Sph3u Practice Unit Test: Kinematics (Solutions) LoRusso
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1 Sph3u Prcice Uni Te: Kinemic (Soluion) LoRuo Nme: Tuey, Ocober 3, 07 Ku: /45 pp: /0 T&I: / Com: Thi i copy of uni e from 008. Thi will be imilr o he uni e you will be wriing nex Mony. you cn ee here re quie few queion on he e. When you wrie uni e you houl lwy mke ure you nwer he following queion fir. Sr wih he queion h re worh he mo in he knowlege ecion. Then focu on pplicion / Thinking & Inveigion queion. Since we only hve one pplicion queion per e uully, ech queion i worh ignificn moun becue i mrke in epre cegory. The me pplie o he T&I queion. Then complee he hor nwer muliple choice followe by he regulr muliple choice l. Why o he muliple choice queion l? ecue you cn lwy gue if you run ou of ime. Muliple Choice [ku: 9] Ienify he leer of he choice h be complee he emen or nwer he queion Which of he following i "clr" quniy?. ince. iplcemen b. velociy e. none of he bove c. ccelerion The erm "uniform moion" men. ccelerion i conn. iplcemen i conn b. pee i conn e. velociy i zero c. velociy i conn The lope of poiion-ime grph lwy repreen. iplcemen. chnge in velociy b. ince e. ccelerion c. velociy The re uner velociy-ime grph lwy repreen. iplcemen. ccelerion b. chnge in velociy e. chnge in ccelerion c. ince The poiion-ime grph picure below repreen he moion of wo objec, n. Which of he following emen concerning he objec' moion i rue?. Objec rvel he greer ince. b. Objec h he greer pee. c. Objec leve he reference poin n erlier ime.. oh objec hve he me pee he poin where he line cro. e. Objec i rvelling for longer perio of ime. The poiion-ime grph h epic bll hrown vericlly upwr h reurn o he me poiion i 7... D e. E c. C The poiion-ime grph h repreen "uniform moion" i.. D b. e. E c. C
2 8. Conier he following velociy-ime grph n elec he emen h i rue. 9.. no ime cn he moion be coniere "uniform." b. The objec reurn o i originl poiion. c. The objec rvel in one irecion n hen he oher.. The objec i ccelering hroughou he enire recore ime. e. The objec pee up n ler low own. Four of he five grph picure below coul ll repreen he me moion. Which grph oe no belong o hi group? Thi queion cully h concepul problem. n D repreen negive ccelerion ( frownie bi) n, C, n E repreen poiive ccelerion miley bi herefore he queion i no cler... D b. e. E c. C Shor nwer Muliple Choice (RFS i NOT require) [ku: 8] 0. cycli rie bicycle 4.0 km we, hen 3.0 km norh. Wh i he cycli' iplcemen?. 7.0 km [37 N of W]. 5.0 km [37 W of N] b. 7.0 km [37 W of N] e..0 km [37 W of N] c. 5.0 km [37 N of W] b nθ b 3.0km[ N] + b θ 4.0km[ W] θ n θ 37. cr rive 6.0 km [E], hen 8.0 km [S] in ol ime of 0.30 h. Wh i he cr' verge pee?. 33 km/h. 47 km/h [E of S] b. 47 km/h e. 47 km/h [S of E] c. 33 km/h [E of S] ol vvg ol + b vvg ol vvg 0.30 v 47 km/ h vg
3 . If n objec ccelere 6. m/ [N], how long will i ke o rech velociy of 5 m/ [N] if ring from re? b. 4.0 m/ e. 4.0 c m/ [ N] Δv Δ v 0 m/ Δv Δ [ ] v 5 m/ N Δ 6. Δ n objec i hrown vericlly upwr 5.0 m/. If i experience n ccelerion ue o grviy of 9.8 m/ [own], wh i he objec' velociy 3.0 ler?. m/ [own]. 4 m/ [own] b. m/ [up] e. zero (i h hi he groun) c. 4 m/ [up] v m/ v v+ 9.8 m/ v ( 9.8)( 3.0) 3.0 v 4.4 m/ 4. one i hrown vericlly ownwr wih pee of 0 m/ from brige. ccelering uner grviy (9.8 m/ ), he one rike he wer.8 ler. From wh heigh bove he wer w he one hrown? (ume ignificn igi.). 50 m. 5 m b. 34 m e. 3 m c. 7 m v 0 m/ v m/.8 ( 0)(.8) + ( 9.8)(.8) 34m
4 5. The igrm below how he fir hree leg of rip: o, o C, n C o D. If peron reurn from poin D o poin, wh i he iplcemen for hi fourh n finl leg?. 7 km [37 W of N]. 7 km [37 E of S] b. 5 km [37 W of N] e. 5 km [37 N of E] c. 5 km [37 E of S] x 3km θ y 4km x + y + 5m ( 3) ( 4) nθ θ n θ 37 0 x y 3 4
5 Problem Solving (ll queion houl be complee in he RFS form). Mr. LoRuo i ning in he hll checking ex mege when Mr. ee run by n hou NO PERSONL ELECTRONIC DEVICES!!! hen grb he cell phone n run hrough he hll conn pee of 4.00 m/, lughing mniclly ll he while. Mr. LoRuo innneouly che fer him ccelering re of.0 m/ houing him Wi!!! I w exing my mom!!! Deermine: [ku: 8] ) how long i ke for Mr. LoRuo o cch up o Mr. ee. (inclue igrm) b) how fr Mr. LoRuo h o run o cch up o him. (Expre your nwer in pr ) n b) o he correc number of ig. fig.) L v 4.0 m/ x LoRuo ee v L vl L + LL x 4.0 x 0+ (.0) ( ) x.0 () Sub () ino () Sub 4.0 ino () x 4.0( 4.0) x 6m 4.0 vl 0 m/ L.0 m/ L x L
6 . fer Mr. LoRuo inercep n rerieve hi phone from Mr. ee, he op hen urn n run he oher wy for 4, ccelering re of.5 m/ which poin he rip n lie forwr for noher 3.0 before he come o op righ Mr. orki fee. [ku: 0] ) How fr i Mr. LoRuo run before he rippe? (inclue igrm) b) How f w he going before he rippe? c) How fr i he lie? ) Wh w hi re of ccelerion uring he lie? Secion v v Secion v 0 m/.5 m/? 4.0 v 0 m/?? 3.0 ) Fin b) Fin v c) Fin ) Fin v v + Δv v + LL ( v + v ) v ( 0) + (.5)( 4.0) Δ ( 0)( 4.0) + (.5)( 4.0) v 6.0 m/ ( )( 3.0 ) v v Δ m v v 6.0 / m 9.0m ( 0) ( 6.0) ( 3.0).0 m/ pplicion When kyiver jump from n irplne he cn rech pee ner 40 km/h uring he freefll porion of he ive. Once he prchue i eploye he prchui pee ecree o 0 km/h. Explin why hen in phyic we conier he ccelerion uring he freefll o be negive n he ccelerion uring he ime he prchue i eploye o be poiive by uing your knowlege of vecor n kinemic. Since he kyiver jump from plne he ccelerion ue o grviy cue he iver pee o incree in he negive irecion. Therefore he iver velociy coninue o become more negive over ime. If he iver i rveling pee of 40km/h, hi/her velociy woul be -40km/h or 40km/h [D]. Once he/he pull eploy he prchue, he pee begin o ecree mening h he velociy i becoming le negive. i.e. chnging from -40km/h o -0km/h. Therefore from vecor perpecive he chnge in velociy i poiive (i.e. Δ v v v ( 0) ( 40) + 30 m/ ) Since he velociy chnge i poiive, Δv herefore he ccelerion mu be poiive ( ) Δ
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