1.5 h; 140 points please print clearly Dr. Ginger Shultz Dr. Kathleen Nolta. Problem Points Score GSI I 32 II 27 III 32 IV 25 V 24 Total 140

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1 hemistry 10 Third Examination First ame Last ame 1.5 h; 10 points please print clearly Dr. Ginger hultz Dr. Kathleen olta ignature UM D # PRT TE FRT LETTER F YUR LAT AME ERE: Problem Points core G 7 V 5 V Total 10 Precision in drawing counts. heck all three-dimensional representations to ensure you are implying an unequivocal direction of bonding and appropriate stereochemistry. Do not forget to include important features such as nonbonding electron pairs and formal charges when appropriate. ndividual point values are given in the corner of each answer space. The exam has 6 pages in addition to this cover page. A pka table is on the last page.

2 ame. ( points) Page 1 Each of the reactions yields a PAR of main organic products, but you should only draw one. Then answer the other questions about the starting material and the products formed. A. starting material l / (i) (ii) heated P (iii) (iv) (v) Provide the complete name (including stereochemical labels as needed) for this starting material (vi) Fill in the predicted number of MR signals expected for the starting material: 1 -MR starting material KMn (i) (ii) Pd (iii) (iv) (v) Provide the complete name (including stereochemical labels as needed) for this starting material (vi) Fill in the predicted number of MR signals expected for the starting material: 1 -MR

3 . (7 points) ame Page election is everywhere. Each of the following transformations exhibits some kind of selection. Provide the required missing materials, either starting materials, products, or complete transformations. A. (i) Draw the alkene starting material s one product (i) Draw one product (ii) This product forms: with with alone (ii) This product forms:. a Despite containing two potential leaving groups, the reaction shown below yields one organic elimination product. Explain this regioselection by showing the conformation (chair) of the starting material that undergoes this E reaction; draw the product, too. with with alone (i) chair conformation favored for E reaction (ii) kinetically favored product Br Br a E D. The following transformation occur in three steps, starting with the formation of an iodonium ion intermediate and ending with deprotonation, yielding a neutral organic product. gnoring stereochemistry, draw a complete curved arrow mechanism for the formation of this product. (i) how the curved arrow mechanism for the first step (ii) Draw all products and show the curved arrow mechanism for the second step (iii) Draw all products and show the curved arrow mechanism for the third step B 10

4 ame. ( points) Page ne starting material undergoes two different transformations in each of these problems. Please draw all main organic products, clearly showing in your drawing all structural and/or stereochemical information as needed; restrict your answers to major regioisomers when regioselection is predicted, assume no rearrangement occurs, and ignore all reaction byproducts unless instructed otherwise. A. (a) Draw product(s) (b) Draw product(s) (+) α-phellandrene a flavoring Pd/ excess 1) ) Zn excess (a) Balance your reactions 1) a ) l 1) l (b) Balance your reactions l ). (a) Draw product(s) (b) Draw 8 1 product(s) Br Br heat (a) Draw product(s) 1) B (b) Draw product(s) ) /a l carene the pungent odor of turpentine

5 V. (5 points) ame Page A. upply the missing information. f any reaction yields more than one product, draw one and write "+ enantiomer" or "+ diastereomer" in the box. f you are supplying reagents and a multistep transformation is required, be sure to number your steps appropriately. equivalents of this product form 1 -MR shows signals Pd/Ba Pb Zn draw each product in the appropriate box 1 -MR shows signals. 5 l only this product is formed draw all products l 1 equivalent 1) a 1 equivalent ) D. Br + / /Pt

6 V. ( points) A. Analyze the compounds shown below. ame Page 5 ompound 1 ompound This drawing represents (fill in a number for each box) This drawing represents (fill in a number for each box) distinct molecule(s) distinct molecule(s) chiral molecule(s) When ompound 1 is treated with mildly acidic conditions, a single molecular rearrangement step results in the dehydration product, ompound. how the complete multi-step mechanism for the formation of. You should show and use the best resonance contributor for any intermediate in your mechanism. hoose your acid/conjugate base wisely. gnore stereochemistry. chiral molecule(s) ompound 1 ompound. Under these same conditions, another dehydration product is also formed, again explained by a single rearrangement step. Predict the structure of ompound 18 ompound, a structural isomer of ompound ompound 1

7 AD (trongest Acid) l l F pk a JUGATE BAE (Weakest Base) -1 l -7. l -.6 F AD l l l pk a JUGATE BAE l l l (Weakest Acid) 9 (trongest Base)

I. (32 points) Name. Page 1. (ii) its diastereomer its structural isomer its enantiomer. The product you have drawn will. H 3 CO Cl form with H 3 CO

I. (32 points) Name. Page 1. (ii) its diastereomer its structural isomer its enantiomer. The product you have drawn will. H 3 CO Cl form with H 3 CO ame. ( points) Page Each of the reactions yields a PAR of main organic products, but you should only draw one. Then answer the other questions about the starting and the products formed. Check boxes are

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