The Laguerre-Pólya Class

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1 Non-linear operators and the Riemann Hypothesis Department of Mathematics s University of Hawai i at Mānoa lukasz@math.hawaii.edu April 23, 2010

2 The Riemann Hypothesis (1859) The most famous of all unresolved problems. Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk

3 The Riemann Hypothesis (1859) The most famous of all unresolved problems. ξ(x/2) = 8 0 Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk Φ(t) cos xt dt,

4 The Riemann Hypothesis (1859) The most famous of all unresolved problems. ξ(x/2) = 8 Φ(t) = n=1 0 Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk Φ(t) cos xt dt, ( 2n 4 π 2 e 9t 3n 2 πe 5t) e n2 πe 4t.

5 The Riemann Hypothesis (1859) The most famous of all unresolved problems. ξ(x/2) = 8 Φ(t) = n=1 0 Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk Φ(t) cos xt dt, ( 2n 4 π 2 e 9t 3n 2 πe 5t) e n2 πe 4t....es ist sehr wahrscheinlich, daß alle Wurzeln reell sind.

6 The Riemann Hypothesis (1859) The most famous of all unresolved problems. ξ(x/2) = 8 Φ(t) = n=1 0 Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk Φ(t) cos xt dt, ( 2n 4 π 2 e 9t 3n 2 πe 5t) e n2 πe 4t....es ist sehr wahrscheinlich, daß alle Wurzeln reell sind. Theorem The Riemann Hypothesis holds if and only if ξ belongs to the Laguerre-Pólya class.

7 (1914) Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk

8 (1914) Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk Functions in the Laguerre-Pólya class are uniform limits of polynomials all of whose zeros are real...

9 (1914) Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk Functions in the Laguerre-Pólya class are uniform limits of polynomials all of whose zeros are real...

10 (1914) Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk Functions in the Laguerre-Pólya class are uniform limits of polynomials all of whose zeros are real......and only the functions in the Laguerre-Pólya class enjoy this property.

11 The Turán Inequalities (1948) A necessary condition. Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk

12 The Turán Inequalities (1948) A necessary condition. Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk Theorem If ϕ(x) = γ k k=0 k! x k is a function in the Laguerre-Pólya class, then γk 2 γ k 1γ k+1 0 for k = 1, 2, 3,....

13 The Riemann ξ Function Bernhard Riemann Edmond Laguerre and George Pólya Paul Turán George Csordas, Richard Varga, Timothy Norfolk ξ(x/2) = 8 Φ(t) = n=1 0 Φ(t) cos xt dt, ( 2n 4 π 2 e 9t 3n 2 πe 5t) e n2 πe 4t. Theorem (Csordas, Varga, Norfolk (1986)) The coefficients of the Riemann ξ function satisfy the Turán inequalities.

14 Non-linear operators. Example Construct a degree 5 polynomial p(x) with zeros x = 1. p(x)

15 Non-linear operators. Example Construct a degree 5 polynomial p(x) with zeros x = 1. p(x) = (x + 1)(x + 1)(x + 1)(x + 1)(x + 1)

16 Non-linear operators. Example Construct a degree 5 polynomial p(x) with zeros x = 1. p(x) = (x + 1)(x + 1)(x + 1)(x + 1)(x + 1) = 1 + 5x + 10x x 3 + 5x 4 + x 5

17 Non-linear operators. Example Construct a degree 5 polynomial p(x) with zeros x = 1. p(x) = (x + 1)(x + 1)(x + 1)(x + 1)(x + 1) = 1 + 5x + 10x x 3 + 5x 4 + x 5 = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + a 4 x 5 + a 5 x 5.

18 Non-linear operators. Example Construct a degree 5 polynomial p(x) with zeros x = 1. p(x) = (x + 1)(x + 1)(x + 1)(x + 1)(x + 1) = 1 + 5x + 10x x 3 + 5x 4 + x 5 = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + a 4 x 5 + a 5 x 5. Replace a k with 3a 2 k 4a k 1a k+1 + a k 2 a k+2.

19 Non-linear operators. Example Construct a degree 5 polynomial p(x) with zeros x = 1. p(x) = (x + 1)(x + 1)(x + 1)(x + 1)(x + 1) = 1 + 5x + 10x x 3 + 5x 4 + x 5 = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + a 4 x 5 + a 5 x 5. Replace a k with 3a 2 k 4a k 1a k+1 + a k 2 a k+2. p(x) becomes x + 105x x x 4 + 3x 5.

20 Non-linear operators. Example Construct a degree 5 polynomial p(x) with zeros x = 1. p(x) = (x + 1)(x + 1)(x + 1)(x + 1)(x + 1) = 1 + 5x + 10x x 3 + 5x 4 + x 5 = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + a 4 x 5 + a 5 x 5. Replace a k with 3a 2 k 4a k 1a k+1 + a k 2 a k+2. p(x) becomes x + 105x x x 4 + 3x 5....and the zeros remain real and negative.

21 Non-linear operators. Example (continued...) p(x) = 1 + 5x + 10x x 3 + 5x 4 + x 5 = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + a 4 x 5 + a 5 x 5. The zeros of p(x) remain real and negative if a k is replaced with: a 2 k a k 1a k+1, 3a 2 k 4a k 1a k+1 + a k 2 a k+2, p(x) becomes x + 105x x x 4 + 3x 5

22 Non-linear operators. Example (continued...) p(x) = 1 + 5x + 10x x 3 + 5x 4 + x 5 = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + a 4 x 5 + a 5 x 5. The zeros of p(x) remain real and negative if a k is replaced with: a 2 k a k 1a k+1, p(x) becomes x + 50x x x 4 + x 5 3a 2 k 4a k 1a k+1 + a k 2 a k+2, p(x) becomes x + 105x x x 4 + 3x 5

23 Non-linear operators. Example (continued...) p(x) = 1 + 5x + 10x x 3 + 5x 4 + x 5 = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + a 4 x 5 + a 5 x 5. The zeros of p(x) remain real and negative if a k is replaced with: a 2 k a k 1a k+1, p(x) becomes x + 50x x x 4 + x 5 3a 2 k 4a k 1a k+1 + a k 2 a k+2, p(x) becomes x + 105x x x 4 + 3x 5 10a 2 k 15a k 1a k+1 + 6a k 2 a k+2 a k 3 a k+3,

24 Non-linear operators. Example (continued...) p(x) = 1 + 5x + 10x x 3 + 5x 4 + x 5 = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + a 4 x 5 + a 5 x 5. The zeros of p(x) remain real and negative if a k is replaced with: a 2 k a k 1a k+1, p(x) becomes x + 50x x x 4 + x 5 3a 2 k 4a k 1a k+1 + a k 2 a k+2, p(x) becomes x + 105x x x 4 + 3x 5 10a 2 k 15a k 1a k+1 + 6a k 2 a k+2 a k 3 a k+3, p(x) becomes x + 280x x x x 5

25 Non-linear operators. Example (continued...) p(x) = 1 + 5x + 10x x 3 + 5x 4 + x 5 = a 0 + a 1 x + a 2 x 2 + a 3 x 3 + a 4 x 5 + a 5 x 5. The zeros of p(x) remain real and negative if a k is replaced with: a 2 k a k 1a k+1, p(x) becomes x + 50x x x 4 + x 5 3a 2 k 4a k 1a k+1 + a k 2 a k+2, p(x) becomes x + 105x x x 4 + 3x 5 10a 2 k 15a k 1a k+1 + 6a k 2 a k+2 a k 3 a k+3, p(x) becomes x + 280x x x x 5 and infinitely many others...

26 Non-linear operators. The Main Result Theorem (Grabarek (2010)) Let ϕ(x) = ω k=0 a kx k, 0 ω, be a function in the Laguerre-Pólya class. If the zeros of ϕ(x) are real and negative, then the zeros remain real and negative after replacing a k with ( ) 2p 1 p ( ) 2p ak 2 p + ( 1) j a k j a k+j (p = 1, 2, 3,...). p j j=1

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