Tsunami Load Determination for On-Shore Structures. Harry Yeh Oregon State University

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1 Tsunami Load Determination for On-Shore Structures Harry Yeh Oregon State University

2 Building survival

3 Vertical Evacuation to Tsunami Shelters

4 How can we estimate the tsunami forces on such onshore structures?

5 Force Category in the Present Codes City and County of Honolulu Building Code (2000) Hydrostatic Forces Buoyant Forces Hydrodynamic Forces Surge Forces Impact Forces Breaking Wave Forces

resulted from an undular bore. (Yeh, et al.

6 Wave breaking at the shore Typical when: steep beach slope narrow continental shelf A collapsing breaker resulted from an undular bore. (Yeh, et al. 1989) A sketch of Scotch Cap Lighthouse (1946 Aleutian Tsunami)

7 Some Considerations Tsunami shelters are located on land some distance away from the shoreline. Tsunami shelters are needed in the areas of relatively flat terrain where natural high-ground safe havens are not accessible. Formation of a surge may be the most likely flow condition. Wave breaking takes place offshore. The only exception is the collapsing breaker type, which occurs right at the shoreline on a steep-slope beach. We will not consider wave-breaking force

8 Force Category in the Present Codes Hydrostatic Forces Buoyant Forces Hydrodynamic Forces Surge Forces Impact Forces Breaking Wave Forces

9 Hydrostatic Force It is usually important for a 2-D structure such as seawalls and dikes, or for evaluation of an individual wall panel, but not for buildings F h = p c A w = g h max h w 2 bh w for h max > h w, else h max h w p c is the hydrostatic pressure at the centroid of the wetted portion of the wall panel, A w is the wetted area of the panel h max is the maximum water height above the base of the wall h w is the height of wall panel

Buoyant Force The buoyant forces act vertically through the center of mass of the displaced volume F B = gv Buoyant forces are a concern for wood frame buildings, empty above-ground and

10 Buoyant Force The buoyant forces act vertically through the center of mass of the displaced volume F B = gv Buoyant forces are a concern for wood frame buildings, empty above-ground and below-ground tanks. and, for evaluation of an individual floor panel where the water level outside is substantially higher than the level inside. (Lesson learned from Hurricane Katrina)

11 Case-by-case evaluation for hydrostatic force and buoyancy forces on an individual wall panel and a floor panel and alike. We only need the water depth h to compute the hydrostatic forces, which is readily estimated from the inundation maps

12 Force Category in the Present Codes Hydrostatic Forces Buoyant Forces Hydrodynamic Forces Surge Forces Impact Forces Breaking Wave Forces

13 Hydrodynamic Force When steady water flows around a building (or structural element or other object) hydrodynamic loads are applied to the building F D = 1 2 C D Au2 Drag Force Width to Depth Ratio Drag Coefficient Cd (w/ds or w/h) From > (FEMA CCM)

14 Hydrodynamic Force Force = 1 2 C d A f u 2 bhu 2 h: water depth u: flow velocity b: breadth Laboratory Data of Tsunami Force on a Squire Column: C d Surge force Hydrodynamic force C d O (1) 2 But, how do we determine the value of h u 2?

15 Force Category in the Present Codes Hydrostatic Forces Buoyant Forces Hydrodynamic Forces Surge Forces Impact Forces Breaking Wave Forces

16 Surge Force (present codes) Surge forces are caused by the leading edge of a surge of water impinging on a structure F s = 4.5 gh 2 b F s b = 1 2 gh2 + u 2 h: u = 2 gh Keulegan (1950) The identical approach by the Building Center of Japan h is the surge height -- how can we determine? u = 2 gy

17 Ramsden, 1993

18 Bore vs Surge No initial water-impact force in dry-bed surges Comparison of the experimental a) wave profile; b) runup; c) pressure head; and d) force due to a strong turbulent bore and a dry bed surge (after Ramsden, 1993)

19 Force Category in the Present Codes Hydrostatic Forces Buoyant Forces Hydrodynamic Forces Surge Forces Impact Forces Breaking Wave Forces

20 Impact Force Impact loads are those that result from debris such as driftwood, small boats, portions of houses, etc., or any object transported by floodwaters, striking against buildings and structures

21 Lincoln City, Oregon Driftwood becomes hazardous

22 Impact Force (present codes) F I = m du dt = m u I t Type of construction Duration (t) of Impact (sec) Wall Pile Wood Steel NA Reinforced Concrete Concrete Masonry (FEMA CCM) This is based on the impulse-momentum approach: I = 0 Fdt = dmu ( ); 0

23 ASCE 7-02 Relevant Literature ASCE Standard Minimum design loads for buildings and other structures. SEI/ASCE City and County of Honolulu Building Code (CCH, 2000) Matsutomi J. Hydr., Coastal, Envr. Engrg., 621, 1999 & Tsunami Engineering Tech. Rep., 13, 1996 Ikeno, et al. 2001, Impulse Force of Drift Body Haehnel and Daly USACOE Report, ERDC/CRREL TR-02-2

24 ASCE 7-02 (2003) F = muc I C O C D C B R max 2 t m: the debris mass, u: the impact velocity of object, C i : the importance coefficient, C O : the orientation coefficient, C D : the depth coefficient, C B : the blockage coefficient, R max : the maximum response ratio for impulsive load t: the impact duration: t = 0.03 sec is recommended City and County of Honolulu Building Code (2000) recommends t = 1.0 sec for wood construction, t = 0.5 sec for steel construction, and t = 0.1 sec for reinforced concrete FEMA CCM, t = 0.2 ~ 1.1 sec

25 Matsutomi: J. Hydr., Coastal, Envr. Engrg., 621, 1999 & Tsunami Engineering Tech. Rep., 13, 1996 Impact force evaluation: F = M dv dt t F ( t) dt = C M MV 0 0 F w D 2 L = 1.6C M u gd 1.2 f w L 0.4 Specifically for lumber impact Using small-scale laboratory experiments, C M = 1.7 (C M = 1.9 for steady flows) Use large-scale dry experiments, u: impact velocity w : specific weight of lumber f : yield stress of lumber ( compressive strength) ~ 20 MPa D: diameter of lumber L: length of lumber

26 Matsutomi s work

27 Haehnel and Daly, 2002 Lumber impact 0; m s» m l ; k s» k t, k l 1 ˆ k = 1 k t + 1 k l m 1 x + ˆk x= 0 x = u m sin t ˆk ˆk m F = ˆkx F max = Max. ˆkx = u ˆkm

28 1.22 x 0.61 x 36.6 m flume. 9.1 x 37 x 2.4 m basin Experiments by Haehnel & Daly

29 Constant Stiffness Approach: Haehnel and Daly F max = Max. ˆkx = u ˆkm 1550u m From their experiments, the effective constant stiffness is 2.4 MN/m (but no flow in their experiments) Impulse-Momentum Approach: F max = 2 um t The impulse-momentum approach reduces to the constant stiffness approach by setting Work-Energy Approach: F max = u2 m x 90.9um 125 mu The work-energy approach reduces to the constant stiffness approach by setting t = 2 x = u m ˆk m ˆk

30 Comments Uncertainty may be resulted from the fact that the prediction models are based on the empirical scaled-down (and small) data. All of the previous works are for impact of a relatively small water-borne missile, e.g. a lumber log. No consideration was made for impact of a large missile such as a ship.

31 Comments Different relations based on the model: Constant Stiffness Approach F u m n = 0.50 Impulse-Momentum Approach F um Work-Energy Approach F u 2 m Ikeno et al. (2003) F u 2.5 m n n 0.58 Matsutomi (1999) F u 1.2 m n n 0.66 Impulse-Momentum Approach: Work-Energy Approach: t = 2 x = u m ˆk m ˆk

32 Summary & Recommendations Forces on a building examined for a tsunami shelter. Hydrodynamic force with C D = 2. Surging force may not be important, but if we consider bore formation, this can be taken into account by using C D = 3 instead of 2. F D = 1 2 C D bhu2 Impact force can be evaluated by the modified constant stiffness approach with an appropriate value of effective stiffness k, and the added mass coefficient C M ( 2). k = 2.4MN/m was recommended for a lumber F max = C M u ˆkm

33 Recommendations - continue Need the design values of h, u, hu 2 at the site of interest. Note that: Max (hu 2 ) Max (h) Max (u 2 ) Obtain the data from detailed numerical simulations with a very fine grid size in the runup zone ( < 10 m). As for a guideline, use of the analytical solutions for 1-D runup on a uniformly sloping beach.

34 A snap shot of numerical simulation Available inundation map

35 Maximum hu 2 distribution in the runup zone (analytic solution for 1-D runup on a uniformly sloping beach) hu 2 g 2 = 0.11 ( x ) ( x ). Max. inundation Yeh (2006) Shore line

36 To obtain the design values of h, u, hu 2 at the site of interest Long-Wave Runup on a Plane Beach Nonlinear Problem Carrier and Greenspan (1958) Carrier, Wu, and Yeh (2003) -- Analytic-Numeric Hybrid Approach 0 x

37 The fully nonlinear shallow-water wave [ u' ( x' + ' )] x' + ' t ' = 0, u' t' + u' u' x' + g' x' = 0, Scaling: u' = g L u; ' = L; x' = Lx; t' = L g t [ ux+ ( ) ] x + t = 0, u t + uu x + x = 0.

38 Introducing the distorted coordinates q and such that: = t u; q = x + The transformation yields: ( qu) q + + u 2 2 u + + u2 2 q = 0. = 0, = + u2 2 = q = x +

39 4 ( ) = 0 where = + u2 2 The same form as the one by Carrier-Greenspan (1958). For convenience, we introduce the variable : = + u 2 2 = ; u = 2 ; = ( ) = 0 Initial Conditions at = t u = 0:,0 ( )= P( ), (,0)= F ( ), ( ) P( )= 2' u( ',0) d', and F( )=,0 ( )+ u2,0 0 2.

40 Summary 4 ( ) = 0, ( )= 2 Fb { ( ) Gb,, ( )db + Pb ( ) G 0 0 ( b,,) } db With ICs: ( ) P( )= 2' u( ',0) d', and F( )=,0 ( )+ u2, = + u 2 2 = ; u = 2 ; = = t u; = x +

41 The initial wave form of a Gaussian shape x

42 (, ) for the Gaussian shaped initial displacement Lambda Sigma

43 Water-surface plot for the Gaussian shaped initial displacement 4.0 t x

44 Water-surface profile at t = x

Water-depth variations: q (a) 3.5 3.0 t t 2.5 2.

45 Water-depth variations: q (a) t t x q

Water velocity: u (a) 3.5 t 3.0 t 2.5 2.0 1.5-0.

46 Water velocity: u (a) 3.5 t 3.0 t x u

47 Momentum Flux (Fluid Force) h u (a) 3.0 t x x q*u^2

48 Initial Waveforms x x x x

(a) Fluid Forces (b) 3.5 3.5 3.0 3.0 x 2.5 2.5 2.0 2.0 1.5-0.

5 3.5 3.0 0.00000 0.00020 0.00040 0.00060 q*u^2 3.0 0.00000 0.00020 0.00040 0.00060 q*u^2 t 2.

49 (a) Fluid Forces (b) x (c) (d) q*u^ q*u^2 t 2.5 t x x q*u^ q*u^2

50 Maximum force distribution from the maximum runup qu 2 gd Location of the initial shoreline LS NW Gaussian Ng-Gaussian X/L from the maximum runup

51 Maximum hu 2 distribution in the runup zone (analytic solution for 1-D runup on a uniformly sloping beach) hu 2 g 2 = 0.11 ( x ) ( x ). Max. inundation Yeh (2006) Shore line

52 Hydrodynamic and Surge Forces Hydrodynamic force with C D = 2. Surging force may not be important, but if we consider bore formation, this can be taken into account by using C D = 3 instead of 2. F D = 1 2 C D bhu2 h max R z datum l x hu 2 g 2 = 0.11 ( x ) ( x ) based on the distance hu 2 gr = z 2 R z R 2 based on the elevation

53 Impact Force max. u Impact force can be evaluated by the modified constant stiffness approach with an appropriate value of effective stiffness k, and the added mass coefficient C M ( 2). k = 2.4MN/m was recommended for a lumber. F I = C M u ˆkm

54 Bore Runup Process

55 Analytical Solution to Determine u max Maximum flow-speed u distribution in the runup zone: at the leading tongue of a surge front where the depth d = 0. uniform bore Ho and Meyer (1962) Yeh et al. (1989) u max = u max = 2 g ( x) 2 gr 1 z R u 2 g tan Yeh (2006) x

56 Floating debris with a finite draft draft Nagappattinam, India, 2004

57 Analytical solution to determine u max for a floatable debris with a finite draft The upper limit of flow-speed u for the depth d: d can be the draft of a floating debris. For bore runup, based on Shen and Meyer (1963), Peregrine and Williams (2001) presented: = 1 ( ) = 1 ( ) where = d R ; = u 2 gr ; = t g R ; = z R

58 The max. flow velocity R = maximum runup elevation. z = ground elevation d = flow depth d/r = (1) 0, (2) , (3) 0.01, (4) 0.02, (5) 0.04, (6) 0.06, (7) 0.08, (8) 0.10, and (9) 0.12.

59 Example Maximum runup height R = 10 m. Beach slope = 1/50 (= 0.02) Location of the shelter 100 m from the shoreline (z = 2 m), and the shelter breadth b = 10 m. Drift wood -- mass = 450 kg; effective stiffness k = N/m Shipping container -- mass = 30,000kg; 12.2m 2.44 m 2.59m h max = 8 m = 1025 kg/m 3 for sea water h max R = 10 m z = 2 m datum

60 Hydrodynamic and surge forces: Example ( hu 2 ) = gr z max R z R F d = 1 2 C B d ( ) hu2 max ( 1025 kg m3) ( 3.0) ( 10 m) ( 80.8 m 3 sec 2 ) = 1 2 = 1240 kn Impact forces (drift wood): 2 = 80.8 m3 sec 2 u max = 2 gr 1 z R = 12.5 m sec. F i = C m u max km = 2.0( 12.5 m sec) ( N m) ( 450 kg) = 822 kn

61 Impact force (shipping container): Example draft d is: d = = W A box kg ( 1025 kg m 3 ) 12.2 m 2.44 m ( ) = 0.98 m At the location of the shelter site, = z/r = 0.2, and the flow depth, d/r = The figure shows u max along the limit curve at = Hence, the maximum velocity is: u max = gr = 2.5 m sec. F i = C m u max km = 2.0( 2.5 m sec) ( N m) ( kg) = 1340 kn

62 1) d/r = 0, 2) , 3) 0.01, 4) 0.02, 5) 0.04, 6) 0.06, 7) 0.08, 8) 0.10, and 9) 0.12

GENERAL SOLUTIONS FOR THE INITIAL RUN-UP OF A BREAKING TSUNAMI FRONT

International Symposium Disaster Reduction on Coasts Scientific-Sustainable-Holistic-Accessible 14 16 November 2005 Monash University, Melbourne, Australia GENERAL SOLUTIONS FOR THE INITIAL RUN-UP OF A