Geodesic motion in Kerr spacetime
|
|
- Aldous Blair
- 5 years ago
- Views:
Transcription
1 Chapte 20 Geodesic motion in Ke spacetime Let us conside a geodesic with affine paamete λ and tangent vecto u µ = dxµ dλ ẋµ. (20.1) In this section we shall use Boye-Lindquist s coodinates, and the dot will indicate diffeentiation with espect to λ. The tangent vecto u µ is solution of the geodesic equations u µ u ν ;µ =0, (20.2) which, as shown in Chapte 11, is equivalent to the Eule-Lagange equations associated to the Lagangian d L dλ ẋ = L α x α (20.3) L (x µ, ẋ µ )= 1 2 g µνẋ µ ẋ ν. (20.4) By defining the conjugate momentum p µ as the Eule-Lagange equations become p µ L ẋ µ = g µνẋ ν, (20.5) d dλ p µ = L x. (20.6) µ Note that, if the metic does not depend on a given coodinate x µ, the conjugate momentum p µ is a constant of motion and coincides with the constant of motion associated to the Killing vecto tangent to the coesponding coodinate lines. The Ke metic in Boye-Lindquist coodinates is indepentent of t and φ, theefoe p t =ẋ t u t = const and p φ =ẋ φ u φ = const; (20.7) these quantities coincide with the constant of motion associated to the Killing vectos k µ = (1, 0, 0, 0) and m µ = (0, 0, 0, 1), i.e. k µ u µ = u t and m µ u µ = u φ. 295
2 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 296 Theefoe, geodesic motion in Ke geomety is chaacteized by two constants of motion, which we indicate as: E k µ u µ = u t = p t constant along geodesics L m µ u µ = u φ = p φ constant along geodesics. (20.8) (20.9) As explained in Section 11.2, fo massive paticles E and L ae, espectively, the enegy and the angula momentum pe unit mass, as measued at infinity with espect to the black hole. Fo massless paticles, E and L ae the enegy and the angula momentum at infinity. Equations (20.2) (o, equivalently, (20.3)) in Ke spacetime ae vey complicate to solve diectly. To simplify the poblem we hall use the conseved quantities, as we did in Chapte 11 in when we studied geodesic motion in Schwazschild s spacetime. Fo this, we need fou algebaic elations involving u µ. Futhemoe g µν u µ u ν = κ (20.10) whee κ = 1 κ = 1 fo timelike geodesics fo spacelike geodesics κ = 0 fo null geodesics. (20.11) Eqs. (20.8), (20.9), (20.10) give thee algebaic elations involving u µ, but they ae not sufficient to to detemine the fou unknowns u µ. In Schwazschild spacetime a fouth equation is povided by the planaity of the obit (u θ = 0 if θ(λ = 0) = π/2); in Ke spacetime obits ae plana only in the equatoial plane theefoe, in geneal, geodesic motion cannot be studied in a simple way, using eqs. (20.8), (20.9), (20.10) only, as we did fo Schazschild. Howeve, as we shall biefly explain in the last section of this chapte, thee exists a futhe conseved quantity, the Cate constant, which allows to find the tangent vecto u µ using algebaic elations Equatoial geodesics In this section we study geodesic motion in the equatoial plane, i.e. geodesics with θ π 2. (20.12) Fist of all, let us pove that such geodesics exist, i.e. that eq. (20.12) is solution of the Eule-Lagange equations. The Lagangian is L = 1 2 g µνẋ µ ẋ ν = 1 2 [ + Σ θ 2 + { ( 1 2M Σ 2 + a 2 + 2Ma2 Σ ) ṫ 2 2M ] } sin 2 θ φ 2 sin2 θ Σ a sin2 θ ṫ φ + Σ ṙ2 (20.13)
3 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 297 and the θ component of Eule-Lagange s equations is d dλ (g θµẋ µ )= d dλ (Σ θ) = Σ θ +Σ,µ ẋ µ 1 θ = 2 g µν,θẋ µ ẋ ν. (20.14) The ight-hand side is 1 2 g µν,θẋ µ ẋ ν = 1 { ( ) (ṙ) 2 Σ,θ 2 +( θ) sin θ cos θ( 2 + a 2 )( φ) 2 2M Σ Σ ( 2,θ a sin 2 θ φ ṫ ) 2 4M ( + a sin 2 θ Σ φ ṫ ) φ} 2a sin θ cos θ (20.15) whee Σ,θ = 2a 2 sin θ cos θ and Σ, =2. It is easy to check that, when θ = π/2, equation (20.14) educes to θ = 2 ṙ θ. (20.16) Theefoe, if θ = 0 and θ = π/2 at λ = 0, then fo λ> 0 θ 0 and θ π/2. Thus, a geodesic which stats in the equatoial plane, emains in the equatoial plane at late times. This also occus in Schwazschild spacetime, and in that case, due to the spheical symmety, it is possible to genealize the esult to any obit, and pove that all geodesics ae plana. This genealization is not possible fo the Ke metic which is axially symmetic. In this case only equatoial geodesics ae plana. On the equatoial plane, Σ = 2, theefoe ( g tt = 1 2M ) g tφ = 2Ma and g = 2 g φφ = 2 + a 2 + 2Ma2 ( E = g tµ u µ = 1 2M L = g φµ u µ = 2Ma ṫ + To solve eqs. (20.18), (20.19) fo ṫ, φ we define ) ( ṫ + 2Ma 2 + a 2 + 2Ma2 (20.17) φ (20.18) ) φ. (20.19) A 1 2M B 2Ma C 2 + a 2 + 2Ma2 (20.20)
4 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 298 and wite eqs. (20.18), (20.19) as E = Aṫ + B φ (20.21) L = Bṫ + C φ. (20.22) Futhemoe, the following elation can be used ( AC + B 2 = 1 2M ) ( ) 2 + a 2 + 2Ma2 + 4M 2 a 2 = 2 2M + a 2 =. (20.23) 2 Theefoe, CE BL = [AC + B 2 ]ṫ =ṫ AL + BE = [AC + B 2 ] φ = φ (20.24) i.e. ṫ = 1 [( φ = a 2 + 2Ma2 [( 1 2M ) ) E 2Ma ] L L + 2Ma ] E. (20.25) The quantity C defined in eq. (20.20) can be witten in a diffeent fom, which will be useful in the following: ( 2 + a 2 ) 2 a 2 2 = 1 2 [(2 + a 2 )( 2 + a 2 ) a 2 ( 2 + a 2 2M)] = 1 2 [(2 + a 2 ) 2 +2Ma 2 ]= 2 + a 2 + 2Ma2 C. (20.26) Note that C is always positive. Let us now deive the equation fo the adial component of the fou-velocity. Equation (20.10) can be witten in tems of A, B, C: g µν u µ u ν = κ = Aṫ 2 2Bṫ φ + C φ ṙ2 = [Aṫ + B φ]ṫ +[ Bṫ + C φ] φ + 2 ṙ2 whee we have used eqs. (20.21), (20.22). Theefoe, = Eṫ + L φ + 2 ṙ2 (20.27) ṙ 2 = 2 (Eṫ L φ + κ) = 1 2 [ CE 2 2BLE AL 2] + κ 2. (20.28)
5 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 299 The polynomial [CE 2 2BLE AL 2 ] has zeos V ± = BL ± B 2 L 2 + ACL 2 C Consequently, eq. (20.28) can be witten as = L C [B ± ]. (20.29) ṙ 2 = C 2 (E V +)(E V )+ κ 2. (20.30) Using eq. (20.26), eqs. (20.30) and (20.29) finally become ṙ 2 = (2 + a 2 ) 2 a 2 (E V 4 + )(E V )+ κ, (20.31) 2 and V ± = 2Ma ± 2 ( 2 + a 2 ) 2 a 2 L. (20.32) In the Schwazschild limit a 0 and V + + V a 0, V + V L2 4 (20.33) theefoe, if we define V V + V, eqs. (20.31), (20.32) educe to the well known fom ṙ 2 = E 2 V (), whee V () = κ ( + L2 = 1 2M ) ( ) κ + L2 (20.34) whee we ecall that κ = 1 fo timelike geodesics, κ = 0 fo null geodesics, κ = 1 fo spacelike geodesics The potentials behaviou V ± = 2MLa ± L2 ( 2 + a 2 ) 2 a 2. (20.35) In pinciple we would have fou possibilities, coesponding to L positive and negative and a positive and negative. In pactice, thee ae only two inteesting cases: La > 0 and La < 0, i.e. the test paticle is eithe cootating o counteotating with the black hole. If the signs of L and a change simultaneously, the potentials V ± intechange: V + becomes V and vicevesa. To avoid this, it is bette to edefine the names of the potentials as follows so that the following inequality is always tue In geneal, we find that: V ± = 2MLa ± L 2 ( 2 + a 2 ) 2 a 2, (20.36) V + V. (20.37)
6 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 300 V + and V coincide fo = 0, i.e. fo while fo > +, > 0 and then V + >V. Futhemoe, which is positive if La > 0, negative if La < 0. In the limit, V ± 0. = + = M + M 2 a 2 (20.38) V + ( + )=V ( + )= 2M +La ( a 2 ) 2, (20.39) If La > 0 (cootating obits), the potential V + is definite positive; V (which is positive at + ) vanishes when which gives =2 Ma 2 ( 2 2M + a 2 )=4M 2 a 2 (20.40) 4 2M 3 + a 2 2 4M 2 a 2 =( 2M)( 3 + a 2 +2Ma 2 ) = 0; (20.41) thus V vanishes at =2M, which is the location of the egosphee in the equatoial plane. If La < 0 (counteotating obits), the potential V is definite negative and V (which is positive at + ) vanishes at =2M. The study of the deivatives of V ±, which is too long to be epoted hee, shows that both potentials, V + and V, have only one stationay point. In summay, V + () and V () have the shapes shown in Figue 20.1 whee the uppe and lowe panels efe, espectively, to the case La > 0 and La < 0 cases Null geodesics In the case of null geodesics the adial equation (20.31) becomes ṙ 2 = C 2 (E V +)(E V )= (2 + a 2 ) 2 a 2 4 (E V + )(E V ) (20.42) Since ṙ 2 must be positive, fom eq. (20.42) we see that, and being ( 2 + a 2 ) 2 a 2 > 0, null geodesics ae possible fo massless paticle whose constant of motion E satisfies the following inequalities E < V o E > V +. (20.43) Thus, the egion V fobidden. < E < V +, coesponding to the dashed egions in Figue 20.1, is
7 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 301 Figue 20.1: The potentials V + () and V (), fo cootating (al > 0) and counteotating (al < 0) obits. The shadowed egion is not accessible to the motion of photons o othe massless paticles. In ode to study the obits, it is useful to compute the adial acceleation. By diffeentiating eq. (20.42) with espect to the affine paamete λ, we find 2ṙ = [ ( C 2 ) (E V + )(E V ) C 2 V +(E V ) C 2 V (E V + ) ] ṙ (20.44) i.e. = 1 ( ) C (E V )(E V ) C [ V (E V )+V (E V +) ], (20.45) whee the pime indicates diffeentiation with espect to. Let us evaluate the adial acceleation in a point whee the adial velocity ṙ is zeo, i.e. when E = V + o E = V : Since = = C 2 V +(V 2 + V ) if E = V + = = C 2 V (V 2 V + ) if E = V. (20.46) 2 L 2 V + V = ( 2 + a 2 ) 2 a 2 = 2 L, (20.47) C
8 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 302 we find = L 2 V ± if E = V ±. (20.48) Unstable cicula obits If E = V + ( max ), whee max is the stationay point of V + (i.e. V + ( max) = 0), the adial acceleation vanishes; since when E = V + ( max ) the adial velocity also vanishes, a massless paticle with that value of E can be captued on a cicula obit, but the obit is unstable, as it is the obit at =3M fo the Schwazschild metic. It is possible to show that max is solution of the equation ( 3M) 2 4Ma 2 =0. (20.49) Note that the value of max is independent of L. The solution of (20.49) is a deceasing function of a, and, in paticula, max = 3M fo a =0 max = M fo a = M max = 4M fo a = M. (20.50) Theefoe, while fo a Schwazschild black hole the unstable cicula obit of a photon is at =3M, fo a Ke black hole it can be much close; in paticula, in the extemal case a = M, fo cootating obits max = M coincides with the oute hoizon. Radial captue A photon falling fom infinity with constant of motion E > V + ( max ), cosses the hoizon and falls towad the singulaity. Deflection If 0 > E > V + ( max ), the paticle eaches the tuning point whee E = V + () and ṙ = 0; eq. (20.48) shows that at the tuning point >0, theefoe the paticle evets its motion and escapes fee at infinity. In this case the paticle is deflected. In the above cases the constant of motion E associated to the timelike Killing vecto is assumed to be positive. It emains to conside the case E < V, and in paticula to see whethe negative values of E, admitted in pinciple admitted by eq. (20.43), have a physical meaning How do we measue the enegy of a paticle The enegy of a paticle is an obseve-dependent quantity. In special elativity, the enegy of a paticle with fou-momentum P µ, measued by an obseve with fou-velocity u µ, is defined as E (u) = η µν u µ P ν = u µ P ν. (20.51) Fo instance, the enegy measued by a static obseve u µ st = (1, 0, 0, 0) is E (ust) = P 0. (20.52)
9 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 303 A negative enegy would coespond to a paticle moving backwads in time, and causality would be violated. Thus, enegy is always positive; if measued by a diffeent obseve it will be diffeent, but still positive. Eq. (20.51) is a tenso equation; it holds in a locally inetial fame, whee g µν η µν, theefoe it can be witten as E (u) = g µν u µ P ν = u µ P µ. (20.53) Thus, by the pinciple of geneal covaiance, eq. (20.53), is the definition of enegy valid in any fame, and consequently E must be positive in any fame. Let us now conside a static obseve with u µ st = (1, 0, 0, 0), in Ke spacetime, located at adial infinity, whee such obseve can exist. Accoding to the definition (20.53), the enegy measued by the static obseve is E (ust) = P 0. Let us now compae this quantity with the constant of motion E = u 0 given in eq. (20.8). If the paticle is massless we can always paametize the geodesic in such a way that P 0 u 0. Thus: E (ust) = P 0 = E (20.54) We conclude that fo a paticle stating (o ending) its motion at adial infinity with espect to the black hole, the constant of motion E is the paticle enegy, as measued by a static obseve located at infinity 1. Fo such paticles obits with negative values of E ae not allowed. Thus, efeing to Figue 20.1, obits with E < V and E negative impinging fom adial infinity ae fobidden, even though fo such values ṙ 2 > 0 (see eq. (20.42)). Let us now conside a massless paticle which stats its motion in the egoegion, i.e. between + and 0 (see Figue 20.1). In this egion static obseves cannot exist, theefoe we need to conside a diffeent obseve, fo instance a ZAMO, whose fou-velocity can be witten as u µ ZAMO = const(1, 0, 0, Ω) (20.55) whee the ZAMO angula velocity Ω on the equatoial plane is (see eq. (19.27)) Ω= 2Ma ( 2 + a 2 ) 2 a 2 (20.56) and the constant is found by imposing g µν u µ u ν = 1. The constant must be positive, othewise the ZAMO would move backwads in time. The paticle enegy measued by the ZAMO is E ZAMO = P µ u µ ZAMO = const(e ΩL), (20.57) whee we have used eqs. (20.8) and (20.9). Thus, the equiement E ZAMO > 0 is equivalent to E>ΩL. (20.58) By compaing (20.56) with the expession of the potentials V ± given by eq. (20.36) we find that V < ΩL < V +. (20.59) 1 similaly, fo massive paticles E is the enegy pe unit mass as measued by a static obseve at infinity.
10 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 304 Theefoe, geodesics with E > V + (20.60) satisfy the positive enegy condition (20.58), and ae allowed, wheeas those with E < V ae fobidden, since do not satisfy eq. (20.58). Thus, efeing to Figue 20.36: a cootating paticle (La > 0) can move within the egoegion only if the costant of motion E is positive and is in the ange V + ( + ) < E < V + ( max ). (20.61) If E > V + ( max ) the paticle can coss the egosphee and escape at infinity. Fo counteotating paticles (La < 0), since in the egoegion V + is negative the equiement E > V + (necessay and sufficient to ensue that E > 0) allows negative values of the constant of motion E. Thus, counteotating paticles moving in the egoegion can have negative E, povided V + ( + )(= V ( + )) < E < 0. (20.62) As we shall show in the next section, this possibility has an inteesting consequence. It should be stessed that this is not a contadiction, because it is only at infinity that E epesents the paticle enegy; the geodesics we ae consideing neve each infinity The Penose pocess In this section we will use a slightly diffeent notation fo the constants of motion E, L, which have been shown to be the enegy and angula momentum pe unit mass, fo massive paticles, and the enegy and angula momentum fo massless paticles, as measued by a static obseve at infinity. Hee we define E and L to be the enegy and angula momentum at infinity, both fo massive and massless paticles, so that eqs. (20.8) and (20.9) become E = k µ P µ, L = m µ P µ. (20.63) This simply means that, fo massive paticles, E and L have been multiplied by the paticle mass m. We shall now show that since paticles with negative E can exist in the egoegion, we can imagine a pocess though which it may be possible to extact otational enegy fom a Ke black hole; this is named Penose s pocess. In what follows we shall set a>0. Assuming a<0 would lead to the same conclusions. Suppose that we shoot a massive paticle with enegy E and angula momentum L fom infinity, so that it falls towads the black hole in the equatoial plane. Its fou-momentum covaiant components ae P µ =( E,0, 0,L). (20.64)
11 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 305 Along the geodesic the paticle fou-momentum changes, but the covaiant components P t = k µ P µ = E, and P φ = m µ P µ = L emain constant, i.e., P µ =( E, P, 0,L). (20.65) When the paticle entes the egoegion, it decays in two photons, with momenta P 1 µ =( E 1,P 1, 0,L 1 ) P 2 µ =( E 2,P 2, 0,L 2 ). (20.66) Since the fou-momentum is conseved in this decay, we have fom which it follows that P µ = P 1 µ + P 2 µ o equivalently P µ = P 1 µ + P 2 µ, E = E 1 + E 2, L = L 1 + L 2. (20.67) Let us assume that ṙ 1 < 0, so that the photon 1 falls into the black hole, and that it has negative constants of motion, i.e. E 1 < 0 and L 1 < 0, with (see eq. (20.62)) V + ( + )(= V ( + )) <E 1 < 0. We futhe assume that ṙ 2 > 0, i.e. the photon 2 comes back to infinity. Note that, as explained in section , this is possible only if Its enegy and angula momentum ae E 2 >V + ( max ). E 2 = E E 1 >E L 2 = L L 1 > L, (20.68) thus, at the end of the pocess the paticle we find at infinity is moe enegetic than the one we sent in. It is possible to show that, since E 1 < 0,L 1 < 0, the captue of photon 1 by the black hole educes its mass-enegy M and its angula momentum J = Ma; indeed thei values M fin, J fin ae espectively: M fin = M + E 1 <M (20.69) J fin = J + L 1 < J. (20.70) To pove the inequality (20.69), we note that, as shown in Chapte 17, the total mass-enegy of the system is Ptot 0 = d 3 x( g)(t 00 + t 00 ), (20.71) V whee V is the volume of a t = const. thee-suface. If we neglect the gavitational field geneated by the paticle, t 00 is due to the black hole only, thus P 0 tot = V d 3 x( g)tpaticle 00 + M. (20.72)
12 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 306 Let us compute this integal when the pocess stats, i.e. at a time when the massive paticle is shoot into the black hole; the spacetime is flat, the paticle enegy is E, and the 00-component of the stess-enegy tenso of a point paticle with enegy E, in Minkowskian coodinates is Tpaticle 00 = Eδ3 (x x(t)). (20.73) Thus eq. (20.72) gives P 0 tot in = E + M in. (20.74) Repeating the computation at the end of the pocess, namely when the photon 2 eaches infinity, we find Ptot 0 fin = E 2 + M fin. (20.75) Due to the stationaity of the Ke metic, if we neglect the outgoing gavitational flux geneated by the paticle, Ptot 0 is a conseved quantity; theefoe by equating the initial and final momentum we find P 0 tot in = P 0 tot fin M fin = M in +(E E 2 ) M fin = M in + E 1 <M in. (20.76) This poves the elation (20.69), and eq. (20.70) can be poved accodingly. In conclusion, by this pocess we have extacted otational enegy fom the black hole The innemost stable cicula obit fo timelike geodesics The study of timelike geodesics is much moe complicate, because equation (20.30) which, when κ = 1, becomes ṙ 2 = C 2 (E V +)(E V ) 2, (20.77) does not allow a simple qualitative study as in the case of null geodesics. Theefoe, hee we only epot some esults of a detailed study of geodesics equation in this geneal case. A vey elevant quantity (of astophysical inteest) is the location of the innemost stable cicula obit (ISCO), which, in the Schwazschild case, is at = 6M. In Ke spacetime, the expession fo ISCO is quite complicate, but its qualitative behaviou is simple: thee ae two solutions ± ISCO(a), (20.78) one coesponding to cootating and counteotating obits. Fo a = 0, the two solutions coincide to 6M, as expected; by inceasing a, the ISCO moves close to the black hole fo cootating obits, and fathe fo counteotating obits. When a = ±M, the cootating ISCO coincides with the oute hoizon, at = + = M. This behaviou is vey simila to that we have aleady seen in the case of unstable cicula obits fo null geodesics. In Figue we show (fo a 0) the locations of the last stable and unstable cicula obits fo timelike geodesics, and of the unstable cicula obit fo null geodesics. This figue is taken fom the aticle whee these obits have been studied (J. Badeen, W. H. Pess, S. A. Teukolsky, Astophys. J. 178, 347, 1972).
13 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 307
14 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME The 3 d Keple law Let us conside a cicula timelike geodesic in the equatoial plane. We emind that the Lagangian (20.4) is and the -component of the Eule-Lagange equation is L = 1 2 g µνẋ µ ẋ ν (20.79) Being g µ = 0 if µ, we have d L dλ ṙ = L. (20.80) Fo cicula geodesic, ṙ = = 0, and this equation educes to The angula velocity is ω = φ/ṫ, thus We emind that on the equatoial plane then The equation has disciminant and solutions 2 ( d dλ (g ṙ) = 1 2 g µν,ẋ µ ẋ ν. (20.81) g tt, ṫ 2 +2g tφ, ṫ φ + g φφ, φ2 =0. (20.82) g φφ, ω 2 +2g tφ, ω + g tt, =0. (20.83) ( g tt = 1 2M g tφ = 2Ma ) g φφ = 2 + a 2 + 2Ma2 Ma2 2 ), (20.84) ω 2 + 4Ma 2 ω 2M 2 =0. (20.85) ( 3 Ma 2 )ω 2 +2Maω M = 0 (20.86) M 2 a 2 + M( 3 Ma 2 )=M 3 (20.87) ω ± = Ma ± M 3 3 Ma 2 = ± M 3/2 a M 3 Ma 2 = ± 3/2 a M M ( 3/2 + a M)( 3/2 a M) M = ± 3/2 ± a M. (20.88)
15 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 309 This is the elation between angula velocity and adius of cicula obits, and educes, in Schwazschild limit a = 0, to M ω ± = ±, (20.89) 3 which is Keple s 3 d law Geneal geodesic motion: the Cate constant To study geodesics in Ke spacetime, it is convenient to use the Hamilton-Jacobi appoach, which allows to indentify a futhe constant of motion. It should be stessed that this constant is not associated to a spacetime symmety. Given the Lagangian of the system and given the conjugate momenta 2 L(x µ, ẋ µ )= 1 2 g µνẋ µ ẋ ν (20.90) p µ = L ẋ µ = g µνẋ ν, (20.91) by inveting eq. (20.91), we can expess ẋ µ in tems of the conjugate momenta: ẋ µ = g µν p ν. (20.92) The Hamiltonian is a functional of the coodinate functions x µ (λ) and of thei conjugate momenta p µ (λ), defined as H(x µ,p ν )=p µ ẋ µ (p ν ) L (x µ, ẋ µ (p ν )). (20.93) Thus, in ou case H = 1 2 gµν p µ p ν. (20.94) Geodesic equations ae equivalent to the Eule-Lagange equations fo the Lagangian functional (20.90), which ae equivalent to the Hamilton equations fo the Hamiltonian functional: ẋ µ = H p µ ṗ µ = H x µ. (20.95) Solving eqs. (20.95) pesents the same difficulties as solving Eule-Lagange s equations. Howeve, in the Hamilton-Jacobi appoach, which we biefly ecall, the futhe constant of motion emeges quite natually. 2 Not to be confused with the fou-momentum of the paticle, which we denote with P µ.
16 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 310 In the Hamilton-Jacobi appoach, we look fo a function of the coodinates and of the cuve paamete λ, S = S(x µ,λ) (20.96) which is solution of the Hamilton-Jacobi equation ( H x µ, S ) x µ + S λ =0. (20.97) In geneal such solution depends on fou integation constants. It can be shown that, if S is a solution of the Hamilton-Jacobi equation, then S x µ = p µ. (20.98) Theefoe, once eq. (20.97) is solved, the expessions of the conjugate momenta (and of ẋ µ ) follows in tems of the fou constants, and allows to wite the solutions of geodesic equations in a closed fom, though integals. Fist of all, we can use what we aleady know, i.e. These conditions equie that H = 1 2 gµν p µ p ν = 1 2 κ p t = E constant p φ = L constant. (20.99) S = 1 2 κλ Et + Lφ + S(θ) (, θ) (20.100) whee S (θ) is a function of and θ to be detemined. Futhemoe, we look fo a sepaable solution, by making the ansatz S = 1 2 κλ Et + Lφ + S() ()+S (θ) (θ). (20.101) Substituting (20.101) into the Hamilton-Jacobi equation (20.97), and using the expession (19.14) fo the invese metic, we find κ + Σ [ 1 ( ds () d ) Σ 2 + a 2 + 2Ma2 Σ ( ds (θ) dθ ] sin2 θ ) 2 E 2 + 4Ma Σ EL + a2 sin 2 θ Σ sin 2 θ L2 =0. (20.102) Using the elation (19.26) ( 2 + a 2 )+ 2Ma2 Σ sin2 θ = 1 Σ [ ( 2 + a 2 ) 2 a 2 sin 2 θ ] (20.103)
17 R() [ C + κ 2 (L ae) 2] + [ E( 2 + a 2 ) La ] 2, (20.109) CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 311 and multiplying by Σ = 2 + a 2 cos 2 θ, we get ( ) ds κ( 2 + a 2 cos 2 () 2 ( ) ds (θ) 2 θ)+ + d dθ [ ( 2 + a 2 ) 2 ] a 2 sin 2 θ E 2 + 4Ma ( ) 1 EL + sin 2 θ a2 L 2 =0 i.e. = ( ) ds () 2 κ 2 (2 + a 2 ) 2 d ( ds (θ) dθ E 2 + 4Ma EL a2 ) 2 + κa 2 cos 2 θ a 2 sin 2 θe 2 1 sin 2 θ L2. L2 (20.104) (20.105) We eaange equation (20.105) by adding to both sides the constant quantity a 2 E 2 + L 2 : ( ) ds () 2 κ 2 (2 + a 2 ) 2 E 2 + 4Ma a2 EL d L2 + a 2 E 2 + L 2 ( ) ds (θ) 2 = + κa 2 cos 2 θ + a 2 cos 2 θe 2 cos2 θ dθ sin 2 θ L2. (20.106) In equation (20.106), the left-hand side does not depend on θ, and is equal to the ight-hand side which does not depend on ; theefoe, this quantity must be a constant C: ( ) ds (θ) 2 [ cos 2 θ (κ + E 2 )a 2 1 ] dθ sin 2 θ L2 = C ( ) ds () 2 κ 2 (2 + a 2 ) 2 E 2 + 4Ma a2 EL d L2 + E 2 a 2 + L 2 ( ) ds () 2 = κ 2 +(L ae) 2 1 [ E( 2 + a 2 ) La ] 2 = C. d (20.107) Note that in eaanging the tems in the last two lines, we have used the elation 2aLE +2aLE 2 + a 2 If we define the functions R() and Θ(θ) as [ Θ(θ) C + cos 2 θ (κ + E 2 )a 2 1 ] sin 2 θ L2 = 4aM LE. (20.108)
18 CHAPTER 20. GEODESIC MOTION IN KERR SPACETIME 312 then ( ) ds (θ) 2 = Θ dθ ( ds () d ) 2 = R 2 (20.110) and the solution of the Hamilton-Jacobi equation has the fom S = 1 2 κλ Et + Lφ + R d + Θdθ. (20.111) Thus, the constant C, which is called Cate s constant, fom its discovee B. Cate, emeges as a sepaation constant and chaacteize, togethe with E and L, geodetic motion in Ke spacetime. We stess again that, unlike E and L, it is not associated to a spacetime symmety. Once we have the solution of the Hamilton-Jacobi equations, depending on fou constants (κ, E, L, C), it is possible to find the paticle tajectoy. Indeed, fom (20.98) we know the expessions of the conjugate momenta theefoe p 2 θ = (Σ θ) 2 = Θ(θ) p 2 = ( ) Σ 2 = R() ṙ 2 (20.112) θ = 1 Σ Θ which can be solved by numeical integation. ṙ = 1 Σ R (20.113)
d 2 x 0a d d =0. Relative to an arbitrary (accelerating frame) specified by x a = x a (x 0b ), the latter becomes: d 2 x a d 2 + a dx b dx c
Chapte 6 Geneal Relativity 6.1 Towads the Einstein equations Thee ae seveal ways of motivating the Einstein equations. The most natual is pehaps though consideations involving the Equivalence Pinciple.
More informationHomework 7 Solutions
Homewok 7 olutions Phys 4 Octobe 3, 208. Let s talk about a space monkey. As the space monkey is oiginally obiting in a cicula obit and is massive, its tajectoy satisfies m mon 2 G m mon + L 2 2m mon 2
More informationConformal transformations + Schwarzschild
Intoduction to Geneal Relativity Solutions of homewok assignments 5 Confomal tansfomations + Schwazschild 1. To pove the identity, let s conside the fom of the Chistoffel symbols in tems of the metic tenso
More informationMASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Department. Problem Set 10 Solutions. r s
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Depatment Physics 8.033 Decembe 5, 003 Poblem Set 10 Solutions Poblem 1 M s y x test paticle The figue above depicts the geomety of the poblem. The position
More informationClassical Mechanics Homework set 7, due Nov 8th: Solutions
Classical Mechanics Homewok set 7, due Nov 8th: Solutions 1. Do deivation 8.. It has been asked what effect does a total deivative as a function of q i, t have on the Hamiltonian. Thus, lets us begin with
More informationFrom Gravitational Collapse to Black Holes
Fom Gavitational Collapse to Black Holes T. Nguyen PHY 391 Independent Study Tem Pape Pof. S.G. Rajeev Univesity of Rocheste Decembe 0, 018 1 Intoduction The pupose of this independent study is to familiaize
More informationGENERAL RELATIVITY: THE GEODESICS OF THE SCHWARZSCHILD METRIC
GENERAL RELATIVITY: THE GEODESICS OF THE SCHWARZSCHILD METRIC GILBERT WEINSTEIN 1. Intoduction Recall that the exteio Schwazschild metic g defined on the 4-manifold M = R R 3 \B 2m ) = {t,, θ, φ): > 2m}
More informationThe Schwarzschild Solution
The Schwazschild Solution Johannes Schmude 1 Depatment of Physics Swansea Univesity, Swansea, SA2 8PP, United Kingdom Decembe 6, 2007 1 pyjs@swansea.ac.uk Intoduction We use the following conventions:
More informationTutorial Exercises: Central Forces
Tutoial Execises: Cental Foces. Tuning Points fo the Keple potential (a) Wite down the two fist integals fo cental motion in the Keple potential V () = µm/ using J fo the angula momentum and E fo the total
More informationThe Precession of Mercury s Perihelion
The Pecession of Mecuy s Peihelion Owen Biesel Januay 25, 2008 Contents 1 Intoduction 2 2 The Classical olution 2 3 Classical Calculation of the Peiod 4 4 The Relativistic olution 5 5 Remaks 9 1 1 Intoduction
More informationMechanics Physics 151
Mechanics Physics 151 Lectue 5 Cental Foce Poblem (Chapte 3) What We Did Last Time Intoduced Hamilton s Pinciple Action integal is stationay fo the actual path Deived Lagange s Equations Used calculus
More informationarxiv:gr-qc/ v1 1 Sep 2005
Radial fall of a test paticle onto an evapoating black hole Andeas Aste and Dik Tautmann Depatment fo Physics and Astonomy, Univesity of Basel, 456 Basel, Switzeland E-mail: andeas.aste@unibas.ch June
More informationThe Schwartzchild Geometry
UNIVERSITY OF ROCHESTER The Schwatzchild Geomety Byon Osteweil Decembe 21, 2018 1 INTRODUCTION In ou study of geneal elativity, we ae inteested in the geomety of cuved spacetime in cetain special cases
More informationASTR415: Problem Set #6
ASTR45: Poblem Set #6 Cuan D. Muhlbege Univesity of Mayland (Dated: May 7, 27) Using existing implementations of the leapfog and Runge-Kutta methods fo solving coupled odinay diffeential equations, seveal
More informationPhysics 506 Winter 2006 Homework Assignment #9 Solutions
Physics 506 Winte 2006 Homewok Assignment #9 Solutions Textbook poblems: Ch. 12: 12.2, 12.9, 12.13, 12.14 12.2 a) Show fom Hamilton s pinciple that Lagangians that diffe only by a total time deivative
More informationPhysics 161: Black Holes: Lecture 5: 22 Jan 2013
Physics 161: Black Holes: Lectue 5: 22 Jan 2013 Pofesso: Kim Giest 5 Equivalence Pinciple, Gavitational Redshift and Geodesics of the Schwazschild Metic 5.1 Gavitational Redshift fom the Schwazschild metic
More information= 4 3 π( m) 3 (5480 kg m 3 ) = kg.
CHAPTER 11 THE GRAVITATIONAL FIELD Newton s Law of Gavitation m 1 m A foce of attaction occus between two masses given by Newton s Law of Gavitation Inetial mass and gavitational mass Gavitational potential
More informationGeometry of the homogeneous and isotropic spaces
Geomety of the homogeneous and isotopic spaces H. Sonoda Septembe 2000; last evised Octobe 2009 Abstact We summaize the aspects of the geomety of the homogeneous and isotopic spaces which ae most elevant
More informationS7: Classical mechanics problem set 2
J. Magoian MT 9, boowing fom J. J. Binney s 6 couse S7: Classical mechanics poblem set. Show that if the Hamiltonian is indepdent of a genealized co-odinate q, then the conjugate momentum p is a constant
More informationHomework # 3 Solution Key
PHYSICS 631: Geneal Relativity Homewok # 3 Solution Key 1. You e on you hono not to do this one by hand. I ealize you can use a compute o simply look it up. Please don t. In a flat space, the metic in
More informationThis gives rise to the separable equation dr/r = 2 cot θ dθ which may be integrated to yield r(θ) = R sin 2 θ (3)
Physics 506 Winte 2008 Homewok Assignment #10 Solutions Textbook poblems: Ch. 12: 12.10, 12.13, 12.16, 12.19 12.10 A chaged paticle finds itself instantaneously in the equatoial plane of the eath s magnetic
More information4. Kruskal Coordinates and Penrose Diagrams.
4. Kuskal Coodinates and Penose Diagams. 4.1. Removing a coodinate ingulaity at the chwazschild Radius. The chwazschild metic has a singulaity at = whee g 0 and g. Howeve, 00 we have aleady seen that a
More informationIs there a magnification paradox in gravitational lensing?
Is thee a magnification paadox in gavitational ing? Olaf Wucknitz wucknitz@asto.uni-bonn.de Astophysics semina/colloquium, Potsdam, 6 Novembe 7 Is thee a magnification paadox in gavitational ing? gavitational
More informationChapter 13 Gravitation
Chapte 13 Gavitation In this chapte we will exploe the following topics: -Newton s law of gavitation, which descibes the attactive foce between two point masses and its application to extended objects
More informationA New Approach to General Relativity
Apeion, Vol. 14, No. 3, July 7 7 A New Appoach to Geneal Relativity Ali Rıza Şahin Gaziosmanpaşa, Istanbul Tukey E-mail: aizasahin@gmail.com Hee we pesent a new point of view fo geneal elativity and/o
More informationPHYS 110B - HW #7 Spring 2004, Solutions by David Pace Any referenced equations are from Griffiths Problem statements are paraphrased
PHYS 0B - HW #7 Sping 2004, Solutions by David Pace Any efeenced euations ae fom Giffiths Poblem statements ae paaphased. Poblem 0.3 fom Giffiths A point chage,, moves in a loop of adius a. At time t 0
More informationSpherical Solutions due to the Exterior Geometry of a Charged Weyl Black Hole
Spheical Solutions due to the Exteio Geomety of a Chaged Weyl Black Hole Fain Payandeh 1, Mohsen Fathi Novembe 7, 018 axiv:10.415v [g-qc] 10 Oct 01 1 Depatment of Physics, Payame Noo Univesity, PO BOX
More informationPhysics 181. Assignment 4
Physics 181 Assignment 4 Solutions 1. A sphee has within it a gavitational field given by g = g, whee g is constant and is the position vecto of the field point elative to the cente of the sphee. This
More information15 Solving the Laplace equation by Fourier method
5 Solving the Laplace equation by Fouie method I aleady intoduced two o thee dimensional heat equation, when I deived it, ecall that it taes the fom u t = α 2 u + F, (5.) whee u: [0, ) D R, D R is the
More informationNewton s Laws, Kepler s Laws, and Planetary Orbits
Newton s Laws, Keple s Laws, and Planetay Obits PROBLEM SET 4 DUE TUESDAY AT START OF LECTURE 28 Septembe 2017 ASTRONOMY 111 FALL 2017 1 Newton s & Keple s laws and planetay obits Unifom cicula motion
More informationPhysics 161 Fall 2011 Extra Credit 2 Investigating Black Holes - Solutions The Following is Worth 50 Points!!!
Physics 161 Fall 011 Exta Cedit Investigating Black Holes - olutions The Following is Woth 50 Points!!! This exta cedit assignment will investigate vaious popeties of black holes that we didn t have time
More informationScattering in Three Dimensions
Scatteing in Thee Dimensions Scatteing expeiments ae an impotant souce of infomation about quantum systems, anging in enegy fom vey low enegy chemical eactions to the highest possible enegies at the LHC.
More informationOn the integration of the equations of hydrodynamics
Uebe die Integation de hydodynamischen Gleichungen J f eine u angew Math 56 (859) -0 On the integation of the equations of hydodynamics (By A Clebsch at Calsuhe) Tanslated by D H Delphenich In a pevious
More informationPendulum in Orbit. Kirk T. McDonald Joseph Henry Laboratories, Princeton University, Princeton, NJ (December 1, 2017)
1 Poblem Pendulum in Obit Kik T. McDonald Joseph Heny Laboatoies, Pinceton Univesity, Pinceton, NJ 08544 (Decembe 1, 2017) Discuss the fequency of small oscillations of a simple pendulum in obit, say,
More information= e2. = 2e2. = 3e2. V = Ze2. where Z is the atomic numnber. Thus, we take as the Hamiltonian for a hydrogenic. H = p2 r. (19.4)
Chapte 9 Hydogen Atom I What is H int? That depends on the physical system and the accuacy with which it is descibed. A natual stating point is the fom H int = p + V, (9.) µ which descibes a two-paticle
More informationMath 124B February 02, 2012
Math 24B Febuay 02, 202 Vikto Gigoyan 8 Laplace s equation: popeties We have aleady encounteed Laplace s equation in the context of stationay heat conduction and wave phenomena. Recall that in two spatial
More informationThe Poisson bracket and magnetic monopoles
FYST420 Advanced electodynamics Olli Aleksante Koskivaaa Final poject ollikoskivaaa@gmail.com The Poisson backet and magnetic monopoles Abstact: In this wok magnetic monopoles ae studied using the Poisson
More informationAn Exact Solution of Navier Stokes Equation
An Exact Solution of Navie Stokes Equation A. Salih Depatment of Aeospace Engineeing Indian Institute of Space Science and Technology, Thiuvananthapuam, Keala, India. July 20 The pincipal difficulty in
More informationAs is natural, our Aerospace Structures will be described in a Euclidean three-dimensional space R 3.
Appendix A Vecto Algeba As is natual, ou Aeospace Stuctues will be descibed in a Euclidean thee-dimensional space R 3. A.1 Vectos A vecto is used to epesent quantities that have both magnitude and diection.
More informationMASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Department. Problem Set 9
MASSACHUSETTS INSTITUTE OF TECHNOLOGY Physics Depatment Physics 8.033 Novembe 17, 2006 Poblem Set 9 Due: Decembe 8, at 4:00PM. Please deposit the poblem set in the appopiate 8.033 bin, labeled with name
More informationAST2000 Lecture Notes
AST000 Lectue Notes Pat C Geneal Relativity: Basic pinciples Questions to ponde befoe the lectue 1. What is a black hole? how would you define it?). If you, situated in a safe place fa away fom the black
More informationworking pages for Paul Richards class notes; do not copy or circulate without permission from PGR 2004/11/3 10:50
woking pages fo Paul Richads class notes; do not copy o ciculate without pemission fom PGR 2004/11/3 10:50 CHAPTER7 Solid angle, 3D integals, Gauss s Theoem, and a Delta Function We define the solid angle,
More informationHilbert s forgotten equation of velocity dependent acceleration in a gravitational field
Hilbet s fogotten equation of velocity dependent acceleation in a gavitational field David L Bekahn, James M Chappell, and Deek Abbott School of Electical and Electonic Engineeing, Univesity of Adelaide,
More informationSuch objects are called black holes, and there is extremely strong circumstantial evidence that they exist.
Chapte 11 Spheical black holes One of the most spectacula consequences of geneal elativity is the pediction that gavitational fields can become so stong that they can effectively tap even light. Space
More informationElectrostatics (Electric Charges and Field) #2 2010
Electic Field: The concept of electic field explains the action at a distance foce between two chaged paticles. Evey chage poduces a field aound it so that any othe chaged paticle expeiences a foce when
More informationBlack Holes. Tom Charnock
Black Holes Tom Chanock Contents 1 Why Study Black Holes? 2 2 Relativity 4 2.1 The Metic............................................ 4 2.1.1 Chistoffel Connections................................. 4 2.2
More informationLecture 8 - Gauss s Law
Lectue 8 - Gauss s Law A Puzzle... Example Calculate the potential enegy, pe ion, fo an infinite 1D ionic cystal with sepaation a; that is, a ow of equally spaced chages of magnitude e and altenating sign.
More informationStress, Cauchy s equation and the Navier-Stokes equations
Chapte 3 Stess, Cauchy s equation and the Navie-Stokes equations 3. The concept of taction/stess Conside the volume of fluid shown in the left half of Fig. 3.. The volume of fluid is subjected to distibuted
More informationEM Boundary Value Problems
EM Bounday Value Poblems 10/ 9 11/ By Ilekta chistidi & Lee, Seung-Hyun A. Geneal Desciption : Maxwell Equations & Loentz Foce We want to find the equations of motion of chaged paticles. The way to do
More informationFlux. Area Vector. Flux of Electric Field. Gauss s Law
Gauss s Law Flux Flux in Physics is used to two distinct ways. The fist meaning is the ate of flow, such as the amount of wate flowing in a ive, i.e. volume pe unit aea pe unit time. O, fo light, it is
More informationBut for simplicity, we ll define significant as the time it takes a star to lose all memory of its original trajectory, i.e.,
Stella elaxation Time [Chandasekha 1960, Pinciples of Stella Dynamics, Chap II] [Ostike & Davidson 1968, Ap.J., 151, 679] Do stas eve collide? Ae inteactions between stas (as opposed to the geneal system
More informationAST 121S: The origin and evolution of the Universe. Introduction to Mathematical Handout 1
Please ead this fist... AST S: The oigin and evolution of the Univese Intoduction to Mathematical Handout This is an unusually long hand-out and one which uses in places mathematics that you may not be
More informationPhysics 2B Chapter 22 Notes - Magnetic Field Spring 2018
Physics B Chapte Notes - Magnetic Field Sping 018 Magnetic Field fom a Long Staight Cuent-Caying Wie In Chapte 11 we looked at Isaac Newton s Law of Gavitation, which established that a gavitational field
More informationPhysics 107 TUTORIAL ASSIGNMENT #8
Physics 07 TUTORIAL ASSIGNMENT #8 Cutnell & Johnson, 7 th edition Chapte 8: Poblems 5,, 3, 39, 76 Chapte 9: Poblems 9, 0, 4, 5, 6 Chapte 8 5 Inteactive Solution 8.5 povides a model fo solving this type
More informationPhysics 235 Chapter 5. Chapter 5 Gravitation
Chapte 5 Gavitation In this Chapte we will eview the popeties of the gavitational foce. The gavitational foce has been discussed in geat detail in you intoductoy physics couses, and we will pimaily focus
More informationKEPLER S LAWS OF PLANETARY MOTION
EPER S AWS OF PANETARY MOTION 1. Intoduction We ae now in a position to apply what we have leaned about the coss poduct and vecto valued functions to deive eple s aws of planetay motion. These laws wee
More informationis the instantaneous position vector of any grid point or fluid
Absolute inetial, elative inetial and non-inetial coodinates fo a moving but non-defoming contol volume Tao Xing, Pablo Caica, and Fed Sten bjective Deive and coelate the govening equations of motion in
More informationConditions for the naked singularity formation in generalized Vaidya spacetime
Jounal of Physics: Confeence Seies PAPER OPEN ACCESS Conditions fo the naked singulaity fomation in genealized Vaidya spacetime To cite this aticle: V D Vetogadov 2016 J. Phys.: Conf. Se. 769 012013 View
More information8 Separation of Variables in Other Coordinate Systems
8 Sepaation of Vaiables in Othe Coodinate Systems Fo the method of sepaation of vaiables to succeed you need to be able to expess the poblem at hand in a coodinate system in which the physical boundaies
More informationPhysics 121 Hour Exam #5 Solution
Physics 2 Hou xam # Solution This exam consists of a five poblems on five pages. Point values ae given with each poblem. They add up to 99 points; you will get fee point to make a total of. In any given
More informationGravitational Memory?
Gavitational Memoy? a Petubative Appoach T. Haada 1, Depatment of Physics, Waseda Univesity, Shinjuku, Tokyo 169-8555, Japan B.J. Ca 2,andC.A.Goyme 3 Astonomy Unit, Queen May and Westfield College, Univesity
More informationThe tunneling spectrum of Einsein Born-Infeld Black Hole. W. Ren2
Intenational Confeence on Engineeing Management Engineeing Education and Infomation Technology (EMEEIT 015) The tunneling spectum of Einsein Bon-Infeld Black Hole J Tang1 W Ren Y Han3 1 Aba teaches college
More informationProjection Gravitation, a Projection Force from 5-dimensional Space-time into 4-dimensional Space-time
Intenational Jounal of Physics, 17, Vol. 5, No. 5, 181-196 Available online at http://pubs.sciepub.com/ijp/5/5/6 Science and ducation Publishing DOI:1.1691/ijp-5-5-6 Pojection Gavitation, a Pojection Foce
More informationAppendix B The Relativistic Transformation of Forces
Appendix B The Relativistic Tansfomation of oces B. The ou-foce We intoduced the idea of foces in Chapte 3 whee we saw that the change in the fou-momentum pe unit time is given by the expession d d w x
More informationarxiv:gr-qc/ v2 23 May 2005
Pionee s Anomaly and the Sola Quadupole Moment Henando Quevedo Instituto de Ciencias Nucleaes Univesidad Nacional Autónoma de México A.P. 70-543, México D.F. 04510, México axiv:g-qc/0501006v2 23 May 2005
More informationTo Feel a Force Chapter 7 Static equilibrium - torque and friction
To eel a oce Chapte 7 Chapte 7: Static fiction, toque and static equilibium A. Review of foce vectos Between the eath and a small mass, gavitational foces of equal magnitude and opposite diection act on
More informationA Relativistic Electron in a Coulomb Potential
A Relativistic Electon in a Coulomb Potential Alfed Whitehead Physics 518, Fall 009 The Poblem Solve the Diac Equation fo an electon in a Coulomb potential. Identify the conseved quantum numbes. Specify
More informationPhysics 2A Chapter 10 - Moment of Inertia Fall 2018
Physics Chapte 0 - oment of netia Fall 08 The moment of inetia of a otating object is a measue of its otational inetia in the same way that the mass of an object is a measue of its inetia fo linea motion.
More informationCurvature singularity
Cuvatue singulaity We wish to show that thee is a cuvatue singulaity at 0 of the Schwazschild solution. We cannot use eithe of the invaiantsr o R ab R ab since both the Ricci tenso and the Ricci scala
More informationKEPLER S LAWS AND PLANETARY ORBITS
KEPE S AWS AND PANETAY OBITS 1. Selected popeties of pola coodinates and ellipses Pola coodinates: I take a some what extended view of pola coodinates in that I allow fo a z diection (cylindical coodinates
More informationOSCILLATIONS AND GRAVITATION
1. SIMPLE HARMONIC MOTION Simple hamonic motion is any motion that is equivalent to a single component of unifom cicula motion. In this situation the velocity is always geatest in the middle of the motion,
More informationPhysics: Work & Energy Beyond Earth Guided Inquiry
Physics: Wok & Enegy Beyond Eath Guided Inquiy Elliptical Obits Keple s Fist Law states that all planets move in an elliptical path aound the Sun. This concept can be extended to celestial bodies beyond
More informationChapter 12: Kinematics of a Particle 12.8 CURVILINEAR MOTION: CYLINDRICAL COMPONENTS. u of the polar coordinate system are also shown in
ME 01 DYNAMICS Chapte 1: Kinematics of a Paticle Chapte 1 Kinematics of a Paticle A. Bazone 1.8 CURVILINEAR MOTION: CYLINDRICAL COMPONENTS Pola Coodinates Pola coodinates ae paticlaly sitable fo solving
More information10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11.
NSWRS - P Physics Multiple hoice Pactice Gavitation Solution nswe 1. m mv Obital speed is found fom setting which gives v whee M is the object being obited. Notice that satellite mass does not affect obital
More informationAdiabatic evolution of the constants of motion in resonance (I)
Adiabatic evolution of the constants of motion in esonance (I) BH Gavitational 重 力力波 waves Takahio Tanaka (YITP, Kyoto univesity) R. Fujita, S. Isoyama, H. Nakano, N. Sago PTEP 013 (013) 6, 063E01 e-pint:
More informationPHYSICS NOTES GRAVITATION
GRAVITATION Newton s law of gavitation The law states that evey paticle of matte in the univese attacts evey othe paticle with a foce which is diectly popotional to the poduct of thei masses and invesely
More informationDetermining solar characteristics using planetary data
Detemining sola chaacteistics using planetay data Intoduction The Sun is a G-type main sequence sta at the cente of the Sola System aound which the planets, including ou Eath, obit. In this investigation
More informationQuantum Mechanics I - Session 5
Quantum Mechanics I - Session 5 Apil 7, 015 1 Commuting opeatos - an example Remine: You saw in class that Â, ˆB ae commuting opeatos iff they have a complete set of commuting obsevables. In aition you
More informationCOORDINATE TRANSFORMATIONS - THE JACOBIAN DETERMINANT
COORDINATE TRANSFORMATIONS - THE JACOBIAN DETERMINANT Link to: phsicspages home page. To leave a comment o epot an eo, please use the auilia blog. Refeence: d Inveno, Ra, Intoducing Einstein s Relativit
More informationME 210 Applied Mathematics for Mechanical Engineers
Tangent and Ac Length of a Cuve The tangent to a cuve C at a point A on it is defined as the limiting position of the staight line L though A and B, as B appoaches A along the cuve as illustated in the
More informationNumerical Integration
MCEN 473/573 Chapte 0 Numeical Integation Fall, 2006 Textbook, 0.4 and 0.5 Isopaametic Fomula Numeical Integation [] e [ ] T k = h B [ D][ B] e B Jdsdt In pactice, the element stiffness is calculated numeically.
More informationQuantum Mechanics II
Quantum Mechanics II Pof. Bois Altshule Apil 25, 2 Lectue 25 We have been dicussing the analytic popeties of the S-matix element. Remembe the adial wave function was u kl () = R kl () e ik iπl/2 S l (k)e
More informationDoes a black hole rotate in Chern-Simons modified gravity?
PHYSICAL REVIEW D 76, 024009 (2007) Does a black hole otate in Chen-Simons modified gavity? Kohkichi Konno,, * Toyoki Matsuyama, 2 and Satoshi Tanda Depatment of Applied Physics, Hokkaido Univesity, Sappoo
More informationChapter 7-8 Rotational Motion
Chapte 7-8 Rotational Motion What is a Rigid Body? Rotational Kinematics Angula Velocity ω and Acceleation α Unifom Rotational Motion: Kinematics Unifom Cicula Motion: Kinematics and Dynamics The Toque,
More informationDo not turn over until you are told to do so by the Invigilator.
UNIVERSITY OF EAST ANGLIA School of Mathematics Main Seies UG Examination 2015 16 FLUID DYNAMICS WITH ADVANCED TOPICS MTH-MD59 Time allowed: 3 Hous Attempt QUESTIONS 1 and 2, and THREE othe questions.
More information(read nabla or del) is defined by, k. (9.7.1*)
9.7 Gadient of a scala field. Diectional deivative Some of the vecto fields in applications can be obtained fom scala fields. This is vey advantageous because scala fields can be handled moe easily. The
More informationPhysics 2212 GH Quiz #2 Solutions Spring 2016
Physics 2212 GH Quiz #2 Solutions Sping 216 I. 17 points) Thee point chages, each caying a chage Q = +6. nc, ae placed on an equilateal tiangle of side length = 3. mm. An additional point chage, caying
More informationMODULE 5 ADVANCED MECHANICS GRAVITATIONAL FIELD: MOTION OF PLANETS AND SATELLITES VISUAL PHYSICS ONLINE
VISUAL PHYSICS ONLIN MODUL 5 ADVANCD MCHANICS GRAVITATIONAL FILD: MOTION OF PLANTS AND SATLLITS SATLLITS: Obital motion of object of mass m about a massive object of mass M (m
More informationRadial Inflow Experiment:GFD III
Radial Inflow Expeiment:GFD III John Mashall Febuay 6, 003 Abstact We otate a cylinde about its vetical axis: the cylinde has a cicula dain hole in the cente of its bottom. Wate entes at a constant ate
More informationQualifying Examination Electricity and Magnetism Solutions January 12, 2006
1 Qualifying Examination Electicity and Magnetism Solutions Januay 12, 2006 PROBLEM EA. a. Fist, we conside a unit length of cylinde to find the elationship between the total chage pe unit length λ and
More informationExceptional regular singular points of second-order ODEs. 1. Solving second-order ODEs
(May 14, 2011 Exceptional egula singula points of second-ode ODEs Paul Gaett gaett@math.umn.edu http://www.math.umn.edu/ gaett/ 1. Solving second-ode ODEs 2. Examples 3. Convegence Fobenius method fo solving
More information6.4 Period and Frequency for Uniform Circular Motion
6.4 Peiod and Fequency fo Unifom Cicula Motion If the object is constained to move in a cicle and the total tangential foce acting on the total object is zeo, F θ = 0, then (Newton s Second Law), the tangential
More informationarxiv: v1 [gr-qc] 4 Dec 2018
Distinguishing a Ke-like black hole and a naked singulaity in pefect fluid dak matte via pecession fequencies Muhammad Rizwan, 1,, Mubashe Jamil, 1, and Kimet Jusufi3, 4, 1 Depatment of Mathematics, School
More informationI. CONSTRUCTION OF THE GREEN S FUNCTION
I. CONSTRUCTION OF THE GREEN S FUNCTION The Helmohltz equation in 4 dimensions is 4 + k G 4 x, x = δ 4 x x. In this equation, G is the Geen s function and 4 efes to the dimensionality. In the vey end,
More information11) A thin, uniform rod of mass M is supported by two vertical strings, as shown below.
Fall 2007 Qualifie Pat II 12 minute questions 11) A thin, unifom od of mass M is suppoted by two vetical stings, as shown below. Find the tension in the emaining sting immediately afte one of the stings
More informationChapter 12. Kinetics of Particles: Newton s Second Law
Chapte 1. Kinetics of Paticles: Newton s Second Law Intoduction Newton s Second Law of Motion Linea Momentum of a Paticle Systems of Units Equations of Motion Dynamic Equilibium Angula Momentum of a Paticle
More informationrt () is constant. We know how to find the length of the radius vector by r( t) r( t) r( t)
Cicula Motion Fom ancient times cicula tajectoies hae occupied a special place in ou model of the Uniese. Although these obits hae been eplaced by the moe geneal elliptical geomety, cicula motion is still
More informationF(r) = r f (r) 4.8. Central forces The most interesting problems in classical mechanics are about central forces.
4.8. Cental foces The most inteesting poblems in classical mechanics ae about cental foces. Definition of a cental foce: (i) the diection of the foce F() is paallel o antipaallel to ; in othe wods, fo
More informationThree dimensional flow analysis in Axial Flow Compressors
1 Thee dimensional flow analysis in Axial Flow Compessos 2 The ealie assumption on blade flow theoies that the flow inside the axial flow compesso annulus is two dimensional means that adial movement of
More informationCHAPTER 25 ELECTRIC POTENTIAL
CHPTE 5 ELECTIC POTENTIL Potential Diffeence and Electic Potential Conside a chaged paticle of chage in a egion of an electic field E. This filed exets an electic foce on the paticle given by F=E. When
More information