1 Adda247 No. 1 APP for Banking & SSC Preparation Website: bankersadda.com sscadda.com store.adda247.com

Size: px

Start display at page:

Download "1 Adda247 No. 1 APP for Banking & SSC Preparation Website: bankersadda.com sscadda.com store.adda247.com"

Ashley Freeman
5 years ago
Views:

1 1 Adda247 No. 1 APP for Banking & SSC Preparation

2 S1. Ans.(d) Sol. Let cost price of article A be Rs. 10x cost price of article B = 10x 80 = Rs. 8x And, Selling price of article A = 10x 140 = Rs. 14x And selling price of article B = 8x 120 = Rs. 9.6 x 14x 9.6x = x = 528 x = Rs.120 Hence, cost price of article B = 8x = Rs. 960 S2. Ans.(e) Sol. Area of circle = πr² πr² = 144π r = 12cm Let side of a square be a cm. a² + a² = (12)² 2a² = 144 a² = 72 a = 6 2 cm required perimeter = 4a = 24 2 cm Solutions S. Ans.(d) Sol. Let rate of interest offered by scheme A be R% p.a. Amount invested by Ayush at C.I = 5000 R = (R ) Rs Equivalent rate of interest of 10% C.I. for two years = ( R+5000) 21 = R = 1218 R = 8% S4. Ans.(d) Sol. Required ratio = ( ) 108 = = 10 : 9 = 21% S5. Ans.(e) Sol. Domestic crockery items sold in 2015 and imported crockery items sold in 2016 together = = 16 Imported crockery items sold in 2014 and domestic crockery items sold in 2017 together = = 168 Required difference = = 2 2 Adda247 No. 1 APP for Banking & SSC Preparation

S6. Ans.(a) Sol. Domestic crockery items sold in 201 = 12 88 = 150 Imported crockery items sold in 201 = 150 4 5 = 120 Now, required % = 120 80 = 150% S7. Ans.(d) Sol.

3 S6. Ans.(a) Sol. Domestic crockery items sold in 201 = = 150 Imported crockery items sold in 201 = = 120 Now, required % = = 150% S7. Ans.(d) Sol. Domestic crockery items sold in 2016 & 2017 together = = 204 Imported crockery items sold in 2016 & 2018 together = = Now, required % = = % = 27.5% 160 S8. Ans.(b) Sol. Average of imported crockery items sold in 2017 & 2018 = Average of domestic crockery items sold in 2015, 2017 & 2018 = Required difference = = 12 S9. Ans.(a) Sol. Imported crockery items sold in 2019 = 96 4 = 128 Domestic crockery items sold in 2019 = = ( ) required ratio = = 276 = 2 : 17 ( ) 204 S10. Ans.(c) Sol. Wrong number = = = = = = = 0240 there should be 12 in place of 18. S11. Ans.(d) Sol. Wrong number = (7)³ = = (6)³ = = (5)³ = = (4)³ = = ()³ = = (2)³ = = 704 there should be 1144 in place of = = 104 Adda247 No. 1 APP for Banking & SSC Preparation

4 S12. Ans.(a) Sol. Wrong number = (19)² = = (17)² = = (1)² = = (11)² = = (7)² = = (5)² = = 10 there should be 88 in place of 840. S1. Ans.(d) Sol. Wrong number = = = = = = 9 there should be 114 in place of 110. S14. Ans.(a) Sol. Wrong numbers = = = = = = = 1296 there should be 1600 in place of S15. Ans.(d) Sol. Number of bottles filled by machine B in 1 hour = = 00 Hence, numbers of bottles filled by machine B in 8 hours = 00 8 = 2400 S16. Ans.(b) Sol. Number of divisible of 5 in first natural numbers = = 20 Number of divisible of 7 in first natural numbers = = 14 Since, 5 and 70 both numbers are divisible by 5 & 7. total number of possible outcomes = = 2 Required probability = 2 = Adda247 No. 1 APP for Banking & SSC Preparation 7 5

S17. Ans.(c) Sol. Let number of teachers & students in I.T. branch be x & 19x respectively. 19x x = 256 x = 16 number of teachers in I.T. branch = x = 48 Let numbers of teacher and students in Chemical branch be y & 1y respectively.

5 S17. Ans.(c) Sol. Let number of teachers & students in I.T. branch be x & 19x respectively. 19x x = 256 x = 16 number of teachers in I.T. branch = x = 48 Let numbers of teacher and students in Chemical branch be y & 1y respectively. 1y y = 168 y = 14 Hence, number of teachers in Chemical branch = y = 14 Required difference = = 4 S18. Ans.(e) Sol. Let number of students & teachers in Computer Science branch be 12x & x respectively. 12x x = 275 x = 25 number of students in Computer Science branch = 12x = 00 Now, let number of students & teachers in mechanical branch be 21y & 2y respectively. 21y 2y = 228 y = 12 Hence, number of students in Mechanical branch = 21y = 252 required % = 252 = 84% 00 S19. Ans.(b) Sol. Let number of students & teachers in Civil branch be 1x and 4x respectively. 1x 4x = 126 x = 14 Hence, number of students in Civil branch = 1x = 182 Number of teachers in Civil branch = 4x = 56 Now, Number of girls in Civil branch = = 78 Required % = = % = % S20. Ans.(c) Sol. Let number of students & teachers in Computer Science branch be 12x & x respectively. 12x x = 275 x = 25 Hence, number of students in Computer Science branch = 12x = 00 Number of boys in Computer Science branch = = 175 Number of girls in Computer Science branch = = 125 Now, 5 Adda247 No. 1 APP for Banking & SSC Preparation

6 Let number of students & teachers in Electrical branch be 15y & 2y respectively. 15y 2y = 24 y = 18 Hence, number of students in Electrical branch = 15y = 270 Number of boys in Electrical branch = = 162 And number of girls in Electrical branch = = 108 Required difference = ( ) ( ) = 7 2 = 104 S21. Ans.(a) Sol. Let number of students & teachers in I.T. branch be 19x & x respectively. 19x x = 256 x = 16 Hence, number of students in I.T. branch = 19x = 04 and number of teachers in I.T. branch = x = 48 Let number of students & teaches in Electrical branch be 15y & 2y respectively. 15y 2y = 24 y = 18 Hence, number of students in Electrical branch = 15y = 270 And number of teachers in Electrical branch = 2y = 6 Now, Required ratio = = 41 : = S22. Ans.(d) Sol. Let number of students and teachers in Chemical branch be 1x & x respectively. 1x x = 168 x = 14 And number of teachers in Chemical branch = x = 14 Let number of students and teachers in mechanical branch be 21y & 2y respectively 21y 2y = y = 228 y = 12 Require percentage = = % 6 Adda247 No. 1 APP for Banking & SSC Preparation

7 S2. Ans.(c) Sol. Final quantity of mixture left after replacing x lit. of water = total quantity of mixture (1 quantity of mixture replaced total quantity of mixture ATQ 44.8 = 70 (1 x 70 )2 ) no.of time process performed 16 = (1 x )2 x = 14, 126 lit. As x cannot be greater than 70 lit x =14 lit. 14 liters of mixture can be taken out as capacity of vessel is only 70 liters. S24. Ans.(e) Sol. Total number of students who got passed in 2018 = = 1104 Total number of boys who got passed in 2018 = = ( ) Required % = = = 265 = 88 1 % S25. Ans.(b) Sol. CSA of hemispherical bowl = 2πr² 2πr² = 69 r² = r² = r = 10.5 cm Now, Height of conical tent = = 15 cm Radius of conical tent = 10.5 cm Required volume = = cm³ S26. Ans.(d) Sol. 24? 625 = =? ? =? = Adda247 No. 1 APP for Banking & SSC Preparation

8 S27. Ans.(a) Sol. 660 (? ) 2 = (65)² (? ) 2 = (? ) 2 = ? = 9? = S28. Ans.(c) Sol =? =? + 792? = 6000 S29. Ans.(b) Sol.? = ? = 126 S0. Ans.(a) Sol ? = (26 5) ? = ? 5 5 = ? = 0 5 4? = 1250 Solution (1-5) Total number of students studying in Science of College P = 1800 total number of students studying in Management of College P = 1800 = Let number of students studying in Law and Arts of College P be x and y respectively. As, y = x And x = 120 y y = 1750 and x = 2 Number of students studying in Commerce of College P = = 0 7 Total students in college P = ( ) = 9140 Let total number of students studying in Commerce of College Q be 8x total number of students studying in Management of College Q be 9x ATQ Given, 9x 8x = 200 x = Adda247 No. 1 APP for Banking & SSC Preparation

Total number of students studying in Commerce of College Q = 1600 Total number of students studying in Management of College Q = 1800 Total number of students in College Q = 9140 2480 =6660 so, total

9 Total number of students studying in Commerce of College Q = 1600 Total number of students studying in Management of College Q = 1800 Total number of students in College Q = =6660 so, total number of students studying in Medical of College Q= = 666 Total students studying in science & law in college Q = 6660 ( ) = 144 total number of students studying in Science of College Q = = total number of students studying in Law of College Q = ( ) = 784 S1. Ans (c) Sol. Required ratio = = Courses P Q Commerce Management Arts Medical Science Law Total S2. Ans (e) Sol. Required percentage = (0+1600)+( ) ( )+(2+784) = % 67 S. Ans (a) Sol. Number of girls in Science of College Q = 40 Number of girls in Management of College Q = 40 Let number of girls studying Law in College Q be x x = 458 x = 40 boys studying in Law of College Q = = = = 720 S4. Ans (b) Sol. Required ratio = = S5. Ans (a) Sol. Required percentage = ( ) ( ) ( ) = 640 = 21 1 % Adda247 No. 1 APP for Banking & SSC Preparation

1 Adda247 No. 1 APP for Banking & SSC Preparation Website: bankersadda.com sscadda.com store.adda247.com

1 Adda247 No. 1 APP for Banking & SSC Preparation S46. Ans.(d) Sol. Let width of the path = x cm So, length of the park will be = (x + 4) cm So, 4 3 (Area of path) = Area of the park Solutions => 4 [x(x