STA 4321/5325 Solution to Homework 5 March 3, 2017

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1 STA 4/55 Solution to Homework 5 March, 7. Suppose X is a RV with E(X and V (X 4. Find E(X +. By the formula, V (X E(X E (X E(X V (X + E (X. Therefore, in the current setting, E(X V (X + E (X Therefore, E(X + E(X + 4X + 4 E(X + 4E(X (WMS, Problem 4.8. The proportion of time per day that all checkout counters in a supermarket are busy is a RV Y with PDF { cy ( y 4, y f(y, elsewhere. (a Find the value of c that makes f(y a probability density function. (b Find E(Y. (a Observe that f(x dx Hence, from c f(x dx, we get (b Note that E(Y y ( y 4 dy ( z z 4 ( dz (substitute z y ( b a ( z z 4 dz g(x dx ( z + z z 4 dz (z 4 z 5 + z 6 dz ( z 5 5 z6 6 + z7 7 yf(y dy c 5. a y y ( y 4 dy b g(x dx ( ( z z 4 dz (substitute z y ( z + z z z 4 dz (z 4 z 5 + z 6 z 7 dz

2 ( z z6 6 ( z7 7 z An absolutely continuous RV X with PDF f is called symmetric (about, if for every x R, f(x f( x. (a Assuming it exists, show that E(X. (b If F denotes the DF of X, show that F (. Hence find the median of X. (You can assume F to be strictly increasing on a neighborhood of. [Hint: Use the properties of odd and even functions.] (a Method (Direct proof: Note that E(X xf(x dx ( yf( y( dy ( yf( y dy ( yf(y dy yf(y dy E(X Hence, E(X E(X. substitue y x dy dx ( b a g(x dx g(x dx a since f(y f( y for all y b Method (Using property of odd functions: By definition, E(X xf(x dx. Note that the integrand g(x xf(x is odd, since g( x xf( x xf(x g(x. Hence, E(X, an (definite integral of an odd function over the symmetric interval (,, is zero. (b We have, f(y dy (integral of a PDF over the entire real line. integrand f(y is an even function since f(y f( y. Therefore, f(y dy Thus, F ( P (Y P (Y >. f(y dy P (Y > P (Y >. Note that the To find the median φ /, first note that F is strictly increasing on a neighborhood of. So, F exists as a function on that neighborhood. Therefore, φ / is obtained by solving F (φ / ( φ / F F (F (.

3 4. (WMS, Problem 4.. The proportion of time Y that an industrial robot is in operation during a 4-hour week is a random variable with probability density function { y, y f(y, elsewhere. (a Find E(Y and V (Y. (b For the robot under study, the profit X for a week is given by X Y 6. Find E(X and V (X. (c Find an interval in which the profit should lie for at least 75% of the weeks that the robot is in use. and (a We have E(Y E(Y yf(y dy y f(y dy y y dy y y y dy y4 4 Therefore, V (Y E(Y E (Y (b By the formula, E(X E(Y 6 E(Y 6 (/ 6 / and V (X V (Y 6 V (Y /9. (c Recall from Chebyshev s theorem, the two standard deviation (k interval about mean has probability greater than or equal to k %. Hence, required interval in the current setting [/ /9, /+ /9] [.9476, 67.64]. 5. (WMS, Problem The failure of a circuit board interrupts work that utilizes a computing system until a new board is delivered. The delivery time, Y, is uniformly distributed on the interval one to five days. The cost of a board failure and interruption includes the fixed cost c of a new board and a cost that increases proportionally to Y. If C is the cost incurred, C + c Y. (c is a constant. (a Find the probability that the delivery time exceeds two days. (b In terms of c and c, find the expected cost associated with a single failed circuit board. (a By assumption, Y U(θ, θ 5. Let F Y ( denote the DF of Y. Therefore, required probability P (Y > P (Y F Y ( θ θ θ (b Recall, if Y U(θ, θ then E(Y θ +θ and V (Y (θ θ 4. Therefore, E(Y V (Y + E (Y (See solution to problem. Hence, E(C E(c + c Y + c E(Y + c.

4 6. Recall that the MGF of a RV X is defined by M X (t : E(e tx. Hence, for continuous X, M X (t etx f(x dx, f being the PDF of X. From this definition, find the MGF of X when X Exp(β. Hence (by differentiating find E(X and E(X. Then find V (X. By definition, M X (t e tx f(x dx provided β t > t < β. Note that M X(t d dt M X(t β β β e tx β e x β dx e e ( β tx dx ( e βt x β dx ( βt β ( βt β x ( βt ( β β ( βt M X(t d dt M X(t d dt M X(t β βt, ( βt ( β β ( βt. Therefore, E(X M X (t t β and E(X M X (t t β. Hence V (X E(X E (X β β β. 7. (WMS, Problem A manufacturing plant uses a specific bulk product. The amount of product used in one day can be modeled by an exponential distribution with β 4 (measurements in tons. (a Find the probability that the plant will use more than 4 tons on a given day. (b How much of the bulk product should be stocked so that the plants chance of running out of the product is only.5? Let X denote the amount (in tons of product used in one day. Then by assumption X Exp(β 4. So, the DF of X is F X (x e x/β e x/4 for x. (a Required probability P (X > 4 P (X 4 F X (4 ( e 4/4 e.679. (b We need x (in tons such that P (X > x.5. Now P (X > x F X (x e x/4. Therefore, e x/4.5 x/4 log(.5 x 4 log( tons. 8. (WMS, Problem 4.9. Let Y have an exponential distribution with P (Y >.8. Find E(Y and P (Y.7. 4

5 Let Y Exp(β. We need to find β. Recall Y has DF F Y (y e y/β for y. Therefore, P (Y > F Y ( e /β.8 β log(.8 β log(.8.8. Hence, E(Y β.8 and P (Y.7 e.7/

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