moene penalseer nden onderskrte weggelaat s ne. OPTION 1/OPSIE V 10 Ω = I 10 Ω R = 0,6 x 10 = 6 V I 6Ω = R V Any one Enge een Do not penalse or subscrpts. Moene penalseer nden onderskrte weggelaat s ne. = 6 6 = 1 A I tot = 1 + 0,6 = 1,6 A 9..3 POSITIVE MARKING FROM QUESTION POSITIEWE NASIEN VAN VRAAG E = I(R + r) 30 = 1,6(3, r) r = Ω (4) (4) [19] Please turn over/blaa om asseble

16 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 16 DBE/Feb. Mar./Feb. Mrt. 013 QUESTION 10/VRAAG Q/splt rng commutator/commutator Q/spltrngkommutator/kommutator (1) 10. Replace Q/splt rng commutator wth slp rngs. Vervang Q/spltrngkommutator met sleeprnge. (1) 10.3 AC can be stepped-up at power statons/ws kan by de kragstase verhoog word to reduce energy loss durng transmsson./om energeverles tydens transmsse te vermnder. () Imax/maks I rms/wgk = 0,35 = I = 0,5 A rms/wgk I subscrpts omtted: no mark or ormula Inden onderskte weggelaat s: geen punt vr ormule (3) OPTION 1/OPSIE 1 Vrms/wgk Pave / = R = R R = 960 Ω gemd OPTION /OPSIE P ave/gemd = I rms/wgkr 60 = (0,5) R R = 960 Ω OPTION 3/OPSIE 3 Vrms/ wgk R = Irms/ wgk 40 = 0,5 = 960 Ω Do not penalse subscrpts are omtted. Moene penalseer nden onderskrte weggelaat s ne Accept/Aanvaar: V R = as ormula/ormule I (3) [10] Please turn over/blaa om asseble

17 Want a tutor to help you ace ths exam? Physcal Scences P1/Fsese Wetenskappe V1 17 DBE/Feb. Mar./Feb. Mrt. 013 QUESTION 11/VRAAG Quantum/packet o energy/kwantum/pakke energe ound n lght/in lg gevnd () OPTION 1/OPSIE 1 E = hc λ 6,9 x (6,63 10 = λ λ =,9 x 10-7 m 34 8 )(3 10 ) OPTION / OPSIE E = h 6,9 x = 6,63 x = 1,04 x Hz c = λ 3 x 10 8 = 1,04 x λ λ =,88 x 10-7 m Both ormulae Bede ormules Accept/Aanvaar: v = λ (5) 11.. E = W o + Ek 6,9 x = 6,4 x E k E k = 5 x 10-0 J (3) Increases/Vermeerder More photons (packets o energy) strke the surace o the metal per unt tme./meer otone (pakkes energe) tre de oppervlakte van de metaal per eenhed tyd. More (photo)electrons ejected per unt tme./meer (oto)elektrone vrygestel per eenhed tyd. (3) Increases/Vermeerder (Photo)electrons are emtted wth hgher knetc energy/move aster./ (Foto)elektrone word vrygestel met hoër knetese energe/beweeg vnnger. Increase n rate o low o charge./same number o charges pass a pont n a shorter tme./toename n tempo van vloe van ladng/deselde aantal ladng beweeg verby 'n punt n 'n korter tyd. (3) [16] TOTAL SECTION B/TOTAAL AFDELING B: GRAND TOTAL/GROOTTOTAAL:

NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 12

NATIONAL SENIOR CERTIFICATE NASIONALE SENIOR SERTIFIKAAT GRADE/GRAAD 1 PHYSICAL SCIENCES: PHYSICS (P1) FISIESE WETENSKAPPE: FISIKA (V1) FEBRUARY/MARCH/FEBRUARIE/MAART 013 MEMORANDUM MARKS/PUNTE: 150 This