C sp2 trigonal planar trigonal planar 3

Size: px
Start display at page:

Download "C sp2 trigonal planar trigonal planar 3"

Transcription

1 I. ( points) ame Page A. Rocuronium bromide (Zemuron) is a muscle relaxant that is used in the application of anesthesia. It is used most often to facilitate endotracheal intubation because of its powerful neuromuscular blocking effect. (a) Label the indicated chiral stereocenters with the appropriate stereochemical designation. pts/label + - (b) For each of the atoms indicated with an arrow, provide the atom's most reasonable hybridization as well as its electronic (VSEPR) geometry, and its observable geometry (shape). Atom ybridization sp sp sp Electronic (VSEPR) geom. tetrahedral bs. geom (shape) sp trigonal planar trigonal planar tetrahedral trigonal planar trigonal pyramid bent bent. Each of the following transformations yields one major organic product (i.e., no mixtures of stereoisomers or regioisomers). Draw this product for each (do not worry about byproducts, focus on the product that is being synthesized). Please pay close attention to the direction of each arrow. ) /Fe ) ) S (cat.) ) S a S (cat.)

2 II. ( points) ame Page A. For each of the compounds shown below: () Identify any sources of stereochemistry by circling the site(s) and providing appropriate stereolabel(s) for each site. If no stereochemistry is present, write "E." () Then choose the statements (A-F) that can be used to describe that molecule and write the letters in the box under each molecule. If no descriptions apply, write "E" in the smaller box. E A) is a meso compound ) has at least one chiral diastereomer ) has an enantiomer D) has at least one achiral diastereomer E) has a meso stereoisomer F) would show < -MR signals. For each of the following pairs, choose all the descriptions (A-G) that apply; write the letters corresponding to those descriptions in the box with the pair of drawings. and : F D E A F and 6: G (Z) 6 A) are enantiomers ) are diastereomers ) are structural isomers D) are conformational isomers (conformers) E) are identical molecules F) contain at least one R stereocenter (in the pair) G) represent at least one achiral compound pts for the label(s) pt each if there are labels pts (no partial) for descriptions 7 7 and 8: F G and :. Translate the molecular structure to a name and the name to a molecular structure (include stereochemistry): and 0: D A F Z E F 0 (i) - pts/error, numbering is one error (ii) --chloro--methylcyclobut--ene --bromohept--yne can be drawn many ways, check stereochem

3 III. (0 points) ame Page A. The following rearrangment reaction yields an isocyanate product that is useful in organic syntheses. It begins with a proton transfer, then a rearrangement step completes the transformation. Provide the missing information in each box. (ii)the product of this first step is best shown as a set of two resonance contributors, each containing only one charged atom: draw them. (i) Provide the curved arrow mechanism second blue arrow may be replaced with two red arrows proton transfer (iii) Using the EST resonance contributor, show the curvedarrow mechanism for the formation of product set shown below. (iv) Draw the other major resonance contributors for the isocyanate product pts each for the resonance contributor points for the mechanism - pts if the wrong resonance contributor is used the right resonance contributor is better + 0 isocyanate product (v) Assuming the hybridization model for all atoms (considering all resonance contributors) provide an accurate and complete three-dimensional orbital picture for the best overall resonance contributor for the isocyanate product, using lines, dashes, wedges, and p orbitals (lone or overlapping) to show the direction of all electrons (or empty orbitals) in your drawing. All bond angles should reflect the appropriate geometry and hybridization chosen for your drawing. pts each atom (- both as ) geom must be correct/linear. The following energy diagram reveals the energy changes that occur during a specific reaction when formation of one carbocation leads to two possible rearrangements, eventually leading to structurally isomeric products. Answer the questions about the diagram. e sure to show the sign of all energy changes. Energy A (i)what step is the ratedetermining step in the to A Step or I to (reverse) transformation? D E Reaction Progress I J F G kcal/mol (ii) Which product would be favored if the reaction were run reversibly, under thermodynamic conditions? (iii) List the points that represent transition states in this diagram. (iv) Estimate the ΔG for the step with the smallest k r in the A to (forward) transformation. (v) What is the ΔG for the ratedetermining step for the complete A to G (forward) transformation?, D,, J, F +6 kcal/mol + kcal/mol

4 IV. ( points) A. Provide the missing information. (i) note the rings are different ame Page (iii) Using a ewman projection, draw the most stable conformation for the - bond; should be in front. / only this stereochemistry (ii) alone forms: with its enantiomer circle one with its diastereomer - if wrong molecule - if wrong conformer When Molecule is treated with a bulky base, a bimolecular elimination process yields alkene product(s). Draw all products expected to form. (iv) DU E. The following addition reaction yields a variety of structurally isomeric products sharing the formula 8 6. Draw the other products (,, and ), given the information provided. onnectivity alone (no stereochemistry) should be considered in your drawings. after a single rearrangement (i) without rearrangement (ii) -MR: 8 signals (iii) -MR: 6 signals stereoisomeric mix stereoisomeric mix single achiral molecule S (cat.) only this stereochem 6 (iv) Draw the most straightforward curved arrow mechanism for the formation of 6 from, using and + as needed. This transformation requires two rearrangement steps. Ignore stereochemistry. pts per step (all arrows must be correct) pts per intermediate (charges, too) Grading stops with first illogical step 6 8

5 V. ( points) ame Page A. Molecule undergoes bimolecular elimination to yield a single alkene product. Provide a drawing for the conformation of that undergoes this elimination. As always, be sure to show both axial and equatorial positions for all substituted ring atoms. Draw bond angles carefully, and show connectivity and stereochemistry clearly. (i) hair conformation that undergoes E (ii) alkene product - pts per error (bond angles, missing, etc.) points if correct chair (connectivity + stereochem) then points for the right conformation 6 The results of the above reaction might change if Molecule is used as the starting material instead of Molecule. Answer the questions to show if (and how) anything might change. (iii) Molecule and Molecule are: circle one enantiomers diastereomers structural isomers unrelated compounds (iv) Molecule will yield circle one a larger a smaller the same (v) Molecule will react circle one more slowly than faster than at the same rate as number of E products as Molecule Molecule. Each of the following reactions yields two major products that share the same molecular formula. Draw these products, showing all stereochemistry (if any) clearly, and define their relationship. no credit if drawings are incorrect (i) ) 9- ) /a s may be drawn in and are: (circle one) enantiomers diastereomers structural isomers (ii) 6 no credit if drawings are incorrect and 6 are: (circle one) (excess) Pd/ enantiomers diastereomers structural isomers 6 6

6 VI. (0 points) A. Draw a circle around the compounds which are aromatic or contain at least one aromatic ring. ame Page 6 no partial. The Pictet-Spengler Reaction involves an interesting twist on EAS reactions. When the starting material is placed in an acidic environment, a proton transfer generates the strong electrophile required for EAS. Provide the most straightforward three-step curved arrow mechanism that leads to the product shown; the acid used to generate the electrophile is regenerated. You may use - and - for any proton transfer step. R mechanistic arrows should reflect the contributor drawn R must pick the right for complexation intermediate pts pts per step (all curved arrows) pts per intermediate +. omplete the following by providing the missing information. If any product forms as a stereoisomeric mixture, please draw one structure showing stereochemistry clearly and write "+ enantiomer" or "+ diastereomer" in the box. When providing reagents, be sure to number steps and draw all appropriately. (i) equivalents ) a/ or Pd/aS Pb ) ) Zn no partial for reagents - if missing numbers R Mn ) Pd/aS Pb ) ) ) /a/ - for adding + enantiomer or + diastereomer when not needed or both dashed - for + enantiomer + enantiomer no partial for reagents - if missing numbers - for + enantiomer S or Al or Fe, etc ) / S (cat.) ) Fe

2 h; 240 points please print clearly Dr. Kathleen Nolta Signature UM ID # Problem Points Score GSI I 42 II 44 III 40 IV 43 V 31 VI 40 Total 240

2 h; 240 points please print clearly Dr. Kathleen Nolta Signature UM ID # Problem Points Score GSI I 42 II 44 III 40 IV 43 V 31 VI 40 Total 240 hemistry 10 First ame Final Examination Last ame h; 0 points please print clearly Dr. Kathleen olta ignature UM ID # PRIT TE FIRT LETTER F YUR LAT AME ERE: Problem Points core GI I II III 0 IV V 1 VI 0

More information

I. (42 points) (a) Label the indicated sites (circles and oval box) with the appropriate stereochemical designation.

I. (42 points) (a) Label the indicated sites (circles and oval box) with the appropriate stereochemical designation. I. ( points) ame Page A. etamethasone is a powerful anti-inflammatory drug that comes with unfortunate immunosupressive properties. It is often prescribed as a topical cream that can be used to alleviate

More information

O N N. electrons in ring

O N N. electrons in ring ame I. ( points) Page 1 A. The compound shown below is a commonly prescribed antifungal drug. It belongs to a category of compounds known as triazoles. Analyze the geometry and other properties for various

More information

HO HO. 1) BH 3 HCl. + enantiomer either one may be drawn 4. + enantiomer either one may be drawn 4 1) O 3

HO HO. 1) BH 3 HCl. + enantiomer either one may be drawn 4. + enantiomer either one may be drawn 4 1) O 3 . (0 points) Page 1 A. Reaction analysis: provide the requested information in each of the following chemical transformations. how all missing starting materials and products unless otherwise indicated,

More information

"Pip tazo" is a nickname given to a popular combination of antibiotics prescribed for a variety of infections. A.

Pip tazo is a nickname given to a popular combination of antibiotics prescribed for a variety of infections. A. ame I. ( points) Page 1 "Pip tazo" is a nickname given to a popular combination of antibiotics prescribed for a variety of infections. A. piperacillin tazobactam (a) ircle all the tetrahedral (chiral)

More information

"Pip tazo" is a nickname given to a popular combination of antibiotics prescribed for a variety of infections. A.

Pip tazo is a nickname given to a popular combination of antibiotics prescribed for a variety of infections. A. ame I. (6 points) Page 1 "Pip tazo" is a nickname given to a popular combination of antibiotics prescribed for a variety of infections. (a) ircle all the tetrahedral (chiral) stereocenters in both piperacillin

More information

stereoselection view Product 1 with its enantiomer

stereoselection view Product 1 with its enantiomer . ( points) A. Complete the following reactions as directed. (a) Cl C1 C i) major product DBU C C C C C Page 1 ii) Draw a ewman Projection for the conformation of the C1-C bond indicated that specifically

More information

2.0 h; 240 points please print clearly Dr. Kathleen Nolta Signature. Problem Points Score GSI I 42 II 35 III 36 IV 46 V 42 VI 39 Total 240

2.0 h; 240 points please print clearly Dr. Kathleen Nolta Signature. Problem Points Score GSI I 42 II 35 III 36 IV 46 V 42 VI 39 Total 240 hemistry 10 irst ame inal Examination Last ame.0 h; 0 points please print clearly Dr. Kathleen olta ignature UM ID # Problem Points core GI I II 5 III IV V VI 9 Total 0 Precision in drawing counts. heck

More information

2 h; 240 points Signature UM ID # Problem Points Score GSI I 42 II 45 III 35 IV 46 V 36 VI 36 Total 240

2 h; 240 points Signature UM ID # Problem Points Score GSI I 42 II 45 III 35 IV 46 V 36 VI 36 Total 240 hemistry 10 First ame Final Examination Last ame June 5, 01 please print clearly h; 0 points Signature UM ID # PRIT TE FIRST LETTER F YUR LAST AME ERE: Problem Points Score GSI I II 5 III 5 IV V VI Total

More information

If Compound 2 (below) was used in the above reaction, how might things change? Name Page 1. I. (23 points)

If Compound 2 (below) was used in the above reaction, how might things change? Name Page 1. I. (23 points) I. (2 points) ame Page itrogen atoms in amines can undergo substitution reactions repeatedly under mildly basic conditions. Provide the structure of the starting amine and supply the missing reagent(s).

More information

diene. If stereoisomeric mixtures form, indicate by drawing one and writing "+ enantiomer" and/or "+ diastereomer" in the box.

diene. If stereoisomeric mixtures form, indicate by drawing one and writing + enantiomer and/or + diastereomer in the box. I. (9 points) Page A. Consider how varying the conditions of a reaction can vastly influence the rate of a reaction as well as the product(s) formed. First draw the product(s) that form in the reference

More information

I. (32 points) Name. Page 1. (ii) its diastereomer its structural isomer its enantiomer. The product you have drawn will. H 3 CO Cl form with H 3 CO

I. (32 points) Name. Page 1. (ii) its diastereomer its structural isomer its enantiomer. The product you have drawn will. H 3 CO Cl form with H 3 CO ame. ( points) Page Each of the reactions yields a PAR of main organic products, but you should only draw one. Then answer the other questions about the starting and the products formed. Check boxes are

More information

180 C 2 -C 3 bond rotation

180 C 2 -C 3 bond rotation I. ( points) Valnoctamides have been used as sedatives and inducers for hypnosis for decades. The most biologically active molecule from this class of compounds is shown. Using ewman projections, analyze

More information

For each of the pairs shown below, choose the statements that can be used to describe the drawings and their relationship, if a relationship exists.

For each of the pairs shown below, choose the statements that can be used to describe the drawings and their relationship, if a relationship exists. I. ( points) ame Page or each of the pairs shown below, choose the statements that can be used to describe the drawings and their relationship, if a relationship exists. (a) (b) and : "heck" any/all descriptions

More information

Problem Points Score GSI I 30 II 21 III 28 IV 30 V 31 Total 140

Problem Points Score GSI I 30 II 21 III 28 IV 30 V 31 Total 140 hemistry 0 First ame Third Examination Last ame.5 h; 0 points please print clearly Dr. Kathleen olta ignature UM ID # PRIT TE FIRT LETTER F YUR LAT AME ERE: Problem Points core GI I 0 II III 8 IV 0 V Total

More information

For each of the pairs shown below, choose the statements that can be used to describe the drawings and their relationship, if a relationship exists.

For each of the pairs shown below, choose the statements that can be used to describe the drawings and their relationship, if a relationship exists. I. ( points) ame Page or each of the pairs shown below, choose the statements that can be used to describe the drawings and their relationship, if a relationship exists. (a) (b) and : "Check" any/all descriptions

More information

1.5 h; 120 points please print clearly Dr. Kathleen Nolta Signature. Problem Points Score GSI I 20 II 27 III 25 IV 22 V 26 Total 120

1.5 h; 120 points please print clearly Dr. Kathleen Nolta Signature. Problem Points Score GSI I 20 II 27 III 25 IV 22 V 26 Total 120 hemistry 0 First ame econd Examination Last ame. h; 0 points please print clearly Dr. Kathleen olta ignature UM ID # PRIT TE FIRT LETTER F YUR LAT AME ERE: Problem Points core GI I 0 II 7 III IV V Total

More information

"Check" all descriptions that apply. is a meso compound has at least one chiral diastereomer has an enantiomer has at least one achiral diastereomer

Check all descriptions that apply. is a meso compound has at least one chiral diastereomer has an enantiomer has at least one achiral diastereomer I. ( points) ame Page For each of the compounds shown below: () Identify any sources of stereochemistry by circling the site(s) and providing appropriate stereolabel(s) for each site. If no stereochemistry

More information

1.5 h; 120 points please print clearly Dr. Kathleen Nolta Dr. Jordan Walk. Problem Points Score GSI I 23 II 27 III 24 IV 22 V 24 Total 120

1.5 h; 120 points please print clearly Dr. Kathleen Nolta Dr. Jordan Walk. Problem Points Score GSI I 23 II 27 III 24 IV 22 V 24 Total 120 hemistry 10 econd Examination First ame Last ame 1.5 h; 10 points please print clearly Dr. Kathleen olta Dr. Jordan Walk ignature UM ID # PRIT TE FIRT LETTER F YUR LAT AME ERE: Problem Points core GI I

More information

Problem Points Score GSI I 22 II 26 III 28 IV 19 V 25 Total 120

Problem Points Score GSI I 22 II 26 III 28 IV 19 V 25 Total 120 hemistry 0 First ame econd Examination Last ame.5 h; 0 points please print clearly Dr. Kathleen olta ignature UM ID # PRIT TE FIRT LETTER F YUR LAT AME ERE: Problem Points core GI I II 6 III 8 IV 9 V 5

More information

Learning Guide for Chapter 17 - Dienes

Learning Guide for Chapter 17 - Dienes Learning Guide for Chapter 17 - Dienes I. Isolated, conjugated, and cumulated dienes II. Reactions involving allylic cations or radicals III. Diels-Alder Reactions IV. Aromaticity I. Isolated, Conjugated,

More information

1.5 h; 140 points please print clearly Dr. Ginger Shultz Dr. Kathleen Nolta. Problem Points Score GSI I 32 II 27 III 32 IV 25 V 24 Total 140

1.5 h; 140 points please print clearly Dr. Ginger Shultz Dr. Kathleen Nolta. Problem Points Score GSI I 32 II 27 III 32 IV 25 V 24 Total 140 hemistry 10 Third Examination First ame Last ame 1.5 h; 10 points please print clearly Dr. Ginger hultz Dr. Kathleen olta ignature UM D # PRT TE FRT LETTER F YUR LAT AME ERE: Problem Points core G 7 V

More information

HO 1:1 1:1. Amines, like cathine, are often excellent nucleophiles Provide the requested information for the following one-step reaction scheme.

HO 1:1 1:1. Amines, like cathine, are often excellent nucleophiles Provide the requested information for the following one-step reaction scheme. I. (4 points) A. athine (shown at right) is a psychoactive amphetamine drug obtained from the plant atha edulis (also known as khat). View down the 1 - bond indicated ( 1 being the front atom), and answer

More information

KEY Page 1. Name H H H 3 C C 3. Cl CH. AlCl 3 H H. + enantiomer H 3 C CH 3. Cl CH3 HNO 3. AlCl NO 2 CH 3 1) O 3 2) H 2 O 2 OH H 3 C C.

KEY Page 1. Name H H H 3 C C 3. Cl CH. AlCl 3 H H. + enantiomer H 3 C CH 3. Cl CH3 HNO 3. AlCl NO 2 CH 3 1) O 3 2) H 2 O 2 OH H 3 C C. ame Page 1 I. (8 points) omplete the following reactions as directed. Transformations requiring sequential experimental steps should be numbered appropriately. Show the major organic product(s) unless

More information

1.5 h; 120 points Signature. Problem Points Score GSI I 23 II 30 III 23 IV 24 V 20 Total 120

1.5 h; 120 points Signature. Problem Points Score GSI I 23 II 30 III 23 IV 24 V 20 Total 120 hemistry 0 econd Examination June, 0 First ame Last ame please print clearly.5 h; 0 points ignature For fastest return, if you are in lab this term. LAB GI: UM ID # PRIT TE FIRT LETTER F YUR LAT AME ERE:

More information

KEY I. (28 points) i) NOTE: sp-hybridized carbanions make good nucleophiles for substitution reactions. Product A C C CH 3. Product B.

KEY I. (28 points) i) NOTE: sp-hybridized carbanions make good nucleophiles for substitution reactions. Product A C C CH 3. Product B. I. (8 points) Page 1 A. omplete the following as necessary NT: sp-hybridized carbanions make good nucleophiles for substitution reactions NaN N Na Na (optional) i equivalents of Product A Product B a)

More information

Note: You must have your answers written in pen if you want a regrade!!!!

Note: You must have your answers written in pen if you want a regrade!!!! NAME (Print): SIGNATURE: hemistry 310M/318M Dr. Brent Iverson 2nd Midterm November 1, 2007 Please print the first three letters of your last name in the three boxes Please Note: This test may be a bit

More information

CHEMpossible. 261 Exam 1 Review

CHEMpossible. 261 Exam 1 Review CHEMpossible 261 Exam 1 Review A. Rank the following carboxylic acids from least acidic to most acidic: B. Draw the line-angle formulas for three acylic (non-cyclic) esters with the molecular formula C

More information

Nuggets of Knowledge for Chapter 17 Dienes and Aromaticity Chem 2320

Nuggets of Knowledge for Chapter 17 Dienes and Aromaticity Chem 2320 Nuggets of Knowledge for Chapter 17 Dienes and Aromaticity Chem 2320 I. Isolated, cumulated, and conjugated dienes A diene is any compound with two or C=C's is a diene. Compounds containing more than two

More information

2. 2D Lewis structure (large structure with possible formal charge) 20

2. 2D Lewis structure (large structure with possible formal charge) 20 hem 201 Final Fall, 2017 Beauchamp ame Problems Points redit 1. Functional Group omenclature (1 large structure) 30 2. 2D Lewis structure (large structure with possible formal charge) 20 3. yclohexane

More information

Note: You must have your answers written in pen if you want a regrade!!!!

Note: You must have your answers written in pen if you want a regrade!!!! NAME (Print): SIGNATURE: hemistry 310M/318M Dr. ent Iverson 2nd Midterm November 1, 2007 Please print the first three letters of your last name in the three boxes Please Note: This test may be a bit long,

More information

CHEMISTRY 112A FALL 2015 EXAM 1 SEPTEMBER 27, 2016 NAME- WRITE BIG STUDENT ID: SECTION AND/OR GSI IF YOU ARE IN THE LABORATORY COURSE:

CHEMISTRY 112A FALL 2015 EXAM 1 SEPTEMBER 27, 2016 NAME- WRITE BIG STUDENT ID: SECTION AND/OR GSI IF YOU ARE IN THE LABORATORY COURSE: CHEMISTRY 112A FALL 2015 EXAM 1 SEPTEMBER 27, 2016 NAME- WRITE BIG STUDENT ID: SECTIN AND/R GSI IF YU ARE IN THE LABRATRY CURSE: You will have 75 minutes in which to work. BE NEAT! Non-legible structure

More information

CHE 321 Summer 2010 Exam 2 Form Choose the structure(s) that represent cis-1-sec-butyl-4-methylcyclohexane. I II III

CHE 321 Summer 2010 Exam 2 Form Choose the structure(s) that represent cis-1-sec-butyl-4-methylcyclohexane. I II III CE 321 Summer 2010 Exam 2 orm 2 Multiple Choice Questions: 60 points 1. Choose the structure(s) that represent cis-1-sec-butyl-4-methylcyclohexane. I II III (A) I only (B) II only (C) I and II only II

More information

Midterm #1 Chem 3A - Fall 2013 Sept. 7, :00 8:30 pm. Name SID

Midterm #1 Chem 3A - Fall 2013 Sept. 7, :00 8:30 pm. Name SID Midterm #1 Chem 3A - Fall 2013 Sept. 7, 2013 7:00 8:30 pm ame SID Including the title page, there should be 5 total questions spread over 7 pages (printed on both sides). The back of the last page may

More information

More Tutorial at

More Tutorial at 1. MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question (50 pts). 1) Which of the following statements about propene, CH3CH CH2, is 1) correct? A) There

More information

1. What are the respective hybridizations of the atoms numbered 1 to 4 in this compound?

1. What are the respective hybridizations of the atoms numbered 1 to 4 in this compound? EM 331: hapter 1/2: Structures (Atoms, Molecules, Bonding) 1. What are the respective hybridizations of the atoms numbered 1 to 4 in this compound? N 2 N 2 N 1 2 3 4 2. What hybrid orbitals are used to

More information

Chem 3719 Example Exams. Chemistry 3719 Practice Exams

Chem 3719 Example Exams. Chemistry 3719 Practice Exams Chem 3719 Example Exams Chemistry 3719 Practice Exams Fall 2018 Chemistry 3719, Fall 2017 Exam 1 Student Name: Y Number: This exam is worth 100 points out of a total of 700 points for Chemistry 3719/3719L.

More information

Note: You must have your answers written in pen if you want a regrade!!!!

Note: You must have your answers written in pen if you want a regrade!!!! NAME (Print): SIGNATURE: hemistry 310M/318M Dr. ent Iverson 2nd Midterm ctober 29, 2009 Please print the first three letters of your last name in the three boxes Please Note: This test may be a bit long,

More information

Chem 112A: Final Exam

Chem 112A: Final Exam Chem 112A: Final Exam December 15th, 2010 Please provide all answers in the spaces provided. You are not allowed to use a calculator for this exam, but you may use molecular model kits. nly cyclohexane

More information

13. Free Radical Chemistry

13. Free Radical Chemistry hem 201 Study Session Final Beauchamp ame Problems Points redit 1. Functional Group omenclature (1 large structure) 2. Various possibilities: Types of Isomers, Degrees of Unsaturation, common nomenclature,

More information

CHEMISTRY 31 Name: KEY Exam #1 100 pts 1. (6 pts) Provide the complete IUPAC name for each of the following compounds:

CHEMISTRY 31 Name: KEY Exam #1 100 pts 1. (6 pts) Provide the complete IUPAC name for each of the following compounds: CEMISTRY 31 ame: KEY Exam #1 100 pts 1. (6 pts) Provide the complete IUPAC name for each of the following compounds: (1S,3S)-1-bromo-3-butylcyclopentane 3,4-diethyl-2,2-dimethyloctane 1-cyclopropyl-2-methylcyclobutane

More information

California State Polytechnic University, Pomona Nomenclature (one structure) 25

California State Polytechnic University, Pomona Nomenclature (one structure) 25 alifornia State Polytechnic University, Pomona 1 hem 314 Final Exam Spring, 2005 Beauchamp ame Problem Points redit 1. omenclature (one structure) 25 2. 2D Lewis structure (large structure with 20 possible

More information

Chem 201 Final. Beauchamp

Chem 201 Final. Beauchamp hem 201 Final Winter, 2018 Beauchamp ame KEY Problems Points redit 1. Functional Group omenclature (1 large structure) 0 2. Lewis tructures, esonance, Formal harge 18. yclohexane onformations, 2 substituents,

More information

CHEM J-10 June The structure of ( )-linalool, a commonly occurring natural product, is shown below.

CHEM J-10 June The structure of ( )-linalool, a commonly occurring natural product, is shown below. CEM1102 2014-J-10 June 2014 The structure of ( )-linalool, a commonly occurring natural product, is shown below. 4 What is the molecular formula of ( )-linalool? C 10 18 O Which of the following best describes

More information

NAME (Print): Chemistry 610A/618A Dr. Brent Iverson 2nd Exam Oct. 29, 2003 SIGNATURE:

NAME (Print): Chemistry 610A/618A Dr. Brent Iverson 2nd Exam Oct. 29, 2003 SIGNATURE: NAME (Print): SIGNATURE: hemistry 610A/618A Dr. ent Iverson 2nd Exam ct. 29, 2003 Please Note: This test may be a bit long, but there is a reason. I would like to give you a lot of little questions, so

More information

1. (6 points) Provide IUPAC accepted names for the following compounds. 2. (6 points) Provide a structure for the following compounds.

1. (6 points) Provide IUPAC accepted names for the following compounds. 2. (6 points) Provide a structure for the following compounds. Chem52 omework Set 1 This homework set is similar to a Chem 51 final exam. Please provide answers in the spaces provided or, preferably, on attached sheets. Point values are listed only to give you the

More information

CHEM1902/ N-9 November 2014

CHEM1902/ N-9 November 2014 CEM1902/4 2014-N-9 November 2014 The elimination of 2 O from alcohol A can form the isomeric alkenes B and C. Elimination of Br from the alkyl halide D can generate the same two alkenes. 7 Assign the absolute

More information

Chem 201 Sample Midterm Beauchamp

Chem 201 Sample Midterm Beauchamp hem 201 Sample Midterm Beauchamp Exams are designed so that no one question will make or break you. The best strategy is to work steadily, starting with those problems you understand best. Partial credit

More information

Chem 112A: Final Exam

Chem 112A: Final Exam Chem 112A: Final Exam December 14th, 2011 Please provide all answers in the spaces provided. You are not allowed to use a calculator for this exam, but you may use molecular model kits. nly cyclohexane

More information

CHEM 240: Survey of Organic Chemistry at North Dakota State University Midterm Exam 02 - Tue, 23 Sep 2014!! Name:! KEY!

CHEM 240: Survey of Organic Chemistry at North Dakota State University Midterm Exam 02 - Tue, 23 Sep 2014!! Name:! KEY! CEM 240: Survey of rganic Chemistry at orth Dakota State University Midterm Exam 02 - Tue, 23 Sep 2014!! ame:! KEY! Please read through each question carefully and answer in the spaces provided. A good

More information

(a) Draw a circle around the longest C-C bond(s) in serotonin. sp 2. sp 3

(a) Draw a circle around the longest C-C bond(s) in serotonin. sp 2. sp 3 I. ( points) ame Page A. Serotonin is an important neurotransmitter that is thought to play an essential role in the regulation of moods, despite being concentrated in the enterochromaffin cells in the

More information

Basic Organic Chemistry Course code : CHEM (Pre-requisites : CHEM 11122)

Basic Organic Chemistry Course code : CHEM (Pre-requisites : CHEM 11122) Basic Organic Chemistry Course code : CHEM 12162 (Pre-requisites : CHEM 11122) Chapter 01 Mechanistic Aspects of S N2,S N1, E 2 & E 1 Reactions Dr. Dinesh R. Pandithavidana Office: B1 222/3 Phone: (+94)777-745-720

More information

Midterm #2 Chem 3A - Fall 2013 Nov. 12, :00 8:45 pm. Name SID

Midterm #2 Chem 3A - Fall 2013 Nov. 12, :00 8:45 pm. Name SID Midterm #2 Chem 3A - Fall 2013 Nov. 12, 2013 7:00 8:45 pm Name SID Including the title page, there should be 6 total questions spread over 8 pages (printed on both sides). Please provide all answers in

More information

1. Use appropriate curved arrows to indicate the complete mechanism of each of these reactions. KH (1 equiv.) + KCl THF. + HBr.

1. Use appropriate curved arrows to indicate the complete mechanism of each of these reactions. KH (1 equiv.) + KCl THF. + HBr. 1. Use appropriate curved arrows to indicate the complete mechanism of each of these reactions. K (1 equiv.) TF K 3 2 2 3 enantiomer While writing the mechanism, justify both the regiochemistry the relative

More information

5. Stereochemical Analysis. 7. Dipole Moments and Inductive versus Resonance Effects. 8. Types of isomers from a given formula. 9. Physical Properties

5. Stereochemical Analysis. 7. Dipole Moments and Inductive versus Resonance Effects. 8. Types of isomers from a given formula. 9. Physical Properties hem 201 Sample Midterm Beauchamp ame Problems Points redit 1. Functional Group omenclature (1 large structure) 2. Lewis Structures, Resonance, Formal harge 3. yclohexane onformations, 2 substituents, ewman

More information

OChem1 Old Exams. Chemistry 3719 Practice Exams

OChem1 Old Exams. Chemistry 3719 Practice Exams OChem1 Old Exams Chemistry 3719 Practice Exams Fall 2017 Chemistry 3719 Practice Exam A1 This exam is worth 100 points out of a total of 600 points for Chemistry 3719/3719L. You have 50 minutes to complete

More information

FALL 2018 CEM 251: Organic Chemistry I Sections September 25, 2018

FALL 2018 CEM 251: Organic Chemistry I Sections September 25, 2018 FALL 2018 CEM 251: Organic Chemistry Sections 25-36 TUE-TU 8:00 9:20 AM September 25, 2018 Name: Section: PD: TA: This is a closed book and note examination. f boxes are provided for your answers, only

More information

1. The barrier to rotation around the C-C bonds for 2-methylpropane and 2,2-dimethylpropane are shown below.

1. The barrier to rotation around the C-C bonds for 2-methylpropane and 2,2-dimethylpropane are shown below. 1. The barrier to rotation around the C-C bonds for 2-methylpropane and 2,2-dimethylpropane are shown below. E Rot = 14.2 kj/mol E Rot = 19.6 kj/mol a. Why does the potential energy of a molecule increase

More information

FALL 2018 CEM 251: Organic Chemistry I Sections September 25, 2018

FALL 2018 CEM 251: Organic Chemistry I Sections September 25, 2018 ALL 2018 CEM 251: rganic Chemistry Sections 25-36 TUE-TU 8:00 9:20 AM September 25, 2018 Name: Section: PD: TA: This is a closed book and note examination. f boxes are provided for your answers, only what

More information

1. Make two superimposable models of bromochloroiodomethane. Position your models on your desk to prove that they are superimposable.

1. Make two superimposable models of bromochloroiodomethane. Position your models on your desk to prove that they are superimposable. HM 204 Organic hemistry Introduction to Stereochemistry Recall that two models are identical if they can be superimposed without breaking bonds. Recall that conformations (conformers) are structures that

More information

Enantiomers. nonsuperimposable mirror image Both Configuration will be opposite. Both Configuration will be opposite

Enantiomers. nonsuperimposable mirror image Both Configuration will be opposite. Both Configuration will be opposite Optical Isomerism Isomerism of Organic Molecules: Two chiral centers Many organic compounds have more than one asymmetric carbon. The more asymmetric carbons a compound has, the more number of stereoisomers

More information

CHEMISTRY 112A FALL 2014 FINAL EXAM DECEMBER 17, 2014 NAME- WRITE BIG STUDENT ID: SECTION AND/OR GSI IF YOU ARE IN THE LABORATORY COURSE:

CHEMISTRY 112A FALL 2014 FINAL EXAM DECEMBER 17, 2014 NAME- WRITE BIG STUDENT ID: SECTION AND/OR GSI IF YOU ARE IN THE LABORATORY COURSE: CEMISTRY 112A FALL 2014 FINAL EXAM DECEMBER 17, 2014 NAME- WRITE BIG STUDENT ID: SECTIN AND/R GSI IF YU ARE IN TE LABRATRY CURSE: You will have 2 hours 50 minutes in which to work. BE NEAT! Non-legible

More information

sp 2 sp 2 trigonal planar bent 2

sp 2 sp 2 trigonal planar bent 2 I. ( points) ame Page 1 Methylenedioxypyrovalerone (MDPV) is one terribly dangerous ingredient in the recreational drugs better known as "bath salts." This psychoactive drug acts as a stimulant with dangerous,

More information

ATOM O1 ATOM N2 ATOM O2 ATOM N1 ATOM N2 ATOM C

ATOM O1 ATOM N2 ATOM O2 ATOM N1 ATOM N2 ATOM C I. (8 points) ame Page 1 AMPA, shown below, is a synthetic compound that mimics the effects of the neurotransmitter glutamate. When evaluating the structure of this compound, please remember to take into

More information

Name: CHEM 633/634 Problem Set 1: Review Due Tues, Aug 29, 2017 (First Lecture!)

Name: CHEM 633/634 Problem Set 1: Review Due Tues, Aug 29, 2017 (First Lecture!) ame: CEM 633/634 Problem Set 1: Review Due Tues, Aug 29, 2017 (First Lecture!) Please print this problem set. Answers must be in the spaces or boxes provided to receive full credit. You may work in groups,

More information

Problems Points Credit

Problems Points Credit hem 201 Final Fall, 2012 Beauchamp Name Problems Points redit 1. Functional Group Nomenclature (1 large structure) (R/S and E/Z too) 30 2. Types of Isomers, Degrees of Unsaturation 25 3. yclohexane onformations,

More information

CHEM 261 HOME WORK Lecture Topics: MODULE 1: The Basics: Bonding and Molecular Structure Text Sections (N0 1.9, 9-11) Homework: Chapter 1:

CHEM 261 HOME WORK Lecture Topics: MODULE 1: The Basics: Bonding and Molecular Structure Text Sections (N0 1.9, 9-11) Homework: Chapter 1: CHEM 261 HOME WORK Lecture Topics: MODULE 1: The Basics: Bonding and Molecular Structure Atomic Structure - Valence Electrons Chemical Bonds: The Octet Rule - Ionic bond - Covalent bond How to write Lewis

More information

2311A and B Practice Problems to help Prepare for Final from Previous Marder Exams.

2311A and B Practice Problems to help Prepare for Final from Previous Marder Exams. 2311A and B Practice Problems to help Prepare for Final from Previous Marder Exams. Disclaimer.: Use only to help learn what you need to know and don t expect the final to be in the same form. 1 1. Short

More information

Midterm Exam 1. Chem 3B, Fall 2016 Thursday, September 29, :00 9:00 pm. Name. Student ID

Midterm Exam 1. Chem 3B, Fall 2016 Thursday, September 29, :00 9:00 pm. Name. Student ID Midterm Exam 1 Chem 3B, Fall 2016 Thursday, September 29, 2016 7:00 9:00 pm ame Student ID You have 120 minutes to complete this exam. Please provide all answers in the space provided. Work drawn in the

More information

1. What are the respective hybridizations of the atoms numbered 1 to 4 in this compound?

1. What are the respective hybridizations of the atoms numbered 1 to 4 in this compound? CEM 331: Chapter 1/2: Structures (Atoms, Molecules, Bonding) 1. What are the respective hybridizations of the atoms numbered 1 to 4 in this compound? N C 2 C N C 2 C N 1 2 3 4 1: three sigma bonds and

More information

10:30 AM 1:00 PM December 13, 2016 in MATH 100

10:30 AM 1:00 PM December 13, 2016 in MATH 100 CEM 3311 ARRIGT Exam 4 KEY 10:30 AM 1:00 PM December 13, 016 in MAT 100 Instructions. o notes, books, laptops, phones, calculators, models, or stencils are allowed. Periodic Table, Electronegativity Chart,

More information

Cl 7 8 N 9 H 6 HS 4. 2-(5,5-dimethyl-3-chlorocyclopent-2-enyl)-5-oxo-6-methyl-7-cyanoheptyl 2-hydroxy-3,3-dimethyl-4-(1-mercapto-

Cl 7 8 N 9 H 6 HS 4. 2-(5,5-dimethyl-3-chlorocyclopent-2-enyl)-5-oxo-6-methyl-7-cyanoheptyl 2-hydroxy-3,3-dimethyl-4-(1-mercapto- hem 0 Sample Midterm Beauchamp Exams are designed so that no one question will make or break you. The best strategy is to work steadily, starting with those problems you understand best. Partial credit

More information

Chem ORGANIC CHEMISTRY I

Chem ORGANIC CHEMISTRY I ORGANIC CHEMISTRY I CHEM 221 /2 01 Final Examination December 20, 2005 1400-1700 Dr. Cerrie ROGERS x x molecular model kits (without instructions) programmable calculators must be reset Chem 221 --- ORGANIC

More information

Exam Analysis: Organic Chemistry, Midterm 1

Exam Analysis: Organic Chemistry, Midterm 1 Exam Analysis: Organic Chemistry, Midterm 1 1) TEST BREAK DOWN: There are three independent topics covered in the first midterm, which are hybridization, structure and isomerism, and resonance. The test

More information

Columbia University C99ORG14.DOC S3443D Summer 99 Professor Grace B. Borowitz Exam No. 4 - Final July 1, 1999

Columbia University C99ORG14.DOC S3443D Summer 99 Professor Grace B. Borowitz Exam No. 4 - Final July 1, 1999 olumbia University 99RG14.D S44D Summer 99 Professor Grace B. Borowitz Exam No. 4 - Final July 1, 1999 Name: Aroma T. ity and Al Lylic Grade: Please use a non-red pen. Answer questions in the provided

More information

STEREOCHEMISTRY A STUDENT SHOULD BE ABLE TO:

STEREOCHEMISTRY A STUDENT SHOULD BE ABLE TO: A STUDENT SHOULD BE ABLE TO: STEREOCHEMISTRY 1. Determine the relationship between two given structures (which may be any of the kinds below). Also, define the following terms, and give examples of pairs

More information

You must have your answers written in PERMANENT ink if you want a regrade!!!! This means no test written in pencil or ERASABLE INK will be regraded.

You must have your answers written in PERMANENT ink if you want a regrade!!!! This means no test written in pencil or ERASABLE INK will be regraded. AME (Print): IGATURE: hemistry 320M/328M Dr. Brent Iverson 2nd Midterm ctober 25, 2012 Please print the first three letters of your last name in the three boxes Please ote: This test may be a bit long,

More information

Chemistry 201. MW 12:00pm 1:15pm Examination #2 August 15 th Bronco ID. Question Score Possible Points. 1 (12pts) 2 (24pts) 3 (25pts)

Chemistry 201. MW 12:00pm 1:15pm Examination #2 August 15 th Bronco ID. Question Score Possible Points. 1 (12pts) 2 (24pts) 3 (25pts) Chemistry 201 MW 12:00pm 1:15pm Examination #2 August 15 th 2016 Name Bronco ID. Question Score Possible Points 1 (12pts) 2 (24pts) 3 (25pts) 4... (12pts) 5 (27pts). Total (100pts) 1. Read each question

More information

CHEMISTRY 341. Final Exam Tuesday, December 16, Problem 1 15 pts Problem 9 8 pts. Problem 2 5 pts Problem pts

CHEMISTRY 341. Final Exam Tuesday, December 16, Problem 1 15 pts Problem 9 8 pts. Problem 2 5 pts Problem pts CEMISTRY 341 Final Exam Tuesday, December 16, 1997 Name NAID Problem 1 15 pts Problem 9 8 pts Problem 2 5 pts Problem 10 21 pts Problem 3 26 pts Problem 11 15 pts Problem 4 10 pts Problem 12 6 pts Problem

More information

UCF - ORGANIC CHEMISTRY 1 - PROF. DAOUDI UCF PROF. DAOUDI EXAM 3 REVIEW.

UCF - ORGANIC CHEMISTRY 1 - PROF. DAOUDI UCF PROF. DAOUDI EXAM 3 REVIEW. UCF PROF. DAOUDI EXAM 3 REVIEW www.clutchprep.com 1 PRACTICE: Identify the most stable and the least stable alkene PRACTICE: Create the full arrow pushing mechanism which shows all intermediates and all

More information

Organic Chemistry I (CHE ) Examination I S ep t ember 2 9, KEY Name (PRINT LEGIBLY):

Organic Chemistry I (CHE ) Examination I S ep t ember 2 9, KEY Name (PRINT LEGIBLY): Organic hemistry I (E 2 3 0-001 ) Examination I S ep t ember 2 9, 2 0 0 4 KEY Name (PRINT LEGIBLY): Please provide clear and concise answers to all of the following questions. Use equations and/or drawings

More information

Homework Problem Set 7 Iverson CH320M/328M Due Friday, Nov. 2

Homework Problem Set 7 Iverson CH320M/328M Due Friday, Nov. 2 NAME (Print): SIGNATURE: hemistry 320M/328M Dr. Brent Iverson 7th omework October 29, 2018 Please print the first three letters of your last name in the three boxes 1 Score: 2 1. For the following reactions,

More information

Chem 232. Problem Set 9. Question 1. D. J. Wardrop

Chem 232. Problem Set 9. Question 1. D. J. Wardrop Chem 232 D. J. Wardrop wardropd@uic.edu Problem Set 9 Question 1. a. Rank in order of increasing number of chirality centers (1 = fewest chirality centers; 5 = most chirality). 3 C C 3 b. Rank in order

More information

Lecture Notes Chem 51B S. King I. Conjugation

Lecture Notes Chem 51B S. King I. Conjugation Lecture Notes Chem 51B S. King Chapter 16 Conjugation, Resonance, and Dienes I. Conjugation Conjugation occurs whenever p-orbitals can overlap on three or more adjacent atoms. Conjugated systems are more

More information

5. (6 pts) Show how the following compound can be synthesized from the indicated starting material:

5. (6 pts) Show how the following compound can be synthesized from the indicated starting material: Exam 2 Name CHEM 212 1. (36 pts) Complete the following chemical reactions showing all major organic products; illustrate proper stereochemistry where appropriate. If no reaction occurs, indicate NR :

More information

Chemistry 3A. Midterm 2. Dr. Steven Pedersen November 9, Student name: ANSWERS Student signature:

Chemistry 3A. Midterm 2. Dr. Steven Pedersen November 9, Student name: ANSWERS Student signature: r. Steven Pedersen ovember 9, 2015 Chemistry 3A Midterm 2 Student name: ASWERS Student signature: Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 (18 pts) (30 pts) (32 pts) (18 pts)

More information

Homework - Review of Chem 2310

Homework - Review of Chem 2310 omework - Review of Chem 2310 Chapter 1 - Atoms and Molecules Name 1. What is organic chemistry? 2. Why is there an entire one year course devoted to the study of organic compounds? 3. Give 4 examples

More information

Chem 342 Organic Chemistry II Final Exam 13 May 2009

Chem 342 Organic Chemistry II Final Exam 13 May 2009 hem 342 rganic hemistry II Final Exam 13 May 2009 KEY Please read through each question carefully and answer in the spaces provided. A good strategy is to go through the test and answer all the questions

More information

a. Does the model have a plane of symmetry? Yes No The central carbon is said to be a stereocenter, stereogenic center, or chiral carbon.

a. Does the model have a plane of symmetry? Yes No The central carbon is said to be a stereocenter, stereogenic center, or chiral carbon. Name: TA Name Lab Section: Day Time OPTICAL ISOMERISM 1. Construct a model that has a central carbon atom with 4 different colored spheres attached to it, representing four different atoms or groups. Draw

More information

ON THE FIRST DAY OF CHRISTMAS DR. RUSSELL GAVE TO ME, ORGANIC CHEMISTRY... Thanks to Dr R for the title!

ON THE FIRST DAY OF CHRISTMAS DR. RUSSELL GAVE TO ME, ORGANIC CHEMISTRY... Thanks to Dr R for the title! N TE FIRST DAY F RISTMAS DR. RUSSELL GAVE T ME, RGANI EMISTRY... Thanks to Dr R for the title! rganic hemistry E 310, Final Exam 150 cautiously optimistic points! December 11, 2017 Note: This exam totals

More information

Form 0 CHE321 Exam 1 9/26/2006

Form 0 CHE321 Exam 1 9/26/2006 CE321 Exam 1 9/26/2006 Multiple Choice Questions. 60 points 1. Draw the two best contributing structures for methylimidate. To get you started a partial structure is given. C C C Choose the incorrect statement.

More information

NAME (please print) MIDTERM EXAM FIRST LAST JULY 13, 2011

NAME (please print) MIDTERM EXAM FIRST LAST JULY 13, 2011 CEMISTRY 140A NAME (please print) MIDTERM EXAM IRST LAST JULY 13, 2011 SIGNATURE Vollhardt & Schore 6 th Edition Cp. 1 through 5 ID NUMBER LAST NAME PERSN SEATED IN T YUR RIGT: LAST NAME PERSN SEATED T

More information

1. (3 pts) Circle the highest priority substituent of the following list:

1. (3 pts) Circle the highest priority substituent of the following list: Ch 334 Midterm #3 November 17, 2006 Code 1. (3 pts) Circle the highest priority substituent of the following list: 2. (4 pts) Rank the following groups in order of increasing priority. Place the letter

More information

CHEMISTRY 112A FALL 2015 FINAL EXAM DECEMBER 16, 2015 NAME- WRITE BIG STUDENT ID: SECTION AND/OR GSI IF YOU ARE IN THE LABORATORY COURSE:

CHEMISTRY 112A FALL 2015 FINAL EXAM DECEMBER 16, 2015 NAME- WRITE BIG STUDENT ID: SECTION AND/OR GSI IF YOU ARE IN THE LABORATORY COURSE: CEMISTRY 112A FALL 2015 FINAL EXAM DECEMBER 16, 2015 NAME- WRITE BIG STUDENT ID: SECTIN AND/R GSI IF YU ARE IN TE LABRATRY CURSE: You will have 2 hours 45 minutes minutes in which to work. Problem Points

More information

CHEM 344 Fall 2016 Spectroscopy and WebMO Exam (75 pts)

CHEM 344 Fall 2016 Spectroscopy and WebMO Exam (75 pts) CHEM 344 Fall 2016 Spectroscopy and WebMO Exam (75 pts) Name: TA Name: Exam Length = 90 min DO NOT REMOVE ANY PAGES FROM THIS EXAM PACKET. Directions for drawing molecules, reactions, and electron-pushing

More information

California State Polytechnic University, Pomona 1

California State Polytechnic University, Pomona 1 alifornia State Polytechnic University, Pomona 1 hem 2010 Final Fall, 2018 Beauchamp ame Problems Points redit 1. Functional Group omenclature (1 large structure) 30 2. 3D structure and resonance 20 3.

More information

CEM 351 2nd EXAM/Version A Friday, October 17, :50 2:40 p.m. Room 138, Chemistry

CEM 351 2nd EXAM/Version A Friday, October 17, :50 2:40 p.m. Room 138, Chemistry Name (print) Signature Student # Section Number CEM 351 2nd EXAM/Version A Friday, October 17, 2003 1:50 2:40 p.m. Room 138, Chemistry Ann Swerkey Grade? 1.(20 2.(20. 3.(20 4.(20 5.(20 6.(20 TOTAL 100

More information

Chemistry 123: Physical and Organic Chemistry Topic 1: Organic Chemistry

Chemistry 123: Physical and Organic Chemistry Topic 1: Organic Chemistry Topic 1: Mechanisms and Curved Arrows etc Reactions of Alkenes:.Similar functional groups react the same way. Why? Winter 2009 Page 73 Topic 1: Mechanisms and Curved Arrows etc Reactivity:.Electrostatic

More information

CEM 251, Fall 2011 Sections Tuesday Thursday 6:00 7:30 pm Midterm #2 October 27, 2011

CEM 251, Fall 2011 Sections Tuesday Thursday 6:00 7:30 pm Midterm #2 October 27, 2011 CEM 251, Fall 2011 Sections 25 36 Tuesday Thursday 6:00 7:30 pm ctober 27, 2011 Name: Section: PID: TA: This is a closed book and note examination. If boxes are provided for your answers, only what is

More information

Problem Points Credit. 1. Nomenclature (one structure) 30

Problem Points Credit. 1. Nomenclature (one structure) 30 alifornia State Polytechnic University, Pomona 1 hem 2010 Midterm #2 Fall, 2018 Beauchamp ame KY (int your name legibly) oblem Points redit 1. omenclature (one structure) 30 2. xplain relative stabilities

More information