Antenna Arrays. Contents
|
|
- Gabriella Lucas
- 6 years ago
- Views:
Transcription
1 Antenna Arras Antenna arras are forme from an assembl of raiating or receiving elements in a particular electrical an geometrical configuration. The cooperative effect of all elements in the arra permits to obtain raiation characteristics that coul not be achieve with a single element. Contents. Introuction. Two-element arras 3. N-element linear arras 4. Phase arras 5. Planar arras 6. Mutual coupling
2 . Introuction Motivation for the use of antenna arras To enlarge the imension of the antenna 4p for more irective characteristics D = A em l To be able to steer the beam in man ifferent irections (phase arras) To shape the beams for particular applications (beamforming) low-sielobe patterns Aaptive nulling
3 Principle of function Fiels from elements in the arra interfere constructivel for certain irections ( maima) an estructivel for other irections ( nulls) S maimum Parameters that influence the overall pattern of an arra Geometrical arra configuration (linear, circular, rectangular, elliptical, spherical, clinrical, conformal to a nonplanar surface, etc) Relative spacing between elements Amplitue ecitation of elements Phase ecitation of elements Relative pattern of iniviual elements 3
4 . Two-elements arras Let us assume that two horiontal infinitesimal ipoles (length L<<l) are positione along the -ais at a istance from each other. The two ientical ipoles are fe with ientical amplitue I an phase ifference (i <ks-ee>). I I wt / / The raiation pattern in the -plane for a ipole oriente along the -ais is obtaine through a rotation See bottom of p. 8 of Wire Antennas for rigorous treatment. The epenence in 3D is in fact eual to - sin sin f which reuces to cos in the -plane ( f = 9). sin cos 4
5 Assuming no mutual coupling between the two elements, we can write the total fiel as the superposition of the fiels from both ipoles Et = E + E r r - jkr [ + /] -jkr [ - /] ki L e e aj ˆ h ì cos cos 4p r r ü ï = í + ï ý / r ï î ïþ Far-fiel approimations:»» / #: phase + / #: phase - / r» r» r r r» r + cos üï ï ïýï» r - cos ï ïþ for amplitue term for phase term / r r r ki Le 4pr -jkr - jk ( cos + ) / + jk ( cos + ) / Et = aˆ jh cos { e + e } cos[ ( k cos + ) /] / 5
6 E t -jkr ki Le = aj ˆ h cos cos[ ( k cos + ) /] 4pr single element pattern arra factor Total fiel pattern in the -plane Arra factor (far fiel) The arra factor is a function of the geometr of the arra (number of elements, relative istance) an the ecitation phase an amplitue. Simple epressions are obtaine when the elements have ientical amplitues, phases an spacing. The arra factor correspons to the pattern of the arra where the actual raiating elements are replace with isotropic point sources. Pattern multiplication (far fiel) The far-one fiel istribution of an arra of ientical elements is eual to the prouct of the fiel of a single element at the reference point (origin) an the arra factor of that arra E = E arra factor t ( single element at reference point) Note: Mutual coupling (later) is not inclue in pattern multiplication. 6
7 Eample : Fin the element pattern, arra factor an total fiel pattern of a two-element arra of infinitesimal ipoles with uarter-wave inter-element istance ( = l/4) an ientical phase ecitation ( = ). -plane B Single element = Arra factor cos k cos [ ] Total fiel 3D Linear = Single element in 3D: cos sin sin - f 7
8 Eample : Fin the pattern nulls for = l/4 an = -9. Solution: éæ pö ù p l p E µ cos cos kcos k ç - with = = êë è øúû l 4 ép ù E µ cos cos ( cos - ) êë 4 úû Element nulls: = = cos ( cos ) ( cos ) cos n n 9 Arra factor nulls: é p ù ép ù p n - = n - = êë 4 úû êë4 úû p p a) ( cos n - ) =+ n oes not eist 4 p p o b) ( cos n - ) =- n = 8 4 = 8
9 Eample 3: Compare the arra factors for = l/4 an the two phases = ±9. Solution: =-9 =+ 9 AF ép ù µ cos ( cos -) êë4 úû AF ép ù µ cos ( cos + ) êë4 úû constructive interference f+ = estructive interference f+ = 8 =-9 =+ 9 = l /4 f = 9 = l /4 f = 9 estructive interference - f+ =-8 constructive interference - f + = 9
10 3. N-element linear arras We now want to generalie the concepts introuce b etening the linear arra to N ientical elements along. To obtain the arra factor, we consier all elements to be isotropic sources. N 4 3 r N cos r 4 r 3 r r The elements are fe with a current ecitation with ientical amplitue I. Each succeeing element has a progressive phase relative to the preceing one. I I wt 3 Far fiel approimation: The path ifference from two ajacent elements in the far-fiel is given b cos
11 The arra factor can then be written as the superposition of all far fiel contributions N r N AF = + e + e + + e + j( k cos + ) + j ( k cos + ) + j( N - )( k cos + ) 4 3 cos r 4 r 3 r r ( ) (**) phase from path ifference ecitation phase N jn ( ) AF = å e + - Y where Y = k cos + n= * ìï = ï í ïaf e = e + e + e + + e + e ïî jy jy jn ( -) Y jn ( -) Y AF e e e e jy jy jy j3y jn ( -) Y jny ( ) ( ) ( jy ) jny ** - * AF e - = e - jn Y jn ( /) Y -jn ( /) Y e - j[ ( N-/ ) ] Y e -e [( / ) ] sin é j N- Y ( N / ) Yù AF = = e = e ë û jy j( /) Y -j( /) Y e - e -e siné( /) Yù ë û center of arra
12 If we chose the reference point in the phsical center of the arra, the arra factor reuces to æn ö sin ç Y çè AF ø = æ ö sin ç Y çè ø The maimum value of this arra factor is eual to N. Therefore, in orer to have a maimum value eual to one, the arra factor is often given in normalie form AF n = æn ö sin ç çè Y ø N æ ö sin ç Y çè ø with Y= k cos + Normalie arra factor for the uniform linear N- element arra For small values of Y, e.g. near the maimum of the arra factor AF n æn ö sin ç çè Y ø» N Y ( also for l, = )
13 Nulls an maima: Nulls are foun b setting the AF to ero, i.e. AF n = æn ö sin ç çè Y ø N æ ö sin ç Y çè ø ì æn ö sin ç Y = ï çè ø í æ ö sin Y ¹ ï çè ïî ø N Y = n = np Y= k cos + æ ö n = cos - p êp ç N ë çè øúû ì n =,, 3,... ï í ï n ¹ N, N,3 N,... ïî é l n ù - The maimum value of the AF occurs when its enominator becomes ero "" ç æ AF n ö çè ø Y= ( k cos + ) =mp = m Y= k cos + l m = cos é - (- mp) ù êë p úû m =,,,3,... The number of nulls an maima will be a function of the element spacing an the phase ecitation ifference. 3
14 Broasie arra The maimum of raiation is irecte normal to the arra ( = 9 ) N = 5 = l / = Y= ( k cos + ) = = = 9! = Elements have the same phase! En-fire arra The maimum of raiation is irecte along the ais of the arra (either = or = 8 or both) N = = l /4 =+ 8! ìïy = ( k cos + ) = k + = = = í ï ï =-k ïî! ìïy = ( k cos + ) =- k + = = 8 = 8 í ï ï = + k ïî 4
15 Arra factors for broasie arras: epenence on element spacing ( N =, = ) = l /4 = l / = l (3D: linear) 5
16 Arra factors for en-fire arras: N =, = l / 4 =-k (3 representations) =+k (3D: linear) 6
17 Arra factors for en-fire arras: Depenence on element spacing ( N = 6, =-k) = l / = l /4 = l / = 3 l /4 (3D: linear) 7
18 Broasie vs. en-fire arras: N =, = l / 4 = =-k Omniirectional pattern Directional pattern 8
19 Uniform amplitue broasie arra ( = 9 ) Uniform amplitue en-fire arra ( = ) (see p. 3) Nulls Maima æ n lö ìï n =,, 3,... ï ç è N ø ï n ¹ N, N,... ïî - n = cos í - æ lö m = ç m m = è ø cos,,,... n n,, 3,... - æ n lö ìï = = cos ï ç - í è N ø ï n ¹ N, N,... ïî - æ lö m = ç - m m = è ø cos,,,... Half-power points h - æ.39lö p cos ç ç çè pn ø l h - æ.39lö p cos ç - pn çè ø l Minor lobe maima s cos - é (s + ) lù ì s =,,... ê ï í ê ë N ú û ï p / l ïî s - cos é (s + ) lù ì s =,,... - ï í ê ë N ú û ï p / l ïî First null beamwith (FNBW) ép Q n = -cos êë - æ l ö ù ç èn øúû - æ l ö ç è N ø Q n = cos - Half-power beamwith (HPBW) First sielobe BW (FSLBW) ép - æ.39lö ù p Qh - cos ç çè pn êë øúû l ép - æ 3l ö ù p QS - cos ç çè N êë øúû l Eamples follow later. - æ.39lö p Qh cos ç - pn çè ø l - æ 3l ö p QS cos ç - N çè ø l 9
20 4. Phase arras (scanning arras) We have seen that controlling the progressive phase ecitation between the elements permits to change the irection of maimum raiation from normal (broasie) to along the arra ais (en-fire). We will show now that the maimum raiation can be steere electronicall in an irection to form a scanning arra., = =-k =? = 9 = en-fire broasie
21 To steer the main beam in irection of with 8, we nee to ajust the progressive phase ecitation between the elements Y= k cos + = k cos + = =-k cos =! n 5 N = 6 = l / = phase shifters The phase cause b path ifference is compensate b the ecitation phase for
22 Scanning arra eample N =, = l / 4 (3D: linear) = 9 = 6 = =-45 = 3 = =-77.9 =-9
23 Full-fiel simulations E-fiel amplitue in the plane Linear arra of 4 Hertian ipoles along = l/ = 9 = = 6 = -9 = 3 = (3D: linear) 3
24 Hansen-Wooar en-fire Arra To enhance the irectivit of an en-fire uniform arra without estroing an other characteristics, Hansen an Wooar propose that the reuire phase shift between closel space elements of a ver long arra shoul be æ.94ö o =- k ç + N = çè ø æ.94ö =+ k ç + = 8 N çè ø This approimation gives goo results for ver long, finite length iscrete arras with closel space elements. The above conition oes not guarantee that the maimum is along en-fire. An aitional conition efines the reuire element spacing o = l /4 = l / = N - l N 4 l» 4 for N large Uniform Hansen-Wooar arra N = =- ( k +.94/ N ) 4
25 Hansen-Wooar vs orinar en-fire arra N =, = l / 4 Hansen-Wooar en-fire arra: Higher irectivit (b.5 B) Orinar en-fire arra: Lower sielobe level (b 4 B) Hansenwooar 6.7 Orinar en-fire =- =-9 (3D: linear) 5
26 Uniform amplitue Hansen-Wooar en-fire arras towars = Same, towar = 8 Nulls n æ l ö ìï n =,, 3,... ï ç è N ø ï n ¹ N, N,... ïî - = cos + ( - n) í 8-n Maima m æ l ö ìï m =,, 3,... [ m ] ï ç è N ø ï p / l î - = cos + -( + ) í 8-m Half-power points h - æ l ö = ç - è N ø p l cos.398, N large 8-h Minor lobe maima s s,, 3,... - é sl ù ìï = = cos ï - í ê ë N ú û ï p / l ïî 8-s First null beamwith (FNBW) - æ l ö Q n = cos ç - è N ø Same Half-power beamwith (HPBW) - æ l ö ç è N ø p l Q h = cos -.398, N large Same First sielobe BW (FSLBW) - æ l ö ç è N ø p l Q S = cos - Same 6
27 Directivit of N-element linear arras Broasie Arra: U é æn ö ù é æn öù sin k cos sin k cos è ç ø çè ø ésin ù µ n =» N = æ ö N sin kcos k cos êë úû ê çè ø ú ê ë û ë úû ( ) ( AF ) é æn ö ù p sin k cos ç çè U ø = Pra = sin p N 4 ò k cos ê ë úû N - k ésin ù U =- Nk ò êë úû N k D U = U ma ésin ù p» Nk ò = êë úû Nk - p if Nk / large l Use substitution: N = kcos N =- k sin U ma = D U U ma =» Nk p Epressing D as a function of the arra length L = ( N -) p k = l æ Lö D» N = l ç + çè øl 7
28 Similarl: æ Lö Orinar en-fire arra: D» 4N = 4 l ç + çè øl Hansen-Wooar en-fire arra: æ Lö D =.85 4N =.85 4 l ç + çè øl Summar: Approimate irectivit of large closel-space arras Directivit D in terms of N Directivit D in terms of L Broasie arra Orinar en-fire arra N l 4N l æ Lö ç + çè øl æ Lö 4 ç + çè øl Hansen-Wooar en-fire arra æ Lö.85 4N.85 4 l ç + çè øl 8
29 Eample Ten isotropic elements are place along the -ais. Design a Hansen-Wooar en-fire arra with the maimum irecte towars = 8 o. Fin the following values a) esire spacing & progressive phase shift (in egrees) b) location of all the nulls (in egrees) c) first null beamwith ) irectivit Solution: N - l 9 l a) = = =.5 l ; = k + = p.5 + =.757 ra = N 4 4 N - l - ( n) b) Since in this eample = 8, n = 8- cos é + ( - n) ù = 8-cos é + - ù êë N úû êë 4.5 úû = 4.6, = 9.47, = 83.6, 3 = 56.5, = 4 5 c) - é l ù Q n = cos - êë N úû - é ù = cos - = êë 4.5úû Q n / ) D =.85 4N = l = B 9
30 Eample A linear arra is forme of isotropic elements place along the -ais with inter-element istance = l/4. Assuming uniform amplitue istribution, fin the progressive phase (in egrees), half power beamwith (in egrees), first null beamwith (in egrees), relative sie lobe level maimum (in B), an irectivit (in B) for the following arra tpes: a) broasie b) orinar en-fire c) Hansen-Wooar en-fire Solution a) broasie = ép æ.39lö ù - HPBW: Q = cos.4 h - ç pn = ê ë çè øúû ép æ l ö ù - FNBW: Q = cos 47.6 n - ç N = ê ë çè øúû ép æ - 3l ö ù FSLBW: Q = cos s - ç N = ê ë çè øúû é æ ö ù SLL: AF (at first sie lobe)» B Note: log n 3p ç 3 p ê ë çè øúû D = N = B Numerical computation gives B l ( ) -3 B Q h Q s Q n Broasie 3
31 pl p b) Orinar en-fire = k = = = 9 l 4 é æ.39l ö ù - HPBW: Q = cos 69.5 h - ç pn = ê ë çè øúû é - l ù FNBW: Q = cos - = 6.6 n ê N ú ë û é - 3l ù FSLBW: Q = cos - = 3.84 s ê N ú ë û SLL: AF (at first sie lobe)» B n 3p D = 4N = B Numeric ( all B) l En-fire c) Hansen-Wooar æ.94ö æp ö = k + = +.94 =6.7 èç N ø èç ø Hansen-Wooar HPBW: é l ù Q = cos = 38.5 h ê N ú ë û FNBW: cos é l ù Q = - - = n ê N ú ë û FSLBW: cos é l ù Q = - - = 6.6 s ê N ú ë û SLL: AF (at first sie lobe)»-9 B n D =.85 4N = B Numericall ( B) l 3
32 Eample 3 Design a uniform linear scanning arra whose maimum of the arra factor is 3º from the ais of the arra ( = 3º). The esire half-power beamwith is º while the spacing between the elements is l/4. Determine the ecitation of the elements (amplitue an phase), length of the arra L (in wavelengths), number of elements, an irectivit (in B). Solution: Uniform amplitue istribution Progressive phase: pl =- k cos =- cos 3= l 4 From the graph: ( L ) 5 L 49.75l N l Directivit nees to be solve numericall: HPBW: D» B = 3 = N = 3
33 Grating Lobes When the spacing between the elements is large enough to permit in-phase aition of raiate fiels in more than one irection, multiple maima of eual magnitue can be forme. The principal maimum is referre to as the major lobe, the remaining as the grating lobes. To avoi grating lobes in linear broasie arras, choose < l N = = l 6 /4 N = 6 = l / N = 6 = 3 l /4 N = 6 = l N = 6 = 3 l / N = = 6 l Remark: The conition for en fire arra is: < l/ (c.f. p. 7) 33
34 Low sielobes istributions ( non uniform amplitues) The far-fiel pattern is the Fourier transform of the amplitue (aperture) istribution. Therefore, b varing the amplitues of the element ecitations, the shape of the arra factor can be influence. This is commonl use in the esign of low-sielobe istributions. Eample: N = 6 = l / = I n : variable Uniform amplitues Binomial istribution SLL: SieLobe Level SLL: B SLL: - B 34
35 Dolph-Chebshev Talor n = 4 Hamming SLL: esign parameter SLL: esign parameter SLL: fie but low Note: - Traeoff: Sielobe level vs. beamwith - The aperture efficienc of the arra is ecrease b non constant istributions 35
36 Ecitation Pattern snthesis: Variation of the amplitue an phases of the iniviual elements permits to shape the beam of the arra. Eamples: Compute with genetic algorithm ) 6 elements, linear arra 5 bit amplitue taper Amplitue control Element # Normalie far-fiel (B) Angle ( ) ) elements, linear arra with comple taper (amplitue an phase) Mask (specification) Ecitation amplitue Phase an amplitue control Ecitation phase ( ) Element # Normalie far-fiel (B) Angle ( ) 36
37 5. Planar arras Etening the arra in a plane (instea of just along a line) provies aitional variables which can be use to control an shape the pattern of the arra. Basicall, aing a imension to the arra provies control over the secon angular coorinate. The patterns of a planar arra are therefore irectional an can be use to scan the main beam of the antenna towar an point in space. Linear arra (along ) Planar arra (-plane) f 37
38 Arra factor of a planar arra Arra along Consier a linear arra of M elements in the irection M AF = å Ime AF m= = M ( - )( k sin cosf+ ) jm For uniform ecitation, we can write [ M ) Y ] [ ) Y ] sin ( / sin(/ where Y = k sin cos f+ M f Etension to D: The linear arra along is consiere as a single element (with pattern AF ) of a linear arra along Arra along AF N 38
39 Rectangular arra in the -plane N é M jm ( - )( k sincosf+ ) ù jn ( - )( k sinsinf+ ) AF = åi n Ime e êå n= ë ú m= û M jm ( - )( k sincosf+ ) jn ( - )( k sinsinf+ ) = åime åi ne m = n= AF AF N 3 4 f N M The arra factor of the rectangular arra is the prouct of the arra factors of the arras in the - an -irections. Ecitation of element mn: I mn e I I m n j é( m ) ( n ) ù ê ë úû Assume that I = I I mn m n = I = const an normalie: sin é( M / ) Y ù sin é ( N / ) Y ù AF( f, ) n = ë û ë û M sin é( / ) ù N sin é( / ) ù ë Y û ë Y û with ìy = k sin cosf+ ï í ïy = k sin sin f+ ïî 39
40 Eample of a planar arra: Isotropic elements, uniform amplitues plane plane ìï N = 7, N = 4 ï í = = l / ï = = ïî plane plane (3D: B scale) 4
41 Steering planar arras For a rectangular arra, the maima of AF n an AF n are locate at Y = k sin cos f+ = mp m =,, Y = k sin sin f+ = np n =,, The main beam is irecte towars, f when ( m =, n = ) =-k sin cosf =-k sin sin f Grating lobes will occur at ìsin cos f- sin cos f =ml/ ï í ïsin sin f- sin sin f =nl/ ïî irections where all contributions are in phase constructive interference! é - sin sin f nl/ ù f = tan êsin cos f ml/ ú ë û é - sin cos f ml/ ù é sin sin f nl/ - ù = sin = sin ê ë cosf ú û ê ë sin f ú û For a true grating lobe, both euations must be satisfie simultaneousl! 4
42 Grating lobes in rectangular arras: N = N = 5, = = (3D: linear) 4
43 Grating lobes in planar arras = = l /4 N = N = 5, = = = = l / = = 3 l /4 ( plane) = = l = = 3 l / = = l General rule to avoi grating lobes: < l/, < l/ 43
44 Beamwith To fin the beamwith of a scanne planar arra is ver ifficult. Approimate values for large arras with maimum near broasie can be foun using the results of the uniform linear arra Q : HPBW of a broasie linear arra with M elements Q : HPBW of a broasie linear arra with N elements Cross-section Q h Y h Then for a large arra with maimum near broasie, the elevation-plane beamwith (at = ) is f Q = h cos é cosf sin f ù æ ö æ ö + êèç Q ø ç Q ë è ø ú û an in the plane perpenicular to = For a suare arra with M = N an Q =Q =Q Y h = é sin f æ cosf ö ù Q Q = Y =Q : cos, h æ ö + ê ç è Q ø ç Q ë è ø ú û h 44
45 Beam soli angle W A =QhYh W = A Q Q sec é ùé æ ö ù æ ö sin f Q cosf sin f çq cos f + +ç ç èq ø ê çq ëê ûúë è ø ú û Directivit 4 p AF (, f ) AF (, f ) D = p p òò é ùé ù * ë ûë û ma * [ AF ( f, )][ AF ( f, )] sin f For large planar arras with maimum near broasie D p 3, 4» = W / ras W / egrees A A or, more accurate: D = pcos D D 45
46 Eample : Effect of scanning angle on beamwith an irectivit f = = 9 f = 3 = 9 N 5 = = l / = N = f = 6 = 9 f = 9 = 9 (3D: linear) 46
47 Eample : Design a 8 ( in the -irection an 8 in the -irection) element uniform planar arra so that the main maimum is oriente along =, = 9. For a spacing of = = /8 between the elements, fin a) the progressive phase shift between the elements in the an irections b) the irectivit of the arra c) the half-power beamwiths (in two perpenicular planes) of the arra Solution: = = l/8, M =, N = 8, =, f = 9 a) b) c) =- k sin cosf = pl =- k sin sin f =- sin=-.364 ra =-7.8 l 8 D = pcos D D ; ìï D = M = =.5 ï í l 8 ïd = N = 8 =. ïî l 8 D = p cos.5 = B é æ.39l öù - é -æ.39 8öù Q = 9 cos 9 cos - = - = 4.49 pm ç p ê ç è ø ë è øúû êë úû é æ -.39l öù é -æ.39 8öù Q = 9 cos 9 cos - = - = 5.56 pn çè 8p ê èç ø ú ëê øûú ë û (linear) 47
48 53.37 h cos cos cos9 sin 9 sin cos h 4.49 sin sin 9 cos9 cos , 4 3, 4 3, 4 D B / egrees / egrees A h h plane plane 48
49 Eample 3: Low-sielobe istributions N = N = 4, = =, = = l/ Uniform ecitation Hamming winow Linear representation B, Dnamic range: 5 B Polar, B 49
50 Eample 4: Effect of the element patterns Consier a uniform arra of horiontal ipoles oriente in irection: N = N = 5, = =, = = l = Horiontal ipoles (-irection) Arra factor (isotropic elements) Arra pattern 5
51 Arra Factor: Formula versus iniviual elements Eample : Arra with ientical amplitues an progressive phase shift between elements e e o j 3 o j o e -j o 3 e -j Eample : Arra with ifferent amplitues an same phase AF n = æ4 ö sin é o k cos + ù ç çè êë úû ø 4 æ ö o sin ék cos + ù ç êë úû çè ø jk cos AF =+ 3e + e -jk cos -jk - 3e + 5e 3 4 =+ 3e + e jk cos cos jk(.5 )cos jk(.5 )cos - 3e + 5e -jk(.5 )cos -jk(.5 )cos 5
52 Eample 3: Arra elements off the ais jk cos jk cos AF =+ e -e cos cos = a a + a = a a + a a = ( sin sin f+ cos ) ( ) r r r = a -a -a = -a a -a a = (-sin sin f-cos ) ( ) r r r ( sin sin f + cos ) - ( sin sin f + cos ) jk jk AF = e -e 5
53 Three arra eamples. Dual-polarie receiver arra for raio astronom Vivali antenna elements Each element is attache to its own receiver Transitions: Coaial to coplanar to slotline subarra Mutual coupling between elements nees to be consiere!! 53
54 . Conformal arras The arra elements are locate on a curve surface Avantages: Wier angle coverage possible Mounting on high-spee aircrafts Arra pattern: r r n Iˆ n E (, f) n E (, ) I e E (, f) N ˆ jkrn r tot f = å n n n= irection unit vector element position element ecitation (comple) element pattern Conformal arra for LEO platform Mutual coupling nees to be consiere 54
55 3. Steerable arras ESPAR Electronicall Steerable Passive Arra Raiator Quasi maima ever 5 55
56 6. Mutual coupling Mutual coupling between the elements in the arra have been neglecte up to now. Inter-element coupling changes the current in antennas an the input impeance V I I Z L V ì V = Z I + Z I ï í ï V = Z I + Z I ïî ( Z ) V, in = = - = I Z + ZL Z Z ( Z Z ) Eample: Two element parasitic arra ìï -ZV ï í ï í ï V = Z I + Z I Z V î ïi = l ïî ì I = ï = ZI + ZI ï ZZ - Z ï ZZ - Z Z epens on spacing ( /4 results in small Z ) Z epens on length of element l > resonant length => Z has inuctive reactance (reflector) l < resonant length => Z has capacitive reactance (irector) 56
57 Yagi-Ua antenna ì = Z-, -I- + Z-,I + Z-,I +... Z-, NI V = Z, -I- + Z,I + Z,I +... Z, NIN ï í ï = ZN, -I- + ZN,I + ZN,I +... ZN, NIN ïî Since all ajustable parameters are interrelate, esigns are mainl carrie out eperimentall an/or with fiel solvers (tpical : 8- elements, gain 4 B, banwith of a few percent) N i V - main lobe li N Practical eample Directivit Bi Banwith % l i t=. To increase the banwith: lengthen reflector (low freuencies) shorten irectors (high freuencies) however: gain will be reuce b up to 5 B 57
58 Illustration: Yagi-Ua Antenna Vertical ipole + irector + 6 irectors.3l D =.76 B D» 5.4 B D» B 58
59 -D Vivali arra: Influence of mutual coupling Mutual coupling reuces return loss an increases sielobes! 59
Lecture 1b. Differential operators and orthogonal coordinates. Partial derivatives. Divergence and divergence theorem. Gradient. A y. + A y y dy. 1b.
b. Partial erivatives Lecture b Differential operators an orthogonal coorinates Recall from our calculus courses that the erivative of a function can be efine as f ()=lim 0 or using the central ifference
More informationTutorial 1 Differentiation
Tutorial 1 Differentiation What is Calculus? Calculus 微積分 Differential calculus Differentiation 微分 y lim 0 f f The relation of very small changes of ifferent quantities f f y y Integral calculus Integration
More informationx f(x) x f(x) approaching 1 approaching 0.5 approaching 1 approaching 0.
Engineering Mathematics 2 26 February 2014 Limits of functions Consier the function 1 f() = 1. The omain of this function is R + \ {1}. The function is not efine at 1. What happens when is close to 1?
More informationExam 2 Review Solutions
Exam Review Solutions 1. True or False, an explain: (a) There exists a function f with continuous secon partial erivatives such that f x (x, y) = x + y f y = x y False. If the function has continuous secon
More informationUnit #6 - Families of Functions, Taylor Polynomials, l Hopital s Rule
Unit # - Families of Functions, Taylor Polynomials, l Hopital s Rule Some problems an solutions selecte or aapte from Hughes-Hallett Calculus. Critical Points. Consier the function f) = 54 +. b) a) Fin
More informationTrigonometric Functions
72 Chapter 4 Trigonometric Functions 4 Trigonometric Functions To efine the raian measurement system, we consier the unit circle in the y-plane: (cos,) A y (,0) B So far we have use only algebraic functions
More informationTable of Common Derivatives By David Abraham
Prouct an Quotient Rules: Table of Common Derivatives By Davi Abraham [ f ( g( ] = [ f ( ] g( + f ( [ g( ] f ( = g( [ f ( ] g( g( f ( [ g( ] Trigonometric Functions: sin( = cos( cos( = sin( tan( = sec
More informationCalculus 4 Final Exam Review / Winter 2009
Calculus 4 Final Eam Review / Winter 9 (.) Set-up an iterate triple integral for the volume of the soli enclose between the surfaces: 4 an 4. DO NOT EVALUATE THE INTEGRAL! [Hint: The graphs of both surfaces
More information3.7 Implicit Differentiation -- A Brief Introduction -- Student Notes
Fin these erivatives of these functions: y.7 Implicit Differentiation -- A Brief Introuction -- Stuent Notes tan y sin tan = sin y e = e = Write the inverses of these functions: y tan y sin How woul we
More informationLecture 6: Calculus. In Song Kim. September 7, 2011
Lecture 6: Calculus In Song Kim September 7, 20 Introuction to Differential Calculus In our previous lecture we came up with several ways to analyze functions. We saw previously that the slope of a linear
More informationHomework 7 Due 18 November at 6:00 pm
Homework 7 Due 18 November at 6:00 pm 1. Maxwell s Equations Quasi-statics o a An air core, N turn, cylinrical solenoi of length an raius a, carries a current I Io cos t. a. Using Ampere s Law, etermine
More informationIn the usual geometric derivation of Bragg s Law one assumes that crystalline
Diffraction Principles In the usual geometric erivation of ragg s Law one assumes that crystalline arrays of atoms iffract X-rays just as the regularly etche lines of a grating iffract light. While this
More information5.4 Fundamental Theorem of Calculus Calculus. Do you remember the Fundamental Theorem of Algebra? Just thought I'd ask
5.4 FUNDAMENTAL THEOREM OF CALCULUS Do you remember the Funamental Theorem of Algebra? Just thought I' ask The Funamental Theorem of Calculus has two parts. These two parts tie together the concept of
More informationCalculus in the AP Physics C Course The Derivative
Limits an Derivatives Calculus in the AP Physics C Course The Derivative In physics, the ieas of the rate change of a quantity (along with the slope of a tangent line) an the area uner a curve are essential.
More informationAntennas and Propagation Array. Alberto Toccafondi
Antennas an Propagation Array Alberto Toccafoni Two-element array z Ø Array of two ientical horizontal wire antennas positione along the z-axis Ø Consier a reference antenna on the origin of the coorinate
More informationPrep 1. Oregon State University PH 213 Spring Term Suggested finish date: Monday, April 9
Oregon State University PH 213 Spring Term 2018 Prep 1 Suggeste finish ate: Monay, April 9 The formats (type, length, scope) of these Prep problems have been purposely create to closely parallel those
More informationTHE ACCURATE ELEMENT METHOD: A NEW PARADIGM FOR NUMERICAL SOLUTION OF ORDINARY DIFFERENTIAL EQUATIONS
THE PUBISHING HOUSE PROCEEDINGS O THE ROMANIAN ACADEMY, Series A, O THE ROMANIAN ACADEMY Volume, Number /, pp. 6 THE ACCURATE EEMENT METHOD: A NEW PARADIGM OR NUMERICA SOUTION O ORDINARY DIERENTIA EQUATIONS
More informationd dx But have you ever seen a derivation of these results? We ll prove the first result below. cos h 1
Lecture 5 Some ifferentiation rules Trigonometric functions (Relevant section from Stewart, Seventh Eition: Section 3.3) You all know that sin = cos cos = sin. () But have you ever seen a erivation of
More informationCalculus of Variations
Calculus of Variations Lagrangian formalism is the main tool of theoretical classical mechanics. Calculus of Variations is a part of Mathematics which Lagrangian formalism is base on. In this section,
More informationEquations of lines in
Roberto s Notes on Linear Algebra Chapter 6: Lines, planes an other straight objects Section 1 Equations of lines in What ou nee to know alrea: The ot prouct. The corresponence between equations an graphs.
More informationMATH 205 Practice Final Exam Name:
MATH 205 Practice Final Eam Name:. (2 points) Consier the function g() = e. (a) (5 points) Ientify the zeroes, vertical asymptotes, an long-term behavior on both sies of this function. Clearly label which
More informationOptimal Variable-Structure Control Tracking of Spacecraft Maneuvers
Optimal Variable-Structure Control racking of Spacecraft Maneuvers John L. Crassiis 1 Srinivas R. Vaali F. Lanis Markley 3 Introuction In recent years, much effort has been evote to the close-loop esign
More informationShort Intro to Coordinate Transformation
Short Intro to Coorinate Transformation 1 A Vector A vector can basically be seen as an arrow in space pointing in a specific irection with a specific length. The following problem arises: How o we represent
More informationSection 2.1 The Derivative and the Tangent Line Problem
Chapter 2 Differentiation Course Number Section 2.1 The Derivative an the Tangent Line Problem Objective: In this lesson you learne how to fin the erivative of a function using the limit efinition an unerstan
More informationVectors in two dimensions
Vectors in two imensions Until now, we have been working in one imension only The main reason for this is to become familiar with the main physical ieas like Newton s secon law, without the aitional complication
More information1. The electron volt is a measure of (A) charge (B) energy (C) impulse (D) momentum (E) velocity
AP Physics Multiple Choice Practice Electrostatics 1. The electron volt is a measure of (A) charge (B) energy (C) impulse (D) momentum (E) velocity. A soli conucting sphere is given a positive charge Q.
More informationSummary: Differentiation
Techniques of Differentiation. Inverse Trigonometric functions The basic formulas (available in MF5 are: Summary: Differentiation ( sin ( cos The basic formula can be generalize as follows: Note: ( sin
More informationChapter 2 Derivatives
Chapter Derivatives Section. An Intuitive Introuction to Derivatives Consier a function: Slope function: Derivative, f ' For each, the slope of f is the height of f ' Where f has a horizontal tangent line,
More informationx f(x) x f(x) approaching 1 approaching 0.5 approaching 1 approaching 0.
Engineering Mathematics 2 26 February 2014 Limits of functions Consier the function 1 f() = 1. The omain of this function is R + \ {1}. The function is not efine at 1. What happens when is close to 1?
More informationMath 1271 Solutions for Fall 2005 Final Exam
Math 7 Solutions for Fall 5 Final Eam ) Since the equation + y = e y cannot be rearrange algebraically in orer to write y as an eplicit function of, we must instea ifferentiate this relation implicitly
More informationAntiderivatives and Indefinite Integration
60_00.q //0 : PM Page 8 8 CHAPTER Integration Section. EXPLORATION Fining Antierivatives For each erivative, escribe the original function F. a. F b. F c. F. F e. F f. F cos What strateg i ou use to fin
More informationBasic Differentiation Rules and Rates of Change. The Constant Rule
460_00.q //04 4:04 PM Page 07 SECTION. Basic Differentiation Rules an Rates of Change 07 Section. The slope of a horizontal line is 0. Basic Differentiation Rules an Rates of Change Fin the erivative of
More informationm (ft-lb/ft). Using the point-slope
ENGR 1990 Engineering athematics pplications of Derivatives E 560, E 570 Eample #1 Consier a long slener beam of length with a concentrate loa acting at istance a from the left en. Due to this loa, the
More informationMeasuring Inconsistency of Pair-wise Comparison Matrix with Fuzzy Elements
International Journal of Operations Research International Journal of Operations Research Vol., No., 8 (3) Measuring Inconsistency of Pair-wise Comparison Matri with Fuzzy Elements Jaroslav Ramík an Petr
More informationPhysics 2212 GJ Quiz #4 Solutions Fall 2015
Physics 2212 GJ Quiz #4 Solutions Fall 215 I. (17 points) The magnetic fiel at point P ue to a current through the wire is 5. µt into the page. The curve portion of the wire is a semicircle of raius 2.
More informationMath 1272 Solutions for Spring 2005 Final Exam. asked to find the limit of the sequence. This is equivalent to evaluating lim. lim.
Math 7 Solutions for Spring 5 Final Exam ) We are gien an infinite sequence for which the general term is a n 3 + 5n n + n an are 3 + 5n aske to fin the limit of the sequence. This is equialent to ealuating
More informationOpen Access An Exponential Reaching Law Sliding Mode Observer for PMSM in Rotating Frame
Sen Orers for Reprints to reprints@benthamscience.ae The Open Automation an Control Systems Journal, 25, 7, 599-66 599 Open Access An Exponential Reaching Law Sliing Moe Observer for PMSM in Rotating Frame
More informationAnalytic Scaling Formulas for Crossed Laser Acceleration in Vacuum
October 6, 4 ARDB Note Analytic Scaling Formulas for Crosse Laser Acceleration in Vacuum Robert J. Noble Stanfor Linear Accelerator Center, Stanfor University 575 San Hill Roa, Menlo Park, California 945
More informationCS9840 Learning and Computer Vision Prof. Olga Veksler. Lecture 2. Some Concepts from Computer Vision Curse of Dimensionality PCA
CS9840 Learning an Computer Vision Prof. Olga Veksler Lecture Some Concepts from Computer Vision Curse of Dimensionality PCA Some Slies are from Cornelia, Fermüller, Mubarak Shah, Gary Braski, Sebastian
More informationSeparation of Variables
Physics 342 Lecture 1 Separation of Variables Lecture 1 Physics 342 Quantum Mechanics I Monay, January 25th, 2010 There are three basic mathematical tools we nee, an then we can begin working on the physical
More informationSemiclassical analysis of long-wavelength multiphoton processes: The Rydberg atom
PHYSICAL REVIEW A 69, 063409 (2004) Semiclassical analysis of long-wavelength multiphoton processes: The Ryberg atom Luz V. Vela-Arevalo* an Ronal F. Fox Center for Nonlinear Sciences an School of Physics,
More informationProblem Solving 4 Solutions: Magnetic Force, Torque, and Magnetic Moments
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics 8.0 Spring 004 Problem Solving 4 Solutions: Magnetic Force, Torque, an Magnetic Moments OJECTIVES 1. To start with the magnetic force on a moving
More informationRADIATING ELEMENTS MAY BE: DIPOLES, SLOTS, POLYRODS, LOOPS, HORNS, HELIX, SPIRALS, LOG PERIODIC STRUCTURES AND EVEN DISHES Dipoles simple structures,
ANTENNA ARRAYS Array - collection of radiating elements An array may be: 1D (linear), 2D (planar), 3D (frequency selective) structure of radiating elements Purpose More directivity, Steereable beams Radiation
More informationPhysics 2212 K Quiz #2 Solutions Summer 2016
Physics 1 K Quiz # Solutions Summer 016 I. (18 points) A positron has the same mass as an electron, but has opposite charge. Consier a positron an an electron at rest, separate by a istance = 1.0 nm. What
More informationSolution Set #7
05-455-0073 Solution Set #7. Consier monochromatic light of wavelength λ 0 incient on a single slit of with along the -ais an infinite length along y. The light is oserve in the Fraunhofer iffraction region
More informationCalculus I. Lecture Notes for MATH 114. Richard Taylor. Department of Mathematics and Statistics. c R. Taylor 2007
Calculus I Lecture Notes for MATH 4 Richar Talor Department of Mathematics an Statistics c R. Talor 2007 last revision April 5, 2007 MATH 4 Calculus I Page 2 of 26 Contents Preinaries 6 2 Functions 6 2.
More information12.5. Differentiation of vectors. Introduction. Prerequisites. Learning Outcomes
Differentiation of vectors 12.5 Introuction The area known as vector calculus is use to moel mathematically a vast range of engineering phenomena incluing electrostatics, electromagnetic fiels, air flow
More informationLecture XII. where Φ is called the potential function. Let us introduce spherical coordinates defined through the relations
Lecture XII Abstract We introuce the Laplace equation in spherical coorinates an apply the metho of separation of variables to solve it. This will generate three linear orinary secon orer ifferential equations:
More informationx = c of N if the limit of f (x) = L and the right-handed limit lim f ( x)
Limit We say the limit of f () as approaches c equals L an write, lim L. One-Sie Limits (Left an Right-Hane Limits) Suppose a function f is efine near but not necessarily at We say that f has a left-hane
More informationOn colour-blind distinguishing colour pallets in regular graphs
J Comb Optim (2014 28:348 357 DOI 10.1007/s10878-012-9556-x On colour-blin istinguishing colour pallets in regular graphs Jakub Przybyło Publishe online: 25 October 2012 The Author(s 2012. This article
More information6.003 Homework #7 Solutions
6.003 Homework #7 Solutions Problems. Secon-orer systems The impulse response of a secon-orer CT system has the form h(t) = e σt cos(ω t + φ)u(t) where the parameters σ, ω, an φ are relate to the parameters
More informationPHY 114 Summer 2009 Final Exam Solutions
PHY 4 Summer 009 Final Exam Solutions Conceptual Question : A spherical rubber balloon has a charge uniformly istribute over its surface As the balloon is inflate, how oes the electric fiel E vary (a)
More informationMoving Charges And Magnetism
AIND SINGH ACADEMY Moving Charges An Magnetism Solution of NCET Exercise Q -.: A circular coil of wire consisting of turns, each of raius 8. cm carries a current of. A. What is the magnitue of the magnetic
More informationChapter 1 Prerequisites for Calculus
Section. Chapter Prerequisites for Calculus Section. Lines (pp. 9) Quick Review.. ( ) (). ( ). m 5. m ( ) 5 ( ) 5. (a) () 5 Section. Eercises.. (). 8 () 5. 6 5. (a, c) 5 B A 5 6 5 Yes (b) () () 5 5 No
More informationMagnetic field generated by current filaments
Journal of Phsics: Conference Series OPEN ACCESS Magnetic fiel generate b current filaments To cite this article: Y Kimura 2014 J. Phs.: Conf. Ser. 544 012004 View the article online for upates an enhancements.
More informationSYNCHRONOUS SEQUENTIAL CIRCUITS
CHAPTER SYNCHRONOUS SEUENTIAL CIRCUITS Registers an counters, two very common synchronous sequential circuits, are introuce in this chapter. Register is a igital circuit for storing information. Contents
More informationPERMANENT MAGNETS CHAPTER MAGNETIC POLES AND BAR MAGNETS
CHAPTER 6 PERAET AGET 6. AGETIC POLE AD BAR AGET We have seen that a small current-loop carrying a current i, prouces a magnetic fiel B o 4 ji ' at an axial point. Here p ia is the magnetic ipole moment
More informationImplicit Differentiation
Implicit Differentiation Thus far, the functions we have been concerne with have been efine explicitly. A function is efine explicitly if the output is given irectly in terms of the input. For instance,
More informationLagrangian and Hamiltonian Mechanics
Lagrangian an Hamiltonian Mechanics.G. Simpson, Ph.. epartment of Physical Sciences an Engineering Prince George s Community College ecember 5, 007 Introuction In this course we have been stuying classical
More informationDissipative numerical methods for the Hunter-Saxton equation
Dissipative numerical methos for the Hunter-Saton equation Yan Xu an Chi-Wang Shu Abstract In this paper, we present further evelopment of the local iscontinuous Galerkin (LDG) metho esigne in [] an a
More information18 EVEN MORE CALCULUS
8 EVEN MORE CALCULUS Chapter 8 Even More Calculus Objectives After stuing this chapter you shoul be able to ifferentiate an integrate basic trigonometric functions; unerstan how to calculate rates of change;
More informationChapter 6. Electromagnetic Oscillations and Alternating Current
hapter 6 Electromagnetic Oscillations an Alternating urrent hapter 6: Electromagnetic Oscillations an Alternating urrent (hapter 31, 3 in textbook) 6.1. Oscillations 6.. The Electrical Mechanical Analogy
More informationA Sketch of Menshikov s Theorem
A Sketch of Menshikov s Theorem Thomas Bao March 14, 2010 Abstract Let Λ be an infinite, locally finite oriente multi-graph with C Λ finite an strongly connecte, an let p
More informationARCH 614 Note Set 5 S2012abn. Moments & Supports
RCH 614 Note Set 5 S2012abn Moments & Supports Notation: = perpenicular istance to a force from a point = name for force vectors or magnitue of a force, as is P, Q, R x = force component in the x irection
More informationCENTURION UNIVERSITY OF TECHNOLOGY & MANAGEMENT,ODISHA CUEE-2015
CENTURION UNIVERSITY OF TECHNOLOGY & MANAGEMENT,ODISHA CUEE-015 PHYSICS 1. The imensional formula of angular momentum is a) ML T - b) MLT - c) MLT -1 ) ML T -1. If A B = B A, then the angle between A an
More informationforce reduces appropriately to the force exerted by one point charge on another. (20 points)
Phsics III: Theor an Simulation Examination 3 December 4, 29 Answer All Questions Analtical Part: Due 5: p.m., M, 12/7/9 Name SOUTIONS 1. Two line charges A an B of the same length are parallel to each
More informationThe Principle of Least Action
Chapter 7. The Principle of Least Action 7.1 Force Methos vs. Energy Methos We have so far stuie two istinct ways of analyzing physics problems: force methos, basically consisting of the application of
More informationIB Math High Level Year 2 Calc Differentiation Practice IB Practice - Calculus - Differentiation (V2 Legacy)
IB Math High Level Year Calc Differentiation Practice IB Practice - Calculus - Differentiation (V Legac). If =, fin the two values of when = 5. Answer:.. (Total marks). Differentiate = arccos ( ) with
More informationector ition 1. Scalar: physical quantity having only magnitue but no irection is calle a scalar. eg: Time, mass, istance, spee, electric charge, etc.. ector: physical quantity having both magnitue an irection
More informationMath Notes on differentials, the Chain Rule, gradients, directional derivative, and normal vectors
Math 18.02 Notes on ifferentials, the Chain Rule, graients, irectional erivative, an normal vectors Tangent plane an linear approximation We efine the partial erivatives of f( xy, ) as follows: f f( x+
More informationGATE PHYSICS-PH 2019 SECTION : GENERAL APTITUDE
1 GAT PHYSICS-PH 19 SCTION : GNRAL APTITUD 1. The fishermen, the floo victims owe lives, were reware by the government. whom to which to whom that. Until Iran came along, Inia ha never been in kabai. efeate
More informationAssignment 1. g i (x 1,..., x n ) dx i = 0. i=1
Assignment 1 Golstein 1.4 The equations of motion for the rolling isk are special cases of general linear ifferential equations of constraint of the form g i (x 1,..., x n x i = 0. i=1 A constraint conition
More informationChapter Primer on Differentiation
Capter 0.01 Primer on Differentiation After reaing tis capter, you soul be able to: 1. unerstan te basics of ifferentiation,. relate te slopes of te secant line an tangent line to te erivative of a function,.
More informationFree rotation of a rigid body 1 D. E. Soper 2 University of Oregon Physics 611, Theoretical Mechanics 5 November 2012
Free rotation of a rigi boy 1 D. E. Soper 2 University of Oregon Physics 611, Theoretical Mechanics 5 November 2012 1 Introuction In this section, we escribe the motion of a rigi boy that is free to rotate
More informationSpace-time Linear Dispersion Using Coordinate Interleaving
Space-time Linear Dispersion Using Coorinate Interleaving Jinsong Wu an Steven D Blostein Department of Electrical an Computer Engineering Queen s University, Kingston, Ontario, Canaa, K7L3N6 Email: wujs@ieeeorg
More informationb) The array factor of a N-element uniform array can be written
to Eam in Antenna Theo Time: 18 Mach 010, at 8.00 13.00. Location: Polacksbacken, Skivsal You ma bing: Laboato epots, pocket calculato, English ictiona, Råe- Westegen: Beta, Noling-Östeman: Phsics Hanbook,
More informationVortex Shedding on Combined Bodies at Incidence to a Uniform Air Stream T. Yavuz x, Y. E. Akansu xx, M. Sarıo lu xxx, and M.
Vorte Sheing on Combine Boies at Incience to a Uniform Air Stream T. Yavuz, Y. E. Akansu, M. Sarıo lu, an M. Özmert. Ba kent Universit, : Nige Universit,, : Karaeniz Technical Universit,Turke Abstract
More informationPhysics 505 Electricity and Magnetism Fall 2003 Prof. G. Raithel. Problem Set 3. 2 (x x ) 2 + (y y ) 2 + (z + z ) 2
Physics 505 Electricity an Magnetism Fall 003 Prof. G. Raithel Problem Set 3 Problem.7 5 Points a): Green s function: Using cartesian coorinates x = (x, y, z), it is G(x, x ) = 1 (x x ) + (y y ) + (z z
More information6. Friction and viscosity in gasses
IR2 6. Friction an viscosity in gasses 6.1 Introuction Similar to fluis, also for laminar flowing gases Newtons s friction law hols true (see experiment IR1). Using Newton s law the viscosity of air uner
More informationThe Sokhotski-Plemelj Formula
hysics 25 Winter 208 The Sokhotski-lemelj Formula. The Sokhotski-lemelj formula The Sokhotski-lemelj formula is a relation between the following generalize functions (also calle istributions), ±iǫ = iπ(),
More informationPolynomial Inclusion Functions
Polynomial Inclusion Functions E. e Weert, E. van Kampen, Q. P. Chu, an J. A. Muler Delft University of Technology, Faculty of Aerospace Engineering, Control an Simulation Division E.eWeert@TUDelft.nl
More informationinflow outflow Part I. Regular tasks for MAE598/494 Task 1
MAE 494/598, Fall 2016 Project #1 (Regular tasks = 20 points) Har copy of report is ue at the start of class on the ue ate. The rules on collaboration will be release separately. Please always follow the
More informationIn Leibniz notation, we write this rule as follows. DERIVATIVE OF A CONSTANT FUNCTION. For n 4 we find the derivative of f x x 4 as follows: lim
.1 DERIVATIVES OF POLYNOIALS AND EXPONENTIAL FUNCTIONS c =c slope=0 0 FIGURE 1 Te grap of ƒ=c is te line =c, so fª()=0. In tis section we learn ow to ifferentiate constant functions, power functions, polnomials,
More informationPart D. Complex Analysis
Part D. Comple Analsis Chapter 3. Comple Numbers and Functions. Man engineering problems ma be treated and solved b using comple numbers and comple functions. First, comple numbers and the comple plane
More informationPrecedence Effect. Beamforming
Preceence Effect Beaforing Deo of the ranssen effect Deonstrates preceence Introuction to 3D Auio capture Directivity of icrophone. Oni-irectional Avantages are that icrophones capture all soun incluing
More informationSECTION 3.2 THE PRODUCT AND QUOTIENT RULES 1 8 3
SECTION 3.2 THE PRODUCT AND QUOTIENT RULES 8 3 L P f Q L segments L an L 2 to be tangent to the parabola at the transition points P an Q. (See the figure.) To simplify the equations you ecie to place the
More informationLect. 4 Waveguides (1)
Lect. 4 Waveguies (1) - Waveguie: Confines an guies EM waves Metallic, Dielectric, Plasmonic - We are intereste in ielectric waveguie Total internal reflection b refractive inex ifferences n A B C D n
More informationCALCULATION OF 2D-THERMOMAGNETIC CURRENT AND ITS FLUCTUATIONS USING THE METHOD OF EFFECTIVE HAMILTONIAN. R. G. Aghayeva
CALCULATION OF D-THERMOMAGNETIC CURRENT AND ITS FLUCTUATIONS USING THE METHOD OF EFFECTIVE HAMILTONIAN H. M. Abullaev Institute of Phsics, National Acaem of Sciences of Azerbaijan, H. Javi ave. 33, Baku,
More informationOPG S. LIST OF FORMULAE [ For Class XII ] OP GUPTA. Electronics & Communications Engineering. Indira Award Winner
OPG S MAHEMAICS LIS OF FORMULAE [ For Class XII ] Covering all the topics of NCER Mathematics et Book Part I For the session 0-4 By OP GUPA Electronics & Communications Engineering Inira Awar Winner Visit
More informationMATH2231-Differentiation (2)
-Differentiation () The Beginnings of Calculus The prime occasion from which arose my iscovery of the metho of the Characteristic Triangle, an other things of the same sort, happene at a time when I ha
More informationLaplace s Equation in Cylindrical Coordinates and Bessel s Equation (II)
Laplace s Equation in Cylinrical Coorinates an Bessel s Equation (II Qualitative properties of Bessel functions of first an secon kin In the last lecture we foun the expression for the general solution
More informationChapter 24: Magnetic Fields and Forces Solutions
Chapter 24: Magnetic iels an orces Solutions Questions: 4, 13, 16, 18, 31 Exercises & Problems: 3, 6, 7, 15, 21, 23, 31, 47, 60 Q24.4: Green turtles use the earth s magnetic fiel to navigate. They seem
More informationElectric Charge and Electrostatic Force
PHY 049 Lecture Notes Chapter : Page 1 of 8 Electric Charge an Electrostatic Force Contemporary vision: all forces of nature can be viewe as interaction between "charges", specific funamental properties
More informationWith the Chain Rule. y x 2 1. and. with respect to second axle. dy du du dx. Rate of change of first axle. with respect to third axle
0 CHAPTER Differentiation Section The Chain Rule Fin the erivative of a composite function using the Chain Rule Fin the erivative of a function using the General Power Rule Simplif the erivative of a function
More informationensembles When working with density operators, we can use this connection to define a generalized Bloch vector: v x Tr x, v y Tr y
Ph195a lecture notes, 1/3/01 Density operators for spin- 1 ensembles So far in our iscussion of spin- 1 systems, we have restricte our attention to the case of pure states an Hamiltonian evolution. Toay
More informationStatics. There are four fundamental quantities which occur in mechanics:
Statics Mechanics isabranchofphysicsinwhichwestuythestate of rest or motion of boies subject to the action of forces. It can be ivie into two logical parts: statics, where we investigate the equilibrium
More information1 ode.mcd. Find solution to ODE dy/dx=f(x,y). Instructor: Nam Sun Wang
Fin solution to ODE /=f(). Instructor: Nam Sun Wang oe.mc Backgroun. Wen a sstem canges wit time or wit location, a set of ifferential equations tat contains erivative terms "/" escribe suc a namic sstem.
More information. Using a multinomial model gives us the following equation for P d. , with respect to same length term sequences.
S 63 Lecture 8 2/2/26 Lecturer Lillian Lee Scribes Peter Babinski, Davi Lin Basic Language Moeling Approach I. Special ase of LM-base Approach a. Recap of Formulas an Terms b. Fixing θ? c. About that Multinomial
More informationPhysics 41 Chapter 38 HW Serway 9 th Edition
Physics 4 Chapter 38 HW Serway 9 th Eition Questions: 3, 6, 8, Problems:, 4, 0,, 5,,, 9, 30, 34, 37, 40, 4, 50, 56, 57 *Q383 Answer () The power of the light coming through the slit ecreases, as you woul
More informationDusty Plasma Void Dynamics in Unmoving and Moving Flows
7 TH EUROPEAN CONFERENCE FOR AERONAUTICS AND SPACE SCIENCES (EUCASS) Dusty Plasma Voi Dynamics in Unmoving an Moving Flows O.V. Kravchenko*, O.A. Azarova**, an T.A. Lapushkina*** *Scientific an Technological
More information