After the completion of this section the student. V.4.2. Power Series Solution. V.4.3. The Method of Frobenius. V.4.4. Taylor Series Solution
|
|
- Susan Lewis
- 5 years ago
- Views:
Transcription
1 Chapter V ODE V.4 Power Series Solutio Otober, V.4 Power Series Solutio Objetives: After the ompletio of this setio the studet - should reall the power series solutio of a liear ODE with variable oeffiiets - should reall the defiitios of ordiary ad sigular poits - should reall the Frobeius method of the power series solutio about a regular sigular poit Cotets: V.4.. Defiitios V.4.. Power Series Solutio V.4.3. The Method of Frobeius V.4.4. Taylor Series Solutio V.4.5. Power Series Solutio with Maple V.4.6. Review Questios ad Eerises
2 386 Chapter V ODE V.4 Power Series Solutio Otober, POWER SERIES SOLUTION V.4.. DEFINITIONS I the previous setio we studied how to solve a liear ODE with ostat oeffiiets, ad we disovered that for them we always a fid liearly idepedet solutios (fudametal set). For oe speial form of a liear ODE with variable oeffiiets, amely the Euler-Cauhy equatio, we a fid the solutio by redutio to a equatio with ostat oeffiiets. I geeral, for liear equatios with variable oeffiiets, the fudametal set aot be determied by some uiversal azats their solutios have a wide variety of futioal forms. But if the oeffiiets of the differetial equatio are well eough behaved futios, the the solutios of the liear ODE are aalytial futios (reall Setio II.4) ad they a be represeted by the power series epasio (aalyti futio) about some poit : () + ( ) + + ( ) + ( ) y where oeffiiets have to be determied. y power series power series about y power series about overgee Series overges at if the sequee of partial sums overges N ( ) S S overges. absolute overgee if the series of absolute values radius of overgee R lim + R lim iterval of overgee diverges overges diverges R + R absolutely overges for all R < < + R Covergee at boudary poits ± R has to be ivestigated separately. aalyti futio Futio is alled aalyti at if it has a Taylor series epasio about. Power series defies a aalyti futio i its iterval of overgee: f, ( R, R + ) shift of ide + m a am m + m + m dummy ide idetity theorem If for all, the all oeffiiets
3 Chapter V ODE V.4 Power Series Solutio Otober, operatios with series Let f ( ) a ad overge i ( R, R + ) : summatio f ( ) ± g( ) ( a ) ± b g b multipliatio f ( ) g( ) a b( ), ab differetiatio f a f a itegratio f ( ) d a( ) d ( ) a + + Taylor series f ( ) ( ) ( ) ( ) f! ( ) f f f ( ) !! Malauri series f ( ) ( f )! ( ) f f !! f Table of Taylor series si 5. os 6. sih 7. osh < < < < ( ) < < ( ) ( + ) + <! ( ) <! ( + ) < < + < <! < <! 8. l( + ) ( ) + < < + 9. e < <!
4 388 Chapter V ODE V.4 Power Series Solutio Otober, 8 d order ODE I our aalysis, without sigifiat loss of geerality, we restrit ourselves to solutio of the d order homogeeous liear ODE for D : a y + a y + a y () Dividig equatio () by the leadig oeffiiet a ormal form we a rewrite it i the y + p y + q y (3) a ( ) p( ) ad q( ) where oeffiiets are p( ) a ( ) ad a ( ) q a ( ). However, we do ot require a ( ) for all D. We will distiguish the poits of the domai by the followig riteria: ordiary poit The poit a. is alled the ordiary poit of the ODE (), if sigular poit The poit a. is alled the sigular poit of the ODE (), if regular sigular poit The sigular poit is alled the regular sigular poit of ODE (3), if + ( ) + ( ) + ( ) p p p p... p (4) q( ) q + q( ) + q( ) +... q ( ) are aalyti at. (5) Eamples ) If the poit is a ordiary poit the we will be able to fid two liearly idepedet solutios of ODE () i the form of the power series () about the ordiary poit. If the poit is a sigular poit, the for the speial ase of the regular sigular poit we will be able to fid oe solutio i the form of the power series epasio about the sigular poit, ad the seod solutio a be ostruted i some speial way by the Frobeius method. y + y + si y all poits are ordiary y + y + y is the oly sigular poit ) 3) y y y i, i are the sigular poits y + y y 4) y + y y p ( ) + is aalyti, p q is aalyti, q Therefore, is a regular sigular poit.
5 Chapter V ODE V.4 Power Series Solutio Otober, V.4.. POWER SERIES SOLUTION R R iterval of overgee sigular poit + R Theorem (power series solutio about the ordiary poit) Let all oeffiiets a of ODE () be aalyti i some ope iterval D, ad let D be a ordiary poit of ODE (). The two liearly idepedet solutios of ODE () a be foud i the form of the power series y( ) () with the radius of overgee at least (a be bigger) R where is the earest to a sigular poit. I other words, if oeffiiets of () are aalytial futios, the aalytial solutio of () a be foud. The proedure of fidig the solutio briefly will osist of the followig steps:. Choose a ordiary poit (usually,, if ot, the by the hage of variable ξ, the ordiary poit a be traslated to ). y. Assume the solutio i the form ad substitute it ito ODE () (reall that overget power series a be differetiated term by term). 3. Combie the obtaied equatio ito a sigular power series ad use the Idetity Theorem to establish the reurree relatio for oeffiiets. Appliatio of the reurree relatio will yield two sets of oeffiiets otaiig the arbitrary ostats ad. 4. Eah set of oeffiiets will produe a liearly idepedet solutio i the form of the power series (). The both solutios a be tested for the radius of overgee. Eample (power series solutio about the ordiary poit) Solutio: Fid the solutio of the differetial equatio y + y + y (6) We will loo for the solutio of this liear ODE with variable oeffiiets i the form of power series aordig to Theorem. All oeffiiets of the give equatio are aalyti for all. There are o sigular poits of this equatio.. Choose a ordiary poit. Assume the solutio i the form y. Fid the derivatives of the assumed solutio (differetiate term by term): y (summatio effetively starts with ) (summatio effetively starts with y Substitute ito equatio (5): )
6 39 Chapter V ODE V.4 Power Series Solutio Otober, 8 3. To ombie all sigma-terms i a sigle summatio we eed all of them to have the same ide i the powers of m ad the same startig ide of summatio m m. First, reame the idies i eah sigma-term (reall that ide of summatio is dummy ad that the same result a be ahieved with ay other letter): m m m m+ + + m m m m+ m m m+ m+ + m + m m m To have the ommo startig ide of summatio m, write the first term i the first ad the third sums epliitly: m m m + + m+ m+ + m + + m m m m m m Now we a orgaize the equatio i oe power series m ( + ) + ( m+ )( m+ ) m+ + ( m+ ) m m We have that the power series is equal to zero. The aordig to the Idetity Theorem all oeffiiets should be equal to zero: ( + ) m+ m+ + m+ m,,... m+ m From whih we have (7) m+ m m+ m,,... (the reurree relatio) (8) Coeffiiets ad are ot defied by equatios (7-8) ad a be hose arbitrarily. The varyig the ide i equatios (7-8), we have: arbitrary arbitrary m 3 m m 3 3 m 4 m 5 5
7 Chapter V ODE V.4 Power Series Solutio Otober, 8 39 m m ( ) ( ) Substitute the obtaied oeffiiets ito the power series y ( ) ( ) ( ) + ( ) ( ) y ( ) 5. Geeral solutio i power series form: ( )! +!! + y ( ) y( ) ( )! ( ) + ( )!! +,, The last epressio is obtaied by maipulatio with the idies i the oeffiiets i order to obtai the simpler form of the result (this trasformatio is ot always obvious ad should ot eessarily be performed). The obtaied solutio i the form of two power series with the arbitrary oeffiiets ad is the geeral solutio of the ODE (6). There are o sigular poits of the equatio (6), therefore, both power series have a ifiite radius of overgee (it also a be ofirmed by the Ratio Test). Use Maple to seth the solutio urves. Note that i the Maple solutio (see Eample), the reurree equatio (8) is used diretly for evaluatio of the oeffiiets. Tris with fatorials: 3! 4 6 3! ( ) ( + ) ( 4 6 ) ( + ) ( + )!!
8 39 Chapter V ODE V.4 Power Series Solutio Otober, 8 V.4.3. THE METHOD OF FROBENIUS iterval of overgee ordiary poit overges sigular poit overges sigular poit If the liear ODE with variable oeffiiets has sigular poits the the radius of overgee of the power series solutio about the ordiary poit a be redued by the presee of sigular poits. Sometimes a epasio about a sigular poit a have some advatage beause suh solutios a have a bigger radius of overgee. The followig theorem provides the basis for the power series solutio about the regular sigular poit. For simpliity, we formulate this theorem for the regular sigular poit. Frobeius Theorem Theorem (power series solutio about the regular sigular poit ) Let the liear equatio y + p y + q y (3) haz a regular sigular poit, ad let p ( ) p + p + p +... p for R < (4a) q q + q + q +... q for < R (5a) Ferdiad Georg Frobeius ( ) Let r,r be the solutios of the idiial equatio r + ( p r ) + q () Re r Re r. ideed suh that The the liear ODE (3) has a geeral solutio + y ay by for R R mi R,R, ad liearly idepedet futios y ad y have the form: < <, where { }. If r r (do ot differ by a iteger) the + r y + r y d d. If r r (differ by a positive iteger) the + r y + r + y d y l d, a be zero 3. If r r (equal roots r r r) the + r y + r + y d y l
9 Chapter V ODE V.4 Power Series Solutio Otober, Eample Use the Frobeius method to fid a series solutio for the ODE y + y y () aroud the poit. Seth the solutio urves.. Poit is the oly sigular poit of the ODE (). Che if it is a regular sigular poit. Rewrite the equatio i the ormal form y + y y y + p y + q y p ( ) + is aalyti p q is aalyti q Therefore, is a regular sigular poit. Idiial equatio (): r + p r+ q r( r ) r + r+ roots r r r r That orrespods to Case of Frobeius Theorem:. The first solutio y a be foud i the form: + r + y + y + differetiate ad substitute ito Equatio () y m + m+ m + m m + m+ m + m hage of the idies m+ m+ m+ m+ m m m m m m m m m+ m+ + m+ m+
10 394 Chapter V ODE V.4 Power Series Solutio Otober, 8 write the zero terms epliitly m + m + m + + m + m + m+ m+ m+ m+ m m m m m m m m { } m + m m m m m+ m+ m+ + m+ { } m + m m m + m + m use the Idetity Theorem m m m + m + m m m+ + m m+ m m m reurree relatio m ay m m m is absorbed by ! y ! 3! 4! 5! ( ) ( + ) + st solutio! y 3. The seod solutio (ase of Frobeius Theorem) Substitutio of the trial form (ase ) ito equatio: multiply by ad add terms + y d y l y d y l y + + y ( ) d + y l + y + y y d + y l + y y + d + y l + y y l y d y l
11 Chapter V ODE V.4 Power Series Solutio Otober, d + d d d + y l + y l + y y + y y l y y l d + d d d + y y + y + y + y y y l beause y is a solutio d + d d d + y y+ y y y ( ) ( + ) + reall the st solutio! ( ) ( + ) + differetiate ad substitute ito the equatio! ( ) ( ) ( ) + ( + ) ( + ) d + d d d + +!!! m + m + m + m m m m m m m m+ m+ ( ) ( ) ( ) + ( + ) ( + ) + + +!!! d d d d ( ) ( ) ( ) m+ m m+ m m m m m m m ( + ) m m m m m m m m m m m md md m d d m! m! m! write terms for m ad m epliitly: m d d m + d+ d d d+ + ( ) ( ) ( ) m+ m m+ m m m m m m m ( + ) m m m m! m! m! m m m m m m m m md md m d d for m d d for m d + d d d + the the equatio beomes: m m m m ( d d) ( m ) mdm+ mdm ( m ) dm+ dm ombie i oe summatio m m m m
12 396 Chapter V ODE V.4 Power Series Solutio Otober, 8 { } m m+ m m m+ m m+ d + m d { } m m+ m m m+ m d + m d m+ m dm+ + m dm use the Idetity Theorem m+ m m+ d + d d dm + m+ m reurree formula for m d d d ay (but aot be hose as d ) d ay hoose d the d + m+ m dm m the the seod solutio beomes + d d + d d d d( ) y d y l or it a be simply writte as y ( ) The seod solutio of () 4. Alterative solutio for y ( ). Beause the seod solutio is i a simple losed form y ( ) we a use the redutio formula (Setio 5., Equatio (3)) to obtai the other liear idepedet solutio as: y a d a e y y d e ( ) ( ) d d e ( ) d d + l e d ( ) e d e ( ) (table itegral)
13 Chapter V ODE V.4 Power Series Solutio Otober, Let us see if we a retrieve this solutio from the power-series solutio. y ( ) We derived i the first part: ( ) ( + )! + +! 3! 4! ! 3! 4! add ad subtrat term e ( ) + + +! 3! 4! ( ) + e + e This solutio a be verified by diret substitutio ito ODE (). So, the geeral solutio of the ODE () a be writte as y y + y + e + ( )( ) e + + reame arbitrary ostats a ( ) + be The the Geeral Solutio of equatio () a be writte i losed form: y + e for all 5. Solutio urves for differet values of ad
14 398 V.4.4 Chapter V ODE V.4 Power Series Solutio Otober, 8 Taylor series solutio + + y( ) y p y q y y Loo for solutio i the form of the Taylor series about : iv y y 3 y 4 y( ) y( ) + y ( ) ( ) ! 3! 4! The first two oeffiiets are from the iitial oditios: y y The third oeffiiet a be foud from the give differetial equatio rewritte as, the evaluate y ( ) p( ) y ( ) q( ) y( ) y p y q y To fid the et oeffiiets, differetiate the equatio ad evaluate it at : y p y q y y... iv iv y y y... ad so o The with the foud ( ) y ostrut the Taylor series solutio iv y y 3 y 4 y( ) y( ) + y ( ) ( ) ! 3! 4!
15 Chapter V ODE V.4 Power Series Solutio Otober, Eample 3 Fid the first si terms of the power series solutio of the differetial equatio os y + y y subjet to iitial oditios: y, y 3. y
16 4 Chapter V ODE V.4 Power Series Solutio Otober, 8 V.4.5. POWER SERIES SOLUTION WITH MAPLE. Fid the solutio of the differetial equatio y + y + y (see Eample ) > restart; > M:4; M : 4 > []; > []; > []:-[]; : > for m from to M do [m+]:-[m]/(m+) od; 3 : 4 : 3 5 : 8 6 : 5 > m:'m': > y():sum([m]*^m,m..m+); y( ) : > y():ollet(y(),{[],[]}); y( ) : > f:subs({[]i,[]j},y()); f : i j > p:{seq(seq(f,i-4..4),j-4..4)}: > plot(p, ,olorbla);
17 Chapter V ODE V.4 Power Series Solutio Otober, 8 4. Solutio of IVP: y(), y'() > E:subs(,y()); > yp():diff(y(),); 5 E : yp( ) : > E:subs(,yp()); E : > solve({e,e},{[],[]}); {, } 8 7 > y():subs({[]-45/8,[]6/7},y()); y( ) : > plot(y(),-..);
18 4 Chapter V ODE V.4 Power Series Solutio Otober, 8 3. Power Series Solutio with the POWERSERIES paage: Fid the solutio of the differetial equatio 3 y y about the ordiary poit > restart; > with (powseries): > ODE:diff(y(),$)-^3*y(); d ODE : y( ) 3 y( ) d Fid the power series solutio with error of order O(^5): Covert to polyomial: > y():powsolve(ode); y( ) : pro( powparm )... ed pro > y():tpsform(y(),,5); C C C C y( ) : C + C O( 5 ) > y():overt(y(),polyom); y( ) : C + C C 5 3 C 6 8 C 33 C Plot solutio urves: > f:subs({ci,cj},y()); f : i + j i 5 3 j 6 8 i 33 j > p:{seq(seq(f,i-..),j-..)}: > plot(p,-3..,y-5..5,olorbla);
19 Chapter V ODE V.4 Power Series Solutio Otober, 8 43 V.4.6. REVIEW QUESTIONS. What is a aalytial futio? EXERCISES. What equatios are solved i the form of a power series? 3. What is a ordiary poit? 4. What is a sigular poit? 5. What is a regular sigular poit? 6. What is the radius of overgee of a power series solutio about a ordiary poit? 7. What are the mai steps i fidig a power series solutio about a ordiary poit? 8. What is the Method of Frobeius? 9. What is the idiial equatio?. What ases for the roots of the idiial equatio are osidered i the Frobeius Theorem?. What is the form of oe solutio whih a be foud for all three ases?. Why a it be advatageous to fid a solutio about a sigular poit? ) Give the power series epasios of ad their radius of overgee. ) Fid the iterval of overgee of the power series:! a) b) ( ) ) d) + 3 3) Fid the sigular poits of the equatios a) y y y ) + + b) λ d) y 3 y 4) Show that q( ) 3 ( ) 3 y + y y y y + y is aalyti at. i ad determie ( ) ( + 3 ) 5) Usig the power series method or the method of Frobeius, fid the geeral solutio of the followig differetial equatios: 3 a) y λ y f) y + y y b) y λ y g) y ( ) y y ) y y + y h) y + y y 3 d) y y i) y + y + y 4 e) y y y ;y y + + y y 6) Cosider the differetial equatio ) y y + y a) fid the geeral solutio of the give ODE i the form of a power series about the poit ; b) What is the radius of overgee of the obtaied power series solutio? ) Seth the solutio urves. 4 d) Fid the solutio subjet to the iitial oditios: y ; y 6.
20 44 Chapter V ODE V.4 Power Series Solutio Otober, 8
Explicit and closed formed solution of a differential equation. Closed form: since finite algebraic combination of. converges for x x0
Chapter 4 Series Solutios Epliit ad losed formed solutio of a differetial equatio y' y ; y() 3 ( ) ( 5 e ) y Closed form: sie fiite algebrai ombiatio of elemetary futios Series solutio: givig y ( ) as
More informationPOWER SERIES METHODS CHAPTER 8 SECTION 8.1 INTRODUCTION AND REVIEW OF POWER SERIES
CHAPTER 8 POWER SERIES METHODS SECTION 8. INTRODUCTION AND REVIEW OF POWER SERIES The power series method osists of substitutig a series y = ito a give differetial equatio i order to determie what the
More informationSolutions 3.2-Page 215
Solutios.-Page Problem Fid the geeral solutios i powers of of the differetial equatios. State the reurree relatios ad the guarateed radius of overgee i eah ase. ) Substitutig,, ad ito the differetial equatio
More informationBernoulli Numbers. n(n+1) = n(n+1)(2n+1) = n(n 1) 2
Beroulli Numbers Beroulli umbers are amed after the great Swiss mathematiia Jaob Beroulli5-705 who used these umbers i the power-sum problem. The power-sum problem is to fid a formula for the sum of the
More informationWe are mainly going to be concerned with power series in x, such as. (x)} converges - that is, lims N n
Review of Power Series, Power Series Solutios A power series i x - a is a ifiite series of the form c (x a) =c +c (x a)+(x a) +... We also call this a power series cetered at a. Ex. (x+) is cetered at
More informationCalculus 2 TAYLOR SERIES CONVERGENCE AND TAYLOR REMAINDER
Calulus TAYLO SEIES CONVEGENCE AND TAYLO EMAINDE Let the differee betwee f () ad its Taylor polyomial approimatio of order be (). f ( ) P ( ) + ( ) Cosider to be the remaider with the eat value ad the
More informationSubject: Differential Equations & Mathematical Modeling -III. Lesson: Power series solutions of Differential Equations. about ordinary points
Power series solutio of Differetial equatios about ordiary poits Subject: Differetial Equatios & Mathematical Modelig -III Lesso: Power series solutios of Differetial Equatios about ordiary poits Lesso
More informationSummation Method for Some Special Series Exactly
The Iteratioal Joural of Mathematis, Siee, Tehology ad Maagemet (ISSN : 39-85) Vol. Issue Summatio Method for Some Speial Series Eatly D.A.Gismalla Deptt. Of Mathematis & omputer Studies Faulty of Siee
More informationSubject: Differential Equations & Mathematical Modeling-III
Power Series Solutios of Differetial Equatios about Sigular poits Subject: Differetial Equatios & Mathematical Modelig-III Lesso: Power series solutios of differetial equatios about Sigular poits Lesso
More informationSx [ ] = x must yield a
Math -b Leture #5 Notes This wee we start with a remider about oordiates of a vetor relative to a basis for a subspae ad the importat speial ase where the subspae is all of R. This freedom to desribe vetors
More informationε > 0 N N n N a n < ε. Now notice that a n = a n.
4 Sequees.5. Null sequees..5.. Defiitio. A ull sequee is a sequee (a ) N that overges to 0. Hee, by defiitio of (a ) N overges to 0, a sequee (a ) N is a ull sequee if ad oly if ( ) ε > 0 N N N a < ε..5..
More informationMost text will write ordinary derivatives using either Leibniz notation 2 3. y + 5y= e and y y. xx tt t
Itroductio to Differetial Equatios Defiitios ad Termiolog Differetial Equatio: A equatio cotaiig the derivatives of oe or more depedet variables, with respect to oe or more idepedet variables, is said
More information62. Power series Definition 16. (Power series) Given a sequence {c n }, the series. c n x n = c 0 + c 1 x + c 2 x 2 + c 3 x 3 +
62. Power series Defiitio 16. (Power series) Give a sequece {c }, the series c x = c 0 + c 1 x + c 2 x 2 + c 3 x 3 + is called a power series i the variable x. The umbers c are called the coefficiets of
More informationDigital Signal Processing. Homework 2 Solution. Due Monday 4 October Following the method on page 38, the difference equation
Digital Sigal Proessig Homework Solutio Due Moda 4 Otober 00. Problem.4 Followig the method o page, the differee equatio [] (/4[-] + (/[-] x[-] has oeffiiets a0, a -/4, a /, ad b. For these oeffiiets A(z
More informationFluids Lecture 2 Notes
Fluids Leture Notes. Airfoil orte Sheet Models. Thi-Airfoil Aalysis Problem Readig: Aderso.,.7 Airfoil orte Sheet Models Surfae orte Sheet Model A aurate meas of represetig the flow about a airfoil i a
More informationQuiz. Use either the RATIO or ROOT TEST to determine whether the series is convergent or not.
Quiz. Use either the RATIO or ROOT TEST to determie whether the series is coverget or ot. e .6 POWER SERIES Defiitio. A power series i about is a series of the form c 0 c a c a... c a... a 0 c a where
More informationSOLUTION SET VI FOR FALL [(n + 2)(n + 1)a n+2 a n 1 ]x n = 0,
4. Series Solutios of Differetial Equatios:Special Fuctios 4.. Illustrative examples.. 5. Obtai the geeral solutio of each of the followig differetial equatios i terms of Maclauri series: d y (a dx = xy,
More informationClass #25 Wednesday, April 19, 2018
Cla # Wedesday, April 9, 8 PDE: More Heat Equatio with Derivative Boudary Coditios Let s do aother heat equatio problem similar to the previous oe. For this oe, I ll use a square plate (N = ), but I m
More informationObserver Design with Reduced Measurement Information
Observer Desig with Redued Measuremet Iformatio I pratie all the states aot be measured so that SVF aot be used Istead oly a redued set of measuremets give by y = x + Du p is available where y( R We assume
More informationANOTHER PROOF FOR FERMAT S LAST THEOREM 1. INTRODUCTION
ANOTHER PROOF FOR FERMAT S LAST THEOREM Mugur B. RĂUŢ Correspodig author: Mugur B. RĂUŢ, E-mail: m_b_raut@yahoo.om Abstrat I this paper we propose aother proof for Fermat s Last Theorem (FLT). We foud
More informationCalculus 2 - D. Yuen Final Exam Review (Version 11/22/2017. Please report any possible typos.)
Calculus - D Yue Fial Eam Review (Versio //7 Please report ay possible typos) NOTE: The review otes are oly o topics ot covered o previous eams See previous review sheets for summary of previous topics
More information9.3 Power Series: Taylor & Maclaurin Series
9.3 Power Series: Taylor & Maclauri Series If is a variable, the a ifiite series of the form 0 is called a power series (cetered at 0 ). a a a a a 0 1 0 is a power series cetered at a c a a c a c a c 0
More informationLinear Differential Equations of Higher Order Basic Theory: Initial-Value Problems d y d y dy
Liear Differetial Equatios of Higher Order Basic Theory: Iitial-Value Problems d y d y dy Solve: a( ) + a ( )... a ( ) a0( ) y g( ) + + + = d d d ( ) Subject to: y( 0) = y0, y ( 0) = y,..., y ( 0) = y
More informationCertain inclusion properties of subclass of starlike and convex functions of positive order involving Hohlov operator
Iteratioal Joural of Pure ad Applied Mathematial Siees. ISSN 0972-9828 Volume 0, Number (207), pp. 85-97 Researh Idia Publiatios http://www.ripubliatio.om Certai ilusio properties of sublass of starlike
More informationx x x Using a second Taylor polynomial with remainder, find the best constant C so that for x 0,
Math Activity 9( Due with Fial Eam) Usig first ad secod Taylor polyomials with remaider, show that for, 8 Usig a secod Taylor polyomial with remaider, fid the best costat C so that for, C 9 The th Derivative
More informationSeptember 2012 C1 Note. C1 Notes (Edexcel) Copyright - For AS, A2 notes and IGCSE / GCSE worksheets 1
September 0 s (Edecel) Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets September 0 Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets September 0 Copyright
More informationCHAPTER 5. Theory and Solution Using Matrix Techniques
A SERIES OF CLASS NOTES FOR 2005-2006 TO INTRODUCE LINEAR AND NONLINEAR PROBLEMS TO ENGINEERS, SCIENTISTS, AND APPLIED MATHEMATICIANS DE CLASS NOTES 3 A COLLECTION OF HANDOUTS ON SYSTEMS OF ORDINARY DIFFERENTIAL
More informationZeros of Polynomials
Math 160 www.timetodare.com 4.5 4.6 Zeros of Polyomials I these sectios we will study polyomials algebraically. Most of our work will be cocered with fidig the solutios of polyomial equatios of ay degree
More informationChapter 4: Angle Modulation
57 Chapter 4: Agle Modulatio 4.1 Itrodutio to Agle Modulatio This hapter desribes frequey odulatio (FM) ad phase odulatio (PM), whih are both fors of agle odulatio. Agle odulatio has several advatages
More informationf t dt. Write the third-degree Taylor polynomial for G
AP Calculus BC Homework - Chapter 8B Taylor, Maclauri, ad Power Series # Taylor & Maclauri Polyomials Critical Thikig Joural: (CTJ: 5 pts.) Discuss the followig questios i a paragraph: What does it mea
More informatione to approximate (using 4
Review: Taylor Polyomials ad Power Series Fid the iterval of covergece for the series Fid a series for f ( ) d ad fid its iterval of covergece Let f( ) Let f arcta a) Fid the rd degree Maclauri polyomial
More informationPAPER : IIT-JAM 2010
MATHEMATICS-MA (CODE A) Q.-Q.5: Oly oe optio is correct for each questio. Each questio carries (+6) marks for correct aswer ad ( ) marks for icorrect aswer.. Which of the followig coditios does NOT esure
More informationBESSEL EQUATION and BESSEL FUNCTIONS
BESSEL EQUATION ad BESSEL FUNCTIONS Bessel s Equatio Summary of Bessel Fuctios d y dy y d + d + =. If is a iteger, the two idepedet solutios of Bessel s Equatio are J J, Bessel fuctio of the first kid,
More informationTHE SOLUTION OF NONLINEAR EQUATIONS f( x ) = 0.
THE SOLUTION OF NONLINEAR EQUATIONS f( ) = 0. Noliear Equatio Solvers Bracketig. Graphical. Aalytical Ope Methods Bisectio False Positio (Regula-Falsi) Fied poit iteratio Newto Raphso Secat The root of
More informationIn algebra one spends much time finding common denominators and thus simplifying rational expressions. For example:
74 The Method of Partial Fractios I algebra oe speds much time fidig commo deomiators ad thus simplifyig ratioal epressios For eample: + + + 6 5 + = + = = + + + + + ( )( ) 5 It may the seem odd to be watig
More informationChapter 2: Numerical Methods
Chapter : Numerical Methods. Some Numerical Methods for st Order ODEs I this sectio, a summar of essetial features of umerical methods related to solutios of ordiar differetial equatios is give. I geeral,
More information(8) 1f = f. can be viewed as a real vector space where addition is defined by ( a1+ bi
Geeral Liear Spaes (Vetor Spaes) ad Solutios o ODEs Deiitio: A vetor spae V is a set, with additio ad salig o elemet deied or all elemets o the set, that is losed uder additio ad salig, otais a zero elemet
More information3.2 Properties of Division 3.3 Zeros of Polynomials 3.4 Complex and Rational Zeros of Polynomials
Math 60 www.timetodare.com 3. Properties of Divisio 3.3 Zeros of Polyomials 3.4 Complex ad Ratioal Zeros of Polyomials I these sectios we will study polyomials algebraically. Most of our work will be cocered
More informationMATH2007* Partial Answers to Review Exercises Fall 2004
MATH27* Partial Aswers to Review Eercises Fall 24 Evaluate each of the followig itegrals:. Let u cos. The du si ad Hece si ( cos 2 )(si ) (u 2 ) du. si u 2 cos 7 u 7 du Please fiish this. 2. We use itegratio
More informationThe type of limit that is used to find TANGENTS and VELOCITIES gives rise to the central idea in DIFFERENTIAL CALCULUS, the DERIVATIVE.
NOTES : LIMITS AND DERIVATIVES Name: Date: Period: Iitial: LESSON.1 THE TANGENT AND VELOCITY PROBLEMS Pre-Calculus Mathematics Limit Process Calculus The type of it that is used to fid TANGENTS ad VELOCITIES
More informationApply change-of-basis formula to rewrite x as a linear combination of eigenvectors v j.
Eigevalue-Eigevector Istructor: Nam Su Wag eigemcd Ay vector i real Euclidea space of dimesio ca be uiquely epressed as a liear combiatio of liearly idepedet vectors (ie, basis) g j, j,,, α g α g α g α
More informationMa 530 Introduction to Power Series
Ma 530 Itroductio to Power Series Please ote that there is material o power series at Visual Calculus. Some of this material was used as part of the presetatio of the topics that follow. What is a Power
More informationSOME NOTES ON INEQUALITIES
SOME NOTES ON INEQUALITIES Rihard Hoshio Here are four theorems that might really be useful whe you re workig o a Olympiad problem that ivolves iequalities There are a buh of obsure oes Chebyheff, Holder,
More informationChapter 10 Partial Differential Equations and Fourier Series
Math-33 Chapter Partial Differetial Equatios November 6, 7 Chapter Partial Differetial Equatios ad Fourier Series Math-33 Chapter Partial Differetial Equatios November 6, 7. Boudary Value Problems for
More informationCHAPTER 10 INFINITE SEQUENCES AND SERIES
CHAPTER 10 INFINITE SEQUENCES AND SERIES 10.1 Sequeces 10.2 Ifiite Series 10.3 The Itegral Tests 10.4 Compariso Tests 10.5 The Ratio ad Root Tests 10.6 Alteratig Series: Absolute ad Coditioal Covergece
More informationUNIVERSITY OF CALIFORNIA - SANTA CRUZ DEPARTMENT OF PHYSICS PHYS 116C. Problem Set 4. Benjamin Stahl. November 6, 2014
UNIVERSITY OF CALIFORNIA - SANTA CRUZ DEPARTMENT OF PHYSICS PHYS 6C Problem Set 4 Bejami Stahl November 6, 4 BOAS, P. 63, PROBLEM.-5 The Laguerre differetial equatio, x y + ( xy + py =, will be solved
More informationPower Series: A power series about the center, x = 0, is a function of x of the form
You are familiar with polyomial fuctios, polyomial that has ifiitely may terms. 2 p ( ) a0 a a 2 a. A power series is just a Power Series: A power series about the ceter, = 0, is a fuctio of of the form
More informationENGI 9420 Engineering Analysis Assignment 3 Solutions
ENGI 9 Egieerig Aalysis Assigmet Solutios Fall [Series solutio of ODEs, matri algebra; umerical methods; Chapters, ad ]. Fid a power series solutio about =, as far as the term i 7, to the ordiary differetial
More informationChapter 4. Fourier Series
Chapter 4. Fourier Series At this poit we are ready to ow cosider the caoical equatios. Cosider, for eample the heat equatio u t = u, < (4.) subject to u(, ) = si, u(, t) = u(, t) =. (4.) Here,
More informationMath 113, Calculus II Winter 2007 Final Exam Solutions
Math, Calculus II Witer 7 Fial Exam Solutios (5 poits) Use the limit defiitio of the defiite itegral ad the sum formulas to compute x x + dx The check your aswer usig the Evaluatio Theorem Solutio: I this
More informationCHAPTER 1 SEQUENCES AND INFINITE SERIES
CHAPTER SEQUENCES AND INFINITE SERIES SEQUENCES AND INFINITE SERIES (0 meetigs) Sequeces ad limit of a sequece Mootoic ad bouded sequece Ifiite series of costat terms Ifiite series of positive terms Alteratig
More informationMATH 10550, EXAM 3 SOLUTIONS
MATH 155, EXAM 3 SOLUTIONS 1. I fidig a approximate solutio to the equatio x 3 +x 4 = usig Newto s method with iitial approximatio x 1 = 1, what is x? Solutio. Recall that x +1 = x f(x ) f (x ). Hece,
More informationA brief introduction to linear algebra
CHAPTER 6 A brief itroductio to liear algebra 1. Vector spaces ad liear maps I what follows, fix K 2{Q, R, C}. More geerally, K ca be ay field. 1.1. Vector spaces. Motivated by our ituitio of addig ad
More informationChapter 5: Take Home Test
Chapter : Take Home Test AB Calulus - Hardtke Name Date: Tuesday, / MAY USE YOUR CALCULATOR FOR THIS PAGE. Roud aswers to three plaes. Sore: / Show diagrams ad work to justify eah aswer.. Approimate the
More informationMathematical Series (You Should Know)
Mathematical Series You Should Kow Mathematical series represetatios are very useful tools for describig images or for solvig/approimatig the solutios to imagig problems. The may be used to epad a fuctio
More informationRecursive Algorithms. Recurrences. Recursive Algorithms Analysis
Recursive Algorithms Recurreces Computer Sciece & Egieerig 35: Discrete Mathematics Christopher M Bourke cbourke@cseuledu A recursive algorithm is oe i which objects are defied i terms of other objects
More informationCHAPTER I: Vector Spaces
CHAPTER I: Vector Spaces Sectio 1: Itroductio ad Examples This first chapter is largely a review of topics you probably saw i your liear algebra course. So why cover it? (1) Not everyoe remembers everythig
More informationAnalytic Continuation
Aalytic Cotiuatio The stadard example of this is give by Example Let h (z) = 1 + z + z 2 + z 3 +... kow to coverge oly for z < 1. I fact h (z) = 1/ (1 z) for such z. Yet H (z) = 1/ (1 z) is defied for
More informationSociété de Calcul Mathématique SA Mathematical Modelling Company, Corp.
oiété de Calul Mathéatique A Matheatial Modellig Copay, Corp. Deisio-aig tools, sie 995 iple Rado Wals Part V Khihi's Law of the Iterated Logarith: Quatitative versios by Berard Beauzay August 8 I this
More information( ) ( ) ( ) ( ) ( + ) ( )
LSM Nov. 00 Cotet List Mathematics (AH). Algebra... kow ad use the otatio!, C r ad r.. kow the results = r r + + = r r r..3 kow Pascal's triagle. Pascal's triagle should be eteded up to = 7...4 kow ad
More informationContinuous Functions
Cotiuous Fuctios Q What does it mea for a fuctio to be cotiuous at a poit? Aswer- I mathematics, we have a defiitio that cosists of three cocepts that are liked i a special way Cosider the followig defiitio
More information1 Approximating Integrals using Taylor Polynomials
Seughee Ye Ma 8: Week 7 Nov Week 7 Summary This week, we will lear how we ca approximate itegrals usig Taylor series ad umerical methods. Topics Page Approximatig Itegrals usig Taylor Polyomials. Defiitios................................................
More informationCS537. Numerical Analysis and Computing
CS57 Numerical Aalysis ad Computig Lecture Locatig Roots o Equatios Proessor Ju Zhag Departmet o Computer Sciece Uiversity o Ketucky Leigto KY 456-6 Jauary 9 9 What is the Root May physical system ca be
More informationMAT1026 Calculus II Basic Convergence Tests for Series
MAT026 Calculus II Basic Covergece Tests for Series Egi MERMUT 202.03.08 Dokuz Eylül Uiversity Faculty of Sciece Departmet of Mathematics İzmir/TURKEY Cotets Mootoe Covergece Theorem 2 2 Series of Real
More informationRecurrence Relations
Recurrece Relatios Aalysis of recursive algorithms, such as: it factorial (it ) { if (==0) retur ; else retur ( * factorial(-)); } Let t be the umber of multiplicatios eeded to calculate factorial(). The
More information(Figure 2.9), we observe x. and we write. (b) as x, x 1. and we write. We say that the line y 0 is a horizontal asymptote of the graph of f.
The symbol for ifiity ( ) does ot represet a real umber. We use to describe the behavior of a fuctio whe the values i its domai or rage outgrow all fiite bouds. For eample, whe we say the limit of f as
More informationInverse Matrix. A meaning that matrix B is an inverse of matrix A.
Iverse Matrix Two square matrices A ad B of dimesios are called iverses to oe aother if the followig holds, AB BA I (11) The otio is dual but we ofte write 1 B A meaig that matrix B is a iverse of matrix
More informationMAT 271 Project: Partial Fractions for certain rational functions
MAT 7 Project: Partial Fractios for certai ratioal fuctios Prerequisite kowledge: partial fractios from MAT 7, a very good commad of factorig ad complex umbers from Precalculus. To complete this project,
More informationSOLUTIONS TO EXAM 3. Solution: Note that this defines two convergent geometric series with respective radii r 1 = 2/5 < 1 and r 2 = 1/5 < 1.
SOLUTIONS TO EXAM 3 Problem Fid the sum of the followig series 2 + ( ) 5 5 2 5 3 25 2 2 This series diverges Solutio: Note that this defies two coverget geometric series with respective radii r 2/5 < ad
More informationj=1 dz Res(f, z j ) = 1 d k 1 dz k 1 (z c)k f(z) Res(f, c) = lim z c (k 1)! Res g, c = f(c) g (c)
Problem. Compute the itegrals C r d for Z, where C r = ad r >. Recall that C r has the couter-clockwise orietatio. Solutio: We will use the idue Theorem to solve this oe. We could istead use other (perhaps
More informationPolynomials with Rational Roots that Differ by a Non-zero Constant. Generalities
Polyomials with Ratioal Roots that Differ by a No-zero Costat Philip Gibbs The problem of fidig two polyomials P(x) ad Q(x) of a give degree i a sigle variable x that have all ratioal roots ad differ by
More informationFourier Series and the Wave Equation
Fourier Series ad the Wave Equatio We start with the oe-dimesioal wave equatio u u =, x u(, t) = u(, t) =, ux (,) = f( x), u ( x,) = This represets a vibratig strig, where u is the displacemet of the strig
More information2. Fourier Series, Fourier Integrals and Fourier Transforms
Mathematics IV -. Fourier Series, Fourier Itegrals ad Fourier Trasforms The Fourier series are used for the aalysis of the periodic pheomea, which ofte appear i physics ad egieerig. The Fourier itegrals
More informationMath 20B. Lecture Examples.
Math 20B. Leture Examples. (7/9/09) Setio 0.3. Covergee of series with positive terms Theorem (Covergee of series with positive terms) A ifiite series with positive terms either overges or diverges to.
More informationSection 11.8: Power Series
Sectio 11.8: Power Series 1. Power Series I this sectio, we cosider geeralizig the cocept of a series. Recall that a series is a ifiite sum of umbers a. We ca talk about whether or ot it coverges ad i
More information( a) ( ) 1 ( ) 2 ( ) ( ) 3 3 ( ) =!
.8,.9: Taylor ad Maclauri Series.8. Although we were able to fid power series represetatios for a limited group of fuctios i the previous sectio, it is ot immediately obvious whether ay give fuctio has
More informationFor use only in Badminton School November 2011 C2 Note. C2 Notes (Edexcel)
For use oly i Badmito School November 0 C Note C Notes (Edecel) Copyright www.pgmaths.co.uk - For AS, A otes ad IGCSE / GCSE worksheets For use oly i Badmito School November 0 C Note Copyright www.pgmaths.co.uk
More informationCS321. Numerical Analysis and Computing
CS Numerical Aalysis ad Computig Lecture Locatig Roots o Equatios Proessor Ju Zhag Departmet o Computer Sciece Uiversity o Ketucky Leigto KY 456-6 September 8 5 What is the Root May physical system ca
More informationIn exercises 1 and 2, (a) write the repeating decimal as a geometric series and (b) write its sum as the ratio of two integers _
Chapter 9 Curve I eercises ad, (a) write the repeatig decimal as a geometric series ad (b) write its sum as the ratio of two itegers _.9.976 Distace A ball is dropped from a height of 8 meters. Each time
More informationSection 1 of Unit 03 (Pure Mathematics 3) Algebra
Sectio 1 of Uit 0 (Pure Mathematics ) Algebra Recommeded Prior Kowledge Studets should have studied the algebraic techiques i Pure Mathematics 1. Cotet This Sectio should be studied early i the course
More informationChapter 6 Infinite Series
Chapter 6 Ifiite Series I the previous chapter we cosidered itegrals which were improper i the sese that the iterval of itegratio was ubouded. I this chapter we are goig to discuss a topic which is somewhat
More informationPresentation of complex number in Cartesian and polar coordinate system
a + bi, aεr, bεr i = z = a + bi a = Re(z), b = Im(z) give z = a + bi & w = c + di, a + bi = c + di a = c & b = d The complex cojugate of z = a + bi is z = a bi The sum of complex cojugates is real: z +
More informationComparison Study of Series Approximation. and Convergence between Chebyshev. and Legendre Series
Applied Mathematical Scieces, Vol. 7, 03, o. 6, 3-337 HIKARI Ltd, www.m-hikari.com http://d.doi.org/0.988/ams.03.3430 Compariso Study of Series Approimatio ad Covergece betwee Chebyshev ad Legedre Series
More informationLecture 8. Dirac and Weierstrass
Leture 8. Dira ad Weierstrass Audrey Terras May 5, 9 A New Kid of Produt of Futios You are familiar with the poitwise produt of futios de ed by f g(x) f(x) g(x): You just tae the produt of the real umbers
More informationPhysics 116A Solutions to Homework Set #1 Winter Boas, problem Use equation 1.8 to find a fraction describing
Physics 6A Solutios to Homework Set # Witer 0. Boas, problem. 8 Use equatio.8 to fid a fractio describig 0.694444444... Start with the formula S = a, ad otice that we ca remove ay umber of r fiite decimals
More informationMa 530 Infinite Series I
Ma 50 Ifiite Series I Please ote that i additio to the material below this lecture icorporated material from the Visual Calculus web site. The material o sequeces is at Visual Sequeces. (To use this li
More informationSequences and Series of Functions
Chapter 6 Sequeces ad Series of Fuctios 6.1. Covergece of a Sequece of Fuctios Poitwise Covergece. Defiitio 6.1. Let, for each N, fuctio f : A R be defied. If, for each x A, the sequece (f (x)) coverges
More informationCONTENTS. Course Goals. Course Materials Lecture Notes:
INTRODUCTION Ho Chi Mih City OF Uiversity ENVIRONMENTAL of Techology DESIGN Faculty Chapter of Civil 1: Orietatio. Egieerig Evaluatio Departmet of mathematical of Water Resources skill Egieerig & Maagemet
More informationME260W Mid-Term Exam Instructor: Xinyu Huang Date: Mar
ME60W Mid-Term Exam Istrutor: Xiyu Huag Date: Mar-03-005 Name: Grade: /00 Problem. A atilever beam is to be used as a sale. The bedig momet M at the gage loatio is P*L ad the strais o the top ad the bottom
More informationThe picture in figure 1.1 helps us to see that the area represents the distance traveled. Figure 1: Area represents distance travelled
1 Lecture : Area Area ad distace traveled Approximatig area by rectagles Summatio The area uder a parabola 1.1 Area ad distace Suppose we have the followig iformatio about the velocity of a particle, how
More informationSection 7 Fundamentals of Sequences and Series
ectio Fudametals of equeces ad eries. Defiitio ad examples of sequeces A sequece ca be thought of as a ifiite list of umbers. 0, -, -0, -, -0...,,,,,,. (iii),,,,... Defiitio: A sequece is a fuctio which
More informationTopic 9 - Taylor and MacLaurin Series
Topic 9 - Taylor ad MacLauri Series A. Taylors Theorem. The use o power series is very commo i uctioal aalysis i act may useul ad commoly used uctios ca be writte as a power series ad this remarkable result
More information8. Applications To Linear Differential Equations
8. Applicatios To Liear Differetial Equatios 8.. Itroductio 8.. Review Of Results Cocerig Liear Differetial Equatios Of First Ad Secod Orders 8.3. Eercises 8.4. Liear Differetial Equatios Of Order N 8.5.
More informationPAijpam.eu ON DERIVATION OF RATIONAL SOLUTIONS OF BABBAGE S FUNCTIONAL EQUATION
Iteratioal Joural of Pure ad Applied Mathematics Volume 94 No. 204, 9-20 ISSN: 3-8080 (prited versio); ISSN: 34-3395 (o-lie versio) url: http://www.ijpam.eu doi: http://dx.doi.org/0.2732/ijpam.v94i.2 PAijpam.eu
More informationMathematical Methods for Physics and Engineering
Mathematical Methods for Physics ad Egieerig Lecture otes Sergei V. Shabaov Departmet of Mathematics, Uiversity of Florida, Gaiesville, FL 326 USA CHAPTER The theory of covergece. Numerical sequeces..
More informationx x x 2x x N ( ) p NUMERICAL METHODS UNIT-I-SOLUTION OF EQUATIONS AND EIGENVALUE PROBLEMS By Newton-Raphson formula
NUMERICAL METHODS UNIT-I-SOLUTION OF EQUATIONS AND EIGENVALUE PROBLEMS. If g( is cotiuous i [a,b], te uder wat coditio te iterative (or iteratio metod = g( as a uique solutio i [a,b]? '( i [a,b].. Wat
More information6.3 Testing Series With Positive Terms
6.3. TESTING SERIES WITH POSITIVE TERMS 307 6.3 Testig Series With Positive Terms 6.3. Review of what is kow up to ow I theory, testig a series a i for covergece amouts to fidig the i= sequece of partial
More informationCalculus II - Problem Drill 21: Power Series, Taylor and Maclaurin Polynomial Series
Calculus II - Problem Drill : Power Series, Taylor ad Maclauri Polyomial Series Questio No. of 0 Istructios: () Read the problem ad aswer choices carefully () Work the problems o paper as 3 4 3 4. Fill
More informationAdditional Notes on Power Series
Additioal Notes o Power Series Mauela Girotti MATH 37-0 Advaced Calculus of oe variable Cotets Quick recall 2 Abel s Theorem 2 3 Differetiatio ad Itegratio of Power series 4 Quick recall We recall here
More information