The Λ(1405) is an anti-kaon nucleon molecule. Jonathan Hall, Waseem Kamleh, Derek Leinweber, Ben Menadue, Ben Owen, Tony Thomas, Ross Young

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1 The Λ(1405) is an anti-kaon nucleon molecule Jonathan Hall, Waseem Kamleh, Derek Leinweber, Ben Menadue, Ben Owen, Tony Thomas, Ross Young

2 The Λ(1405) The Λ(1405) is the lowest-lying odd-parity state of the Λ baryon. Even though it contains a heavy strange quark and has odd parity its mass is lower than any other excited spin-1/2 baryon. It has a mass of MeV. This is lower than the lowest odd-parity nucleon state (N(1535)), even though it has a valence strange quark. 2 of 40

3 The Λ(1405) The Λ(1405) is the lowest-lying odd-parity state of the Λ baryon. Even though it contains a heavy strange quark and has odd parity its mass is lower than any other excited spin-1/2 baryon. It has a mass of MeV. This is lower than the lowest odd-parity nucleon state (N(1535)), even though it has a valence strange quark. Before the existence of quarks was confirmed, Dalitz and co-workers speculated that it might be a molecular state of an anti-kaon bound to a nucleon. 2 of 40

4 The Λ(1405) The Λ(1405) is the lowest-lying odd-parity state of the Λ baryon. Even though it contains a heavy strange quark and has odd parity its mass is lower than any other excited spin-1/2 baryon. It has a mass of MeV. This is lower than the lowest odd-parity nucleon state (N(1535)), even though it has a valence strange quark. Before the existence of quarks was confirmed, Dalitz and co-workers speculated that it might be a molecular state of an anti-kaon bound to a nucleon. For almost 50 years the structure of the Λ(1405) resonance has been a subject of debate. 2 of 40

5 The Λ(1405) Here we ll see how a new lattice QCD simulation showing The Λ(1405) strange magnetic form factor vanishes, together with A Hamiltonian effective field theory analysis of the lattice QCD energy levels, unambiguously establishes that the structure is dominated by a bound anti-kaon nucleon component. 3 of 40

6 Why focus on the strange magnetic form factor? It provides direct insight into the possible dominance of a molecular K N bound state. 4 of 40

7 Why focus on the strange magnetic form factor? It provides direct insight into the possible dominance of a molecular K N bound state. In forming such a molecular state, the Λ(u, d, s) valence quark configuration is complemented by A u, u pair making a K (s, u) - proton (u, u, d) bound state, or A d, d pair making a K 0 (s, d) - neutron (d, d, u) bound state. 4 of 40

8 Why focus on the strange magnetic form factor? It provides direct insight into the possible dominance of a molecular K N bound state. In forming such a molecular state, the Λ(u, d, s) valence quark configuration is complemented by A u, u pair making a K (s, u) - proton (u, u, d) bound state, or A d, d pair making a K 0 (s, d) - neutron (d, d, u) bound state. In both cases the strange quark is confined within a spin-0 kaon and has no preferred spin orientation. 4 of 40

9 Why focus on the strange magnetic form factor? It provides direct insight into the possible dominance of a molecular K N bound state. In forming such a molecular state, the Λ(u, d, s) valence quark configuration is complemented by A u, u pair making a K (s, u) - proton (u, u, d) bound state, or A d, d pair making a K 0 (s, d) - neutron (d, d, u) bound state. In both cases the strange quark is confined within a spin-0 kaon and has no preferred spin orientation. To conserve parity, the kaon has zero orbital angular momentum. 4 of 40

10 Why focus on the strange magnetic form factor? It provides direct insight into the possible dominance of a molecular K N bound state. In forming such a molecular state, the Λ(u, d, s) valence quark configuration is complemented by A u, u pair making a K (s, u) - proton (u, u, d) bound state, or A d, d pair making a K 0 (s, d) - neutron (d, d, u) bound state. In both cases the strange quark is confined within a spin-0 kaon and has no preferred spin orientation. To conserve parity, the kaon has zero orbital angular momentum. Thus, the strange quark does not contribute to the magnetic form factor of the Λ(1405) when it is in a KN molecule. 4 of 40

11 Outline Techniques for exciting the Λ(1405) in Lattice QCD Quark-sector contributions to the electric form factor of the Λ(1405) Quark-sector contributions to the magnetic form factor of the Λ(1405) Hamiltonian effective field theory model: m 0, πσ, KN, KΞ and ηλ. Conclusion 5 of 40

12 The Λ(1405) and Lattice QCD Our recent work has successfully isolated three low-lying odd-parity spin-1/2 states. B. Menadue, W. Kamleh, D. B. Leinweber, M. S. Mahbub, Phys. Rev. Lett. 108, (2012) An extrapolation of the trend of the lowest state reproduces the mass of the Λ(1405). Subsequent studies have confirmed these results. G. P. Engel, C. B. Lang, A. Schäfer, Phys. Rev. D 87, (2013) 6 of 40

13 The Λ(1405) and Lattice QCD 6 of 40

14 Simulation Details We are using the PACS-CS (2 + 1)-flavour ensembles, available through the ILDG. S. Aoki et al (PACS-CS Collaboration), Phys. Rev. D 79, (2009) Lattice size of with β = L 3 fm. 7 of 40

15 Simulation Details We are using the PACS-CS (2 + 1)-flavour ensembles, available through the ILDG. S. Aoki et al (PACS-CS Collaboration), Phys. Rev. D 79, (2009) Lattice size of with β = L 3 fm. 5 pion masses, ranging from 640 MeV down to 156 MeV. 7 of 40

16 Simulation Details We are using the PACS-CS (2 + 1)-flavour ensembles, available through the ILDG. S. Aoki et al (PACS-CS Collaboration), Phys. Rev. D 79, (2009) Lattice size of with β = L 3 fm. 5 pion masses, ranging from 640 MeV down to 156 MeV. Single strange quark mass, with κ s = We use κ s = for the valence strange quarks to reproduce the physical kaon mass. 7 of 40

17 Simulation Details We are using the PACS-CS (2 + 1)-flavour ensembles, available through the ILDG. S. Aoki et al (PACS-CS Collaboration), Phys. Rev. D 79, (2009) Lattice size of with β = L 3 fm. 5 pion masses, ranging from 640 MeV down to 156 MeV. Single strange quark mass, with κ s = We use κ s = for the valence strange quarks to reproduce the physical kaon mass. The strange quark κ s is held fixed as the light quark masses vary. Changes in the strange quark contributions are environmental effects. 7 of 40

18 Simulation Details We are using the PACS-CS (2 + 1)-flavour ensembles, available through the ILDG. S. Aoki et al (PACS-CS Collaboration), Phys. Rev. D 79, (2009) Lattice size of with β = L 3 fm. 5 pion masses, ranging from 640 MeV down to 156 MeV. Single strange quark mass, with κ s = We use κ s = for the valence strange quarks to reproduce the physical kaon mass. The strange quark κ s is held fixed as the light quark masses vary. Changes in the strange quark contributions are environmental effects. We consider both the Sommer and PACS-CS schemes to set the scale. 7 of 40

19 The Λ(1405) and Lattice QCD The variational analysis is necessary to isolate the Λ(1405). 8 of 40

20 Variational Analysis By using multiple operators, we can isolate and analyse individual energy eigenstates: Construct the correlation matrix G ij (p; t) = x e i p x tr ( Γ Ω χ i (x) χ j (0) Ω ), for some set { χ i } operators that couple to the states of interest. 9 of 40

21 Variational Analysis By using multiple operators, we can isolate and analyse individual energy eigenstates: Construct the correlation matrix G ij (p; t) = x e i p x tr ( Γ Ω χ i (x) χ j (0) Ω ), for some set { χ i } operators that couple to the states of interest. We seek the linear combinations of the operators { χ i } that perfectly isolate individual energy eigenstates, α, at momentum p: φ α = v α i (p) χ i, φ α = u α i (p) χ i. 9 of 40

22 Variational Analysis When successful, only state α participates in the correlation function, and one can write recurrence relations G(p; t + δt) u α (p) = e Eα(p) δt G(p; t) u α (p) v αt (p) G(p; t + δt) = e Eα(p) δt v αt (p) G(p; t) 10 of 40

23 Variational Analysis When successful, only state α participates in the correlation function, and one can write recurrence relations G(p; t + δt) u α (p) = e Eα(p) δt G(p; t) u α (p) v αt (p) G(p; t + δt) = e Eα(p) δt v αt (p) G(p; t) Solve for the left, v α (p), and right, u α (p), generalised eigenvectors of G(p; t + δt) and G(p; t): 10 of 40

24 Eigenstate-Projected Correlation Functions Using these optimal operators, eigenstate-projected correlation functions are obtained G α (p; t) = x = x e i p x Ω φ α (x) φ α (0) Ω e i p x Ω v α i (p) χ i (x) χ j (0) u α j (p) Ω = v αt (p) G(p; t) u α (p) 11 of 40

25 The importance of eigenstate isolation (red) ln(g) Euclidean Time 12 of 40

26 Probing with the electromagnetic current ln(g) Euclidean Time 13 of 40

27 Only the projected correlator has acceptable χ 2 /dof ln(g) χ 2 /dof = Euclidean Time 14 of 40

28 Operators Used in Λ(1405) Analysis We consider local three-quark operators with the correct quantum numbers for the Λ channel, including Flavour-octet operators χ 8 1 = 1 6 ε abc ( 2(u a Cγ 5 d b )s c + (u a Cγ 5 s b )d c (d a Cγ 5 s b )u c) χ 8 2 = 1 6 ε abc ( 2(u a Cd b )γ 5 s c + (u a Cs b )γ 5 d c (d a Cs b )γ 5 u c) Flavour-singlet operator χ 1 = 2ε abc ( (u a Cγ 5 d b )s c (u a Cγ 5 s b )d c + (d a Cγ 5 s b )u c) 15 of 40

29 Operators Used in Λ(1405) Analysis We also use gauge-invariant Gaussian smearing to increase our operator basis. These results use 16 and 100 sweeps. Gives a 6 6 matrix. 16 of 40

30 Operators Used in Λ(1405) Analysis We also use gauge-invariant Gaussian smearing to increase our operator basis. These results use 16 and 100 sweeps. Gives a 6 6 matrix. Also considered 35 and 100 sweeps. Results are consistent with larger statistical uncertainties. 16 of 40

31 Flavour structure of the Λ(1405) 1.0 unit eigenvector component sweeps χ 8 1 χ 8 2 χ sweeps χ 8 1 χ 8 2 χ of 40 m π 2 [GeV 2 ]

32 Extracting Form Factors from Lattice QCD To extract the form factors for a state α, we need to calculate the three-point correlation function G µ α(p, p; t 2, t 1 ) = x 1, x 2 e i p x 2 e i(p p) x 1 Ω φ α (x 2 ) j µ (x 1 ) φ α (0) Ω 18 of 40

33 Extracting Form Factors from Lattice QCD To extract the form factors for a state α, we need to calculate the three-point correlation function G µ α(p, p; t 2, t 1 ) = This takes the form e Eα(p )(t 2 t 1 ) e Eα(p)t 1 x 1, x 2 e i p x 2 e i(p p) x 1 Ω φ α (x 2 ) j µ (x 1 ) φ α (0) Ω s, s Ω φ α p, s p, s j µ p, s p, s φ α Ω 18 of 40

34 Extracting Form Factors from Lattice QCD ln(g) χ 2 /dof = Euclidean Time 18 of 40

35 Extracting Form Factors from Lattice QCD To extract the form factors for a state α, we need to calculate the three-point correlation function G µ α(p, p; t 2, t 1 ) = This takes the form e Eα(p )(t 2 t 1 ) e Eα(p)t 1 x 1, x 2 e i p x 2 e i(p p) x 1 Ω φ α (x 2 ) j µ (x 1 ) φ α (0) Ω s, s Ω φ α p, s p, s j µ p, s p, s φ α Ω p, s j µ p, s encodes the form factors of the interaction. 18 of 40

36 Current Matrix Elements for Spin-1/2 Baryons The current matrix element for spin-1/2 baryons has the form p, s j µ p, s = ( mα 2 ) 1/2 E α (p)e α (p ) ) u(p ) (F 1 (q 2 ) γ µ + i F 2 (q 2 µν qν ) σ u(p) 2m α 19 of 40

37 Current Matrix Elements for Spin-1/2 Baryons The current matrix element for spin-1/2 baryons has the form p, s j µ p, s = ( mα 2 ) 1/2 E α (p)e α (p ) ) u(p ) (F 1 (q 2 ) γ µ + i F 2 (q 2 µν qν ) σ u(p) 2m α The Dirac and Pauli form factors are related to the Sachs form factors through G E (q 2 ) = F 1 (q 2 ) G M (q 2 ) = F 1 (q 2 ) + F 2 (q 2 ) q2 (2m α ) 2 F 2(q 2 ) 19 of 40

38 Current Matrix Elements for Spin-1/2 Baryons The light- and strange-quark sector contributions can be isolated. Eg. The strange sector is isolated by setting q u = q d = 0. q s is set to unity such that we report results for single quarks of unit charge. Symmetry in the u-d sector provides G u (Q 2 ) = G d (Q 2 ) G l (Q 2 ) for q u = q d = of 40

39 G E for the Λ(1405) at Q GeV G E light strange m π 2 [GeV 2 /c 4 ] 21 of 40

40 Correcting for Varying Q 2 Since the Q 2 changes with m 2 π, we need to shift to a common Q 2 to make meaningful comparisons: 22 of 40

41 Correcting for Varying Q 2 Since the Q 2 changes with m 2 π, we need to shift to a common Q 2 to make meaningful comparisons: Assume a dipole dependence on Q 2 : G E (Q 2 ) = ( Q2 Λ 2 ) 2 G E (0) 22 of 40

42 Correcting for Varying Q 2 Since the Q 2 changes with m 2 π, we need to shift to a common Q 2 to make meaningful comparisons: Assume a dipole dependence on Q 2 : G E (Q 2 ) = ( Q2 Λ 2 ) 2 G E (0) Solve for Λ using G E (0) = 1 (unit charge quarks) for each m 2 π 22 of 40

43 Correcting for Varying Q 2 Since the Q 2 changes with m 2 π, we need to shift to a common Q 2 to make meaningful comparisons: Assume a dipole dependence on Q 2 : G E (Q 2 ) = ( Q2 Λ 2 ) 2 G E (0) Solve for Λ using G E (0) = 1 (unit charge quarks) for each m 2 π Evaluate G E at a common Q 2 (we select 0.16 GeV 2 ) 22 of 40

44 G E for the Λ(1405) at Q 2 = 0.16 GeV G E original light strange corrected light strange m π 2 [GeV 2 /c 4 ] 23 of 40

45 Structure of the Λ(1405) When compared to the ground state, these results are consistent with the development of a non-trivial KN component at light quark masses. 24 of 40

46 Structure of the Λ(1405) When compared to the ground state, these results are consistent with the development of a non-trivial KN component at light quark masses. Noting that the centre of mass of the K(s, l) N(l, u, d) is nearer the heavier N, The anti light-quark contribution, l, is distributed further out by the K and leaves an enhanced light-quark form factor. 24 of 40

47 Structure of the Λ(1405) G E Λ light Λ(1405) light m π 2 [GeV 2 /c 4 ] 24 of 40

48 Structure of the Λ(1405) When compared to the ground state, these results are consistent with the development of a non-trivial KN component at light quark masses. Noting that the centre of mass of the K(s, l) N(l, u, d) is nearer the heavier N, The anti light-quark contribution, l, is distributed further out by the K and leaves an enhanced light-quark form factor. The strange quark may be distributed further out by the K and thus have a smaller form factor. 24 of 40

49 Structure of the Λ(1405) G E Λ light strange Λ(1405) light strange m π 2 [GeV 2 /c 4 ] 24 of 40

50 G M for the Λ(1405) at Q GeV light sector strange sector 0.8 G N D of 40 m p 2 D

51 Λ(1405) magnetic form factor observations SU(3)-flavour symmetry is manifest for m l m s. All three quark flavours play a similar role. G l M Gu M Gd M Gs M for the heaviest three masses. 26 of 40

52 Λ(1405) magnetic form factor observations 1.0 light sector strange sector 0.8 G N D of 40 m p 2 D

53 Λ(1405) magnetic form factor observations The internal structure of the Λ(1405) reorganises at the lightest quark mass. The strange quark contribution to the magnetic form factor of the Λ(1405) drops by an order of magnitude and approaches zero. 26 of 40

54 Λ(1405) magnetic form factor observations 1.0 light sector strange sector 0.8 G N D of 40 m p 2 D

55 Correlation function ratio providing G s M(Q 2 ) m p = GeVêc 2 m p = GeVêc N D G M s of time

56 Λ(1405) magnetic form factor observations As the simulation parameters describing the strange quark are held fixed, this is a remarkable environmental effect of unprecedented strength. We observe an important rearrangement of the quark structure within the Λ(1405) consistent with the dominance of a molecular KN bound state. 26 of 40

57 Hamiltonian Effective Field Theory Model In a finite periodic volume, momentum is quantised to n (2π/L). 27 of 40

58 Hamiltonian Effective Field Theory Model In a finite periodic volume, momentum is quantised to n (2π/L). Working on a cubic volume of extent L on each side, it is convenient to define the momentum magnitudes k n = nx 2 + ny 2 + nz 2 2π L, with n i = 0, 1, 2,... and integer n = n 2 x + n 2 y + n 2 z. 27 of 40

59 Hamiltonian Effective Field Theory Model In a finite periodic volume, momentum is quantised to n (2π/L). Working on a cubic volume of extent L on each side, it is convenient to define the momentum magnitudes k n = nx 2 + ny 2 + nz 2 2π L, with n i = 0, 1, 2,... and integer n = n 2 x + n 2 y + n 2 z. The non-interacting Hamiltonian H 0 has diagonal entries corresponding to the relativistic non-interacting meson-baryon energies available on the finite periodic volume at total three-momentum zero. 27 of 40

60 Hamiltonian Effective Field Theory Model In a finite periodic volume, momentum is quantised to n (2π/L). Working on a cubic volume of extent L on each side, it is convenient to define the momentum magnitudes k n = nx 2 + ny 2 + nz 2 2π L, with n i = 0, 1, 2,... and integer n = n 2 x + n 2 y + n 2 z. The non-interacting Hamiltonian H 0 has diagonal entries corresponding to the relativistic non-interacting meson-baryon energies available on the finite periodic volume at total three-momentum zero. The four octet meson-baryon interaction channels of the Λ(1405) are included: πσ, KN, KΞ and ηλ. 27 of 40

61 Hamiltonian Effective Field Theory Model In a finite periodic volume, momentum is quantised to n (2π/L). Working on a cubic volume of extent L on each side, it is convenient to define the momentum magnitudes k n = nx 2 + ny 2 + nz 2 2π L, with n i = 0, 1, 2,... and integer n = n 2 x + n 2 y + n 2 z. The non-interacting Hamiltonian H 0 has diagonal entries corresponding to the relativistic non-interacting meson-baryon energies available on the finite periodic volume at total three-momentum zero. The four octet meson-baryon interaction channels of the Λ(1405) are included: πσ, KN, KΞ and ηλ. It also includes a single-particle state with bare mass, m 0 + α 0 m 2 π. 27 of 40

62 Hamiltonian model, H 0 Denoting each meson-baryon energy by ω MB (k n ) = ω M (k n ) + ω B (k n ), with ω A (k n ) kn 2 + ma 2, the non-interacting Hamiltonian takes the form m 0 + α 0 mπ ω πσ (k 0 ) ω ηλ (k 0 ) H 0 = ω πσ (k 1 ) ω ηλ (k 1 ) of 40

63 Hamiltonian model, H I Interaction entries describe the coupling of the single-particle state to the two-particle meson-baryon states. 29 of 40

64 Hamiltonian model, H I Interaction entries describe the coupling of the single-particle state to the two-particle meson-baryon states. Each entry represents the S-wave interaction energy of the Λ(1405) with one of the four channels at a certain value for k n. 0 g πσ (k 0 ) g ηλ (k 0 ) g πσ (k 1 ) g ηλ (k 1 ) g πσ (k 0 ) H I = g ηλ (k 0 ).. g πσ (k 1 ).. g ηλ (k 1 ). 29 of 40

65 Eigenvalue Equation Form The eigenvalue equation corresponding to our Hamiltonian model is λ = m 0 + α 0 m 2 π M,B n=0 with λ denoting the energy eigenvalue. g 2 MB (k n) ω MB (k n ) λ. 30 of 40

66 Eigenvalue Equation Form The eigenvalue equation corresponding to our Hamiltonian model is λ = m 0 + α 0 m 2 π M,B n=0 with λ denoting the energy eigenvalue. g 2 MB (k n) ω MB (k n ) λ. As λ is finite, the pole in the denominator of the right-hand side is never accessed. The bare mass m 0 + α 0 m 2 π encounters self-energy corrections that lead to avoided level-crossings in the finite-volume energy eigenstates. 30 of 40

67 Eigenvalue Equation Form The eigenvalue equation corresponding to our Hamiltonian model is λ = m 0 + α 0 m 2 π M,B n=0 with λ denoting the energy eigenvalue. g 2 MB (k n) ω MB (k n ) λ. As λ is finite, the pole in the denominator of the right-hand side is never accessed. The bare mass m 0 + α 0 m 2 π encounters self-energy corrections that lead to avoided level-crossings in the finite-volume energy eigenstates. Reference to chiral effective field theory provides the form of g MB (k n ). 30 of 40

68 Hamiltonian model, H I The form of the interaction is derived from chiral effective field theory. g MB (k n ) = ( κmb 16π 2 f 2 π C 3 (n) 4π ( 2π L ) ) 3 1/2 ω M (k n ) u 2 (k n ). κ MB denotes the SU(3)-flavour singlet couplings κ πσ = 3ξ 0, κ KN = 2ξ 0, κ KΞ = 2ξ 0, κ ηλ = ξ 0, with ξ 0 = 0.75 reproducing the physical Λ(1405) πσ width. 31 of 40

69 Hamiltonian model, H I The form of the interaction is derived from chiral effective field theory. g MB (k n ) = ( κmb 16π 2 f 2 π C 3 (n) 4π ( 2π L ) ) 3 1/2 ω M (k n ) u 2 (k n ). κ MB denotes the SU(3)-flavour singlet couplings κ πσ = 3ξ 0, κ KN = 2ξ 0, κ KΞ = 2ξ 0, κ ηλ = ξ 0, with ξ 0 = 0.75 reproducing the physical Λ(1405) πσ width. C 3 (n) is a combinatorial factor equal to the number of unique permutations of the momenta indices ±n x, ±n y and ±n z. 31 of 40

70 Hamiltonian model, H I The form of the interaction is derived from chiral effective field theory. g MB (k n ) = ( κmb 16π 2 f 2 π C 3 (n) 4π ( 2π L ) ) 3 1/2 ω M (k n ) u 2 (k n ). κ MB denotes the SU(3)-flavour singlet couplings κ πσ = 3ξ 0, κ KN = 2ξ 0, κ KΞ = 2ξ 0, κ ηλ = ξ 0, with ξ 0 = 0.75 reproducing the physical Λ(1405) πσ width. C 3 (n) is a combinatorial factor equal to the number of unique permutations of the momenta indices ±n x, ±n y and ±n z. u(k n ) is a dipole regulator, with regularization scale Λ = 0.8 GeV. 31 of 40

71 Hamiltonian model solution and fit The LAPACK software library routine dgeev is used to obtain the eigenvalues and eigenvectors of H. 32 of 40

72 Hamiltonian model solution and fit The LAPACK software library routine dgeev is used to obtain the eigenvalues and eigenvectors of H. The bare mass parameters m 0 and α 0 are determined by a fit to the lattice QCD results. 32 of 40

73 Hamiltonian model fit 33 of 40

74 Avoided Level Crossing 34 of 40

75 Energy eigenstate, E, basis state composition 35 of 40

76 Infinite-volume reconstruction of the Λ(1405) energy 36 of 40

77 Bootstrap uncertainty at the physical pion mass Bootstraps are calculated by altering the value of each lattice data point by a Gaussian-distributed random number, weighted by the uncertainty. 37 of 40

78 Λ(1405) mass distribution at the physical pion mass 38 of 40

79 Infinite-volume reconstruction of the Λ(1405) energy 39 of 40

80 Conclusions The Λ(1405) has been identified on the lattice through a study of its quark mass dependence and its relation to avoided level crossings in effective field theory. 40 of 40

81 Conclusions The Λ(1405) has been identified on the lattice through a study of its quark mass dependence and its relation to avoided level crossings in effective field theory. The structure of the Λ(1405) is dominated by a molecular bound state of an anti-kaon and a nucleon. 40 of 40

82 Conclusions The Λ(1405) has been identified on the lattice through a study of its quark mass dependence and its relation to avoided level crossings in effective field theory. The structure of the Λ(1405) is dominated by a molecular bound state of an anti-kaon and a nucleon. This structure is signified by: The vanishing of the strange quark contribution to the magnetic moment of the Λ(1405), and 40 of 40

83 Conclusions The Λ(1405) has been identified on the lattice through a study of its quark mass dependence and its relation to avoided level crossings in effective field theory. The structure of the Λ(1405) is dominated by a molecular bound state of an anti-kaon and a nucleon. This structure is signified by: The vanishing of the strange quark contribution to the magnetic moment of the Λ(1405), and The dominance of the K N component found in the finite-volume effective field theory Hamiltonian treatment. 40 of 40

84 Conclusions The presence of a nontrivial single-particle three-quark component explains why the state is readily accessible in lattice correlation matrix analyses constructed with three-quark operators. 40 of 40

85 Conclusions The presence of a nontrivial single-particle three-quark component explains why the state is readily accessible in lattice correlation matrix analyses constructed with three-quark operators. In the infinite-volume limit, the Hamiltonian model describes a quark mass dependence that is consistent with Nature. 40 of 40

86 Conclusions The presence of a nontrivial single-particle three-quark component explains why the state is readily accessible in lattice correlation matrix analyses constructed with three-quark operators. In the infinite-volume limit, the Hamiltonian model describes a quark mass dependence that is consistent with Nature. The result ends 50 years of speculation on the structure of the Λ(1405) resonance. 40 of 40

87 Conclusions The presence of a nontrivial single-particle three-quark component explains why the state is readily accessible in lattice correlation matrix analyses constructed with three-quark operators. In the infinite-volume limit, the Hamiltonian model describes a quark mass dependence that is consistent with Nature. The result ends 50 years of speculation on the structure of the Λ(1405) resonance. The structure of the Λ(1405) is dominated by a molecular bound state of an anti-kaon and a nucleon. 40 of 40