Problem 1 (From the reservoir to the grid)

Size: px
Start display at page:

Download "Problem 1 (From the reservoir to the grid)"

Transcription

1 ÈÖÓ º ĺ ÙÞÞ ÐÐ ÈÖÓ º ʺ ³ Ò Ö ½ ½¹¼ ¼¹¼¼ ËÝ Ø Ñ ÅÓ Ð Ò ÀË ¾¼½ µ Ü Ö ÌÓÔ ÀÝ ÖÓ Ð ØÖ ÔÓÛ Ö ÔÐ ÒØ À Èȵ ¹ È ÖØ ÁÁ Ð ÖÒ Ø Þº ÇØÓ Ö ½ ¾¼½ Problem (From the reservoir to the grid) The causality diagram of the entire system (i.e. including the second part of the HEPP exercise) is shown in Figure. Again, blocks with drop shadows are dynamic, the others are algebraic. This solution is not unique, for example you might chose to have volume or mass flows instead of velocities. The outputs of the dynamic blocks were chosen to be the level variables, algebraic blocks were introduced where required. The signals are explained in Table. Table : Signals in the causality diagram. Symbol h R h W p W p F v T v F v V V A V u x T G T T ω I U net p Description Water level of the reservoir Water level of the water tank Pressure after the water tank Pressure after the down pipe Velocity in the tunnel Velocity in the down pipe Velocity after the valve Dynamic volume of the compressibility Opening area of the valve Input of the valve s needle Position of the valve s needle Torque of the generator Torque of the turbine Angular velocity of turbine and generator Current Voltage of the grid Ambient pressure

2 Figure : The causality diagram of the hydroelectric power plant.

3 Turbine The turbine and the generator are connected through a rigid shaft. It can be assumed that the inertias of the turbine, generator and shaft are all summarized in the Θ value. The turbine s torque can be calculated using the momentum law: T T (t) = F T.5 d T urb = ρ d T urb (v V (t).5 d T urb ω(t) ) A V (t) v V (t). () where F T is the mean force acting on the turbine s blades. The rotational speed can be formulated using the principle of angular momentum dω(t) = Θ (T T (t) T G (t) ), (2) where the friction term d ω(t) was omitted, since much smaller compared to the other two torques. The generator s torque T G (t) is a function of the current I(t) and will be discussed in the next section. Table 2: Signals and parameters for the subsystem Turbine. Description Symbol Units Inputs Exit velocity after the valve v V m/s Opening area of the valve A V m 2 Torque of the generator T G N m Outputs Rotational speed of the turbine ω rad/s Parameters Density of the water ρ kg/m 3 Diameter of the turbine d T urb m Moment of inertia of turbine, generator and shaft Θ kg m 2 Generator und Grid L G R G L net R net + U ind (t) U net (t) I(t) Figure 2: Schematic of the circuit. The schematic of the LR-circuit is shown in Figure 2. The voltage induced in the generator is a function of the rotational speed: U ind (t) = κ ω(t). (3)

4 using the Kirchhoff s voltage law, the following equation can be written: κ ω(t) L tot di(t) R tot I(t) = () di(t) = κ ω(t) R tot I(t), L tot (5) where R tot = R G + R net and L tot = L G + L net. The generator s torque, which works against turbine s torque, is proportional to the current: T G (t) = κ I(t). (6) Therefore the grid s voltage can be calculated as following: U net (t) = L net di(t) + R net I(t). (7) Table 3: Signals and parameters for the subsystem Generator and Grid. Description Symbol Units Inputs Rotational speed of the turbine ω rad/s Outputs Generated current I A Torque of the generator T G Nm Voltage of the grid U net V Parameters Constant of the generator κ Vs Inductance of the generator L G Vs/A Resistance of the generator R G Ω Inductance of the grid L net Vs/A Resistance of the grid R net Ω

5 Problem 2 (Simulate the entire hydroelectric power plant) Once you will have connected all the subsystem similarly to the structure of the causality diagram, you should be ready to simulate the entire system. In case you were not able to do it, you can use the Simulink model provided with the solution. The equations contained in this model are the ones found in Exercise and 5. The initial condition for each integrator in the system are the following: x(t = ) = m h W (t = ) = 3 m v T (t = ) = m /s v F (t = ) = m /s V (t = ) = l F π d F 2 ω(t = ) = rad /s I(t = ) = A These are the system s equilibrium (i.e. steady state conditions) values when the valve is closed. In this case a solver that can handle stiff differential equations, like ode23s(stiff), was used. The trajectories of the system s state variables, for the given valve position s evolution, are shown in Figure 3. Valve s Position 25 Water tank s water level 7 x 6 Pressure before Valve x [ ].6. h W [m] 5 p F [Pa] Tunnel s Volume Flow 5 Downpipe s Volume Flow 25 Turbine s Rotational Speed V T [m 3 /s] 2 V F [m 3 /s] 2 ω [rad/s] x 5 Grid s Voltage Grid s Current 8 x 7 Grid s Power U net [V] I net [A] 6 P net [W] Figure 3: Signals evolution of hte considered variables using the Simulink model provided Model_SysMod26.slx and the identified parameters contained in Parameters_HEPP.m All information without warranty.

Problem 1 (From the reservoir to the grid)

Problem 1 (From the reservoir to the grid) ÈÖÓ º ĺ ÙÞÞ ÐÐ ÈÖÓ º ʺ ³ Ò Ö ½ ½¹¼ ¹¼¼ ËÝ Ø Ñ ÅÓ Ð Ò ÀË ¾¼½ µ Ü Ö ËÓÐÙØ ÓÒ ÌÓÔ ÀÝ ÖÓ Ð ØÖ ÔÓÛ Ö ÔÐ ÒØ À Èȵ ¹ È ÖØ ÁÁ Ð ÖÒ Ø Þº ÇØÓ Ö ¾ ¾¼½ Problem 1 (From the reservoir to the grid) The causality diagram

More information

Exercise 5 - Hydraulic Turbines and Electromagnetic Systems

Exercise 5 - Hydraulic Turbines and Electromagnetic Systems Exercise 5 - Hydraulic Turbines and Electromagnetic Systems 5.1 Hydraulic Turbines Whole courses are dedicated to the analysis of gas turbines. For the aim of modeling hydraulic systems, we analyze here

More information

Conservation of Angular Momentum

Conservation of Angular Momentum 10 March 2017 Conservation of ngular Momentum Lecture 23 In the last class, we discussed about the conservation of angular momentum principle. Using RTT, the angular momentum principle was given as DHo

More information

Manufacturing Equipment Control

Manufacturing Equipment Control QUESTION 1 An electric drive spindle has the following parameters: J m = 2 1 3 kg m 2, R a = 8 Ω, K t =.5 N m/a, K v =.5 V/(rad/s), K a = 2, J s = 4 1 2 kg m 2, and K s =.3. Ignore electrical dynamics

More information

Answers to questions in each section should be tied together and handed in separately.

Answers to questions in each section should be tied together and handed in separately. EGT0 ENGINEERING TRIPOS PART IA Wednesday 4 June 014 9 to 1 Paper 1 MECHANICAL ENGINEERING Answer all questions. The approximate number of marks allocated to each part of a question is indicated in the

More information

Modeling and Analysis of Dynamic Systems

Modeling and Analysis of Dynamic Systems Modeling and Analysis of Dynamic Systems by Dr. Guillaume Ducard Fall 2016 Institute for Dynamic Systems and Control ETH Zurich, Switzerland 1/22 Outline 1 Lecture 5: Hydraulic Systems Pelton Turbine:

More information

ECEN 420 LINEAR CONTROL SYSTEMS. Lecture 6 Mathematical Representation of Physical Systems II 1/67

ECEN 420 LINEAR CONTROL SYSTEMS. Lecture 6 Mathematical Representation of Physical Systems II 1/67 1/67 ECEN 420 LINEAR CONTROL SYSTEMS Lecture 6 Mathematical Representation of Physical Systems II State Variable Models for Dynamic Systems u 1 u 2 u ṙ. Internal Variables x 1, x 2 x n y 1 y 2. y m Figure

More information

Exercise 8 - Turbocompressors

Exercise 8 - Turbocompressors Exercise 8 - Turbocompressors A turbocompressor TC) or turbocharger is a mechanical device used in internal combustion engines to enhance their power output. The basic idea of a TC is to force additional

More information

Center of Gravity Pearson Education, Inc.

Center of Gravity Pearson Education, Inc. Center of Gravity = The center of gravity position is at a place where the torque from one end of the object is balanced by the torque of the other end and therefore there is NO rotation. Fulcrum Point

More information

Model of a DC Generator Driving a DC Motor (which propels a car)

Model of a DC Generator Driving a DC Motor (which propels a car) Model of a DC Generator Driving a DC Motor (which propels a car) John Hung 5 July 2011 The dc is connected to the dc as illustrated in Fig. 1. Both machines are of permanent magnet type, so their respective

More information

Introduction to Control (034040) lecture no. 2

Introduction to Control (034040) lecture no. 2 Introduction to Control (034040) lecture no. 2 Leonid Mirkin Faculty of Mechanical Engineering Technion IIT Setup: Abstract control problem to begin with y P(s) u where P is a plant u is a control signal

More information

θ α W Description of aero.m

θ α W Description of aero.m Description of aero.m Determination of the aerodynamic forces, moments and power by means of the blade element method; for known mean wind speed, induction factor etc. Simplifications: uniform flow (i.e.

More information

DcMotor_ Model Help File

DcMotor_ Model Help File Name of Model: DcMotor_021708 Author: Vladimir L. Chervyakov Date: 2002-10-26 Executable file name DcMotor_021708.vtm Version number: 1.0 Description This model represents a Nonlinear model of a permanent

More information

Chapter 8: Momentum, Impulse, & Collisions. Newton s second law in terms of momentum:

Chapter 8: Momentum, Impulse, & Collisions. Newton s second law in terms of momentum: linear momentum: Chapter 8: Momentum, Impulse, & Collisions Newton s second law in terms of momentum: impulse: Under what SPECIFIC condition is linear momentum conserved? (The answer does not involve collisions.)

More information

ME 316: Thermofluids Laboratory

ME 316: Thermofluids Laboratory ME 316 Thermofluid Laboratory 6.1 KING FAHD UNIVERSITY OF PETROLEUM & MINERALS ME 316: Thermofluids Laboratory PELTON IMPULSE TURBINE 1) OBJECTIVES a) To introduce the operational principle of an impulse

More information

Final Exam April 30, 2013

Final Exam April 30, 2013 Final Exam Instructions: You have 120 minutes to complete this exam. This is a closed-book, closed-notes exam. You are allowed to use a calculator during the exam. Usage of mobile phones and other electronic

More information

DC Motor Position: System Modeling

DC Motor Position: System Modeling 1 of 7 01/03/2014 22:07 Tips Effects TIPS ABOUT BASICS INDEX NEXT INTRODUCTION CRUISE CONTROL MOTOR SPEED MOTOR POSITION SUSPENSION INVERTED PENDULUM SYSTEM MODELING ANALYSIS DC Motor Position: System

More information

Robust Control For Variable-Speed Two-Bladed Horizontal-Axis Wind Turbines Via ChatteringControl

Robust Control For Variable-Speed Two-Bladed Horizontal-Axis Wind Turbines Via ChatteringControl Robust Control For Variable-Speed Two-Bladed Horizontal-Axis Wind Turbines Via ChatteringControl Leonardo Acho, Yolanda Vidal, Francesc Pozo CoDAlab, Escola Universitària d'enginyeria Tècnica Industrial

More information

Physics 207 Lecture 25. Lecture 25. HW11, Due Tuesday, May 6 th For Thursday, read through all of Chapter 18. Angular Momentum Exercise

Physics 207 Lecture 25. Lecture 25. HW11, Due Tuesday, May 6 th For Thursday, read through all of Chapter 18. Angular Momentum Exercise Lecture 5 Today Review: Exam covers Chapters 14-17 17 plus angular momentum, rolling motion & torque Assignment HW11, Due Tuesday, May 6 th For Thursday, read through all of Chapter 18 Physics 07: Lecture

More information

Chapters 10 & 11: Rotational Dynamics Thursday March 8 th

Chapters 10 & 11: Rotational Dynamics Thursday March 8 th Chapters 10 & 11: Rotational Dynamics Thursday March 8 th Review of rotational kinematics equations Review and more on rotational inertia Rolling motion as rotation and translation Rotational kinetic energy

More information

Scanned by CamScanner

Scanned by CamScanner Scanned by CamScanner Scanned by CamScanner t W I w v 6.00-fall 017 Midterm 1 Name Problem 3 (15 pts). F the circuit below, assume that all equivalent parameters are to be found to the left of port

More information

AP Physics QUIZ Chapters 10

AP Physics QUIZ Chapters 10 Name: 1. Torque is the rotational analogue of (A) Kinetic Energy (B) Linear Momentum (C) Acceleration (D) Force (E) Mass A 5-kilogram sphere is connected to a 10-kilogram sphere by a rigid rod of negligible

More information

An Example file... log.txt

An Example file... log.txt # ' ' Start of fie & %$ " 1 - : 5? ;., B - ( * * B - ( * * F I / 0. )- +, * ( ) 8 8 7 /. 6 )- +, 5 5 3 2( 7 7 +, 6 6 9( 3 5( ) 7-0 +, => - +< ( ) )- +, 7 / +, 5 9 (. 6 )- 0 * D>. C )- +, (A :, C 0 )- +,

More information

Homework 6. Solution 1. r ( V jet sin( θ) + ω r) ( ρ Q r) Vjet

Homework 6. Solution 1. r ( V jet sin( θ) + ω r) ( ρ Q r) Vjet Problem 1 Water enters the rotating sprinkler along the axis of rotation and leaves through three nozzles. How large is the resisting torque required to hold the rotor stationary for the angle that produces

More information

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. Exam Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) Two men, Joel and Jerry, push against a wall. Jerry stops after 10 min, while Joel is

More information

Chapter 12: Rotation of Rigid Bodies. Center of Mass Moment of Inertia Torque Angular Momentum Rolling Statics

Chapter 12: Rotation of Rigid Bodies. Center of Mass Moment of Inertia Torque Angular Momentum Rolling Statics Chapter 1: Rotation of Rigid Bodies Center of Mass Moment of Inertia Torque Angular Momentum Rolling Statics Translational vs Rotational / / 1/ m x v dx dt a dv dt F ma p mv KE mv Work Fd P Fv / / 1/ I

More information

1. Which of the following is the unit for angular displacement? A. Meters B. Seconds C. Radians D. Radian per second E. Inches

1. Which of the following is the unit for angular displacement? A. Meters B. Seconds C. Radians D. Radian per second E. Inches AP Physics B Practice Questions: Rotational Motion Multiple-Choice Questions 1. Which of the following is the unit for angular displacement? A. Meters B. Seconds C. Radians D. Radian per second E. Inches

More information

z F 3 = = = m 1 F 1 m 2 F 2 m 3 - Linear Momentum dp dt F net = d P net = d p 1 dt d p n dt - Conservation of Linear Momentum Δ P = 0

z F 3 = = = m 1 F 1 m 2 F 2 m 3 - Linear Momentum dp dt F net = d P net = d p 1 dt d p n dt - Conservation of Linear Momentum Δ P = 0 F 1 m 2 F 2 x m 1 O z F 3 m 3 y Ma com = F net F F F net, x net, y net, z = = = Ma Ma Ma com, x com, y com, z p = mv - Linear Momentum F net = dp dt F net = d P dt = d p 1 dt +...+ d p n dt Δ P = 0 - Conservation

More information

UNITS AND DEFINITIONS RELATED TO BIOMECHANICAL AND ELECTROMYOGRAPHICAL MEASUREMENTS

UNITS AND DEFINITIONS RELATED TO BIOMECHANICAL AND ELECTROMYOGRAPHICAL MEASUREMENTS APPENDIX B UNITS AND DEFINITIONS RELATED TO BIOMECHANICAL AND ELECTROMYOGRAPHICAL MEASUREMENTS All units used are SI (Système International d Unités). The system is based on seven well-defined base units

More information

2 Hallén s integral equation for the thin wire dipole antenna

2 Hallén s integral equation for the thin wire dipole antenna Ú Ð Ð ÓÒÐ Ò Ø ØØÔ»» Ѻ Ö Ùº º Ö ÁÒغ º ÁÒ Ù ØÖ Ð Å Ø Ñ Ø ÎÓк ÆÓº ¾ ¾¼½½µ ½ ¹½ ¾ ÆÙÑ Ö Ð Ñ Ø Ó ÓÖ Ò ÐÝ Ó Ö Ø ÓÒ ÖÓÑ Ø Ò Û Ö ÔÓÐ ÒØ ÒÒ Ëº À Ø ÑÞ ¹Î ÖÑ ÞÝ Ö Åº Æ Ö¹ÅÓ Êº Ë Þ ¹Ë Ò µ Ô ÖØÑ ÒØ Ó Ð ØÖ Ð Ò Ò

More information

Dynamic Modeling of Fluid Power Transmissions for Wind Turbines

Dynamic Modeling of Fluid Power Transmissions for Wind Turbines Dynamic Modeling of Fluid Power Transmissions for Wind Turbines EWEA OFFSHORE 211 N.F.B. Diepeveen, A. Jarquin Laguna n.f.b.diepeveen@tudelft.nl, a.jarquinlaguna@tudelft.nl Offshore Wind Group, TU Delft,

More information

Coupled Drive Apparatus Modelling and Simulation

Coupled Drive Apparatus Modelling and Simulation University of Ljubljana Faculty of Electrical Engineering Victor Centellas Gil Coupled Drive Apparatus Modelling and Simulation Diploma thesis Menthor: prof. dr. Maja Atanasijević-Kunc Ljubljana, 2015

More information

PH Nuclear Physics Laboratory Gamma spectroscopy (NP3)

PH Nuclear Physics Laboratory Gamma spectroscopy (NP3) Physics Department Royal Holloway University of London PH2510 - Nuclear Physics Laboratory Gamma spectroscopy (NP3) 1 Objectives The aim of this experiment is to demonstrate how γ-ray energy spectra may

More information

TOPIC E: OSCILLATIONS EXAMPLES SPRING Q1. Find general solutions for the following differential equations:

TOPIC E: OSCILLATIONS EXAMPLES SPRING Q1. Find general solutions for the following differential equations: TOPIC E: OSCILLATIONS EXAMPLES SPRING 2019 Mathematics of Oscillating Systems Q1. Find general solutions for the following differential equations: Undamped Free Vibration Q2. A 4 g mass is suspended by

More information

where = rate of change of total energy of the system, = rate of heat added to the system, = rate of work done by the system

where = rate of change of total energy of the system, = rate of heat added to the system, = rate of work done by the system The Energy Equation for Control Volumes Recall, the First Law of Thermodynamics: where = rate of change of total energy of the system, = rate of heat added to the system, = rate of work done by the system

More information

Chapter 9 Objectives

Chapter 9 Objectives Chapter 9 Engr8 Circuit Analysis Dr Curtis Nelson Chapter 9 Objectives Understand the concept of a phasor; Be able to transform a circuit with a sinusoidal source into the frequency domain using phasor

More information

You know for EE 303 that electrical speed for a generator equals the mechanical speed times the number of poles, per eq. (1).

You know for EE 303 that electrical speed for a generator equals the mechanical speed times the number of poles, per eq. (1). Stability 1 1. Introduction We now begin Chapter 14.1 in your text. Our previous work in this course has focused on analysis of currents during faulted conditions in order to design protective systems

More information

Modeling and Analysis of Dynamic Systems

Modeling and Analysis of Dynamic Systems Modeling and Analysis of Dynamic Systems Dr. Guillaume Ducard Fall 2017 Institute for Dynamic Systems and Control ETH Zurich, Switzerland G. Ducard c 1 / 34 Outline 1 Lecture 7: Recall on Thermodynamics

More information

FEEDBACK CONTROL SYSTEMS

FEEDBACK CONTROL SYSTEMS FEEDBAC CONTROL SYSTEMS. Control System Design. Open and Closed-Loop Control Systems 3. Why Closed-Loop Control? 4. Case Study --- Speed Control of a DC Motor 5. Steady-State Errors in Unity Feedback Control

More information

Oscillatory Motion SHM

Oscillatory Motion SHM Chapter 15 Oscillatory Motion SHM Dr. Armen Kocharian Periodic Motion Periodic motion is motion of an object that regularly repeats The object returns to a given position after a fixed time interval A

More information

Chapter 3: Fundamentals of Mechanics and Heat. 1/11/00 Electromechanical Dynamics 1

Chapter 3: Fundamentals of Mechanics and Heat. 1/11/00 Electromechanical Dynamics 1 Chapter 3: Fundamentals of Mechanics and Heat 1/11/00 Electromechanical Dynamics 1 Force Linear acceleration of an object is proportional to the applied force: F = m a x(t) F = force acting on an object

More information

Name: Date: Period: AP Physics C Rotational Motion HO19

Name: Date: Period: AP Physics C Rotational Motion HO19 1.) A wheel turns with constant acceleration 0.450 rad/s 2. (9-9) Rotational Motion H19 How much time does it take to reach an angular velocity of 8.00 rad/s, starting from rest? Through how many revolutions

More information

T i t l e o f t h e w o r k : L a M a r e a Y o k o h a m a. A r t i s t : M a r i a n o P e n s o t t i ( P l a y w r i g h t, D i r e c t o r )

T i t l e o f t h e w o r k : L a M a r e a Y o k o h a m a. A r t i s t : M a r i a n o P e n s o t t i ( P l a y w r i g h t, D i r e c t o r ) v e r. E N G O u t l i n e T i t l e o f t h e w o r k : L a M a r e a Y o k o h a m a A r t i s t : M a r i a n o P e n s o t t i ( P l a y w r i g h t, D i r e c t o r ) C o n t e n t s : T h i s w o

More information

The basic principle to be used in mechanical systems to derive a mathematical model is Newton s law,

The basic principle to be used in mechanical systems to derive a mathematical model is Newton s law, Chapter. DYNAMIC MODELING Understanding the nature of the process to be controlled is a central issue for a control engineer. Thus the engineer must construct a model of the process with whatever information

More information

Introduction to Controls

Introduction to Controls EE 474 Review Exam 1 Name Answer each of the questions. Show your work. Note were essay-type answers are requested. Answer with complete sentences. Incomplete sentences will count heavily against the grade.

More information

ADMISSION TEST INDUSTRIAL AUTOMATION ENGINEERING

ADMISSION TEST INDUSTRIAL AUTOMATION ENGINEERING UNIVERSITÀ DEGLI STUDI DI PAVIA ADMISSION TEST INDUSTRIAL AUTOMATION ENGINEERING September 26, 2016 The candidates are required to answer the following multiple choice test which includes 30 questions;

More information

Linearize a non-linear system at an appropriately chosen point to derive an LTI system with A, B,C, D matrices

Linearize a non-linear system at an appropriately chosen point to derive an LTI system with A, B,C, D matrices Dr. J. Tani, Prof. Dr. E. Frazzoli 151-0591-00 Control Systems I (HS 2018) Exercise Set 2 Topic: Modeling, Linearization Discussion: 5. 10. 2018 Learning objectives: The student can mousavis@ethz.ch, 4th

More information

F(jω) = a(jω p 1 )(jω p 2 ) Û Ö p i = b± b 2 4ac. ω c = Y X (jω) = 1. 6R 2 C 2 (jω) 2 +7RCjω+1. 1 (6jωRC+1)(jωRC+1) RC, 1. RC = p 1, p

F(jω) = a(jω p 1 )(jω p 2 ) Û Ö p i = b± b 2 4ac. ω c = Y X (jω) = 1. 6R 2 C 2 (jω) 2 +7RCjω+1. 1 (6jωRC+1)(jωRC+1) RC, 1. RC = p 1, p ÓÖ Ò ÊÄ Ò Ò Û Ò Ò Ö Ý ½¾ Ù Ö ÓÖ ÖÓÑ Ö ÓÒ Ò ÄÈ ÐØ Ö ½¾ ½¾ ½» ½½ ÓÖ Ò ÊÄ Ò Ò Û Ò Ò Ö Ý ¾ Á b 2 < 4ac Û ÒÒÓØ ÓÖ Þ Û Ö Ð Ó ÒØ Ó Û Ð Ú ÕÙ Ö º ËÓÑ Ñ ÐÐ ÕÙ Ö Ö ÓÒ Ò º Ù Ö ÓÖ ½¾ ÓÖ Ù Ö ÕÙ Ö ÓÖ Ò ØÖ Ò Ö ÙÒØ ÓÒ

More information

Tutorial 1 - Drive fundamentals and DC motor characteristics

Tutorial 1 - Drive fundamentals and DC motor characteristics University of New South Wales School of Electrical Engineering & elecommunications ELEC4613 ELECRIC DRIVE SYSEMS utorial 1 - Drive fundamentals and DC motor characteristics 1. In the hoist drive system

More information

This document has been prepared by Sunder Kidambi with the blessings of

This document has been prepared by Sunder Kidambi with the blessings of Ö À Ö Ñ Ø Ò Ñ ÒØ Ñ Ý Ò Ñ À Ö Ñ Ò Ú º Ò Ì ÝÊ À Å Ú Ø Å Ê ý Ú ÒØ º ÝÊ Ú Ý Ê Ñ º Å º ² ºÅ ý ý ý ý Ö Ð º Ñ ÒÜ Æ Å Ò Ñ Ú «Ä À ý ý This document has been prepared by Sunder Kidambi with the blessings of Ö º

More information

Chapter 14 Periodic Motion

Chapter 14 Periodic Motion Chapter 14 Periodic Motion 1 Describing Oscillation First, we want to describe the kinematical and dynamical quantities associated with Simple Harmonic Motion (SHM), for example, x, v x, a x, and F x.

More information

Thermodynamics I Spring 1432/1433H (2011/2012H) Saturday, Wednesday 8:00am - 10:00am & Monday 8:00am - 9:00am MEP 261 Class ZA

Thermodynamics I Spring 1432/1433H (2011/2012H) Saturday, Wednesday 8:00am - 10:00am & Monday 8:00am - 9:00am MEP 261 Class ZA Thermodynamics I Spring 1432/1433H (2011/2012H) Saturday, Wednesday 8:00am - 10:00am & Monday 8:00am - 9:00am MEP 261 Class ZA Dr. Walid A. Aissa Associate Professor, Mech. Engg. Dept. Faculty of Engineering

More information

We define angular displacement, θ, and angular velocity, ω. What's a radian?

We define angular displacement, θ, and angular velocity, ω. What's a radian? We define angular displacement, θ, and angular velocity, ω Units: θ = rad ω = rad/s What's a radian? Radian is the ratio between the length of an arc and its radius note: counterclockwise is + clockwise

More information

BASIC EQUATION. Rotational speed = = ABC 60

BASIC EQUATION. Rotational speed = = ABC 60 CENTRIFUGAL PUMP BASIC EQUATION Rotational speed = =?@ = ABC 60 = = linear velocity in m/s? = radius in m @ = angular velocity in rad/s B = diameter in m C = rotation per minute Power OPQR? = S U = O V

More information

Review: control, feedback, etc. Today s topic: state-space models of systems; linearization

Review: control, feedback, etc. Today s topic: state-space models of systems; linearization Plan of the Lecture Review: control, feedback, etc Today s topic: state-space models of systems; linearization Goal: a general framework that encompasses all examples of interest Once we have mastered

More information

Mechatronics Engineering. Li Wen

Mechatronics Engineering. Li Wen Mechatronics Engineering Li Wen Bio-inspired robot-dc motor drive Unstable system Mirko Kovac,EPFL Modeling and simulation of the control system Problems 1. Why we establish mathematical model of the control

More information

α = p = m v L = I ω Review: Torque Physics 201, Lecture 21 Review: Rotational Dynamics a = Στ = I α

α = p = m v L = I ω Review: Torque Physics 201, Lecture 21 Review: Rotational Dynamics a = Στ = I α Physics 1, Lecture 1 Today s Topics q Static Equilibrium of Rigid Objects(Ch. 1.1-3) Review: Rotational and Translational Motion Conditions for Translational and Rotational Equilibrium Demos and Exercises

More information

ANALYSIS AND OPTIMIZATION OF A VERTICAL AXIS WIND TURBINE SAVONIUS-TYPE PANEL USING CFD TECHNIQUES

ANALYSIS AND OPTIMIZATION OF A VERTICAL AXIS WIND TURBINE SAVONIUS-TYPE PANEL USING CFD TECHNIQUES ANALYSIS AND OPTIMIZATION OF A VERTICAL AXIS WIND TURBINE SAVONIUS-TYPE PANEL USING CFD TECHNIQUES J. Vilarroig, S. Chiva*, R. Martínez and J. Segarra** *Author for correspondence ** Heliotec.SL Department

More information

MAE106 Homework 2 - Solution DC Motors & Intro to the frequency domain

MAE106 Homework 2 - Solution DC Motors & Intro to the frequency domain MAE06 Homework 2 - Solution DC Motors & Intro to the frequency domain University of California, Irvine Department of Mechanical and Aerospace Engineering Problem You are given the circuit shown in Figure.

More information

General Physics (PHY 2130)

General Physics (PHY 2130) General Physics (PHY 130) Lecture 0 Rotational dynamics equilibrium nd Newton s Law for rotational motion rolling Exam II review http://www.physics.wayne.edu/~apetrov/phy130/ Lightning Review Last lecture:

More information

is acting on a body of mass m = 3.0 kg and changes its velocity from an initial

is acting on a body of mass m = 3.0 kg and changes its velocity from an initial PHYS 101 second major Exam Term 102 (Zero Version) Q1. A 15.0-kg block is pulled over a rough, horizontal surface by a constant force of 70.0 N acting at an angle of 20.0 above the horizontal. The block

More information

Hydraulic (Fluid) Systems

Hydraulic (Fluid) Systems Hydraulic (Fluid) Systems Basic Modeling Elements Resistance apacitance Inertance Pressure and Flow Sources Interconnection Relationships ompatibility Law ontinuity Law Derive Input/Output Models ME375

More information

CIRCULAR MOTION, HARMONIC MOTION, ROTATIONAL MOTION

CIRCULAR MOTION, HARMONIC MOTION, ROTATIONAL MOTION CIRCULAR MOTION, HARMONIC MOTION, ROTATIONAL MOTION 1 UNIFORM CIRCULAR MOTION path circle distance arc Definition: An object which moves on a circle, travels equal arcs in equal times. Periodic motion

More information

Physics 201. Professor P. Q. Hung. 311B, Physics Building. Physics 201 p. 1/1

Physics 201. Professor P. Q. Hung. 311B, Physics Building. Physics 201 p. 1/1 Physics 201 p. 1/1 Physics 201 Professor P. Q. Hung 311B, Physics Building Physics 201 p. 2/1 Rotational Kinematics and Energy Rotational Kinetic Energy, Moment of Inertia All elements inside the rigid

More information

A j = 0.1 cm 2 10 cm 10 cm 10 cm. W j Wj. W j W j. W j. 10 cm 10 cm 10 cm. r i

A j = 0.1 cm 2 10 cm 10 cm 10 cm. W j Wj. W j W j. W j. 10 cm 10 cm 10 cm. r i ME 131B Fluid Mechanics Solutions to Week Eight Problem Session: Angular Momentum Principle (3/2/98) 1. In control volume analysis, all governing principles share the same common structure: storage = inow

More information

N5 H AH Physical Quantity Symbol Unit Unit Abbrev. 5 absorbed dose D gray Gy

N5 H AH Physical Quantity Symbol Unit Unit Abbrev. 5 absorbed dose D gray Gy 5 absorbed dose D gray Gy 5 absorbed dose rate D gray per second gray per hour gray per year Gys -1 Gyh -1 Gyy -1 5 6 7 acceleration a metre per second per second m s -2 5 6 7 acceleration due to gravity

More information

CLASS Fourth Units (Second part)

CLASS Fourth Units (Second part) CLASS Fourth Units (Second part) Energy analysis of closed systems Copyright The McGraw-Hill Companies, Inc. Permission required for reproduction or display. MOVING BOUNDARY WORK Moving boundary work (P

More information

AP Physics C Mechanics Objectives

AP Physics C Mechanics Objectives AP Physics C Mechanics Objectives I. KINEMATICS A. Motion in One Dimension 1. The relationships among position, velocity and acceleration a. Given a graph of position vs. time, identify or sketch a graph

More information

Fundamentals of Thermodynamics. Chapter 8. Exergy

Fundamentals of Thermodynamics. Chapter 8. Exergy Fundamentals of Thermodynamics Chapter 8 Exergy Exergy Availability, available energy Anergy Unavailable energy Irreversible energy, reversible work, and irreversibility Exergy analysis : Pure Thermodynamics

More information

IM4. Modul Mechanics. Coupled Pendulum

IM4. Modul Mechanics. Coupled Pendulum IM4 Modul Mechanics Coupled Pendulum Two pendulums that can exchange energy are called coupled pendulums. The gravitational force acting on the pendulums creates rotational stiffness that drives each pendulum

More information

Dynamic Modeling. For the mechanical translational system shown in Figure 1, determine a set of first order

Dynamic Modeling. For the mechanical translational system shown in Figure 1, determine a set of first order QUESTION 1 For the mechanical translational system shown in, determine a set of first order differential equations describing the system dynamics. Identify the state variables and inputs. y(t) x(t) k m

More information

Game Physics. Game and Media Technology Master Program - Utrecht University. Dr. Nicolas Pronost

Game Physics. Game and Media Technology Master Program - Utrecht University. Dr. Nicolas Pronost Game and Media Technology Master Program - Utrecht University Dr. Nicolas Pronost Essential physics for game developers Introduction The primary issues Let s move virtual objects Kinematics: description

More information

Physics A - PHY 2048C

Physics A - PHY 2048C Physics A - PHY 2048C and 11/15/2017 My Office Hours: Thursday 2:00-3:00 PM 212 Keen Building Warm-up Questions 1 Did you read Chapter 12 in the textbook on? 2 Must an object be rotating to have a moment

More information

Example: DC Motor Speed Modeling

Example: DC Motor Speed Modeling Page 1 of 5 Example: DC Motor Speed Modeling Physical setup and system equations Design requirements MATLAB representation and open-loop response Physical setup and system equations A common actuator in

More information

Rolling without slipping Angular Momentum Conservation of Angular Momentum. Physics 201: Lecture 19, Pg 1

Rolling without slipping Angular Momentum Conservation of Angular Momentum. Physics 201: Lecture 19, Pg 1 Physics 131: Lecture Today s Agenda Rolling without slipping Angular Momentum Conservation o Angular Momentum Physics 01: Lecture 19, Pg 1 Rolling Without Slipping Rolling is a combination o rotation and

More information

DEVIL PHYSICS BADDEST CLASS ON CAMPUS IB PHYSICS

DEVIL PHYSICS BADDEST CLASS ON CAMPUS IB PHYSICS DEVIL PHYSICS BADDEST CLASS ON CAMPUS IB PHYSICS OPTION B-1A: ROTATIONAL DYNAMICS Essential Idea: The basic laws of mechanics have an extension when equivalent principles are applied to rotation. Actual

More information

Assessment of Power Coefficient of an Offline Wind Turbine Generator System

Assessment of Power Coefficient of an Offline Wind Turbine Generator System RESEARCH Assessment of Power Coefficient of an Offline Wind Turbine Generator System Parikshit G. Jamdade 1 *, Santosh V. Patil, Shrinivas G. Jamdade 1. Assistant Professor, PVG s College of Engineering

More information

PHYSICS 218 Final Exam Fall, 2014

PHYSICS 218 Final Exam Fall, 2014 PHYSICS 18 Final Exam Fall, 014 Name: Signature: E-mail: Section Number: No calculators are allowed in the test. Be sure to put a box around your final answers and clearly indicate your work to your grader.

More information

Engineering Unit 1: Engineering Principles

Engineering Unit 1: Engineering Principles Write your name here Surname Other names Pearson BTEC Level 3 Extended Certificate, Foundation Diploma, Diploma, Extended Diploma Centre Number Learner Registration Number Engineering Unit 1: Engineering

More information

FORMULAS FOR MOTORIZED LINEAR MOTION SYSTEMS

FORMULAS FOR MOTORIZED LINEAR MOTION SYSTEMS FOR MOTORIZED LINEAR MOTION SYSTEMS Haydon Kerk Motion Solutions Pittman Motors : 203 756 7441 : 267 933 2105 SYMBOLS AND UNITS Symbol Description Units Symbol Description Units a linear acceleration m/s

More information

Figure 1 Answer: = m

Figure 1 Answer: = m Q1. Figure 1 shows a solid cylindrical steel rod of length =.0 m and diameter D =.0 cm. What will be increase in its length when m = 80 kg block is attached to its bottom end? (Young's modulus of steel

More information

Uniform Circular Motion

Uniform Circular Motion Uniform Circular Motion Motion in a circle at constant angular speed. ω: angular velocity (rad/s) Rotation Angle The rotation angle is the ratio of arc length to radius of curvature. For a given angle,

More information

Moment of Inertia Race

Moment of Inertia Race Review Two points, A and B, are on a disk that rotates with a uniform speed about an axis. Point A is closer to the axis than point B. Which of the following is NOT true? 1. Point B has the greater tangential

More information

E = K + U. p mv. p i = p f. F dt = p. J t 1. a r = v2. F c = m v2. s = rθ. a t = rα. r 2 dm i. m i r 2 i. I ring = MR 2.

E = K + U. p mv. p i = p f. F dt = p. J t 1. a r = v2. F c = m v2. s = rθ. a t = rα. r 2 dm i. m i r 2 i. I ring = MR 2. v = v i + at x = x i + v i t + 1 2 at2 E = K + U p mv p i = p f L r p = Iω τ r F = rf sin θ v 2 = v 2 i + 2a x F = ma = dp dt = U v dx dt a dv dt = d2 x dt 2 A circle = πr 2 A sphere = 4πr 2 V sphere =

More information

AP Physics 1. Course Overview

AP Physics 1. Course Overview Radnor High School Course Syllabus AP Physics 1 Credits: Grade Weighting: Yes Prerequisites: Co-requisites: Length: Format: 1.0 Credit, weighted Honors chemistry or Advanced Chemistry Honors Pre-calculus

More information

Control of Proton Electrolyte Membrane Fuel Cell Systems. Dr. M. Grujicic Department of Mechanical Engineering

Control of Proton Electrolyte Membrane Fuel Cell Systems. Dr. M. Grujicic Department of Mechanical Engineering Control of Proton Electrolyte Membrane Fuel Cell Systems Dr. M. Grujicic 4 Department of Mechanical Engineering OUTLINE. Feedforward Control, Fuel Cell System. Feedback Control, Fuel Cell System W Cp Supply

More information

ENT 254: Applied Thermodynamics

ENT 254: Applied Thermodynamics ENT 54: Applied Thermodynamics Mr. Azizul bin Mohamad Mechanical Engineering Program School of Mechatronic Engineering Universiti Malaysia Perlis (UniMAP) azizul@unimap.edu.my 019-4747351 04-9798679 Chapter

More information

Applied Fluid Mechanics

Applied Fluid Mechanics Applied Fluid Mechanics 1. The Nature of Fluid and the Study of Fluid Mechanics 2. Viscosity of Fluid 3. Pressure Measurement 4. Forces Due to Static Fluid 5. Buoyancy and Stability 6. Flow of Fluid and

More information

Physics 201, Lecture 21

Physics 201, Lecture 21 Physics 201, Lecture 21 Today s Topics q Static Equilibrium of Rigid Objects(Ch. 12.1-3) Review: Rotational and Translational Motion Conditions for Translational and Rotational Equilibrium Demos and Exercises

More information

Chapter three. Mathematical Modeling of mechanical end electrical systems. Laith Batarseh

Chapter three. Mathematical Modeling of mechanical end electrical systems. Laith Batarseh Chapter three Mathematical Modeling of mechanical end electrical systems Laith Batarseh 1 Next Previous Mathematical Modeling of mechanical end electrical systems Dynamic system modeling Definition of

More information

PHYSICS SAMPLE PAPER MARKING SCHEME

PHYSICS SAMPLE PAPER MARKING SCHEME PHYSICS SAMPLE PAPER MARKING SCHEME Ques. No. Electric field Vector. P= VI Value Points I=P/V = 60/0=0.7 A. R= ρ l/a Volume remains constant A l = A l I = l A = A/ R = 4 R 4. (Equally spaced parallel lines

More information

hp calculators HP 35s Solving for roots Roots of an equation Using the SOLVE function Practice solving problems involving roots

hp calculators HP 35s Solving for roots Roots of an equation Using the SOLVE function Practice solving problems involving roots Roots of an equation Using the SOLVE function Practice solving problems involving roots Roots of an equation The roots of an equation are values of X where the value of Y is equal to zero. For example,

More information

PHYSICS 025 FINAL EXAMINATION Friday, 2003 April 11

PHYSICS 025 FINAL EXAMINATION Friday, 2003 April 11 Print Name: Student No. A 1-10 A 11-20 A 21-30 B1 B2 B3 B4 C1 C2 C3 Total PHYSICS 025 FINAL EXAMINATION Friday, 2003 April 11 Time: 7:00 10:00 PM 1. This is a closed book test. You may use only a calculator,

More information

CHAPTER 9 ROTATIONAL DYNAMICS

CHAPTER 9 ROTATIONAL DYNAMICS CHAPTER 9 ROTATIONAL DYNAMICS PROBLEMS. REASONING The drawing shows the forces acting on the person. It also shows the lever arms for a rotational axis perpendicular to the plane of the paper at the place

More information

Chapter 10: Sinusoidal Steady-State Analysis

Chapter 10: Sinusoidal Steady-State Analysis Chapter 10: Sinusoidal Steady-State Analysis 1 Objectives : sinusoidal functions Impedance use phasors to determine the forced response of a circuit subjected to sinusoidal excitation Apply techniques

More information

Chapter 5. Mass and Energy Analysis of Control Volumes

Chapter 5. Mass and Energy Analysis of Control Volumes Chapter 5 Mass and Energy Analysis of Control Volumes Conservation Principles for Control volumes The conservation of mass and the conservation of energy principles for open systems (or control volumes)

More information

Angular Momentum. Objectives CONSERVATION OF ANGULAR MOMENTUM

Angular Momentum. Objectives CONSERVATION OF ANGULAR MOMENTUM Angular Momentum CONSERVATION OF ANGULAR MOMENTUM Objectives Calculate the angular momentum vector for a moving particle Calculate the angular momentum vector for a rotating rigid object where angular

More information

Rotation. I. Kinematics - Angular analogs

Rotation. I. Kinematics - Angular analogs Rotation I. Kinematics - Angular analogs II. III. IV. Dynamics - Torque and Rotational Inertia Work and Energy Angular Momentum - Bodies and particles V. Elliptical Orbits The student will be able to:

More information

Example: Modeling DC Motor Position Physical Setup System Equations Design Requirements MATLAB Representation and Open-Loop Response

Example: Modeling DC Motor Position Physical Setup System Equations Design Requirements MATLAB Representation and Open-Loop Response Page 1 of 5 Example: Modeling DC Motor Position Physical Setup System Equations Design Requirements MATLAB Representation and Open-Loop Response Physical Setup A common actuator in control systems is the

More information

Conservation of Angular Momentum

Conservation of Angular Momentum Physics 101 Section 3 March 3 rd : Ch. 10 Announcements: Monday s Review Posted (in Plummer s section (4) Today start Ch. 10. Next Quiz will be next week Test# (Ch. 7-9) will be at 6 PM, March 3, Lockett-6

More information