AB for hydrogen in steel is What is the molar flux of the hydrogen through the steel? Δx Wall. s kmole
|
|
- Leon Gilmore
- 5 years ago
- Views:
Transcription
1 ignen 6 Soluion - Hydogen ga i oed a high peue in a ecangula conaine (--hick wall). Hydogen concenaion a he inide wall i kole / and eenially negligible on he ouide wall. The B fo hydogen in eel i.6 / ec ha i he ola flu of he hydogen hough he eel?. Δ all i o = Given daa: difuivi y.6, B kole Hydogen concenaion inide he ank (inide wall) i, kole o, Hydogen concenaion ouide he ank (ouide wall) all hickne. upion i) iffuion i only in one diecion i.e. diecion aco he wall heefoe he ye can be aued o ac a a lab ii) Seady ae wih no cheical eacion i.e. and R pply he above aupion o he equaion of coninuiy of pecie fo ecangula coodinae (Equaion -7 Gikey):
2 y y R eady ae o flu o flu o cheical eacion To obain: Theefoe i independen of i.e. i i a conan Modified Eq.-6 give: B + ( + B ) Since concenaion of coponen in he conaine wall i vey all,. Then bulk flow will be negligible. Eg. -6 give: B nd ince conan (concenaion ouide he all i negligible), hen: B B o i Subiuing he given daa: B o i.6. kole The ola flu of hydogen hough eel fo hi cae i:.6 kole.
3 -9 Benene a i open o he aophee in a cicula ank (6. in diaee). Vapo peue and pecific gaviy fo benene ae. a and.88. n ai fil of 5- hickne i above he benene. ha i he co of evapoaed benene pe (aue value of benene i $ pe gallon)? i fil Benene Given aa: Benene Tepeaue = Vapou peue of Benene =. a Specific gaviy =.88 i fil of hickne = 5 iaee of ank = 6. o of benene = $ pe gallon upion: iffuion of olecule (Benene) i only in one diecion i.e. in he diecion no flu in and y diecion Seady ae wih no cheical eacion i.e. and R In hi cae, he ye i a liquid (benene) evapoaing ino Ga B (ai) i.e. diffuion hough a agnan ga fil odel. pply he above aupion o he equaion of coninuiy of pecie fo ecangula coodinae (Equaion -7 Gikey): y y R eady ae o flu o y flu o cheical eacion
4 To obain: Theefoe i independen of i.e. i i a conan Modified Eg. -6 give: + B ( + B ) B = (Sagnan ai) Then eaanging give: ( ) B Equaion knowing Replace he above equaion ino equaion, we can deive he ola flu of olecule in e of ole facion : ( ) B Since, R and T ae conan, he can be facoed ou of he deivaive o obain: B ( ) Equaion The equaion obained above (equaion ) can be inegaed ove he following boun condiion:
5 = = = = ( ) B B B B ln B ( ) ln ( ( ) ) Leing (hickne) and eaanging he equaion above we obain: ( ) B ln ( ) ( ) Equaion The above equaion of flu (Equaion ) can be wien in e of ole facion fo he aionay olecule i.e. B a follow: B B ln Equaion 5 ( ) B he uface of benene liquid: The vapou peue of benene =. a heefoe:. a a =. and B uing all he benene i wep away by oving olecule of ai above he agnan ai fil i.e. he concenaion of benene above he ai fil i negligible, hen:
6 Since he diffuiviy of benene i no given, i can be calculaed fo he following equaion: B T M B B M B Fo -- in Gikey: Benene M k 97 o K i nd, B M B k B o K B B KT k k B o K To obain B, able -- can be ued uing: kt B Theefoe he diffuiviy i: B K B a.. B ow ha we have all he paaee needed o deeine he ola flu of benene, we can ubiue he above paaee ino he ola flu equaion deived ealie:
7 B ln ( ).999 B B g. ol.ec a ln a K (.5 ) ol. K Fo he ola flu, he aoun of benene in gol/ec can be deeined a follow: Z g. ol g. ol.ec 6. The aoun of benene evapoaed pe : = M.899 g. ol g 78. gol 88 g 6 h h. Gallon of benene evapoaed in one :. 6.7 gallon gallon Theefoe he o of benene evapoaed pe : o of benene evapoaed = gallon dola 7.5 dolla - Hydogen ga( 7 ; ba) i oed in a --diaee pheical ank (hick wall). Mola concenaion of hydogen a he inne and oue wall ae.5 kgole/ and. iffuiviy of hydogen in eel i. / ec. Find he iniial ae of hydogen lo hough he wall a well a he iniial ae of peue dop in he ank.
8 R i R o Given aa: Hydogen ga = olecule Seel = B olecule Tepeaue = 7 Iniial peue = ba oncenaion of hydogen inide ank =.5 kgole/ oncenaion of hydogen ouide wall = kgole/ iffuiviy B =. Spheical ank diaee = Tank wall hickne = upion: iffuion of olecule (hydogen ga) i only in one diecion i.e. in he diecion no flu in θ and diecion Seady ae wih no cheical eacion i.e. and R o bulk flow of fluid ince he concenaion of hydogen in he wall of he pheical ank i negligible. pply he above aupion o he equaion of coninuiy of pecie fo pheical coodinae (Equaion -8 Gikey): in in in R eady ae o flu o flu o cheical eacion
9 To obain: Theefoe i a conan Then, uing he odified Equaion -6 Gikey: Modified Eq. -6: B + ( + B ) In he wall,, o bulk flow. The equaion above educe o: B nd B Equaion Inegaing he above equaion (equaion above) ove he following boun condiion: = i = R i = o = R o B B Ro Ri i B Ro Ri o i
10 B R i o R o i Subiuing he given daa in he above equaion: kole kgole Theefoe he iniial ae of hydogen dop hough he wall of he pheical ank i: 7.5 kgole Fo eue dop V n n V Theefoe peue dop ae i: d V gole ec a 8. gole. K.5 K d.5 acal.5 7 Ba
Lecture 17: Kinetics of Phase Growth in a Two-component System:
Lecue 17: Kineics of Phase Gowh in a Two-componen Sysem: descipion of diffusion flux acoss he α/ ineface Today s opics Majo asks of oday s Lecue: how o deive he diffusion flux of aoms. Once an incipien
More informationLecture 18: Kinetics of Phase Growth in a Two-component System: general kinetics analysis based on the dilute-solution approximation
Lecue 8: Kineics of Phase Gowh in a Two-componen Sysem: geneal kineics analysis based on he dilue-soluion appoximaion Today s opics: In he las Lecues, we leaned hee diffeen ways o descibe he diffusion
More informationENV 6015 Solution to Mixing Problem Set
EN 65 Soluion o ixing Problem Se. A slug of dye ( ) is injeced ino a single ank wih coninuous mixing. The flow in and ou of he ank is.5 gpm. The ank volume is 5 gallons. When will he dye concenraion equal
More information7 Wave Equation in Higher Dimensions
7 Wave Equaion in Highe Dimensions We now conside he iniial-value poblem fo he wave equaion in n dimensions, u c u x R n u(x, φ(x u (x, ψ(x whee u n i u x i x i. (7. 7. Mehod of Spheical Means Ref: Evans,
More informationCircular Motion. Radians. One revolution is equivalent to which is also equivalent to 2π radians. Therefore we can.
1 Cicula Moion Radians One evoluion is equivalen o 360 0 which is also equivalen o 2π adians. Theefoe we can say ha 360 = 2π adians, 180 = π adians, 90 = π 2 adians. Hence 1 adian = 360 2π Convesions Rule
More informationMolecular Evolution and Phylogeny. Based on: Durbin et al Chapter 8
Molecula Evoluion and hylogeny Baed on: Dubin e al Chape 8. hylogeneic Tee umpion banch inenal node leaf Topology T : bifucaing Leave - N Inenal node N+ N- Lengh { i } fo each banch hylogeneic ee Topology
More informationThe Global Trade and Environment Model: GTEM
The Global Tade and Envionmen Model: A pojecion of non-seady sae daa using Ineempoal GTEM Hom Pan, Vivek Tulpulé and Bian S. Fishe Ausalian Bueau of Agiculual and Resouce Economics OBJECTIVES Deive an
More informationStress Analysis of Infinite Plate with Elliptical Hole
Sess Analysis of Infinie Plae ih Ellipical Hole Mohansing R Padeshi*, D. P. K. Shaa* * ( P.G.Suden, Depaen of Mechanical Engg, NRI s Insiue of Infoaion Science & Technology, Bhopal, India) * ( Head of,
More informationFundamental Vehicle Loads & Their Estimation
Fundaenal Vehicle Loads & Thei Esiaion The silified loads can only be alied in he eliinay design sage when he absence of es o siulaion daa They should always be qualified and udaed as oe infoaion becoes
More informationÖRNEK 1: THE LINEAR IMPULSE-MOMENTUM RELATION Calculate the linear momentum of a particle of mass m=10 kg which has a. kg m s
MÜHENDİSLİK MEKANİĞİ. HAFTA İMPULS- MMENTUM-ÇARPIŞMA Linea oenu of a paicle: The sybol L denoes he linea oenu and is defined as he ass ies he elociy of a paicle. L ÖRNEK : THE LINEAR IMPULSE-MMENTUM RELATIN
More informationPressure Vessels Thin and Thick-Walled Stress Analysis
Pessue Vessels Thin and Thick-Walled Sess Analysis y James Doane, PhD, PE Conens 1.0 Couse Oveview... 3.0 Thin-Walled Pessue Vessels... 3.1 Inoducion... 3. Sesses in Cylindical Conaines... 4..1 Hoop Sess...
More informationMA 214 Calculus IV (Spring 2016) Section 2. Homework Assignment 1 Solutions
MA 14 Calculus IV (Spring 016) Secion Homework Assignmen 1 Soluions 1 Boyce and DiPrima, p 40, Problem 10 (c) Soluion: In sandard form he given firs-order linear ODE is: An inegraing facor is given by
More informationComplete solutions to Exercise 14(b) 1. Very similar to EXAMPLE 4. We have same characteristic equation:
Soluions 4(b) Complee soluions o Exercise 4(b). Very similar o EXAMPE 4. We have same characerisic equaion: 5 i Ae = + Be By using he given iniial condiions we obain he simulaneous equaions A+ B= 0 5A
More informationPhysics 240: Worksheet 16 Name
Phyic 4: Workhee 16 Nae Non-unifor circular oion Each of hee proble involve non-unifor circular oion wih a conan α. (1) Obain each of he equaion of oion for non-unifor circular oion under a conan acceleraion,
More informationPHYS PRACTICE EXAM 2
PHYS 1800 PRACTICE EXAM Pa I Muliple Choice Quesions [ ps each] Diecions: Cicle he one alenaive ha bes complees he saemen o answes he quesion. Unless ohewise saed, assume ideal condiions (no ai esisance,
More informationCONTROL SYSTEMS. Chapter 10 : State Space Response
CONTROL SYSTEMS Chaper : Sae Space Repone GATE Objecive & Numerical Type Soluion Queion 5 [GATE EE 99 IIT-Bombay : Mark] Conider a econd order yem whoe ae pace repreenaion i of he form A Bu. If () (),
More informationFINITE DIFFERENCE APPROACH TO WAVE GUIDE MODES COMPUTATION
FINITE DIFFERENCE ROCH TO WVE GUIDE MODES COMUTTION Ing.lessando Fani Elecomagneic Gou Deamen of Elecical and Eleconic Engineeing Univesiy of Cagliai iazza d mi, 93 Cagliai, Ialy SUMMRY Inoducion Finie
More informationr P + '% 2 r v(r) End pressures P 1 (high) and P 2 (low) P 1 , which must be independent of z, so # dz dz = P 2 " P 1 = " #P L L,
Lecue 36 Pipe Flow and Low-eynolds numbe hydodynamics 36.1 eading fo Lecues 34-35: PKT Chape 12. Will y fo Monday?: new daa shee and daf fomula shee fo final exam. Ou saing poin fo hydodynamics ae wo equaions:
More informationThe sudden release of a large amount of energy E into a background fluid of density
10 Poin explosion The sudden elease of a lage amoun of enegy E ino a backgound fluid of densiy ceaes a song explosion, chaaceized by a song shock wave (a blas wave ) emanaing fom he poin whee he enegy
More informationThe Production of Polarization
Physics 36: Waves Lecue 13 3/31/211 The Poducion of Polaizaion Today we will alk abou he poducion of polaized ligh. We aleady inoduced he concep of he polaizaion of ligh, a ansvese EM wave. To biefly eview
More informationLecture 5. Chapter 3. Electromagnetic Theory, Photons, and Light
Lecue 5 Chape 3 lecomagneic Theo, Phoons, and Ligh Gauss s Gauss s Faada s Ampèe- Mawell s + Loen foce: S C ds ds S C F dl dl q Mawell equaions d d qv A q A J ds ds In mae fields ae defined hough ineacion
More informationPHYS GENERAL RELATIVITY AND COSMOLOGY PROBLEM SET 7 - SOLUTIONS
PHYS 54 - GENERAL RELATIVITY AND COSMOLOGY - 07 - PROBLEM SET 7 - SOLUTIONS TA: Jeome Quinin Mach, 07 Noe ha houghou hee oluion, we wok in uni whee c, and we chooe he meic ignaue (,,, ) a ou convenion..
More informationHomework-8(1) P8.3-1, 3, 8, 10, 17, 21, 24, 28,29 P8.4-1, 2, 5
Homework-8() P8.3-, 3, 8, 0, 7, 2, 24, 28,29 P8.4-, 2, 5 Secion 8.3: The Response of a Firs Order Circui o a Consan Inpu P 8.3- The circui shown in Figure P 8.3- is a seady sae before he swich closes a
More informationME 391 Mechanical Engineering Analysis
Fall 04 ME 39 Mechanical Engineering Analsis Eam # Soluions Direcions: Open noes (including course web posings). No books, compuers, or phones. An calculaor is fair game. Problem Deermine he posiion of
More informationENGI 4430 Advanced Calculus for Engineering Faculty of Engineering and Applied Science Problem Set 9 Solutions [Theorems of Gauss and Stokes]
ENGI 44 Avance alculus fo Engineeing Faculy of Engineeing an Applie cience Poblem e 9 oluions [Theoems of Gauss an okes]. A fla aea A is boune by he iangle whose veices ae he poins P(,, ), Q(,, ) an R(,,
More informationLecture 22 Electromagnetic Waves
Lecue Elecomagneic Waves Pogam: 1. Enegy caied by he wave (Poyning veco).. Maxwell s equaions and Bounday condiions a inefaces. 3. Maeials boundaies: eflecion and efacion. Snell s Law. Quesions you should
More informationMath 333 Problem Set #2 Solution 14 February 2003
Mah 333 Problem Se #2 Soluion 14 February 2003 A1. Solve he iniial value problem dy dx = x2 + e 3x ; 2y 4 y(0) = 1. Soluion: This is separable; we wrie 2y 4 dy = x 2 + e x dx and inegrae o ge The iniial
More informationArea A 0 level is h 0, assuming the pipe flow to be laminar. D, L and assuming the pipe flow to be highly turbulent.
Pipe Flows (ecures 5 o 7). Choose he crec answer (i) While deriving an expression f loss of head due o a sudden expansion in a pipe, in addiion o he coninuiy and impulse-momenum equaions, one of he following
More informationMEEN 617 Handout #11 MODAL ANALYSIS OF MDOF Systems with VISCOUS DAMPING
MEEN 67 Handou # MODAL ANALYSIS OF MDOF Sysems wih VISCOS DAMPING ^ Symmeic Moion of a n-dof linea sysem is descibed by he second ode diffeenial equaions M+C+K=F whee () and F () ae n ows vecos of displacemens
More informationFirst Order RC and RL Transient Circuits
Firs Order R and RL Transien ircuis Objecives To inroduce he ransiens phenomena. To analyze sep and naural responses of firs order R circuis. To analyze sep and naural responses of firs order RL circuis.
More informationEE202 Circuit Theory II
EE202 Circui Theory II 2017-2018, Spring Dr. Yılmaz KALKAN I. Inroducion & eview of Fir Order Circui (Chaper 7 of Nilon - 3 Hr. Inroducion, C and L Circui, Naural and Sep epone of Serie and Parallel L/C
More informationChapter 5: Control Volume Approach and Continuity Principle Dr Ali Jawarneh
Chaper 5: Conrol Volume Approach and Coninuiy Principle By Dr Ali Jawarneh Deparmen of Mechanical Engineering Hashemie Universiy 1 Ouline Rae of Flow Conrol volume approach. Conservaion of mass he coninuiy
More informationFI 2201 Electromagnetism
FI Electomagnetim Aleande A. Ikanda, Ph.D. Phyic of Magnetim and Photonic Reeach Goup ecto Analyi CURILINEAR COORDINAES, DIRAC DELA FUNCION AND HEORY OF ECOR FIELDS Cuvilinea Coodinate Sytem Cateian coodinate:
More informationMath 2214 Solution Test 1 B Spring 2016
Mah 14 Soluion Te 1 B Spring 016 Problem 1: Ue eparaion of ariable o ole he Iniial alue DE Soluion (14p) e =, (0) = 0 d = e e d e d = o = ln e d uing u-du b leing u = e 1 e = + where C = for he iniial
More informationChapter Finite Difference Method for Ordinary Differential Equations
Chape 8.7 Finie Diffeence Mehod fo Odinay Diffeenial Eqaions Afe eading his chape, yo shold be able o. Undesand wha he finie diffeence mehod is and how o se i o solve poblems. Wha is he finie diffeence
More informationCHAPTER 12 DIRECT CURRENT CIRCUITS
CHAPTER 12 DIRECT CURRENT CIUITS DIRECT CURRENT CIUITS 257 12.1 RESISTORS IN SERIES AND IN PARALLEL When wo resisors are conneced ogeher as shown in Figure 12.1 we said ha hey are conneced in series. As
More informationLecture 13 RC/RL Circuits, Time Dependent Op Amp Circuits
Lecure 13 RC/RL Circuis, Time Dependen Op Amp Circuis RL Circuis The seps involved in solving simple circuis conaining dc sources, resisances, and one energy-sorage elemen (inducance or capaciance) are:
More informationViscous Damping Summary Sheet No Damping Case: Damped behaviour depends on the relative size of ω o and b/2m 3 Cases: 1.
Viscous Daping: && + & + ω Viscous Daping Suary Shee No Daping Case: & + ω solve A ( ω + α ) Daped ehaviour depends on he relaive size of ω o and / 3 Cases:. Criical Daping Wee 5 Lecure solve sae BC s
More informationMath 2214 Solution Test 1A Spring 2016
Mah 14 Soluion Tes 1A Spring 016 sec Problem 1: Wha is he larges -inerval for which ( 4) = has a guaraneed + unique soluion for iniial value (-1) = 3 according o he Exisence Uniqueness Theorem? Soluion
More informationGeneral Non-Arbitrage Model. I. Partial Differential Equation for Pricing A. Traded Underlying Security
1 Geneal Non-Abiage Model I. Paial Diffeenial Equaion fo Picing A. aded Undelying Secuiy 1. Dynamics of he Asse Given by: a. ds = µ (S, )d + σ (S, )dz b. he asse can be eihe a sock, o a cuency, an index,
More informationAN ANALYTICAL METHOD OF SOLUTION FOR SYSTEMS OF BOOLEAN EQUATIONS
CHAPTER 5 AN ANALYTICAL METHOD OF SOLUTION FOR SYSTEMS OF BOOLEAN EQUATIONS 51 APPLICATIONS OF DE MORGAN S LAWS A we have een in Secion 44 of Chaer 4, any Boolean Equaion of ye (1), (2) or (3) could be
More informationLecture 23 Damped Motion
Differenial Equaions (MTH40) Lecure Daped Moion In he previous lecure, we discussed he free haronic oion ha assues no rearding forces acing on he oving ass. However No rearding forces acing on he oving
More informationLecture-V Stochastic Processes and the Basic Term-Structure Equation 1 Stochastic Processes Any variable whose value changes over time in an uncertain
Lecue-V Sochasic Pocesses and he Basic Tem-Sucue Equaion 1 Sochasic Pocesses Any vaiable whose value changes ove ime in an unceain way is called a Sochasic Pocess. Sochasic Pocesses can be classied as
More informationModule 2 F c i k c s la l w a s o s f dif di fusi s o i n
Module Fick s laws of diffusion Fick s laws of diffusion and hin film soluion Adolf Fick (1855) proposed: d J α d d d J (mole/m s) flu (m /s) diffusion coefficien and (mole/m 3 ) concenraion of ions, aoms
More informationr r r r r EE334 Electromagnetic Theory I Todd Kaiser
334 lecoagneic Theoy I Todd Kaise Maxwell s quaions: Maxwell s equaions wee developed on expeienal evidence and have been found o goven all classical elecoagneic phenoena. They can be wien in diffeenial
More informationControl Volume Derivation
School of eospace Engineeing Conol Volume -1 Copyigh 1 by Jey M. Seizman. ll ighs esee. Conol Volume Deiaion How o cone ou elaionships fo a close sysem (conol mass) o an open sysem (conol olume) Fo mass
More information( /100 pts) Total. Name: Key (TAB/DI ) Section: One staple or binder clip here.
One ale o binde cli hee. Name: Key (TAB/I.. Peon on my lef i: Peon on my igh i: xam Sing Thuday Mach (:-: in RICH, and Oienaion: You ae icly fobidden o collaboae by any mean collaboaion/cheaing F coue
More information, on the power of the transmitter P t fed to it, and on the distance R between the antenna and the observation point as. r r t
Lecue 6: Fiis Tansmission Equaion and Rada Range Equaion (Fiis equaion. Maximum ange of a wieless link. Rada coss secion. Rada equaion. Maximum ange of a ada. 1. Fiis ansmission equaion Fiis ansmission
More informationECE 2100 Circuit Analysis
ECE 1 Circui Analysis Lesson 35 Chaper 8: Second Order Circuis Daniel M. Liynski, Ph.D. ECE 1 Circui Analysis Lesson 3-34 Chaper 7: Firs Order Circuis (Naural response RC & RL circuis, Singulariy funcions,
More informationCHBE320 LECTURE IV MATHEMATICAL MODELING OF CHEMICAL PROCESS. Professor Dae Ryook Yang
CHBE320 LECTURE IV MATHEMATICAL MODELING OF CHEMICAL PROCESS Professor Dae Ryook Yang Spring 208 Dep. of Chemical and Biological Engineering CHBE320 Process Dynamics and Conrol 4- Road Map of he Lecure
More informationAPPM 2360 Homework Solutions, Due June 10
2.2.2: Find general soluions for he equaion APPM 2360 Homework Soluions, Due June 10 Soluion: Finding he inegraing facor, dy + 2y = 3e µ) = e 2) = e 2 Muliplying he differenial equaion by he inegraing
More informationDERIVATION OF LORENTZ TRANSFORMATION EQUATIONS AND THE EXACT EQUATION OF PLANETARY MOTION FROM MAXWELL AND NEWTON Sankar Hajra
PHYSICAL INTERPRETATION OF RELATIVITY THEORY CONFERENCE, LONDON, 4 DERIVATION OF LORENTZ TRANSFORMATION EQUATIONS AND THE EXACT EQUATION OF PLANETARY MOTION FROM MAXWELL AND NEWTON Sanka Haja CALCUTTA
More informationMECHANICS OF MATERIALS Poisson s Ratio
Fouh diion MCHANICS OF MATRIALS Poisson s Raio Bee Johnson DeWolf Fo a slende ba subjeced o aial loading: 0 The elongaion in he -diecion is accompanied b a conacion in he ohe diecions. Assuming ha he maeial
More informationMA Study Guide #1
MA 66 Su Guide #1 (1) Special Tpes of Firs Order Equaions I. Firs Order Linear Equaion (FOL): + p() = g() Soluion : = 1 µ() [ ] µ()g() + C, where µ() = e p() II. Separable Equaion (SEP): dx = h(x) g()
More informationQ & Particle-Gas Multiphase Flow. Particle-Gas Interaction. Particle-Particle Interaction. Two-way coupling fluid particle. Mass. Momentum.
Paicle-Gas Muliphase Flow Fluid Mass Momenum Enegy Paicles Q & m& F D Paicle-Gas Ineacion Concenaion highe dilue One-way coupling fluid paicle Two-way coupling fluid paicle Concenaion highe Paicle-Paicle
More information( ) c(d p ) = 0 c(d p ) < c(d p ) 0. H y(d p )
8.7 Gavimeic Seling in a Room Conside a oom of volume V, heigh, and hoizonal coss-secional aea A as shown in Figue 8.18, which illusaes boh models. c(d ) = 0 c(d ) < c(d ) 0 y(d ) (a) c(d ) = c(d ) 0 (b)
More informationReview - Quiz # 1. 1 g(y) dy = f(x) dx. y x. = u, so that y = xu and dy. dx (Sometimes you may want to use the substitution x y
Review - Quiz # 1 (1) Solving Special Tpes of Firs Order Equaions I. Separable Equaions (SE). d = f() g() Mehod of Soluion : 1 g() d = f() (The soluions ma be given implicil b he above formula. Remember,
More informationTesting the Random Walk Model. i.i.d. ( ) r
he random walk heory saes: esing he Random Walk Model µ ε () np = + np + Momen Condiions where where ε ~ i.i.d he idea here is o es direcly he resricions imposed by momen condiions. lnp lnp µ ( lnp lnp
More informationAQA Maths M2. Topic Questions from Papers. Differential Equations. Answers
AQA Mahs M Topic Quesions from Papers Differenial Equaions Answers PhysicsAndMahsTuor.com Q Soluion Marks Toal Commens M 600 0 = A Applying Newonís second law wih 0 and. Correc equaion = 0 dm Separaing
More informationME 304 FLUID MECHANICS II
ME 304 LUID MECHNICS II Pof. D. Haşme Tükoğlu Çankaya Uniesiy aculy of Engineeing Mechanical Engineeing Depamen Sping, 07 y du dy y n du k dy y du k dy n du du dy dy ME304 The undamenal Laws Epeience hae
More informationAns: In the rectangular loop with the assigned direction for i2: di L dt , (1) where (2) a) At t = 0, i1(t) = I1U(t) is applied and (1) becomes
omewok # P7-3 ecngul loop of widh w nd heigh h is siued ne ve long wie cing cuen i s in Fig 7- ssume i o e ecngul pulse s shown in Fig 7- Find he induced cuen i in he ecngul loop whose self-inducnce is
More informationCH.7. PLANE LINEAR ELASTICITY. Continuum Mechanics Course (MMC) - ETSECCPB - UPC
CH.7. PLANE LINEAR ELASTICITY Coninuum Mechanics Course (MMC) - ETSECCPB - UPC Overview Plane Linear Elasici Theor Plane Sress Simplifing Hpohesis Srain Field Consiuive Equaion Displacemen Field The Linear
More informationCHAPTER 7: SECOND-ORDER CIRCUITS
EEE5: CI RCUI T THEORY CHAPTER 7: SECOND-ORDER CIRCUITS 7. Inroducion Thi chaper conider circui wih wo orage elemen. Known a econd-order circui becaue heir repone are decribed by differenial equaion ha
More informationHow to Solve System Dynamic s Problems
How o Solve Sye Dynaic Proble A ye dynaic proble involve wo or ore bodie (objec) under he influence of everal exernal force. The objec ay uliaely re, ove wih conan velociy, conan acceleraion or oe cobinaion
More information8. Basic RL and RC Circuits
8. Basic L and C Circuis This chaper deals wih he soluions of he responses of L and C circuis The analysis of C and L circuis leads o a linear differenial equaion This chaper covers he following opics
More informationCHE302 LECTURE IV MATHEMATICAL MODELING OF CHEMICAL PROCESS. Professor Dae Ryook Yang
CHE302 LECTURE IV MATHEMATICAL MODELING OF CHEMICAL PROCESS Professor Dae Ryook Yang Fall 200 Dep. of Chemical and Biological Engineering Korea Universiy CHE302 Process Dynamics and Conrol Korea Universiy
More informationMA 366 Review - Test # 1
MA 366 Review - Tes # 1 Fall 5 () Resuls from Calculus: differeniaion formulas, implici differeniaion, Chain Rule; inegraion formulas, inegraion b pars, parial fracions, oher inegraion echniques. (1) Order
More informationWORK POWER AND ENERGY Consevaive foce a) A foce is said o be consevaive if he wok done by i is independen of pah followed by he body b) Wok done by a consevaive foce fo a closed pah is zeo c) Wok done
More informationū(e )(1 γ 5 )γ α v( ν e ) v( ν e )γ β (1 + γ 5 )u(e ) tr (1 γ 5 )γ α ( p ν m ν )γ β (1 + γ 5 )( p e + m e ).
PHY 396 K. Soluion for problem e #. Problem (a: A poin of noaion: In he oluion o problem, he indice µ, e, ν ν µ, and ν ν e denoe he paricle. For he Lorenz indice, I hall ue α, β, γ, δ, σ, and ρ, bu never
More informationPHYSICS 151 Notes for Online Lecture #4
PHYSICS 5 Noe for Online Lecure #4 Acceleraion The ga pedal in a car i alo called an acceleraor becaue preing i allow you o change your elociy. Acceleraion i how fa he elociy change. So if you ar fro re
More informationChapter 7: Inverse-Response Systems
Chaper 7: Invere-Repone Syem Normal Syem Invere-Repone Syem Baic Sar ou in he wrong direcion End up in he original eady-ae gain value Two or more yem wih differen magniude and cale in parallel Main yem
More informationu(t) Figure 1. Open loop control system
Open loop conrol v cloed loop feedbac conrol The nex wo figure preen he rucure of open loop and feedbac conrol yem Figure how an open loop conrol yem whoe funcion i o caue he oupu y o follow he reference
More informationINTRODUCTION TO INERTIAL CONFINEMENT FUSION
INTODUCTION TO INETIAL CONFINEMENT FUSION. Bei Lecure 7 Soluion of he imple dynamic igniion model ecap from previou lecure: imple dynamic model ecap: 1D model dynamic model ρ P() T enhalpy flux ino ho
More information-6 1 kg 100 cm m v 15µm = kg 1 hr s. Similarly Stokes velocity can be determined for the 25 and 150 µm particles:
009 Pearon Educaion, Inc., Upper Saddle Rier, NJ. All righ reered. Thi publicaion i proeced by Copyrigh and wrien periion hould be obained fro he publiher prior o any prohibied reproducion, orage in a
More information13.1 Circuit Elements in the s Domain Circuit Analysis in the s Domain The Transfer Function and Natural Response 13.
Chaper 3 The Laplace Tranform in Circui Analyi 3. Circui Elemen in he Domain 3.-3 Circui Analyi in he Domain 3.4-5 The Tranfer Funcion and Naural Repone 3.6 The Tranfer Funcion and he Convoluion Inegral
More informationChapter 7 Response of First-order RL and RC Circuits
Chaper 7 Response of Firs-order RL and RC Circuis 7.- The Naural Response of RL and RC Circuis 7.3 The Sep Response of RL and RC Circuis 7.4 A General Soluion for Sep and Naural Responses 7.5 Sequenial
More informationu(x) = e x 2 y + 2 ) Integrate and solve for x (1 + x)y + y = cos x Answer: Divide both sides by 1 + x and solve for y. y = x y + cos x
. 1 Mah 211 Homework #3 February 2, 2001 2.4.3. y + (2/x)y = (cos x)/x 2 Answer: Compare y + (2/x) y = (cos x)/x 2 wih y = a(x)x + f(x)and noe ha a(x) = 2/x. Consequenly, an inegraing facor is found wih
More informationOn Control Problem Described by Infinite System of First-Order Differential Equations
Ausalian Jounal of Basic and Applied Sciences 5(): 736-74 ISS 99-878 On Conol Poblem Descibed by Infinie Sysem of Fis-Ode Diffeenial Equaions Gafujan Ibagimov and Abbas Badaaya J'afau Insiue fo Mahemaical
More informationBoyce/DiPrima 9 th ed, Ch 2.1: Linear Equations; Method of Integrating Factors
Boc/DiPrima 9 h d, Ch.: Linar Equaions; Mhod of Ingraing Facors Elmnar Diffrnial Equaions and Boundar Valu Problms, 9 h diion, b William E. Boc and Richard C. DiPrima, 009 b John Wil & Sons, Inc. A linar
More informationDifferential Equations
Mah 21 (Fall 29) Differenial Equaions Soluion #3 1. Find he paricular soluion of he following differenial equaion by variaion of parameer (a) y + y = csc (b) 2 y + y y = ln, > Soluion: (a) The corresponding
More informationSTUDY OF THE STRESS-STRENGTH RELIABILITY AMONG THE PARAMETERS OF GENERALIZED INVERSE WEIBULL DISTRIBUTION
Inenaional Jounal of Science, Technology & Managemen Volume No 04, Special Issue No. 0, Mach 205 ISSN (online): 2394-537 STUDY OF THE STRESS-STRENGTH RELIABILITY AMONG THE PARAMETERS OF GENERALIZED INVERSE
More informationdy dx = xey (a) y(0) = 2 (b) y(1) = 2.5 SOLUTION: See next page
Assignmen 1 MATH 2270 SOLUTION Please wrie ou complee soluions for each of he following 6 problems (one more will sill be added). You may, of course, consul wih your classmaes, he exbook or oher resources,
More informationThe Non-Truncated Bulk Arrival Queue M x /M/1 with Reneging, Balking, State-Dependent and an Additional Server for Longer Queues
Alied Maheaical Sciece Vol. 8 o. 5 747-75 The No-Tucaed Bul Aival Queue M x /M/ wih Reei Bali Sae-Deede ad a Addiioal Seve fo Loe Queue A. A. EL Shebiy aculy of Sciece Meofia Uiveiy Ey elhebiy@yahoo.co
More informationSubstances that are liquids or solids under ordinary conditions may also exist as gases. These are often referred to as vapors.
Chapte 0. Gases Chaacteistics of Gases All substances have thee phases: solid, liquid, and gas. Substances that ae liquids o solids unde odinay conditions may also exist as gases. These ae often efeed
More informationECE 2100 Circuit Analysis
ECE 1 Circui Analysis Lesson 37 Chaper 8: Second Order Circuis Discuss Exam Daniel M. Liynski, Ph.D. Exam CH 1-4: On Exam 1; Basis for work CH 5: Operaional Amplifiers CH 6: Capaciors and Inducor CH 7-8:
More informationY 0.4Y 0.45Y Y to a proper ARMA specification.
HG Jan 04 ECON 50 Exercises II - 0 Feb 04 (wih answers Exercise. Read secion 8 in lecure noes 3 (LN3 on he common facor problem in ARMA-processes. Consider he following process Y 0.4Y 0.45Y 0.5 ( where
More informationX-Ray Notes, Part III
oll 6 X-y oe 3: Pe X-Ry oe, P III oe Deeo Coe oupu o x-y ye h look lke h: We efe ue of que lhly ffee efo h ue y ovk: Co: C ΔS S Sl o oe Ro: SR S Co o oe Ro: CR ΔS C SR Pevouly, we ee he SR fo ye hv pxel
More information2.1. Differential Equations and Solutions #3, 4, 17, 20, 24, 35
MATH 5 PS # Summr 00.. Diffrnial Equaions and Soluions PS.# Show ha ()C #, 4, 7, 0, 4, 5 ( / ) is a gnral soluion of h diffrnial quaion. Us a compur or calculaor o skch h soluions for h givn valus of h
More informationLECTURE 14. m 1 m 2 b) Based on the second law of Newton Figure 1 similarly F21 m2 c) Based on the third law of Newton F 12
CTU 4 ] NWTON W O GVITY -The gavity law i foulated fo two point paticle with ae and at a ditance between the. Hee ae the fou tep that bing to univeal law of gavitation dicoveed by NWTON. a Baed on expeiental
More informationUNIT #4 TEST REVIEW EXPONENTIAL AND LOGARITHMIC FUNCTIONS
Name: Par I Quesions UNIT #4 TEST REVIEW EXPONENTIAL AND LOGARITHMIC FUNCTIONS Dae: 1. The epression 1 is equivalen o 1 () () 6. The eponenial funcion y 16 could e rewrien as y () y 4 () y y. The epression
More informationCh23. Introduction to Analytical Separations
Ch3. Inoducion o Analyical Sepaaions 3. Medical Issue : Measuing Silicones Leaking fo Beas Iplans High olecula ass poly(diehylsiloane), PDMS, [(CH 3 ) SiO] n : Used as GC saionay phase, gels in beas iplans
More informationSelective peracetic acid determination in the presence of hydrogen peroxide using the molecular absorption properties of catalase
Analyical and Bioanalyical Chemisry Elecronic Supplemenary Maerial Selecive peraceic acid deerminaion in he presence of hydrogen peroxide using he molecular absorpion properies of caalase Javier Galbán,
More informationln 2 1 ln y x c y C x
Lecure 14 Appendi B: Some sample problems from Boas Here are some soluions o he sample problems assigned for Chaper 8 8: 6 Soluion: We wan o find he soluion o he following firs order equaion using separaion
More informationLAPLACE TRANSFORM AND TRANSFER FUNCTION
CHBE320 LECTURE V LAPLACE TRANSFORM AND TRANSFER FUNCTION Professor Dae Ryook Yang Spring 2018 Dep. of Chemical and Biological Engineering 5-1 Road Map of he Lecure V Laplace Transform and Transfer funcions
More informationBayesian Designs for Michaelis-Menten kinetics
Bayeian Deign for ichaeli-enen kineic John ahew and Gilly Allcock Deparen of Saiic Univeriy of Newcale upon Tyne.n..ahew@ncl.ac.uk Reference ec. on hp://www.a.ncl.ac.uk/~nn/alk/ile.h Enzyology any biocheical
More informationMath 2214 Solution Test 1B Fall 2017
Mah 14 Soluion Tes 1B Fall 017 Problem 1: A ank has a capaci for 500 gallons and conains 0 gallons of waer wih lbs of sal iniiall. A soluion conaining of 8 lbsgal of sal is pumped ino he ank a 10 galsmin.
More information(b) (a) (d) (c) (e) Figure 10-N1. (f) Solution:
Example: The inpu o each of he circuis shown in Figure 10-N1 is he volage source volage. The oupu of each circui is he curren i( ). Deermine he oupu of each of he circuis. (a) (b) (c) (d) (e) Figure 10-N1
More informationy = (y 1)*(y 3) t
MATH 66 SPR REVIEW DEFINITION OF SOLUTION A funcion = () is a soluion of he differenial equaion d=d = f(; ) on he inerval ff < < fi if (d=d)() =f(; ()) for each so ha ff
More informationProblem Set #1. i z. the complex propagation constant. For the characteristic impedance:
Problem Se # Problem : a) Using phasor noaion, calculae he volage and curren waves on a ransmission line by solving he wave equaion Assume ha R, L,, G are all non-zero and independen of frequency From
More informationWall. x(t) f(t) x(t = 0) = x 0, t=0. which describes the motion of the mass in absence of any external forcing.
MECHANICS APPLICATIONS OF SECOND-ORDER ODES 7 Mechanics applicaions of second-order ODEs Second-order linear ODEs wih consan coefficiens arise in many physical applicaions. One physical sysems whose behaviour
More information