MECHANIC MECHANIC VIRTUAL WORK MATHEMATICS B.SC BY: KALEEM ARIF. International Islamic University ISLAMABAD

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1 MECHANIC MECHANIC VIRTUAL WORK MATHEMATICS B.SC BY: KALEEM ARIF International Islamic University ISLAMABAD

2 V i r t u a l W o r k P a g e 1 MECHANIC (B.SC MATHEMATICS) "VIRTUAL WORK" ٹ : اسchapter constraint تاور Thrust ت رے وركڈنا Particle ا ز دہ اور Rigid ڈى negative اور Thrust Positive If a particle is moving down on an inclined plane, then constraint on its motion is its contact with plane. Any displacement along the plane is consistent with the constraint. If the force does no virtual work then the constraint is called workless. For Single Particle: A particle subjected to workless constraint is in equilibrium iff zero virtual work done by the applied force in any arbitrary infinitesimal displacement consistent with the constraint. Proof: Let the total force acting on the particle be F, As the particle is in equilibrium so F = 0. Let Fa and Fc be the applied and constraint forces acting on the particle then, a F +Fc =0. Let r be any arbitrary infinitesimal displacement consistent with the constraint then Fa Fc. r 0. As constraint are workless so Fa. r Fc. r 0 as constraint are workless, then Fc. r 0 then Fa. r 0. For set of particle: A set of particles subjected to a workless constraint, is in equilibrium iff zero virtual work is done by applied force in any arbitrary infinitesimal displacement consistent with the constraints. Proof: Let m1, m, m3... m n be the particles. Let total force acting on m i be the Fia & F ic. As the particle are in equilibrium so Fia + Fic 0, i= 1,, 3... Let ri be any arbitrary infinitesimal displacement of m i, then total work done by all forces n n n acting on the particles is Fia Fic. ri =0. Then Fia. ri Fic. ri 0 As constraint i1 i1 i1 n forces are workless, since r 0 so Fia. ri 0. i1 For rigid Body: A set of rigid body subjected to a workless constraint is in equilibrium iff zero virtual work is done by applied forces and applied torque in any arbitrary infinitesimal displacement consistent with the constraint. IIUI By Kaleem Arif 1

3 V i r t u a l W o r k P a g e Proof: As any system of forces acting on rigid body can be reduced to a single force and single couple. Let "R" be the single force and "G" be the moment of single couple. As body is in equilibrium so R= 0, and G=0 further Ra Rc 0 and Ga Gc 0 where Ra and R c are the total applied and constraint forces. Similarly Ga and G c be the total applied torques and torque of constraints. Let r & be any arbitrary infinitesimal linear and angular displacement consistent with the constraints. Ra Rc. r 0 And Ga Gc. 0 Example#01: A Particle of mass 0lb is suspended by a force of magnitude x lbs, which make an angle of 30 with the inclined plane of inclination 60. Find "x" and also the reaction of the plane on the particle? Let r be the infinitesimal displacement along the plane. As the system is in equilibrium., we have xcos r Sin r x 0 x 0 lbs Again consider s be the displacement along line perpendicular to the plane. As system is in equilibrium so by applying the p.v.w we have, R 0Cos 60 xsin 30 Where x = 0 lbs So, R = 0 lb IIUI By Kaleem Arif

4 V i r t u a l W o r k P a g e 3 Example #0: A light thin rod, 1 ft long, can turn in a vertical plane about one of its points which is attached to a pivot. If weights of 3 lbs and 4 lbs are suspended from its ends, it rests in a horizontal position. Find the position of the pivot and its reaction on the rod. Let "x" be the distance of pivot from end A. Let " " be infinitesimal angular displacement of the rod. As the rod is in equilibrium. So by applying p.v.w, We have 3x 41 x 0 6 3x 48 4x 0, x 6 ft 7 Let " r " be the infinitesimal displacement along the direction of reaction. As system is in equilibrium so by applying p.v.w, R. r 3 r 4 r 0, R=7 lbs Example #03: Four equal uniform rods are smoothly jointed to form a rhombus ABCD, which is placed in a vertical plane with AC vertical and A resting on a horizontal plane. The rhombus is kept in shape, with the measure of angle BAC equal to, by a light string joining B and D. Find the tension in the string. Four equal uniform rods each of length l and weight w are freely jointed to form rhombus with A fixed in horizontal. Angle BAC =. Shape of rhombus is kept joining B and D by a string. Height of C.G of rod AB and AD = ( ) Height of C.G of rod BC and CD = ( ) Length of String BD = ( ) Applying principle of Virtual Work, IIUI By Kaleem Arif 3

5 V i r t u a l W o r k P a g e 4 3 ( ) ( ) ( ) = 0 ( ) 3 ( ) ( ) = 0 = ( ) Example# 04: A heavy elastic string whose natural length is, is placed round a smooth cone whose axis is vertical and whose semi-vertical angle has measure. If W be the weight and l the modulus of string, prove that it will be in equilibrium when in the form of a circle of radius (1 + ( ))? l A heavy elastic string of natural length is placed on a smooth cone, whose axis is vertical and semi-vertical angle is. And l is the modulus of string. Let "x" be the radius of string when placed on the cone then = l( ) Applying principle of virtual work ( )= 0, l = 0 Or, = + ( )= l l ( ) = (1 + ) l IIUI By Kaleem Arif 4

6 V i r t u a l W o r k P a g e 5 Example# 05: Six equal rods AB, BC, CD, DE, EF and FA are each of weight W and are freely jointed at their extremities so as to form a hexagon. The rod AB is fixed in a horizontal position and the middle points of AB and DE are jointed by a string. Prove that its tension is 3W? Six equal uniform rods of length l and weights W are freely jointed to Depth of C.G of AF and BC = ( ) Depth of C.G of CD and EF = ( ) Depth of C.G of DE = ( ) Length of string = ( ) form a hexagonal. Rod AB is fixed in horizontal position. Mid points of AB and DE are joined by a string. 3 ( ) + ( ) + ( ( ) ( ) = 0 3 ( ) + ( ) + ( ) ( ) = 0 6 = h = Example# 06: A weightless tripod, consisting of three legs of equal length l, smoothly jointed at the vertex, stands on a smooth horizontal plane. A weight W hangs from the apex. The tripod is prevented from collapsing by three inextensible strings, each of length l/, joining the mid-points of legs. Show that tension in each string is IIUI By Kaleem Arif 5

7 V i r t u a l W o r k P a g e 6 Three equal uniform rods of length l are freely jointed to form a tripod which is placed on smooth plane. Mid points of rods are jointed by three inextensible strings each of length l/. A weight W hangs from the apex. Height of pt of application of W = ( ) Height of the rod DG = ( ), Height of rod DH = ( ) = ( ) Height of rod DE = h = = ( ), 3 ( ) 3 ( ) = 0 ( ) 3 3 ( ) = = tan ( ) As length of string is = = ( ) h =, tan = So, = = IIUI By Kaleem Arif 6

8 V i r t u a l W o r k P a g e 7 Exercise # 6 Question # 01: A uniform ladder rests with its upper end against a smooth vertical wall and its foot on rough horizontal ground. Show that the force of friction at the ground is ( ), where W is weight of the ladder and is its inclination with the vertical. A uniform rod of length "l" and weight "W" rests with end A on a rough horizontal ground and end B on a smooth vertical wall. Inclination of the ladder with the vertical is, ( ) + ( ( ) ) = 0 = ( ) Question# 0 : Four equal heavy uniform rods are freely jointed to form a rhombus ABCD which is freely suspended from A, and kept in shape of a square by an inextensible string connecting A and C. Show that tension in the string is W, where W is the weight of one rod. Four equal uniform rods each of length "l" and weight "W" are freely jointed to form a rhombus which is suspended at A. Shape is kept by joining A and C by an inextensible string AC, Depth of C.G of rods AB and AD = ( ) 3 Depth of C.G of rods BC and CD = lcos Length of String = lcos IIUI By Kaleem Arif 7

9 V i r t u a l W o r k P a g e 8 l 3 w Cos w lcos T lcos 0 l 3 w Sin w lsin T lsin 0 T W Question# 03: Six equal uniform rods AB, BC, CD, DE, EF, FA, each of weight "W" are freely jointed to form a regular hexagon. The rod AB is fixed in a horizontal position, and the shape of the hexagon is maintained by a light rod joining C and F. Show that the thrust in the rod is 3W. Six equal uniform rods each of length "l" and weight "W" are freely jointed to form a regular hexagon, with rod AB fixed in horizontal position. C and F are joined by a light rod to maintain the shape. l Height of C.G of the rod's BC and AF = Sin 3l Height of C.G of the rod's CD and EF = Sin Height of C.G of the rod's DE = lsin, Length of rod CF = l lcos IIUI By Kaleem Arif 8

10 V i r t u a l W o r k P a g e 9 l 3 w Sin w lsin w lsin T l lcos 0 l 3 w Cos w lcos wlcos T lsin 0 1 T 3w 3w 3 Question# 04: A hexagon ABCDEF, consisting of six equal heavy rods, of weight w, freely jointed together, hangs in a vertical plane with AB horizontal, and the frame is kept in the form of a regular hexagon by a light rod connecting the mid-points of CD and EF. Show that the thrust in the light rod is 3w? l Depth of C.G of rod's BC and AF = Sin 3 Depth of C.G of rod's CD and EF = lsin Depth of C.G of rod's DE = lsin, length of rod GH = l lcos l 3 w Sin w lsin w lsin T l lcos 0 l 3 w Cos w Cos wlcos T lsin 0 1 T 6w 3w 3 IIUI By Kaleem Arif 9

11 V i r t u a l W o r k P a g e 10 Question# 05: Three equal rods, each of weight "w" are freely jointed together at one extremity of each to form a tripod, and rest with their other extremities on a smooth horizontal plane, each rod inclined at an angle of measure to the vertical, equilibrium being maintained by three equal light strings each joining two of these tan extremities. Prove that the tension in each string is w 3 Three equal uniform rods each of length "l" and weight "W" are freely jointed at one end to form a tripod. The other extremities are placed on a horizontal plane. Angle of each rod with the vertical is. Extremities are joined by three equal length strings. l Height of C.G of rods OA, OB, OC = Cos From figure it is clear, that CG lsin, CH CG Cos30 3 lsin Length of each strings = CH 3lSin 3 l w Cos 3 T 3 lsin 0 w T tan 3 IIUI By Kaleem Arif 10

12 V i r t u a l W o r k P a g e 11 Question# 06: Six equal uniform rods freely joined at their extremities form a tetrahedron. If this tetrahedron is placed with one face on a smooth horizontal table, w prove that the thrust along a horizontal rod is, where w is the weight of a rod. 6 Six equal uniform rods each of length "l" and weight "w" are freely joined to form a tetrahedron which is placed with one face on a smooth horizontal table. Let be the angle with vertical of each rod. l Height of C.G of rods AD, AB and AC = Cos From figure DG lsin, DH DGCos30 3 lsin Length of each horizontal rod is = DH 3lSin 3 l w Cos 3 T 3 lsin 0 3 l w Sin 3 T 3 lcos 0 w T tan 3 As length of rod = l = 3lSin w 1 w So, T 3 6 IIUI By Kaleem Arif 11

13 V i r t u a l W o r k P a g e 1 Question# 07 Four equal uniform rods, each of weight w, are connected at one end of each by means of a smooth joint, and the other ends rest on a smooth table and are connected by equal strings. A weight W is suspended from the joint. Show that the tension in each W w a string is? 4 4l a Four equal uniform rods OA, OB, OC, and OD each of length "l" and weight "W" are freely jointed at O. The other extremities are placed on a smooth table. Shape is kept by joining each of the extremities by four equal length string (each of length a). A weight W hangs at O. Let be the angle of each rod with the vertical. l Height of C.G of OA, OB, OC, and OD = Cos Height of C.G of weight W = lcos From figure, BG lsin, and BH BGCos45 1 lsin Length of each string is given by = BH lsin 4 l w Cos W lcos 4 T lsin 0 w W Sin T = w W 4 Cos 4 tan IIUI By Kaleem Arif 1

14 V i r t u a l W o r k P a g e 13 a As length of string = a = lsin, therefore tan l a aw W a aw W By putting this value in T, get T 4 l a 4 4l a Question# 08: Four uniform rods are freely jointed at their extremities and form a parallelogram ABCD, which is suspended from the joint A, and is kept in shape by an inextensible string AC. Prove that the tension of the string is equal to half the whole weight. Four uniform rods are freely jointed to form a parallelogram which is suspended at A. Shape is kept joining A and C by a string let l and w be the length and weight respectively of rod AD and BC. Let 1 1 l and w be the length and weight of rod AB and CD. Let 1 be the angle of rod AD and BC with the vertical and be the angle of rods AB and CD with the vertical. l1 Depth of C.G of rod AD = Cos 1 l Depth o f C.G of rod AB = Cos l1 Depth of C.G of rod BC = l Cos Cos1 l Depth of C.G of rod CD = l Cos Cos 1 1 Length of string = l1cos1 lcos IIUI By Kaleem Arif 13

15 V i r t u a l W o r k P a g e 14 l1 l l1 l w 1 Cos 1 w Cos w 1 lcos Cos 1 w lcos 1 1 Cos T lcos 1 1 lcos 0 w w T 1 l Sin w w T 1 l Sin 0 1 T w 1 w, which is half of whole weight. Question# 09: A string, of length a, form the shorter diagonal of a rhombus formed by four uniform rods, each of length b and weight W, which are hinged together. If one of the rod be supported in a W b a horizontal position, Prove that tension in the string is b 4b a Four equal uniform rods of length "b" and weight "w" are freely jointed to form a rhombus which is suspended with rod AB fixed in horizontal position. A string of length "a " for shorter diagonal of rhombus. b Depth of C.G of rod AD and BC = Sin Depth of C.G of rod CD = bsin, Depth of C.G of rod AE= bsin Depth of C.G of rod AE = bsin IIUI By Kaleem Arif 14

16 V i r t u a l W o r k P a g e 15 b w Sin w bsin T bsin 0 b 1 w Cos wbcos T bcos 0 wcos T Cos AS length of string =a = bsin and Sin a b wb a Therefore, T 4 4b a Question# 10: A uniform rod of length a rest in equilibrium against a smooth vertical wall and upon a smooth peg at a distance b from the wall. Show that in the position of equilibrium, the beam is inclined to b the wall at an angle Sin a? A uniform rod of length "a" rest in equilibrium with one end on a smooth vertical wall and supported at "p" by a peg at a distance "b" from the wall. Let be the angle of rod with the wall. IIUI By Kaleem Arif 15

17 V i r t u a l W o r k P a g e 16 b From the figure it is clear that Sin, and AP bcsc AP PG AG AP a bco sec Height of the rod above peg = PGCos acos bcot w acos bcot 0, and wasin bcsc b Sin a Question# 11: Two equal particles are connected by two given weightless strings, which are placed like a necklace on a smooth cone whose axis is vertical and whose vertex is uppermost. Show that the tension of each string is W Cot, where W is weight of each particle and the measure of vertical angle of cone. Two equal particles each of weight "w" are connected by two strings which are placed on a smooth vertical cone of semi-vertical angle" " like a necklace. Let "x" be the radius of circle formed by the plane of string in equilibrium position and "y" be the depth of plane from vertex O'. x From figures y tan x ytan IIUI By Kaleem Arif 16

18 V i r t u a l W o r k P a g e 17 The total weight of both the particles is "w". Let "T" be the tension in the string. Consider the virtual displacement such that x changes to x x. w y T x 0 w y T x 0 As given that x y tan, therefore وات ١ دو ں ف y x w T 0 w T tan So T= w Cot y Question# 1: A reg ula r octahe dro n fo rmed o f twelve equal ro ds, each o f weig ht w, f reely jointe d tog ether is suspend ed from o ne co rner. Sho w t hat the thrus t in ea ch ho riz onta l ro d is 3 w? Twelve equal uniform rods each of length "" and weight "w" are freely jointed to form a octahedron which is suspended at O. Let "" be the angle of each rod with vertical. Depth of C.G of rod OA, OB, OC, and OD = Cos 3 Depth of C.G of rods O'A, O'B, O'C, and O'D = Cos IIUI By kaleem Arif 17

19 V i r t u a l W o r k P a g e 18 Depth of C.G of rods AB, BC, CD, DA = Cos and from fig, Sin DG Sin, DH DGCos 45,then CD= Sin 3 4w Cos 4w Cos 4w Cos 4T Sin 0 3 1wSin 4 TCos, Finally T= w Question# 13: A rhombus ABCD of smoothly jointed rods, rests on a smooth table with the rod BC fixed in position. The middle points of AD, DC are connected by a string which is kept taut by a couple G applied to the rod AB. Prove that the tension of string is G 1 Cos ABC AB A rhombus ABCD is placed on a smooth horizontal table. Rod BC is fixed in position. Middle points of AD and CD are joined by string. A couple G is applied on the rod AB to keep the string tight. Then from figure, EG Sin, And length of string is EG Sin IIUI By kaleem Arif 18

20 V i r t u a l W o r k P a g e 19 G T Sin 0 G T Cos 1 0 G T Cos G T 1 ABCos ABC IIUI By kaleem Arif 19

STATICALLY INDETERMINATE STRUCTURES

STATICALLY INDETERMINATE STRUCTURES INTRODUCTION Generally the trusses are supported on (i) a hinged support and (ii) a roller support. The reaction components of a hinged support are two (in horizontal