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1 1 Adda247 No. 1 APP for Banking & SSC Preparation

2 S46. Ans.(d) Sol. Let width of the path = x cm So, length of the park will be = (x + 4) cm So, 4 3 (Area of path) = Area of the park Solutions => 4 [x(x + 4) (x 4)(x + 4 4)] = x(x + 4) 3 From this equation we can find out the value of x and hence all value can be find out. S47. Ans.(d) Sol. Let C invested for t days A B C : : xt And, = xt Here, x will depend on t and value of t can be maximum 8 month and minimum 1 months On putting t = 8 X = 1800 Putting t = 6 x = 2400 on putting t = 4 x = 3600 on putting t = 2 x = 7200 S48. Ans. (e) Sol. Let x men do the work in (a 6) days And y women do the work in a days So, x(a 6) = y(a) From (i) Let x= 5p And y = 6p 5p(a 6) = 6p(a) 5a 30 = 6a a = -30 not possible From (ii), 10p(a 6) = 3p(a) 10a 60 = 3a 7a = 60 a = 60 it is possible 7 2 Adda247 No. 1 APP for Banking & SSC Preparation

3 From (iii) 8p (a 6) = 5p(a) 8a 48 = 5a 3a = 48 a = 16 possible From (iv) 10p (a 6) = 7p (a) 10a 60 = 7a a = 20 possible So, (ii), (iii) and (iv) are possible S49. Ans.(d) Sol. Let total population of village A in 2000, 2008 and 2012 be 200x, 300x and 400x respectively So, x + 300x + 400x = x = x = 9 Required population = = 1800 S50. Ans.(d) Sol. Let population of village C in 2000, 2008 and 2012 be (x + 2n), (x + n) and x respectively So, (x + n) = (x) 5x + 5n = 7x 2x = 5n n = 2 5 x Required percentage = x+2n x x+2n = x 9 5 x = % S51. Ans.(a) Sol. Sum of literate from B in 2000 and 2008 = 1530 Sum of literate from B in 2008 and 2012 = 2010 And sum of liteate from B in all years = 2490 So, literate in 2008 = ( ) 2490 = 1050 Let population of B in 2008 be x So, 40% of x = 1050 x = Adda247 No. 1 APP for Banking & SSC Preparation

4 S52. Ans.(e) Sol. From (i) & (ii), Let, HCF be x then LCM is 44x 44x + x = 540 x = = 12 From (iii), A + B = 10K Let, A = 12a & B = 12b Then A + B = 12 (a + b), where a & b are coprime. Also, a b = 44 Possible values of a and b are (4, 11) or (1, 44) Sum of A + B = 12 (4 + 11) = 180 Or A + B = 12 (1 + 44) = 540 So, questioned can t be answered even after including all the statements. S53. Ans.(d) Sol. Let A litres is removed and B litre of water is added to the mixture Initially, Ratio of milk and water is 5 : 1. ATQ, A = 40 A 6 + B = 2A + 3B Among the options only A, B and D satisfy this eqn. S54. Ans.(b) Sol. Let number of red, green and blue ball be x, y and z respectively ATQ, x y = y z y = x+z 2 And z or 2y = x + z z x+y+z > 0.2 > 1 3y 5 5z > 3y If y = 5, then z > 3 If y = 10, then z > 6, but this isn t possible Hence, Red Green Blue , 5, 5 isn t possible as number of balls is different Hence, from given options only (b), (d) and (e) can be the answers. So, option, Only (b), (d) and (e) is our correct answer. 4 Adda247 No. 1 APP for Banking & SSC Preparation

5 S55. Ans.(c) Sol. Let CP = & MP = 160 From A If profit = 60% Hence no discount is possible here so, it is not satisfy equation From B When profit is 20% then discount will be 40 = 25% When it doubles i.e. discount = 50% Then, SP = = 80 So, it gave loss of 20% not possible From C When profit = 48% Then discount = 12 = 7.5% 160 When it doubles = 15% Then SP = = 124 So, profit is 24% So, option C is possible From D When profit = 36% Discount = 24 = 15% 160 When discount gets doubled = 30% SP = = 112 So profit is 12%, hence possible From E When profit = 44% = 10% When discount = 20% SP = = 128 Profit is 28% So, it is possible Then C, D and E values are possible S56. Ans.(d) Sol. Let first and fifth numbers be 2x and 2a respectively. Then, third number (A) = 2x+2a = x + a 2 Second number = 2x = x 2 2x x x+a 62 2a ATQ, 2x + x + x + a = 127 4x + a = Adda247 No. 1 APP for Banking & SSC Preparation

6 From option (a) x + a = 64 3x = 63 x = 21 Average of five numbers = (64 21) = 55 5 According to this, option (d) 64, 55 is our correct answer. S57. Ans.(b) Sol. Let income of D and E is x and y respectively. We have to find the value of x y. From (I) 0.72x 0.5y = 3200 From (II) 0.4x 0.4y = 8000 x y = = Hence, only (II) is sufficient to answer the question. S58. Ans.(e) Sol. Let Rs C s income is Rs x Atq, 0.44x+0.52x 2 = x = = 40, A s income = ,000 = 48,000 A s expense in the month of November = 60 S59. Ans.(d) Sol. Let, income of B is Rs x From (I) 0.6x 0.4x = x = = 80, = Rs Amount invested by B is PPF = 80, = Rs 12,000 From (II) 0.6x 0.4x = x = = 80, Amount invested by B in PPF = ,000 = Rs Hence, Either statement (I) or statement (II) by itself is sufficient to answer the question. 6 Adda247 No. 1 APP for Banking & SSC Preparation

7 Solution (60-62): Village No. of wind Maximum units No. of Wind mills operative mills produced houses Week1 Week 2 Week 3 Week 4 A 24 2 lakh/week % 50% 75% % B /week % 75% % 50% C 15 1 lakh/week % 60% 80% 60% D lakh/week % 50% 50% 75% S60. Ans.(b) Sol. Number of mills operative in week 1 of village A = = 18 Level 1 (upper limit) of efficiency range 2 means 55% Total units produced in village A in first week when operated at level 1 of efficiency range 2 = Similarly, Number of mills operative in village B in week 2 = = level 2 (mid limit) of efficiency Range 1 = % = 65% Total units produced in village B in week 2 when operated at level 2 of efficiency range 1 = Required ratio = = 33 : 13 2 S61. Ans.(b) Sol. Mills operating in village C in week second and fourth is = 3 15 and 3 15 respectively. 5 5 Total units produced at level 1 of efficiency range 1 = (9 + 9), = = Mills operating in village A in first and fourth week is Total units produced at level 2 of efficiency range 1 = ( ) = = 5,460,000 units Required percentage = = % and 24 respectively S62. Ans.(e) Sol. No. of mills operating in B in fourth week = = 10 Total units consumed at level 3 of efficiency range 3 per house = = 0 units/house 240 No. of mills operating in C in second week = = 9 Total units consumed at level 1 of efficiency range 2 = 9 1, = 3300 unit/house 150 Required ratio = Adda247 No. 1 APP for Banking & SSC Preparation

8 S63. Ans.(b) Sol. Quantity I: m n = 72. m 5. n 10 If m>0, n< 0, then Quantity I > 0 Quantity II: x9 4+2 y = 4 3 x7 y If x < 0, y < 0, then quantity II > 0 Quantity III: 48 5 a b (12 4 1) = 40a 5 b 7 6 If a > 0, b < 0, then Quantity III < 0. Relation between Quantity I and Quantity II can t be established but Quantity II > Quantity III is our correct answer. Quantity I > Quantity II = Quantity III S64. Ans.(d) Sol. Quantity I: (p+n)2 (p n) 2 8pn(p+n) 2 = 1 p 2 +n 2 +2pn (p 2 +n 2 2pn) 8pn(p+n) 2 = 1 4pn 8pn(p+n) 2 = = (p + n)2 p = 1 2 n Quantity II: (q+n)3 (q n) 3 = 1 (n 2 +3q 2 ) 2 8n q 3 + n 3 + 3q 2 n + 3n 2 q (q 3 n 3 3q 2 n + 3n 2 q) (n 2 + 3q 2 ) 2 = 1 8n 2n 3 + 6q 2 n (n 2 + 3q 2 ) 2 = 1 8n 2n(n 2 + 3q 2 ) (n 2 + 3q 2 ) 2 = 1 8n 16n 2 = n 2 + 3q 2 q = 5n Quantity III: r+n+ r n r+n r n = 2 r + n + r n = 2( r + n r n) 3 r n = r + n 9(r n) = (r + n) 8r = 10n r = 10n 8 = 1.25n Quantity I < Quantity II > Quantity III 8 Adda247 No. 1 APP for Banking & SSC Preparation

9 S65. Ans(c) Sol. Quantity I Probability of at most two students will solve the question = 1 probability of all three students will solve the question = 1 (0.5) (0.6) (0.3) = = 0.91 Quantity II Total balls = = 12 Probability of getting at least 1 green ball = 1 probability of no green = = Quantity III P (Arun speak truth) = 4 5 P (Bhavya speak truth) = 6 7 Required probability = = = Quantity I > Quantity II > Quantity III S66. Ans.(e) Sol. ATQ, S = D (i) T (S + 10) = D (ii) T 2 (S 15) = D (ii) T+6 On solving (i), (ii) & (iii) D = 400 km, S = 40 km/hr. T = 10 hour Statement 1, 2 and 4 can be found out from the given data but statement 3 can t be solved as length of tunnel is not given. S67. Ans.(c) Sol. Let length of train A be (x + ) m So, length of train B be x m (2x + 150) = ( ) m = m = 450 m x = 150 m 9 Adda247 No. 1 APP for Banking & SSC Preparation

10 Length of train A = 250 m Length of train B = 150 m (i) Cannot be obtained because speed of man is not given (ii) Can be obtained ( ) t = 81 5 = sec (iii) it has already obtained (iv) can t be obtained because no other condition regarding C has been given Hence only (ii) and (iii) can be find out. S68. Ans.(b) Sol. Let the original number by xy According to given condition (10x + y) > 3(10y + x) 7x 29y > 0 On putting y=1 X has to be more than or equal to 5 So for y = 1, Possible values for x are 5, 6, 7, 8,9 So, 5 numbers are possible when y is 1 (51), (61), (71), (81), (91) be On putting y = 2 X has to be 9 So 92 is another number Values greater than 2 are not possible for y. If we take y = 3 than x has to be 13 which is not possible So there are 6 possible numbers. S69. Ans.(c) Sol. 2R 00 = 1400 R = 7% Now for x = 1 R = 8% for CI Equivalent CI at rate of 8% for 2 yrs = = 16.64% CI at 8% for 2 yr = Approximately = = Rs 114 = = 1881 For 9% CI = = Approx. = = 2166 For 10% = = = 2394 So, 3 values of x are possible i.e, 1, 2 and Adda247 No. 1 APP for Banking & SSC Preparation

11 S70. Ans.(b) Sol. Let marked price of article A and B be 400x and 500x respectively ATQ 400x ( d) 400 4d = 410 5d d = 10% Cost price of article A = = 300x Rs. = 500x ( d 18) x 120 Cost price of article B = 500x ( 28) 125 = 288x Rs. ATQ (500x x) (400x 300x) = x 60x = 384 x = 32 Cost price of article A = = Rs.9600 Cost price of article B = = Rs.9216 S71. Ans.(b) Sol. Efficiency of tap = 250 L/h In November there are total 30 days. Total flats = 20 Let tank is refilled n times So, n = n = 6 hours S72. Ans.(d) Sol. Total time in which tank gets emptied = = hours So, Rate of flow = = 200 L/hour 30 A% = = 20% 250 S73. Ans.(d) Sol. Let n number of flats were occupied x 250 = x = 24 flats B% = 24 = 60% Adda247 No. 1 APP for Banking & SSC Preparation

12 S74. Ans.(e) Sol. Efficiency of a tap in October = = 200 l/hour 5 New capacity of the tank = = l 5 Occupied flats in October = 30 Required time = = 80 hours S75. Ans.(d) Sol. Pattern of the series is, S76. Ans.(c) Sol. Pattern of the series is So, next terms will be , , , 4.5 Do not calculate exact values. Just calculate approximate values because with increase in values next term will be for away from 2835 So, is approx. 150 And, is approx is approx So, multiplies of 4.5 is nth term which is 10 th term. S77. Ans.(d) Sol. Second series 12 Adda247 No. 1 APP for Banking & SSC Preparation

13 S78. Ans.(e) Sol. ATQ 5x + 24 (A + B)x + (A + B C) ( ) = x x + 5 ( ) = x = 48 x = 4 (A + B + C) work for = = days S79. Ans.(c) Sol. Speed of current = Let s still water speed = x km/hr ATQ, (x 2) 28 (x + 2) = 3 21x x + 56 = 3x² 12 7x + 98 = 3x² 12 3x² + 7x 110 = 0 x = 5 km/hr 5 = 2 km hr S80. Ans(e) Sol. Volume of cylindrical vessel = 22 = cm 3 Volume of milk = = cm h = h = 462 h = 22 cm Adda247 No. 1 APP for Banking & SSC Preparation

1 Adda247 No. 1 APP for Banking & SSC Preparation S1. Ans.(d) Sol. Let cost price of article A be Rs. 10x cost price of article B = 10x 80 = Rs. 8x And, Selling price of article A = 10x 140 = Rs. 14x And

### 1 Adda247 No. 1 APP for Banking & SSC Preparation Website:store.adda247.com

1 Adda247 No. 1 APP for Banking & SSC Preparation Solutions S1. Ans.(a) S2. Ans.(b) S3. Ans.(b) S4. Ans.(d) 2 Adda247 No. 1 APP for Banking & SSC Preparation S5. Ans.(d) S6. Ans.(a) As E < Z and Z Y so,

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