Chap. 3 The Second Law. Spontaneous change
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1 Chap. 3 The Second Law Spontaneous change
2 Some things happen naturally; some things don t. the spontaneous direction of change, the direction of change that does not require work to be done to bring it about. The recognition of spontaneous and non-spontaneous is summarized by the Second Law of thermodynamics. No process is possible in which the sole result is the absorption of heat from a reservoir and its complete conversion into work.
3 The direction of spontaneous change What determines the direction of spontaneous change? The First Law of thermodynamics states that energy is conserved in any process. When a change occurs, the total energy of an isolated system remains constant but it is parcelled out in different ways. Can it be, therefore, that the direction of change is related to the distribution of energy? Dispersal of energy
4 3.1 The dispersal of energy highly improbable that energy will become localized, leading to uniform motion of the ball s atoms. We look for the direction of change that leads to dispersal of the total energy of the isolated system.
5 3.2 Entropy First Law of thermodynamics: internal energy, U. - state function - whether a change is permissible (the internal energy of an isolated system remains constant). Second Law of thermodynamics: entropy, S - signpost of spontaneous change The First Law uses the internal energy to identify permissible changes; the Second Law uses the entropy to identify the spontaneous changes among those permissible changes. The entropy of an isolated system increases in the course of a spontaneous change: S tot > 0
6 (a) The thermodynamic definition of entropy motivated by the idea that a change in the extent to which energy is dispersed depends on how much energy is transferred as heat. Heat stimulates random motion in the surroundings. On the other hand, work stimulates uniform motion of atoms in the surroundings and so does not change their entropy.
7 Molecular Interpretation 2.1 Heat Work
8
9 Surrounding is constant volume or constant temperature reservoir
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11 Self Test 3.2 Calculate the entropy change in the surroundings when 1.00 mol N2O4(g) is formed from 2.00 mol NO2(g) under standard conditions at 298 K.
12 (b) The entropy as a state function 1. Carnot cycle in PG 2. True whatever working substance 3. True for any cycle
13 1. Reversible isothermal expansion from A to B at T h 2. Reversible adiabatic expansion from B to C. 3. Reversible isothermal compression from C to D at T c. 4. Reversible adiabatic compression from D to A. = 0 Justification 3.1 (PG)
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15 eqn 3.7 applies to any material, not just a perfect gas efficiency, ε (epsilon), The Second Law of thermodynamics implies that all reversible engines have the same efficiency regardless of their construction.
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17
18 (c) The thermodynamic temperature Engine that is working reversibly between a hot source at a temperature T h and a cold sink at a temperature T Thermodynamic temperature scale ε = 1 T=0 Triple point of water : K If T h is , and measure ε, T of cold sink can be founded. This expression enabled Kelvin to define the thermodynamic temperature scale in terms of the efficiency of a heat engine. The zero of the scale occurs for a Carnot efficiency of 1.
19 The thermodynamics of refrigeration Coefficient of performance The rate of heat leak : A(T h T c )
20 (d) The Clausius inequality dw rev dw, or dw dw rev 0 In an isolated system, the entropy cannot decrease when a spontaneous change occurs.
21
22 3.3 Entropy changes accompanying specific processes (a) Expansion (isothermal) S of the system * Reversible process S tot = 0 = - S * Irreversible process: isothermal expansion q = 0 S sur = 0 >0
23 (b) Phase transition transition to be accompanied by a change in entropy. Consider a system and its surroundings at the normal transition temperature, T trs, the temperature at which two phases are in equilibrium at 1 atm.
24 Trouton s rule : approximately the same standard entropy of vaporization (about 85 J K 1 mol 1 ).
25
26 (c) Heating
27 Example 3.2 Calculating the entropy change Calculate the entropy change when argon at 25 C and 1.00 bar in a container of volume 0.500dm 3 is allowed to expand to dm 3 and is simultaneously heated to 100 C. rev. isothermal exp. rev. const V. v
28 (d) The measurement of entropy C p = at 3
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30 Cp = at3
31 3.4 The Third Law of thermodynamics (a) The Nernst heat theorem The entropy change accompanying any physical or chemical transformation approaches zero as the temperature approaches zero: S 0 as T 0 provided all the substances involved are perfectly crystalline. Third Law of thermodynamics: The entropy of all perfect crystalline substances is zero at T = 0.
32
33 (b) Third-Law entropies standard (Third-Law) entropy standard reaction entropy
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