CAREER POINT. MOCK TEST PAPER for AIPMT. Physics, Chemistry & Biology Solutions ANSWER KEY PHYSICS

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1 CEE PONT MOCK TEST PPE fo PMT Physics, Chemisty & iology Solutions NSWE KEY PHYSCS Ques ns Ques ns CHEMSTY Ques ns Ques ns OLOGY Ques ns Ques ns Ques ns. 3 3 Ques ns Ques ns PHYSCS.[3] F 5 t t s t mpulse Fdt 3.[3] Let m be the mass of the disc. Then tanslational kinetic enegy of the disc is : K T mv CP Towe, P, oad No., Kota (aj.), Ph: () When it ascends on a smooth tack its otational kinetic enegy will emain same while tanslational kinetic enegy will go on deceasing. t highest point. KT mgh

2 o.[] P o h mv mgh v g ().8 m Enegy dm gh time dt kw m l 5.[] (i) W ΔU g mgl 7.[] Fom consevation of linea momentum 8 v v ms s kinetic enegy mv v 7.[3] m m 3m nitial momentum mv final momentum 3mV mv 3mV V v/3 8.[] y cm 9.[3] my my m m m 3m (5) y m 3m y 5 cm M 5 V 3.[3] U.[3] Y GMm ; K F/ Δx L V L L F GMm ; E F Y Δx L L 5.[3] θ ms ΔT Δ θ P Δt (P) () 5. 5 Cal.[] φ γp ; θ P 7.[] 8.[] C V min 3 n n n n C p nc p dt Q n(pλ) n3(t T) Q 3nT 9.[] T sec T π g 5 π 8 sec g TT (8)() t T T 8 8 t 3 GMm.[] k ω.[] Fom figue V/ Numbe of oscillation of shote pendulum t n 3 T π π.[] K λ π λ cm ns. λ/ cm Vω V net (fo lowest point) v ω v v and cceleation v O v (Since linea speed is constant) Hence (D).[] v Δt T.. v μ L v.[] y theoy. Δt 3.[] W q (V V ). 8 8 m/s. sec. CP Towe, P, oad No., Kota (aj.), Ph:

3 q E.d 3a λ q πε a λq πε.d ln 3.[] (n μf) 5 μc n 5 5.[] Ω, Ω 3.[] The coect answe is b. counteclockwise cuent will be induced in the wie as the font edge entes the coil. This can be deduced by applying the ight Hand ule to the fee chages in the length of wie as they tavel tough the magnetic field, o by using Faaday's Law to examine the inceasing magnetic flux though the aea of the loop as it entes the magnetic field. This cuent-caying wie, exposed to the extenal magnetic field, expeiences a magnetic foce F in a diection opposite v, again detemined using the ight Hand ule and it is this magnetic foce that causes the glide to slow down. FL V max V V max V 3.[3] V V [consideing that bulb will not fuse] V V 8 V V V V 7 V f 7 volt is applied ulb will fuse. Hence coect answe is 8 volt.[] 3 y symmety. 7.[] 3 l l 3 3l l l 75 cm 8.[3] Thee will be no foce on the loop due to hoizontal cuent caying wies because foces acting on these wies will be equal and opposite. Futhe, F D > F C. F D is diected towads left hand side and F C towads ight hand side (accoding ight hand ule). Theefoe, the net foce acting on the loop will be towads wie. 9.[] ε Vl.5 3 V O v O 5 5 î ĵ v 5 5 î ĵ v / O î ; v / O 5 m/s 3.[] Path diffeence at s is is λ. Theefoe, fo minimum intensity at P, let x be the minimum distance fom s then, CP Towe, P, oad No., Kota (aj.), Ph: s p s λ 3λ λ sp sp 3λ o λ x x 7λ Solving Eq. (), we get x Note that if we substitute s P s P λ/ in Eq. (), we get 5λ 7λ x which is geate than. 3.[] M.P. m m e 3 m m 8 x

4 35.[] min (a a) min (a a) Clealy, the intensity of minima inceases. gain max (a a) max (a a) Clealy, the intensity of maxima inceases 3.[3] p'.5 p & λ p h λ' λ λ' λ λ 37.[3] use, λ 38.[] F hp p p'.5 % h mqv du 39.[] F mω d mω mv lso, v ω mv.[3] nh πmω t T / / T /.[] α.9 ΔC.9 Δ E.[3] 3.[] Vitual, nveted nh π d.[] g d g g g 5.[] M ML CHEMSTY.[3] atom of X 3 3 Mole atom of X.5 8 tomic wt. of X.5 7.[3] Numbe of electons [] T.5 3 n sec. Z 3 T () () 3 3 T () (3) 7 CP Towe, P, oad No., Kota (aj.), Ph: Mx M X M3x3 9.[] M av. x x x3 ccoding to option () M (M ) (M ) (M.5) then L.H.S..H.S 5.[] ΔE n n 5.[] oiling moles the bond stianed 5.[] w.33 nt log 53.[] V V N (g) O (g) NO (g)... () NO (g) N O (g)... () N (g) O (g) N O(g)... (3) i.e. (3) () () K 3 K K ' K 3 K 3 5.[] K sp S S Ksp S 55.[] fte mixing [g ] 5 5 M [Cl ] 5 5 M K ip [g ] [Cl ] (5 5 ).5 9 Since ionic poduct is geate than Ksp hence pecipitation will take place.

5 57.[3] FCC lattice have six face and each face is shaed by one othe unit cell. 58.[] (π No. of paticel) 59.[] y P X y P X y. (3)(3).[] Fact λ M NaNO 3 λ M KNO 3 λ M KCl S cm mol.[] E cell Eº Cell.[] 3.[3] K.59 (. (.7)) V C [] 7.[3] β-keto acid. C 3 ( ) log 3 D (Fe log sec 8.[] nclude steeo isomes. 9.[] t has localised l.p. 7.[] ntamolecula Cannizzao. 7.[] Nucleophilicity K b. ).59 log (.) (.) 3 9.[] NCET-X, page No [] NCET-X, page No [] NCET-X, page No. 59.[] No. of bp length of DN (Å) 3.Å.[] ase atio is constant fo a species. 3.[3] Cat Felidae Dog Canidae 33.[] ll wee included in Plantae. [NCET, Class X, Page no.] 3.[] Floidean stach is banched cabohydate simila to amylopectin and glycogen. 35.[] Oange ot is caused by ltenaia. 39.[] Selaginella, Equisetum, C Fen, D Salvinia.[] Lignified cell wall is not pesent in meistematic tissue..[] Heat wood 3.[] Still oot.[] NCET X page no. 9 8.[] NCET-X, Page No. 3, [] Mitosis can not occu without DN eplication. 5.[3] Meiosis always occus in diploid cell. 5.[] Cell wall consists of lignin, hemicellulose, pectin and cellulose. 5.[] NCET-X, Page No.,.. 55.[] NCET-X, Page No. 33, [] oth show satuation effect. 58.[3] Nucleolus disappea, astal ay fomation, 7.[] Ph NO Ph NH Ph N C Ph NH CH 3 79.[] ntamolecula E.S.. OLOGY 9.[3] NCET-X, page No. 7 9.[] NCET-X, page No [3] NCET-X, page No. 5 9.[] NCET-X, page No [] NCET-X, page No. 5 CP Towe, P, oad No., Kota (aj.), Ph:

Calculate the electric potential at B d2=4 m Calculate the electric potential at A d1=3 m 3 m 3 m

Calculate the electric potential at B d2=4 m Calculate the electric potential at A d1=3 m 3 m 3 m MTE : Ch 13 5:3-7pm on Oct 31 ltenate Exams: Wed Ch 13 6:3pm-8:pm (people attending the altenate exam will not be allowed to go out of the oom while othes fom pevious exam ae still aound) Thu @ 9:-1:3