STUDY PACKAGE. Subject : Mathematics Topic : DIFFRENTIATION Available Online :
|
|
- Spencer Christian Clark
- 5 years ago
- Views:
Transcription
1 fo/u fopkjr Hk# tu] uga vkjehks ke] foifr ns[k NksM+s rqjar e/;e eu j ';kea iq#"k flag layi j] lgrs foifr vus] ^cuk^ u NksM+s /;s; ks] j?kqcj jk[ks VsAA jfpr% ekuo /kez izksrk ln~q# J jknksm+nklt egkjkt STUDY PACKAGE Subject : Matematics Topic : DIFFRENTIATION Available Online : wwwmatsbsuagcom R Ine Teor Sort Revision Eercise (E + 5 6) Assertion & Reason 5 Que from Compt Eams 6 9 Yrs Que from IIT-JEE(Avance) 7 5 Yrs Que from AIEEE (JEE Main) Stuent s Name : Class Roll No : : Aress : Plot No 7, III- Floor, Near Patiar Stuio, Above Bon Classes, Zone-, MP NAGAR, Bopal : , , WatsApp wwwtekoclassescom wwwmatsbsuagcom
2 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom Differentiation A First Principle Of Differentiation Te erivative of a given function f at a point a on its omain is efine as: Limit f(a ) f(a) 0, provie te limit eists & is enote b f (a) ie f (a) Limit f() f(a) a, provie te limit eists a If an + belong to te omain of a function f efine b f(), ten Limit f( ) f() 0 if it eists, is calle te Derivative of f at & is enote b f () or ie, f () Limit 0 f( ) f() Tis meto of ifferentiation is also calle ab-initio meto or first principle Solve Eample # Fin erivative of following functions b first principle (i) f() (ii) f() tan (iii) f() e sin Solution (i) f() lim 0 ( ) (ii) f() lim tan( ) tan 0 lim tan( )[ tan tan( )] 0 sin ( ) sin (iii) f() lim e e 0 sin ( ) sin e esin lim 0 sin( ) sin e sin lim sin( ) sin 0 Differentiation of some elementar functions f() f() lim 0 sin( ) sin lim e sin cos n n n ( R, n R) a a n a n log a n a 5 sin cos 6 cos sin 7 sec sec tan 8 cosec cosec cot 9 tan sec 0 tan ( + tan ) sec 0 cot Basic Teorems cosec (f ± g) f() ± g() (k f()) k f() (f() g()) f() g() + g() f() f() g() f() f()g () g() g () 5 (f(g())) f(g()) g() Tis rule is also calle te cain rule of ifferentiation an can be written as z z Note tat an important inference obtaine from te cain rule is tat Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page OF 8 Successful People / Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't
3 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom anoter wa of epressing te same concept is b consiering f() an g() as inverse functions of eac oter f() an g() g() f() Solve Eample # Fin te ifferential of te following functions wit respect to (i) f() e sin (ii) f() sin( ) (iii) f() Solution (i) f() e sin f() e sin (sin ) (ii) f() sin ( ) e sin cos cos( ) (sin ( + )) sin ( ) sin ( ) (iii) f() ( ) () f() ( ) ( ) (iv) f() sin f() cos + sin Solve Eample # If f() sin ( + tan) ten fin value of f(0) Solution f() cos ( + tan) ( + sec ) f(0) Self Practice Problems : Fin te erviative of following functions using first principle (i) f() sin (ii) f() sin Ans (i) cos + sin (ii) sin cos Evaluate if f(5) 7, ten f(5 t) f(5 t) t 0 t Differentiate te following functions Ans 7 (i) ( + ) ( ) (ii) (iv) (vii) sin cos ( ) ( )( ) (iii) (v) cos sin (vi) e sin (viii) n (sin cos ) Ans (i)6 (5 + ) (ii) ( ) ( ) (v) cos cos sin B (vi) e ((sin + cos ) + sin ) (vii) (iii) sec Derivative Of Inverse Trigonometric Functions sin sin (iv) (iv) / / ( ) ( ) (viii) f() sin cos sin sin cos cos cos < < sin Note ere tat cos sin, rater cos ± sin but for values of,, cos is alwas positive an ence te result similarl let us fin erivative of oter inverse trigonometric functions Let tan tan sec + tan + ( R) Also if sec [0, ] sec sec tan tan sec Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page OF 8 Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't
4 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom sec (, ) (, ) sec results for te erivative of inverse trigonometric functions can be summarize as : f() f() sin ; < cos ; < tan ; R cot ; R sec ; > cosec - ; > Solve Eample # If f() n (sin ) fin f() Solution f() (sin ) ( ) (sin ) Solve Eample # 5 If f() sec cosec () ten fin f( ) Solution f() sec () + f( ) sec ( ) f( ) + C Metos Of Differentiation Logritmic Differentiation Te process of taking logaritm of te function first an ten ifferentiate is calle Logaritmic Differentiation It is useful if (i) a function is te prouct or quotient of a number of functions OR (ii) a function is of te form [f()] g() were f & g are bot erivable, Solve Eample # 6 If fin Solution n n + n ( + n ) Solve Eample # 7 If (sin ) n, fin Solution n n n (sin ) n (sin ) + n cos sin / ( ) Solve Eample # 8 If / / 5 ( ) ( ) / (sin ) n fin Solution n n + n ( ) n ( ) 5 n ( ) n sin cot ( ) ( ) 5 ( ) 9 6 ( ) ( ) 5 ( ) Implicit ifferentiation If f(, ) 0, is an implicit function ten in orer to fin /, we ifferentiate eac term wrt regaring as a functions of & ten collect terms in / Solve Eample # 9 If + fin Solution Differentiation bot sies wrt, we get + + Note tat above result ols onl for points were 0 n Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page OF 8 Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't
5 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom Solve Eample # 0 If e, ten fin Solution Taking log on bot sies n ( ) (i) ifferentiating wrt, we get + ln Solve Eample # If + ten fin u v Solution u + v + 0 were u & v n u n & n v n u u + n & v n v n + ( n ) u v n & n n + n n 0 n Self Practice Problems Differentiate te following functions : (i) sec ( ) (ii) tan (iii) (iv) e (v) (ln ) + () sin Fin if (i) cos ( + ) (ii) / + / a / (iii) n ( ) n If e, ten prove tat ( n ) If log Ans a, prove tat (i) (ii) (iii) n (iv) e (n + ) (v) sin n ( n) n (n ) + sin cos n sin( ) ( ) (i) (ii) (iii) sin( ) ( ) Differentiation using substitution Following substitutions are normall use to sumplif tese epression / (i) a a tan or a cot (ii) a a sin or a cos (iii) a a sec or a cosec a (iv) a cos a Solve Eample # : Differentiate tan Solution Let tan tan ;, sec tan [ sec sec, ] tan Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page 5 OF 8 Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't
6 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom cos tan sin tan tan [tan (tan) for, ] tan ( ) Solve Eample # : Fin were tan Solution cos cos () ; [0, ] tan tan cos cos tan tan cos cos cos Note tat cos cos tan cos cos sin sin Solve Eample # 5 If + a( ), ten prove tat Solution Put sin sin () sin sin () cos + cos a (sin sin) Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't but for 0,, Also tan (tan ) for, Solve Eample # If f() sin ten fin (i) f() (ii) f Solution tan tan () ; < < (iii) f() cos cos sin (sin ) tan f() tan f() ( tan ) ( ) 8 (i) f() (ii) f (iii) f( 5 + ) & f( ) + 5 f() oes not eist Aliter Above problem can also be solve witout an substution also, but in a little teious wa f() sin f() f() ( ( ( ( ) ) ) ) ( ) {( ) } ( ( ( ) ) ) tus f() Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page 6 OF 8
7 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Aliter Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom cos cos a cos sin cot (a) sin sin cot (a) ifferentiating wrt to Using implicit ifferention a 0 a a + ( ) ( )( ) ( )( ) ( ) Hence prove a a ( )( ) ( )( ) Parametric Differentiation If f() & g() were is a parameter, ten Solve Eample # 6 If a cos t an a sin t Fin / t / t a sin acos t cost t sint tan t Solve Eample # 7 If a cos t an a (t sint) fin te value of at t asint) a( cos t) t 5 Derivative of one function wit respect to anoter Let f(); z g() ten / f'( ) z z / g'( ) Solve Eample # 8 Fin erivative of n wit respect to z e / z z / e Self Practice Problems : Fin wen (i) a (cos t + t sin t) & a (sin t t cos t) (ii) a t t & b t t ( t )b Ans (i) tan t (ii) at If sin a a ten prove tat a If tan ten prove tat ( ) cot a / / Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page 7 OF 8 Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't
8 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom u u If u sin (m cos ) an v cos (m sin ) ten prove tat v v D Derivatives of Higer Orer Let a function f() be efine on an open interval (a, b) It s erivative, if it eists on (a, b) is a certain function f () [or (/) or ] & is calle te first erivative of w r t If it appens tat te first erivative as a erivative on (a, b) ten tis erivative is calle te secon erivative of w r t & is enote b f () or ( / ) or Similarl, te r orer erivative of w r t, if it eists, is efine b or Solve Eample # 9 If n ten an Solution n + n + 6 n n n + Solve Eample # 0 If ten fin () Solution n n wen ( + n ) ( + n ) (i) again iff wrt to, ( + n ) ( + ln ) (using (i)) () 0 It must be carefull note tat in case of parametric functions / t altoug but / t wic on appling cain rule can be resolve as t / t t / t t t t t t / t / t rater t t t t t Solve Eample # If t + an t + t ten fin Solution t + t ; t t t + t + 6t t (t + t ) t It is also enote b f () / t / t Solve Eample # If cos t cos t an sin t sin t ten fin value of Solution cos t cos t sin t sin t t t t cost cost sin t sin t t tan t sin sin t t cos sin t t tan at t t t tan t Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page 8 OF 8 Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't
9 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom t sec (sint sint) t Solve Eample # Fin secon orer erivative of sin wit respect to z e / cos Solution z z / e cos cos z z e e z e sin cos e (e ) e (sin cos) z e Solve Eample # : f() an g() are inverse functions of eac oter tan epress g() an g() in terms of erivative of f() Solution f() an g() g() f() (i) again ifferentiating wrt to g() f () f () f() g() f() f() g() f() (ii) wic can also be remembere as Solve Eample # 5 sin (sin) ten prove tat + (tan) + cos 0 Solution Suc epression can be easil prove using implict ifferention cos (sin ) cos sec cos (sin ) again ifferentiating wrt, we can get sec + sec tan sin (sin ) cos tan cos +(tan) + cos 0 Self Practice Problems : n n If ten fin Ans Prove tat + tan satisfies te ifferentiation equation cos + 0 sec If a (cos + sin ) an a(sin cos) ten fin Ans a sin cos Fin secon erivative of n wit respect to sin Ans cos 5 if e (A cos + B sin ), prove tat Solve Eample # 6 If (tan ) ten prove tat ( + ) Solution + ( + ) tan ( + ) tan () ( + ) + ( ) ( + ) + ( + ) Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page 9 OF 8
10 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom f() l() If F() u() f'() l() u() g'() m() v() g() m() v() '() n() w() () n(), were f, g,, l, m, n, u, v, w are ifferentiable functions of ten F () w() f() l'() + u() L Hospital s Rule: g() m'() v() () n'() w() If f() & g() are functions of suc tat: (i) (ii) (iii) Limit a f() 0 a + f() l() u'() g() m() v'() () n() w'() Limit g() OR Limit a f() Limit a g() & Bot f() & g() are continuous at a & Bot f() & g() are ifferentiable at a & (iv) Bot f () & g () are continuous at a, Ten f() f'() f"() Limit a Limit g() a Limit g'() a & so on till ineterminant form vanises g"() QUESTION BANK ON METHOD OF DIFFERENTIATION Select te correct alternative : (Onl one is correct) Q If g is te inverse of f & f () ten g () 5 + [g()] 5 (C) 5 [ g( )] [ g( )] e 5 n Q If tan ne + tan n ten 6 n (C) 0 (D) Q If f & f () tan ten 5 6 tan tan tan 5 6 (C) f ( 5 6) tan 5tan 6 Q If sin & + p, ten p ( ) 0 sin (C) sin of tese Q5 If f & f () sin ten sin sin (C) Q6 Let g is te inverse function of f & f () 5 a 0 0 a Q7 If sin () + cos () 0 ten 0 (C) sin If g() a ten g () is equal to a 0 a (C) (D) 0 a a (D) Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page 0 OF 8 Q8 If sin ten is : Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't
11 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom 5 5 (C) 5 Q9 Te erivative of sec wrt at is : / (C) Q0 If P(), is a polnomial of egree, ten equals : Q P () + P () P () P () (C) P () P () (D) a constant Let f() be a quaratic epression wic is positive for all real If g() f() + f () + f (), ten for an real, wic one is correct g() < 0 g() > 0 (C) g() 0 (D) g() 0 Q If p q ( + ) p + q ten is : inepenent of p but epenent on q epenent on p but inepenent of q (C) epenent on bot p & q (D) inepenent of p & q bot Q Let f() g ( ) cos if 0 were g() is an even function ifferentiable at 0, passing troug te 0 if 0 origin Ten f (0) : is equal to is equal to 0 (C) is equal to (D) oes not eist Q If n m p m + m n p n + m p n p ten at emnp is equal to: e mnp e mn/p (C) e np/m Q5 log cos sin Lim 0 as te value equal to log cos sin (C) of tese Q6 If f is ifferentiable in (0, 6) & f () 5 ten Limit f f ( ) c 5 5/ (C) 0 (D) 0 Q7 Let l Lim 0 m (ln ) n were m, n N ten : l is inepenent of m an n l is inepenent of m an epens on m (C) l is inepenent of n an epenent on m (D) l is epenent on bot m an n cos Q8 Let f() sin Ten Limit f( ) 0 tan (C) (D) cos sin cos Q9 Let f() cos sin cos ten f cos sin cos 0 (C) (D) Q0 People living at Mars, instea of te usual efinition of erivative D f(), efine a new kin of erivative, D*f() b te formula f ( ) f ( ) D*f() Limit were f () means [f()] If f() ln ten 0 D * f ( ) e as te value e e (C) e Q If f() g() ; f () 9 ; g () 6 ten Limit f ( ) g( ) is equal to : (C) 0 Q If f() is a ifferentiable function of ten Limit f ( ) f ( ) 0 f () 5f () (C) 0 Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page OF 8 Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't
12 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom Q If + e ten is : e e e (C) (D) e e e Q If + ten te value of at te point (, ) is : 5 (C) 8 Q5 If f(a), f (a), g(a), g (a) ten te value of Limit g( ) f ( a) g( a) f ( ) a is: a 5 /5 (C) 5 Q6 If f is twice ifferentiable suc tat f ( ) f( ), f ( ) g( ) ( ) f( ) g( ) an ( 0), ( ) ten te equation () represents : a curve of egree a curve passing troug te origin (C) a straigt line wit slope (D) a straigt line wit intercept equal to Q7 Te erivative of te function, f()cos - ( cos sin ) UVW + sin ( cos sin ) UVW wrt at is : RST 5 (C) 0 (D) 0 Q8 Let f() be a polnomial in Ten te secon erivative of f(e ), is : f (e ) e + f (e ) f (e ) e + f (e ) e (C) f (e ) e (D) f (e ) e + f (e ) e Q9 Te solution set of f () > g (), were f() (5 + ) & g() 5 + (ln 5) is : > 0 < < (C) 0 (D) > 0 Q0 If sin + sec, > ten is equal to : (C) 0 (D) Q If ten a b a b a b a b a b (C) (D) ab a ab b ab b ab a Q Let f () be a polnomial function of secon egree If f () f ( ) an a, b, c are in AP, ten f '(a), f '(b) an f '(c) are in GP HP (C) AGP (D) AP Q If sin m ten te value of 5 (were subscripts of sows te orer of erivatiive) is: inepenent of but epenent on m epenent of but inepenent of m (C) epenent on bot m & (D) inepenent of m & Q If + R (R > 0) ten k were k in terms of R alone is equal to (C) (D) R R R R Q5 If f & g are ifferentiable functions suc tat g (a) & g(a) b an if fog is an ientit function ten f (b) as te value equal to : / (C) 0 (D) / Q6 Given f() + sin 5 a sin a sin a 5 arc sin (a 8a + 7) ten : f() is not efine at sin 8 f (sin 8) > 0 Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't RST Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page OF 8
13 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom (C) f () is not efine at sin 8 (D) f (sin 8) < 0 Q7 A function f, efine for all positive real numbers, satisfies te equation f( ) for ever > 0 Ten te value of f () (C) / (D) cannot be etermine Q8 Given : f() 6 cos a + sin a sin 6a + n a a ten : f() is not efine at / f (/) < 0 (C) f () is not efine at / (D) f (/) > 0 Q9 If (A + B) e m + (m ) e ten m + m is equal to : e e m (C) e m (D) e ( m) Q0 Suppose f () e a + e b, were a b, an tat f '' () f ' () 5 f () 0 for all Ten te prouct ab is equal to 5 9 (C) 5 (D) 9 Q Let () be ifferentiable for all an let f () (k + e ) () were k is some constant If (0) 5, ' (0) an f ' (0) 8 ten te value of k is equal to 5 (C) (D) Q Let e f() ln If g() is te inverse function of f() ten g () equals to : e e + (C) ( e e ) (D) e ( + ln ) Q Te equation e 9e efines as a ifferentiable function of Te value of for an is 5 9 (C) (D) 5 5 an g() ten : f () an g () f () an g () (C) f () an g () 0 (D) f () an g () Q5 Te function f() e +, being ifferentiable an one to one, as a ifferentiable inverse f () Te value of (f ) at te point f(l n) is (C) n log sin cos Q6 If f () for < 0 logsin cos for 0 ten, te number of points of iscontinuit of f in, is 0 (C) (D) Q7 If ( a ) a ( b ) b ten werever it is efine is equal to : a b Q Let f() ( a b) ( a ) ( b) ( a b) ( a ) ( b) (C) ( a b) ( a ) ( b) Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't (D) ( a b) ( a ) ( b) Q8 If is a function of ten + 0 If is a function of ten te equation becomes : (C) 0 (D) 0 Q9 A function f () satisfies te conition, f () f () + f () + f () + were f () is a ifferentiable function inefinitel an as enotes te orer of erivative If f (0), ten f () is : e / e (C) e (D) e cos6 6cos 5cos 0 Q50 If, ten cos5 5cos 0cos sin + cos sin (C) cos (D) sin Q5 If + K ten te value of K is equal to (C) (D) 0 Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page OF 8
14 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom sin sin ( ) were 0, ten f ' () as te value equal to Q5 If f() ( ) zero (C) ( ) (D) e if 0 Q5 Let f() 0 if 0 Ten wic of te following can best represent te grap of f()? (C) (D) m n mn m n mn mn n m Q5 Diffrential coefficient of wrt is 0 (C) (D) b mn Q55 Let f () be iffrentiable at ten Lim g f ( ) f ( ) is equal to f() + f '() f() + f '() (C) f() + f '() (D) f() f '() Q56 If at + bt + c an t a + b + c, ten equals a (at + b) a (a + b) (C) a (at + b) (D) a (a + b) Q57 Limit 0 a arc tan b arctan a b as te value equal to a b 0 (C) ( a b ) (D) a b 6a b a b Q58 Let f () be efine for all > 0 & be continuous Let f() satisf f f () f () for all, & f(e) Ten : f() is boune f 0 as 0 (C) f() as 0 (D) f() ln Q59 Suppose te function f () f () as te erivative 5 at an erivative 7 at Te erivative of te function f () f () at, as te value equal to 9 9 (C) 7 (D) Q60 If 5 cot 8 an a + b ten te value of a + b is equal to 5 cot Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't 5 (C) tan Q6 Suppose tat () f () g() an F() 5 (D) tan 8 f g(), were f () ; g() 5 ; g'() ; f '() an f '(5), ten F'() '() F'() '() (C) F'() '() Q6 Let f () wic one of te properties of te erivative enables ou to conclue tat f () as an inverse? f ' () is a polnomial of even egree f ' () is self inverse (C) omain of f ' () is te range of f ' () (D) f ' () is alwas positive Q6 Wic one of te following statements is NOT CORRECT? Te erivative of a iffrentiable perioic function is a perioic function wit te same perio If f () an g () bot are efine on te entire number line an are aperioic ten te function F() f () g () can not be perioic (C) Derivative of an even ifferentiable function is an o function an erivative of an o ifferentiable function is an even function (D) Ever function f () can be represente as te sum of an even an an o function Select te correct alternatives : (More tan one are correct) Q6 If tan tan tan ten as te value equal to : Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page OF 8
15 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom sec tan tan + sec tan tan + sec tan tan (cosec + cosec + cosec 6) (C) sec sec sec (D) sec + sec + sec Q65 If e e ten equals e e e e (C) (D) Q66 If ten ln ( ln + ) (C) ( ln + ) (D) ln e Q67 Let ten (C) (D) Q68 If + + ten as te value equal to : (C) (D) Q69 Te functions u e sin ; v e cos satisf te equation : v u u v u + v u v (C) v u of tese Q70 Let f () ten : Q7 f (0) f (/) (C) omain of f () is Two functions f & g ave first & secon erivatives at 0 & satisf te relations, f(0) g( 0) (0) g (0) g (0), g (0) 5 f (0) 6 f(0) ten : if () f ( ) g( ) (0) 5 if k() f() g() sin ten k (0) (C) Limit 0 Q7 If (C) g ( ) f ( ) n( n) ( n) n, ten is equal to : n n n n n (ln )ln (ln ) ( ln (ln ) + ) ((ln ) + ln (ln )) (D) n ( ln (ln ) + ) n ANSWER KEY Q A Q C Q B Q D Q5 B Q6 B Q7 B Q8 C Q9 A Q0 C Q B Q D Q B Q D Q5 C Q6 D Q7 A Q8 B Q9 C Q0 C Q A Q B Q B Q B Q5 C Q6 C Q7 C Q8 D Q9 D Q0 C Q D Q D Q D Q B Q5 D Q6 D Q7 B Q8 D Q9 A Q0 C Q C Q C Q D Q D Q5 B Q6 C Q7 B Q8 C Q9 A Q50 B Q5 D Q5 B Q5 C Q5 B Q55 A Q56 D Q57 D Q58 D Q59 A Q60 B Q6 B Q6 D Q6 B Q6 A,B,C Q65 A,C Q66 C,D Q67 A,C,D Q68 A,B,C,D Q69 A,B,C Q70 A,B Q7 A,B,C Q7 B,D Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page 5 OF 8 Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't
16 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom EXERCISE - Part : Onl one correct option If f() an f( ) ten at is (C) (D) If ten n ( n + ) (C) ( n + ) (D) n e tan sin If f() e, ten f(0) If a b a a ab a ten b ab b (C) (D) If f(), g(), () are polnomials in of egree an F() f g f g, ten F() is equal to 0 (C) (D) f() g() () If sin m ten te value of 5 (were settings of sows te orer of erivative) is: Successful People Replace te 6 wors 7 like; 8 "wis", "tr" & "soul" wit "I Will" Ineffective People on't (C) a ab b 5 Let f() sin ; g() & () log e & F() [g(f())] ten F is equal to: cosec cot ( ) cosec ( ) (C) cot (D) cosec 6 If ( + ) ( + ) ( + ) ( + n ), ten at 0 is (C) 0 (D) n 7 If sin 0 8 If e t were t sin 9 If sin an ( ) + p, ten p (D) b ab a (C) sin (D) ten : (C) (D) + sec, > ten is equal to: 0 Te ifferential coefficient of sin t t t (C) (C) 0 (D) wrt cos Differentiation of tan wrt tan is: tan tan (C) t t is: tan (D) ( tan ) Let f() be a polnomial in Ten te secon erivative of f(e ), is: f (e ) e + f (e ) f (e ) e + f (e ) e (C) f (e ) e (D) f (e ) e + f (e ) e f g Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page 6 OF 8
17 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom inepenent of but epenent on m epenent of but inepenent of m (C) epenent on bot m & (D) inepenent of m & 5 7 ten Limit f ( 5 t) f ( 5 t) t0 If f (5) t (C) 7 (D) Let e f() ln If g() is te inverse function of f() ten g () equals to: e e + (C) 7 If u a + b ten n n u [f(u)] n n [f(a + b)] is equal to: 8 If f & f () sin ten (C) sin sin n e e (D) e + ln a n u [f(u)] (C) an n u [f(u)] (D) an n [f(u)] Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't n sin 9 If P(), is a polnomial of egree, ten equals: P () + P () P () P () (C) P () P () (D) a constant Part : Ma ave more tan one options correct 0 Two functions f & g ave first & secon erivatives at 0 & satisf te relations, f(0) g( 0) (0) g (0) g (0), g (0) 5 f (0) 6 f(0) ten: if () f ( ) g( ) (0) 5 if k() f() g() sin ten k (0) (C) Limit g ( ) 0 f ( ) f n () If f n () e for all n N an f o (), ten {fn ()} is equal to: f n () {fn ()} f n () f n () (C) f n () f n () f () f () of tese If f is twice ifferentiable suc tat f() f() an f() g() If () is a twice ifferentiable function suc tat () [f()] + [g()] If (0), (), ten te equation () represents: a curve of egree a curve passing troug te origin (C) a straigt line wit slope (D) a straigt line wit intercept equal to Given f() + sin 5 a sin a sin a 5 sin (a 8a + 7) ten: f() + sin6 sin sin8 f (sin 8) > 0 (C) f () is not efine at sin 8 (D) f (sin 8) < 0 If f() + f() + f() for all R ten f(0) + f() f() f(0) + f() 0 (C) f() + f() f() of tese 5 If f() (a + b) sin + (c + ) cos, ten te values of a, b, c an suc tat f() cos for all are a b 0 (C) c 0 (D) b c EXERCISE - If A e kt cos (p t + c) ten prove tat + k + n 0, were n p + k t t Evaluate te following limits using L ospitale rule as oterwise Limit log (tan ) 0 If f () tan (a) (b) (c) (a) (b) (c) ten f () (a) (b) (c) (a) (b) (c) Fin te value of n Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page 7 OF 8
18 FREE Downloa Stu Package from website: wwwtekoclassescom & wwwmatsbsuagcom Get Solution of Tese Packages & Learn b Vieo Tutorials on wwwmatsbsuagcom If a t & b t, were t is a parameter, ten prove tat sina 5 If sin sin (a + ), sow tat cosa 8b 7 7a t 6 F" f" g" c F f g If F() f() g() & f () g () c, prove tat & F f g fg F f g 7 If be a repeate root of a quaratic equation f() 0 & A(), B(), C() be te polnomials of egree, & 5 A() B() C() A( ) respectivel, ten sow tat A'( ) 8 Sow tat R / B( ) B'( ) C( ) is ivisible b f(), were as enotes te erivative C' ( ) can be reuce to te form R / Also sow tat, if a sin ( + cos ) & a cos ( cos ) ten te value of R equals to a cos 9 Differentiate te following functions wit respect to (i) n e (i) Eercise # sin cos sin cos (iii) tan tan cos cos A C A D 5 D 6 B 7 D 8 B 9 C 0 A C D B D 5 C 6 C 7 C 8 B 9 C 0 ABC AC CD AD ABC 5 ABC Eercise # 9 (i) e ( n + + n ) (ii) sincos ( ) (iii) sec For 9 Years Que from IIT-JEE(Avance) & 5 Years Que from AIEEE (JEE Main) we istribute a book in class room Teko Classes, Mats : Suag R Karia (S R K Sir), Bopal Pone : , page 8 OF 8 Successful People Replace te wors like; "wis", "tr" & "soul" wit "I Will" Ineffective People on't
STUDY PACKAGE. Subject : Mathematics ENJOY MATHEMATICS WITH SUHAAG SIR. Student s Name : Class Roll No.
fo/u fopkjr Hk# tu] uga vkjehks dke] foifr ns[k NksM+s rqjar e/;e eu dj ';kea iq#"k flag ladyi dj] lgrs foifr vusd] ^cuk^ u NksM+s /;s; dks] j?kqcj jk[ks VsdAA jfpr% ekuo /kez izksrk ln~q# J jknksm+nklt
More informationSTUDY PACKAGE. Subject : Mathematics Topic : INVERSE TRIGONOMETRY. Available Online :
fo/u fopkjr Hkh# tu] ugha vkjehks dke] for ns[k NksM+s rqjar e/;e eu dj ';kea iq#"k flag ladyi dj] lgrs for vusd] ^cuk^ u NksM+s /;s; dks] j?kqcj jk[ks VsdAA jfpr% ekuo /kez iz.ksrk ln~q# Jh j.knksm+nklth
More informationChapter Primer on Differentiation
Capter 0.01 Primer on Differentiation After reaing tis capter, you soul be able to: 1. unerstan te basics of ifferentiation,. relate te slopes of te secant line an tangent line to te erivative of a function,.
More informationDerivatives. if such a limit exists. In this case when such a limit exists, we say that the function f is differentiable.
Derivatives 3. Derivatives Definition 3. Let f be a function an a < b be numbers. Te average rate of cange of f from a to b is f(b) f(a). b a Remark 3. Te average rate of cange of a function f from a to
More informationf(x + h) f(x) f (x) = lim
Introuction 4.3 Some Very Basic Differentiation Formulas If a ifferentiable function f is quite simple, ten it is possible to fin f by using te efinition of erivative irectly: f () 0 f( + ) f() However,
More informationMETHODS OF DIFFERENTIATION. Contents. Theory Objective Question Subjective Question 10. NCERT Board Questions
METHODS OF DIFFERENTIATION Contents Topic Page No. Theor 0 0 Objective Question 0 09 Subjective Question 0 NCERT Board Questions Answer Ke 4 Sllabus Derivative of a function, derivative of the sum, difference,
More information1 Lecture 13: The derivative as a function.
1 Lecture 13: Te erivative as a function. 1.1 Outline Definition of te erivative as a function. efinitions of ifferentiability. Power rule, erivative te exponential function Derivative of a sum an a multiple
More informationSubject : Mathematics Topic : Trigonometric Ratio & Identity
fo/u fopkjr Hkh# tu] ugha vkjehks dke] foifr ns[k NksM+s rqjar e/;e eu dj ';ke iq#"k flag ladyi dj] lgrs foifr vusd] ^cuk^ u NksM+s /;s; dks] j?kqcj jk[ks Vsd jfpr% ekuo /kez iz.ksrk ln~xq# Jh j.knksm+nklth
More information2.4 Exponential Functions and Derivatives (Sct of text)
2.4 Exponential Functions an Derivatives (Sct. 2.4 2.6 of text) 2.4. Exponential Functions Definition 2.4.. Let a>0 be a real number ifferent tan. Anexponential function as te form f(x) =a x. Teorem 2.4.2
More informationSTUDY PACKAGE. Subject : Mathematics Topic : Trigonometric Ratio & Identity
fo/u fopkjr Hkh# tu] ugha vkjehks dke] foifr ns[k NksMs rqjar e/;e eu dj ';ke iq#"k flag ladyi dj] lgrs foifr vusd] ^cuk^ u NksMs /;s; dks] j?kqcj jk[ks Vsd jfpr% ekuo /kez iz.ksrk ln~xq# Jh j.knksmnklth
More information(a 1 m. a n m = < a 1/N n
Notes on a an log a Mat 9 Fall 2004 Here is an approac to te eponential an logaritmic functions wic avois any use of integral calculus We use witout proof te eistence of certain limits an assume tat certain
More informationStudent s Name : Class Roll No. ADDRESS: R-1, Opp. Raiway Track, New Corner Glass Building, Zone-2, M.P. NAGAR, Bhopal
fo/u fopkjr Hkh# tu] ugha vkjehks dke] foifr ns[k NksM+s rqjar e/;e eu dj ';kea iq#"k flag ladyi dj] lgrs foifr vusd] ^cuk^ u NksM+s /;s; dks] j?kqcj jk[ks VsdAA jfpr% ekuo /kez izksrk ln~q# Jh jknksm+nklth
More informationMath 242: Principles of Analysis Fall 2016 Homework 7 Part B Solutions
Mat 22: Principles of Analysis Fall 206 Homework 7 Part B Solutions. Sow tat f(x) = x 2 is not uniformly continuous on R. Solution. Te equation is equivalent to f(x) = 0 were f(x) = x 2 sin(x) 3. Since
More informationDifferential Calculus Definitions, Rules and Theorems
Precalculus Review Differential Calculus Definitions, Rules an Teorems Sara Brewer, Alabama Scool of Mat an Science Functions, Domain an Range f: X Y a function f from X to Y assigns to eac x X a unique
More informationIn Leibniz notation, we write this rule as follows. DERIVATIVE OF A CONSTANT FUNCTION. For n 4 we find the derivative of f x x 4 as follows: lim
.1 DERIVATIVES OF POLYNOIALS AND EXPONENTIAL FUNCTIONS c =c slope=0 0 FIGURE 1 Te grap of ƒ=c is te line =c, so fª()=0. In tis section we learn ow to ifferentiate constant functions, power functions, polnomials,
More informationRules of Differentiation
LECTURE 2 Rules of Differentiation At te en of Capter 2, we finally arrive at te following efinition of te erivative of a function f f x + f x x := x 0 oing so only after an extene iscussion as wat te
More informationUsing the definition of the derivative of a function is quite tedious. f (x + h) f (x)
Derivative Rules Using te efinition of te erivative of a function is quite teious. Let s prove some sortcuts tat we can use. Recall tat te efinition of erivative is: Given any number x for wic te limit
More information1 ode.mcd. Find solution to ODE dy/dx=f(x,y). Instructor: Nam Sun Wang
Fin solution to ODE /=f(). Instructor: Nam Sun Wang oe.mc Backgroun. Wen a sstem canges wit time or wit location, a set of ifferential equations tat contains erivative terms "/" escribe suc a namic sstem.
More informationDerivatives of trigonometric functions
Derivatives of trigonometric functions 2 October 207 Introuction Toay we will ten iscuss te erivates of te si stanar trigonometric functions. Of tese, te most important are sine an cosine; te erivatives
More informationSTUDY PACKAGE. Subject : PHYSICS Topic : OPTICAL INSTRUMENTS. Available Online :
fo/u fopkjr Hkh# tu] ugha vkjehks dke] foifr ns[k NksM+s rqjar e/;e eu dj ';kea iq#"k flag ladyi dj] lgrs foifr vusd] ^cuk^ u NksM+s /;s; dks] j?kqcj jk[ks VsdAA jfpr% ekuo /kez iz.ksrk ln~xq# Jh j.knksm+nklth
More informationdoes NOT exist. WHAT IF THE NUMBER X APPROACHES CANNOT BE PLUGGED INTO F(X)??????
MATH 000 Miterm Review.3 Te it of a function f ( ) L Tis means tat in a given function, f(), as APPROACHES c, a constant, it will equal te value L. Tis is c only true if f( ) f( ) L. Tat means if te verticle
More informationDifferentiation Rules and Formulas
Differentiation Rules an Formulas Professor D. Olles December 1, 01 1 Te Definition of te Derivative Consier a function y = f(x) tat is continuous on te interval a, b]. Ten, te slope of te secant line
More informationDifferential Calculus: Differentiation (First Principles, Rules) and Sketching Graphs (Grade 12) *
OpenStax-CNX moule: m39313 1 Differential Calculus: Differentiation (First Principles, Rules) an Sketcing Graps (Grae 12) * Free Hig Scool Science Texts Project Tis work is prouce by OpenStax-CNX an license
More informationjfpr% ekuo /kez iz.ksrk ln~xq# Jh j.knksm+nklth egkjkt
Phone : (0755) 00 000, 9890 5888 WhatsApp 9009 60 559 QUADRATIC EQUATIONS PART OF fo/u fopkjr Hkh# tu] ugha vkjehks dke] foifr ns[k NksM+s rqjar e/;e eu dj ';kea iq#"k flag ladyi dj] lgrs foifr vusd] ^cuk^
More information160 Chapter 3: Differentiation
3. Differentiation Rules 159 3. Differentiation Rules Tis section introuces a few rules tat allow us to ifferentiate a great variety of functions. By proving tese rules ere, we can ifferentiate functions
More informationDifferentiation Rules c 2002 Donald Kreider and Dwight Lahr
Dierentiation Rules c 00 Donal Kreier an Dwigt Lar Te Power Rule is an example o a ierentiation rule. For unctions o te orm x r, were r is a constant real number, we can simply write own te erivative rater
More informationThis file is /conf/snippets/setheader.pg you can use it as a model for creating files which introduce each problem set.
Yanimov Almog WeBWorK assignment number Sections 3. 3.2 is ue : 08/3/207 at 03:2pm CDT. Te (* replace wit url for te course ome page *) for te course contains te syllabus, graing policy an oter information.
More informationLogarithmic functions
Roberto s Notes on Differential Calculus Capter 5: Derivatives of transcendental functions Section Derivatives of Logaritmic functions Wat ou need to know alread: Definition of derivative and all basic
More information0.1 Differentiation Rules
0.1 Differentiation Rules From our previous work we ve seen tat it can be quite a task to calculate te erivative of an arbitrary function. Just working wit a secon-orer polynomial tings get pretty complicate
More informationLinear and quadratic approximation
Linear an quaratic approximation November 11, 2013 Definition: Suppose f is a function that is ifferentiable on an interval I containing the point a. The linear approximation to f at a is the linear function
More informationSection The Chain Rule and Implicit Differentiation with Application on Derivative of Logarithm Functions
Section 3.4-3.6 The Chain Rule an Implicit Differentiation with Application on Derivative of Logarithm Functions Ruipeng Shen September 3r, 5th Ruipeng Shen MATH 1ZA3 September 3r, 5th 1 / 3 The Chain
More informationSECTION 2.1 BASIC CALCULUS REVIEW
Tis capter covers just te very basics of wat you will nee moving forwar onto te subsequent capters. Tis is a summary capter, an will not cover te concepts in-ept. If you ve never seen calculus before,
More informationA: Derivatives of Circular Functions. ( x) The central angle measures one radian. Arc Length of r
4: Derivatives of Circular Functions an Relate Rates Before we begin, remember tat we will (almost) always work in raians. Raians on't ivie te circle into parts; tey measure te size of te central angle
More information3.6. Implicit Differentiation. Implicitly Defined Functions
3.6 Implicit Differentiation 205 3.6 Implicit Differentiation 5 2 25 2 25 2 0 5 (3, ) Slope 3 FIGURE 3.36 The circle combines the graphs of two functions. The graph of 2 is the lower semicircle an passes
More information130 Chapter 3 Differentiation
0 Capter Differentiation 20. (a) (b) 2. C position, A velocity, an B acceleration. Neiter A nor C can be te erivative of B because B's erivative is constant. Grap C cannot be te erivative of A eiter, because
More informationRecapitulation of Mathematics
Unit I Recapitulation of Mathematics Basics of Differentiation Rolle s an Lagrange s Theorem Tangent an Normal Inefinite an Definite Integral Engineering Mathematics I Basics of Differentiation CHAPTER
More informationINTRODUCTION TO CALCULUS LIMITS
Calculus can be divided into two ke areas: INTRODUCTION TO CALCULUS Differential Calculus dealing wit its, rates of cange, tangents and normals to curves, curve sketcing, and applications to maima and
More informationFREE Download Study Package from website: &
SHORT REVISION (FUNCTIONS) THINGS TO REMEMBER :. GENERAL DEFINITION : If to every value (Considered as real unless otherwise stated) of a variable which belongs to some collection (Set) E there corresponds
More information30 is close to t 5 = 15.
Limits Definition 1 (Limit). If te values f(x) of a function f : A B get very close to a specific, unique number L wen x is very close to, but not necessarily equal to, a limit point c, we say te limit
More informationMath Module Preliminary Test Solutions
SSEA Summer 207 Mat Module Preliminar Test Solutions. [3 points] Find all values of tat satisf =. Solution: = ( ) = ( ) = ( ) =. Tis means ( ) is positive. Tat is, 0, wic implies. 2. [6 points] Find all
More informationChapter 2 Derivatives
Chapter Derivatives Section. An Intuitive Introuction to Derivatives Consier a function: Slope function: Derivative, f ' For each, the slope of f is the height of f ' Where f has a horizontal tangent line,
More informationy = 3 2 x 3. The slope of this line is 3 and its y-intercept is (0, 3). For every two units to the right, the line rises three units vertically.
Mat 2 - Calculus for Management and Social Science. Understanding te basics of lines in te -plane is crucial to te stud of calculus. Notes Recall tat te and -intercepts of a line are were te line meets
More informationMAT01A1: Differentiation of Polynomials & Exponential Functions + the Product & Quotient Rules
MAT01A1: Differentiation of Polynomials & Exponential Functions + te Prouct & Quotient Rules Dr Craig 22 Marc 2017 Semester Test 1 Scripts will be available for collection from Tursay morning. For marking
More informationLecture 6: Calculus. In Song Kim. September 7, 2011
Lecture 6: Calculus In Song Kim September 7, 20 Introuction to Differential Calculus In our previous lecture we came up with several ways to analyze functions. We saw previously that the slope of a linear
More informationIntegral Calculus, dealing with areas and volumes, and approximate areas under and between curves.
Calculus can be divided into two ke areas: Differential Calculus dealing wit its, rates of cange, tangents and normals to curves, curve sketcing, and applications to maima and minima problems Integral
More informationClick here to see an animation of the derivative
Differentiation Massoud Malek Derivative Te concept of derivative is at te core of Calculus; It is a very powerful tool for understanding te beavior of matematical functions. It allows us to optimize functions,
More informationMath 180, Exam 2, Fall 2012 Problem 1 Solution. (a) The derivative is computed using the Chain Rule twice. 1 2 x x
. Fin erivatives of the following functions: (a) f() = tan ( 2 + ) ( ) 2 (b) f() = ln 2 + (c) f() = sin() Solution: Math 80, Eam 2, Fall 202 Problem Solution (a) The erivative is compute using the Chain
More informationSection 2.1 The Derivative and the Tangent Line Problem
Chapter 2 Differentiation Course Number Section 2.1 The Derivative an the Tangent Line Problem Objective: In this lesson you learne how to fin the erivative of a function using the limit efinition an unerstan
More informationx f(x) x f(x) approaching 1 approaching 0.5 approaching 1 approaching 0.
Engineering Mathematics 2 26 February 2014 Limits of functions Consier the function 1 f() = 1. The omain of this function is R + \ {1}. The function is not efine at 1. What happens when is close to 1?
More informationRecall from our discussion of continuity in lecture a function is continuous at a point x = a if and only if
Computational Aspects of its. Keeping te simple simple. Recall by elementary functions we mean :Polynomials (including linear and quadratic equations) Eponentials Logaritms Trig Functions Rational Functions
More information1. Questions (a) through (e) refer to the graph of the function f given below. (A) 0 (B) 1 (C) 2 (D) 4 (E) does not exist
Mat 1120 Calculus Test 2. October 18, 2001 Your name Te multiple coice problems count 4 points eac. In te multiple coice section, circle te correct coice (or coices). You must sow your work on te oter
More informationUniversity Mathematics 2
University Matematics 2 1 Differentiability In tis section, we discuss te differentiability of functions. Definition 1.1 Differentiable function). Let f) be a function. We say tat f is differentiable at
More informationThe Derivative. Chapter 3
59957_CH0a_-90q 9/5/09 7:7 PM Page Capter Te Derivative cos (0, ) e e In Tis Capter Te wor calculus is a iminutive form of te Latin wor cal, wic means stone In ancient civilizations small stones or pebbles
More informationUnit #6 - Families of Functions, Taylor Polynomials, l Hopital s Rule
Unit # - Families of Functions, Taylor Polynomials, l Hopital s Rule Some problems an solutions selecte or aapte from Hughes-Hallett Calculus. Critical Points. Consier the function f) = 54 +. b) a) Fin
More information1 Calculus. 1.1 Gradients and the Derivative. Q f(x+h) f(x)
Calculus. Gradients and te Derivative Q f(x+) δy P T δx R f(x) 0 x x+ Let P (x, f(x)) and Q(x+, f(x+)) denote two points on te curve of te function y = f(x) and let R denote te point of intersection of
More informationA.P. CALCULUS (AB) Outline Chapter 3 (Derivatives)
A.P. CALCULUS (AB) Outline Capter 3 (Derivatives) NAME Date Previously in Capter 2 we determined te slope of a tangent line to a curve at a point as te limit of te slopes of secant lines using tat point
More informationGet Solution of These Packages & Learn by Video Tutorials on SHORT REVISION
FREE Download Stu Pacage from website: www.teoclasses.com & www.mathsbsuhag.com Get Solution of These Pacages & Learn b Video Tutorials on www.mathsbsuhag.com SHORT REVISION DIFFERENTIAL EQUATIONS OF FIRST
More information1 The concept of limits (p.217 p.229, p.242 p.249, p.255 p.256) 1.1 Limits Consider the function determined by the formula 3. x since at this point
MA00 Capter 6 Calculus and Basic Linear Algebra I Limits, Continuity and Differentiability Te concept of its (p.7 p.9, p.4 p.49, p.55 p.56). Limits Consider te function determined by te formula f Note
More informationACCESS TO SCIENCE, ENGINEERING AND AGRICULTURE: MATHEMATICS 1 MATH00030 SEMESTER /2019
ACCESS TO SCIENCE, ENGINEERING AND AGRICULTURE: MATHEMATICS MATH00030 SEMESTER 208/209 DR. ANTHONY BROWN 6. Differential Calculus 6.. Differentiation from First Principles. In tis capter, we will introduce
More informationTOPIC 4 CONTINUITY AND DIFFRENTIABILITY SCHEMATIC DIAGRAM
TOPIC 4 CONTINUITY AND DIFFRENTIABILITY SCHEMATIC DIAGRAM Topic Concepts Degree of importance Refrences NCERT Tet Book XII E 007 Continuity& Differentiability Limit of a function Continuity *** E 5 QNo-,
More informationMath 115 Section 018 Course Note
Course Note 1 General Functions Definition 1.1. A function is a rule that takes certain numbers as inputs an assigns to each a efinite output number. The set of all input numbers is calle the omain of
More informationx f(x) x f(x) approaching 1 approaching 0.5 approaching 1 approaching 0.
Engineering Mathematics 2 26 February 2014 Limits of functions Consier the function 1 f() = 1. The omain of this function is R + \ {1}. The function is not efine at 1. What happens when is close to 1?
More information(a) At what number x = a does f have a removable discontinuity? What value f(a) should be assigned to f at x = a in order to make f continuous at a?
Solutions to Test 1 Fall 016 1pt 1. Te grap of a function f(x) is sown at rigt below. Part I. State te value of eac limit. If a limit is infinite, state weter it is or. If a limit does not exist (but is
More informationContinuity and Differentiability Worksheet
Continuity and Differentiability Workseet (Be sure tat you can also do te grapical eercises from te tet- Tese were not included below! Typical problems are like problems -3, p. 6; -3, p. 7; 33-34, p. 7;
More informationTOTAL NAME DATE PERIOD AP CALCULUS AB UNIT 4 ADVANCED DIFFERENTIATION TECHNIQUES DATE TOPIC ASSIGNMENT /6 10/8 10/9 10/10 X X X X 10/11 10/12
NAME DATE PERIOD AP CALCULUS AB UNIT ADVANCED DIFFERENTIATION TECHNIQUES DATE TOPIC ASSIGNMENT 0 0 0/6 0/8 0/9 0/0 X X X X 0/ 0/ 0/5 0/6 QUIZ X X X 0/7 0/8 0/9 0/ 0/ 0/ 0/5 UNIT EXAM X X X TOTAL AP Calculus
More informationSTUDY PACKAGE. Available Online :
fo/u fopkjr Hkh# tu] ugha vkjehks dke] foifr ns[k NksM+s rqjar e/;e eu dj ';kea iq#"k flag ladyi dj] lgrs foifr vusd] ^cuk^ u NksM+s /;s; dks] j?kqcj jk[ks VsdAA jfpr% ekuo /kez i.ksrk ln~q# Jh j.knksm+nklth
More informationTOPIC 4 CONTINUITY AND DIFFRENTIABILITY SCHEMATIC DIAGRAM
ISSUED BY K V - DOWNLOADED FROM WWWSTUDIESTODAYCOM TOPIC 4 CONTINUITY AND DIFFRENTIABILITY SCHEMATIC DIAGRAM Topic Concepts Degree of importance Refrences NCERT Tet Book XII E 007 Continuity& Differentiability
More informationWith the Chain Rule. y x 2 1. and. with respect to second axle. dy du du dx. Rate of change of first axle. with respect to third axle
0 CHAPTER Differentiation Section The Chain Rule Fin the erivative of a composite function using the Chain Rule Fin the erivative of a function using the General Power Rule Simplif the erivative of a function
More informationLecture Notes Di erentiating Trigonometric Functions page 1
Lecture Notes Di erentiating Trigonometric Functions age (sin ) 7 sin () sin 8 cos 3 (tan ) sec tan + 9 tan + 4 (cot ) csc cot 0 cot + 5 sin (sec ) cos sec tan sec jj 6 (csc ) sin csc cot csc jj c Hiegkuti,
More informationSFU UBC UNBC Uvic Calculus Challenge Examination June 5, 2008, 12:00 15:00
SFU UBC UNBC Uvic Calculus Callenge Eamination June 5, 008, :00 5:00 Host: SIMON FRASER UNIVERSITY First Name: Last Name: Scool: Student signature INSTRUCTIONS Sow all your work Full marks are given only
More informationCHAPTER 3 DERIVATIVES (continued)
CHAPTER 3 DERIVATIVES (continue) 3.3. RULES FOR DIFFERENTIATION A. The erivative of a constant is zero: [c] = 0 B. The Power Rule: [n ] = n (n-1) C. The Constant Multiple Rule: [c *f()] = c * f () D. The
More informationFunction Composition and Chain Rules
Function Composition an Cain Rules James K. Peterson Department of Biological Sciences an Department of Matematical Sciences Clemson University November 2, 2018 Outline Function Composition an Continuity
More informationTHEOREM: THE CONSTANT RULE
MATH /MYERS/ALL FORMULAS ON THIS REVIEW MUST BE MEMORIZED! DERIVATIVE REVIEW THEOREM: THE CONSTANT RULE The erivative of a constant function is zero. That is, if c is a real number, then c 0 Eample 1:
More informationDifferentiation. Area of study Unit 2 Calculus
Differentiation 8VCE VCEco Area of stud Unit Calculus coverage In tis ca 8A 8B 8C 8D 8E 8F capter Introduction to limits Limits of discontinuous, rational and brid functions Differentiation using first
More informationComputing Derivatives Solutions
Stuent Stuy Session Solutions We have intentionally inclue more material than can be covere in most Stuent Stuy Sessions to account for groups that are able to answer the questions at a faster rate. Use
More information2.2 Derivative. 1. Definition of Derivative at a Point: The derivative of the function f x at x a is defined as
. Derivative. Definition of Derivative at a Point: Te derivative of te function f at a is defined as f fa fa a lim provided te limit eists. If te limit eists, we sa tat f is differentiable at a, oterwise,
More informationSection 2.7 Derivatives and Rates of Change Part II Section 2.8 The Derivative as a Function. at the point a, to be. = at time t = a is
Mat 180 www.timetodare.com Section.7 Derivatives and Rates of Cange Part II Section.8 Te Derivative as a Function Derivatives ( ) In te previous section we defined te slope of te tangent to a curve wit
More information5.1 We will begin this section with the definition of a rational expression. We
Basic Properties and Reducing to Lowest Terms 5.1 We will begin tis section wit te definition of a rational epression. We will ten state te two basic properties associated wit rational epressions and go
More informationDifferentiation Rules Derivatives of Polynomials and Exponential Functions
Derivatives of Polynomials an Exponential Functions Differentiation Rules Derivatives of Polynomials an Exponential Functions Let s start with the simplest of all functions, the constant function f(x)
More information11.6 DIRECTIONAL DERIVATIVES AND THE GRADIENT VECTOR
SECTION 11.6 DIRECTIONAL DERIVATIVES AND THE GRADIENT VECTOR 633 wit speed v o along te same line from te opposite direction toward te source, ten te frequenc of te sound eard b te observer is were c is
More information(x,y) 4. Calculus I: Differentiation
4. Calculus I: Differentiation 4. The eriatie of a function Suppose we are gien a cure with a point lying on it. If the cure is smooth at then we can fin a unique tangent to the cure at : If the tangent
More informationThe tangent line and the velocity problems. The derivative at a point and rates of change. , such as the graph shown below:
Capter 3: Derivatives In tis capter we will cover: 3 Te tanent line an te velocity problems Te erivative at a point an rates o cane 3 Te erivative as a unction Dierentiability 3 Derivatives o constant,
More informationMAT1A01: Differentiation of Polynomials & Exponential Functions + the Product & Quotient Rules
MAT1A01: Differentiation of Polynomials & Exponential Functions + te Prouct & Quotient Rules Dr Craig 22 Marc 2016 Semester Test 1 Results ave been publise on Blackboar uner My Graes. Scripts will be available
More informationSECTION 3.2 THE PRODUCT AND QUOTIENT RULES 1 8 3
SECTION 3.2 THE PRODUCT AND QUOTIENT RULES 8 3 L P f Q L segments L an L 2 to be tangent to the parabola at the transition points P an Q. (See the figure.) To simplify the equations you ecie to place the
More information1.5 Functions and Their Rates of Change
66_cpp-75.qd /6/8 4:8 PM Page 56 56 CHAPTER Introduction to Functions and Graps.5 Functions and Teir Rates of Cange Identif were a function is increasing or decreasing Use interval notation Use and interpret
More informationLines, Conics, Tangents, Limits and the Derivative
Lines, Conics, Tangents, Limits and te Derivative Te Straigt Line An two points on te (,) plane wen joined form a line segment. If te line segment is etended beond te two points ten it is called a straigt
More informationThe derivative function
Roberto s Notes on Differential Calculus Capter : Definition of derivative Section Te derivative function Wat you need to know already: f is at a point on its grap and ow to compute it. Wat te derivative
More informationPre-Calculus Review Preemptive Strike
Pre-Calculus Review Preemptive Strike Attaced are some notes and one assignment wit tree parts. Tese are due on te day tat we start te pre-calculus review. I strongly suggest reading troug te notes torougly
More informationCalculus I Homework: The Derivative as a Function Page 1
Calculus I Homework: Te Derivative as a Function Page 1 Example (2.9.16) Make a careful sketc of te grap of f(x) = sin x and below it sketc te grap of f (x). Try to guess te formula of f (x) from its grap.
More informationThe Chain Rule. y x 2 1 y sin x. and. Rate of change of first axle. with respect to second axle. dy du. du dx. Rate of change of first axle
. The Chain Rule 9. The Chain Rule Fin the erivative of a composite function using the Chain Rule. Fin the erivative of a function using the General Power Rule. Simplif the erivative of a function using
More informationSOLUTION OF IIT JEE 2010 BY SUHAAG SIR &
fo/u fokjr Hkh: tu] ugha vkjehks dke] foifr ns[k NksM+s rqjaar e/;e eu dj ';ke A iq:"k flag ladyi dj] lgrs foifr vusd] cuk* u NksM+s /;s; dks] j?kqcj jk[ks Vsd AA jfr% ekuo /kez iz.ksrk ln~q: Jh j.knksm+nklth
More informationA. Incorrect! The letter t does not appear in the expression of the given integral
AP Physics C - Problem Drill 1: The Funamental Theorem of Calculus Question No. 1 of 1 Instruction: (1) Rea the problem statement an answer choices carefully () Work the problems on paper as neee (3) Question
More information1 Lecture 20: Implicit differentiation
Lecture 20: Implicit ifferentiation. Outline The technique of implicit ifferentiation Tangent lines to a circle Derivatives of inverse functions by implicit ifferentiation Examples.2 Implicit ifferentiation
More informationExam 1 Solutions. x(x 2) (x + 1)(x 2) = x
Eam Solutions Question (0%) Consider f() = 2 2 2 2. (a) By calculating relevant its, determine te equations of all vertical asymptotes of te grap of f(). If tere are none, say so. f() = ( 2) ( + )( 2)
More informationMath 1271 Solutions for Fall 2005 Final Exam
Math 7 Solutions for Fall 5 Final Eam ) Since the equation + y = e y cannot be rearrange algebraically in orer to write y as an eplicit function of, we must instea ifferentiate this relation implicitly
More informationDerivatives of Exponentials
mat 0 more on derivatives: day 0 Derivatives of Eponentials Recall tat DEFINITION... An eponential function as te form f () =a, were te base is a real number a > 0. Te domain of an eponential function
More informationMATHEMATICS FOR ENGINEERING DIFFERENTIATION TUTORIAL 1 - BASIC DIFFERENTIATION
MATHEMATICS FOR ENGINEERING DIFFERENTIATION TUTORIAL 1 - BASIC DIFFERENTIATION Tis tutorial is essential pre-requisite material for anyone stuing mecanical engineering. Tis tutorial uses te principle of
More informationContinuity and Differentiability of the Trigonometric Functions
[Te basis for te following work will be te definition of te trigonometric functions as ratios of te sides of a triangle inscribed in a circle; in particular, te sine of an angle will be defined to be te
More informationName: Sept 21, 2017 Page 1 of 1
MATH 111 07 (Kunkle), Eam 1 100 pts, 75 minutes No notes, books, electronic devices, or outside materials of an kind. Read eac problem carefull and simplif our answers. Name: Sept 21, 2017 Page 1 of 1
More information2.8 The Derivative as a Function
.8 Te Derivative as a Function Typically, we can find te derivative of a function f at many points of its domain: Definition. Suppose tat f is a function wic is differentiable at every point of an open
More information